Answers
Answer:
Airbags:
" As the airbags comes in inbuilt form these days in most of the cars, as they fulfill the safety concerns of the passengers and make it sure that non of the individuals gets hurt in any accident faced during the travel."
Angle of Deployment:As the airbags will only deploy in the specific conditions provided, as the car must be speed over about the 25 km/hr and the accident must be more like a head-on-collision making the airbags to deploy. Or else if the car experiences an side wise crash with any other entity then it will never deploy in that case.
Related Questions
Read this passage from Beowulf, in which Wiglaf, one of Beowulf's men, speaks to his companions as Beowulf battles the dragon. Wiglaf then joins Beowulf and addresses him. “I remember the time when, tasting the mead-cup, We promised in the hall the lord of us all Who gave us these ring-treasures, that this battle-equipment, Swords and helmets, we’d certainly quite him, Should need of such aid ever befall him: How we have forfeited our liegelord’s confidence! In the war-band he chose us for this journey spontaneously, Stirred us to glory and gave me these jewels, Since he held and esteemed us trust-worthy spearmen, Hardy helm-bearers, though this hero-achievement Our lord intended alone to accomplish, Ward of his people, for most of achievements, Doings audacious, he did among earth-folk. Our lord is in sore need of us. The day is now come when the ruler of earthmen Needeth the vigor of valiant heroes: Let us wend us towards him, the war-prince to succor, While the heat yet rageth, horrible fire-fight.” ... Through the bale-smoke he stalked then, Went under helmet to the help of his chieftain, Briefly discoursing: “Beowulf dear, Perform thou all fully, as thou formerly saidst, In thy youthful years, that while yet thou livedst Thou wouldst let thine honor not ever be lessened. Thy life thou shalt save, mighty in actions, Atheling undaunted, with all of thy vigor; The monster advances on them. I’ll give thee assistance.” Complete the following sentences based on your reading of the passage. In his speech to his companions, Wiglaf . Throughout this passage, Wiglaf is presented as .
Answers
1. encouraging them to act and unite
2. valiant and courageous
Answer:
1. 3) urges them to remember their duty and 2. 1) a model of loyalty are the correct answers.
Explanation:
In the first question, Wiglaf tries to convince his mates not to give up and to help his lord and also remembering what their intention was. Beowulf is supposed to receive help because he is old and he cannot deal with the monster by himself anymore, so Wiglaf is there because of that.
In the second one, it is seen that Wiglaf is the only one who doesn't give up on Beowulf, even when Beowulf is about to die after the fight with the dragon and Wiglaf kills it as a maximum expression of his loyalty.
The type of interference that increases the energy of the resulting wave is called interference. The type of interference that results in a loss of energy is called interference.
Answers
The type of interference that increases the energy of the resulting wave is called constructive interference. The type of interference that results in a loss of energy is called destructive interference.
When two or more waves are in the same medium, they can cross at a given point, where interference happens. When the two waves are in phase, the resulting amplitude in the point of interference is maxed. This is called constructive interference.
When the two waves are in opposing phases, the resulting amplitude in the point of interference is minimized. This is called destructive interference.
Have a nice day!
Answer:
constructive + destructive.
Explanation:
edge 22.
a body of mass 5kg falls from height of 10m above the ground what kinetic energy of the body before it strike the ground
Answers
GPE = mgh
GPE = 5kg x 9.8m/s^2 x 10m
GPE = 490 J
Kinetic Energy = 490 J
(This is assuming that gravitation field strength (g) is 9.8m/s^2, sometimes you may round this to 10m/s^2, therefore making the final result:
Kinetic energy = 500 J)
What are the three longest wavelengths for standing waves on a 280-cm-long string that is fixed at both ends? enter your answers numerically separated by commas?
Answers
[tex]\lambda_n=\frac{2L}{n}; n=1,2,3,4,5,...[/tex]
Where L is the length of a string and n is the number of nodes of the standing wave.
From this formula, we see that the more nodes you have the lower your wavelength is.
We need to calculate wavelengths for n=1, n=2, and n=3.
[tex]\lambda_1=\frac{2L}{1}=560$cm\\ \lambda_2=\frac{2L}{2}=280$cm\\ \lambda_3=\frac{2L}{3}=186.67$cm\\[/tex]
Which statement best describes a risk associated with using radioisotopes in nuclear reactors? A Radioisotopes are very expensive and do not produce the amount of energy that coal and oil produce. B If the radiation were to leak out of the reactors, it could produce an abundance of new plants and organisms. C Radioisotopes are extremely difficult to obtain and can only be retrieved from the Sun. D If the radiation were to leak out of the reactors, it could cause significant damage to living organisms.
Answers
D If the radiation were to leak out of the reactors, it could cause significant damage to living organisms.
In fact, ionizing radiation that leaks out from nuclear reactor is able to damage the DNA of living organisms, causing mutations and/or diseases like cancer.
The most accurate description of a risk with using radioisotopes in nuclear reactors is the potential for radiation to leak and cause significant harm to living organisms which is described in option D. This includes the possibility of serious malfunctions in cell processes and the challenge of managing high-level radioactive waste.
The statement that best describes a risk associated with using radioisotopes in nuclear reactors is D: If the radiation were to leak out of the reactors, it could cause significant damage to living organisms. Radioactive emissions from radioisotopes can fragment or ionize molecules, which leads to the production of highly reactive ions and molecular fragments. This damage to biomolecules can cause disruptions in cell processes, leading to illness or death. Accidents or leaks from nuclear reactors can also result in the exposure of these radioisotopes to the environment, affecting humans, animals, and the ecosystem.
Moreover, the disposal of high-level radioactive waste generated from spent nuclear fuel is a significant concern. It presents long-term risks due to the potential leakage of radiation into the environment and the complex and costly processes required for safe disposal. Hence, although nuclear energy is a potent source without greenhouse gas emissions, the risks involving radiation leaks and waste management are genuine concerns.
A 2.61-kg mass is pushed against a horizontal spring of force constant 23.3 n/cm on a frictionless air table. the spring is attached to the tabletop, and the mass is not attached to the spring in any way. when the spring has been compressed enough to store 10.7 j of potential energy in it, the mass is suddenly released from rest.
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What is the correct displacement for the following vectors: 4km south, 2 km north, 5 km south, and 5 km north ?
Answers
you get 2 km south .
Answer:
2 km south
Explanation:
In order to calculate this you just have to have in mind that your starting point will be 0, and as south and north are contrary, one of the will benegative, in this case we will take south as negative, so lets begin:
-4 km south
+2 km north
-5 km south
+5 km north
This equals -2 km, since it is negative we know that it´s south, so the displacement after all will be 2 kilometers south from the starting point.
———- muscle tissue is found in the visceral
Rough
Cardiac
Skeletal
Smooth
Answers
A mass m = 14 kg is pulled along a horizontal floor, with a coefficient of kinetic friction μk = 0.08, for a distance d = 7.8 m. then the mass is continued to be pulled up a frictionless incline that makes an angle θ = 30° with the horizontal. the entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of θ = 30° (thus on the incline it is parallel to the surface) and has a tension t = 32 n. 1) what is the work done by tension before the block gets to the incline? j 2) what is the work done by friction as the block slides on the flat horizontal surface? j 3) what is the speed of the block right before it begins to travel up the incline? m/s 4) how far up the incline does the block travel before coming to rest? m 5) what is the work done by gravity as it comes to rest? j 6) during the entire process, the net work done on the block is: positive negative zero
Answers
The work done by tension is zero. The work done by friction is negative. The net work done is positive.
Explanation:1) The work done by tension before the block gets to the incline is zero because the tension force is acting perpendicular to the displacement.
2) The work done by friction as the block slides on the flat horizontal surface is negative because the friction force is acting opposite to the displacement.
3) The speed of the block right before it begins to travel up the incline can be calculated using the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.
4) The distance up the incline that the block travels before coming to rest can be calculated using the work-energy theorem and the work done by friction.
5) The work done by gravity as the block comes to rest is zero since there is no displacement in the vertical direction.
6) The net work done on the block during the entire process is positive.
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A force of 230 N applied on a hydraulic lift raises an automobile weighing 6500 N. If the applied force is exerted on a 7.0 m^2 piston, what is the area of the piston beneath the automobile?
a.
2.0 x 10^2 m^2
b.
4.0 m^2
c.
0.25 m^2
d.
0.0050 m^2
Answers
Pressure = Force/Area
Let the area of the piston beneath the automobile be A. (230/7) = (6500/A) A = 197.826 m^2 or 2.0 x 10^2 m^2 if your rounded it off to the nearest hundreds.
Answer:
197.83 m^2
Explanation:
F = 6500 N, A = ?
f = 230 N, a = 7 m^2
Let the area of piston beneath the automobile is A.
By use of Pascal's law
F / A = f / a
6500 / A = 230 / 7 A = 197.83 m^2
A wheel rotates clockwise 10 times per second. what is its angular speed answer
Answers
The angular speed of a wheel that rotates clockwise 10 times per second is 20π rad/s. The direction of this rotational movement is determined by the right-hand rule used in physics and engineering. It is important to note that if the angular velocity is not constant, then the system has an angular acceleration.
Explanation:The question is asking about the angular speed of a wheel that rotates clockwise 10 times per second. In physics, angular speed is defined as the measure of how quickly an object moves through an angle. It is calculated by dividing the number of rotations or revolutions by the time period. In this case, the wheel rotates 10 times per second, which is the same as making 10 complete revolutions each second. We know that one complete revolution (360 degrees) is equivalent to 2π radians, so the angular speed in radians per second would be 10 * 2π, which is equal to 20π rad/s.
The concept of angular speed is often used in physics and engineering to describe the motion of objects rotating around an axis. The direction of angular velocity is determined by the right-hand rule. The right-hand rule is such that if the fingers of your right hand wrap counterclockwise from the x-axis (the direction in which increases) toward the y-axis, your thumb points in the direction of the positive z-axis (Figure 10.5). An angular velocity that points along the positive z-axis therefore corresponds to a counterclockwise rotation, whereas an angular velocity that points along the negative z-axis corresponds to a clockwise rotation. If the system's angular velocity is not constant, then the system has an angular acceleration.
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"explain why the orbital radius and the speed of a satellite in circular orbit are not independent"
Answers
[tex]\frac{mv^2}{r}=G\frac{mM}{r^2} \\ v^2=G\frac{M}{r}\\ v=\sqrt{G\frac{M}{r}[/tex]
This relationship tells closer the closser your orbit is to the surface of the planet the faster you have to go. Which makes sense because the closer you are to the planet the stronger gravitational force gets.
You drive a 6,000 kg boat due north, while the wind exerts a force of 600 N due south and the water exerts a resistive force of 1,200 N due south. The generated force by the boat’s engines is 4,200 N. Find the magnitude and direction of the boat’s acceleration.
Answers
[tex] F_{net} =(mass)(acceleration)[/tex]
Since what we are looking for is acceleration, we need to tweak our formula to derive our formula for acceleration.
[tex]acceleration = F_{net}/mass [/tex]
Our only problem is we do not have the value of the net force yet, but we can do so with the given presented.
Let's first wake into account all the forces acting upon the object.
F1 = 600N South
F2 = 1,200 N South
F3 - 4,200 N North
Net Force is the sum of all forces acting on an object. But you need to take into account that the forces are not all going towards the same direction. In this case, there are forces that are going against each other.
Thinking about the Cartesian plane, if you count going downwards the values are negative and if you count going up, the numbers are positive. We can apply this to our scenario here.
South is negative and north is positive. Our Forces then will now be considered this way:
F1 = -600N South
F2 = -1,200N South
F3 = 4,200N North
Now we can come up with our net force.
[tex] F_{net} = (-600N) + (-1,200N) + 4,200N[/tex]
[tex] F_{net} = (-1,800N) + 4,200N[/tex]
[tex] F_{net} = 2,400N[/tex]
Our net force is equal to 2,400N. It is positive so the direction is North.
Since we have our net force, we can now solve for acceleration.
[tex]acceleration = F_{net}/mass [/tex]
[tex]acceleration = 2,400N/6,000kg [/tex]
[tex]acceleration = 0.40m/s^{2} [/tex]
So the boat is moving at [tex]0.40 m/ s^{2} [/tex] to the North.
An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 200 n. (a) what is the equivalent spring constant of the bow
Answers
[tex]F=kx[/tex]
Where
F = force
k = spring constant
x = displacement from initial position
We have information:
F=200N
x=0.4m
k=?
400=k*0.4
k=1000N/m
Problem 4: a long wire carries current towards east. a positive charge moves westward and just north from the wire. what is the direction of the force experienced by this charge?
Answers
The force experienced by a positively charged particle moving westward and just north of a wire with a current directed east will be downward, based on the right-hand rule of electromagnetism.
Explanation:The scenario described involves a current-carrying wire and the motion of a charged particle, both of which invoke the concept of the magnetic force as per the right-hand rule in electromagnetism. According to this rule, if we point the thumb of our right hand in the direction of the current (which in this case is east), and our fingers in the direction of the velocity of the positive charge (which is west), then the palm faces toward the direction of the force on a positive charge. Since the charge is moving just north of the wire, the magnetic field will be directed towards the earth's surface (downwards if we consider the conventional 3D coordinate system). Therefore, the resulting force experienced by the positively charged particle will be downward, towards the ground.
A car with a mass of 525kg is being pushed west (left) by a force of 375n from its engine. the coefficient of friction felt by the car is .0420.
a.calculate the force weight of the car.
b.calculate the force friction acting on the car.
c.what is the net force acting on this car?
d.calculate the acceleration of the car.
Answers
Explanation:
It is given that,
Mass of the car, m = 525 kg
Applied force, F = 375 N
The coefficient of friction felt by the car is 0.42, [tex]\mu=0.42[/tex]
(a) The weight of the car is given by :
[tex]W=mg[/tex]
[tex]W=525\times 9.8[/tex]
W = 5145 N
(b) The force of friction acts in the opposite direction of motion. It can be calculated as :
[tex]f=\mu mg[/tex]
[tex]f=0.42\times 5145[/tex]
f = 2160.9 N
(c) Here, the force of friction is greater than the applied force. As a result, the ball will not moves. So, the net force acting on this car is 0.
(d) As the net force acting on the car is 0. There will be no acceleration in the car.
Final answer:
a. The force weight of the car is 5145 N. b. The force friction acting on the car is 216.09 N. c. The net force acting on the car is 158.91 N. d. The acceleration of the car is 0.714 m/s².
Explanation:
a. To calculate the force weight of the car, we can use the formula:
Force weight = mass * acceleration due to gravity
Given that the mass of the car (m) is 525 kg and the acceleration due to gravity (g) is 9.8 m/s², we can substitute these values into the formula:
Force weight = 525 kg * 9.8 m/s² = 5145 N
So, the force weight of the car is 5145 N.
b. To calculate the force friction acting on the car, we can use the formula:
Force friction = coefficient of friction * force weight
Given that the coefficient of friction (µ) is 0.0420 and the force weight is 5145 N, we can substitute these values intothe formula:
Force friction = 0.0420 * 5145 N = 216.09 N
So, the force friction acting on the car is 216.09 N.
c. The net force acting on the car can be calculated by subtracting the force friction from the force applied by the engine:
Net force = force applied - force friction
Given that the force applied by the engine is 375 N and the force friction is 216.09 N, we can substitute these values into the formula:
Net force = 375 N - 216.09 N = 158.91 N
So, the net force acting on the car is 158.91 N.
d. To calculate the acceleration of the car, we can use Newton's second law of motion:
Force = mass * acceleration
Given that the force applied by the engine is 375 N and the mass of the car is 525 kg, we can substitute these values into the formula:
375 N = 525 kg * acceleration
Solving for acceleration:
acceleration = 375 N / 525 kg = 0.714 m/s²
So, the acceleration of the car is 0.714 m/s².
While at the beach, Sam and Sal recorded the temperatures on land and at sea. They discovered that at night the ocean air temperature was higher than the temperature over land. During the night, which direction will the wind MOST LIKELY blow?
Answers
the air over the ocean will rise, and the air from the land will
slip in under it.
The wind will blow FROM the land out TO the ocean.
Answer: From land towards sea
Explanation:
Land breeze occurs at night in coastal regions. At night, the land cools down faster a compared to water in the sea. Thus, the air above the sea is less dense and thus, has low air pressure as compared to air over land. Thus, the wind would blow from land towards sea during night. This is known as land breeze.
In an industrial process, nitrogen is heated to 500 k at a constant volume of 1 m3 . the gas enters the container at 300 k and 100 atm. the mass of the gas is 92.4 kg. use the van der waals equation to determine the approximate pressure of the gas at its working temperature of 500 k.
Answers
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The peak intensity of radiation from Mars is about 14,000 nm. What is the average surface temperature of Mars rounded to the nearest whole number?
Answers
blablabla
207 K
406 K
4,857 K
Mars does not emit radiation.
Then the answer is 207 K.
Answer:
T = 206 K
Explanation:
As we know by Wein's law of displacement that if we draw all radiations intensity with all possible wavelengths radiated from the object then the wavelength corresponding to maximum intensity of radiation is inversely dependent to the absolute temperature of the object.
So here we can say
[tex]\lambda = \frac{b}{T}[/tex]
here we know
b = Wein's constant
[tex]b = 2.89 \times 10^{-3}[/tex]
now we have
[tex]\lambda = 14000 nm[/tex]
from above equation
[tex]14000 \times 10^{-9} = \frac{2.89 \times 10^{-3}}{T}[/tex]
[tex]T = 206 K[/tex]
when a the irregularities of one surface come into contact with those of another surface ,occurs
Answers
A 2.8 kg block is dropped from rest from a height of 4.5 m above the top of the spring. when the block is momentarily at rest, the spring is compressed by 25.0 cm. what is the speed of the block when the compression of the spring is 15.0 cm?
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what will most likely happen in the absence of a vacuole photosynthesis will not take place genetic information will not be transmitted by the cell energy will not be released during cellular respiration the cell will not store food water nutrients and waste
Answers
Answer:
D) The cell will not store food water nutrients and waste
Photosynthesis in plants takes place to synthesis food and energy. In the absence of this process, plants cannot store food and nutrients .
What is photosynthesis ?Photosynthesis is a biochemical process takes place in plants to synthesis chemical energy in the form of glucose by the aid of light energy. The green pigment in leaves called chlorophyll helps to absorb sufficient light energy for this process.
In a photosynthetic reaction, water and carbon dioxide combines to form oxygen gas and glucose. This glucose is the source of energy in plants. The oxygen gas released by photosynthesis is used by animals for respiration.
If photosynthesis does not taking place, plants fails to synthesis their food which further affect the cellular respiration as well. Therefore, option d is correct.
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Loni makes a diagram to help organize what she has learned about the gas laws.
Which label belongs in the region marked X?
involves changes in temperature
has a constant volume
shows an inversely proportional relationship
does not describe pressure changes
Answers
This question is based on Boyle's law and Charles' law.
As per Boyle's law the volume of a given mass of a gas is inversely proportional to the applied pressure at constant temperature. Mathematically it can be written as
[tex]P\ \alpha \frac{1}{V}[/tex] [at constant T and n]
Charles'law: It states that at constant pressure the volume of a given mass of a gas increases or decreases by 1/273 th of its volume at zero degree celsius for every 1 degree centigrade rise or fall of temperature.One may say that volume is directly proportional to temperature. Mathematically it can be written as
V∝T [at constant P and n]
Here P,V,T and n stand for pressure,volume,temperature and number of moles respectively.
In the diagram given in the question the point X is present in the region where Boyle's law is obeyed.Hence the correct option will be the third one which depicts the presence inverse relationship which is true for pressure and volume at constant temperature.
A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the electric field?
Answers
[tex]F=qE[/tex]
In our problem, we know the magnitude of the charge ([tex]q=6.0 \cdot 10^{-4}C[/tex]) and of the force ([tex]F=4.5 \cdot 10^{-4}N[/tex]), so we can find the intensity of the electric field:
[tex]E= \frac{F}{q}= \frac{4.5 \cdot 10^{-4}N}{6.0 \cdot 10^{-4}C}=0.75 NC^{-1} [/tex]
The strength of an electric field (E) can be determined using the formula:
[tex]\[ E = \frac{F}{q} \][/tex]
where:
- [tex]\( E \)[/tex] is the electric field strength,
- [tex]\( F \)[/tex] is the force experienced by the charge,
- [tex]\( q \)[/tex] is the magnitude of the charge.
In this case, the given values are:
- [tex]\( F = 4.5 \times 10^{-4} \, \text{N} \) (force)[/tex],
- [tex]\( q = 6.0 \times 10^{-4} \, \text{C} \) (charge)[/tex].
Now, plug these values into the formula:
[tex]\[ E = \frac{4.5 \times 10^{-4} \, \text{N}}{6.0 \times 10^{-4} \, \text{C}} \][/tex]
[tex]\[ E = \frac{4.5}{6.0} \, \text{N/C} \][/tex]
[tex]\[ E = 0.75 \, \text{N/C} \][/tex]
Therefore, the strength of the electric field is [tex]\(0.75 \, \text{N/C}\)[/tex].
A satellite of mass 5420 kg orbits the earth and has a period of 6560 s.determine the radius of its circular orbit.
Answers
Final answer:
To determine the radius of the satellite's circular orbit, use Kepler's third law.
Explanation:
To determine the radius of the satellite's circular orbit, we can use Kepler's third law, which states that the period of an orbit is related to the radius of the orbit. The formula for Kepler's third law is:
T² = (4π²*r³) / (G*M)
Where T is the period, r is the radius, G is the gravitational constant, and M is the mass of the Earth. We are given the period of the satellite (6560 s) and the mass of the satellite (5420 kg), so we can solve for the radius using the formula.
T² = (4π²*r³) / (G*M)
6560² = (4π²*r³) / (6.67 x 10⁻¹¹ * 5.97 x 10²⁴)
Using this equation, we can solve for r, the radius of the satellite's circular orbit.
what nuclear physics means?
Answers
On a particle level, what happens when thermal conduction occurs within a solid?
Answers
Final answer:
Thermal conduction in solids occurs as atoms and molecules rapidly move or vibrate, transferring kinetic energy to neighboring particles, and through movement of electrons, facilitating heat transfer without the mass flow characteristic of convection.
Explanation:
On a particle level, when thermal conduction occurs within a solid, rapidly moving or vibrating atoms and molecules transfer some of their kinetic energy to adjacent particles. This is the principal means for heat transfer within a solid, with the close fixed spatial relationships between atoms in a solid facilitating this transfer by vibration. Heat is also transferred by the movement of electrons from one atom to another. Unlike convection which occurs in fluids, heat transfer by conduction in solids does not involve large-scale flow of matter.
For example, the heat from an electric burner transfers to the bottom of a pan via conduction. The hot surface causes the atoms in the pan to vibrate more energetically, which then collide with neighboring atoms, spreading the heat throughout the pan. Conductive heat transfer efficiency is affected by the temperature difference, size and thickness of the material, as well as its thermal properties.
A solid ball, a solid disk, and a hoop, all with the same mass and the same radius, are set rolling without slipping up an incline, all with the same initial linear (translational) speed. which goes farthest up the incline?
Answers
The solid sphere will go the farthest up the incline because it has the smallest moment of inertia, allowing for a larger proportion of kinetic energy to be used in translational motion compared to a solid disk and a hoop with the same mass and radius.
The situation involves a solid ball, a solid disk, and a hoop rolling up an incline which raises a fascinating question about rotational motion and energy conservation in physics. They all have the same mass, radius, and initial translational speed, so the one that will go farthest up the incline is the one with the smallest rotational inertia relative to its mass. When an object rolls without slipping, kinetic energy is divided between translational motion (linear movement) and rotational motion (spinning).
The moment of inertia (I) characterizes an object's resistance to changes in its rotational motion. The moment of inertia is different for each object:
For a hoop, I = MR²
For a solid disk, I = (1/2)MR²
For a solid sphere, I = (2/5)MR2²
Since all objects have the same mass (M) and radius (R), the one with the smallest 'I' will have the most translational kinetic energy, and therefore, it will go the farthest up the incline before stopping. The solid sphere has the smallest moment of inertia, meaning it has a higher proportion of its kinetic energy in translational form than the disk and the hoop. As such, the solid sphere will reach the highest point on the incline before coming to a stop.
A horizontal line above the time axis of a speed vs. time graph means an object is ___.
a zero
b constant
c decreasing
Answers
A horizontal line on a speed vs. time graph signifies that the object is maintaining a constant velocity because there is no change in speed over time.
A horizontal line above the time axis of a speed vs. time graph indicates that an object is travelling at a constant velocity. This is because the speed does not change over time, and thus the graph shows a straight line parallel to the time axis, with no slope. When examining an acceleration vs. time graph, a horizontal line at zero would mean the acceleration is zero, which aligns with the object maintaining a constant speed, as acceleration is the rate of change of velocity.
A 8.0 n force acts on a 0.70-kg object for 0.50 seconds. by how much does the object's momentum change (in kg-m/s)? (never include units in the answer to a numerical question.)
Answers
[tex]F=ma[/tex]
Rewriting the acceleration as the increment of velocity [tex]\Delta v[/tex] in a time [tex]\Delta t[/tex]: [tex]a= \frac{\Delta v}{\Delta t} [/tex], F becomes
[tex]F=m \frac{\Delta v}{\Delta t} [/tex]
But given the definition of momentum: [tex]p=mv[/tex], then [tex]m \Delta v[/tex] represents the momentum change. So we can rewrite F as
[tex]F= \frac{\Delta p}{\Delta t} [/tex]
And re-arranging the formula we can calculate the value of the change in momentum:
[tex]\Delta p = F \Delta t=(8.0 N)(0.50 s)=4 kg m/s[/tex]
Given the force acting on the object, the change in its momentum is 4kg.m/s.
Force; [tex]F = 8.0N = 8 kg.m/s^2[/tex]Mass; [tex]m = 0.7kg[/tex]Time, [tex]t = 0.50s[/tex]To determine the object's change in momentum, we use the Impulse Momentum Theorem:
The impulse applied to a body or matter is equal to the change in its momentum
Impulse = Change in Momentum
[tex]Impulse = F * dt[/tex]
Where F is the force applied and [tex]dt[/tex] is the elapsed time
Hence
[tex]Change \ in \ Momentum = F * dt[/tex]
We substitute our given values into the equation
[tex]Change \ in \ Momentum = 8 kg.m/s^2 * 0.50s\\\\Change \ in \ Momentum =4kg.m/s[/tex]
Therefore, given the force acting on the object, the change in its momentum is 4kg.m/s.
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