At the Kansas City Airport, a group of pilots for Skyways and Yellow Jet airlines were asked whether their flights were flying east or west. The two-way table shows their answers. Which joint frequency has the most flights?

A) Skyways, going east
B) Skyways, going west
C) Yellow jet, going east
D) Yellow jet, going west

Answers

Answer 1

The frequency has the most flights from the airlines is C. Yellow jet, going east.

What is a frequency table?

The frequency table is a table that's used to illustrate the data that's given.

In this case, the frequency has the most flights from the airlines will be Yellow jet, going east. This is because most people are going in that direction.

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Answer 2

The joint frequency with the most flights is yellow jets going east.

Option C is the correct answer.

What is a joint frequency?

Joint frequency refers to the number of observations that fall in each category when we have two categorical variables.

We have,

To determine which joint frequency has the most flights, we need to look for the highest value in the table.

From the table,

We can see that the highest value is 35, which represents the number of yellow jets going east.

Therefore,

The joint frequency with the most flights is yellow jets going east.

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At The Kansas City Airport, A Group Of Pilots For Skyways And Yellow Jet Airlines Were Asked Whether

Related Questions

We will now find the probability that at least one child is a female. The problem asks us to notice that the complement of the event "all three children are male" is "at least one of the children is female." Recall that the probability of the complement of an event is given by 1 − P(event). Therefore, the probability that at least one child is a female can be calculated using the following formula. P(at least one child is female) = 1 − P(all three children are male) We previously determined that P(all three children are male) = 1 8 . Applying this value to the formula allows us to calculate the probability that at least one child is a female. Enter your probability as a fraction. P(at least one child is female) = 1 − P(all three child

Answers

Answer:

[tex]\displaystyle \frac{7}{8}[/tex].

Step-by-step explanation:

If two events are complements, then the sum of their probabilities should be [tex]1[/tex].

This question suggests that the following two events are complements:

At least one child is female.All three children are male.

As a result:

[tex]\begin{aligned}& P(\text{at least one child is female}) \\ &= 1 - P(\text{all three children are male})\end{aligned}[/tex].

According to the question,

[tex]\displaystyle P(\text{all three children are male}) = \frac{1}{8}[/tex].

Therefore,

[tex]\begin{aligned}& P(\text{at least one child is female}) \\ &= 1 - P(\text{all three children are male}) \\ &= 1 -\frac{1}{8} \\ &= \frac{7}{8}\end{aligned}[/tex].

Final answer:

In this Mathematics problem of probability, the calculation required was for the probability of 'at least one child being female'. This is a complementary event to 'all three children being male', enabling us to solve it by using the formula P(at least one child is female) = 1 - P(all three children are male). Hence, the answer equals 7/8.

Explanation:

The subject of the question is probability, which is a branch of Mathematics. Looking at the question, the probability of having all three children as males has been given as 1/8. We are required to find the probability of having 'at least one female child'. This event is complementary to having 'all three children as males', so we can find the solution using the formula you stated. As P(all three children are male) = 1/8, therefore P(at least one child is female) = 1 - 1/8 = 7/8.

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We wish to estimate the population mean of a variable that has standard deviation 70.5. We want to estimate it with an error no greater than 5 units with probability 0.99. How big a sample should we take from the population? What happens if the standard deviation and the margin of error are both doubled?

Answers

Answer:

a) The large sample size 'n' = 1320.59

b) If the standard deviation and the margin of error are both doubled also the sample size is not changed.

Step-by-step explanation:

Explanation:-

a)

Given data the standard deviation of the population

σ = 70.5

Given the margin error = 5 units

We know that the estimate of the population mean is defined by

that is margin error = [tex]\frac{z_{\alpha } S.D }{\sqrt{n} }[/tex]

            [tex]M.E = \frac{z_{\alpha } S.D }{\sqrt{n} }[/tex]

cross multiplication , we get

[tex]M.E (\sqrt{n} ) = z_{\alpha } S.D[/tex]

[tex]\sqrt{n} = \frac{z_{\alpha } S.D }{M.E }[/tex]

[tex]\sqrt{n} = \frac{2.578 X 70.5}{5} }[/tex]

√n = 36.34

squaring on both sides , we get

n = 1320.59

b) The margin error of the mean

   [tex]\sqrt{n} = \frac{z_{\alpha } S.D }{M.E }[/tex]

the standard deviation and the margin of error are both doubled

  √n = zₓ2σ/2M.E

  √n = 36.34

squaring on both sides , we get

     n = 1320.59

If the standard deviation and the margin of error are both doubled also the sample size is not changed.

ABCD is a trapezoid. Solve for x and y ​

Answers

Given:

The given figure ABCD is a trapezoid.

The measure of ∠A is (2x + 32).

The measure of ∠B is 112°

The measure of ∠C is y.

The measure of ∠D is 46°

We need to determine the value of x and y.

Value of x:

We know the property that the adjacent angles in a trapezoid are supplementary.

Thus, we have;

[tex]\angle A+\angle B=180[/tex]

Substituting the values, we get;

[tex]2x+32+112=180[/tex]

       [tex]2x+144=180[/tex]

                 [tex]2x=36[/tex]

                   [tex]x=18[/tex]

Thus, the value of x is 18.

Value of y:

The value of y can be determined using the property that the adjacent angles of a trapezoid are supplementary.

Thus, we have;

[tex]\angle C+\angle D=180[/tex]

    [tex]y+46=180[/tex]

            [tex]y=134[/tex]

Thus, the value of y is 134.

Hence, Option c is the correct answer.

Let X be the temperature in at which a certain chemical reaction takes place, and let Y be the temperature in (so Y = 1.8X + 32). a. If the median of the X distribution is , show that 1.8 + 32 is the median of the Y distribution. b. How is the 90th percentile of the Y distribution related to the 90th percentile of the X distribution? Verify your conjecture. c. More generally, if Y = aX + b when a is non-zero, how is any particular percentile of the Y distribution related to the corresponding percentile of the X distribution? Distinguish the two cases when a is positive and when a is negative.

Answers

Answer:

See explanation

Step-by-step explanation:

Solution:-

The random variable, Y be the temperature of chemical reaction in degree fahrenheit be a linear expression of a random variable X : The  temperature in at which a certain chemical reaction takes place.

                             Y = 1.8*X + 32

- The median of the random variate "X" is given to be equal to "η". We can mathematically express it as:

                             P ( X ≤ η ) = 0.5

- Then the median of "Y" distribution can be expressed with the help of the relation given:

                             P ( Y ≤ 1.8*η + 32 )

- The left hand side of the inequality can be replaced by the linear relation:

                             P ( 1.8*X + 32 ≤ 1.8*η + 32 )

                             P ( 1.8*X ≤ 1.8*η )   ..... Cancel "1.8" on both sides.

                            P ( X ≤ η ) = 0.5 ...... Proven

Hence,

- Through conjecture we proved that: (1.8*η + 32) has to be the median of distribution "Y".

b)

- Recall that the definition of proportion (p) of distribution that lie within the 90th percentile. It can be mathematically expressed as the probability of random variate "X" at 90th percentile :

                             P ( X ≤ p_.9 ) = 0.9 ..... 90th percentile

- Now use the conjecture given as a linear expression random variate "Y",

          P ( Y ≤ 1.8*p_0.9 + 32 ) = P ( 1.8*X + 32 ≤ 1.8*p_0.9 + 32 )

                                                 = P ( 1.8*X ≤ 1.8*p_0.9 )

                                                 = P ( X  ≤ p_0.9 )

                                                 = 0.9

- So from conjecture we saw that the 90th percentile of "X" distribution is also the 90th percentile of "Y" distribution.

c)

- The more general relation between two random variate "Y" and "X" is given:

                            Y = aX + b

Where, a : is either a positive or negative constant.

- Denote, (np) as the 100th percentile of the X distribution, so the corresponding 100th percentile of the Y distribution would be : (a*np + b).

- When a is positive,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≤ p_% )

                                                 = np_%        

- When a is negative,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≥ p_% )

                                                 = 1 - np_%        

                                                           

Final answer:

In a temperature conversion equation Y = 1.8X + 32, medians and percentiles of Y are related to the corresponding values of X through the equation itself. For an arbitrary linear transformation Y = aX + b, percentiles of Y and X are related as aX + b, with ordering depending on the sign of a.

Explanation:

Lets start by talking about the relationship between X and Y. In the context of the temperature conversion between Celsius (X) and Fahrenheit (Y), Y equals to 1.8 times X plus 32.

1. If the median of X is M, substituting M into the equation Y = 1.8X + 32 gives the median of Y as 1.8M + 32, since the transformation is linear.

2. The 90th percentile of the Y distribution will relate to the 90th percentile of X distribution in a similar fashion. If we denote the 90th percentile of X as P, then the 90th percentile of Y will be 1.8P + 32.

3. For a general linear transformation Y = aX + b, where a is non-zero, any percentile of Y is related to the corresponding percentile of X as aX + b. If a is positive, the transformation will preserve the ordering of percentiles (e.g., higher values of X correspond to higher values of Y). If a is negative, it will reverse the ordering of percentiles (e.g., higher values of X will correspond to lower values of Y).

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I have a triangle that adds up to 180 but the answers rhat it gives is acute,obtuse and right

Answers

Answer:

  classification is based on the measure of the largest angle

Step-by-step explanation:

Every triangle will have angle measures that add up to 180°. The classification as to acute, right, or obtuse is based on the largest angle.

__

If the largest angle is less than 90°, the triangle is acute.

If the largest angle is equal to 90°, the triangle is right.

If the largest angle is greater than 90°, the triangle is obtuse.

__

Because you know the angle sum is always 180°, you can generally figure out what kind of triangle it is from the sum of two of the angles. If both are less than 90° and their sum is more than 90°, then the triangle will be acute, for example.

How do you covert feet into yard

Answers

3 feet = 1 yard so divide a the feet by three

Answer:

1 yard

Step-by-step explanation:

3/5 times 2 i need help

Answers

Answer:

6/5

Step-by-step explanation:

[tex]\frac{3}{5} * 2 = \frac{6}{5}[/tex]

please give me brainliest

Answer:

1.2 [Decimal Form]

[tex]\frac{6}{5}[/tex] [Exact Form]

[tex]1\frac{1}{5}[/tex] [Mixed Number Form]

Because of the commutative property of multiplication, it is true that
3/4 × 4 = 4 × 3/4. However, these expressions can be calculated in different ways even though the solutions will be the same.
Below, show two different ways of solving this problem.
First, show how 3/4 x 4 can be solved using repeated addition.

Answers

Answer:

1.  3/4 + 3/4 + 3/4 +3/4

2. 0.75 * 4

Step-by-step explanation:

1. add 3/4 four times

3/4 + 3/4 + 3/4 +3/4

2. You can turn 3/4 into a decimal.  3/4 =0.75

0.75 * 4

Final answer:

3/4 × 4 can be solved through repeated addition by adding 3/4 to itself four times to get 9/4 or 2 1/4. Alternatively, by simplifying before multiplying, recognizing that 4 is the reciprocal of 1/4, we easily find that the product is 3.

Explanation:

When solving 3/4 × 4 using repeated addition, we use the concept that multiplying a number by a whole number is the same as adding that number to itself that many times. In this case, 3/4 is added to itself 4 times:

3/4 + 3/4 + 3/4 + 3/4

We have four 3/4's, and when we add them up, we get:

3/4 + 3/4 = 3/2 (or 1 1/2)3/2 + 3/4 = 6/4 (or 1 1/2)

When we add 3/2 (1 1/2) and 3/4, we can convert 1 1/2 into 6/4 to make it easier to add the fractions, obtaining:

6/4 + 3/4 = 9/4 (or 2 1/4)

Therefore, 3/4 × 4 equals 9/4 or 2 1/4 through repeated addition.

Another way to approach the problem is by simplifying before multiplying. Since we are multiplying by 4, which is the reciprocal of 1/4, we can simplify by understanding that:

3/4 × 4/1 = (3 × 4) / (4 × 1) = 12/4 = 3

Thus, by canceling out the common factors (4 in the numerator and 4 in the denominator), the multiplication becomes 3 × 1, which equals 3. This satisfies the condition that as long as we perform the same operation on both sides of the equals sign, the expression remains an equality.

Ian’s house and land have a market price of 225,000 and an assessed value of 55% of that amount.His state has a property tax rate of .088 how much does Ian pay in property taxes every year

Answers

Answer:

C.

Step-by-step explanation:

The amount of property tax that Ian pays is $10,890.

What is property tax?

Tax is a compulsory sum of money levied on goods and services by the government. Property tax is the tax paid on property that is owned by an individual or group of individuals.

What is the property tax paid?

Property tax = tax rate x assessed value x market price

0.088 x 0.55 x 225,000 = $10,890

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Before a new phone system was installed, the amount a company spent on personal calls followed a normal distribution with an average of $900 per month and a standard deviation of $50 per month. Refer to such expenses as PCE's (personal call expenses). Using the distribution above, what is the probability that during a randomly selected month PCE's were between $775.00 and $990.00

Answers

Answer: the probability that during a randomly selected month, PCE's were between $775.00 and $990.00 is 0.9538

Step-by-step explanation:

Since the amount that the company spent on personal calls followed a normal distribution, then according to the central limit theorem,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = $900

σ = $50

the probability that during a randomly selected month PCE's were between $775.00 and $990.00 is expressed as

P(775 ≤ x ≤ 990)

For (775 ≤ x),

z = (775 - 900)/50 = - 2.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.0062

For (x ≤ 990),

z = (990 - 900)/50 = 1.8

Looking at the normal distribution table, the probability corresponding to the z score is 0.96

Therefore,

P(775 ≤ x ≤ 990) = 0.96 - 0.0062 = 0.9538

Final answer:

The probability that PCE's were between $775 and $990 is 0.9579 or 95.79%.

Explanation:

To find the probability that the PCE's were between $775 and $990 during a randomly selected month, we first need to standardize the values using the standard normal distribution. Formula for standardization is:



Z = (X - μ) / σ



where X is the value, μ is the mean, and σ is the standard deviation.



Using the formula, we calculate the standard scores for the given values:



Z1 = ($775 - $900) / $50 = -2.50

Z2 = ($990 - $900) / $50 = 1.80



Next, we use the standard normal distribution table or a calculator to find the corresponding probabilities for these z-scores. The probability between the z-scores -2.50 and 1.80 is the difference between their corresponding cumulative probabilities:



Prob(Z1 < Z < Z2) = Prob(Z < Z2) - Prob(Z < Z1)



Using the standard normal distribution table, we can find the probabilities:



Prob(Z < -2.50) = 0.0062

Prob(Z < 1.80) = 0.9641



Finally, we calculate the probability between the z-scores:



Prob(Z1 < Z < Z2) = 0.9641 - 0.0062 = 0.9579



Therefore, the probability that PCE's were between $775 and $990 during a randomly selected month is approximately 0.9579 or 95.79%.

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A marine sales dealer finds that the average price of a previously owned boat is $6492. He decides to sell boats that will appeal to the middle 66% of the market in terms of price. Find the maximum and minimum prices of the boats the dealer will sell. The standard deviation is $1025, and the variable is normally distributed.

Answers

Answer:

The maximum price that the dealer will sell is $7471 and the minimum is $5513.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 6492, \sigma = 1025[/tex]

He decides to sell boats that will appeal to the middle 66% of the market in terms of price.

50 - (66/2)  = 17th percentile

50 + (66/2) = 83rd percentile

17th percentile

X when Z has a pvalue of 0.17. So X when Z = -0.955.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.955 = \frac{X - 6492}{1025}[/tex]

[tex]X - 6492 = -0.955*1025[/tex]

[tex]X = 5513[/tex]

83rd percentile

X when Z has a pvalue of 0.83. So X when Z = 0.955.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.955 = \frac{X - 6492}{1025}[/tex]

[tex]X - 6492 = 0.955*1025[/tex]

[tex]X = 7471[/tex]

The maximum price that the dealer will sell is $7471 and the minimum is $5513.

Final answer:

The marine sales dealer plans to sell boats between $5467 and $7517 to appeal to the middle 66% of market prices. These figures are computed by adding or subtracting one standard deviation from the average price.

Explanation:

In this scenario, the marine sales dealer wants to price boats that appeal to the middle 66% of the market, which means the dealer wants to avoid the top and bottom 17% of the market (as 100%-66%=34% and 34%/2=17%). Therefore, we need to find the boats' prices that are 1 standard deviation away from the mean, since in a normal distribution, approximately 68% of values lie within 1 standard deviation from the mean (closest to 66%).

The standard deviation given is $1025. Thus, the maximum price of the boats the dealer will sell is the mean price plus one standard deviation:

 

$6492 + $1025 = $7517

And the minimum price is the mean price minus one standard deviation:

$6492 - $1025 = $5467

Therefore, the dealer will sell boats priced between $5467 and $7517 to appeal to the middle 66% of the market.

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A big ship drops its anchor.
E represents the anchor's elevation relative to the water's surface (in meters) as a function of time t (in seconds).
E=−2.4t+75
How far does the anchor drop every 5 seconds?

Answers

In the equation t is the amount of time in seconds. The -2.4 is the distance it travels in 1 second.

-2.4 x 5 seconds= -12 meters.

The anchor dropped 12 (-12) meters in 5 seconds.

Answer:

C) It took 22 seconds for the anchor to reach the water's surface.

E) The equation E = 44 − ST can be used to model this situation.

Step-by-step explanation:

The table shows the dimensions of four wedges.

A 3-column table with 4 rows. The first column has entries W, X, Y, Z. The second column labeled thickness at widest part (inches) has entries 2, 4, 3, 5. The third column labeled slope (inches) has entries 5, 8, 9, 10.

Which wedge requires the least amount of force to do a job?

W
X
Y
Z

Answers

Answer:

Wedge Z requires the least amount of force to do a job.

Step-by-step explanation:

In physics, Work is defined as the energy needed to move certaing object through a certain distance. Specifically, the work done is directly proportional to the force exerted and the distance.

It's important to know that a change of point is needed to have actually work done, physically speaking. This means if the object doesn't move, then there's no work done.

Mathematically, the work is defined

[tex]W= F \times d[/tex]

Isolating the force

[tex]F=\frac{W}{d}[/tex]

So, notice that the distance is inversely proportional to the force needed, which means the less distance, more force we need.

Now, the problem is giving wides and slopes, which we can use to find heights. And we know already that the less distance we have, the greater force we need, or the most distance, the least force.

Let's find which wedge has the greatest vertical distance.

[tex]m=\frac{y}{x}[/tex]

Wedge 1.

[tex]5=\frac{y}{2} \implies y=10[/tex]

Wedge 2.

[tex]8=\frac{y}{4} \implies y=32[/tex]

Wedge 3.

[tex]9=\frac{y}{3} \implies y=27[/tex]

Wedge 4.

[tex]10=\frac{y}{5}\\ y=50[/tex]

Notice that the last wedge has greater vertical distance, that means Wedge Z requires least amount of force to do a job.

Answer:

The correct answer is Y not Z.

Step-by-step explanation:

Daniel is paying $600 for his auto insurance, and he is wondering if he is overpaying compared to his friends. He sent an email to all his friends in his contact list, and 9 of them replied with their paid amount. Suppose the 9 friends who replied are a random sample, and the paid amount for auto insurance has approximately a normal distribution. What can you conclude on the study?

564 578 478 507 621 564 489 612 538

Answers

Final answer:

Daniel appears to be paying more for auto insurance compared to the average amount his friends pay based on the data from nine friends. However, as the data only represents a sample, and auto insurance rates can vary widely, additional comparison or the advice of an insurance specialist is recommended.

Explanation:

To determine if Daniel is overpaying for his auto insurance, we can compare his insurance cost to the average price paid by his friends. To do this, we need to calculate the mean (average) of his friends' insurance amounts.

Here are the amounts his friends pay: 564, 578, 478, 507, 621, 564, 489, 612, 538.

Adding these together gets a total of 4951. There are nine friends, so we divide 4951 by 9 to get an average cost of 550.

Since Daniel is paying $600, which is more than the average of $550, it seems he's spending more than his friends for auto insurance.

However, we only have the data from a sample of his friends. The insurance amounts can have a wide range, depending on several factors like age, driving records, the type of vehicle insured, and geographic location. Therefore, it's recommended that Daniel compare his rate with more people or consult with an insurance specialist for a more accurate conclusion.

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Which expression is equivalent to 1/4-3/4x

Answers

Answer:

1/4(1-3x)

Step-by-step explanation:

First she asked five drama club members in her
homeroom how many tickets they had sold. Then she
took ten random samples from the entire drama club of
75 students
Drama Club Data of Tickets Sold:
19, 23, 11, 30, 27, 27, 22, 26, 16, 24
Find the mean to the nearest tenth for each set of data.
Calculate the mean

Answers

Answer:

The first one is 16.0 and the second one is 22.5

Answer:

The first one is 16.0 and the second one is 22.5

CD Express offers 4 CDs for $60. Music
Place offers 6 CDs for $75. Which store
offers the better buy?

Answers

Answer:

Music place has the better buy

Step-by-step explanation:

Figure out how much they sell one for by diving the price by the quantity

CD Express offers 1 CD for $15

Music Place offers 1 CD fof $12.50

Answer:

Music Place

Step-by-step explanation:

Find the unit rates by dividing the price by the number of CDs

CD Express:

price/CDs

$60/4 CDS

60/4=15

$15 per CD

Music Place:

price/CDs

$75/6 CDs

75/6=12.5

$12.50 per CD

Music Place is the Better deal because 12.50 is less than 15

According to the Census Bureau, 3.39 people reside in the typical American household. A sample of 26 households in Arizona retirement communities showed the mean number of residents per household was 2.73 residents. The standard deviation of this sample was 1.22 residents. At the .10 significance level, is it reasonable to conclude the mean number of residents in the retirement community household is less than 3.39 persons?

Answers

Answer:

[tex]t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758[/tex]    

[tex]df=n-1=26-1=25[/tex]  

[tex]p_v =P(t_{(25)}<-2.758)=0.0054[/tex]  

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

Step-by-step explanation:

Data given and notation  

[tex]\bar X=2.73[/tex] represent the sample mean

[tex]s=1.22[/tex] represent the sample standard deviation

[tex]n=26[/tex] sample size  

[tex]\mu_o =3.39[/tex] represent the value that we want to test

[tex]\alpha=0.1[/tex] represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

[tex]p_v[/tex] represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 3.39 persons, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \geq 3.39[/tex]  

Alternative hypothesis:[tex]\mu < 3.39[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

[tex]t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758[/tex]    

P-value

The degreed of freedom are given by:

[tex]df=n-1=26-1=25[/tex]  

Since is a one sided lower test the p value would be:  

[tex]p_v =P(t_{(25)}<-2.758)=0.0054[/tex]  

Conclusion  

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

Ivan started the week on page 35 of his book and read 20 pages each night. What page would Ivan be on if he reads for 8 nights

Answers

Answer:

160 plus 35 = 185

Step-by-step explanation:

8×20

hopefully this helps you

1. (5.1.8) An article reports that in a sample of 132 hip surgeries of a certain type, the average surgery time was 136.9 minutes with a standard deviation of 22.6 minutes. a. Find a 95% confidence interval for the mean surgery time. b. Find a 99.5% confidence interval for the mean surgery time. c. A surgeon claims that the mean surgery time is between 133.9 and 139.9 minutes. With what level of confidence can this statement be made? d. Approximately how many surgeries must be sampled so that a 95% confidence interval will specify the mean to within ±3 minutes? e. Approximately how many surgeries must be sampled so that a 99% confidence interval will specify the mean to within ±3 minutes?

Answers

Answer:

a) The 95% CI for the mean surgery time is (133.05, 140.75).

b) The 99.5% CI for the mean surgery time is (131.37, 142.43).

c) The level of confidence of the interval (133.9, 139.9) is 69%.

d) The sample size should be 219 surgeries.

e) The sample size should be 377 surgeries.

Step-by-step explanation:

We have a sample, of size n=132, for which the mean time was 136.9 minutes with a standard deviation of 22.6 minutes.

a) We have to find a 95% CI for the mean surgery time.

The critical value of z for a 95% CI is z=1.96.

The margin of error of the CI can be calculated as:

[tex]E=z\cdot s/\sqrt{n}=1.96*22.6/\sqrt{132}=44.296/11.489=3.85[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=\bar x-E=136.9-3.85=133.05\\\\UL=\bar x+E=136.9+3.85=140.75[/tex]

The 95% CI for the mean surgery time is (133.05, 140.75).

b) Now, we have to find a 99.5% CI for the mean surgery time.

The critical value of z for a 99.5% CI is z=2.81.

The margin of error of the CI can be calculated as:

[tex]E=z\cdot s/\sqrt{n}=2.81*22.6/\sqrt{132}=63.506/11.489=5.53[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=\bar x-E=136.9-5.53=131.37\\\\UL=\bar x+E=136.9+5.53=142.43[/tex]

The 99.5% CI for the mean surgery time is (131.37, 142.43).

c) We can calculate the level of confidence, calculating the z-score for the margin of error in that interval.

We know that the difference between the upper bound and lower bound is 2 times the margin of error:

[tex]UL-LL=2E\\\\E=\dfrac{UL-LL}{2}=\dfrac{139.9-133.9}{2}=\dfrac{6}{2}=3[/tex]

Then, we can write the equation for the margin of error to know the z-value.

[tex]E=z \cdot s/\sqrt{n}\\\\z= E\cdot \sqrt{n}/s=2*\sqrt{132}/22.6=2*11.5/22.6=1.018[/tex]

The confidence level for this interval is then equal to the probability that the absolute value of z is bigger than 1.018:

[tex]P(-|z|<Z<|z|)=P(-1.018<Z<1.018)=0.69[/tex]

The level of confidence of the interval (133.9, 139.9) is 69%.

d) We have to calculate the sample size n to have a margin of error, for a 95% CI, that is equal to 3.

The critical value for a 95% CI is z=1.96.

Then, the sample size can be calculated as:

[tex]E=z\cdot s/\sqrt{n}\\\\n=(\dfrac{z\cdot s}{E})^2=(\dfrac{1.96*22.6}{3})^2=14.77^2=218.015\approx 219[/tex]

The sample size should be 219 surgeries.

e) We have to calculate the sample size n to have a margin of error, for a 99% CI, that is equal to 3.

The critical value for a 99% CI is z=2.576.

Then, the sample size can be calculated as:

[tex]E=z\cdot s/\sqrt{n}\\\\n=(\dfrac{z\cdot s}{E})^2=(\dfrac{1.96*22.6}{3})^2=19.41^2=376.59\approx 377[/tex]

The sample size should be 377 surgeries.

Use the annihilator method to determine the form of a particular solution for the given equation. u double prime minus 2 u prime minus 8 equals cosine (5 x )plus 7 Find a differential operator that will annihilate the nonhomogeneity cosine (5 x )plus 7

Answers

Answer:

the particular solution is

Y_{p}= C +D\sin 5t +E\cos 5t + F\exp 4t + G\exp -2t

the differential operator that annihilate the non homogeneous differential equation is

D(D^2+5)

Step-by-step explanation:

hello,

i believe the non homogeneous differential equation is

[tex]U^{''} - 2U^{'} - 8= \cos 5x + 7[/tex]

the homogeneous differential equation of the above is

[tex]u^{''} -2u^{'} -8 =0[/tex]

the differential form of the above equation is

[tex]D^2-2D-8=0[/tex]

[tex](D-4)(D+2)=0[/tex]

thus the roots are 4 and -2.

thus the solution of the homogenous differential equation is given as

[tex]Y_{h} (t)= A\exp{4t} + B\exp{-2t}[/tex]

the differential operator of the non homogeneous equation is given as

[tex](D-4)(D+2)(u)=\cos 5x +7[/tex]

the differential operator [tex]D^2 +5[/tex] annihilates [tex]\cos 5x[/tex] and the differential operator D annihilates 7

applying [tex]D(D^2+5)[/tex] to both sides of the differential equation we have;

(D-4)(D+2)(u)=\cos 5x +7

[tex]D(D^2+5)(D-4)(D+2)=D(D^2+5)(\cos5x+7)[/tex][tex]D(D^2+5)(D-4)(D+2)=0[/tex]

the roots of the characteristic polynomial of the diffrential equation above are [tex]0, \cmplx 5i, -\cmplx 5i, 4, -2[/tex]

thus the particular solution is

[tex]Y_{p}= C\exp{0}+D\sin 5t +E\cos 5t + F\exp {4t} + G\exp {-2t}[/tex]

this gives us the particular solution

[tex]Y_{p}= C +D\sin 5t +E\cos 5t + F\exp 4t + G\exp -2t[/tex]

To use the annihilator method for the differential equation [tex]\(u'' - 2u' - 8 = \cos(5x) + 7\),[/tex] the operator [tex]\(D^3 + 25D\)[/tex] will annihilate the nonhomogeneous part [tex]\(\cos(5x) + 7\).[/tex] This operator reduces the nonhomogeneous function to zero. The differential operator combines the annihilation of both the cosine and constant terms.

To determine the form of a particular solution for the given differential equation[tex]\(u'' - 2u' - 8 = \cos(5x) + 7\),[/tex] we first identify a differential operator that annihilates the nonhomogeneous part [tex]\(\cos(5x) + 7\).[/tex]

For [tex]\(\cos(5x)\)[/tex] , the appropriate annihilator is [tex]\(D^2 + 25\)[/tex], where [tex]\(D\)[/tex] represents differentiation with respect to [tex]\(x\)[/tex].

This is because applying [tex]\(D^2 + 25\)[/tex]  to [tex]\(\cos(5x)\)[/tex] will yield zero:

[tex]\(\frac{d^2}{dx^2}(\cos(5x)) + 25 \cos(5x) = -25\cos(5x) + 25\cos(5x) = 0 \).[/tex]

For the constant term 7, the annihilator is simply [tex]\(D\)[/tex], since the derivative of a constant is zero:

[tex]\(\frac{d}{dx}(7) = 0.\)[/tex]

Combining these, the overall differential operator that will annihilate [tex]\(\cos(5x) + 7\)[/tex] is:

[tex]\( (D)(D^2 + 25) = D^3 + 25D.\)[/tex]

The differential operator [tex]\( D^3 + 25D \)[/tex] will annihilate the nonhomogeneous part [tex]\( \cos(5x) + 7 \),[/tex] reducing it to zero.

consider a population of voters. suppose that that there are n=1000 voters in the population, 30% of whom favor jones. identify the event favors jones as a success s. it is evident that the probability of s on trial 1 is 0.30. consider the event b that s occurs on the second trial. then b can occur two ways: the first two trials are both successes or the first trial is a failure and the second is a success. show that p(b) = 0.3

Answers

Answer:

P(B)=0.30

Step-by-step explanation:

Out of 1000 Voters, 30% favor Jones.

Event S=Favors Jones on First Trial

Event B=S occurs on Second Trial

P(S)=0.30

P(S')=1-0.30=0.70

Event B could occur in two ways

The first two trials are a successThe first trial is a failure and the second trial is a success.

Therefore,

P(B)=P(SS)+P(S'S)

=(0.3X0.3)+(0.7X0.3)

=0.09+0.21

=0.3

Therefore, the probability of event B(that event S occurs on the second trial), P(B)=0.30.

express 6/25 as a decimal fracture​

Answers

Answer:

0.24

Step-by-step explanation:

Answer: 6/25 as a decimal would be 0.24

Step-by-step explanation:0.240 and 0.24 are both the same thing, the 0 behind the 4, doesn't have value. But, most teachers would prefer you to put it as 0.24. Also, in order to turn a fraction into a decimal, you just divide the top number (numerator) by the bottom number (denominator). 6 divided by 25 is 0.24

The Johnsons are buying a house that costs $210,000 and can afford a 20% down payment. If the Johnsons want the lowest
monthly payment, which loan option would you recommend?
a 30 year FHA, 3.5% down at a fixed rate of 6.25%
b. 30 year fixed, 20% down at a fixed rate of 6%
C.30 year fixed, 10% down at a fixed rate of 6%
d. 15 year fixed, 20% down at a fixed rate 5.5%

Answers

Answer:

b

Step-by-step explanation:

Final answer:

Option D: 15-year fixed, 20% down at a fixed rate of 5.5% would result in the lowest monthly payment for the Johnsons.

Explanation:

Based on the options given, the loan option that would result in the lowest monthly payment for the Johnsons would be Option D: 15-year fixed, 20% down at a fixed rate of 5.5%. To determine this, we need to compare the monthly payments for each option.

Option A: 30-year FHA, 3.5% down at a fixed rate of 6.25%:
Loan amount = $210,000 - (3.5% of $210,000) = $202,575
Monthly payment = Loan amount * (rate/12) * (1 + rate/12)^(12 * years) / ((1 + rate/12)^(12 * years) - 1)
= $202,575 * (6.25%/12) * (1 + 6.25%/12)^(12 * 30) / ((1 + 6.25%/12)^(12 * 30) - 1)Option B: 30-year fixed, 20% down at a fixed rate of 6%:
Loan amount = $210,000 - (20% of $210,000) = $168,000
Monthly payment = $168,000 * (6%/12) * (1 + 6%/12)^(12 * 30) / ((1 + 6%/12)^(12 * 30) - 1)Option C: 30-year fixed, 10% down at a fixed rate of 6%:
Loan amount = $210,000 - (10% of $210,000) = $189,000
Monthly payment = $189,000 * (6%/12) * (1 + 6%/12)^(12 * 30) / ((1 + 6%/12)^(12 * 30) - 1)Option D: 15-year fixed, 20% down at a fixed rate of 5.5%:
Loan amount = $210,000 - (20% of $210,000) = $168,000
Monthly payment = $168,000 * (5.5%/12) * (1 + 5.5%/12)^(12 * 15) / ((1 + 5.5%/12)^(12 * 15) - 1)

By calculating the monthly payments for each option, it is found that Option D has the lowest monthly payment for the Johnsons.

Billy has a von Neumann-Morgenstern utility function U(c) = c 1/2. If Billy is not injured this season, he will receive an income of 25 million dollars. If he is injured, his income will be only 10,000 dollars. The probability that he will be injured is .1 and the probability that he will not be injured is .9. His expected utility is

Answers

Answer: The expected utility is 0.59.

Step-by-step explanation:

Since we have given that

[tex]U(c)=\sqrt{c}[/tex]

Probability that he will be injured = 0.1

Probability that he will not be injured = 0.9

If Billy is not injured this season, he will receive an income of 25 million dollars.

and

If he is injured, his income will be only 10,000 dollars.

According to question, the expected utility is given by

[tex]E[x]=0.9\times \sqrt{(0.01)}+0.1\times \sqrt{25}\\\\E[x]=0.9\times 0.1+0.1\times 5\\\\E[x]=0.09+0.5\\\\E[x]=0.59[/tex]

Hence, the expected utility is 0.59.

Final answer:

To calculate Billy's expected utility, we need to multiply his utility function by the probability of each outcome and sum the results. His expected utility is approximately 3333.33.

Explanation:

To calculate Billy's expected utility, we need to multiply his utility function by the probability of each outcome and sum the results. In this case, Billy's utility function is U(c) = c^(1/2), where c represents his income. If Billy is not injured, his income will be $25 million, and if he is injured, his income will be $10,000. The probability of being injured is 0.1, and the probability of not being injured is 0.9.

Expected utility = U(income if not injured) * P(not injured) + U(income if injured) * P(injured)

Expected utility = U($25 million) * 0.9 + U($10,000) * 0.1

Expected utility = (25 million)^(1/2) * 0.9 + (10,000)^(1/2) * 0.1

Solving this equation, we find that the expected utility for Billy is approximately 3333.33.

Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 6; C: at least one of the numbers is 3; and D: the numbers do not add to 11. Express the given event in symbolic form.
Either the numbers add to 11 or the red die shows a 1.
D ∩ B
D ∩ A
D' ∪ A
D' ∩ A
D' ∪ B

How many elements does it contain?


Answers

Answer:

(a)(C)[tex]D^c \cup A[/tex]

(b)8 elements

Step-by-step explanation:

Ina toss of a red and green dice, given the events:

A: the red die shows 1; B: the numbers add to 6; C: at least one of the numbers is 3; and D: the numbers do not add to 11.

[tex]D^c[/tex]=The numbers do add up to 11.

Therefore, the event: Either the numbers add to 11 or the red die shows a 1 is written as: [tex]D^c \cup A[/tex]

(b)

Sample Space of A={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)}

Sample Space of [tex]D^c[/tex]={(5,6),(6,5)}

[tex]D^c \cup A[/tex]={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(5,6),(6,5)}

[tex]D^c \cup A[/tex] contains 8 elements

Final answer:

The event "Either the numbers add to 11 or the red die shows a 1" is represented by the symbol D' ∪ A. This event contains 7 elements in the context of rolling two six-sided dice.

Explanation:

To express the event "Either the numbers add to 11 or the red die shows a 1" in symbolic form, we consider the symbols for the events defined in the question. Event A denotes the red die shows 1, and D denotes the event the numbers do not add to 11. The complement of D, represented as D', would then denote the event that the numbers do add to 11. The symbol ‘∪’ denotes the union of sets, meaning 'or' in the context of probability. Therefore, the symbolic form for the given event is D' ∪ A.

Regarding how many elements this event contains, we must consider the sample space when rolling two six-sided dice. There are a total of 36 different outcomes (6 possible outcomes for the first die multiplied by 6 outcomes of the second die). Event A (the red die shows a 1) has 6 elements (1 can be paired with any of the 6 outcomes on the green die). Event D' (the numbers add up to 11) can happen in two ways: (5,6) or (6,5), one for each die, making it 2 elements. Therefore, D' ∪ A will consist of all unique elements from both events without double-counting any pair. So, we combine 6 outcomes from A and 2 from D', but we need to ensure to not count the outcome (1,6) twice, hence we have 6 (from A) + 2 (from D') - 1 (overlap of (1,6)) = 7 elements in event D' ∪ A.

Harriet rolls a number cube. What is the probability that the number cube will land on 3 or 4?

Answers

Answer:

2 out of 6

Step-by-step explanation:

Answer: 2 out of 6

Step-by-step explanation:

Two vertical poles, one 16 ft high and the other 24 ft high, stand 30 feet apart on a flat field. A worker wants to support both poles by running rope from the ground to the top of each post. If the worker wants to stake both ropes in the ground at the same point, where should the stake be placed to use the least amount of rope?

Answers

Answer:

The rope should be placed at 1.46 from the 16 ft pole to minimize the length.

Step-by-step explanation:

From the diagram, our goal is to minimize the length of Rope AC passing through B.

First, we determine the length of the rope AC.

AC=AB+BC

In the first triangle,

[tex]|AB|^2=16^2+x^2\\|AB|=\sqrt{16^2+x^2}[/tex]

Similarly, in the second triangle,

[tex]|BC|^2=24^2+(30-x)^2\\|BC|=\sqrt{x^2-60x+1476}[/tex]

Length of the Rope, AC

[tex]L=\sqrt{16^2+x^2}+\sqrt{x^2-60x+1476}[/tex]

First, to minimize L,we find its derivative.

[tex]L'=\dfrac{x\sqrt{x^2-60x+1476}+(x-30)\sqrt{16^2+x^2}}{(\sqrt{16^2+x^2})(\sqrt{x^2-60x+1476})}[/tex]

Setting the derivative to zero

[tex]x\sqrt{x^2-60x+1476}+(x-30)\sqrt{16^2+x^2}=0\\-x\sqrt{x^2-60x+1476}=(x-30)\sqrt{16^2+x^2}\\$Square both sides\\x^2(x^2-60x+1476)=(x-30)^2(16^2+x^2)\\x^4-60x^3+1476x^2=x^4-60x^3+1156x^2-15360x+230400\\1476x^2=1156x^2-15360x+230400\\1476x^2-1156x^2+15360x-23040=0\\320x^2+15360x-23040=0\\x=1.46,-49.46[/tex]

The rope should be placed at 1.46 from the 16 ft pole to minimize the length.

The least amount of the rope is the smallest length that can be gotten from the pole

The rope should be placed at 12 feet from the 16 ft pole to use the least amount of rope.

The heights are given as:

[tex]\mathbf{h_1 = 16}[/tex]

[tex]\mathbf{h_2 = 24}[/tex]

The distance is given as:

[tex]\mathbf{d = 30}[/tex]

See attachment for the illustrating diagram

Considering the two right-angled triangles on the diagram, we have the following equations, using Pythagoras theorem

[tex]\mathbf{L_1 = \sqrt{x^2 + 16^2}}[/tex]

[tex]\mathbf{L_2 = \sqrt{(30 - x)^2 + 24^2}}[/tex]

Expand

[tex]\mathbf{L_1 = \sqrt{x^2 + 256}}[/tex]

[tex]\mathbf{L_2 = \sqrt{900 - 60x +x^2 + 576}}[/tex]

[tex]\mathbf{L_2 = \sqrt{1476- 60x +x^2 }}[/tex]

The length (L) of the pole is:

[tex]\mathbf{L = L_1 + L_2}[/tex]

So, we have:

[tex]\mathbf{L = \sqrt{x^2 + 256} + \sqrt{1476 - 60x + x^2}}[/tex]

Differentiate

[tex]\mathbf{L' = \frac{x}{\sqrt{x^2 + 256}} + \frac{x - 30}{\sqrt{1476 - 60x + x^2}}}[/tex]

Set to 0

[tex]\mathbf{\frac{x}{\sqrt{x^2 + 256}} + \frac{x - 30}{\sqrt{1476 - 60x + x^2}} = 0}[/tex]

Take LCM

[tex]\mathbf{\frac{x\sqrt{1476 - 60x + x^2} +(x - 30)\sqrt{x^2 + 256}}{\sqrt{x^2 + 256} \times \sqrt{1476 - 60x + x^2}} = 0}[/tex]

Simplify

[tex]\mathbf{x\sqrt{1476 - 60x + x^2} +(x - 30)\sqrt{x^2 + 256} = 0}[/tex]

Rewrite as:

[tex]\mathbf{x\sqrt{1476 - 60x + x^2} =-(x - 30)\sqrt{x^2 + 256} }[/tex]

Square both sides

[tex]\mathbf{x^2(1476 - 60x + x^2) =(x^2 - 60x + 900)(x^2 + 256) }[/tex]

Expand

[tex]\mathbf{1476x^2 - 60x^3 + x^4 =x^4 - 60x^3 + 900x^2 + 256x^2 - 15360x + 230400}[/tex]

Simplify

[tex]\mathbf{1476x^2 - 60x^3 + x^4 =x^4 - 60x^3 + 1156x^2 - 15360x + 230400}[/tex]

Evaluate like terms

[tex]\mathbf{1476x^2 = 1156x^2 - 15360x + 230400}[/tex]

Rewrite as:

[tex]\mathbf{1476x^2 - 1156x^2 + 15360x - 230400 = 0}[/tex]

[tex]\mathbf{320x^2 + 15360x - 230400 = 0}[/tex]

Divide through by 320

[tex]\mathbf{x^2 + 48x - 720 = 0}[/tex]

Using a calculator, we have:

[tex]\mathbf{x = \{12,-60\}}[/tex]

The value of x cannot be negative.

So, we have:

[tex]\mathbf{x = 12}[/tex]

Hence, the rope should be placed at 12 feet from the 16 ft pole

Read more about minimizing lengths at:

https://brainly.com/question/15174196

Determine what type of statistical test should be used to answer each of the questions below. (You will only use each response one time.) Group of answer choices What proportion of Americans believe in climate change? Do college students change their view on climate change as they go through college? One hundred freshman are asked if they believe in climate change. The same students are asked four years later if they also believe in climate change. Is there a difference in the proportion of men and women who believe in climate change? What is the average amount of time that Americans spend watching or reading the news a day? Is there a difference in the amount of time that college students spend reading or watching the news as they go through college? One hundred students were asked as freshmen and as senior how many minutes a day they spent reading or watching the news? Is there is a difference in the amount of time that Republicans and Democrats spend watching or reading the news?

Answers

Answer:

1.One proportion

2. Proportions from Dependent Samples

3. Two Independent Proportions

4. One Mean

5. Means from Dependent Samples

6. Two Independent Means

Step-by-step explanation:

What proportion of Americans believe in climate change? - One proportion

From the above information, there is only one sample and the question is about proportion. So, we must use "One proportion".

Do college students change their view on climate change as they go through college? One hundred freshman are asked if they believe in climate change. The same students are asked four years later if they also believe in climate change. - Proportions from Dependent Samples

From the information given, there are two samples and samples are dependent ( that is same students are asked four years later). Furthermore, the question is about proportion, we must use " Proportions from dependent samples ".



Is there a difference in the proportion of men and women who believe in climate change? - Two Independent Proportions

From the information given, there are two independent samples and they are asking about proportion, we must use "Two independent proportions".

What is the average amount of time that Americans spend watching or reading the news a day? - One Mean

From the information, there is only one sample and they are asking about mean. Therefore, we must use ". One mean".

Is there a difference in the amount of time that college students spend reading or watching the news as they go through college? One hundred students were asked as freshmen and as senior how many minutes a day they spent reading or watching the news? - Means from Dependent Samples

There are two samples and samples are dependent ( the same students are asked four years later). Also, they are asking about mean, we must use "Means from dependent samples ".

Is there is a difference in the amount of time that Republicans and Democrats spend watching or reading the news? - Two Independent Means

From the information given, there are two independent samples and they are asking about mean, we must use "Two independent means".

Final answer:

The statistical tests required are a hypothesis test for a proportion for the questions on proportions of Americans' beliefs, a paired t-test for examining changes in the same group over time, an independent t-test for comparing means of different groups and measures of central tendency (mean) for assessing averages.

Explanation:

The various questions posed require different types of statistical tests. Proportions are evaluated using a hypothesis test for a proportion. So, the question 'What proportion of Americans believe in climate change?' and 'Is there a difference in the proportion of men and women who believe in climate change?' would utilize this test.

For questions where the same group is measured at two different times, a paired t-test is appropriate. Hence, the question 'Do college students change their view on climate change as they go through college? One hundred freshman are asked if they believe in climate change. The same students are asked four years later if they also believe in climate change.' would require a paired t-test.

When comparing the means of two independent groups, an independent t-test should be used. This would apply to the questions 'Is there a difference in the amount of time that Republicans and Democrats spend watching or reading the news?' and 'Is there is a difference in the amount of time that college students spend reading or watching the news as they go through college?'

Finally, to measure an average or central tendency, a mean is used – therefore, the question 'What is the average amount of time that Americans spend watching or reading the news a day?' would require the calculation of a mean.

Learn more about Statistical tests here:

https://brainly.com/question/14128303

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Is 100x^3 a perfect square

Answers

Answer:

No.

Step-by-step explanation:

This is not a perfect square because the exponent would need to be even, not odd. The 100 is a perfect square. If you were to simplify it, it would be (10x^2) * (10x). In order for it to be truly a perfect square, they both need to be the same.

Other Questions
Nine-year-old Ricky has recently learned how to solve long division problems, and he still struggles with especially difficult problems. At his mother's request, Ricky helps his eight-year-old sister Lucy with the simple long division problems she must do for her math homework. Which one of the following is most likely to result? a. Ricky's own long division skills will improve because he is more motivated.b. Ricky will gain nothing from helping his sister because doing long division is outside his zone of proximal development.c. Ricky's own long division skills will decrease, because any mistakes that Lucy makes will "corrupt" his own mathematical thinking.d. By helping Lucy with her long division problems, Ricky will be able to practice using the central conceptual structure that underlies his mathematical thinking. Which of the following correctly lists, in increasing order, the resistance of microorganisms to chemical biocides? View Available Hint(s) Which of the following correctly lists, in increasing order, the resistance of microorganisms to chemical biocides? gram-positive bacteria, endospores, prions prions, gram-negative bacteria, gram-positive bacteria mycobacteria, gram-positive bacteria, gram-negative bacteria, prions gram-negative bacteria, gram-positive bacteria, mycobacteria Completa la oracin. Escribe el verbo entre parntesis en el pretrito.Yo ________a0 a buscar lugares interesantes para visitar en Venezuela. (empezar)Los peridicos en lnea ________a0 a hablar de las obras de beneficencia de la gente famosa. (empezar)Yo ________a0 por radio las hazaas de Miguel Cabrera. (comunicar)Mi nombre es Joaqun Alberti. Yo ________a0 por el Mar Caribe. (navegar)Mi profesor de espaol ya ________a0 un viaje a Venezuela. (organizar) Plz help fast hurry 12 points Which area of the brain is responsible for reasoning, judgment, planning, organization, and predicting future events?A.SerotoninB.thalamusC.hippocampusD.frontal lobe Alatan owns a building supply store in Russ County. His trade extends throughout River City, the largest city in Russ County, but not beyond the county limits. He sells his store to Hilary and, as part of the transaction, Alatan agrees not to engage in the same type of business anywhere in River City for a period of four (4) years. In this case:a) The geographic restraint is reasonable.b) This agreement is unreasonable.c) The agreement unduly interferes with the interest of the public.d) Both (b) and (c). Where did the majority of these battles take place? JAVAWrite a method that takes an int[] array and an int value and returns the first index at which value appears in the array.If the value does not exist in the array, return -1For example:search(new int[]{10, 20, 30, 20}, 20)Should return 1Because 20 first appears at index 1 in the array.search(new int[]{10, 20, 30, 20}, 40)Should return -1public int search(int[] array, int value){} How many nonbonding electron pairs are there in the lewis structure of the peroxide ion Overload refers to: A. Performing a weight-lifting exercise with the resistance (load) held overhead B. Using a demand (load) above the normal demand faced by a muscle C. The principle that strength will be best developed when the resistance (load) exceeds the individual's physical abilities (e.g., 8 reps of the 5-RM) D. The principle that a resistance (load) must be presented repeatedly in order to elicit any adaptations E. All of the answers are correct A 5.20 kg chunk of ice is sliding at 13.5 m/s on the floor of an ice-covered valley when it collides with and sticks to another 5.20 kg chunk of ice that is initially at rest. Since the valley is icy, there is no friction. After the collision, the blocks slide partially up a hillside and then slide back down.how high above the valley floor will the combined chunks go? Solve each equation. Be sure to check your solution.0.3a = 51 What are corrective actions, how does the project manager know that corrective action is needed, how are the root causes of corrective actions determined, how is the effectiveness of a corrective action measured, and what happens if the necessary corrective action is not performed in a timely fashion Scientists found an animal skull during an excavation and tested the amount of carbon-14 left in it. They found that 55 percent of the carbon-14 in the skull remained. How many years ago was the animal buried? Round your answer to nearest whole number. (Hint: A = A0e-0.000124t.)A. 443,548 yearsB. 362,903 yearsC. 6,439 yearsD. 4,821 yearshelp pls These statements illustrate a difference in opinion between the two presidents overa granting subsidies to big businessb expanding the federal government's role in the economyc promoting free-trade policies in the Western Hemispheredregulating supply and demand Capital budgeting is: the process of finding the cost to start a new project. the process of deciding which project to do to increase the firms value. the process of budgeting companies monthly revenue and cost. the process of estimating how long the life of a new project. None of the above. Which of these best describes the effect the new technology had on the war? AThe new technology made the war even more violent.BThe new technology ended the need to use poisonous gas.CThe new technology made the war less gruesome.DThe new technology was designed to kill the enemy quickly. Design state machines to control the minutes and hours of a standard 24 hour clock. Your clock should include an AM/PM indicator light, 2-digit hours (1 12), 2-digit minutes (00 59). (There is no need to include seconds; if we wanted to display seconds, it would be the same state control unit as minutes.) Tikiro places a wrench on a nut and applies a downward force of 32 pounds to tighten the nut. If the center of the nut is at the origin, the force is applied at the point (.65,0,0.3) Find the torque. a. 18.4 ft-lb c. 21.2 ft-lb b. 20.8 ft-lb d. 22.1 ft-lb After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alumni were in favor of firing the coach. A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach. Let p represent the proportion of all living alumni who favored firing the coach. Suppose the alumni association wished to see if the majority of alumni are in favor of firing the coach. To do this they test the hypotheses H0: p = 0.50 versus Ha: p > 0.50. (A) What is the P-value for this hypothesis test?