1. At approximately 50°C and 0.5 kPa, what phase of matter is water in? *


A. Solid

B. liquid

C. vapor

D. both liquid and vapor


2. A sample of neon occupies a volume of 375 mL at STP. What will be the volume of the neon if the pressure is reduced to 90.0 kPa? *


A.422 mL

B.422 L

C. 333 mL

D. 333 L


3. A gas at 155 kPa and standard temperature has an initial volume of 1.00 L. The pressure of the gas rises to 500 kPa as the temperature also rises to 135°C. What is the new volume? *


A. 2.16 L

B. 0.463 L

C. 0.207 L

D. 4.82 L


4. What pressure will be exerted by 0.650 mol of a gas at 30.0°C if it is contained in a 0.700 L vessel? *


A. 2340 kPa

B. 2340 atm

C. 231 kPa

D. 231 atm


5. The vapor pressure of water is *


a. high due to very weak intermolecular attractions

b. high due to water's polarity

c. low due to water's high specific heat

d. low due to relatively strong intermolecular attractions


6. Which mixture contains the largest particles? *


a. solution

b. suspension

c. colloid

d. emulsion


7. How does evaporation of a liquid differ from boiling a liquid?


8. Describe the Tyndall Effect and how it could affect my drive home on a foggy night.

Answers

Answer 1
The answer would have to be the letter a for question 1

Related Questions

If the concentration of cucl2 drops from 1.000 m to 0.655 m in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?

Answers

The average rate of reaction is calculated by dividing the change in concentration of a reactant or product by the time interval. For CuCl₂ decreasing from 1.000 M to 0.655 M in 30.0 s, the average rate of reaction is 0.0115 M/s.

The average rate of reaction over a given time interval can be determined by calculating the change in concentration of a reactant or product and dividing by the time interval over which the change occurred. In the scenario provided, the concentration of CuCl₂ decreases from 1.000 M to 0.655 M over a period of 30.0 seconds. To calculate the average rate of reaction, we follow these steps:

Identify the initial concentration and final concentration of CuCl₂. In this case, [tex]C_{i}[/tex]= 1.000 M and [tex]C_{f}[/tex] = 0.655 M.Calculate the change in concentration (ΔC) using the formula ΔC = [tex]C_{f}[/tex]- [tex]C_{i}[/tex]. Therefore, ΔC = 0.655 M - 1.000 M = -0.345 M. The negative sign indicates a decrease in concentration.Determine the time interval (t) over which the change in concentration has occurred, which is given as 30.0 s.Calculate the average rate of reaction (Rate) using the formula Rate = ΔC / t. The correct answer is thus Rate = -0.345 M / 30.0 s = -0.0115 M/s.

The negative sign in rate typically indicates the consumption of a reactant. However, when discussing rates of reaction, it is common to report them as positive values, so the average rate of reaction from this calculation would be 0.0115 M/s.

Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 4-methyl-3-hexanone. (enter your choices as a string of letters without punctuation, i.e. ace.)

Answers

I have provided the full reaction scheme for the synthesis of 4-methyl-3-hexanone from the reaction of acetylene and bromoethane. Acetylene is initially reacted with NaNH₂ which is a strong base that deprotonates the C-H of the acetylene which creates a carbon nucleophile which will then attack the electrophilic carbon containing the bromo in bromoethane. This is a simple sn2 substitution. Essentially an ethyl group is added to each side of the triple bond in acetylene.

With the 3-hexyne in hand, the triple bond is reduced using Lindlar's catalyst which will hydrogenate only to the alkene and stop. The 3-hexene is then reacted with a peroxycarboxylic acid which is used to epoxidize the alkene, to give the epoxide.

The epoxide is reacted with the grignard reagent which treats the methyl as a strong nucleophile. The methyl adds to one carbon of the epoxide and opens the ring. The acid is added at the end to protonate the alcohol.

Finally, the alcohol is oxidized with chromic acid which will oxidize a secondary alcohol to the ketone. The final product is 4-methyl-3-hexanone.

number of moles in 3.70 x 10^-1 g of boron

Answers

Answer:

0.0342 mol

Explanation:

The molar mass of boron is 10.81 g/mol, that is, 1 mole of boron (6.02 × 10²³ molecules of boron) has a mass of 10.81 grams. This is the ratio that we will use to find the number of moles in 3.70 × 10⁻¹ g, using a conversion fraction.

3.70 × 10⁻¹ g B × (1 mol B / 10.81 g B) = 0.0342 mol B

Final answer:

To find the number of moles in Boron, you divide the given mass by the molar mass of Boron. Given the mass of Boron as 3.70 x 10^-1 g and the molar mass as 10.8 g/mol, the result is approximately 0.034 moles.

Explanation:

To find the number of moles in a sample, we use the formula: Moles = mass / molar mass. We already know the mass of boron, which is 3.70 x 10^-1 g. The average atomic mass of boron, considering its isotopes, is approximately 10.8 amu. Converting this into grams gives you 10.8 g/mol (since 1 amu = 1 g/mol).

Therefore, the number of moles of boron is calculated to be Moles = 3.70 x 10^-1 / 10.8 = approximately 0.034 moles.

Note that an atomic mass unit (amu) is basically the mass of one atom, on a scale where the carbon-12 atom is exactly 12.0 amu. However, no single boron atom weighs exactly 10.8 amu; 10.8 amu is the average mass of all boron atoms, considering the isotopes.

Learn more about moles of Boron here:

https://brainly.com/question/10728903

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If a 3.00-l flask contains 0.400 mol of co2 and 0.100 mol of o2 at equilibrium, how many moles of co are also present in the flask?

Answers

The equilibrium constant is the proportion of the equilibrium concentration of the product to the reactants. The moles of CO present in a flask is 1.89 moles.

What are moles?

Moles are the product of the molar concentration and the volume of the solution. It is given in mol.

The balanced chemical reaction can be shown as:

[tex]\rm 2CO(g) + O_{2}(g) \rightarrow 2CO_{2}(g)[/tex]

The equilibrium constant is given as,

[tex]\rm K_{c} = \dfrac{[CO_{2}]^{2}}{[CO_{2}]^{2} [O_{2}]}[/tex]

The concentration of carbon dioxide is calculated as:

[tex]\dfrac{0.4 \;\rm mol}{3\;\rm L} = 0.13[/tex]

The concentration of oxygen is calculated as:

[tex]\dfrac{0.1 \;\rm mol}{3\;\rm L} = 0.03[/tex]

Substituting values in the formula of the equilibrium constant:

[tex]\begin{aligned}{1.4 \times 10^{2} &= \rm \dfrac{0.13^{2}}{ [CO]^{2} \times 0.03}\\\\\rm [CO] &= \sqrt{0.004} \\\\&= 0.63 \end{aligned}[/tex]

The moles of carbon monoxide will be  [tex]0.63 \times 3 = 1.89\;\rm moles.[/tex]

Therefore, 1.89 moles of carbon monoxide are present in the flask.

Learn more about moles here:

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The correct answer is that there are 0.200 moles of CO present in the flask at equilibrium.

To solve this problem, we need to consider the chemical equilibrium of the reaction involved, which is the decomposition of carbon dioxide (CO2) into carbon monoxide (CO) and oxygen (O2). The balanced chemical equation for this reaction is:

[tex]\[ \text{CO}_2(g) \rightleftharpoons \text{CO}(g) + \frac{1}{2}\text{O}_2(g) \][/tex]

According to the stoichiometry of the balanced equation, for every mole of CO2 that decomposes, one mole of CO is produced and half a mole of O2 is produced.

Given that we have 0.400 moles of CO2 and 0.100 moles of O2 in the flask, we can use the stoichiometry of the reaction to find out how many moles of CO are present. Since the reaction produces one mole of CO for every mole of CO2 that decomposes, we can calculate the moles of CO produced by the decomposition of CO2 as follows:

[tex]\[ \text{Moles of CO produced} = \text{Moles of CO2 decomposed} \][/tex]

However, we also know that the reaction produces half a mole of O2 for every mole of CO2 that decomposes. Therefore, the moles of O2 produced can be calculated as:

[tex]\[ \text{Moles of O2 produced} = \frac{1}{2} \times \text{Moles of CO2 decomposed} \][/tex]

Since we have 0.100 moles of O2, we can set up the equation:

[tex]\[ 0.100 = \frac{1}{2} \times \text{Moles of CO2 decomposed} \][/tex]

Solving for the moles of CO2 decomposed, we get:

[tex]\[ \text{Moles of CO2 decomposed} = 0.100 \times 2 = 0.200 \][/tex]

This means that 0.200 moles of CO2 have decomposed to produce 0.200 moles of CO and 0.100 moles of O2. Therefore, the moles of CO present in the flask at equilibrium is 0.200 moles.

Using the given data, calculate the rate constant of this reaction.

Answers

according to the attached picture of the complete question that you have missed:
when Rate = K [A]^x * [B]^z
So to get the rate we have to get X & Z
first, we choose two value of [A] which [A] changed and [B] still constant
that appears in trial 1 & 3 SO, we will use Rate 1 & rate 3 and [A1] &[A3] and we can neglect [B] as it is constant:
Rate3/Rate1 = ([A3]/[A1])^x
0.0852/0.0213 = (0.62/0.31)^x
4 = 2^x ∴ X = 2 
- second, we have to choose two value of [B] which [B] changed and [A] still constant and that appears in trail 1&2, we will use the rate 1 &2 and [B1] & [ B2] and we can neglect [A] as it is constant:
Rate 2 / Rate 1 = ([B2]/[B1])^z
0.0213/0.0213 = (0.68/0.34)^z
1 = 2^z ∴ Z= zero 
SO Rate1 = K [A]^2[B]^0
   0.0213 = K * (0.31)^2 *1
∴ K = 0.222 m^-1.S^-1

One of the most important industrial sources of ethanol is the reaction of steam with ethene derived from crude oil: c2h4(g) + h2o(g) â c2h5oh(g)δh o rxn = â47.8 kjkc = 9.00 à 103 at 600. k at equilibrium, the partial pressure of ethanol (c2h5oh) is 200. atm and the partial pressure of water is 400. atm. calculate the partial pressure of ethene (c2h4).

Answers

We are asked to find the partial pressure of ethene given the equilibrium constant and the partial pressures of the other species. The reaction and equilibrium constant are shown below:

C₂H₄ (g) + H₂O (g) → C₂H₅OH (g)          Kc = 9 x 10³

Since we are given the equilibrium constant, Kc, which is regarding the concentration of species. However, we want the value of Kp which is the equilibrium constant regarding partial pressures. To convert these values we use the following formula:

Kp = Kc · (RT)ⁿ

R = 0.08206 Latm/molK
T = 600 K
Kc = 9 x 10³
Δn = sum of stoichiometric coefficients of products - sum of stoichiometric coefficients of reactants = -1

Kp = Kc/RT = (9 x 10³)/(0.08206)(600)
Kp = 183

Kp = [Pethanol]/[Pwater][Pethene] = 183
183 = (200)/(400)(Pethene)

P
ethene = (200)/(400)(183)
Pethene = 0.00273 atm

The partial pressure of ethene was found to be 0.00273 atm. This appears to be a very small number, however, it agrees with the scenario as we were told that the equilibrium constant was a very large number which suggests that the equilibrium falls far to the right. Based on this partial pressure of ethene, it appears that the majority of the ethene has reacted to form ethanol.

A 14.01 g sample of n2 reacts with 3.02 g of h2 to form ammonia (nh3). if ammonia is the only product, what mass of ammonia is formed? 17.01 g 1.10 g 14.01 g 3.02 g 23.07 g

Answers

Answer is: mass of ammonia is 17 grams.
Chemical reaction: 3H₂ + N₂ → 2NH₃.
m(N₂) = 14,01 g.
n(N₂) = m(N₂) ÷ M(N₂).
n(N₂) = 14,01 g ÷ 28,02.
n(N₂) = 0,5 mol.
m(H₂) = 3,02 g.
n(H₂) = 3,02 g ÷ 2,01 g/mol.
n(H₂) = 1,5 mol.
From chemical reaction: n(N₂) : n(H₂) = 1 : 3.
From chemical reaction: n(N₂) : n(NH₃) = 1 : 2.
n(NH₃) = 2 · 0,5 mol = 1 mol.
m(NH₃) = 1 mol · 17 g/mol.
m(NH₃) = 17 g.


Final answer:

The mass of ammonia formed when 14.01 g of N2 reacts with 3.02 g of H2 is the sum of the reactant masses, which equals 17.03 g of NH3.

Explanation:

The question involves a chemical reaction where nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). The balanced equation for the formation of ammonia is:
N2(g) + 3H2(g) → 2NH3(g).

In the scenario provided, 14.01 g of N2 reacts with 3.02 g of H2. Given the stoichiometry of the reaction and the law of conservation of mass, the mass of the reactants equals the mass of the product. Therefore, if you start with 14.01 g of N2 and 3.02 g of H2, the mass of ammonia formed would be the sum of the masses of nitrogen and hydrogen, which is 17.03 g NH3.

Calculate the mass of aluminum in 250 g of Al(C2H3O2)3

Answers

i think its 204.113598

A gas has a volume of 590 mL at a temperature of -55°C what volume will the gas occupy at 30°C

Answers

Using ideal gas formula (PV=nRT), you can conclude that volume directly related to the temperature. That means an increase in temperature will cause an increased volume too. Note that the temperature is using Kelvin, not Celsius. The calculation would be:

V1/T1= V2/T2
590ml / (-55+ 273)K = V2/ (30+273)K
V2= (590ml/ 218K) * 303K
V2= 820ml

What mass (in grams) of iron(iii) oxide contains 58.7 g of iron? iron(iii) oxide is 69.94 % iron by mass?

Answers

The percent composition  (%) of iron (Fe+3) in Fe2O3 equals:
Fe % = Atomic mass of Fe / (Molecular weight of Fe2O3)
∵ Atomic mass of Fe = 55.8 g/mol
and, the atomic mass of Oxygen is 16 g/mol
∴ percent of iron in Fe2O3 = [(2*55.8) / ((3*16) + (2*55.8))] *100 = 69.92 % >>> (1)
And if the mass of the iron is 58.7 g 
∴ mass of Fe2O3 = 58.7 * 100 / 69.92 = 83.95 g >>>> (2)
So, from (2), the mass of iron (III) oxide is 83.95 g
and, from (1), the iron III oxide is 69.92 % iron by mass not 69.94% 


A substance's percent composition basically reveals to you what number of grams of every constituent component you get per 100 g of said substance. 
For this situation, a percent composition of 
69.94% implies that for each 100 g of iron(III) oxide, 
Fe2O3, you get 69.94 g of iron.

So the solution for this problem would be: 58.7 g Fe = 100 g Fe2O3 / 69.94 g Fe = 83.93 g Fe2O3

How does size influence the appearance of a star? Give an example in your response
ILL GIVE 40PTS

Answers

makes it seem bigger and brighter

When the size of a star increases, the brighter it gets.

The color of the star is determined by the temperature.

If the temperature of the star is lower, that means the star is an orange/red color.

If the star's temperature is higher, that means the star is an blue/white color.

20 points

Choose all the answers that apply. Which of the following is an example of an ion?
Na+
Cl-
Ar
F+

Answers

na+ cl- and f+ is the answer

When NaOH is added to water, the hydroxide concentration increases. What can you conclude about NaOH?

Answers

Answer:

NaOH dissociates into ions.

Explanation:

Hydroxide is one of the ions that compose NaOH, therefore the NaOH must dissociate into its constituent ions:

NaOH ⇒ Na⁺ + OH⁻

Calculate the theoretical yield of ammonia produced by the reaction of 100g of H2 gas and 200g of N2 gas

Answers

To get the theoretical yield of ammonia NH3:
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
                     = 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles 
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
                      = 14.28 * 17 = 242.76 g

what is the representative particle for silicon

Answers

Final Answer:

The representative particle for silicon is the silicon atom.

Explanation:

Silicon, a chemical element with the symbol Si and atomic number 14, is a metalloid commonly found in nature. The representative particle for silicon is the silicon atom, which serves as the fundamental building block of silicon-based materials. At its core, silicon has 14 protons and electrons, and its atomic mass is approximately 28.09 atomic mass units (amu). The electronic configuration of a silicon atom is 1s² 2s² 2p⁶ 3s² 3p², indicating the distribution of electrons in its various energy levels and orbitals.

Silicon's unique atomic structure contributes to its versatile properties, making it a crucial element in the field of electronics and semiconductor technology. The outermost electron shell of a silicon atom contains four electrons, allowing silicon to form covalent bonds with other atoms, particularly other silicon atoms.

This ability to form strong covalent bonds is essential for the creation of the crystalline structure that characterizes silicon in its solid state. Silicon's role as a semiconductor arises from its ability to conduct electricity under certain conditions, making it an integral component in the production of microchips and other electronic devices.

In summary, the silicon atom, with its specific atomic number, mass, and electron configuration, serves as the representative particle for silicon. Understanding the properties of the silicon atom is fundamental to grasping the unique characteristics that make silicon a cornerstone of modern technology.

A mole of silicon contains 6.02 × 10²³silicon atoms.

A representative particle is the smallest unit in which a substance naturally exists. For the majority of elements, the representative particle is the atom. Silicon (Si), with an atomic number of 14 and an atomic mass of 28.09, is no exception to this rule. Therefore, the representative particle for silicon is the atom. This means a mole of silicon contains 6.02 × 10²³ silicon atoms, as determined by Avogadro's number.

how many grams of glucose, C6H12O6, in 2.47 mole?

Answers

Answer:
number of grams = 444.6 grams

Explanation:
From the periodic table, we can find that:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of oxygen = 16 grams
This means that:
molar mass of C6H12O6 = 6(12) + 12(1) + 6(16) = 180 grams

Now, number of moles can be calculated using the following rule:
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass = 2.47 * 180
mass = 444.6 grams

Hope this helps :)
First, we need to find the atomic mass of [tex]C_{6}H_{12}O_{6}[/tex].

According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16

As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The molar mass of  [tex]C_{6}H_{12}O_{6}[/tex] = 6 * 12.01 + 12 * 1.008 + 6 * 16

The molar mass of  [tex]C_{6}H_{12}O_{6}[/tex] = 180.156 grams/mole

Now that we have the molar mass of  [tex]C_{6}H_{12}O_{6}[/tex], we can find the grams of glucose by using:

mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)

Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams

Ans: Mass of glucose in grams in 2.47 moles = 444.99 grams

-i

A solution has an initial concentration of 0.0100 m hclo (ka = 3.5×10−8 ) and 0.0300 m naclo. what is the ph after the addition of 0.0030 mol of solid naoh to 1.00 l of this solution? assume no volume change.

Answers

When [HClO]= 0.01 M  & [ClO]^- = 0.03M & NaOH = 0.003 mol and
 Ka = 3.5 x 10^-8 
and the equation is:
            HClO + NaOH → Na^+  + ClO^-
initial     0.01     0.003        0.03     0.03
            -0.003 - 0.003      +0.003  + 0.003
Final    0.007        0             0.033      0.033

We can get the PH from this formula:
PH = Pka + ㏒[conjugent base/weak acid]
PH = -㏒Ka + ㏒[Na]/[HClO]
      = - ㏒ 3.5x10^-8 + ㏒(0.033/0.007)
     = 8.13 

The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?

Answers

hbro  dissociate  as  follows
HBro--->  H+  +  BrO-
  Ka=  (H+)(BrO-)  /  HBro
 PH  =  -log (H+)
therefore (H+)  =  10^-4.48= 3.31  x10^-5
ka is  therefore= ( 3.31  x 10^-5)^2/0.55=1.99  x10^-9

What volume of a 0.25 m phosphoric acid solution is required to react completely with 1.0 l of 0.35 m sodium hydroxide?

Answers

The moles have to be equal. Always start with a balanced equation. This reaction is a double replacement.
The basic equation is
NaOH + H3PO4 ===> Na3PO4 + HOH

The balanced equation is.
3NaOH + H3PO4 ===> Na3PO4 + 3HOH

moles of NaOH = moles of H3PO4
mols of NaOH = molarity * Volume
molarity = 0.35 mol/L
Volume = 1.0 L
moles NaOH = 0.35 * 1 = 0.35 mols

Find the moles of H3PO4
For every mol of H3PO4 used, you require 3 mols of NaOH
3/1 = 0.35/x
3x = 0.35
x = 0.35/3
x = 0.1167 moles of H3PO4 needed for this reaction.

Now the volume needs to be calculated.
n = 0.1167
M = 0.25 mol/L
V = ??

Formula
M = n/V
V = n/M
V = 0.1157/0.25 
V = 0.467 L

Note: I merely copied the reaction given myself to the next line. I'm not copying from an outside source.

A solution was prepared by dissolving 25.0 g of kcl in 225 g of water. calculate the mass percent of kcl in the solution.

Answers

To calculate the percent mass of a molecule, you need to divide its mass with the total mass of the solution. The solution prepared in this question is made by dissolving 25.0 g of KCl in 225 g of water, which will make a solution with a total mass of : 25+225= 250 g.

The mass percent of KCl mass would be: 25g/ 250g= 10%

Final answer:

The mass percent of KCl in the solution is calculated by dividing the mass of KCl by the total mass of the solution and then multiplying by 100%, resulting in a mass percent of 10%.

Explanation:

To calculate the mass percent of KCl in the solution, you can use the formula: (mass of solute ÷ mass of solution) × 100%. First, calculate the mass of the solution by adding the mass of KCl and the mass of water. In this case, it would be 25.0 g of KCl + 225 g of water, which equals 250.0 g of solution.

Now, take the mass of KCl (25.0 g) and divide it by the mass of the solution (250.0 g). Multiply the result by 100% to get the mass percent of KCl in the solution.

So, the calculation is (25.0 g ÷ 250.0 g) × 100% which equals 10%. Therefore, the mass percent of KCl in the solution is 10%.

Kia is doing an experiment in science lab. She is given a beaker containing 100 g of liquid. The beaker has markings on the side for measuring volume. The water comes up to the 100 mL mark. Kia puts the liquid on a hot plate by mistake. By the time she realizes the mistake, half of her liquid has evaporated.

Kia still needs 100 g of liquid for her experiment. To find out how much liquid she has to replace, she needs to re-weigh her liquid. However, the balance she used before is now broken. The teacher tells Kia that she can tell how much water is left by looking. The water now comes up to the 50 mL mark.

How much mass does Kia's remaining water have?

Answers

The key to solving this problem is density. Density determines the mass of a molecule for a certain volume. Kia is given a beaker containing 100 g which volume is at 100 mL mark. Then the density of the liquid would be:
density=mass/volume
density= 100g/ 100ml= 1g/ml

If the water now comes up to the 50 mL mark, then the weight would be:
density = mass/volume
mass = volume * density
mass = 50ml * (1g/ml)= 50g

The correct answer is 50g.

The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its conjugate, and the other half still remains unreacted. if 0.500 moles of a monoprotic weak acid (ka = 5.0 × 10-5) is titrated with naoh, what is the ph of the solution at the half-equivalence point?

Answers

Answer is: pH of the solution at the half-equivalence point is 4,30.
Chemical reaction: HA + NaOH → NaA + H₂O.
n₀(HA) = 0,500 mol.
Ka = 5,0·10⁻⁵.
Half of the analyte has reacted, so n(HA) = 0,5 mol ÷ 2 = 0,25 mol.
From chemical reaction: n(HA) : n(NaOH) = 1 : 1.
n(NaOH) = n(NaA) = 0,25 mol.
pH = pKa + log(n(NaA)/n(HA).
pH = -log(5,0·10⁻⁵) + log (0,25 mol/0,25 mol).
pH = 4,30.

The average rate of consumption of br− is 1.86×10−4 m/s over the first two minutes. what is the average rate of formation of br2 during the same time interval?

Answers

By considering the reaction equation is:
5Br(aq)+BrO3(aq)+6H(aq)= 3Br2(aq)+3H2O(l)
when the average rate of consumption of Br = 1.86x10^-4 m/s
So from the reaction equation 
5Br → 3Br2 when we measure the average rate of formation (X) during the same interval So,
∴ 1.86x10^-4/5 = X / 3
∴X = 1.1 x 10^-4 m/s
∴the average rate of formation of Br2 = 1.1x10^-4 m/s


The average rate of formation of Br₂ during the first two minutes is 1.12×10⁻⁴ M/s.

This was calculated using the stoichiometric relationship between Br⁻ and Br₂ in the given reaction. The rate of formation is obtained by multiplying the rate of disappearance of Br⁻ by the stoichiometric ratio (3/5).

The chemical reaction in question is:

5Br⁻(aq) + BrO₃⁻(aq) + 6H⁺ (aq) → 3Br₂(aq) + 3H₂O(l)

Given that the average rate of consumption of Br⁻ (bromide ions) is 1.86×10⁻⁴ M/s, we need to determine the average rate of formation of Br₂ (bromine) during the same time interval.

This reaction shows that for every 5 moles of Br− consumed, 3 moles of Br₂ are produced. Therefore, the rate of formation of Br₂ will be:

Rate of Br₂ formation = (3/5) × Rate of Br⁻ consumption

Using the given rate of Br− consumption:

Rate of Br₂ formation = (3/5) × 1.86×10⁻⁴ M/s = 1.12×10⁻⁴ M/s

Thus, the average rate of formation of Br₂ during the first two minutes is 1.12×10⁻⁴ M/s.

An example of kinetic energy continuously being changed to potential energy and back again might be -
f electric charges moving in a straight path
g a train moving down a track
h a plate sitting on the edge of a table
j a girl swinging on a swing

Answers

F. electric charges moving in a straight path


hope this helps<3

A sample of c3h8 has 4.56 Ã 1024 h atoms. how many carbon atoms does the sample contain?

Answers

Answer is: there is 1,368·10²⁵ atoms of carbon.
N(C₃H₈) = 4,56·10²⁴.
From molecular formula: in one molecule of propane there is three atoms of carbon:
N(C) = 3 · 4,56·10²⁴.
N(C) = 1,368·10²⁵.

In a chemical reaction, it is determined that the equilibrium constant is 0.213. Which of the following is a correct statement regarding this reaction?
There are more products than reactants at equilibrium.


The reaction will continue until no reactant remains.


There are more reactants than products at equilibrium.


The reaction has stopped completely.

Answers

Answer: There are more reactants than products at equilibrium.

Explanation:

1) The equilibrium constant is defined as the ratio of the constant of reaction for the forward reaction divided by the constant of reaction for the reverse reaction.

2) If the constant of reacton for the forward reaction is greater than the constant of reaction for the reverse reaction, then the equilbrium constant is greater than 1 and the equilibrium is reached at a point where there are more products than reactants.

This is not the case given that the equilibrium constant is less than 1.

3) If the constant of reaction for the forward reaction is less than the constant of reaction for the reverse reaction, then the equilibrium constant is less than 1 and at equilibrium there will be more reactants than products.


This is the case given, since the equilibrium constant is 0.123.

Therefore, the answer is: there are more reactants than products at equilibrium.

Final answer:

The correct statement for a chemical reaction with an equilibrium constant of 0.213 is that there are more reactants than products at equilibrium.

Explanation:

Given that the equilibrium constant is 0.213 for a chemical reaction, we can make certain determinations about the state of the reaction at equilibrium. When the equilibrium constant (K) is less than 1, this generally means that the ratio of products to reactants at equilibrium is small and the reaction system favors the reactants. Therefore, the correct statement is that there are more reactants than products at equilibrium.

It is important to understand that when equilibrium is reached, the reaction has not stopped; rather, it is a dynamic state where the forward and reverse reactions continue at the same rate, maintaining constant concentrations of reactants and products. The idea that the reaction continues until no reactant remains is incorrect because a reaction at equilibrium does not favor complete conversion to products unless the equilibrium constant is significantly greater than 1.

Using the periodic table, choose the more reactive metal. (hint: reactivity of Ga > Al: reactivity of Zn > Ga) Pt or Ag

Answers

Answer:

Silver (Ag) is more reactive than platinum (Pt) :) hope this helps!!!

Explanation:

is a measure of the quantity of matter in an object. A) Volume B) Mass C) Density D)Weight

Answers

Mass is a measure of the quantity of matter in an object

Answer:

Mass is a measure of the quantity of matter in an object

Explanation:

Describe how the law of conservation of energy is demonstrated in this laboratory activity.

Answers

What laboratory activity. The law of conservation of energy is that energy remains constant. This relates to physics

Law of conservation of energy can be evidenced by the  total heat energy of reaction and mechanical energy of dynamic system. And the energy transfer into mass during a nuclear reaction.

What is law of conservation of mass?

According to energy conservation law, energy can neither be created nor be destroyed.  Therefore, the total energy in a system is conserved.

However, energy can be transformed from one form to the other such as conversion of electrical energy to chemical energy, electrical energy to mechanical energy etc.

The sum of kinetic energy and potential energy is called mechanical energy. If kinetic energy of a body increases, its potential energy decreases. Thus, total mechanical energy is constant.

This can be well explained by ,measuring the kinetic and potential energy of the a moving pendulum when it is at rest and on motion.

Similarly in chemical reactions, the total heat energy will be constant and if we take the nuclear reactions, where the energy of the product side and reactant side will be equal.

To find more about energy conservation, refer the link below:

https://brainly.com/question/2137260

#SPJ5

the variable that a scientist changes when conducting an experiment is called the _____variable.
a. dependent
b.responding
c.manipulated

Answers

Answer: The correct answer is option (a).

Explanation:

Dependent variables are the variables whose value depend on another variable. Its value changes as the independent variable changes.

Independent variables are the variables which do not depend on any other variable beside . Its value does not change with a change in other dependent  variables.

While conducting experiment scientist changes dependent variable in order to record observations.

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