Final answer:
To produce 22 g of CO₂, we calculate the moles of CO₂ and use the 1:1 molar ratio with O₂ to find that 16 g of oxygen gas is required, according to the balanced chemical equation for the reaction.
Explanation:
Calculating Mass of Oxygen Required to Produce Carbon Dioxide
To determine the mass of oxygen gas required to produce 22 g of carbon dioxide in the reaction C(s) + O₂(g)
ightarrow CO₂(g), we will first consider the molar masses of the substances involved. The molar mass of carbon dioxide (CO₂) is 44.009 g/mol, which means 1 mole of CO₂ weighs 44.009 grams. Since carbon is a pure element in its solid form, its molar mass is equivalent to its atomic mass, which is 12.0 g/mol. The molar mass of oxygen (O₂) is 32.0 g/mol because one mole of O₂ consists of 2 atoms of oxygen and the atomic mass of oxygen is 16.0 g/mol per atom.
Using the stoichiometry from the balanced chemical equation, we know that 1 mole of C will react with 1 mole of O₂ to produce 1 mole of CO₂. Therefore, if we have 22 g of CO₂, we can calculate the moles of CO₂ and then the moles of O₂ required:
Calculate moles of CO₂ produced: (22 g CO₂) / (44.009 g/mol) = 0.5 mol CO₂.
We need 0.5 mol of O2 since the mole ratio is 1:1.
Calculate mass of O₂ required: (0.5 mol O₂) times (32.0 g/mol) = 16 g O₂.
So, the mass of oxygen gas required to produce 22 g of carbon dioxide is 16 g.
3.00 L of Ch4 is known to contain 0.650 moles at a certain temperature and pressure if the volume of a chamber of CH4 increased from 7.00L to 8.20 L how many moles CH4 were added assume temperature and pressure stayed constant
Final answer:
When the volume of a chamber containing CH₄ increased from 7.00L to 8.20L, 0.260 moles of CH₄ were added, assuming constant temperature and pressure.
Explanation:
To determine how many moles of CH₄ (methane) were added when the volume of the chamber increased from 7.00L to 8.20L, we can use the molar volume concept under the assumption that temperature and pressure remain constant, therefore following Avogadro's Law. According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of moles. You can calculate the number of moles in the new volume by setting up a proportion based on the known conditions (3.00 L contains 0.650 moles) and then solving for the number of moles in the new volume of 8.20 L.
First, determine the number of moles in the 7.00 L chamber:
moles in 3.00 L / 3.00 L = moles in 7.00 L / 7.00 L
0.650 moles / 3.00 L = x moles / 7.00 L
x = (0.650 moles / 3.00 L) × 7.00 L
x = 1.517 moles in 7.00 L
Now, calculate the number of moles in the increased volume of 8.20 L:
moles in 3.00 L / 3.00 L = moles in 8.20 L / 8.20 L
0.650 moles / 3.00 L = y moles / 8.20 L
y = (0.650 moles / 3.00 L) × 8.20 L
y = 1.777 moles in 8.20 L
The number of moles added is the difference between the moles in 8.20 L and the moles in 7.00 L:
moles added = 1.777 moles - 1.517 moles
moles added = 0.260 moles
Therefore, when the volume of the CH₄ chamber increased from 7.00L to 8.20L, 0.260 moles of CH₄ were added.
Genes are NOT found inside cells. True or False
Answer:
False
Explanation:
Genes are found inside chromosomes and chromosomes are in cells. So technically genes are in cells
Photochemical smog is formed when primary pollutants interact with
Answer: Sunlight.
Explanation:
Photochemical smog is formed when primary pollutants such nitrogen oxides and volatile organic compound (VOC) react with sunlight, forming a brown haze above cities.
Photochemical smog can only occur during the day.
Photochemical smog is formed when primary pollutants such as nitrogen oxides and volatile organic compounds interact with sunlight. The reaction between these pollutants in the presence of sunlight leads to the formation of smog.
Explanation:Photochemical smog is formed when primary pollutants such as nitrogen oxides (NOx) and volatile organic compounds (VOCs) interact with sunlight. These primary pollutants, which can come from sources like vehicle emissions and industrial processes, undergo chemical reactions in the presence of sunlight to produce secondary pollutants, including ozone. The reaction between NOx and VOCs in the presence of sunlight leads to the formation of photochemical smog, which appears as a brown haze above cities.
Before using glassware in the lab, it is important to _______.
A.
make sure that the glassware is clean and dry
B.
carefully inspect the glassware for cracks and chips
C.
know the location of the classroom broom, dustpan, and broken glassware container
D.
all of these
Answer:
D All of these
Explanation:
hope this helped
In lecture we discussed two aspects of the critical concentration. What is the relationship between the critical concentration and whether or not actin filaments will form in a reaction? What is the relationship between critical concentration and reaction that contains f-actin at steady state?
The critical concentration is key in determining whether actin monomers will form filaments or disassemble. Above this concentration, polymerization of actin occurs, while below it, monomers dissociate. A steady state is reached at the critical concentration, essential for cell motility and structure.
The critical concentration is the threshold at which actin filaments will either form or dissociate. In the presence of actin monomers above this concentration, the actin will polymerize into filaments; below it, the filaments will disassemble into monomers. At the critical concentration, there is a dynamic state where the rates of polymerization and depolymerization are equal, leading to a steady state in the reaction containing F-actin (filamentous actin).
Actin dynamics are essential for various cellular functions, including muscle contraction and cell motility. The polymerization and depolymerization processes are regulated by ATP-binding and hydrolysis, with critical concentration playing a crucial role in achieving a steady state of F-actin within cells. This balance affects the cell's ability to exert forces on itself and its environment, a key aspect of cellular motility and structure.
Determine the molarity of a solution formed by dissolving 468 mg of mgi2 in enough water to yield 50.0 ml of solution.
Answer : The molarity of a solution is, 0.0337 M
Explanation : Given,
Mass of [tex]MgI_2[/tex] = 468 mg = 0.468 g (1 mg = 0.001 g)
Volume of solution = 50.0 mL
Molar mass of [tex]MgI_2[/tex] = 278 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Mass of }MgI_2\times 1000}{\text{Molar mass of }MgI_2\times \text{Volume of solution (in mL)}}[/tex]
Now put all the given values in this formula, we get:
[tex]\text{Molarity}=\frac{0.468g\times 1000}{278g/mole\times 50.0mL}=0.0337mole/L=0.0337M[/tex]
Therefore, the molarity of a solution is, 0.0337 M
The molarity of the solution formed is 0.0337 M
From the question,
We are to determine the molarity of the solution formed.
First, we will determine the number of moles MgI₂ dissolved
Mass of MgI₂ dissolved = 468 mg = 0.468 g
From the formula
[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]
Molar mass of MgI₂ = 278.1139 g/mol
∴ Number of moles of MgI₂ present = [tex]\frac{0.468}{278.1139}[/tex]
Number of moles of MgI₂ present = 0.001682764 mole
Now,
For the molarity of the solution formed,
Using the formula
[tex]Molarity = \frac{Number\ of\ moles}{Volume}[/tex]
Volume of the solution = 50.0 mL = 0.050 L
∴ Molarity of the solution = [tex]\frac{0.001682764}{0.050}[/tex]
Molarity of the solution = 0.033655
Molarity of the solution ≅ 0.0337 M
Hence, the molarity of the solution formed is 0.0337 M
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Mrs Salge is very particular about her ice cream. Her
ice cream cone recipe is 1 cone, 1 scoop of blue ice
cream and 2 scoops of red ice cream. There is also a
cherry on top!
How many ice cream cones could Mrs Salge make if
she had 10 cones, 12 scoops of blue ice cream, 12
scoops of red ice cream and 10 cherries?
Answer: Mrs. Salge can make 6 ice cream cones
Explanation:
Mrs. Salge's recipe:
1 cone
1 scoop blue ice cream
2 scoops red ice cream
1 cherry
Now we will find what the limiting ingredient is:
We know she has:
10 cones. → 10 ice cream cones
12 scoops blue ice cream. → 12 ice cream cones
12 scoops red ice cream. → 6 ice cream cones
10 cherries. → 10 ice cream cones
The red ice cream is the limiting factor. Mrs. Salge can make 6 ice cream cones.
Mrs. Salge can make a total of 6 ice cream cones with her available ingredients, as the red ice cream scoops are the limiting factor.
To determine how many ice cream cones Mrs. Salge can make given her resources, we must find out which ingredient limits the number of cones she can make. Her recipe requires one cone, one scoop of blue ice cream, two scoops of red ice cream, and one cherry for each ice cream cone. Therefore, we will check each ingredient to see which will run out first if she keeps making the ice cream cones as per the recipe.
Cone: 10 availableBlue ice cream: 12 scoops availableRed ice cream: 12 scoops availableCherry: 10 availableSince each cone requires 2 scoops of red ice cream, the number of cones she can make will be limited by the red ice cream. With 12 scoops of red ice cream, she can make 6 cones because each cone requires 2 scoops. This is the limiting factor because even though she has 10 cones and 10 cherries, after making 6 cones, she will run out of red ice cream.
Therefore, Mrs. Salge can make a total of 6 ice cream cones with the ingredients available to her before one of the ingredients runs out and prevents her from making more.
A gas has a volume of 3 L at a temperature of 78 c.Find the volume of the gas at standard temperature
Answer:
The answer to your question is V2 = 2.5 l
Explanation:
Data
Volume 1 = V1 = 3 l
Temperature 1 = T1 = 78°C
Volume 2 = V2 = ?
Temperature 2 = T2 = 20°C Standard temperature = 20°C
Process
To solve this problem use Charles' law
V1/T1 = V2/T2
-Solve for V2
V2 = V1T2 / T1
1.- Convert the temperature to °K
T1 = 78 + 273 = 352°K
T2 = 20 + 273 = 293°K
2.- Substitution
V2 = (3 x 293) / 352
3.- Simplification
V2 = 879/352
4.- Result
V2 = 2.5 l
How many moles of Pb(NO3)2 are required
if 8 moles of AICI: are consumed?
3Pb(NO3)2 + 2AlCl3 + 3PbCl2 + 2A1(NO3)3
Answer:
12 moles Pb(NO₄)₂ needed.
Explanation:
3Pb(NO₃)₂ +2AlCl₃ => 3PbCl₂ + 2Al(NO₃)₃
Given => ? moles 8 moles
from reaction stoichiometry, 2 moles AlCl₃ requires 3 moles Pb(NO₄)₂ then 8 moles AlCl₃ requires 3/2(8) moles of the Pb(NO₄)₂ => 12 moles Pb(NO₄)₂ needed.
Using the following balanced equation to the question that follows.
1 Zn + 2 MnO2 + 1 H2O → 1 Zn(OH)2 + 1 Mn2O3
How many moles of MnO2 are needed to produce 8.54 moles of Zn(OH)2?
Answer:
17.08 moles of manganese dioxide
Explanation:
From the balanced reaction equation;
Zn + 2 MnO2 + 1 H2O → Zn(OH)2 + Mn2O3 (notice that I did not put 1 as a stoichiometric coefficient. It is expected that any specie written without a coefficient should have a coefficient of 1)
It is clear from the reaction equation that 2 moles of manganese dioxide produced 1 mole of zinc II hydroxide
Hence x moles of manganese dioxide will produce 8.54 moles of zinc II hydroxide
x= 2× 8.54/1
x= 17.08 moles of manganese dioxide
20.352 mL of chlorine under a pressure of 680. mm Hg are
placed in a container
under a pressure of 1210 mm Hg. The temperature remains
constant at 296 K.
What is the volume of the container in liters?
Answer:
0.01144L or 1.144x10^-2L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 20.352 mL
P1 (initial pressure) = 680mmHg
P2 (final pressure) = 1210mmHg
V2 (final volume) =.?
Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:
P1V1 = P2V2
680 x 20.352 = 1210 x V2
Divide both side by 1210
V2 = (680 x 20.352)/1210
V2 = 11.44mL
Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:
1000mL = 1 L
11.44mL = 11.44/1000 = 0.01144L
Therefore the volume of the container is 0.01144L or 1.144x10^-2L
Answer:
0.011437L
Explanation:
In the question, we are told that under a pressure of 680mmHg, chlorine gas occupies a volume of 20.352mL and then the pressure is changed to 1210mmHg at constant temperature.
Boyle's law states that the volume of a fixed mass of gas is directly proportional to the pressure of the gas at constant temperature.
Mathematically;
P1V1=P2V2
P1= initial pressure
V1= initial volume
P2= final pressure
V2= final volume
We will apply Boyle's law to get the new volume.
From, the relationship P1V1=P2V2
We make V2 subject of formula
V2= (P1V1)/P2
Given;
P1=680mmHg
V1=20.352mL= 20.352/1000L= 0.020352L
P2=1210mmHg
V2=(680×0.020352)/1210
V2=0.011437L
During nuclear fusion, energy is generated as
Final answer:
Nuclear fusion is a reaction in which two nuclei combine to form a larger nucleus, releasing energy. It is the process that powers the sun and stars.
Explanation:
Nuclear fusion is a reaction in which two nuclei are combined to form a larger nucleus, releasing energy. It is the process that powers the sun and other stars. In the sun, hydrogen nuclei combine to form helium, releasing a significant amount of energy.
Describe the process of ipm as an environmental solution
Answer:
IPM is also known as Integrated Pest management.
IPM is an ecosystem-based strategy that deals with long-term prevention of pests or their damage through a combination of techniques such as biological control, habitat manipulation, modification of cultural practices, and use of resistant varieties.
These factors are very important in protecting the environment and it prevents some crops and animals from going into extinction.
The process of IPM involves prevention, monitoring and intervening as an environmental solution.
What is IPM stands for?IPM stands for 'Integrated Pest management', it is an ecosystem-based strategy.
IPM works on three main aspects and that are:
Prevent: In this phase they prevent the crops from the build-up pests.Monitor: In this phase they monitor the crop, to carry out natural control mechanism for pests.Intervene: In this phase they take some control steps when needed by determining the most appropriate cost effectively and environmental friendly scheme. They done this by physical, chemical or biologically and prevents some crops and animals from going into extinction.Hence, the process of IPM raised out as an environmental solution.
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How many grams of silver chloride are produced from 5.0g of silver nitrate reacting with an excess of
barium chloride?
How many grams of barium chloride would actually be necessary to complete the reaction of the silver nitrate?
Final answer:
From 5.0 grams of silver nitrate reacting with barium chloride, 4.21 grams of silver chloride are produced. The exact amount of barium chloride is not calculated because it is in excess.
Explanation:
To determine how many grams of silver chloride are produced from the reaction of 5.0g of silver nitrate (AgNO3) with an excess of barium chloride (BaCl2), we use the stoichiometry of the balanced chemical equation. The balanced equation is:
AgNO3 (aq) + BaCl2 (aq) → AgCl (s) + Ba(NO3)2 (aq)
To calculate the mol product, we follow the equation:
(mol product) = (mol reactant) × (stoichiometric mole ratio)
For AgNO3 with a molar mass of 169.88 g/mol, we calculate the moles of reactant:
moles of AgNO3 = mass of AgNO3 / molar mass of AgNO3
= 5.0 g / 169.88 g/mol
= 0.0294 moles of AgNO3
For silver chloride (AgCl) with a molar mass of 143.32 g/mol, we calculate the mass of AgCl produced:
mass of AgCl = moles of AgCl x molar mass of AgCl
= 0.0294 moles × 143.32 g/mol
= 4.2094 grams of AgCl (rounded to 4.21 grams)
Regarding the amount of barium chloride needed, since it is in excess and not limiting the reaction, the exact amount needed is not calculated. However, if one wanted to calculate it, we would use the stoichiometry of the reaction based on the amount of silver nitrate, ensuring that barium chloride is in excess.
please help!
Which statement is NOT correct?
a) In an ionic compound, a metal and a non metal form a compound, and electrons are transferred from one to the other.
b) In an ionic compound, a metal and a polyatomic ion form a compound, and electrons are shared.
c) In both ionic and molecular compounds, valence electrons take part in bonding.
d) In a molecular compound, a non-metal and a non-metal form a compound, and electrons are shared
Answer:
D is the answer
Explanation:
I'm pretty sure a molecular compound doesn't form between 2 non metals
...I think, but I can't remember
The incorrect statement is that in an ionic compound, a metal and a polyatomic ion form a compound, and electrons are shared. In ionic compounds, electrons are transferred, not shared, resulting in the formation of cations and anions.
Explanation:The statement that is NOT correct is: b) In an ionic compound, a metal and a polyatomic ion form a compound, and electrons are shared. This statement is incorrect because in an ionic compound, electrons are not shared but are transferred from the metal to the non-metal or to the polyatomic ion, forming cations and anions.
In ionic compounds, metals lose valence electrons to form positively charged ions, while nonmetals gain those electrons to form negatively charged ions, both achieving a full outer shell as per the octet rule. Covalent compounds, on the other hand, form when non-metals share electrons, producing molecular compounds.
Therefore, the correct statements are:
a) In an ionic compound, a metal and a non-metal form a compound, and electrons are transferred from one to the other.
c) In both ionic and molecular compounds, valence electrons take part in bonding.
d) In a molecular compound, a non-metal and a non-metal form a compound, and electrons are shared.
What is the pressure of an ideal solution containing .5 moles of a nonvolatile solute and 300g of ethanol at 40C? The vapor pressure of ethanol is 134 torr at 40C
Answer:
The pressure of the solution is 144 torr
Explanation:
Step 1: Data given
Number of moles of a nonvolatile solute = 0.5 moles
Mass of ethanol = 300 grams
Molar mass of ethanol = 46.07 g/mol
Temperature = 40°C
The vapor pressure of ethanol = 134 torr
Step 2: Calculate moles ethanol
Moles ethanol = mass ethanol / molar mass ethanol
Moles ethanol = 300 grams / 46.07 g/mol
Moles ethanol = 6.51 moles
Step 3: Calculate the total moles
Total moles = 0.5 moles + 6.51 moles
Total moles = 7.01 moles
Step 4: Calculate mol fraction
Mol fraction = moles / total moles
Mol fraction ethanol = 6.51 / 7.01 moles
Mol fraction ethanol = 0.93
Mol fraction nonvolatile solute
0.5 moles / 7.01 moles = 0.07
Step 5: Calculate Total pressure of the solution
Vapor pressure ethanol = mol fraction * total pressure solution
134 torr = 0.93 * total pressure solution
Total pressure solution = 134 torr/ 0.93
Total pressure solution = 144 torr
The pressure of the solution is 144 torr
which is not an example of a vestigial structure
Answer:
the femur
Explanation:
a vestigial structure is useless, and a femur bone is not uselsess
Answer:
Pelvic bone of a snake
Explanation:
200.0 mL OF A 5.10 M solution are diluted to 500.0 mL. What is the concentration of the resulting solution? *
Answer:
Concentration of the resulting solution = 2.04 M
Explanation:
Data:
M1 = 5.10 M
V1 = 200.0 mL
V2 = 500.0 mL
M2 = ?
By modifying the volume of solution, keeping the amount of solute constant, the concentration changes. To perform the calculations, the equation will be:
[tex]M1*V1=M2*V2[/tex]
Where M1 is the initial concentration of the solution, M2 the final concentration and V is the value of the volumes of the initial and final solution.
Clearing the value of M2 from the equation and replacing the values we have:
[tex]M2=\frac{M1*V1}{V2} =\frac{5.10M*200mL}{500mL} =2.04M[/tex]
Answer:
2.04M
Explanation:
Using C1V1 = C2V2
where;
C1 = Concentration of stock solution = 5.10M
C2 = Final concentration of new solution = x
V1 = Volume of stock solution = 200ml
V2 = Final volume of new solution = 500ml
Inserting the values into the formulae, we have;
5.10 * 200 = x * 500
x = (5.10 * 200) / 500
x = 2.04M
Calculate the equilibrium constant for the decomposition of water 2h2o(l) 2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –237.2 kj/mol.
The equilibrium constant for the decomposition of water is approximately 1.01 × 10^-13.
Explanation:The equilibrium constant (Kc) for the decomposition of water can be calculated using the equation: Kc = [H2]2[O2]/[H2O]2.
Given that ΔG°f(H2O(l)) = -237.2 kJ/mol, we can use the equation ΔG° = -RTlnK to find the equilibrium constant. R is the ideal gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin (25 °C + 273.15 = 298.15 K). Plugging in the values, we can solve for K.
ΔG° = -RTlnK
-237.2 kJ/mol = -(8.314 J/(mol·K) × 298.15 K) × lnK
lnK = -237.2 kJ/mol ÷ (8.314 J/(mol·K) × 298.15 K)
lnK ≈ -29.155
K ≈ e-29.155
K ≈ 1.01 × 10-13
Therefore, the equilibrium constant for the decomposition of water at 25 °C is approximately 1.01 × 10-13.
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"how many liters of a 0.2 m naoh solution are needed in order to have 0.4 moles of naoh?"
Answer:
2
Explanation:
well since the question has given you the concentration of the solution 0.2mol/L and the wanted amount (moles) of naoh(0.4mol) you are able put this into the formula n=cV; where n is the moles of naoh the solution, c is the concentraton of the solution and V is the volume of the solution in litres.
therefore the for the solution to have 0.4 moles of naoh you put it into the formula, giving you:
0.4 = 0.2V
V = 2
V = 2 litres
Final answer:
To obtain 0.4 moles of NaOH from a 0.2 M NaOH solution, you would need to measure out 2 liters of the solution.
Explanation:
To calculate the volume of a 0.2 M NaOH solution needed to have 0.4 moles of NaOH, we can use the molarity equation, which is:
Molarity (M) = Moles of solute / Volume of solution in liters (L)
We can rearrange this equation to solve for the volume:
Volume of solution (L) = Moles of solute / Molarity (M)
Substituting the given values:
Volume of solution (L) = 0.4 moles NaOH / 0.2 M NaOH
Volume of solution (L) = 2 liters
Therefore, you would need 2 liters of a 0.2 M NaOH solution to have 0.4 moles of NaOH.
someone help please!
Answer:
your answer is either c or d but probably c
What is white light?
Answer:
A white light is apparently colourless light, for example ordinary daylight. It contains all the wavelengths of the visible spectrum at equal intensity.
Answer:
White Light is a light having a mixture of frequencies, being perceived as having no specific colour; such as sunlight.
Explanation:
what is the compound MnCL2 called
The compound MnCL2 called
Manganese cloride
Answer:
Explanation:
Cloruro de manganeso
At the melting point of a substance, temperature ______ as heat is being added and the substance is changing from a solid to a liquid.
A. increases
B. remains constant
C. decreases
D. ceases to exist
will the reaction of addition to an inhibitor be fast or slow?
Answer:hope we can be friends
can i please get brainliest
Although phlorizin inhibition of Na+-glucose cotransport occurs within a few seconds, 3H-phlorizin binding to the sodium-coupled glucose transport protein(s) requires several minutes to reach equilibrium (the fast-acting slow-binding paradigm). Using kinetic models of arbitrary dimension that can be reduced to a two-state diagram according to Cha’s formalism, we show that three basic mechanisms of inhibitor binding can be identified whereby the inhibitor binding step either (A) represents, (B) precedes, or (C) follows the rate-limiting step in a binding reaction. We demonstrate that each of mechanisms A–C is associated with a set of unique kinetic properties, and that the time scale over which one may expect to observe mechanism C is conditioned by the turnover number of the catalytic cycle. In contrast, mechanisms A and B may be relevant to either fast-acting or slow-binding inhibitors.
Explanation:
help on identifying the solute and solvent
Answer:
Solute is Lithium nitrate, and solvent is water.
Explanation:
Lithium nitrate is trigonal crystal which is soluble in water.
Given the two standard reduction potentials below what is the ksp of ag2cro4 at 25 °c
To determine the Ksp of Ag2CrO4 at 25 °C, you would first need to determine the standard reduction potentials and use the free energy equation ∆G° = -nFE°. Next, use the relationship between the equilibrium constant and ∆G° given by ∆G° = -RT ln Ksp to find the Ksp. However, without the necessary information, a precise value cannot be given.
Explanation:To find the solubility product constant (Ksp) of Ag2CrO4 at 25 °C given the provided standard reduction potentials, we would need to look at the relationship between the equilibrium constant, K, and ∆G° (standard free energy). The equation ∆G° = -RT ln K is used in these cases, where R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant that we're interested in. Note that in order to use this equation, we first need to calculate ∆G° using the given reduction potentials and the equation ∆G° = -nFE°, where n is the number of electrons transferred, F is Faraday's constant, and E° is the standard reduction potential.
For example, if the ∆G° for the reaction came out to be around 167.9 kJ as per the details provided, and we can use ∆G° = -RT ln Ksp to find the Ksp. However, without the complete standard reduction potentials, a precise Ksp value for Ag2CrO4 at 25 °C cannot be provided here.
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how many electrons are in a atom of zicronium
Answer:
There are 40 electrons in one atom of Zirconium.
Explanation:
Note: The word is not zicronium, it is Zirconium.
Answer:
Name Zirconium
Atomic Mass 91.224 atomic mass units
Number of Protons 40
Number of Neutrons 51
Number of Electrons 40
Explanation:
A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas in celcius.
Answer:
The new temperature of the gas is 200 Celsius degrees.
Explanation:
Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly.
In this way, Charles's law is a law that says that the quotient that exists between volume and temperature will always have the same value:
[tex]\frac{V}{T} =k[/tex]
Assuming you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, if you vary the volume of gas to a new value V2, then the temperature will change to T2, and it will hold:
[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
In this case:
V1= 20 LT1= 100 °CV2= 40 LT2= ?Replacing:
[tex]\frac{20}{100} =\frac{40}{T2}[/tex]
Solving:
[tex]T2=\frac{40}{\frac{20}{100} }[/tex]
T2=200 °C
The new temperature of the gas is 200 Celsius degrees.
Answer:
473°C
Explanation:
We'll begin by analysing what was given from the question. This is illustrated below:
Initial temperature (T1) = 100°C
Initial volume (V1) = 20 L
Final volume (V2) = 40 L
Final temperature (T2) =?
Next, we shall be converting the temperature in celsius to Kelvin temperature. This is illustrated below:
Temperature (Kelvin) = temperature (celsius) + 273
Initial temperature (T1) = 100°C = 100°C + 273 = 373K
Next, we shall obtain the new temperature by applying the Charles' law equation. This is illustrated below:
V1/T1 = V2/T2
20/373 = 40/T2
Cross multiply to express in linear form
20 x T2 = 373 x 40
Divide both side by 20
T2 = (373 x 40) /20
T2 = 746K
Next, we shall be converting the new temperature obtained from Kelvin to celsius temperature. This is illustrated below:
Temperature (celsius) = Temperature (Kelvin) - 273
Temperature (celsius) = 746K - 273
Temperature (celsius) = 473°C
A catalyst:
A. Increases the energy of the activated complex
B. decreases the ∆H of the reaction
C. Decreases the energy of the reactants
D. Decreases the activation energy of the reaction
Answer:
D
Explanation:
well, just need to remember
Answer:
Catalyst decreases activation energy
Explanation:
Consider the attached diagram and note the annotation => top of transition diagram for catalyzed reaction is lower than uncatalyzed reaction.