Barry has an ice tray that makes ice cubes shaped like a cone with a diameter of 2 cm and height of 2 cm. To the nearest cubic centimeter, what is the volume of an ice cube from Barry's tray?

Answers

Answer 1
8 because 2^3 or 2 x 2 x 2 = 8

Related Questions

For which set of lines is it reasonable to state that The two lines are ALMOST perpendicular to each other? A) y = 2.1x + 3, y = 2.1x + 5 B) y = 0.9x + 5, y = -1.26x + 8 C) y = 5x + 1.25, y = -5x + 1.25 D) y = 3 4 x + 0.28, y = 4 3 x + 0.29

Answers

Selection B is the best.

The product of the slopes of the lines is closest to -1 for that pair of lines.

A survey asks 48 randomly chosen students if they plan to buy a school newspaper this week. Of the 48 surveyed,32 plant to buy a school newspaper. If 360 students bought papers,predict the number of students enrolled at the school.

Answers

The answer is 540 because 32/48 is 2/3 and 360/540 equals 2/3

The number of students enrolled at the school is 540.

A survey asks 48 randomly chosen students if they plan to buy a school newspaper this week. Of the 48 surveyed, 32 plan to buy a school newspaper. If 360 students bought papers, predict the number of students enrolled at the school. To solve this, we use a proportion based on the survey results to predict the total enrollment. The proportion of students who plan to buy the newspaper based on the survey is 32 out of 48, which simplifies to 2 out of 3 when reduced. If 360 students actually bought the paper, and assuming the proportion holds for the entire school, we can set up the equation:

2/3 = 360 / total students

To find the total number of students, solve for 'total students':

total students = 360 × 3 / 2

total students = 540

Therefore, based on the survey results and the actual number of newspapers bought, we can predict there are 540 students enrolled at the school.

state the degree of the polynomial xy+3x2-7+x

Answers

xy+6-7+x
Combine (6+-7)+xy
xy+x-1
xy+3x^2-7+x the degree is 2 

Just use the 'formula' for finding the degree of a polynomial. ie--look for the value of the largest exponent the answer is 2 since that is the largest exponent.

PLEASEEEEE HEEEEEELPPPPPPPPPPPPPPP

Suppose ABCD is a rhombus such that the angle bisector of ∠ABD meets AD at point K. Prove that m∠AKB = 3m∠ABK.

Answers

1. Let m∠ABK=x°. Since line BK bisects ∠ABD, then

m∠ABK=m∠KBD=x°.

Also m∠ABD=m∠ABK+m∠KBD=2x°.

2. The diagonal BD of rhombus ABCD bisects ∠ABC, then

m∠ABD=m∠DBC=2x°.

This gives you that

m∠ABC=4x°.

3. Angles A and B are supplementary, so

m∠A+m∠B=180°,

m∠A=180°-4x°.

4. Consider triangle ABK. The sum of the measures of interior angles in triangle is always 180°, thus

m∠A+m∠ABK+m∠AKB=180°,

m∠AKB=180°-x°-(180°-4x°),

m∠AKB=3x°=3m∠ABK.

Answer:

Given information: ABCD is a rhombus, angle bisector of ∠ABD meets AD at point K.

[tex]\angle ABK\cong \angle DBK[/tex]         (Definition of angle bisector)

[tex]m\angle ABK=m\angle DBK[/tex]          (Definition of concurrency)

Let as assume the measure of angle ABK is x.

[tex]m\angle ABK=x[/tex]

[tex]m\angle ABD=m\angle ABK+m\angle DBK[/tex]

[tex]m\angle ABD=x+x[/tex]

[tex]m\angle ABD=2x[/tex]

All sides of a rhombus are same.

Since AB=AD, therefore ABD is an isosceles triangle and two angles of an isosceles triangle are congruent.

[tex]m\angle ADB=m\angle ABD[/tex]

[tex]m\angle ADB=2x[/tex]

According to exterior angle theorem, sum of two interior angles of a triangle is equal to third exterior angle.

Using exterior angle theorem, we get

[tex]m\angle AKB=m\angle ADB+m\angle DBK[/tex]

[tex]m\angle AKB=2x+x[/tex]

[tex]m\angle AKB=3x[/tex]

[tex]m\angle AKB=3(m\angle ABK)[/tex]

Hence proved.

Does 3pi/5 have a supplementary angle?

Answers

If two angles are supplementary, then their measures add to 180 deg.
Since 180 deg = pi rad, then supplementary angles are two angles whose measures add to pi rad.

Since 3pi/5 is less than 1 rad, then there is an angle that is supplementary to an angle measuring 3pi/5. The measure of the supplement is 2pi/5.

Solve for x: x^4 = 3^x

Answers

There are no algebraic methods for finding solutions to a general mix of exponential and polynomial terms. A graphing calculator can be helpful.

This equation has 3 real solutions, approximately ...
  x ∈ {-0.802246431546, 1.51677641228, 7.17475582739}

_____
In the folder "iteration for solutions" is an equation for Newton's method iteration, essentially, ...
  g(x) = x -f(x)/f'(x)
where f(x) is defined as shown in the picture.

Many graphing calculators can compute a numerical derivative, so you can essentially write the formula in this form without having to do the derivative-taking yourself. This calculator is nicely interactive, so the iteration result is produced at the same time the argument for g(x) is entered. Essentially, you write the answer by copying the answer using the 4-digit zero-crossing values shown on the graph as the iteration starting point.

×
[tex] \frac{x}{4} = \frac{6}{12} [/tex] solve the proportions

Answers

To solve a problem like this, you can use a method called cross-multiplying. This is when you multiply the denominator of the first fraction by the numerator of the other and then multiply the two remaining numbers.

[tex] \frac{x}{4} = \frac{6}{12} [/tex]  To make this easier on yourself, simplify first!
[tex] \frac{x}{4} = \frac{1}{2} [/tex]   Multiply x by 2 and multiply 4 by 1.
2x = 4   Divide both sides by 2.
x = 2

You can check this by comparing the fractions with 2 in the place of x.

[tex] \frac{2}{4} = \frac{6}{12} [/tex]   Simplify!
[tex] \frac{1}{2} = \frac{1}{2} [/tex]

The fractions are equal, so x = 2 .

if y = 6x - 3 which of the following see represents possible inputs and outputs of the function represented as ordered pairs

Answers

If it’s giving you a chart you’ll have to use the inputs which are the x and then simplify each number and it will give you the answer of your outout
y = 6x - 3
 For this case, the first thing we can do is write a table with the input and output values of the function.
 Take an example in the interval from x = 0 to x = 5.
 We have then:
 x    y
 0   -3
 1    3
 2    9
 3    15
 4    21
 5    27

 We now represent the inputs and outputs as ordered pairs:
 (0, -3)
 (1,3)
 (2,9)
 (3,15)
 (4,21)
 (5,27)
 Answer:
 the following is represented possible inputs and outputs of the function represented as ordered pairs

 (0, -3)
 (1,3)
 
(2,9)
 
(3,15)
 
(4,21)
 (5,27)

What is the equation for the vertical asymptote of f(x)= (x+2)/(4x+4)

Answers

Try this option:
if   [tex]f(x)= \frac{x+2}{4x+4} [/tex]
then according to 
[tex] \lim_{x \to (-1-0)} ( \frac{x+2}{4x+4})=+ \infty[/tex]
and [tex]\lim_{x \to (-1+0)} ( \frac{x+2}{4x+4})=- \infty[/tex]
an equation for vertical asymptote is x=-1.
The graph of this function is in the attached picture.

How to find the x intercepts of f(x)=-2x^2+x+5

Answers

Completing the square, you have
.. -2(x^2 -x/2) +5 = 0
.. -2(x^2 -x/2 +1/16) = -5 -1/8 . . . . . add -2*(1/16)
.. (x -1/4)^2 = 2 9/16 . . . . . . . . . . . . divide by -2
.. x = (1 ±√41)/4 . . . . . . . . . . . . . . . .take the square root, add 1/4
.. x ∈ {-1.35078, 1.85072}

What is the value of the leading coefficient a if the polynomial function P(x) = a(x + b)2(x − c) has multiplicity of 2 at the point (−3, 0) and also passes through the points (2, 0) and (0, 36)?
answers:
−2−3336

Answers

The polynomial is of the form:

[tex]P(x)=a (x+b)^{2}(x-c) [/tex]

We are provided with the two zeros in the question statement. The zero with multiplicity 2 is -3, and zero with multiplicity 1 is 2. So using these values, the polynomial becomes:

[tex]P(x)=a (x+3)^{2}(x-2) [/tex]

The polynomial also passes from the point (0,36). This mean if we substitute x=0, the answer should be 36.

[tex]P(0)=36=a (0+3)^{2}(0-2) \\ \\ 36=a(9)(-2) \\ \\ 36=-18a \\ \\ a=-2 [/tex]

Thus the value of a for given polynomial will be -2. The complete equation of polynomial will be:

[tex]P(x)=-2 (x+3)^{2}(x-2)[/tex]

roberto has 12 tiles. each tile is 1 square inch. he will arrange them into a rectangle and glue 1-inch stones around the edge. how can roberto arrange the tiles so that he uses the least number of stones?

Answers

To answer this you will need to determine which area made with the 12 square tiles would give the shortest perimeter.

Think of all the combinations to get 12 square inches
1x12, 2x6, and 3x4. The perimeters of these are 26 in, 16 in, and 14 in.

You should arrange your tiles using the 3 x 4 option. You would need 14 stones.

Answer:

the answer is 4 and 2

Step-by-step explanation:

Your cousin has a goat in his backyard, tied with a 4 foot rope. The goat can move in a circular motion the length of the rope. What is the area of the backyard where his goat can eat the grass? Hint: The 4 foot rope represents the radius of the circle.
1. What equation can be used to calculate the area of the yard that his goat can eat the grass?
2. What is the area of this circle in your cousin’s backyard?
3. What would the new area be if he decides to use a 5 foot rope?

Answers

The stake the rope is tied to is the center of the circle. If the goat pulls the rope as far as it can go and walks around like this he makes a circle and he can eat the grass anywhere within this circle.

(a) Since the area of a circle is given by [tex]A= \pi r^{2} [/tex] this is the formula we can use to find the area of the yard where the goat can roam/eat/reach.

(b) Since the rope is 4 feet the radius r = 4 and the area is given by [tex] 4^{2} \pi =16 \pi ^{2} [/tex] square feet. That's the exact area. For an approximation you could substitute 3.14 for pi and get 50.24 square feet.

(c)Since the rope is 5 feet the radius r = 4 and the area is given by [tex]5^{2} \pi =25 \pi ^{2}[/tex] square feet. That's the exact area. For an approximation you could substitute 3.14 for pi and get 78.5 square feet.

NAME_____________________________________DATE_________________PER._______
TRAPEZOIDS
RSTV is an isosceles trapezoid. Decide whether each statement is TRUE or FALSE.
Justify your answer.

1. TRUE or FALSE
Why?
TR ⊥ SV

2. TRUE or FALSE
Why?
∠RVT ≅ ∠STV

3. TRUE or FALSE
Why?
∠SRV & ∠TVR are
supplementary.

WXYZ is an isosceles trapezoid with bases WZ and XY and median MN. Use the given
information to solve each problem.
4. MN = ____________ Find MN if WZ = 11 and XY = 3.

5. m∠XMN = ____________ Find m∠XMN if m∠WZN = 78°.

6. XY = ____________ If MN = 10 and WZ = 14, find XY.

7. x = ____________ What is the value of ‘x’ if m∠MWZ = (15x –5)° and m∠WZN = (90 – 4x)°?

8. x = ____________ If m∠XWZ = (2x – 7)° and m∠XYZ = 117°, find
the value of ‘x’.

9. x = ____________ If MN = 60, XY = 4x – 1, and WZ = 6x + 11, find
the value of ‘x’.

10. x = ____________ If MN = 10x + 3, WZ = 11, and XY = 8x + 19,
find the value of ‘x’.

11. x = ____________ If MN = 2x + 1, XY = 8, and WZ = 3x – 3, find
the value of ‘x’.

Can someone do this for me? im having a hard time and I have a 42 in math rn and I just need these done cause they are late.. if anyone likes geometry then here you go

Answers

1. False
2. True
3. True
4. I believe the answer is 7

Answer:NAME:     Nzube Erobu        DATE: 02/ 06 / 2020

Step-by-step explanation: With reference to the attached document, below:

1) False, the lines linking between TR and SV are diagonals

2) True,  ∠RVT = ∠ STV because they have the same right angled triangles.

3) True, because they separate triangles that have all angles in each triangle summing up to 180°  

4) (11 + 3)/2 = 14/2= 7

7) (15x - 5)° + (90 - 4x)° = 180°

(15x - 4x + 90 - 5)° = 180°

( x + 85)° = 180°

∴ x = 180° - 85° = 95°

8) (2x - 7)° + 117° = 180°

2x° +117° - 7° = 180°

2x° + 110° = 180°

2x = 180° - 110°

∴ x = 70°/2 = 35°

9) 4x - 1 + 6x + 11 = 60

4x + 6x + 11 -1 = 60

10x + 10 = 60

10x = 60 - 10 = 50

∴ x = 50/10 = 5

10) 18x + 19 - (10x + 3)  = 11

       18x - 10x + 19 - 3 = 11

8x + 16 = 11

8x = 11 - 16 = - 5

∴ x = - 5/8

11) 2x + 1 + 3x - 3 = 8

2x + 3x  - 3 + 1 = 8

5x - 2 = 8

5x = 8 + 2= 10

∴ x = 10/5 = 2

Twenty, which is 4 more than half, of the students in Bryan’s homeroom have tickets to attend the school’s musical. Choose Yes or No to tell whether each of the following equations can be used to find the number of students in Bryan’s homeroom.

Answers

One possible equation would be 20 = 1/2x + 4.

Let x be the number of students in his homeroom.  1/2x is half of the students in his homeroom.  Four more than 1/2 would be 1/2x + 4.  This is, or equals, the 20 students that have tickets.

The equations that can be used to find students with tickets is given as m/2 + 4 = 20. The correct options are (B) and (D).

How to write a linear equation?

A linear equation for the given case can be written by assuming any variable as the unknown quantity. Then, as per the given data the required operations are done and it is equated to some value.

Suppose the number of students in homeroom be m.

Then, as per the question the equation can be written as,

m/2 + 4 = 20

It can also be written as,

4 = 20 - m/2

Hence, the required equation for the given case is m/2 + 4 = 20.

To know more about linear equation click on,

https://brainly.com/question/11897796

#SPJ2

The complete question with all the options is attached here.

Two ships leave the same port in different directions, forming a 120° angle between them. One ship travels 70 mi. and the other 52 mi. before they each drop their anchors. What is the distance between the ships to the nearest mile?

Answers

Answer : Distance between the ships to the nearest miles = 106.03 ≈ 106 mi.

Explanation :

Since we have shown in the figure below :

a=70 mi.

b=52 mi.

c=x mi.

[tex]\text{Since two ships leaves the same port in different directions forming a }120\textdegree\text{angle between them.}[/tex]

So, we use the cosine rule , which states that

 [tex]c^2=a^2+b^2-2ab.cosC\\\\x^2=70^2+52^2-2\times 70\times 52\times cos(120\textdegree)\\\\x^2=4900+2704-7280\times (-0.5)\\\\x^2=7604+3640\\\\x^2=11244\\\\x=\sqrt{11244}\\\\x=106.03[/tex]

So, c = x= 106.03 mi.

Hence, distance between the ships to the nearest miles = 106.03 ≈ 106 mi.


simplify 28-(8+4). (4-2).

Answers

The value of 28-(8+4). (4-2) is 4

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Given;

28-(8+4). (4-2)

=28-(32-16+16-8)

=28-24

=4

Therefore, the value of the algebra will be 4

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ5

Final answer:

To simplify 28-(8+4)·(4-2), calculate the operations within the parentheses first, resulting in 28-12·2. Multiplying 12 by 2 gives 24, and subtracting this from 28 yields the simplified answer, which is 4.

Explanation:

The question requires us to simplify the expression 28-(8+4)·(4-2). We start by simplifying the operations inside the parentheses:


 (8+4) = 12
 (4-2) = 2

Next, we multiply the results from the parentheses:


 12·(4-2) = 12·2 = 24

Lastly, we subtract this value from 28:


 28 - 24 = 4

Therefore, the simplified expression is 4.

A total of
276

tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was two times the number of adult tickets sold. How many adult tickets were sold?

Answers

Final answer:

The number of adult tickets sold for the school play was 92, found by setting up an equation where the number of adult tickets plus twice the number of adult tickets equals the total of 276 tickets sold.

Explanation:

Calculating the Number of Adult Tickets Sold

The student is asked to find out how many adult tickets were sold for the school play, given that a total of 276 tickets were sold and the number of student tickets was two times the number of adult tickets sold. Let's denote the number of adult tickets as x and the number of student tickets as 2x. The total number of tickets is the sum of adult and student tickets which can be represented as:

x + 2x = 276

Combining like terms, we get:

3x = 276

To find the value of x, we divide both sides by 3:

x = 276 / 3

x = 92

Therefore, the number of adult tickets sold was 92.

What value is equivalent to ∣ −14 ∣?

Answers

It is positive 14
The absolute value of any negative number becomes positive.
Your answer is 14

The two lines on each sides mean the number is an absolute value. The absolute value of a number is always positive, even if the number is positive itself!

Hope this helps!

What is decomposing fractions

Answers

Explanation:

"Decomposing fractions" means breaking them into a sum of fractions, often unit fractions (fractions with a numerator of 1). Here are a few examples:

  3/8 = 1/8 + 1/8 + 1/8

  5/6 = 1/2 + 1/3

  3/4 = 1/2 + 1/4

The sum of the reciprocals of two consecutive even integers is 7/24. Write an equation that can be used to find the two integers. Find the two integers.

Answers

Assume the first even integer is x.
The next even integer will be 2 digits after this digit. So the next even integer will be x+2.

The reciprocals of these two even integers can be written as [tex] \frac{1}{x} [/tex] and [tex] \frac{1}{x+2} [/tex] respectively.

The sum of their reciprocals is 7/24. So we can set up the equation as:

[tex] \frac{1}{x}+ \frac{1}{x+2}= \frac{7}{24} [/tex]

Taking LCM on left hand side:

[tex] \frac{x+2+x}{x(x+2)}= \frac{7}{24} \\ \\ \frac{2x+2}{ x^{2} +2x}= \frac{7}{24} [/tex]

Cross Multiplying the denominators:

[tex]24(2x+2)=7({ x^{2} +2x}) \\ \\ 48x+48=7 x^{2} +14x \\ \\ 7 x^{2} +14x-48x-48=0 \\ \\ 7 x^{2} -34x-48=0 \\ \\ [/tex]

Using the quadratic formula to solve the above equation:
[tex]7 x^{2} -34x-48=0 \\ \\ x= \frac{34+- \sqrt{1156+1344} }{14} \\ \\ x= \frac{34+- \sqrt{2500} }{14} \\ \\ x=\frac{34+-50 }{14} \\ \\ x=6 \\ x=- \frac{8}{7} [/tex]

Since, the value of x can only be an integer, we discard the fractional value and keep x=6

So the first even integer is 6 and the next even integer is 8. The sum of reciprocals of 6 and 8 is 7/24

what fraction would you add to 29/6 to make 4

Answers

keeping in mind that 29/6 is greater than 4, is actually 4 and 5/6, so the amount we'll "add" will be a negative one.

[tex]\bf \cfrac{29}{6}+x=4\implies x=4-\cfrac{29}{6}\implies x=\cfrac{4}{1}-\cfrac{29}{6}\implies x=\cfrac{(6)4-(1)29}{6} \\\\\\ x=\cfrac{24-29}{6}\implies x=\cfrac{-5}{6}\\\\ -------------------------------\\\\ \cfrac{29}{6}+\left( -\cfrac{5}{6} \right)=4[/tex]

f(x)=x^2-2x-1  and   g(x)=5x-1/7x-3

find f(x+7) and g(x/2)

Answers

f(x + 7)
(x + 7)² - 2(x + 7) - 1
x² + 14x + 49 - 2x - 14 - 1
x² + 12x + 49 - 15
x² + 12x + 34
f(x + 7) = x² + 12x + 34

g(x/2)
5(x/2)² - 1/7(x/2) - 3
5(x²/4) - x/14 - 3
5x²/4 - x/14 - 3
g(x/2) = 5x²/4 - x/14 - 3

Can I have help with this please?

Answers

Try this:

2. 2.5/5=16/32; 2/4=16/34.

3. one - 6;6;6; two - 6;8;10; three - 5;10;12.

What does x equal (x/4)+12=38

Answers

[tex] \frac{x}{4} +12=38\\\\ \frac{x}{4}=26\\\\x=104[/tex]
x/4 = 26
X = 104
I think that’s it....

Two mechanics can assemble 10 bicycles in 8 hours. How many bicycles could one mechanic assemble in 8 hours?

Answers

Answer:

5 bicycles

Step-by-step explanation:

In the same time period (8 hours), half as many mechanics can assemble half as many bicyles: 10/2 = 5.

Find the value of x. Then find the measures of B and C

Answers

recall that the sum of all interior angles in a triangle is 180°, therefore

[tex]\bf \stackrel{A}{(48)}~+~\stackrel{B}{(6x-28)}~+~\stackrel{C}{2x}~=~180\implies 8x+20=180 \\\\\\ 8x=160\implies x=\cfrac{160}{8}\implies x=20\\\\ -------------------------------\\\\ \measuredangle B=6(20)-28\qquad \qquad \qquad \measuredangle C=2(20)[/tex]

3(10+2j) please help me

Answers

30+6j im not sure but i hope it is the correct answer
30 + 6j plz give me the brainliest.

your banking cupcakes for the school dance and your recipe makes 24 cupcakes and needs 2 cups of milk . you need to make 288 cupcakes how many quarts of milk will you need

Answers

6 quarts of milk will be needed
6 quarts, or 24 cups

If an object is projected upward with an initial velocity of 125 125 ft per​ sec, its height h after t seconds is h equals negative 16 t squared plus 125 t h=−16t2+125t. Find the height of the object after 5 5 seconds.

Answers

for this problem all we need to do is ignore everything except the equation and the input (5.5)

so the steps for this problem are below
we need to plug in 5.5 into our equation as it's our input of time to get our output of height
[tex]t(5.5) = - 16(5.5) {}^{2} + 125(5.5)[/tex]
after simplifying you get

remember to square the 5.5 first (order of operations)

[tex]t(5.5) = - 16(30.25) + 687.5[/tex]

simplify just a tad more and we get this as the final answer
[tex]t(5.5) = - 484 + 687.5 = 203.5[/tex]
[tex]203.5 \: ft[/tex]

244 ft I’m pretty sure
Other Questions
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