The direction of the magnetic field at a point in an electromagnetic wave can be determined using the 'right-hand rule'. Point your thumb in the direction of the electric field and curl your fingers. The direction your fingers curl is the direction of the magnetic field.
Explanation:In physics, particularly electromagnetic theory, the electric and magnetic fields of an electromagnetic wave are always perpendicular to each other and to the direction of propagation. The direction of the magnetic field at point 'a' can be determined by using the 'right-hand rule'. This rule states that if you point your thumb in the direction of the electric field and curl your fingers, the direction your fingers curl is the direction of the magnetic field. So, the direction of the magnetic field at point 'a' would be in the direction your fingers curl when you point your thumb in the direction of the electric field at point 'a'.
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Suppose you have a blocks of iron, a block of copper and a block of aluminum, each of 1 kg at 1000K. You want to warm up a 10 kg of water at 300K as much as possible. 1.1. Imagine that all you can do is to throw one block at a time and wait for it to achieve thermodynamic equilibrium before throwing in the next. Which ordering provides the best result?
Answer:
400k
Explanation:
If the light strikes the first mirror at an angle θ1, what is the reflected angle θ2? express your answer in terms of θ1.
Final answer:
The reflected angle θ2 is equal to the incident angle θ1 due to the Law of Reflection, and when light reflects off two perpendicular mirrors, the outgoing ray is parallel to the incoming ray.
Explanation:
The Law of Reflection states that the angle of reflection (θ2) is equal to the angle of incidence (θ1). This means that when light strikes a mirror at an angle θ1, it reflects off the mirror at the same angle θ2 such that θ2 = θ1. When light reflects from two mirrors that meet at a right angle, the outgoing ray will be parallel to the incoming ray, according to the law of reflection, because the two consecutive reflections each change the direction of the ray by the same angle, effectively rotating the ray by a total of 180 degrees, which makes it parallel to the original direction of incidence.
In summary, if the light strikes the first mirror at an angle θ1, the reflected angle θ2 in terms of θ1 is simply θ2 = θ1.
What is electrical power? how to measure power?
Answer:
Electric power is the rate at which work is done or energy is transformed in an electrical circuit.
P = W/t
Explanation
Where P is Power,
W is work
t = Time passed
Thermal conductors
A have low latent heat
B. have lots of air pockets
C. are often metals
D. have high conductivity
E. have low conductivity
can pick multiple
Answer:
C. are often metals
and
D. have high conductivity
An automobile tire having a temperature of 3.4 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 24 lb/in2 . What would be the gauge pressure in the tire when its temperature rises to 26◦C? For simplicity, assume that the volume of the tire remains constant, that the air does not leak out and that the atmospheric pressure remains constant at 14.7 lb/in2 . Answer in units of lb/in2 .
Answer:
[tex]27.164 lb/in^2[/tex]
Explanation:
We are given that
Gauge pressure at 3.4 degree Celsius,P=[tex]24lb/in^2[/tex]
We have to find the gauge pressure in tire when the temperature rises to 26 degree Celsius.
Atmospheric pressure=[tex]14.7lb/in^2[/tex]
[tex]P_1=P+14.7=24+14.7=38.7lb/in^2[/tex]
K=273+Degree Celsius
[tex]T_1=3.4+273=276.4 K[/tex]
[tex]T_2=26+273=299K[/tex]
[tex]P_2=\frac{P_1T_2}{T_1}[/tex]
[tex]P_2=\frac{38.7\times 299}{276.4}[/tex]
[tex]P_2=41.864 lb/in^2[/tex]
Gauge pressure in tire when the temperature rises to 26 degree Celsius.=[tex]41.864-14.7=27.164lb/in^2[/tex]
Answer:
27.16 lb/in²
Explanation:
initial temperature, T1 = 3.4 °C = 276.4 K
initial gauge pressure, P1 = 24 lb/in²
atmospheric pressure, Po = 14.7 lb/in²
initial absolute pressure, P1' = Po + P1 = 14.7 + 24 = 38.7 lb/in²
final temperature, T2 = 26 °C = 299 K
Let the final gauge pressure is P2.
use the ideal gas equation and the volume is constant.
[tex]\frac{P_{1}'}{T_{1}}=\frac{P_{2}'}{T_{2}}[/tex]
[tex]\frac{38.7}{276.4}=\frac{P_{2}'}{299}[/tex]
P2' = 41.86 lb/in²
Now the gauge pressure, P2 = P2' - Po = 41.86 - 14.7 = 27.16 lb/in²
Thus, the new gauge pressure is 27.16 lb/in².
A football player weighing 110 kg and traveling at +6 m/s runs head on into another player who weighs 150 kg and is traveling at -4 m/s. In which direction will they travel after they collide (stuck together) and what would their combined velocity be?
This is an inelastic collision. The equation for an inelastic collision is: [tex]m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = (m_{1} + m_{2})v_{f}[/tex]
(110)(6) + (150)(-4) = (110 + 150)(vf)
660 - 600 = 260vf
60 = 260vf
vf = 0.2308 m/s
They will travel in the positive direction, right, and their combined velocity will be 0.2308 m/s.
Hope this helps!! :)
When a DVD is played, a laser light hits the surface of the disk and then returns to the detector. An illustration of DVD with an arrow pointing toward a spot on the disk labeled detector. Which wave phenomenon allows the DVD player to work? absorption interference reflection refraction
Answer:
Reflection
Explanation:
The wave phenomenon that allows the DVD player to work is REFLECTION.
Reflection is defined as the repropagation of incident light striking a plane surface.
The light ray striking the surface is incident ray while the repropagated light ray is the reflected ray. The DVD was able to play because the laser light that hits the surface of the disk was able to reflect back and returns to the detector. The detector senses the light and cause the DVD to play. If the laser light didn't reflect, assuming it was absorbed by the surface of the disk, the detector wouldn't have detected the light and the DVD wouldn't have played.
Answer:
C. Reflection
Explanation:
Edge 2020
The U.S. Navy has long proposed the construction of extremely low frequency (ELF waves) communications systems; such waves could penetrate the oceans to reach distant submarines. Calculate the length of a quarter-wavelength antenna for a transmitter generating ELF waves of frequency 71 Hz.
Answer:
The length of the antenna would be L = 1056 km
Explanation:
Given:-
- The frequency of ELF, f = 71 Hz
- The speed of EM wave, c = 3.00 *10^8 m/s
Find:-
Calculate the length of a quarter-wavelength antenna for a transmitter generating ELF waves
Solution:-
- We will first determine the wavelength (λ) of the ELF waves with frequency (f) generated by the transmitter. The relationship that holds true for all types of EM waves is:
λ = c / f
λ = (3.00*10^8 m/s) / ( 71 Hz )
λ = 4225352.11267 m
- The antenna of the transmitter is to be designed such that its length (L) is 1/4-wavelength of ELF generated. So:
L = 0.25*λ
L = 0.25*4225352.11267
L = 1056 km
My reaction time was 0.7268 seconds the first time and 0.3883 the second time. What was yours
Answer:
0.32493
Explanation:
Two resistances, R1 and R2, are connected in series across a 9-V battery. The current increases by 0.450 A when R2 is removed, leaving R1 connected across the battery. However, the current increases by just 0.225 A when R1 is removed, leaving R2 connected across the battery. a) Find R1 b) Find R2
Answer:
a. R1 = 0.162 Ω
b. R2 = 0.340 Ω
Explanation:
Since the resistors R1 and R2 are connected in series, the current flowing through them when the 9 V battery is applied is 9/R1 + R2.
When the current increases by 0.450 A wen only R1 is in the circuit, the current is
9/R1 + R2 + 0.450 A = 9/R1 (1)
When the current increases by 0.225 A when only R2 is in the circuit, the current is
9/R1 + R2 + 0.225 A = 9/R2 (2)
equation (1) - (2) equals
9(1/R1 - 1/R2) = 0.450 A - 0.225
9(1/R1 - 1/R2) = 0.125
(1/R1 - 1/R2) = 0.125 A/9 = 0.0138
1/R1 = 0.0138 + 1/R2
R1 = R2/(1 + 0.0138R2) (3)
From (1)
9/R1 - 9/R1 + R2 = 0.450 A
9R2/[R1(R1 + R2)] = 0.450 A
R2/[R1(R1 + R2)] = 0.450 A/9 = 0.5
R2/[R1(R1 + R2)] = 0.5 (4)
From (3) R2/R1 = (1 + 0.0138R2) and from (4) R2/R1 = 0.5(R1 + R2). So,
(1 + 0.0138R2) = 0.5(R1 + R2)
0.5R1 + 0.5R2 = 1 + 0.0138R2
0.5R1 = 1 + 0.0138R2 - 0.5R2
0.5R1 = 1 - 0.4862R2 (5)
Substituting (3) into (5) we have
0.5R2/(1 + 0.0138R2) = 1 - 0.4862R2
R2 = (1 + 0.0138R2)(1 - 0.4862R2)
R2 = 1 - 0.4724R2 - 0.0067R2²
Collecting like terms, we have
0.0067R2² + 0.4724R2 + R2 - 1 = 0
0.0067R2² + 1.4724R2 - 1 = 0
Using the quadratic formula,
[tex]R_{2} = \frac{-1.4724 +/-\sqrt{(1.4724)^{2} - 4 X 0.0067 X -1} }{2 X 0.0067} \\= \frac{-1.4724 +/-\sqrt{2.1680 + 0.0268} }{0.0268}\\= \frac{-1.4724 +/-\sqrt{2.1948} }{0.0268}\\= \frac{-1.4724 +/- 1.4815 }{0.0268}\\= \frac{-1.4724 + 1.4815 }{0.0268} or \frac{-1.4724 - 1.4815 }{0.0268}\\= \frac{0.0091 }{0.0268} or \frac{-2.9539}{0.0268}\\= 0.340 or -110.22[/tex]
We choose the positive answer.
So R2 = 0.340 Ω
From (5)
R1 = 0.5 - 0.9931R2
= 0.5 - 0.9931 × 0.340
= 0.5 - 0.338
= 0.162 Ω
a. R1 = 0.162 Ω
b. R2 = 0.340 Ω
If forces acting on an object are unbalanced, the object could experience a change in ________. mass, speed, or direction negative acceleration or mass direction, mass, or both speed, direction, or both
Answer:
speed, direction, or both
Explanation:
If forces acting on an object are unbalanced, the object could experience a change in speed, direction, or both.
When the forces operating on an item are imbalanced, it signifies that the object's net force is not zero.
This causes the item to accelerate in the direction of the net force. As a result, depending on the direction of the net force, the object's speed may change, causing it to either accelerate or decelerate.
Due to the uneven forces, the item may potentially change its direction of travel.
The magnitude and direction of the unbalanced forces acting on the item will determine the degree of the changes in speed and direction.
Thus, unbalanced forces can thus induce a range of changes, including changes in speed, direction, or both.
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A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 6 m/s in 5 seco
is the acceleration?
-13 m/s?
-6 m/s
6 m/s
13 m/s
Answer:
Explanation:
Acceleration = a change in velocity / a change in time
Acceleration = ( final velocity - initial velocity) / a change in time
Acceleration = (6m/s - 35 m/s ) / 5 s
= (-29 m/s) /( 5 s)
= - 5.8 m/s^^2
Remember Significant Figures
- 6 m/s^2
P.S I have no idea why the answers say m/s because acceleration is m/s^2.
:)
How can the motion of a charged particle be used to distinguish between a magnetic field and an electric field in a certain region? The charged particle follows a spiral path in a magnetic field. The charged particle follows a linear path in a magnetic field. The charged particle follows a spiral path in an electric field
Answer:
The charged particle follows a spiral path in a magnetic field.
Explanation:
A charge immersed in a region with an electric field experiences a force that acts along the same direction of the electric field. In particular:
- The force has the same direction as the electric field if the charge is positive
- The force has the opposite direction as the electric field if the charge is negative
Therefore, a charge moving in an electric field is accelerated along the direction of the electric field.
On the other hand, a charge in motion in a region with a magnetic field experiences a force that acts perpendicular to the direction of the field. This means that a charge in motion in a magnetic field will acquire a circular motion in the plane perpendicular to the direction of the magnetic field.
As a result, if the particle has also a original motion outside this plane, its final motion will consist of:
- A uniform motion along that direction, +
- A circular motion along the plane perpendicular to the field
So, the resultant motion of the particle will be a spiral path. So the correct answer is
The charged particle follows a spiral path in a magnetic field.
Final answer:
The motion of charged particles differs significantly in electric versus magnetic fields. In magnetic fields, particles exhibit circular or spiral motions, and in electric fields, the motion is linear. This difference allows for the clear distinction between the two types of fields based on the particle's path.
Explanation:
The motion of a charged particle can be a revealing indicator of the presence and type of field it is moving through. When examining the behavior of charged particles, we see distinct patterns emerge in magnetic and electric fields. For magnetic fields, the motion is characterized by circular or spiral paths due to the magnetic force acting perpendicular to the particle's velocity. This is starkly different in an electric field, where the charged particle tends to move in a linear path along the direction of the field.
Magnetic fields cause a charged particle to follow a circular or helical path, with the nature of this motion being dependent on the angle between the velocity of the particle and the magnetic field lines. Technologies such as cyclotrons and mass spectrometers exploit this principle, utilizing magnetic fields to guide charged particles along desired paths.
In contrast, in an electric field, charged particles move linearly, aligning with the electric field lines. This linear motion is a result of the electric force acting along the direction of the field, guiding the particles in a straightforward path. The distinction between these two types of motion provides a clear method for distinguishing between magnetic and electric fields based on the observed path of a charged particle.
Calculate the angular momentum of a 2 kg cylinder pulley with radius 0.1 m that rotates at a constant angular speed of 2 rad/s.
Answer:
The angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .
Explanation:
Given :
Mass of pulley , m = 2 kg .
Radius of pulley , R = 0.1 m .
Angular velocity of pulley , [tex]\omega=2\ rad/s[/tex] .
We need to find the angular momentum
We know , angular momentum of a rigid body is given by :
[tex]L=I\omega[/tex] ......( 1 )
Here , I is the angular momentum of cylindrical pulley and is given by :
[tex]I=\dfrac{MR^2}{2}\\\\I=\dfrac{2\times 0.1^2}{2}\\\\I=0.01\ kg \ m^2[/tex]
Putting value of I and [tex]\omega[/tex] in equation 1 .
We get :
[tex]L=0.01\times 2\ kg\ m^2\ rad /s\\\\L=0.02 \ kg\ m^2\ rad /s\\[/tex]
Therefore , the angular momentum of cylinder pulley is [tex]0.02 \ kg\ m^2\ rad /s\\[/tex] .
The angular momentum of the cylinder pulley can be determined by first calculating the moment of inertia using the mass and the radius of the pulley, and then substituting the obtained values and the given angular velocity into the formula for angular momentum. The calculated angular momentum for this cylinder pulley is 0.02 kg.m²/s.
The angular momentum of a rotating object, such as a cylinder pulley, is calculated by the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. The moment of inertia of a cylinder is I = 0.5mr², where m is the mass and r is the radius of the cylinder.
First, we calculate the moment of inertia for our cylinder pulley: I = 0.5 x 2 kg x (0.1 m)² = 0.01 kg.m². Now, we can determine the angular momentum: L = 0.01 kg.m² x 2 rad/s = 0.02 kg.m²/s.
Therefore, the angular momentum of a 2 kg cylinder pulley with radius 0.1 m rotating at a constant angular speed of 2 rad/s is 0.02 kg.m²/s.
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A car approaches a pedestrian standing on the side of the road. The car is traveling at 24.2 m/s. The horn of the car emits a sound wave with a frequency of 482 Hz. What frequency is heard by the pedestrian
Final answer:
The frequency heard by the pedestrian as the car approaches, using the Doppler Effect, would be approximately 518 Hz.
Explanation:
To determine the frequency heard by the pedestrian as the car approaches, we use the Doppler Effect equation:
f' = f(v + v0)/(v - vs)
where:
f' is the frequency heard by the observer (pedestrian)
f is the frequency of the source (car horn's frequency)
v is the speed of sound
v0 is the speed of the observer (pedestrian, which is 0 m/s since they are standing)
vs is the speed of the source (car)
Given the car horn's frequency, f = 482 Hz, and the car's speed, vs = 24.2 m/s. Assuming the speed of sound on a standard day (approximately 343 m/s), the equation modifies to:
f' = 482(343 + 0)/(343 - 24.2)
We can now calculate:
f' = 482(343)/(318.8) ≈ 518 Hz
The frequency heard by the pedestrian would be approximately 518 Hz when the car is approaching.
what happens overtime to rocks that are stressed
Answer:
Stress is the force applied to an object. In geology, stress is the force per unit area that is placed on a rock. Four types of stresses act on materials.
A deeply buried rock is pushed down by the weight of all the material above it. Since the rock cannot move, it cannot deform. This is called confining stress.
Compression squeezes rocks together, causing rocks to fold or fracture (break) (Figure below). Compression is the most common stress at convergent plate boundaries.
Explanation:
What is the distinction between glass transition temperature and melting temperature?
Answer:
Glass transition temperature is a characteristic of soda lime glass and melting temperature is for a Borosilicate glass.
Explanation:
The glass transition is the change of an amorphous solid from soft and flexible to glass-like, i.e. hard and brittle. On the other hand, the melting temperature is the temperature at which the liquid - solid phase transition occurs in a crystalline substance.
g What is the magnetic potential energy stored in a cylindrical volume of height hcylinhcylin = 50 mmmm and radius RcylinRcylin = 24 mmmm that symmetrically surrounds an infinitely long wire that has radius RwireRwire = 2.1 mmmm and carries current III = 4.9 AA ? The volume in which the energy should be calculated does not contain the wire.
Answer:
[tex]2.9\cdot 10^{-7} J[/tex]
Explanation:
The energy density associated to a magnetic field is:
[tex]u=\frac{B^2}{2\mu_0}[/tex] (1)
where
B is the strength of the magnetic field
[tex]\mu_0[/tex] is the vacuum permeability
The magnetic field produced by a current-carrying wire is
[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]
where
I is the current in the wire
r is the distance from the wire at which the field is calculated
Substituting into (1),
[tex]u=\frac{\mu_0 I^2}{8\pi^2 r^2}[/tex] (2)
Since this is the energy density, the total energy stored in a certain element of volume [tex]dV[/tex] will be
[tex]U=u\cdot dV=\frac{\mu_0I^2}{8\pi^2 r^2}dV[/tex] (3)
Here the field strength changes as we move farther from the wire radially, so we can write dV as
[tex]dV=2\pi h r dr[/tex]
where
h is the height of the cylinder
r is the distance from the wire
So eq(3) becomes:
[tex]dU=\frac{\mu_0I^2}{8\pi^2 r^2} \cdot 2 \pi h r dr = \frac{\mu_0 I^2 h}{4\pi}\frac{1}{r}dr[/tex]
Now we have to integrate this expression to find the total energy stored in the cylindrical volume. We have:
h = 50 mm = 0.050 m is the height of the cylinder
I = 4.9 A is the current in the wire
[tex]b=2.1 mm = 0.0021 m[/tex] is the internal radius of the cylinder (the radius of the wire)
[tex]a=24 mm=0.024 m[/tex] is the external radius of the cylinder
So,
[tex]U=\int\limits^a_b {dU} =\frac{\mu_0 I^2 h}{4\pi} \int\limits^{0.024}_{0.0021} \frac{1}{r}dr = \frac{\mu_0 I^2 h}{4\pi} [ln(a)-ln(b)]=\\=\frac{(4\pi \cdot 10^{-7})(4.9)^2(0.050)}{4\pi}[ln(0.024)-ln(0.0021)]=2.9\cdot 10^{-7} J[/tex]
The roller coaster from problem #1 then tops a second hill at 15.0 m/s, how high is the second hill?
Problem #1: A roller coaster glides from rest from the top of an 80.0 meter hill. What is the speed of the roller coaster at the bottom of the hill?
To find the height of the second hill, we can use the conservation of mechanical energy principle.
Explanation:To find the height of the second hill, we can use the conservation of mechanical energy principle. At the top of the second hill, the roller coaster has a kinetic energy and a gravitational potential energy. The total mechanical energy at the top of the hill is equal to the total mechanical energy at the bottom of the first hill. We can set up the equation:
mgh + 0.5mv^2 = mgh2
where m is the mass of the roller coaster, g is the acceleration due to gravity, h is the height of the first hill, v is the speed at the bottom of the hill, and h2 is the height of the second hill. Substituting the given values into the equation will give us the height of the second hill.
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Final answer:
When a roller coaster tops the second hill at 15.0 m/s, the height of the hill can be calculated by rearranging the conservation of energy equation. By setting the kinetic energy equal to the potential energy, we can solve for the height of the hill.
Explanation:
The question relates to the conservation of energy in physics, specifically within the context of a roller coaster. We are looking to find how high the second hill is, knowing that the roller coaster tops it at 15.0 m/s.
First, let's solve problem #1 as reference: A roller coaster starting from rest on an 80.0 meter hill without friction will convert its potential energy entirely into kinetic energy at the bottom. The formula to calculate the final speed (v) at the bottom is given by v = √(2gh), where g is the acceleration due to gravity (9.8 m/s²) and h is the height. Substituting the given values, we find the final speed at the bottom of the first hill.
For the second part, the roller coaster tops the second hill at 15.0 m/s, which is the kinetic energy at that point. To find the height of the second hill, we'll set that kinetic energy equal to the potential energy at the top of the hill.
The formula rearranged to solve for the height (h) is h = v₂ / (2g). When we input the speed and acceleration due to gravity, we can determine the height of the second hill.
Cosmic microwave background radiation is classified as a form of electromagnetic energy because it
Answer:
travels in waves through space
Explanation:
A cosmic microwave background radiation is classified as a form of electromagnetic energy because it
travels in waves through space
The cosmic microwave background is assumed to be a left over radiation from the Big Bang, or the time when the universe began. This means its radiationis most visible in the microwave part of the electromagnetic spectrum.
Answer:
The answer is:
Because it travels in waves through space.
Explanation:
CMB is a form of radiation discovered in 1965 that is presented as one of the main tests of the cosmic model since it is a type of radiation that fills the entire universe.
It has the characteristics of black-body radiation (a theoretical or ideal object that absorbs all light and all radiant energy incident on it) at a temperature of 2,725 K, with a frequency of 160.2 GHz and a length of 1.9mm wave belonging to the microwave. rank
where do cardiac muscles cause movement in?
-bone
-tendon
-ligament
-organ
Answer:it the tendon
Explanation:
Answer: The answer would be bone... I mean organ
Explanation:
Look in the defenition In edunuity
3. This diagram shows that Al can see the reflections of Ed and Fred in the
mirror. Which two students can both see the reflections of Cy, Di, Ed and
Fred? *
For
Answer:
Only Cy and Di could see the reflections.
Explanation:
Reflection is a property of light that makes it to travel through its initial path on hitting a plane surface. It is good to note that the angle of the incident ray to the surface is equal to the angle of reflection after hitting the surface. It can generally be classified into diffuse and specular.
A ray of light travels on a straight path, the images of the students are formed due to reflection of light at the plane surface. By ray constructions and observation, it would be observed that only Cy and Di could see the reflections of the four students. This is due to their positions with respect to the reflecting surface.
What three changes in motion show that an object is accelerating?
Answer:
There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.
Explanation:
The three changes in motion show that an object is accelerating are,
a = ∆v / ta = F / ma = w²rWhat are the changes happened in an object?An object is accelerating with the changes in motion are,
1. If the velocity is increasing.
From equation of motion
a = ∆v / t
So, if the velocity increases with time, the acceleration increases. But if it decreases with time, it decelerating.
2. Also, from newton second law,
F = ma
a = F / m
Where a = acceleration
F is force applied
m is the mass
So, if the force is increase and the mass is reduced, then the acceleration is increase.
3. Also, in Circular motion,
a = w²r
Where,
a is linear acceleration
w is angular speed
r is the radius.
So, when the angular speed is increased, then the linear acceleration is increased.
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The fastest possible conduction velocity of action potentials is observed in ________.
Please answer the question on the picture
Answer:
radial artery and carotid artery
Explanation:
You are in your car at rest when the traffic light turns green. You place your coffee cup on the horizontal dash and hit the gas. The coffee cup does not slide as you accelerate forward. The work done by friction on your coffee cup is
Answer:
[tex]\mu mgd[/tex]
Explanation:
In the situation described in the problem, there are 3 forces acting on the coffee cup:
- The weight of the cup, acting downward
- The normal force exerted by the horizontal dash on the cup, acting upward
- The force of friction, acting forward and "keeping" the cup travelling together with the car, without sliding backward
For the purpose of this problem, we ignore the weight and the normal force, since they cancel each other out.
The force of friction here pushes the cup forward, allowing it to move together with the dash and the car, without sliding. The magnitude of this force of friction is
[tex]F_f = \mu mg[/tex]
where
[tex]\mu[/tex] is the coefficient of static friction between the cup and the dash
m is the mass of the cup
g is the acceleration of gravity
Since the cup is moving forward together with the car, it means that it has a certain displacement [tex]d[/tex], and therefore the force of friction is performing work, equal to the product between force and displacement, so:
[tex]W=F_f \cdot d = \mu mg d[/tex]
. The density of ice is 917 kg/m3, and the latent heat of fusion of water is 3.35 x 105 J/kg. The driver of the van turns on the rear-window defroster, which operates at 12 V and 29 A. The defroster directly heats an area of 0.56 m2 of the rear window. What is the maximum thickness of ice above this area that the defroster can melt in 3.8 minutes?
Answer:
[tex]s = 1.472\,m[/tex]
Explanation:
The heat require to melt the ice formed in the rear window is:
[tex]Q = m_{ice}\cdot L_{f}[/tex]
[tex]Q = \rho_{ice}\cdot V_{ice}\cdot L_{f}[/tex]
[tex]Q = \rho_{ice}\cdot A_{w}\cdot s \cdot L_{f}[/tex]
The heat transfer rate given by the defroster is:
[tex]\dot Q = \epsilon\cdot i[/tex]
But:
[tex]\epsilon \cdot i \cdot \Delta t = \rho_{ice}\cdot A_{w}\cdot s \cdot L_{f}[/tex]
The maximum thickness of ice that can be melt is:
[tex]s = \frac{\epsilon \cdot i \cdot \Delta t}{\rho_{ice}\cdot A_{w}\cdot L_{f}}[/tex]
[tex]s = \frac{(12\,V)\cdot (29\,A)\cdot (3.8\,min)\cdot (\frac{60\,s}{1\,min} )}{(917\,\frac{kg}{m^{3}} )\cdot (0.56\,m^{2})\cdot (105\,\frac{J}{kg} )}[/tex]
[tex]s = 1.472\,m[/tex]
Answer:
Max thickness; h = 4.61 x 10^(-4) m
Explanation:
We are given;
Current; I = 29A
Voltage; V = 12 V
Time; t = 3.8 minutes = 228 seconds
Density;ρ = 917 kg/m³
latent heat of fusion of water; L = 3.35 x 10^(5) J/kg
Area; A = 0.56 m²
We know that volume = Area x Height.
Thus, V = Ah and h = V/A
We also know that density is given by;
ρ = mass/volume = m/V
Amd V = m/ρ
Thus, h can be written as;
h = (m/ρ)/A - - - - - (eq1)
Now, we know that;
The specific latent heat (L) of a material is a measure of the heat energy (Q) per mass (m) released or absorbed during a phase change.
It is defined through the formula
Q = mL
Thus, m = Q/L
So, putting Q/L for m in eq 1,we have; h = (Q/Lρ)/A = Q/LρA
Now, power(P) is; Q/t where Q is energy dissipated and t is time.
Thus, P = Q/t and thus, Q = Pt
Thus, h = Pt/LρA - - - - (eq2)
We also know that Power = IV
Thus, power = 29 x 12 = 348 W
Thus, plugging in the relevant values into eq(2),we have;
h = (348 x 228)/(3.35 x 10^(5) x 917 x 0.56)
h = 79344/(1720.292 x 10^(5))
h = 4.61 x 10^(-4) m
An ion source is producing 6Li ions, which have charge +e and mass 9.99 × 10-27 kg. The ions are accelerated by a potential difference of 9.2 kV and pass horizontally into a region in which there is a uniform vertical magnetic field of magnitude B = 0.99 T. Calculate the strength of the smallest electric field, to be set up over the same region, that will allow the 6Li ions to pass through undeflected.
Answer:
[tex]5.38\cdot 10^5 V/m[/tex]
Explanation:
At first, the 6Li ions are accelerated by the potential difference, so their gain in kinetic energy is equal to the change in electric potential energy; so we can write:
[tex]q\Delta V=\frac{1}{2}mv^2[/tex]
where
[tex]q=+e=+1.6\cdot 10^{-19}C[/tex] is the charge of one 6Li ion
[tex]\Delta V=9.2 kV=9200 V[/tex] is the potential difference through which they are accelerated
[tex]m=9.99\cdot 10^{-27}kg[/tex] is the mass of each ion
v is the final speed reached by the ions
Solving for v, we find:
[tex]v=\sqrt{\frac{2q\Delta V}{m}}=\sqrt{\frac{2(1.6\cdot 10^{-19})(9200)}{9.99\cdot 10^{-27}}}=5.43\cdot 10^5 m/s[/tex]
After that, the ions pass into a region with a uniform magnetic field of strength
[tex]B=0.99 T[/tex]
The magnetic field exerts a force perpendicular to the direction of motion of the ions, and this force is given by
[tex]F=qvB[/tex]
In order to make the ions passing through undeflected, there should be an electric force balancing this magnetic force. The electric force is given by
[tex]F=qE[/tex]
where E is the strength of the electric field.
Since the two forces must be balanced,
[tex]qE=qvB[/tex]
From which we get
[tex]E=vB[/tex]
So the strength of the electric field must be
[tex]E=(5.43\cdot 10^5)(0.99)=5.38\cdot 10^5 V/m[/tex]
At a given instant an object has an angular velocity. It also has an angular acceleration due to torques that are present. Therefore, the angular velocity is changing. Does the angular velocity at this instant increase, decrease, or remain the same (a) if additional torques are applied so as to make the net torque suddenly equal to zero and (b) if all the torques are suddenly removed
a) Constant
b) Constant
Explanation:
a)
We can answer this question by using the equivalent of Newton's second law of motion of rotational motion, which can be written as:
[tex]\tau_{net} = I \alpha[/tex] (1)
where
[tex]\tau_{net}[/tex] is the net torque acting on the object in rotation
I is the moment of inertia of the object
[tex]\alpha[/tex] is the angular acceleration
The angular acceleration is the rate of change of the angular velocity, so it can be written as
[tex]\alpha = \frac{\Delta \omega}{\Delta t}[/tex]
where
[tex]\Delta \omega[/tex] is the change in angular velocity
[tex]\Delta t[/tex] is the time interval
So we can rewrite eq.(1) as
[tex]\tau_{net}=I\frac{\Delta \omega}{\Delta t}[/tex]
In this problem, we are told that at a given instant, the object has an angular acceleration due to the presence of torques, so there is a non-zero change in angular velocity.
Then, additional torques are applied, so that the net torque suddenly equal to zero, so:
[tex]\tau_{net}=0[/tex]
From the previous equation, this implies that
[tex]\Delta \omega =0[/tex]
Which means that the angular velocity at that instant does not change anymore.
b)
In this second case instead, all the torques are suddenly removed.
This also means that the net torque becomes zero as well:
[tex]\tau_{net}=0[/tex]
Therefore, this means that
[tex]\Delta \omega =0[/tex]
So also in this case, there is no change in angular velocity: this means that the angular velocity of the object will remain constant.
So cases (a) and (b) are basically the same situation, as the net torque is zero in both cases, so the object acts in the same way.
What is the electrical force between q1 and q2? Recall that k = 8.99 × 109 N•meters squared over Coulombs squared.. 4.3 × 10 N 3.5 × 10 N –5.4 × 10 N –5.8 × 10 N?
Answer:
Explanation:
Incomplete question but for understanding.
We want to find the electrical force between two charges, then you can use the coulombs law which states that the force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of their distance apart,
So,
F = kq1•q2 / r²
Where k is a constant and it is given as
K = 8.99 × 10^9 Nm²/C²
q1 and q2 are the charges and in this question it is not given, so the question is incomplete. Let assume that,
q1 = - 1.609 × 10^-19 C electron
q2 = 1.609 × 10^-19 C proton
Since unlike charges attract, then it is force of attraction
Also, r is the distance apart and it is not given, let assume the distance between the two charges is 2 × 10^-5m
Then,
F = kq1•q2 / r²
F = 8.99 × 10^9 × 1.609 × 10^-19 × 1.609 × 10^-19 / (2 × 10^-5)²
F = 5.82 × 10^-19 N
Answer:
c –5.4 × 1010 N on edge
Explanation: