Before sending track and field athletes to the Olympics, the U.S. holds a qualifying meet.
The upper box plot shows the top 12men's long jumpers at the U.S. qualifying meet. The lower box plot shows the distances (in meters) achieved in the men's long jump at the2012 Olympic games.
Which pieces of information can be gathered from these box plots?
Choose all answers that apply:
Choose all answers that apply:

(Choice A)
A
The Olympic jumps were farther on average than the U.S. qualifier jumps.

(Choice B)
B
All of the Olympic jumps were farther than all of the U.S. qualifier jumps.

(Choice C)
C
The Olympic jumps vary noticeably more than the U.S. qualifier jumps.

(Choice D)
D
None of the above
2 horizontal boxplots titled U.S. Qualifier and Olympics are graphed on the same horizontal axis, labeled Distance, in meters. The boxplot titled U.S. Qualifier has a left whisker which extends from 7.68 to 7.7. The box extends from 7.7 to 7.89 and is divided into 2 parts by a vertical line segment at 7.74. The right whisker extends from 7.9 to 7.99. The boxplot titled Olympics has a left whisker which extends from 7.7 to 7.83. The box extends from 7.83 to 8.12 and is divided into 2 parts by a vertical line segment at 8.04. The right whisker extends from 8.12 to 8.31. All values estimated.

Answer:

Step-by-step explanation:

Answer:

The Answer is B.

Step-by-step explanation:

I took the test on Edg 2021 and got it right the first time.

Answer:

9/35

Step-by-step explanation:

-1/7 ÷ -5/9

Copy dot flip

-1/7 * -9/5

Multiply the numerators

-1*-9 = 9

Multiply the denominators

7*5 = 35

9/35

Step-by-step explanation:

[tex]\frac{-\frac{1}{7} }{-\frac{5}{9} }[/tex]

Invert the fraction in the denominator and multiply it by the fraction in the numerator.

[tex](-\frac{1}{7} )(-\frac{9}{5} )\\\\\frac{9}{35}[/tex]

Answer:

[tex] p_v= 0.01[/tex]

Since the significance level is 0.05 we see that [tex]pv<\alpha[/tex] so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: [tex]\mu_{A}=\mu_{B}=\mu_{C}= \mu_D[/tex]

Alternative hypothesis: Not all the means are equal [tex]\mu_{i}\neq \mu_{j}, i,j=A,B,C,D[/tex]

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have [tex]p=4[/tex] groups and on each group from [tex]j=1,\dots,p[/tex] we have [tex]n_j[/tex] individuals on each group we can define the following formulas of variation:  

[tex]SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 [/tex]  

[tex]SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 [/tex]  

[tex]SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 [/tex]  

And we have this property  

[tex]SST=SS_{between}+SS_{within}[/tex]  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

[tex] p_v= 0.01[/tex]

Since the significance level is 0.05 we see that [tex]pv<\alpha[/tex] so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

The correct option is (d)not all of the average gestation periods are the same across all four species.

In a test of hypothesis, the test statistic is a function of the sample data used to decide whether or not to reject the null hypothesis.

Given that,

[tex]\alpha=0.05\\p-value=0.009[/tex]

[tex]H_0:[/tex]The average gestation period is the same for each of the four spices.

Since the p-value is less than the value of the [tex]\alpha[/tex].

So, we reject the [tex]H_0[/tex]

Not all of the average gestation periods are the same across all four species.

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Answer:

the answer is A(4.5)

Step-by-step explanation:

y/6 = 6/8

y=9/2 = 4.5

Answer:

QS + QR > RS

QR + RS > QS

RS + QS > QR

Step-by-step explanation:

JUST TOOK THE TEST

The complete Triangle Inequality is

The triangle inequality theorem defines the relationship between a triangle's three sides. The total of the lengths of the two sides of any triangle is always greater than the length of the third side, according to this theorem. In other words, the shortest distance between two unique points is always a straight line, according to this theorem.

According to Triangle Inequality " the sum of two side of the triangle is greater than the third side of Triangle."

Then, applying Triangle Inequality

QS + QR > RS

QR + RS > QS

RS + QS > QR

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Answer:

Step-by-step explanation:

GIVEN: Suppose you want to make a cylindrical pen for your cat to play in (with open top) and you want the volume to be [tex]100[/tex] cubic feet. Suppose the material for the side costs [tex]\$3[/tex] per square foot, and the material for the bottom costs [tex]\$7[/tex] per square foot.

TO FIND: What are the dimensions of the pen that minimize the cost of building it.

SOLUTION:

Let height and radius of pen be [tex]r\text{ and }h[/tex]

Volume [tex]=\pi r^2h=100\implies h=\frac{100}{\pi r^2}[/tex]

total cost of building cylindrical pen [tex]C=3\times \text{lateral area}+7\times\text{bottom area}[/tex]

                                                                [tex]=3\times2\pi r h+7\times\pi r^2=\pi r(6h+7r)[/tex]

                                                                [tex]=\frac{600}{r}+7\pi r^2[/tex]

for minimizing cost , putting [tex]\frac{d\ C}{d\ r}=0[/tex]

[tex]\implies -\frac{600}{r^2}+44r=0 \Rightarrow r^3=\frac{600}{44}\Rightarrow r=2.39\text{ feet}[/tex]

[tex]\implies h=5.57\text{ feet}[/tex]

Hence the radius and height of cylindrical pen are [tex]2.39\text{ feet}[/tex] and [tex]5.57\text{ feet}[/tex] respectively.

Answer:

16y + 32

Step-by-step explanation:

Expand each term.

(y+6)² - (y-2)²

= (y+6)(y+6) - (y-2)(y-2)

= y² + 12y + 36 - (y² - 4y + 4)

Subtract the second group by changing each term's signs

= y² + 12y + 36 - y² + 4y - 4

Collect like terms

= 16y + 32

Answer:

5 inches.

Step-by-step explanation:

We know that the circumference of a circle is equivalent to πr² or πd.

We need to know the radius given the circumference.

C = πr²

75 = 3.14(r^2)    (Divide both sides by 3.14)

23.88535031847134 = r^2    (Take the square root of both sides)

r ≈ 4.88726409338

r ≈ 5 inches.

Answer:

Step-by-step explanation:

You can use the simple one.

20*0.15*n year= answer

answer+20

or Compound

20*0.15 to de power of the year(s)

Answer:

Domain is where the function is defined.  In other words, all valid values of x that allows us to find y.

Range is values of y for the function.

Step-by-step explanation:

Here is the example of function [tex]y = \sqrt{x}[/tex], so domin is between 0 and positive infinity.  x cannot be negative.

The range is from 0 (because that's the lowest value of y) to positive infinity

Answer:

all nonzero real numbers for both of them

Step-by-step explanation:

e2021

Los tres puntos son (-3,0), (3,0), (0,4).

Por lo tanto, la respuesta es A, espero que esto ayude, que tenga un buen día.

Answer:

3/5 then 11/5

Step-by-step explanation:

These symbols "I  I" represent absolute values.

11/5 equals to 2 1/5

3/5 is less than 2 1/5

Answer:

b) 74

The sample size that needs to be taken if the desired margin of error is 5 or less is 74

Step-by-step explanation:

Explanation:-

Given population variance σ² = 484

                                            σ = √484

                                            σ = 22

The level of significance ∝=0.95

The z-score of 0.95 level of significance = 1.96

Given Margin of error = 5

we know that the margin of error is determined by

[tex]M.E = \frac{Z_{\alpha }S.D }{\sqrt{n} }[/tex]

cross multiplication, we get

[tex]\sqrt{n} = \frac{Z_{\alpha }S.D }{M.E}[/tex]

[tex]\sqrt{n} = \frac{1.96 X22 }{5} = 8.624[/tex]

Squaring on both sides, we get

n = (8.624) ²

n = 74.37 ≅74

Conclusion:-

The sample size that needs to be taken if the desired margin of error is 5 or less is 74

Answer:

C

Step-by-step explanation:

If the line is parallel that means 1.2 has to be the same. And passing through (5,0) means a plus five.

To determine the sample size needed for a 99% confidence interval with a maximum width of .18 for a coin flip experiment, we must rely upon statistical principles such as the law of large numbers and the relationship between sample size and confidence interval width. Although we cannot give a specific number without more details, it is generally true that a larger sample size (i.e., more coin flips) results in a narrower confidence interval.

Your question pertains to finding the necessary sample size for a particular width of a confidence interval in a coin-flip experiment. A confidence interval represents the range where we are certain that the parameter, in this case, the probability of getting a head, lies to a certain degree, say 99%. Narrowing down this interval or making it smaller would require a larger number of coin flips or trials. The probable outcome of our experiment does indeed align with the theoretical probability when a large number of trials is conducted, which is also known as the law of large numbers.

The calculation of the size of a confidence interval involves standard deviation, confidence level (z-score) and sample size. By adjusting these parameters, we can alter the size of a confidence interval. For example, a 90% confidence interval would be smaller compared to a 95% interval due to the decreased degree of certainty. However, without exact numbers we cannot directly calculate how many flips are required for a 99% confidence interval of a certain width.

As a general rule of thumb, when conducting confidence interval tests, it would be safe to suggest that a larger sample size (which for a coin flip experiment would mean more coin flips) will result in a narrower confidence interval. Therefore, to achieve a 99% confidence interval of width at most .18, one would need net a large number of trials, or flips.

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Answer:

y = 6x-4

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

We know the slope is 6 and the y intercept is -4

y = 6x + -4

y = 6x-4

Slope-intercept form: y = mx + b (m = slope and b = y-intercept)

Slope (m) = 6

y-intercept (b) = -4

Put into its final form.

y = 6x - 4

Best of Luck!

Answer:

  $558.68

Step-by-step explanation:

The amount of each monthly payment is given by the amortization formula:

  A = P(r/n)/(1 -(1 +r/n)^(-nt)

where P is the principal borrowed, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.

We want to find nA where we have n=12, r=0.21, t=1, P=500. Filling in these values, we get ...

  nA = Pr/(1 -(1 +r/n)^-n) = $500(0.21)/(1 -1.0175^-12) = $558.68

The total amount needed to repay the loan in 1 year is $558.68.

Answer:

$615.72

Step-by-step explanation:

Use the compound interest formula and substitute the given value: A=$500(1+0.21/12)^12(1)

Simplify using order of operations: A=$500(1.0175)^12=$500(1.231439315)

=$615.72

The area of a rectangle combined with a semi-circle can be found by adding the rectangular area calculated via Length x Width to the semi-circular area calculated by 0.5 x π x r². The total area in this case would be approximately 5981.75 m².

The area of a field that is shaped like a rectangle with a semi-circle at one end can be found by summing the area of the rectangle and the area of the semi-circle. The area of a rectangle is given by the formula Length x Width. So in this instance, the rectangle's area would be 100m x 50m = 5000 m². The area of a semi-circle is given by the formula 0.5 x π x r², where r is the radius of the semi-circle. Given one side of the rectangle is along the diameter of the semi-circle, the radius of the semi-circle would be half the width of the rectangle, i.e., 25m. So the area of the semi-circle would be 0.5 x π x 25m² = 0.5 x 3.1416 x 625 = 981.75 m² approximately.  Therefore, the total area of the field would be 5000 m² + 981.75 m² which is 5981.75 m² approximately.

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Answer:

They should go on to launch the online edition

Step-by-step explanation:

Total surveyed = 400

A = accept if 15% above subscribes

B = reject if subscribers are less than 15%

on the survey it is clearly stated that 67 expressed interest.

 lets get 16% of total survey

      = 15% x 400

      = 60.

Since number of subscribers that showed interest is greater than number 15%

Hence the company can go ahead to launch the online edition

Accept A

Answer:

a) The null hypothesis is

H₀: μ₀ = 3 inches

And the alternative hypothesis is

Hₐ: μ₀ ≠ 3 inches

b) Check Explanation.

c) The $3000 is obviously the cost of a type I error.

Step-by-step explanation:

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and is always about the absence of significant difference between two proportions being compared. It usually maintains that random chance is responsible for the outcome or results of any experimental study/hypothesis testing. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis takes the other side of the hypothesis; that there is indeed a significant difference between two proportions being compared. It usually confirms the the theory being tested by the experimental setup. It usually maintains that other than random chance, there are significant factors affecting the outcome or results of the experimental study/hypothesis testing. It usually contains the signs ≠, < and > depending on the directions of the test.

For this question, we want to verify that the mean diameter produced by the machine is really off-target.

Note that, that target is 3 inches.

Hence, the null hypothesis will be that that there is no difference between the mean diameter of the 100 cylinders sampled and the target of 3 inches.

And the alternative hypothesis will confirm the concerns of the technical staff that there is a significant difference between the mean diameter of the 100 cylinders sampled and the target diameter of 3 inches. That is, the mean diameter is off-target.

Mathematically,

The null hypothesis is

H₀: μ₀ = 3 inches

And the alternative hypothesis is

Hₐ: μ₀ ≠ 3 inches

b) A type I error involves rejecting the null hypothesis and accepting the alternative hypothesis when in reality, the null hypothesis is true. It involves saying there is significant evidence to show that the mean diameter of the sampled cylinders is indeed different from the targeted 3 in. (that is, the mean diameter of sampled cylinders is off-target), so they try to fix the issue when in reality, there is actually no significant difference between the mean diameter of sampled cylinders and the targeted 3 inches.

While a type II error involves failing to reject the null hypothesis when in reality it should have been rejected.

It entails not rejecting the null hypothesis and making conclusions based on the null hypothesis, when in reality, the alternative hypothesis should have been accepted together with its conclusion.

In this one the firm would conclude that they do not need to change anything as there is no significant difference between the mean diameter of the sampled cylinders and the targeted 3 inches, when in reality, there is a significant difference between the mean diameter of the sampled cylinders and the targeted 3 inches diameter.

c) The $3000 is obviously the cost of a type I error.

This is because the type I error is the one that involves tryin to fix the problem that did not even exist in reality.

Hope this Helps!!!

Answer:

Step-by-step explanation:

An Automobile Parts supplier owns a machine that produces a cylindrical engine part. The part is supposed to have an outside diameter of 3 inches in order for customers requirements to be met.

Lately, the company has been producing cylindrical engine parts with diameters that are either < 3inches or > 3inches. Technical staff feel that the mean diameter produced by the machine, from a random sample of 100 engine parts is not equal to 3 inches. The parts supplier wishes to set up a hypothesis test so that the problem-solving team can swing into action if or when the Null Hypothesis is rejected.

The null hypothesis is:

100 Cylindrical Engine Parts have a mean diameter = 3 inches

The alternative hypothesis is:

100 Cylindrical Engine Parts have a mean diameter that is NOT equal to 3 inches

[You can input the "not equal to" sign]

If the null hypothesis is rejected after statistical procedures, the supplier will proceed to employ the services of the problem-solving team!

Given:

Given that the length of VX is 15.

The length of WX is 7.

We need to determine the altitude UX of the given triangle.

Altitude UX:

The value of the altitude UX can be determined using the altitude rule theorem.

Applying the theorem, we have;

[tex]\frac{left}{altitude}=\frac{altitude}{right}[/tex]

Substituting left = UX, altitude = VX and right = VW in the above formula, we get;

[tex]\frac{UX}{VX}=\frac{VX}{XW}[/tex]

Substituting the values, we get;

[tex]\frac{UX}{15}=\frac{15}{7}[/tex]

Multiplying both sides of the equation by 15, we have;

[tex]UX=\frac{15 \times 15}{7}[/tex]

[tex]UX=\frac{225}{7}[/tex]

[tex]UX=32.14[/tex]

Thus, the length of UX is 32.14 units.

Answer: Its 32.14

Step-by-step explanation:

Answer:

The area can be found using the formula A = b h

The area is 21.96 m2.

Step-by-step explanation:

We conclude that the area of the parallelogram is 21.96m²,  so the correct option is the last one.

For a parallelogram of base b and height h, the area is:

A = b*h

In this case, we have that the base is 3.6m and the height is 6.1m, replacing that in the area equation we get:

A = 3.6m*6.1m = 21.96m²

Then we conclude that the area of the parallelogram is 21.96m²,  so the correct option is the last one.

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Answer:

0.13% probability that this selected sample has an average thickness greater than 53

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, we have that:

[tex]\mu = 50, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1[/tex]

What is the probability that this selected sample has an average thickness greater than 53?

This is 1 subtracted by the pvalue of Z when X = 53. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{53 - 50}{1}[/tex]

[tex]Z = 3[/tex]

[tex]Z = 3[/tex] has a pvalue of 0.9987

1 - 0.9987 = 0.0013

0.13% probability that this selected sample has an average thickness greater than 53

Answer:

There are 3 equivalent fractions 28 /30, 42/45,56/6

Answer:

59/10

Step-by-step explanation:

5+9/10

50/10 + 9/10

=59/10

Answer:

it 59/10

Step-by-step explanation:

Answer:

Its the neither option

Step-by-step explanation:

In a normal distribution, the mean and median are equal.

Option C is the correct answer.

It is the average value of the set given.

It is calculated as:

Mean = Sum of all the values of the set given / Number of values in the set

We have,

In a normal distribution,

The mean and median are both measures of central tendency.

The mean is calculated by adding up all the values in the distribution and dividing by the total number of values.

The median is the value that falls in the middle when the data is arranged in order.

Now,

In a perfectly symmetrical normal distribution, the mean and median are equal and they both fall at the exact center of the distribution.

However, if the distribution is skewed to one side or the other, the mean and median may be different.

Thus,

In a normal distribution, the mean and median are equal.

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The optimal point where the cable splits into two branches for Springfield and Shelbyville is at point (4,0) on the x-axis. This is computed through calculus principles for optimization and the distance formula. The minimum total cable length connecting all three towns is about 11.66 units.

The subject of this problem is optimization in mathematics, specifically in coordinate geometry and calculus. The problem can be solved using the distance formula in the xy-plane as well as the principles of differential calculus.

Let's denote the point (x,0) where cable splits as P, Centerville as C, Springfield as S and Shelbyville as Sh. By using the distance formula, we can determine the lengths of the branch cables, CS and CSh.

The total length of the cable is the sum of these two distances. That gives us: Cable Length = sqrt[(8-x)²+7²] + sqrt[(8-x)²+(-7)²].

To find the minimum cable length, we differentiate the above function and equate it to zero to find the critical points. Using differential calculus, we can see that minimum cable length reduces to x = 4. Therefore, the point where cable splits is (4, 0).

Substitute x = 4 into the cable length equation to get the minimum total cable length, which is roughly 11.66 units.

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The location that minimizes the amount of cable is [tex](\frac{7}{\sqrt 3},0)[/tex], total length being 20.12 units.

To minimize the amount of cable needed in the Y-shaped configuration, we need to find the optimal point (x, 0) on the x-axis where the cable splits. This point should minimize the total length of cable from Centerville to Springfield and Shelbyville.

Step-by-Step Solution:

1. Identify the distances involved:

  - The distance from Centerville (8,0) to (x,0) on the x-axis.

  - The distance from (x,0) to Springfield (0,7).

  - The distance from (x,0) to Shelbyville (0,-7).

2. Define the distances mathematically:

  - The distance from Centerville to (x,0) is:

  [tex]\[ L_1 = |8 - x| \] - The distance from \((x,0)\) to Springfield \((0,7)\) is: \[ L_2 = \sqrt{x^2 + 7^2} = \sqrt{x^2 + 49} \] - The distance from \((x,0)\) to Shelbyville \((0,-7)\) is: \[ L_3 = \sqrt{x^2 + (-7)^2} = \sqrt{x^2 + 49} \][/tex]

3. Total length of the cable L:

[tex]\[ L = L_1 + L_2 + L_3 = |8 - x| + \sqrt{x^2 + 49} + \sqrt{x^2 + 49} \] \[ L = |8 - x| + 2\sqrt{x^2 + 49} \][/tex]

4. Optimize the total length L:

  To find the minimum, we need to consider the derivative of L with respect to x. Since L involves absolute value, we'll consider two cases: x ≤ 8) and x > 8.

  Case 1: x ≤ 8

[tex]\[ L = (8 - x) + 2\sqrt{x^2 + 49} \] \[ \frac{dL}{dx} = -1 + 2 \cdot \frac{x}{\sqrt{x^2 + 49}} \][/tex]

  Set the derivative equal to zero to find critical points:

[tex]\[ -1 + 2 \cdot \frac{x}{\sqrt{x^2 + 49}} = 0 \] \[ 2 \cdot \frac{x}{\sqrt{x^2 + 49}} = 1 \] \[ \frac{x}{\sqrt{x^2 + 49}} = \frac{1}{2} \] \[ x = \frac{\sqrt{x^2 + 49}}{2} \][/tex]

  Square both sides to solve for x:

[tex]\[ x^2 = \frac{x^2 + 49}{4} \] \[ 4x^2 = x^2 + 49 \] \[ 3x^2 = 49 \] \[ x^2 = \frac{49}{3} \] \[ x = \frac{7}{\sqrt{3}} = \frac{7\sqrt{3}}{3} \][/tex]

Case 2: (x > 8)

  This case would lead to a contradiction because the optimal point must lie on the interval [tex]\(0 \leq x \leq 8\)[/tex] for the Y-configuration to be practical.

Conclusion:

The point (x, 0) that minimizes the total length is:

[tex]\[x = \frac{7\sqrt{3}}{3}\][/tex]

[tex]1. \(d_1 = |x - 8| = \left| \frac{7}{\sqrt{3}} - 8 \right|\)\\2. \(d_2 = \sqrt{x^2 + 49} = \sqrt{\left(\frac{7}{\sqrt{3}}\right)^2 + 49}\)\\3. \(d_3 = \sqrt{x^2 + 49} = \sqrt{\left(\frac{7}{\sqrt{3}}\right)^2 + 49}\)[/tex]

[tex]\[ \text{Total length} = \left| \frac{7}{\sqrt{3}} - 8 \right| + 2\sqrt{\left(\frac{7}{\sqrt{3}}\right)^2 + 49} \]\[ \text{Total length} = \left| \frac{7}{\sqrt{3}} - 8 \right| + 2\sqrt{\frac{49}{3} + 49} \]\[ \text{Total length} = \left| \frac{7}{\sqrt{3}} - 8 \right| + 2\times \sqrt{16.33+49}\]\[ \text{Total length} = \left| 4.04 - 8 \right| + 2\times 8.08\][/tex]

[tex]\text{Total length}=3.96+16.16=20.12[/tex]

Answer:

m<56. that is all I can help with

Answer:

2.4 or 2 2/5

Step-by-step explanation:

When you multiply 12/15 and 3 you get 2.4 or 2 2/5

Answer:

Exact form: 12/5

Decimal form: 2.4

Mixed number form: 2 2/5

Step-by-step explanation:

You multiply 12 by 3, and 15 by 1, then simplify your answer.