@pinkfloyd @taskmasters PLEASE HELP IM STUCK ONE QUESTION??/
Use the figure to answer the question that follows:

Segments UV and WZ are parallel with line ST intersecting both at points Q and R respectively

When written in the correct order, the two-column proof below describes the statements and reasons for proving that corresponding angles are congruent:


Statements Reasons
segment UV is parallel to segment WZ Given
Points S, Q, R, and T all lie on the same line. Given
I m∠SQT = 180° Definition of a Straight Angle
II m∠SQV + m∠VQT = 180° Substitution Property of Equality
III m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate
m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem
m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality
m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT
m∠SQV = m∠ZRS Subtraction Property of Equality
∠SQV ≅ ∠ZRS Definition of Congruency


Which is the most logical order of statements and reasons I, II, and III to complete the proof?

Answers

Answer 1

The correct logical order for the statements I, II, and III in the proof is: I. Definition of a Straight Angle, III. Angle Addition Postulate, and II. Substitution Property of Equality. This order supports the conclusion that corresponding angles, created by the transversal intersecting parallel lines, are congruent.

To complete the two-column proof that demonstrates the congruence of the corresponding angles when segments UV and WZ are parallel and line ST intersects both at points Q and R respectively, we need to place statements and reasons I, II, and III in the most logical order. This should allow us to show

corresponding angles are congruent, which is the ultimate aim of the proof.

The correct order of statements and reasons to complete the proof is:

Definition of a Straight Angle (I): We know that the angle measure of a straight line is 180°, hence m∠SQT = 180°.

Angle Addition Postulate (III): Based on the postulate, we can express m∠SQV + m∠VQT as equal to the measure of angle SQT because the two angles combine to form the straight angle, therefore m∠SQV + m∠VQT = m∠SQT.

Substitution Property of Equality (II): By substituting the equal values established in statements I and III, we get m∠SQV + m∠VQT = 180°.

After arranging the statements and their corresponding reasons, the proof logically demonstrates that the congruent angle pairs are a result of transversal ST intersecting parallel lines UV and WZ.


Related Questions

Select all that apply.

To solve an equation with a variable, which of the follow are done?

Inverse operations are used
Addition is always used
The variable needs to be isolated
The value of the variable should be guessed first

Answers

answer is inverse operations are used

Answer:

The variable needs to be isolated and inverse operations are used.

Please Help!! I have a 99 in this class. If I get a 45 on a project that’s worth 50% of my grade, what would my grade be?

Answers

So I always go to this site for grade calculations

https:// rogerhub. com   /final-grade-calculator/

So go down to "I already took my final" or something like that

So with you having a 99, then got a 45% on a project that's worth 50% of your grade, your grade unfortunately drops 72%.


solve
(b-2ya^2)(3b-3ya^2)

Answers

Here we are given the expression:

[tex](b-2ya^{2})(3b-3ya^{2})[/tex]

We will use foil method to solve this expression.

The word FOIL is an acronym for the four terms of the product:

First ("first" terms of each binomial are multiplied together)

Outer ("outside" terms are multiplied—that is, the first term of the first binomial and the second term of the second)

Inner ("inside" terms are multiplied—second term of the first binomial and first term of the second)

Last ("last" terms of each binomial are multiplied)

Using this method let us simplify our expression.

[tex](b-2ya^{2})(3b-3ya^{2})[/tex]

=[tex]3b^{2}-3bya^{2}-6bya^{2}+6y^{2}a^{4}[/tex]

Now combining like terms we have:

=[tex]3b^{2}-9bya^{2}+6y^{2}a^{4}[/tex]

Answer: [tex](b-2ya^{2})(3b-3ya^{2})[/tex] simplifies to [tex]3b^{2}-9bya^{2}+6y^{2}a^{4}[/tex]


Answer:

The answer is 3b² - 9bya² - 6y²a².

Explanation:

(b - 2ya²)(3b-3ya²)

3b² - 3bya²-6bya²-6ya²

3b² - 9bya² - 6y²a².

Answer would be 3b² - 9bya² - 6y²a².

Determine the graph behavior at the zero(s) of the polynomial function f(x)=x^2 - 6x+9

Answers

[tex]f(x)=x^2-6x+9=(x-3)^2[/tex]


This a perfect square so the x-axis is a tangent at x=3


The correct answer is C


See graph

Given function is f(x) = x² -6x +9.

It is a quadratic function whose graph is an upward open parabola.

The zero(s) of the given function would be at x-intercepts of the graph i.e. y = 0.

It means 0 = x² -6x +9

We can solve this quadratic equation using factorization as follows:-

0 = x² -6x +9

0 = x² -3x -3x +9

0 = x(x-3) -3(x-3)

0 = (x-3)(x-3)

Therefore, x = 3 with multiplicity two.

Hence, option C is correct, i.e. The graph of the function touches the x-axis at x = 3.

Which linear inequality is represented by the graph? y ≤ 1/2x + 2
y ≥ 1/2x + 2
y ≤ 1/3x + 2
y ≥ 1/3x + 2

Answers

Answer:

I can confirm that the answer is in fact A

Step-by-step explanation:

I took the test and got it right ( edge 2021 )

The linear inequality represented by the graph is y ≤ 1/2x + 2. The correct option is A.

What is inequality?

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to, > ‘greater than, or < ‘less than.

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

The given inequality y ≤ 1/2x + 2 is represented on the graph attached with the answer below.

In the graph, the linear line cut x-axis at ( -4, 0 ) and y-axis at ( 0, 2 ). And inequality covers the whole space below the line y = 1/2x + 2.

The linear inequality represented by the graph is y ≤ 1/2x + 2. The correct option is A.

To know more about inequality follow

https://brainly.com/question/24372553

#SPJ5

The 1906 earthquake in San Francisco had a magnitude of 8.3 on the richter scale. At the same time in Japan an earthquake with magnitude of 4.9 caused minor damage. How many times more was the San Francisco earthquake that the Japan earthquake?

Answers

In 1906 in San Francisco the magnitude of earthquake on richter scale was 8.3.

In the same year the magnitude of earthquake on richter scale in Japan was 4.9.

Now we have to find how many times more was the San Francisco earthquake that the Japan earthquake.

The amount of energy released in an earthquake is very large, so a logarithmic scale avoids the use of large numbers.



The formula used for these calculations is:

[tex]M=log_{10}(\frac{I}{I_{0}})[/tex]

Where M is the magnitude on the richter scale,  I is the intensity of the earthquake being measured and I₀ is the intensity of a reference earthquake.

So because the magnitude is a base 10 log, the Richter number is actually the exponent that 10 is raised to in order to calculate the intensity of the earthquake.



So the difference in magnitudes of the earthquakes can be calculated as follows:

[tex]M=log_{10}(\frac{10^{8.3}}{10^{4.9})}[/tex]

M=3.4

Answer: The San Francisco earthquake was 3.4 times more than Japan earthquake.

Final answer:

The San Francisco earthquake released approximately 2510 times more energy than the earthquake in Japan, calculated using the Richter scale.

Explanation:

To determine how many times stronger the San Francisco earthquake was compared to the earthquake in Japan, we refer to the Richter scale, which is a logarithmic scale. A one-unit increase on this scale represents a ten-fold increase in amplitude of the seismic waves and roughly a thirty-fold increase in energy released. Therefore, to calculate the difference between a magnitude 8.3 earthquake and a magnitude 4.9 earthquake, we subtract the smaller magnitude from the larger one (8.3 - 4.9 = 3.4) and then calculate 10 raised to the power of this difference.

[tex]10^(3.4)[/tex] = 10 x 10 x 10 x 2.51 (approximately), which simplifies to about 2510 times more energy released by the San Francisco earthquake compared to the earthquake in Japan.

#1.-7/9 x 3/5 a.-27/45 b.-7/15c.7/15 d.27/45

Answers

Answer: B


Step-by-step explanation:

[tex]\frac{-7}{9} * \frac{3}{5} = \frac{-7(3)}{9(5)} = \frac{-7(3)}{3 * 3(5)} = \frac{-7}{3(5)} = \frac{-7}{15}[/tex]

is 106.06 bigger than 106.60? I really hate math and i got normal schoolwork to do as well

Answers

106.60 is bigger round up on it and you get 107

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Answers

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the [tex] x^2 [/tex] coefficient is 1, i.e. the equation is written like [tex] x^2+bx+c=0 [/tex], then you can say the following about the coefficients b and c:

[tex] b [/tex] is the opposite of the sum of the roots[tex] c [/tex] is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

[tex] 4+(-2) = 4-2 = 2 \implies b = -2 [/tex][tex] 4 \cdot (-2) = -8 \implies c = -8 [/tex]

So, the equation is [tex] x^2-2x-8=0 [/tex]

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

[tex] \dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4} [/tex][tex] \dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8} [/tex]

And so the equation is

[tex] x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0 [/tex]

In order to have integer coefficients, you can multiply both sides of the equation by 8:

[tex] 8x^2 - 10 + 3 = 0 [/tex]

Jennifer grandmother buys carrots at the farm stand she and her three grandchildren equally shares the carrots the total weight of the carrots is 28kg how many kilograms of carrots will jennifer get

Answers

Solution: We are given that the Jennifer's grandmother bought 28 kg of carrot.

Also we are given that 28 kg of carrot are to be divided into 4 persons.

Therefore, the number of kilograms of carrots that Jennifer will get is:

[tex]\frac{28}{4}[/tex]

[tex]7[/tex] kg

[tex]\therefore[/tex] Jennifer gets 7 kilograms of carrot.

Antoni has read 147 pageof book.He completed 70% of book.How many more pages does he need to read to finish the book

Answers

in total there is 210 pages. so 210 subtract 147 is 63

Matter is anything that

A. has mass and takes up space.
B. has only one physical state.
C. is important to human society.
D. contains two elements combined chemically.

Answers

A. has mass and takes up space :)

The answer is A. Matter is anything that has mass and takes up space

math help what is x? please keep

Answers

Apples = X

Pears = Y

3x+2y = 0.60

pears cost 2X-0.05 replace Y with this:

3X +2(2x-0.05) = 0.60

Simplify:

3X + 4X-0.10 = 0.60

Simplify:

7X -0.10 = 0.60

Add 0.70 to each side:

7X = 0.70

Divide both sides by 7:

X = 0.70 / 7

X = 0.10


Apples cost 0.10 each.

Pears cost 2x-0.05 = 2(0.10) - 0.05 = 0.20 - 0.05 = 0.15 each

Writing Polynomial Function Given a y-Intercept

Answers

We already got

f(x)= a(x-2)(x-3)(x-5)

We got [tex]a=\frac{1}{6}[/tex]

first we multiply the parenthesis in f(x)

f(x)= a(x-2)(x-3)(x-5)

[tex]f(x)= a(x^2-5x+6)(x-5)[/tex]

[tex]f(x) = a(x^3 - 10 x^2 + 31 x - 30)[/tex]

Replace the value of 'a'

[tex]f(x) = \frac{1}{6}(x^3 - 10 x^2 + 31 x - 30)[/tex]

Multiply 1/16 inside the parenthesis

[tex]f(x) = \frac{1}{6}x^3 - \frac{5}{3} x^2 + \frac{31}{6} x - 5[/tex]

HELP ASAP PLEASE!!!

How many seconds are there in 782 minutes?

Use the factor: 1 min= 60 sec

A. 782 sec
B. 13 sec
C. 46,920 sec
D. 0.077 sec

Answers

C. 46,920 seconds is your answer

Answer:


Step-by-step explanation:

C. 46,920 sec

Adding mixed numbers. Could someone explain this to me please?

find the sum or difference

5/6 + 4/9

a. 1 1/2
b. 1 5/18
c. 9/18
d. 1/2

Answers

to do this you must find the LCD which is 18 to get a denominator from 5/6 you multiple everything by 3 so 15/18 and to get that from 4/9 you multiply everything by 2 so 8/18 then you add 15 and 8 for 23 which would be 23/18 then you do 23 minus 18 which is 5 so it would be b. 1 5/18

An albatross can fly 400 kilometers in 8 hours at a constant speed using d as distance and t as number of hours. An equation that represents this situation is d=50t what are two contants of proportionality for the relationship between distance in kilometers and number of hours? What is the relaionship between the two values?

Answers

Answer:

Constant of Proportionality is 50.  

Step-by-step explanation:

Albatross can fly 400 kilometers in 8 hours.

'd' represents the distance and 't' represents the number of hours.

The equation [tex]d=50t[/tex] represents the relationship between the distance and time.

Now, in the equation shown above 50 is the constant of proportionality, and 50 represents the rate of change of distance with time.

The constant of proportionality tells us the rate of change between two variables.

So for every 1 hour of time the distance covered is 50 kilometers.  

 

For a store contest,4 out of every 65 people who visited the store will receive a free dvd. If 455 people visit the store, how many dvds were given?

Answers

Answer:

28  dvds were given if 455 people visit the store.

Step-by-step explanation:

4 out of every 65 people who visited the store will receive a free dvd.

Suppose,  [tex]x[/tex]  dvds were given if 455 people visit the store.

Now, according to the ratio of "people who got dvd"  to "total number of people" , the equation will be.........

[tex]\frac{4}{65}=\frac{x}{455}\\ \\ 65x= 455*4=1820\\ \\ x=\frac{1820}{65}=28[/tex]

So, the number of dvds given is 28.

Answer:

28

Step-by-step explanation:

Given that there is a store contest.  Out of 65 people who visit the store only 4 will be receiving a free dividend.

Remaining 61 will not receive.

There were 455 people who visited the stores.

Of these 455/65 times 4 persons would be given dividends.

i.e. Since 4 out of 65 would be given

no of visitors who received dividend= 455(4)/65 = 7(4) = 28

Hence answer is 28 persons would receive dividend.


Simplify the algebraic expression 3(2x+3y)-(4x+2y

Answers

Hola!

First you simplify the brackets
3(2x+3y)-4x-2y

Expand
6x+9y-4x-2y

Collect like terms
(6x-4x)+(9y-2y)

Simplify
2x+7y

Hope it helps!

What can be concluded about the sequence? The common ratio of the sequence is 2. The common difference of the sequence is 2. The next term of the sequence is represented by the point (5, 64). The next term of the sequence is represented by the point (5, –64).

Answers

Final answer:

The given information suggests that the sequence is a geometric sequence. The common ratio is 2, and the common difference is 2. The next term of the sequence can be found using the coordinates (5, 64) and (5, -64).

Explanation:

The given information about the sequence suggests that it is a geometric sequence.

If the common ratio is 2, it means that each term is obtained by multiplying the previous term by 2.

If the next term is represented by the point (5, 64), it means that the 5th term of the sequence is 64. Using the formula for a geometric sequence, we can find the first term: a * (2^(5-1)) = 64, where a is the first term of the sequence.

Similarly, if the next term is represented by the point (5, -64), it means that the 5th term of the sequence is -64. Using the formula for a geometric sequence, the first term is -8.

If 6 times a number is added to -4, the result is 10 times the number. Find the number.

Answers

the number is - 1

let the number be n then 6 times the number is 6n and added to -4 is

- 4 + 6n = 10n ( equal to 10 times the number )

subtract 6n from both sides

- 4 = 4n ( divide both sides by 4 )

[tex]\frac{-4}{4}[/tex] = n , hence n = - 1


If a and b are integers and 71 < ab < 76, then all of the following could be the values of b except: (A) 18 (B) 8 (C) 12 (D) 7 (E) 5

Answers

We are given that

a and b are integers and 71 < ab < 76

We will check each options

option-A:

b=18

we can plug it

[tex]71<a(18)<76[/tex]

we can divide both sides by 18

[tex]\frac{71}{18} <b<\frac{76}{18}[/tex]

now, we can simplify it

[tex]3.944<a<4.222[/tex]

Since, 'a' is a integer

so, a=4 lies on interval

so, this interval is true

so, this is FALSE

option-B:

b=8

we can plug it

[tex]71<a(8)<76[/tex]

we can divide both sides by 8

[tex]\frac{71}{8} <b<\frac{76}{8}[/tex]

now, we can simplify it

[tex]8.875<a<9.5[/tex]

Since, 'a' is a integer

so, a=9 lies on interval

so, this interval is true

so, this is FALSE

option-C:

b=12

we can plug it

[tex]71<a(8)<76[/tex]

we can divide both sides by 12

[tex]\frac{71}{12} <b<\frac{76}{12}[/tex]

now, we can simplify it

[tex]5.9166<a<6.333[/tex]

Since, 'a' is a integer

so, a=6 lies on interval

so, this interval is true

so, this is FALSE

option-D:

b=7

we can plug it

[tex]71<a(5)<76[/tex]

we can divide both sides by 7

[tex]\frac{71}{7} <b<\frac{76}{7}[/tex]

now, we can simplify it

[tex]10.14285<a<10.857[/tex]

Since, 'a' is a integer

so, no integer lies on this interval

so, this interval is false

so, this is TRUE

option-E:

b=5

we can plug it

[tex]71<a(5)<76[/tex]

we can divide both sides by 5

[tex]\frac{71}{5} <b<\frac{76}{5}[/tex]

now, we can simplify it

[tex]14.2<a<15.2[/tex]

Since, 'a' is a integer

so, a=15

so, this interval is true

so, this is FALSE


Jerry walked a dog from 6:40 am to 7:30am . If he was paid $6 per hour how much did he earn

Answers

Answer:

Amount Jerry earned is $5

Step-by-step explanation:

Jerry is paid $6 per hour.

First we need to find the number of hours he walked the dog.

From 6.40 am to 7.30 am we have 50 minutes. Jerry walked the dog for 50 minutes.

An hour has 60 minutes.

We need to find how much Jerry gets paid for a minute.

Amount paid for a minute     = [tex]\frac{$6}{60}[/tex]

                                               =$[tex]0.1[/tex]

Therefore,

Amount paid for 50 minutes = $[tex]0.1[/tex] * [tex]50[/tex] minutes

                                                =$[tex]5[/tex]

Find the distance between -3 and 4. A) -12 eliminate b) -7 c) -1 d) 7

Answers

The formula of a distance between A and B = |B - A|.

We have -3 and 4. Substitute:

|4 - (-3)| = |4 + 3| = |7| = 7

Answer: d) 7

7.67,7,7.72,7.38 least to greatest

Answers

7 , 7.38, 7.67, 7.72

What is the factored form of the expression over the complex numbers?

121x^2+36y^2


(11x−6iy)(11x−6iy)

(11x+6y)(11x−6y)

(11x+6iy)(11x−6iy)

(11x+6iy)(11x+6iy)

Answers

It's the third answer. This is because since there is no middle term where both variables are combined, that would lead to the signs of the 2 factors to be different. However, that still leaves 2 answers, 3 and 2. If we were to square i, you would get -1. This is because √-1 is equal to i. i^2 would be -1. Since the sign in the unfactored expression is positive and not negative, that would mean that the i in the factoring turned it around. that leads us to believe that answer 3 is the correct answer.

(11x + 6y)(11x - 6y)
This is my answer

Last year a business had profits of 8,000 this year it profit are five time as great what are this year profits

Answers

the profit this year will be 40, 000

Keri walks her dog every morning the length of the walk is 0.55 km on each weekday on each weekend day the walk is 1.4 times as long as a walk on a weekday how many kilometers does keri walk in one week

Answers

Final answer:

Keri walks approximately 4.29 kilometers in one week.

Explanation:

Keri walks her dog every morning. On weekdays, the length of the walk is 0.55 km. On weekends, the walk is 1.4 times as long as a walk on a weekday. To find out how many kilometers Keri walks in one week, we need to calculate the total distance she walks on weekdays and weekends.

Distance walked on weekdays = 0.55 km per day

Distance walked on weekends = 1.4 * 0.55 km per day = 0.77 km per day

Total distance walked in one week = (distance on weekdays * number of weekdays) + (distance on weekends * number of weekends)

Since there are 5 weekdays and 2 weekend days in a week, we can calculate the total distance:

Total distance walked in one week = (0.55 km * 5) + (0.77 km * 2) = 2.75 km + 1.54 km = 4.29 km

Keri walks approximately 4.29 kilometers in one week.

If x > 0 and y < 0, where is the point (x, y) located?

Answers

If x > 0 and y < 0 then the point (x, y) is located in Quadrant IV.

Look at the picture.

Answer:

II

Step-by-step explanation:

A 20-foot length of wire is to be cut into 2 pieces, so that the longer piece is two feet longer than two times the shorter piece. Find the length of each piece.

Answers

2x+2=20-x

3x=18

x=6

2nd=14

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