An aircraft increases its speed by 2% in straight and level flight. If the total lift remains constant determine the revised CL as a percentage of its original value to three significant figure

Answer:

Explained below

Explanation:

Beats are interference pattern between two sounds of slightly different frequencies perceived as periodic vibration in volume whose rate is difference of the two.

Both octave and decibel are the terms of measurement.

Octave(In electronics) is a logarithmic unit for ratio between frequencies,with one octave corresponding to doubling of frequency. For example frequency one octave is from 40 Hz to 80 Hz.

Whereas decibel is a unit of sound intensity. It is one-tenth of A bel. In electronics it is used measure power level of an electrical signal by comparing it with given level of logarithmic scale.

Answer: False

Explanation: Horizontal-axis wind turbine is the major part of wind industry. Horizontal axis have rotating axis of wind turbine in horizontal direction.Horizontal wind produces more electricity from a particular amount of wind that is provided and thus is preferred more.

vertical-axis wind turbines have the rotational axis of the turbine in vertical or perpendicular direction and have easy installation even where wind conditions are not predictable and is lighter in weight but are not able to produce the large amount of electricity as compared to horizontal-axis wind turbine.

Thus the statement given is false.

Answer:

[tex]Q=7.3\times 10^{-3} m^3/s[/tex]

Explanation:

Given that

At top[tex]d_2=30 mm,P_2=860 KPa ,P_1=1000 KPa,d_1=85 mm[/tex]

[tex]\rho =900\dfrac{Kg}{m^3}[/tex]

We know that

[tex]\dfrac{P_1}{\rho g}+\dfrac{V_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{V_2^2}{2g}+Z_2[/tex]

[tex]A_1V_1=A_2V_2[/tex]

[tex]\frac{V_1}{V_2}=\left(\dfrac{d_2}{d_1}\right)^2[/tex]

[tex]\frac{V_1}{V_2}=\left(\dfrac{30}{85}\right)^2[/tex]

[tex]V_2=8.02V_1[/tex]

[tex]Z_2=12 sin60^{\circ}[/tex]

[tex]\dfrac{1000\times 1000}{900\times 9.81}+\dfrac{V_1^2}{2\times 9.81}+0=\dfrac{860\times 1000}{900\times 9.81 }+\dfrac{V_2^2}{2\times 9.81}+12 sin60^{\circ}[/tex]

So [tex]V_1=1.30[/tex]m/s

We know that flow rate Q=AV

[tex]Q=A_1V_1[/tex]

By putting the values

[tex]A_1=\dfrac{\pi}{4}d^2[/tex]

[tex]Q=7.3\times 10^{-3} m^3/s[/tex]

To find the flow rate we do not need the direction of flow,because we are just doing balancing of energy at inlet and at the exits of pipe.

If water is boiling at 130 degrees Celsius inside a pressure cooker, the pressure is approximately 2.7 atmospheres

To determine the pressure inside a pressure cooker where water is boiling at 130 degrees Celsius, we use the properties of water and its boiling point at various pressures.

For water, the pressure at which the boiling point is elevated to 130 degrees Celsius can be found using steam tables.

At 130 degrees Celsius, the saturation pressure of water is approximately 2.7 atmospheres (atm). This is equivalent to :

= 2.7 x 101.325 kPa

= 273.5775 kPa, or about 2.7 bar (since 1 bar = 100 kPa)

Answer:

option a is correct answer i.e. d = 1.6 mm

Explanation:

From conservation principle

force by jet = force required to hold the jet

force by the jet is written as

[tex]force  = \dot{m}(v_{1}-v_{2})\[/tex]

force required to hold the jet = 8N

[tex]\dot{m}(v_{1})\ = 8[/tex]

[tex]\dot{m}=0.13 kg/s[/tex]

[tex]v_{1} = 61.58 m/s[/tex]

we know that mass flow rate is given as

[tex]\dot{m}=\rho Av_{1}[/tex]

substituting value to get required  diameter of the nozzle

[tex]0.13=1000*\frac{\pi }{4}d^{2}*61.58[/tex]

d = 1.6 mm

Answer:

The air-standard assumptions are:

Answer:

The Biot number for this sphere is  0.03

Explanation:

Given data in equation

diameter (d) = 60 mm = 60/1000 = 0.06 m

heat transfer coefficient (h)  = 10 w/m²-K

thermal conductivity (K) = 20 W/m-K

To find out

Biot number for sphere

Solution

we will find boit number by this given formula

Biot Number = ( h × S ) / K     ..................1

here h and K value is given in question

and S = diameter/2

S= 60/2 = 30 mm = 0.03 m

Now put these value S, h and K in equation 1

Biot Number = ( 10 × 0.03 ) / 10

Biot Number =  0.03

Answer: b) possible and currently inexpensive as compared to wind turbines.

Explanation: Wind harvesting through kites is a process that will require less expenses in making and maintenance of it .Kites can be termed as the wind generator that is unconventional. The set up for the kite wind generator is also easy to install and also less costly as compared with turbines. So the correct option is option(a) .

Answer:

a)-True

Explanation:

Three point bending is better than tensile for evaluating the strength of ceramics. It is got a positive benefit to tensile for evaluating the strength of ceramics.

Answer:

25 mm = 0.984252 inches

Explanation:

Millimeter and inches are both units of distance. The conversion of millimeter into inches is shown below:

1 mm = 1/25.4 inches

From the question, we have to convert 25 mm into inches

Thus,

25 mm = (1/25.4)*25 inches

So,

[tex]25 mm=\frac{25}{25.4} inches[/tex]

Thus, solving we get:

25 mm = 0.984252 inches

Answer:

Pre-Flush:

It is also known as In-line Equalization. In this stage of flow equalization, all the flow passes through the equalization basin. It helps in reduction of fluctuation in pollutants concentration and flow rate and helps to control short term surges with the use of basin.

Post-Flush:

Another name for this stage is Off-line Equalization. In this stage, only overflow above a predetermined standard is diverted into the basin. It helps in reducing the fluctuations in loading by a considerable amount and helps to reduce the pumping requirement. It is basically used to capture "first flush" from combined collection systems.

Answer:

Answer:

Pre-Flush:

It is also known as In-line Equalization. In this stage of flow equalization, all the flow passes through the equalization basin. It helps in reduction of fluctuation in pollutants concentration and flow rate and helps to control short term surges with the use of basin.

Post-Flush:

Another name for this stage is Off-line Equalization. In this stage, only overflow above a predetermined standard is diverted into the basin. It helps in reducing the fluctuations in loading by a considerable amount and helps to reduce the pumping requirement. It is basically used to capture "first flush" from combined collection systems.

Explanation:

Answer:

1590 m^2

Explanation:

Given data in this question

Diameter = 45 m

power = 700 kW

wind speed = 12 m/s

turbine speed = 1500 rpm

To find out

swept area of the wind turbine

Solution

we know wind turbine is rotate circular form

and diameter is given so by the area of circular swept we will calculate it

we know area =  [tex]\pi /4[/tex] × d²

put the value of d here

area =  [tex]\pi /4[/tex] × 45²

swept area = 1590 m^2

Answer:

Q = 0.943[tex]m^{3}/s[/tex]

[tex]h_{L}[/tex] = 0.6605 m

Explanation:

Given :

Diameter, d₁ = 0.5 m

Area, A₁ = [tex]\frac{\pi }{4}\times 0.5^{2}[/tex]

             = 0.19625 [tex]m^{2}[/tex]

Enlargement diameter, d₂ = 1 m

Enlargement Area, A₂ = [tex]\frac{\pi }{4}\times 1^{2}[/tex]

             = 0.785 [tex]m^{2}[/tex]

Manometric difference, h = 35 mm

                                          =35 X [tex]10^{-3}[/tex] m

From manometer , we get

[tex]P_{1}+\rho _{w}.g.z_{1}+\rho _{m}.g.h=P_{2}+\rho _{w}.g.(z_{1}+h)[/tex]

[tex]P_{1}-P_{2}=(\rho _{w}-\rho _{m}).g.h[/tex]

[tex]\frac{P_{1}-P_{2}}{\rho _{w}.g}=(1-\frac{\rho _{m}}{\rho _{w}})\times h[/tex]

                                                = [tex](1-13.6)\times 35\times 10^{-3}[/tex]

                                                = -0.441

Now from newtons first law,

[tex]\frac{P_{1}-P_{2}}{\rho _{w}.g}=\frac{V_{2}^{2}-V_{1}V_{2}}{g}[/tex]

-0.441 = [tex]\frac{Q^{2}}{9.81}\times (\frac{1}{A_{2}^{2}}-\frac{1}{A_{1}A_{2}})[/tex]

-0.441 = [tex]\frac{Q^{2}}{9.81}\times (\frac{1}{0.785^{2}}-\frac{1}{(0.19625\times 0.785)^{2}})[/tex]

Therefore. Q = 0.943 [tex]m^{3} /s[/tex]

Now V₁ = [tex]\frac{Q}{A_{1}}[/tex]

            = [tex]\frac{0.943}{0.19625}[/tex]

            = 4.80 m/s

       V₂ =  [tex]\frac{Q}{A_{2}}[/tex]

            = [tex]\frac{0.943}{0.785}[/tex]

            = 1.20 m/s

Therefore, heat loss due to sudden enlargement is given by

  [tex]h_{L}=\frac{(V_{1}-V_{2})^{2}}{2g}[/tex]

[tex]h_{L}=\frac{(4.80-1.20)^{2}}{2\times 9.81}[/tex]

               = 0.6605 m

Answer:

A substitutional solid solution is a kind of alloying process used to improve or strengthen a purer metal by alloying it. this process works out by adding atoms of an alloy element to the atoms of the crystal lattice of the parent or base element, thus forming a substitutional solid solution. This process generates local non uniformity in the lattice due to the presence or mixing of an alloy element with the base element which impedes the plastic deformation.

Factors that favor the formation of substitutional solid solution are:

Answer:

Substitutional solids solution are formed when there is change in position of atom named as A in lattice by some other atoms of different atoms named as B.

Explanation:

Substitutional solids solution are formed when there is change in position of atom named as A in lattice by some other atoms of different atoms named as B.

Strengthening of this solution occurs when solute atom is lager than solvent atom so that it can replace its position

factor affect the extent of solid solution is

1) Relative atomic size

2) crystal structure

3) chemical affinity

4) valency

Answer: (d)Rotational speed of the shaft

Explanation: Shaft design is the design of a shaft that is used for defining the stresses at certain critical part of shaft. The shaft design has shaft diameter as a major part and this is determined by several factors like type of bearing , deflection, torque,safety factor etc.

But the least important factor for determining of the  diameter is the rotational speed because it defines the rotation of an object  around a particular axis, where is it states about the number of turns divisible by time. Therefore option(d) is the correct option.

Answer:

Mass does not affect oscillation frequency.                                                    

Explanation:

Let the bob of the pendulum makes a small angular displacement θ. When the pendulum is displaced from the equilibrium position, a restoring force tries to act upon it and it tries to bring the pendulum back to its equilibrium position. Let this restoring force be F.

Therefore, F = -mgsinθ  

Now for pendulum, for small angle of θ,

sinθ[tex]\simeq[/tex]θ

Therefore, F = -mgθ

Now from Newton's 2nd law of motion,

F = m.a = -mgθ

[tex]\Rightarrow m.\frac{d^{2}x}{dt^{2}} = - mg\Theta[/tex]

Now since, x = θ.L

[tex]\Rightarrow L.\frac{d^{2}\Theta }{dt^{2}}= -g\Theta[/tex]

[tex]\Rightarrow \frac{d^{2}\Theta }{dt^{2}}= -\frac{g}{L}.\Theta[/tex]

[tex]\Rightarrow \frac{d^{2}\Theta }{dt^{2}}+\frac{g}{L}.\Theta =0[/tex]

Therefore, angular frequency

 [tex]\omega ^{2}[/tex] = [tex]\frac{g}{L}[/tex]

ω = [tex]\sqrt{\frac{g}{L}}[/tex]

Also we know angular frequency is , ω = 2.π.f

where f is frequency

Therefore

2πf = [tex]\sqrt{\frac{g}{L}}[/tex]

f = [tex]\frac{1}{2 \pi }\sqrt{\frac{g}{L}}[/tex]

So from here we can see that frequency,f is independent of mass, hence it does not affect frequency.

Answer: True

Explanation:

Yes, it is true that 5 Kw solar system may produce enough energy to power your home as, on an average good quality of 5 KW solar system can produced 22 units per day enough to power all home appliances. As, a 5 KW solar system produced energy is basically depends on the three main factor that are:

Answer:

So heat transfer is 696 kJ

Explanation:

Given:

K = 1.4

[tex]C_{v}[/tex] = 0.716 kJ/kg

[tex]C_{p}[/tex] = 1 kJ/kg

R = 0.287 kJ/kg

V = 1 [tex]m^{3}[/tex]

P = 1000 kPa

T = 1000 K

Work delivered, δW = 696 kJ

It is isothermal process, so the initial and final temperature are same, that is T₁ = T₂ and the internal energy is zero (dU =0)

Therefore from 1st law of thermodynamcis,

δQ = dU + δW

     = 0 + 696

     = 696 kJ

So heat transfer is 696 kJ

Answer:

answer is option A i.e.45.45 hp

Explanation:

Given data:

load =20000 ft lb/s

efficiency = 80%

we know that

1 hp = 550 ft lb/s

minimum horsepower rating can be obtained by using following formula

minimum horse power rating = [tex]\frac{load}{efficiency * 1 horse power} \\[/tex]

                                                = [tex]\frac{20000}{0.8*550} = 45.45 hp[/tex]

Answer:

0.0833 k J/k

Explanation:

Given data in question

total amount of heat transfedded (Q) = 100 KJ

hot reservoir temperature R(h) = 1200 K

cold reservoir temperature R(c) = 600 k

Solution

we will apply here change of entropy (Δs) formula

Δs = [tex]\frac{Q}{R(h)}+\frac{Q}{R(c)}[/tex]

Δs = [tex]\frac{-100}{1200}+\frac{100}{600)}[/tex]

Δs = [tex]\frac{1}{12}[/tex]

Δs = 0.0833 K J/k

this change of entropy Δs is positive so we can say it is feasible and

increase of entropy principle is satisfied

Answer:

0.0837 kJ/K

Explanation:

Given:

Temperature of the cold reservoir T,cold = 600 K

Temperature of the hot reservoir T,hot= 1200 K

Heat transferred , Q=100 kJ

Now the entropy change for the cold reservoir

[tex]\bigtriangleup S,cold=-\frac{Q}{T,cold}[/tex]

[tex]\bigtriangleup S,cold=-\frac{-100}{600}[/tex]

[tex]\bigtriangleup S,cold=0.1667 kJ/K[/tex]

Now the entropy change for the cold reservoir

[tex]\bigtriangleup S,hot=-\frac{Q}{T,hot}[/tex]

[tex]\bigtriangleup S,hot=-\frac{100}{600}[/tex]

[tex]\bigtriangleup S,hot=-0.0833 kJ/K[/tex]

Therefore, the total entropy change for the two reservoir is

[tex]\bigtriangleup S=\bigtriangleup S,hot +\bigtriangleup S,cold[/tex]

thus,

ΔS=0.1667-0.0833

ΔS=0.0833 kJ/K

Since, the change of entropy is positive thus we can say it is possible and

increase of entropy principle is satisfied

Answer:

Answer is c Heisenberg's uncertainty principle

Explanation:

According to Heisenberg's uncertainty principle there is always an inherent uncertainty in measuring the position and momentum of a particle simultaneously.

Mathematically

[tex]\Delta x\times \Delta \overrightarrow{p}\geq \frac{h}{4\pi }[/tex]

here 'h' is planck's constant

Answer:

Repairable component

Explanation:

Repairable component is defined to be the probability that a failed component or system will be restored to a repaired specified condition within a period of time when maintenance is performed in accordance with prescribed procedures.

________is defined to be the probability that a failed component or system will be restored to a repaired specified condition within a period of time when maintenance is performed in accordance with prescribed procedures

Repairable component

Answer Explanation:

SPRING STIFFNESS :The stiffness of a body is a measure of resistance offered by an elastic body to deformation.it is denoted by K every object has some stiffness for spring the spring stiffness is the force required to cause unit deflection

DAMPING CONSTANT: the damping constant is a number decided by manufacturer that describes the material property. Damping is an influence within an oscillatory system that has the effect of restricting its oscillation

Answer:

1. High friction

2. High extrusion temperature

Explanation:

Surface cracking on extruded products are defects or breakage on the surface of the extruded parts. Such cracks are inter granular.

           Surface cracking defects arises from very high work piece temperature that develops cracks on the surface of the work piece. Surface cracking appears when the extrusion speed is very high, that results in high strain rates and generates heat.

          Other factors include very high friction that contributes to surface cracking an d chilling of the surface of high temperature billets.

Answer:

[tex]\\X_{C.G}=\frac{\int xdA}{A}\\Y_{C.G}=\frac{\int ydA}{A}[/tex]

Explanation:

The x co-ordinate of the centroid is given by:

[tex]x_{C.G}=\frac{\int xdA}{A}[/tex]

The y co-ordinate of the centroid is given by:

[tex]Y_{C.G}=\frac{\int ydA}{A}[/tex]

where

[tex]x^{}[/tex] is the x co-ordinate of a diffrential area [tex]dA[/tex]

and [tex]y^{}[/tex]  is the x co-ordinate of a diffrential area  [tex]dA[/tex]

See attached figure

Answer:

121.20 cm

Explanation:

Given data in question

inner dia = 5 cm

flow rate = 75  umin = 1.25 ×10³ cm³/sec

Solution

First we calculate Re by this formula

Re= [tex]\frac{V × D}{v)}[/tex]  = [tex]\frac{Q × D}{π/4 × D²× v)}[/tex]

Re= [tex]\frac{4Q }{π × D× v)}[/tex]

here we know Q is flow rate and D is dia of pipe and v is kinematic viscosity that is 1.14 × [tex]10^{-2}[/tex] cm ² / sec

so Re= [tex]\frac{4Q }{π × D× v)}[/tex]

Re = [tex]\frac{4×1.25× 10³ }{π × 5 × 1.14 × 10^{-2}  )}[/tex]

So Re will be 27936 that is greater than 4000 thats why it is turbulent flow

and we know [tex]\frac{Length}{dia)}[/tex] ≡ 4.4 [tex]Re^{1/6}[/tex]

so [tex]\frac{Length}{dia)}[/tex] ≡ 24.24

length will be 121.20 cm

Answer:

True.

Explanation:

According the engineering flow they don not possess flow energy when they are in rest.

When they are in motion they show a translation energy.

The features if fluids may be different according the variables of pressure and temperature.

Answer:

true

Explanation:

yes, it is true more fuel is burned than is consumed.

nuclear reactor generate electricity from nuclear fission and while nuclear fission  nucleus splits into small parts to generate energy.

these energies can be used for my purposes mainly it is used for power generation.

we can also say that  in nuclear reactor  more fuel is consumed because of metal acting as a fissionable material.

GIVEN:

Amplitude, A = 0.1mm

Force, F =1 N

mass of motor, m = 120 kg

operating speed, N = 720 rpm

[tex]\frac{A}{F}[/tex] =  [tex]\frac{0.1\times 10^{-3}}{1} = 0.1\times 10^{-3}[/tex]

Formula Used:

[tex]A = \frac{F}{\sqrt{(K_{t} - m\omega ^{2}) +(\zeta \omega ^{2})}}[/tex]

Solution:

Let Stiffness be denoted by 'K' for each mounting, then for 4 mountings it is 4K

We know that:

[tex]\omega = \frac{2 \pi\times N}{60}[/tex]

so,

[tex]\omega = \frac{2 \pi\times 720}{60}[/tex] = 75.39 rad/s

Using the given formula:

Damping is negligible, so, [tex]\zeta = 0[/tex]

[tex]\frac{A}{F}[/tex] will give the tranfer function

Therefore,

[tex]\frac{A}{F}[/tex] = [tex] \frac{1}{\sqrt{(4K - 120\ ^{2})}}[/tex]

[tex]0.1\times 10^{-3}[/tex] =  [tex] \frac{1}{\sqrt{(4K - 120\ ^{2})}}[/tex]

Required stiffness coefficient, K = 173009 N/m = 173.01 N/mm

Answer:

[tex](M_t)_{rated}=61.11lb-in[/tex]

Explanation:

speed of motor (N)=1500 rpm

power=4 hp = [tex]4 \times 0.7457 [/tex] =2.9828 KW

service factor(k)= 2.75

now,

[tex]KW=\frac{2\pi n M_t}{60 \times 10^6} \\2.9828=\frac{2\pi \times 1500 M_t}{60 \times 10^6}\\M_t=\frac{2.9828\times 60 \times 10^6}{2\pi \times 1500 }[/tex]

[tex]M_t= 18,989.09 \ N-mm= 168.06 lb-in[/tex]

torque rating

[tex](M_t)_{design}=k_s\times (M_t)_{rated}\\168.06= 2.75\times (M_t)_{rated}\\(M_t)_{rated}=\frac{168.06}{2.75} \\(M_t)_{rated}=61.11lb-in[/tex]