Answer:
B. a ball on a string that stopped at the top of a vertical loop
Explanation:
Motion diagram must represent the direction of velocity of an object in the given figure
here as it is shown in the figure the arrow is vertically downwards which means that the velocity of object at that moment is downwards when it is at the top most point of its circular path
So here
A. a car driving over the top of a hill
Not correct as car is moving tangentially on the top of the hill so its velocity can not be downwards
B. a ball on a string that stopped at the top of a vertical loop
Since ball is stopped at the top most point of its path so here its velocity must be downwards due to free fall so its correct motion diagram for the above condition.
C. a roller coaster car at the top of a vertical loop of a track
Not correct as we know that roller coaster at the top of the loop will move tangentially so its velocity can not be vertically downwards.
D. a bug on the top of a rolling hula hoop
Bug is at the top of rolling hula hoop so its velocity is again tangentially and not vertical downwards.
A few students in your class were probably able to exceed 1 hp of power output. how is this possible considering the fact that a horse is much stronger than a human?
A block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g. When placed in water, the block sinks. What volume of water did it displace?
A. 27.0 cm3
B. 213 cm3
C. 7.89 cm3
D. 0.127 cm3
Answer:
The answer is A.
Explanation:
D = m/V
Volume:
3.00 x 3.00 x 3.00 = 27 cm³
Answer A
The volume of the block is (3cm) · (3cm) · (3cm) = 27 cm³ .
That's how much water gets pushed out of the way when the block sinks in water. It makes no difference what the block is made of, or what its mass or density is. Pick choice-A .
Match the term with the definition. Match Term Definition Compressibility A) Measure of how much heat is given off when a substance is burned Flammability B) The ability of a substance to damage or harm an organism Heat of combustion C) Measure of how much the volume of matter can decrease under pressure Toxicity D) How easily a substance can be set on fire
oohhhhhhh i just figured this out
toxicity- B
heat of combustion- A
flammability- D
compressibility- C
Here are the matched terms with their corresponding definitions:
A) Compressibility: Measure of how much the volume of matter can decrease under pressure.
B) Flammability: How easily a substance can be set on fire.
C) Heat of combustion: Measure of how much heat is given off when a substance is burned.
D) Toxicity: The ability of a substance to damage or harm an organism.
What is Flammability ?Flammability is a property of a substance that refers to how easily it can catch fire or ignite when exposed to an open flame, heat, or other sources of ignition. It is a measure of the substance's susceptibility to burning. Substances with high flammability are more likely to ignite and sustain combustion, while those with low flammability are less likely to do so.
Flammability is an important characteristic to consider in various contexts, including safety regulations, the handling and storage of chemicals, and the development of fire-resistant materials.
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a particle moves along the x axis with an acceleration of a=18t, where a has units if m/s2. if the particle at time t=0 is at the origin with a velocity of -12 m/s, what js its position at t=4.0s?
Answer:
Position at t= 4 seconds is 144 m
Explanation:
It is given that acceleration, a = 18 t, where t is the time.
We know that Velocity, [tex]v = \int { a} \, dt[/tex]
Substituting value of a,
Velocity, [tex]v = \int {18t} \, dt=\frac{18t^2}{2} +c=9t^2+c[/tex]
We know that at t = 0, v = -12 m/s
So, [tex]9*0^2+c=-12\\ \\ c=-12m/s[/tex]
So velocity, [tex]v = (9t^2-12)m/s[/tex]
We also know that displacement, [tex]x = \int { v} \, dt[/tex]
Substituting value of v,
Displacement, [tex]x=\int {(9t^2-12)} \, dt=\frac{9t^3}{3} -12t+c=3t^3-12t+c[/tex]
We know that at t = 0, particle is at origin, x =0.
So, [tex]0=3*0^3-12*0+c\\ \\ c=0[/tex]
Displacement, [tex]x = 3t^3-12t[/tex]
At t = 4 seconds
[tex]x = 3*4^3-12*4=192--48=144m[/tex]
Position at t= 4 seconds is 144 m
]The particle is at 144 meters along the x-axis at t=4.0 seconds.
To find the position, we first need to integrate the acceleration to get the velocity as a function of time, and then integrate again to get the position.
We know that acceleration is the derivative of velocity with respect to time, so:
v(t) = ∫dt = ∫18t dt = 9t2 + C
Where C is the integration constant. Using the initial condition, v(0) = -12 m/s, we find that C = -12.
Now we integrate the velocity to find the position:
x(t) = ∫v(t) dt = ∫(9t2 - 12) dt = 3t3 - 12t + D
Where D is another constant of integration, since the particle is at the origin at time t=0, x(0) = 0, we find D = 0.
Finally, we plug t = 4.0 s into the position function:
x(4) = 3(4)3 - 12(4) = 192 - 48 = 144 meters.
The particle's position at t=4.0 seconds is 144 meters along the x-axis.
If you add together all of forces exerted on an object and get a non zero value this is called the _____ force on the object
Your answer would be the; NET force on the object. Refer to Newton's Laws of Forces and Motion.
Hope that helps!!!!!!!!!!!!!!!! : )
Answer:
Net force
Explanation:
When a number of forces acting on a body, and then a non zero value of force is there. It is called net force acting on a body.
There are two types of forces.
1. Balanced forces
2. Unbalanced forces
When a number of forces acting on a body and then net force is zero, Then the forces are called balanced forces.
When a number of forces acting on a body and net force is non zero . Such forces are called unbalanced forces.
It takes a car one minute to go from rest to 30 m/s east what is the acceleration of this car?
The acceleration of the car that when from rest to 30m/s in 1 minute is 0.5 m/s².
What is the acceleration of the car?The first equation of motion is expressed as:
v = u + at
Given the data in the question:
Elapsed time t = 1 minutes = 1 × 60 = 60 seconds
Initial velocity u = 0
Final velocity = 30 m/s
Acceleration a =?
Plug the given values into the above formula and solve for the acceleration of the car.
v = u + at
30 = 0 + ( a × 60 )
30 = 0 + 60a
30 = 60a
a = 30/60
a = 3/6
a = 0.5 m/s²
Therefore, the acceleration is 0.5 m/s².
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Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.
The most important characteristics that are exhibited by metals are-
1- Metals are ductile
2-Most metals are conductive in nature.
3-Most metals are malleable.
4- Metals have strong inter molecular force of attraction between the.
5-Metals have luster.
6-Metals are sonorous.
Here we are given Tungsten filament.
Tungsten is a metal.So it must be conductive and as well as ductile in nature.
The electric filament that we are using in our electric bulb glows due to the heating effect of current.Hence the chosen substances for glowing electric bulb must have high melting point.
The melting point of tungsten is 1650 degree celsius which is very high.That's why it is used in electric bulb.
Hence the correct answer to the question is the third one i.e Tungsten is ductile,has a high melting point, and is electrically conductive.
Answer:
c) Tungsten is ductile, has a high melting point, and is electrically conductive.
Explanation:
i took the test
Galileo and Newton both studied the night sky. Galileo studied Jupiter and its moons. Newton studied the gravitational force that held the planets in orbit. Which of these statements best explains why the two scientists proposed different theories about the solar system?
Both had limited data.
Both had different interests.
They wanted to contradict each other's theory.
They wanted to be the first to discover new planets.
Explanation :
Galileo studied Jupiter and its moons. Newton studied the gravitational force that held the planets in orbit.
Galileo constructed a telescope called Galileo's Telescopes. He also supported the Copernican theory.
Newton proposed the Universal law of gravitation. According to him, there exists a force between objects in the universe which is directly proportional to the product of masses and inversely proportional to the square of the distance between them.
i.e.
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
So, we can say that the two scientists proposed different theories about the solar system. This shows that they both had different interests.
A bowling ball is whizzing down the bowling lane at 4 m/s. If the mass of the bowling ball is 7-kg, what is its kinetic energy? 52 J 48 J 56 J 66 J
[tex]Given:\\m=7kg\\v=4\frac{m}{s} \\\\Find:\\E_k=?\\\\Solution:\\\\E_k=\frac{mv^2}{2} \\\\E_k=\frac{7kg\cdot (4\frac{m}{s})^2}{2} =\frac{7kg\cdot 16\frac{m^2}{s^2} }{2} =7kg\cdot 8\frac{m^2}{s^2} =56J[/tex]
What is the kinetic energy of a 478 kg object that is moving with the speed of 15 m/s
The kinetic energy of the object is 53775 Joules.
Given the following data:
Mass = 478 kgVelocity = 15 m/s.To find the kinetic energy of the object:
Kinetic energy is an energy that is possessed by a physical object or body due to its motion.
Mathematically, kinetic energy is calculated by using the formula;
[tex]K.E = \frac{1}{2} MV^2[/tex]
Where:
K.E is the kinetic energy.M is the mass of an object.V is the velocity of an object.Substituting the values, we have;
[tex]K.E = \frac{1}{2}[/tex] × [tex]478[/tex] × [tex]15^2[/tex]
[tex]K.E = 239[/tex] × [tex]225[/tex]
Kinetic energy = 53775 Joules
Therefore, the kinetic energy of the object is 53775 Joules.
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Please explain your answer when you found the answer (Only question number 9)
All the bats living in a cave form a _____ of bats in the cave ecosystem.
All the bats living in a cave form a __colony__of bats in the cave ecosystem.
The bats living in a cave form a population of bats within that cave ecosystem. The term 'population' in biology refers to all individuals of a particular species inhabiting a specific area. Factors such as diseases and resource exploitation can though impact a population.
Explanation:All the bats living in a cave form a population of bats in that cave ecosystem. A population refers to all individuals of a species living within a specific area. For instance, the bats in a cave represent the population of bats in that particular cave. It's important to note that populations aren't static - they can be affected by various factors such as disease. For instance, the tragedy of the commons principle suggests that resources held in common, such as a cave, could potentially be overexploited, leading to population decline. A specific example is white-nose syndrome, a disease impacting bat populations that inhabit caves in the eastern United States and Canada.
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How many times louder is a sound wave with an intensity of 50 dB than a sound wave with an intensity of 20 dB?
if an object of mass 6 kg has an acceleratoon of 9 m/s2, what is the unbalanced force acting on it?
a net force of 500N acts on a 100 kg cart what is the acceleration
The formula is sum of the forces = Mass* Acceleration
If there is no friction (which i'm assuming not)
500N = 100 * A
A = 5 M/S/S (Or M/S^2)
Which position-time graph matches the velocity-time graph?
Answer:
b
Explanation:
cuz i no
The slope of the position-time graph represents the corresponding velocity - this relationship forms the basis for the creation of a velocity-time graph. Positive slopes on the position-time graph mean forward motion and negative slopes mean backward motion which is graphically represented as positive and negative slopes on the velocity-time graph respectively.
Explanation:The position-time graph and the velocity-time graph are closely related. The slope of the position-time graph at any given point represents the velocity at that point in time. For example, if you have a straight line on a position-time graph which has a positive slope, it means the object is moving in a positive direction or forward. Therefore, the velocity-time graph for the same object would also have a straight line with positive slope.
A similar concept applies if the slope on the position-time graph is zero, it means the velocity at that time is zero and this would be represented as horizontal line on the velocity-time graph. Another interesting aspect is, if the slope of a position-time graph is negative, it means the object is moving in a negative or backward direction and the corresponding a velocity-time graph would have a negative slope.
It’s notable that straight lines on velocity-time graphs indicate constant velocity, whereas lines with positive or negative slope indicate acceleration or deceleration respectively.
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To which is the watt is equal?
A) joules/second
B) joules/coulomb
C) volts/second
D) amps/coulomb
E) volts/amps
joule / second is the answer
Answer:
Option (A)
Explanation:
Watt is the SI unit of power.
The rate of doing work is defined as power.
Power = work/time
The SI unit of work is joule and the SI unit of time is second, so the SI unit of power is joule per second.
If joule of work is said to be done in second then we can say the power is watt.
Picking up a hot coal is an example of what type of heat transfer?
Conduction
Convection
Radiation
Transmission
That would be a conduction.
conduction
hope this helped
Jenny wants to determine if a new brand name washing detergent is better than her old detergent she washed ten dirty t-shirts with the new washing detergent and ten dirty t-shirts with the old detergent identify the dependent and independent variables for this experiment
Answer:
Independent variable: washer detergent
Dependent varaible: cleaing power of effectivenes of the detergent.
Explanation:
When an experiiment is performed there exists one independent variable, one dependent variable, and some other variables that must be controlled.
The goal of the experiment is to test a hypothesis, which is a statement that relates an effect with a cause and that must be proved true or false.
The effect in the dependent variable, and the cause is the independent variable.
Jenny (the scientist) wants to show how an effect or phenomenun, the dependent variable, is explained by the explanatory, independent, variable.
In the stated experiment, Jenny wants to know how the effectiveness of a new brand detergent and an old one compare with each other. Therefore, she designs a test in which she will determine how the brand of detergent may explain (explanatory or independent variable) the cleaning power or effectiveness, the dependent variable.
Jenny only can manipulate the independent variable and observe the effect on the dependent variable.
To be conclusive, other variables must be controlled, like the fabric and the amount of dirt of the t-shirts.
Several hormones are released during puberty. What are these hormones? How do they impact a teenager during puberty? Justify your answer.
A rock is thrown upward with an initial velocity of 9.6m/s to what hight does it rise and how long does it take to reach that high
Given:
u(initial velocity):9.6 m/s
at the maximum height final velocity =0
The acceleration acting on the body is gravity as it is free falling object
=-9.8m/s^2
Now we know that
v^2-u^2 = 2as
Where v is the final velocity measured in m/s
u is the initial velocity which is measured in m/s
a is the acceleration measured in m/s^2
s is the distance traveled by the rock in this case it is considered as the height
Substituting these values we get
0-9.6= 2 x -9.8 x s
s= 0.49 m
Consider t as the time taken for the rock to travel
v=u+at
0=9.6 -9.8t
t=0.98sec
What do you predict would happen if a person did aerobic exercise but did not work to build muscle?
If a person does aerobic exercise but does not work to build muscle, they may improve cardiovascular fitness and endurance, but may not see significant changes in muscle size or strength.
Explanation:Doing aerobic exercise without working to build muscle can have several effects. Aerobic exercise primarily targets and improves cardiovascular fitness, which includes strengthening the heart and improving lung capacity. However, without resistance training, muscle mass and strength may not significantly increase. This means that while a person may improve their endurance and cardiovascular health, they may not see significant changes in muscle size or strength.
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A team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the loaded sled with its rider has a mass of 210 kg. (a) Calculate the acceleration of the dogs starting from rest if each dog exerts an average force of 185 N backward on the snow. (b) Calculate the force in the coupling between the dogs and the sled.
Further Explanation:
As the dogs collectively full the sled on the wet snow surface, the sled will experience a net force due to all the dogs acting on it.
Part (a):
The net force applied by the 8 dogs on the sled is:
[tex]\begin{aligned}{F_{{\text{net}}}}&=8\timesF\\&=8\times185\\&=1480\,{\text{N}}\\\end{aligned}[/tex]
The net mass of the dog and the sled combined is:
[tex]\begin{aligned}M&=\left({8\times{m_d}}\right)+{m_s}\\&=\left({8\times19}\right)+210\\&=362\,{\text{kg}}\\\end{aligned}[/tex]
The net acceleration of the dogs and the sled combined is:
[tex]a=\frac{{{F_{net}}}}{M}[/tex]
Substitute the values of net force and mass in above expression.
[tex]\begin{aligned}a&=\frac{{1480}}{{362}}\\&=4.088\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\&\approx4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\\end{aligned}[/tex]
Thus, the acceleration of the dogs as they pull the sled on the snow is [tex]\boxed{4.09\,{{\text{m}}\mathord{\left/{\vphantom {{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}[/tex] .
Part (b):
Since the sled is moving with an acceleration of [tex]4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}[/tex] , the net force experienced by the sled due to the pull of the dogs is:
[tex]{F_{sled}}={m_s}\times a[/tex]
Substitute the values in above expression:
[tex]\begin{aligned}{F_{sled}}&=210\times4.09\\&=858.9\,{\text{N}}\\&\approx{\text{859}}\,{\text{N}}\\\end{aligned}[/tex]
Thus, the force experienced by the sled due to the dogs is [tex]\boxed{859\,{\text{N}}}[/tex] .
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Newton’s law of Motion
Keywords:
Team of eight dogs, waxed wood runners, loaded sled, with its rider, acceleration, average force 185 N, coupling between dog and sled, average masses of 19 kg each.
An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its speed, v, and obeys the equation Fdrag=(12.0N⋅s/m)v+(4.00N⋅s2/m2)v2. What is the terminal speed of this object?
Answer:
Terminal velocity of object = 12.58 m/s
Explanation:
We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.
Gravitational force = mg = 80 * 9.8 = 784 N
Drag force = [tex]12.0v+4.00v^2[/tex]
Equating both, we have
[tex]784=12.0v+4.00v^2\\ \\ v^2+3v-196=0\\ \\ (v-12.58)(v+15.58)=0[/tex]
So v = 12.58 m/s or v = -15.58 m/s ( not possible)
So terminal velocity of object = 12.58 m/s
A ball is on a horizontal, flat plane at the orgin of your axis system at t0. the ball has an initial velocity of 1.30m/s along the + y axis and, starting at t0 recieves an acceleration of 2.10 m/s^2 in the + x direction. at t= 2.50s a) what is the position of the ball in terms of its x and y coordinates? b) what is the displacement of the ball? c) what is the velocity of the ball?
It sounds like the ball's velocity along the [tex]y[/tex]-axis should be taken to be constant, in which case the ball has velocity vector
[tex]\mathbf v(t)=\left(2.10\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}[/tex]
We note that at [tex]t=t_0[/tex], we're told the ball is at the origin, so its position at this point is [tex]\mathbf r(t_0)=\mathbf 0[/tex]. We then integrate the velocity vector to find the position vector:
[tex]\mathbf r(t)=\mathbf r(t_0)+\displaystyle\int_{\tau=t_0}^{\tau=t}\mathbf v(\tau)\,\mathrm d\tau[/tex]
[tex]\mathbf r(t)=\displaystyle\int_{\tau=t_0}^{\tau=t}\left(2.10\,\dfrac{\mathrm m}{\mathrm s^2}\right)\tau\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}\,\mathrm d\tau[/tex]
[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)\tau^2\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\tau\,\hat{\jmath}\bigg|_{\tau=t_0}^{\tau=t}[/tex]
[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)(t^2-{t_0}^2)\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)(t-t_0)\,\hat{\jmath}[/tex]
For the sake of simplicity, I'll assume [tex]t_0=0[/tex], so that
[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)t\,\hat{\jmath}[/tex]
(a) Then at [tex]t=2.50\,\mathrm s[/tex], the ball's position in the plane is given by the vector
[tex]\mathbf r(2.50\,\mathrm m)=(6.56\,\mathrm m)\,\hat{\imath}+(3.25\,\mathrm m)\,\hat{\jmath}[/tex]
which is to say its position in the plane is at the point (6.56, 3.25).
(b) The ball's displacement is the same as its position, but in vector form (as above).
(c) The ball has velocity
[tex]\mathbf v(2.50\,\mathrm s)=\left(5.25\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\imath}+\left(1.3\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}[/tex]
That is, the ball has a speed of [tex]\|\mathbf v(2.50\,\mathrm s)\|=5.41\,\dfrac{\mathrm m}{\mathrm s}[/tex] and is traveling in a direction of about [tex]13.9^\circ[/tex] relative to the positive [tex]x[/tex]-axis.
At t=2.5s, the ball's position will be at coordinates (6.5625, 3.25), have a displacement of approximately 7.23 metres, and have a velocity of 5.25 m/s in the x direction and 1.3 m/s in the y direction.
Explanation:The subject of this question is physics, specifically kinematics, and the topic is motion in two dimensions. We will calculate the x and y coordinates, the displacement, and the velocity for the given conditions. First we will calculate the x-coordinate using the equation of motion x = ut + 0.5at^2, where 'u' is initial velocity, 'a' is acceleration and 't' is time. Here, the initial velocity along x-axis is zero, acceleration is 2.10 m/s^2, and time is 2.5 s. Substituting these values, we get x = 0 + 0.5 * 2.1 * (2.5)^2 = 6.5625 m.
Next, for the y-coordinate, since there is no acceleration along y-axis, its position at any time is given by y = ut, where 'u' is initial velocity along y-axis, and 't' is time. So, y = 1.30 * 2.50 = 3.25 m.
Next, the displacement, which is the shortest distance from the initial to the final position, can be found using the Pythagorean theorem, d = sqrt(x^2 + y^2). Thus, d = sqrt((6.5625)^2 + (3.25)^2) = 7.23 m approximately.
Lastly, the velocity of the ball at any point is given by v = u + at, where 'a' is the acceleration along the x-axis, 't' is time and 'u' is the initial velocity (which is zero in this case along the x-axis). So, v = 0 + 2.1 * 2.5 = 5.25 m/s along the + x-direction. And, the velocity along the y-axis remains constant as 1.30 m/s because there's no acceleration in the y direction.
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An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?
1. Define Newtons second law of motion (this will help put things into perspective)
2.Get the mass of the object (in this case 75 kg)
3.The net force acting on the object...find it (in this case 500 N)
4.Change the equation to F=ma (500=75a)
5.Divide both sides by 75 and that is the acceleration.
Answer:
Acceleration, [tex]a=6.66\ m/s^2[/tex]
Explanation:
Given that,
Force acting on the object, F = 500 N
Mass of the object, m = 75 kg
We need to find the acceleration of the object. The force acting on the object is given by :
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{500\ N}{75\ kg}[/tex]
[tex]a=6.66\ m/s^2[/tex]
So, the acceleration of the object is [tex]6.66\ m/s^2[/tex]. Hence, this is the required solution.
An object is moving with a constant velocity of 278m/s. how long will it take to travel 7500m
Velocity = 278m/s
Distance = 7500m
Time = How long it takes?
Time = Distance/Velocity = 7500m ÷ 278m/s = 26.98 seconds (Rounded up to nearest two decimal places)
Is density a physical change, chemical change, physical property, or a chemical property?
Final answer:
Density is a physical property of a substance, which can be observed and measured without changing the substance's chemical identity.
Explanation:
Density is a characteristic of a substance that refers to how much mass is contained in a given volume. It is considered a physical property because it can be observed and measured without changing the substance's chemical identity. Density can be particularly helpful in identifying substances and is measured in units such as grams per cubic centimeter (g/cm³) for solids and liquids or grams per liter (g/L) for gases.
Contrasting with physical properties are chemical properties, which describe how a substance can change or react to form new substances. These require a chemical change to be observed, such as rusting iron or burning wood, which both result in new chemical substances being formed.
Therefore, to answer the student's question, density is not a physical change, a chemical change, nor a chemical property; it is a physical property.
Dina is walking 0.5 m/s forward on a train that is traveling at 8.0 m/s north. What is Dina's velocity relative to the ground?
her velocity is 0.82012
Answer:
Dina's velocity relative to the ground is 7.5 m/s.
Explanation:
Given that,
Velocity of Dina v = 0.5 m/s
Velocity of train v' = 8.0 m/s
We need to calculate the Dina's relative velocity
Using formula of relative velocity
Relative velocity=velocity of train - velocity of Dina
[tex]v_{r}=v'-v[/tex]
Where, v' = Velocity of train
v = Velocity of Dina
Put the value into the formula
[tex]v_{r}=8.0-0.5[/tex]
[tex]v_{r}=7.5\ m/s[/tex]
Hence, Dina's velocity relative to the ground is 7.5 m/s.
Explain the value of using the International System if Units when describing motion. Provide an example that supports your reasoning
The value of using the International System of Units when describing motion is that these units are universally accepted - so an observer that uses these units to describe a motion in a place can compare his results to the results of the same experiment made by another obserber in a different place.
For example, if I measure the speed of a car, and I measure it is 20 m/s, and then another observer measures the speed of another car, and he finds it is 25 m/s, we are able to compare the two speeds and tell which one is greater. On the contrary, if we use two different units (e.g. km/h and miles/h), it would be difficult to compare the two results.