Blue cassests hold 45 min. Of music
Green cassets hold 55 min. Of music
If Niko has 16 cassets containing 830 min. Of music
How many are blue? And how many are green?

Answers

Answer 1
let the number of Blue casset be b and that of green be g.
Thus the total number of cassets will be:
b+g=16
hence
g=16-b.......i

The total amount was:
45b+55g=830..ii
plugging i in ii we get:
45b+55(16-b)=830
45b+880-55b=830
simplifying 
45b-55b=830-880
-10b=-50
thus
b=5
hence
g=16-5=11
number of blue cassets was 5 and that of green was 11 

Related Questions

the speed limit is 55 minutes per hr. write an inequalit to represent the speed limit.

Answers

Answer: Either [tex]x \le 55[/tex] or [tex]0 \le x \le 55[/tex] depending on your teacher's preference. See the note at the bottom for more info. 

=====================================

Let x be the speed limit. It is simply a placeholder. Think of it as a box with the number inside. We don't know what the number is, but we know that the largest it can be is 55. It cannot be larger than 55.

So x can be equal to 55 or it can be smaller

Put another way, x is less than or equal to 55 which is written as [tex]x \le 55[/tex] (on the keyboard you would type " x <= 55 " without quotes). 

---------------------------------------

Note: since negative speeds make no sense, we also must imply that x can't be negative. Your teacher may want you to write this in to clearly state it. If so, then you would also have [tex]x \ge 0[/tex] which when combined with the first inequality, you get this compound inequality [tex]0 \le x \le 55 [/tex] (basically saying "x is some speed between 0 and 55 mph"). This very clearly states the boundaries on what x can be. Though your teacher may want you to stick to the first format as its simpler. 

one more question please help me!!!

Answers

a = (9/6)*10 mm = 15 mm

b = (35/10)*6 mm = 21 mm

The ratio in parentheses is the ratio of corresponding sides in the respective rectangles, so is the scale factor. The unknown dimension is that scale factor applied to the corresponding known dimension.

A mountain climber is at an altitude of 2.9 mi above the earths surface. From the climbers viewpoint what is the distance to the horizon

Answers

we know that
applying the Pythagorean theorem
(3959+2.9)²=x²+3959²
x²=(3959+2.9)²-3959²
x²=3961.9²-3959²
x²=22970.61
x=√22970.61
x=151.56 mi

the answer is
x=151.56 mi

Please help me with this question

Answers

Equation A simplifies to 0 = 0. It is always true.

Equation B simplifies to 1 = -1 for a ≠ 0. It is never true.

Equation C simplifies to 2a = 0. It is true only for a = 0.

Equation D simplifies to 2a = 0. It is only true for a = 0.

The equation that is true for all values of "a" is ...
  A. Equation A

If rain is falling at a rate of ¼ inch per hour, how much rain would you expect after 6 hours

Answers

1 hour = 1/4 inch 

6 hours = 1/4 x 6 = 6/4 = 1 1/2 inches

Answer: 1 1/2 inches

At the deli Jennifer bought roasted turkey and provolone cheese. The turkey costs $6.35 per pound and the cheese costs $4.75 per pound. In total, she bought 3 pounds and the price was $17.13 How many pounds of each did she buy?

Answers

She bought two pounds of turkey and one pound of cheese

Let the amounts of Turkey Jennifer bought be [tex] T [/tex] pounds and that of Cheese be [tex] C [/tex] pounds.

From the given information,

[tex] 6.35T+4.75C=17.13\\
T+C=3 [/tex]

Solving the above two equations together,

[tex] 6.35T+4.75(3-T)=17.13\\
(6.35-4.75)T+4.75*3=17.13\\
1.6T=2.88\\
T=\frac{2.88}{1.6}\\
T=1.8
[/tex]

Thus, Jennifer bought [tex] 1.8\;pounds [/tex] of Turkey and [tex] 3-1.8=1.2\;pounds [/tex] of Cheese.

What are the missing pieces to the steps? –27 = 4x2 – 24x –27 = 4(x2 – 6x) –27 + = 4(x2 – 6x + 9) 9 = 4(x – 3)2 = (x – 3)2 ± = x – 3 = x

Answers

i think the 4 wasn't distributed correctly.  it should be one of the first steps.

Answer:

We can find out the missing pieces by the below explanation,

Here, the given equation,

[tex]-27 = 4x^2 - 24x[/tex]

Step 1 :

[tex]-27=4(x^2-6x)[/tex]

Step 2 :

[tex]-27+36=4(x^2-6x+9)[/tex]

Step 3 :

[tex]9=4(x-3)^2[/tex]

Step 4 :

[tex]\frac{9}{4}=(x-3)^2[/tex]

Step 5 :

[tex]\pm \frac{3}{2}=x-3[/tex]

Step 6 :

[tex]x=3\pm \frac{3}{2}[/tex]

50 POINTS...Which equation would best help solve the following problem? Tania releases a javelin 1.6 meters above the ground with an initial vertical velocity of 25 meters per second. How long will it take the javelin to hit the ground?

Answers

Let [tex]x(t)[/tex] be the vertical position of the javelin at time [tex]t[/tex]. Once it's thrown in the air, the only force acting on it is gravity, so the javelin would be subjected to a constant downward acceleration of approx. 9.8 meters per second per second. So

[tex]x''(t)=-9.8[/tex]

Integrating once with respect to [tex]t[/tex], we get

[tex]x'(t)=-9.8t+C_1[/tex]

where [tex]x'(t)[/tex] is the velocity of the javelin. We're told that [tex]x'(0)=25[/tex], so

[tex]25=-9.8\cdot0+C_1\implies C_1=25[/tex]

Integrating again with respect to [tex]x[/tex] to get

[tex]x(t)=-4.9t^2+25t+C_2[/tex]

and we know the javelin was initially thrown 1.6 meters above the ground, or [tex]x(0)=1.6[/tex], so we get

[tex]1.6=-4.9\cdot0^2+25\cdot0+C_2\implies C_2=1.6[/tex]

So the javelin's position at any time [tex]t[/tex] is given by

[tex]x(t)=-4.9t^2+25t+1.6[/tex]

It will hit ground when [tex]x(t)=0[/tex]. Solve this however you want; you'll find that this will happen at about [tex]t=5.165[/tex] seconds after the javelin has been thrown.
im doing the same quiz anyone know number 1 with the base of a traingle or something

Hey can you please help me out posted picture

Answers

We have for this case:
 For each language we have:
 Number of people who speak Spanish:
 Spanish = 8 + 4 = 12
 Number of people who speak Chinese:
 Chinese = 5 + 6 = 11
 Number of people who speak both languages:
 Both = 3 + 2 = 5
 Adding we have:
 12 + 11 + 5 = 28
 Answer:
 28
 option A
Number of employees who speak only Spanish = 8
Number of employees who speak only Chinese = 6
Number of employees who speak Spanish and Russian = 4
Number of employees who speak Spanish and Chinese = 3
Number of employees who speak all three languages = 2
Number of employees who speak Chinese and Russian = 5

The number of employees who speak Spanish or Chinese or both will be the sum of all above values. The sum is = 28

Thus the correct answer is option A


number of per month__number of moviegoers
more than 7____________96
5-7_______________ ___180
2-4__________________219
less than 2____________205
total _________________700


Use the frequency table. Find the probability that a person goes to the movies at least 2 times a month. Round to the nearest thousandth.

A. 0.138

B. 0.707

C. 0.137

D. 0.394

sorry for the poor graph up top,,,,:/

Answers

Leave out those who went less than twice to get those who went at least twice 
pr = (700 - 205)/700 = 0.7071 <-------

So answer is B

Answer:

B. 0.707

Step-by-step explanation:

The frequency table is given by,

Number of months                         Number of movie goers

     More than 7                                                96                  

           5 - 7                                                      180

           2 - 4                                                      219

      Less than 2                                               205

           Total                                                     700

Since, Probability of an event is the ratio of favorable events to the total number of events.

As, the number of people going to movies atleast 2 times a month = 96 + 180 + 219 = 495

The probability that a person goes to the movies atleast 2 times a month = [tex]\frac{495}{700}=0.707[/tex].

Thus, option B is correct.

the following shows the correlation between the length of a person's handspan and how many jolly ranchers they can pick up with one hand.
Which of the following does the data suggest?
a. strong positive
b. strong negative
c. no relation
d.weak negative
( please help)

Answers

It is A) strong positive, because the slope is graphing up

Answer:

a. strong positive is the answer.

Step-by-step explanation:

The following shows the correlation between the length of a person's hand span and how many jolly ranchers they can pick up with one hand.  

There is a strong positive correlation between the two things. We can see the scatter plot moving up as the hand span increases, the number of jolly ranchers they can pick up also increases.

4.
Find the present value of the annuity.

Amount Per Payment: $4,725

Payment at End of Each: 6 months

Number of Years: 15

Interest Rate: 10%

Compounded: Semiannually


$72,634.83

$35,938.73

$32,242.03

$68,951.03

Answers

To solve this we are going to use the present value of annuity formula: [tex]PV=P[ \frac{1-(1+ \frac{r}{n})^{-kt} }{ \frac{r}{n} } ][/tex]
where
[tex]PV[/tex] is the present value 
[tex]P[/tex] is the periodic payment 
[tex]r[/tex] is the interest rate in decimal form 
[tex]n[/tex] is the number of times the interest is compounded per year 
[tex]k[/tex] is the number of payments per year 
[tex]t[/tex] is the number of years 

We know from our problem that [tex]P=4725[/tex] and [tex]t=15[/tex]. To convert the interest rate to decimal form, we are going to divide it by 100%:
[tex]r= \frac{10}{100} [/tex]
[tex]r=0.1[/tex]
Since the interest is compounded semiannually, it is compounded 2 times per year; therefore, [tex]n=2[/tex]. Similarly, since the payment is made at the end of each 6 months, it is made 2 times per year; therefore, [tex]k=2[/tex].
Lest replace the values in our formula:

[tex]PV=P[ \frac{1-(1+ \frac{r}{n})^{-kt} }{ \frac{r}{n} } ][/tex]
[tex]PV=4725[ \frac{1-(1+ \frac{0.1}{2})^{-(2)(15)} }{ \frac{0.1}{2} } ][/tex]
[tex]PV=72634.83[/tex]

We can conclude that the correct answer is $72,634.83

The quantity demanded each month of the walter serkin recording of beethoven's moonlight sonata, manufactured by phonola media, is related to the price per compact disc. the equation p = −0.00054x + 9 (0 ≤ x ≤ 12,000) where p denotes the unit price in dollars and x is the number of discs demanded, relates the demand to the price. the total monthly cost (in dollars) for pressing and packaging x copies of this classical recording is given by c(x) = 600 + 2x − 0.00002x2 (0 ≤ x ≤ 20,000)

Answers

We can get the Profit function P(x) from the Hint. 

the Profit function is: P(x) = xp(x) - C(x) = -0.00041 x2 + 4x - 600
Attention: don't get confuse by the big P of the profit with the small p of the price To calculate the maximum profit, we need to find the derivative of P(x) then set it to 0 then find x: dP(x)/dx = -0.00082 x + 4 = 0 ,   so x = 4/0.00082 = 4,878 copies each month.
Final answer:

To find the equilibrium price and quantity, we set the demand to be equal to the supply, solve for x, and substitute the value back into the demand equation to find the equilibrium price.

Explanation:

The given equation is:

p = -0.00054x + 9, where p is the unit price in dollars and x is the number of discs demanded.

The total monthly cost for pressing and packaging x copies is given by:

c(x) = 600 + 2x - 0.00002x^2

To find the equilibrium price and quantity, we need to find the point where the demand equals the supply. In this case, the demand is represented by the equation p = -0.00054x + 9 and the supply is represented by the equation c(x) = 600 + 2x - 0.00002x^2.

To solve for the equilibrium price and quantity, we set the demand equals the supply:

-0.00054x + 9 = 600 + 2x - 0.00002x^2

This equation can be solved by rearranging and solving for x:

0.00002x^2 + 2.00054x - 591 = 0

Using the quadratic formula, we can find the values of x that satisfy this equation:

x = (-2.00054 ± sqrt(2.00054^2 - 4*0.00002*(-591))) / (2*0.00002)

After calculating, we find two possible values for x, which are approximately x_1 = 13727.927 and x_2 = -0.036. However, since the quantity demanded cannot be negative, we discard the negative value.

The equilibrium quantity is approximately 13728.

To find the equilibrium price, we substitute the value of x into the demand equation:

p = -0.00054(13728) + 9

p is approximately equal to $1.53.

Learn more about Equilibrium price and quantity here:

https://brainly.com/question/35834365

#SPJ3

Find the absolute maximum of f(x,y) = e^(-x^2-y^2)(x^2+2y^2) on x^2 + y^2 < 2

Answers

[tex]f(x,y)=e^{-x^2-y^2}(x^2+y^2)[/tex]

Notice that converting to polar coordinates, setting
[tex]x=r\cos\theta[/tex]
[tex]y=r\sin\theta[/tex]
[tex]\implies r^2=x^2+y^2[/tex]

allows us to consider [tex]f(x,y)[/tex] as a function of one variable; let's call it [tex]F(r)[/tex], where

[tex]f(x,y)\equiv F(r)=re^{-r}[/tex]

Then

[tex]F'(r)=e^{-r}(1-r)=0\implies r=1[/tex]

We have [tex]F'(r)>0[/tex] for [tex]r<1[/tex], and [tex]F'(r)<0[/tex] for [tex]r>1[/tex], which means [tex]F[/tex] is increasing, then decreasing as [tex]r[/tex] exceeds 1. This suggests that extrema occur for [tex]f(x,y)[/tex] wherever [tex]r^2=x^2+y^2=1[/tex], i.e. along the intersection of the cylinder [tex]x^2+y^2=1[/tex] and [tex]f(x,y)[/tex].

Computing the second derivative of [tex]F(r)[/tex] and setting equal to 0 gives

[tex]F''(r)=-e^{-r}(2-r)=0\implies r=2[/tex]

as a possible point of inflection. We have [tex]F''(r)<0[/tex] for [tex]r<2[/tex], and namely when [tex]r=1[/tex], which means [tex]F(r)[/tex] is concave downward around this point. This confirms that [tex]r=1[/tex] is a site of a maximum. Along this path, we have a maximum value of [tex]F(1)=e^{-1}\approx0.368[/tex].

Next, to check for possible extrema along the border, we can parameterize [tex]f(x,y)[/tex] by [tex]x=\sqrt2\cos t[/tex] and [tex]y=\sqrt2\sin t[/tex], so that

[tex]x^2+y^2=(\sqrt2\cos t)^2+(\sqrt2\sin t)^2=2[/tex]

and we can think of [tex]f(x,y)[/tex] as a function a single variable, [tex]F(t)[/tex], where

[tex]F(t)=2e^{-2}\approx0.271[/tex]

In other words, [tex]f(x,y)[/tex] is constant along its boundary [tex]x^2+y^2=2[/tex], and this is smaller than the maximum we found before.

So to recap, the maximum value of [tex]f(x,y)[/tex] is [tex]\dfrac1e\approx0.368[/tex], which is attained along the surface above the circle [tex]x^2+y^2=1[/tex] in the [tex]x-y[/tex] plane.

The price C, in dollars per share, of a high-tech stock has fluctuated over a twelve-year period according to the equation C= 14 +12x – x2, where x is in years. The price C, in dollars per share, of a second high-tech stock has shown a steady increase during the same time period according to the relationship C = 2x + 30. For what values are the two stock prices the same?

Answers

For this case we have the following equations:
 C = 14 + 12x - x2
 C = 2x + 30
 Equating the equations we have:
 14 + 12x - x2 = 2x + 30
 Rewriting we have:
 -x2 + 10x - 16 = 0
 Solving the polynomial we have:
 x1 = 2
 x2 = 8
 Answer:
 
the two stock prices are the same for:
 
x1 = 2
 
x2 = 8
Final answer:

The values for which the two stock prices are the same are approximately x ≈ -1.405 and x ≈ 11.405.

Explanation:

To find the values for which the two stock prices are the same, we need to set the equations for the prices equal to each other and solve for x.

Equation for the first stock: C = 14 + 12x - x^2

Equation for the second stock: C = 2x + 30

Setting the two equations equal: 14 + 12x - x^2 = 2x + 30

Rearranging the equation and combining like terms: x^2 - 10x - 16 = 0

Using the quadratic formula to solve for x: x = (-b ± sqrt(b^2 - 4ac))/(2a)

Plugging in the values: x = (-(-10) ± sqrt((-10)^2 - 4(1)(-16)))/(2(1))

Simplifying: x = (10 ± sqrt(100 + 64))/2

Calculating: x = (10 ± sqrt(164))/2

Approximate values: x ≈ (10 ± 12.81)/2

Therefore, the two stock prices are the same for x ≈ -1.405 and x ≈ 11.405.

Use the word BULLDOG to answer the question. If the letters of this word are written on paper and then cut into squares with one letter per square, what is the probability of selecting a C or a Z?

Answers

There is a 0% chance of selecting either of those letters as they do not appear in the work BULLDOG. 

When 415 junior college students were surveyed, 150 said they have a passport. constructa 95% confidence interval for the proportion of junior college students that have apassport. round to the nearest thousandth?

Answers

Solution:
The 95% confident interval will be estimated as follows:

sample proportion: 150/415=0.362

ME=1.96*[0.362*0.638/415]=0.0011
thus
95% CI
0.362-0.0011<p<0.362+0.0011

Answer:

[tex]0.362-0.045<p<0.362+0.045[/tex]

Step-by-step explanation:

It is given that When 415 junior college students were surveyed, 150 said they have a passport, then sample proportion will be:

Sample proportion=[tex]\frac{150}{415}=0.362[/tex]

Then, [tex]ME=1.96\sqrt{\frac{0.362{\times}0.638}{415}}[/tex]

=[tex]1.96\sqrt{\frac{0.230}{415}[/tex]

=[tex]1.96(0.023)[/tex]

=[tex]0.045[/tex]

Therefore, at 95% confidence interval, the proportion of junior college students that have a passport is:

[tex]0.362-0.045<p<0.362+0.045[/tex]

Which expression is equivalent to ^4√16x^11y^8/81x^7y^6 ? Assume x > 0 and y = 0

Answers

Final answer:

The equivalent expression to the 4th root of 16x^11y^8/81x^7y^6 is (2x/3)^4, assuming x > 0 and y = 0. The expression simplifies to x because the y terms become 0 and the exponents on x reduce to 1 when the fourth root is taken into account.

Explanation:

The question asks for an expression equivalent to 4th root of the fraction 16x^11y^8/81x^7y^6 assuming that x > 0 and y = 0. First, we need to deal with the fourth root and exponents separately. To find the fourth root of a number, you can raise that number to the 0.25 power. This rule simplifies finding roots, as a full calculation is not always needed with modern calculators that have a y* button or equivalent.

The fourth root of 16 is 2 because (2^4) = 16. We can address the exponents of x and y by subtracting the exponents in the denominator from those in the numerator for each variable: x^(11-7) = x^4 and y^(8-6) = y^2. Now, considering y = 0, any term with y to any power will be 0, so we can omit y terms. For x, we have x^4.

Regarding the numbers, we have (2/3)^4 because the fourth root of 81 is 3, and this is in the denominator. Finally, because y = 0, our expression reduces to just concerning x, which is (2x)^4/(3)^4, or (2x/3)^4. This simplifies to x raised to the power of 1 because (2/3)^4 * x^4 with x^4 raised to the 1/4th power cancels out the fourth power.

Final answer:

To simplify the given expression, we can find the fourth roots of the numbers inside the radical and then simplify the variables using exponent rules.

Explanation:

To simplify the expression ^4√16x^11y^8/81x^7y^6, we can first simplify the numbers inside the radical by finding their fourth roots. The fourth root of 16 is 2, and the fourth root of 81 is 3. So, the expression becomes 2x^(11/4)y^2 / 3x^(7/4)y^6.

Next, we can simplify the variables inside the expression by subtracting the exponents. So, x^(11/4) / x^(7/4) simplifies to x^((11/4)-(7/4)) = x^(4/4) = x^1 = x, and y^2 / y^6 simplifies to y^(2-6) = y^(-4).

Combining the simplified numbers and variables, the expression becomes 2x * y^(-4) / 3 = (2x)/(3y^4).

The Pool Fun Company has learned​ that, by pricing a newly released Fun Noodle at $ 3 comma sales will reach 7000 Fun Noodles per day during the summer. Raising the price to $ 4 will cause the sales to fall to 5000 Fun Noodles per day. a.  Assume that the relationship between sales​ price, x, and number of Fun Noodles​ sold, ​ y, is linear. Write an equation in​ slope-intercept form describing this relationship. Use ordered pairs of the form​ (sales price, number​ sold).

Answers

are there any options

Using standard linear equation, y = m*x + c

where m = slope and c = constant

putting ordered pairs, (3,7000) and (4,5000) in the above equation, we get two equations

3*m + c = 7000         and 4*m + c = 5000

On solving,

m = -2000  and c = 13000


So, the required equation is

   y = -2000*x + 13000

Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

Answers

Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

Finding the horizontal and oblique asymptote of
f(x)= (-3x^2+7x+1)/(x-2)

Solution:

For Horizontal Asymptote:
Line y=L is a horizontal asymptote of the function y=f(x), if either limx→∞f(x)=Llimx→∞f(x)=L or limx→−∞f(x)=Llimx→−∞f(x)=L, and LL is finite.

Calulate limits:

limx→∞(1x−2(−3x2+7x+1))=−∞

limx→−∞(1x−2(−3x2+7x+1))=∞

Thus, there are no horizontal asymptotes.

For Oblique Asymptote:

Do polynomial long division (−3x2+7x+1)/(x-2)=−3x+1+3/(x−2)

The rational term approaches 0 as the variable approaches infinity.

Thus, the slant asymptote is y=−3x+1y=−3x+1.


PLZ HELP NNOOOOOOOWW!! 15 points!!


What is the midpoints of the line segment with endpoints (-3,7) and (9,-2)?

Answers

the midpoint of the line having the endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is [tex](\frac{x_{1}+_x_{2}}{2}, \frac{y_{1}+_y_{2}}{2})[/tex]
basically average them


so given that the line has the endpoints of (-3,7) and (9,-2)
x₁=-3
y₁=7
x₂=9
y₂=-2

so the midpoint can be found by doing
[tex](\frac{-3+9}{2}, \frac{7+(-2)}{2})=[/tex]
[tex](\frac{6}{2}, \frac{7-2}{2})=[/tex]
[tex](3, \frac{5}{2})[/tex]

the midpoint is [tex](3,\frac{5}{2})[/tex]

Question part points submissions used use the gram-schmidt process to find an orthogonal basis for the column space of the matrix. (use the gram-schmidt process found here to calculate your answer. let xi be the ith column of the matrix.) 0 1 1 1 0 1 1 1 0

Answers

Assuming your unformatted string of numbers at the end is a 3x3 matrix, {(0, 1, 1), (2, - 1, 1), (1, 1, - 1)} is an orthogonal basis for its column space.

Hey can you please help me out posted picture

Answers

A because you have to do 3+2+6+5+4+8
For each language we have:
 Number of people who speak Spanish:
 Spanish = 8 + 4 = 12
 Number of people who speak Chinese:
 Chinese = 5 + 6 = 11
 Number of people who speak both languages:
 Both = 3 + 2 = 5
 Adding we have:
 12 + 11 + 5 = 28
 Answer:
 
28
 
option A

A right angle has a league of 13 cm in the hypotenuse of 21 cm what is the length of the other leg

Answers

For a Right Angled Triangle, according to the Pythagoras Theorem, the square of hypotenuse is equal to the sum of squares of its two legs.

One leg is 13cm long, hypotenuse is 21cm long. Let the other leg be x cm. So, we can write:

[tex]21^{2} =13^{2} + x^{2} \\ \\ 272= x^{2} \\ \\ x= \sqrt{272} \\ \\ x=16.49 [/tex]

Rounding of to nearest hundredth, the length of other leg of the Triangle is 16.49
You can use c^2 = a^2 + b^2 to solve for the length of the other leg. Just substitute the values to the variable then transpose to get the value of the missing variable.

Given: a = 13; c = 21
Required: b - other leg
Solution:
   c^2 = a^2 + b^2
 21^2 = 13^2 + b^2
   441 = 169 + b^2
  b^2 = 272
  √b = 16.49
    b = 16.49 cm

The formula for centripetal acceleration, a, is given below, where v is the velocity of the object and r is the object's distance from the center of the circular path. Solve the formula for the velocity. the formula is a= v^2/ r

Answers

For this case we have the following equation:
 a = v ^ 2 / r
 From here, we must clear the value of speed.
 We have then:
 v ^ 2 = a * r
 v = root (a * r)
 Answer:
 the formula for the velocity is:
 v = root (a * r)

Answer:

The required formula is [tex]v=\sqrt{ar}[/tex].

Step-by-step explanation:

The given formula is

[tex]a=\frac{v^2}{r}[/tex]

where, v is the velocity of the object and r is the object's distance from the center of the circular path.

Multiply both sides by r, to solve the formula for the velocity.

[tex]ar=v^2[/tex]

Taking square root both the sides.

[tex]\sqrt{ar}=v[/tex]

Therefore the required formula is [tex]v=\sqrt{ar}[/tex].

Which situation is most likely to have a constant rate of change? A. Length of a bead necklace compared with the number of identical beads B. Distance a school bus travels compared with the number of stops C. Number of trees in a park compared with the area of the park D. Number of runs scored in a baseball game compared with the number of innings

Answers

Answer:

A. Length of a bead necklace compared with the number of identical beads

Step-by-step explanation:

Using identical beads in a necklace means that the length of the necklace will depend on the total number of identical beads in the necklace.

For each bead added, the length of the necklace will increase a given, constant, amount.  This is a constant rate of change.

Answer: A. Length of a bead necklace compared with the number of identical beads

Step-by-step explanation:

A. Length of bead necklace increases simultaneously compared with the increases in number of identical beads . This is a proportional relationship .

So, There is constant rate of change which is equals to the length of each bead.

B. Distance a school bus travels compared with the number of stops .

There is no constant rate of change between the quantities .[The time when bus stops matter]

C.Number of trees in a park compared with the area of the park.

There can be free space ,so there is not proportional relationship .

D.Number of runs scored in a baseball game compared with the number of innings

Not proportional relationship.

Plot and connect the points A(2,3), B(2,-5), C(-4,-3), and find the area of the triangle it forms.

Answers

check the picture below.

so we can simply split the triangular area into two smaller triangles, notice their base and height.

so, simply, get the area of each triangle, sum them up, and that's the area of the triangular section.

[tex]\bf \stackrel{\textit{yellow triangle}}{\cfrac{1}{2}(6)(6)}~~~~+~~~~\stackrel{\textit{blue triangle}}{\cfrac{1}{2}(6)(2)}[/tex]

The area of the triangle is 24 square unit.

What is Area?

Area is the entire amount of space occupied by a flat (2-D) surface or an object's shape. The area of a plane figure is the area that its perimeter encloses. The quantity of unit squares that cover a closed figure's surface is its area.

If we plot the points A(2,3), B(2,-5), C(-4,-3) on the graph we get a triangle which can be divided into two right Triangles.

So, Area of Triangle 1

= 1/2 x base x height

= 1/2 x 6 x 6

= 18 sq units

Now, area of Triangle 2

= 1/2 x base x height

= 1/2 x 6 x 2

= 6 sq units

Thus ,the Area of required triangle

= 18 + 6

= 24 sq units

Learn more about area here:

https://brainly.com/question/19305981

#SPJ3

Find the surface area of the part of the surface z = x y that lies within the cylinder

Answers


A surface area, r radius, and h height

A=2πr²+2πrh

xy should be like a rectangle so x is r and y is h

A=2πx²+2πxy

Determine the mean ,median,modes ,IQR,and rage for the data 3,8,6,6,4,6,9,9,12

Answers

Mean:

Add all the numbers:

3 + 8 + 6 + 6 +4 + 6 + 9 + 9 + 12 = 63

There are 9 numbers.

63 / 9 = 7

Mean = 7

Median:

Order all the numbers:

3, 4, 6, 6, 6, 8, 9, 9, 12

The median is 6.

Mode:

The number that appears the most is 6.

The mode is 6.

Inter-Quartile Range :

Median of 2nd part = 9

Median of 1st part = 5

Subtract:

9 - 5 = 4

The IQR is 4.

Range:

The highest number is 12. The lowest is 3

Subtract:

12 - 3 = 9

The range is 9.

Hope this helped☺☺




Mean=Average/add all the numbers and divide it by how many numbers there are

3+8+6+6+4+6+9+9+12

=63

63/9

=7 is your mean

Median=The middle number in a set of ordered numbers

first place all the numbers from least to greatest

3,4,6,6,6,8,9,9,12

The middle number of this set is 6 so 6 is your median

Mode is the most numbers repeated so if no numbers are repeated there is no mode

6 is repeated 3 times so 6 is your mode

Range: greatest number minus least number


12-3

=9 is your range

IQR=since the median is 6 we would split it and then minus it

so 3,4,6,6,6,8,9,9,12

It would be 9-5

=4is your IQR I am pretty sure that is correct!

^o^




Match each function formula with the corresponding transformation of the parent function y = -4 x . .
1. y = -4x - 1 ANSWERS
Translated right by 1 unit
2. y = 1 - 4x Translated down 1 unit
3. y = -4-x Reflected across the x-axis
4. y = -4x + 1 Reflected across the y-axis
5. y = 4x Translated up by 1 unit
6. y = -1 - 4x Translated left by 1 unit

Answers

Answer:

1. y = - 4(x - 1) ⇒ Translated right by 1 unit

2. y = 1 - 4x ⇒ Translated up by 1 unit

3. y = - 4(-x) ⇒ Reflected across the y-axis

4. y = - 4(x + 1) ⇒ Translated left by 1 unit

5. y = 4x ⇒ Reflected across the x-axis

6. y = -1 - 4x ⇒ Translated down by 1 unit

Step-by-step explanation:

Lets explain how to solve the problem

- If the function f(x) reflected across the x-axis, then the new

 function g(x) = - f(x)

- If the function f(x) reflected across the y-axis, then the new

 function g(x) = f(-x)

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

* Lets solve the problem

∵ y = - 4x is the parent function

- The function after some transformation is:

1. y = - 4(x - 1)

∵ We subtract 1 from x

∴ The function translated right by 1 unit

y = - 4(x - 1) ⇒ Translated right by 1 unit  

2. y = 1 - 4x

∵ We add 1 to y = - 4x

∴ The function translated up by 1 unit

y = 1 - 4x ⇒ Translated up by 1 unit

3. y = -4(-x)

∵ We multiply x by (-)

∴ The function reflected across the y-axis

y = - 4(-x) ⇒ Reflected across the y-axis

4. y = -4(x + 1)

∵ We add 1 to x

∴ The function translated left by 1 unit

y = - 4(x - 1) ⇒ Translated left by 1 unit

5. y = 4x

∵ We multiply y = - 4x by (-)

∴ The function reflected across the x-axis

y = 4x ⇒ Reflected across the x-axis

6. y = -1 - 4x

∵ We subtract 1 from y = - 4x

∴ The function translated down by 1 unit

y = -1 - 4x ⇒ Translated down by 1 unit

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