The velocity of the second ball is 1.2 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
[tex]p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2[/tex]
where:
[tex]m_1 = 3.3 kg[/tex] is the mass of the first ball
[tex]u_1 = 1.3 m/s[/tex] is the initial velocity of the first ball
[tex]v_1 = 0[/tex] is the final velocity of the first ball
[tex]m_2 = 3.6 kg[/tex] is the mass of the second ball
[tex]u_2 = 0[/tex] is the initial velocity of the second ball
[tex]v_2[/tex] is the final velocity of the second ball
Re-arranging the equation and solving for v2, we find the velocity of the second ball after the collision:
[tex]v_2 = \frac{m_1 u_1}{m_2}=\frac{(3.3)(1.3)}{3.6}=1.2 m/s[/tex]
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In the following reaction, what element is made?
Answer:
The correct answer is option A).
Explanation:
The given reaction is a nuclear reaction.
We know that in a nuclear reaction , the indices on both the sides are conserved , i.e the total number of nucleons (A) and the total number of protons (Z) should be the same on the L.H.S and the R.H.S-
Total number of nucleons on L.H.S = 241+4 = 245.
Total number of nucleons on R.H.S = A+1
∴ A+1 = 241+4 = 245
∴ A=244
Total number of protons on L.H.S = 95+2 = 97.
Total number of protons on R.H.S = Z+0
∴ Z+0 = 97.
Z = 97.
Thus the element having A=244 and Z=97 should be the product of this nuclear reaction.
∴ ₉₇²⁴⁴Bk (option A) should be the required product of this reaction.
If the skater has more mass of 60kg, what is her gravitational potential energy at the top of the 4m high half pipe?
2352 Joules is the “Gravitational potential energy” that a skater has.
Explanation:
"Gravitational potential energy" of an object is defined as the energy stored in the object which is at a height. Everybody at a height has some energy that is calculated by using the potential energy formula. Mathematically, "Gravitational potential energy" (GPE) is mass (m) times acceleration due to gravity (g) times height (h) of an object. Therefore, GPE = m × g × h.
From the given question,
Mass of the skater is 60 kg
The height at which skater is located is 4 m
“g” is acceleration due to gravity 9.8 [tex]m/s^2[/tex]
Substitute the given values in the GPE = m × g × h
Gravitational potential energy = 60 × 9.8 × 4
Gravitational potential energy = 2352 J .
How much tension must a rope withstand if it is used to accelerate a 1700-kg car
horizontally at 0.50 m/s^2 ? Ignore friction.
What tension would be required to accelerate
it vertically at the same rate?
Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N what is the coefficient of friction between a walk in the ground
The coefficient of friction is 0.363
Explanation:
There are two forces acting on the scooter in the horizontal direction:
- The applied force, F = 1850 N, forward
- The frictional force, [tex]F_f[/tex], backward
Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:
[tex]F-F_f = 0\\F_f = F = 1850 N[/tex]
The frictional force can be written as
[tex]F_f = \mu R[/tex] (1)
where
[tex]\mu[/tex] is the coefficient of friction
R is the normal reaction of the ground on the scooter
For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:
[tex]R = W = mg[/tex]
where
m = 520 kg is the mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Substituting into (1),
[tex]F_f = \mu mg = 1850 N[/tex]
and solving for [tex]\mu[/tex],
[tex]\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363[/tex]
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d) A wire carrying a current of 10A and 2m in length is placed in a field of flux density
0. 15T. Calculate the force on the wire if it is placed:
i) At 300
to the field
ii) Along the field (4 mks)
1) The force on the wire is 1.5 N
2) The force on the wire is zero
Explanation:
1)
The force experienced by a current-carrying wire in a magnetic field is given by
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the magnetic flux density
[tex]\theta[/tex] is the angle between the direction of the wire and of the field
In this part of the problem we have
I = 10 A
L = 2 m
B = 0.15 T
[tex]\theta=30^{\circ}[/tex]
Substituting, we find
[tex]F=(10)(2)(0.15)(sin 30^{\circ})=1.5 N[/tex]
2)
As before, the force experienced by the wire is
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the magnetic flux density
[tex]\theta[/tex] is the angle between the direction of the wire and of the field
In this case, however, the angle between the wire and the field is
[tex]\theta=0^{\circ}[/tex]
And therefore
[tex]sin 0^{\circ} = 0[/tex]
which means that the wire does not experience any force. In fact, the force experienced by the wire is zero when the wire is parallel to the field (such as in this case) and maximum when the wire is perpendicular to the field.
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A plank rests on top of the axles of two identical wheels. Each wheel's outer radius is 0.25 meters and each wheel's axle has radius 0.05 meters. If the wheels roll 1.00 meter from their original position, how much does the plank move from its original position?
Assume that there is no slipping anywhere, and that the plank does not tip.
Answer:
0·2 m
Explanation:
The distance by which the axle of the wheel is rotated must be the same as the distance travelled by the plank, as it is mentioned that there is no slipping anywhere because if the distance is not same then there will be slipping between them as friction will be acting
Let the angle by which the wheel is rotated when it rolls by 1 m be β
∴ 1 = (outer radius of the wheel) ×β
1 = 0·25 × β
∴ β = 4 radians
The angle by which the wheel's axle is rotated will be the same as the angle rotated by the wheel as both are attached
∴ Wheel's axle will also be rotated by an angle β = 4 radians
Distance by which the axle of the wheel will get rotated = (radius of wheel's axle) × β
= 0·05 × 4 =0·2 m
∴ Plank will move from original position by 0·2 m
3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a hill. Describe the action and reaction forces that cause the locomotive to move up the hill, such as the reaction force and gravity.
This question has been posted before put the answers were not correct.
Answer:
Action - Pulling up the train.
Reaction - Friction on the locomotive
Explanation:
Locomotive is pulling the train upwards ,
Which is the action force applied by the locomotive,
As a reaction locomotive will be pulled by the train which is the reaction of pulling
Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.
For train action is pulling up by locomotive and reaction will be friction acting on it downwards.
Which of these is a landform created due to erosion by glaciers? Delta Horn Sandbars Spit
Answer:
The answer is option B, horn.
Explanation:
The landform horn was formed because when glaciers erode down to form a sharp peak which is called a horn. All of the other options are false because none of those land forms are formed because of the erosion of glaciers
Answer:
i think a delta
Explanation:
I might be wrong but I think it leaves behind a delta.
Can someone explain the gas laws?
* ex...what happens to pressure if volume and temp. increase*
Explanation:
Use the Ideal Gas Law:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is the universal gas constant,
and T is absolute temperature.
First, identify which variables in the problem are constant (note that R is always a constant).
Next, solve for the constants and use that equation to write a proportion.
Finally, plug in the given values and solve for the unknown variable.
For example, if n and R are the constants:
nR = PV/T
Therefore:
P₁V₁/T₁ = P₂V₂/T₂
if you travel for three hours of a speed of 30 km/h, how far will you go?
Answer:
90km
Explanation:
every hour you travel 30km and you are traveling 3 hours 30×3
how does mass speed and gravity affect potential and kinetic energy
Answer:
The formula for potential energy is, P.E = mgh joules
The formula for kinetic energy is K.E = ½ mv² joules
Explanation:
The total mechanical energy of the system is the sum of the K.E and the P.EThe potential energy of the system is associated with the position of the object from the ground.The formula for potential energy is,P.E = mgh joules
The kinetic energy of the object is associated with the velocity of the object.The formula for kinetic energy is,K.E = ½ mv² joules
From the above equation, it is clear that the P.E is dependent on the mass and acceleration due to gravity. The P.E is the product of mass, acceleration due to gravity and height of the object from the ground.Whereas the K.E is dependent on the mass and the velocity of the object. The kinetic energy does not depend on the acceleration due to gravity.In which situation is the object experiencing unbalanced forces?
Question 1 options:
A. A box resting on a horizontal floor
B. A car slowing as it reaches a stop light
C. A car with its cruise control set to 50 mph
D. A rocket sitting on the launch pad
B. A car slowing as it reaches a stop light
Explanation:
According to Newton's second law, the net force exerted on an object is equal to the product between its mass and its acceleration:
[tex]F=ma[/tex]
where
F is the net force
m is the mass of the object
a is its acceleration
This means that when an object is experiencing unbalanced forces ([tex]F\neq 0[/tex]), it must have a non-zero acceleration. Therefore, let's analyze the different options:
A. A box resting on a horizontal floor --> FALSE. Here the acceleration is zero, so no unbalanced forces.
B. A car slowing as it reaches a stop light --> TRUE. Since the car is slowing down, its velocity is changing, so the acceleration is non-zero and there are unbalanced forces.
C. A car with its cruise control set to 50 mph --> FALSE. Here the velocity is constant, so no acceleration and no unbalanced forces.
D. A rocket sitting on the launch pad --> FALSE. Here the rocket is stationary, so no acceleration, and no unbalanced forces.
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An object experiences unbalanced forces when the resultant force on it is non-zero. A car slowing as it reaches a stop light experiences unbalanced forces due to the brakes exerting a force, causing it to decelerate. Hence, the correct answer is B. A car slowing as it reaches a stop light.
In the question, we are asked to determine in which situation an object is experiencing unbalanced forces. An object experiences unbalanced forces when the resultant force acting on it is non-zero, leading to a change in its motion. If we analyze the options given:
A box resting on a horizontal floor is not experiencing unbalanced forces, because it is at rest and there are no net forces acting to change its state of motion (assuming no frictional losses).A car slowing as it reaches a stop light is experiencing unbalanced forces because the brakes are exerting a force opposite to the direction of motion, causing the car to decelerate.A car with its cruise control set to 50 mph is travelling at a constant velocity, indicating that the forces are balanced.A rocket sitting on the launch pad is not experiencing unbalanced forces if it is stationary and not in the process of takeoff.Therefore, the correct answer is B. A car slowing as it reaches a stop light, because this is when it is experiencing a net force that is causing a change in its motion.
What is Snell law of refraction
Answer:
Snell's law tells us the degree of refraction and relation between the angle of incidence, the angle of refraction and refractive indices of given pair of media. We know that light experiences the refraction or bending when it travels from one medium to another medium. Snell's law predicts the degree of the bend.
Explanation:
Final answer:
Snell's law expresses the relationship between the incidence and refraction angles and the indices of refraction of two media, represented by the equation n₁ sin θ₁ = n₂ sin θ₂.
Explanation:
Snell's law describes the relationship between angles and indices of refraction when light passes from one transparent medium to another.
It is an essential concept in the study of optics and can be mathematically expressed as n₁ sin θ₁ = n₂ sin θ₂, where n₁ and n₂ are the refractive indices of the first and second medium, respectively, and θ₁ and θ₂ are the angles of incidence and refraction.
This law is named after the Dutch mathematician Willebrord Snell who described it in 1621, but it was also discovered by the Arabian physicist Ibn Sahl in the 10th century.
Through thorough experiments, it became evident that light rays change direction due to the differing speeds of light in various media, a concept Snell himself was not aware of but was able to confirm through the refractive indices.
what is the net force if you push a cart to the right with 5N of force, and a friend pushes the cart to the left with 5N of force?..
Answer: 0 newtons
Explanation: If you push a cart to the right with 5 newtons of force to the right and a friend pushes the cart 5 newtons to the left, there will be no motion.
To understand this further, take a look at the image I provided. I provided two arrows one of the left and on on the right. If two people are pushing on the cart with the same amount of force, the net force will be 0 so it will be a balanced force. When we have a balanced force, there's no motion.
if you are traveling at 75 km/h how long will it take to travel 32 km?
The time taken is approximately 26 minutes
Explanation:
The motion of the body in this problem is a uniform motion (= at constant velocity), therefore we can use the following equation:
[tex]v=\frac{d}{t}[/tex]
where
v is the speed
d is the distance covered
t is the time taken
In this problem, we have
v = 75 km/h is the speed
d = 32 km is the distance to be covered
Solving for t, we find the time needed:
[tex]t=\frac{d}{v}=\frac{32}{75}=0.43 h[/tex]
Converting into minutes,
[tex]t=0.43 h \cdot 60 = 25.8 min \sim 26 min[/tex]
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Allison needs to graph the yearly average snowfall in Alaska. She should use a:
A)bar graph
B)line graph
Answer: Line graph
Explanation:
Allison needs to graph the yearly average snowfall in Alaska. She should use a:
pie chart
pictograph
bar graph
line graph
A student rapidly rubs the palms of both hands
together, after eating lunch. Which sequence
correctly describes the energy transformations that
occur?
a. chemical mechanical heat
b. mechanical heat chemical
c. heat mechanical chemical
d. mechanical nuclear heat
Answer:
Option a
Explanation:
The action of the rapid rubbing of the hands are a result of chemical reaction and responses that takes place inside our body.
When we rub our hands together, that shows the mechanical motion of the body or we can say that while rubbing hands chemical energy gets converted to mechanical energy (here, Kinetic energy).
While rubbing, due to friction, heat is produced and hence we can say that this mechanical energy has transformed to heat energy.
Thus the conversion here is from chemical to mechanical to heat energy.
Which of the following properties did Rutherford use in his experiment?
A. the negative charge of the alpha particles and the random distribution of protons
B. the negative charge of the alpha particles and the positive charge of the gold foil
C. the positive charge of the alpha particles and the negative charge of the electrons
D. the positive charge of the electrons in a uniform negative charge
Answer:
(C) The positive charge of the alpha particles and the negative charge of the electrons are the properties Rutherford used in his experiment
Explanation:
In his scattering experiment, scientist Ernest Rutherford used the property of positively charged alpha particles and negatively charge electrons. He performed this experiment by passing some of the alpha particles through a gold foil. The result was that the some alpha particles scattered while some passed through the gold foil without collision.
He concluded that the alpha particles are centrally positively charged and needed a large amount repelling force. This experiment of Rutherford is also known as Rutherford model of atom. This experiment helped him in doing so many other discoveries.
Which statement is false?
O Preparations for future situations are helpful to avoid pressured situations.
Once you reach adulthood, you will not experience peer pressure.
Peer pressure is often thought of in negative terms even though it can be positive.
Answer:
Once you reach adulthood, you will not experience peer pressure.
Explanation:
We tend to believe that self-control comes from within, but many of our attitudes depend as much on friends and family as on ourselves. That's because at any stage of our life (even the adult stage) our friends and our family have the power to influence us, sometimes that influence is good and sometimes bad, it's up to us to reason about them.
The people around us have the power to make us fat, consume more alcohol, worry less about the environment and expose ourselves to the sun without proper protection, among many other things.
It is not simply about peer pressure, where you deliberately act in a certain way to suit the group. It is, in fact, largely an unconscious attitude. Without your awareness, your brain is constantly picking up cues from people around you to dictate your behavior. And the consequences can be serious.
Answer:
its B :)
Explanation:
Most of the Earth's volume is contained in the
A. mantle
B.
crust
C.
inner core
D.
outer core
Most of the Earth's volume is contained in the "mantle". The correct answer would be option (A).
What is a mantle?The mantle is a layer of semi-solid rock that lies between the Earth's thin crust and its liquid outer core. The mantle is approximately 2,900 kilometers (1,800 miles) thick and makes up about 84% of the Earth's total volume.
The crust, mantle, and core are the three coatings of the Earth. The crust is made up of minerals and solid rocks. The mantle lies under the crust and is largely made up of solid rocks and minerals, but it is punctured by pliable patches of semi-solid magma.
It is composed primarily of silicate rocks and is considered to be the source of the Earth's heat and most of its volcanic activity.
The mantle also plays a key role in plate tectonics, which is the theory that explains the movement of the Earth's continents and ocean floor.
Thus, the correct answer would be option (A) mantle.
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A roller coaster engineer is trying to design a new coaster to build at the theme park. The cars, when loaded with people, is expected to have a mass of 8000. He wants his roller coaster cars to be going 10 m/s when it reaches the bottom. Assuming that friction is negligible, how high up should the roller coaster start?
_________Number ___M___Units
Then Answer
Well, it turns out that friction is not negligible, the Engineer figured out that the car is going to lose 32000 Joules energy as it goes down the track. this means that he has to start up even higher. what is the actual starting height after taking into account the energy loss from friction?
__________Number _____M____Units
Thank you SOO much :D
1) The initial height of the roller coaster must be 5.1 m
2) The height of the roller coeaster must be 5.5 m
Explanation:
1)
We can solve this problem by using the law of conservation of energy.
In fact, in absence of frictional force, the total mechanical energy must be conserved, so we can write:
[tex]KE+PE = KE'+PE'[/tex]
where
KE = 0 is the initial kinetic energy, at the top (the car starts from rest, so it has zero speed and so zero kinetic energy)
PE = mgh is the initial potential energy, where
m = 8000 kg is the mass of the car
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
h is the initial height
[tex]KE'=\frac{1}{2}mv'^2[/tex] is the kinetic energy of the car at the bottom, where
v' = 10 m/s is the speed of the car at the bottom
PE' = 0 is the potential energy at the bottom (where h = 0)
Re-writing the equation with all the values and solving for h, we find the initial height of the track:
[tex]h=\frac{v^2}{2g}=\frac{10^2}{2(9.8)}=5.1 m[/tex]
2)
In this case, we also have to take into account the energy lost due to friction. So the equation of conservation of energy becomes
[tex]KE+PE = KE'+PE'+W[/tex]
where
W = 32,000 J is the work done by friction
Re-arranging the equation and solving again for h, we find:
[tex]mgh = \frac{1}{2}mv'^2 + W\\h=\frac{v^2}{2g}+\frac{W}{mg}=5.1+\frac{32,000}{(8000)(9.8)}=5.5 m[/tex]
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Bluetooth is a technology that allows wireless devices to communicate data and information to each other. For example, a wireless pair of headphones can play music from a smart phone without a physical connection. However, the technology must be low energy enough not to cause damage to the people using the device. Additionally, the wavelengths used in bluetooth technologies should not be visible. The waves associated with bluetooth technology are most similar to which wave type below?
A) X-rays
B) red light
C) radio waves
D) UV radiation
Answer: Option C. Radio waves
Explanation:
Bluetooth technology primarily uses radio waves, a type of low-energy and invisible electromagnetic radiation, to enable wireless communication between devices.
Explanation:Bluetooth is a technology that enables wireless devices to communicate with each other by transferring data and information. This is accomplished using low-energy radio waves. Among the wave types listed in your options, Bluetooth devices primarily use radio waves to establish communication. Radio waves are a form of electromagnetic radiation, similar to X-rays, red light and UV radiation, but are distinguished by their longer wavelength and lower frequency, which gives them their low energy characteristics. Because of their low energy, they are non-ionizing and safe to use. Also, radio waves are invisible to the human eye which meets the visibility requirement for Bluetooth technology.
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Which statements apply to theories? Check all that apply.
A theory is a factual statement.
B theory is well-tested and widely accepted.
C theory is an explanation.
D theory cannot be revised or replaced.
E theory can help predict future events.
the answer is b,c, and e
Answer:
BCE
Explanation:
You measure the voltage difference of a circuit to be 5 V and the resistance to be 1,000 ohms.
What is the current in the circuit?
Answer:
The current in the circuit will be [tex]5\times 10^{-3}\ Ampere[/tex].
Explanation:
Given:
Voltage difference = V = 5 V
Resistance = R = 1000 ohms
To Find:
Current, I = ?
Solution:
Ohm's Law:
Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.
i.e I ∝ V
∴ V = I × R
Where, I = current
V = voltage
R = resistance
Substituting the values of V and R we get
∴ 5 = I × 1000
[tex]I = \frac{5}{1000} \\I=0.005\ Ampere\\I=5\times 10^{-3}\ Ampere[/tex]
Therefore, the current in the circuit will be [tex]5\times 10^{-3}\ Ampere[/tex].
The current in the circuit can be found using Ohm's Law (I=V/R). The given values for voltage and resistance result in a current of 5 milliamperes.
Explanation:The subject matter in the question falls under the field of Physics, particularly Electricity. The problem is asking for the current in a circuit, based on given values for voltage and resistance. One can solve this by employing Ohm's Law, which describes the relationship between voltage (V), resistance (R), and current (I). Ohm's Law is represented by the formula I = V/R.
Substituting the given values into the formula, the current I is calculated as 5V / 1000Ω, which equals 0.005 Amperes, or 5 Milliamperes (mA). Thus, the current flowing in the circuit is 5 mA.
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A person runs 5 km North and then turns west and travels for 7 km then turn south for 2 km it takes a person 4 hours to make the journey what is the persons distance, speed, displacement and velocity
1) Distance: 14 km
2) Speed: 3.5 km/h
3) Displacement: 7.6 km at [tex]23.2^{\circ}[/tex] north of west
4) Velocity: 1.9 km/h at [tex]23.2^{\circ}[/tex] north of west
Explanation:
1)
Distance is a scalar quantity, and it corresponds to the total length of the path covered by an object during its motion, regardless of its direction.
Here we have the following motion:
[tex]d_{y1}=5 km[/tex] North
[tex]d_x = 7 km[/tex] west
[tex]d_{y2}=2 km[/tex] south
So, the distance covered is:
[tex]d=d_x + d_y = 5 + 7 +2 = 14 km[/tex]
And since it is a scalar, distance has no direction.
2)
Speed is a scalar quantity telling "how fast" an object is moving. It is calculated as:
[tex]speed=\frac{d}{t}[/tex]
where:
d is the distance
t is the time taken
In this problem, we have
d = 14 km (distance)
t = 4 h (time taken)
Substituting,
[tex]speed=\frac{14 km}{4 h}=3.5 km/h[/tex]
And since it is a scalar, it has no direction.
3)
Displacement is a vector quantity connecting the initial position to the final position of motion. The magnitude is the short distance in a straight line between the initial and final position of motion.
Here we have the following motions:
[tex]d_{y1}=5 km[/tex] North
[tex]d_x = 7 km[/tex] west
[tex]d_{y2}=2 km[/tex] south
So the net displacement in the north-south direction is
[tex]d_y = 5 - 2 = 3 km[/tex] North
[tex]d_x, d_y[/tex] are at right angle, so they form the sides of a right triangle, of which the hypothenuse corresponds to the displacement. Therefore, we can find the magnitude of the displacement by using Pythagorean's theorem:
[tex]d=\sqrt{d_x^2+d_y^2}=\sqrt{7^2+3^2}=7.6 km[/tex]
And the direction is given by
[tex]\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{3}{7})=23.2^{\circ}[/tex] north of west.
4)
Velocity is a vector quantity, given by:
[tex]velocity=\frac{d}{t}[/tex]
where
d is the displacement
t is the time taken
In this problem, we have
d = 7.6 km (displacement)
t = 4 h (time taken)
So, the velocity is
[tex]velocity=\frac{7.6 km}{4h}=1.9 km/h[/tex]
And being a vector, velocity has also a direction, which is the same of the displacement: so, [tex]23.2^{\circ}[/tex] north of west.
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Nichrome has a --------------melting piont
Answer:
Nichrome has __High__melting piont
Hope this helps
Answer:
high melting point
Nichrome is consistently silvery-grey in colour, is corrosion-resistant, and has a high melting point of about 1,400 °C (2,550 °F).
Explanation:
2057 Q.No. 9 a A typical car weighs about 1200 N. If the
coefficient of rolling friction is ur = 0.015. What horizontal
force is needed to make the car move with constant speed of
72 km/h on a level road? Also calculate the power developed
by the engine to maintain this speed.
Ans. 18 N, 360 W
Answer:
18N & 360W
Explanation:
Here,
Velocity of car (v) = 72 ∗ 1000 / 60∗60 = 20m/s
weight of car = 1200N
We have,
μr = Fs / R
Fs = μr ∗ R = 0.015 ∗ 1200 = 18N
Power developed by the engine = 18 ∗ 20 =360W
Hope this helps!!!A rock is dropped from a cliff.
What will eventually happen to the rock's motion?
A. Gravity will cause the rock to slow down before it reaches Earth.
B. Air resistance will cause the rock to accelerate as it falls.
C. The rock will continue falling until Earth exerts a contact force on the rock.
D. Friction will cause the rock to continue in its state of motion.
Answer:
C
Explanation:
What is used to measure heat?
change in temperature
constant temperature
constant specific heat
change in specific heat
Answer:
change in temperature
Answer:
Change in temperature
Explanation:
did this on edge yesterday and that was the answer
Increasing which two things would increase gravitational potential energy?
Answer:
Mass and height
Explanation:
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about [tex]9.8 m/s2.[/tex]
Which is represented as;
[tex]PE_g=mgh[/tex]
[tex]PE_g[/tex] stands for gravitational potantial energy,
m stands for mass of object,
g is the gravitational constant and
h is the height.
Here we see that mass of object and height is directly proportional to the gravitational potential energy.
That means increasing in mass and height will result in increasing gravitational potential energy.