A firm produces a product that has the production cost function

​C(x)equals=195195xplus+88408840

and the revenue function

​R(x)equals=260260x.

No more than

229229

units can be sold. Find and analyze the​ break-even quantity, then find the profit function.

Answers

Answer 1

Answer:

136 units

65x - 8840

Step-by-step explanation:

Given,

The production cost function is,

[tex]C(x) = 195x + 8840[/tex]

Revenue function,

[tex]R(x)=260x[/tex]

So, profit would be,

P(x) = Revenue - cost

= 260x - 195x - 8840

= 65x - 8840

In break even condition,

Profit, P(x) = 0

65x - 8840 = 0

65x = 8840

x = 136.

Hence, the break even quantity is 136 units.

Answer 2
Final answer:

The break-even quantity is 1360 units, where the revenue equals the cost. The profit function is given by P(x) = R(x) - C(x).

Explanation:

To find the break-even quantity, we need to find the point where the revenue function equals the production cost function. So we set R(x) equal to C(x) and solve for x:

260x = 195x + 88408

Simplifying the equation, we get:

65x = 88408

x = 1360

Now we analyze the break-even quantity. The break-even quantity is the point at which the firm's revenue equals its cost. In this case, it occurs at 1360 units. At this quantity, the firm's total revenue will equal its total cost, resulting in zero profit.

To find the profit function, we subtract the cost function C(x) from the revenue function R(x). The profit function can be expressed as:

P(x) = R(x) - C(x)


Related Questions

How many ways can you make change for a $50 bill using $5, $10, and $20 bills?

Answers

Answer:

There are 12 ways to make change for a $50 bill using $5, $10 and $20 bills

Step-by-step explanation:

Let's write down every possibility starting by using the largest quantity of $20 bills and we'll go from there, everytime that we get a $10 bill we will split it in the next option into 2 $5 bills.

(20)(20)(10)

(20)(20)(5)(5)

(20) (10)(10)(10)

(20)(10)(10)(5)(5)

(20)(10)(5)(5)(5)(5)

(20)(5)(5)(5)(5)(5)(5)

Now we start with the largest quantity of $10 bills (5) and go from there, splitting them into two 5 dollar bills in the next option.

(10)(10)(10)(10)(10)

(10)(10)(10)(10)(5)(5)

(10)(10)(10)(5)(5)(5)(5)

(10)(10)(5)(5)(5)(5)(5)(5)

(10)(5)(5)(5)(5)(5)(5)(5)(5)

(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)

Answer:

12 ways

Step-by-step explanation:

20 x 20 x 10 x 20 x 20 x 5 x 5

In experiment two, I measured a block to be 4.45 cm by 3.35 em by 6.15 cm and a mass of 155.147g. What is the density of this block in kg/L? 3.

Answers

Answer:

1.69224581396 Kg/L

Step-by-step explanation:

We are given the measure of the block as 4.45 cm × 3.35 cm × 6.15 cm.

Volume of block = 4.45 cm × 3.35 cm × 6.15 cm = 91.681125 cm cube = 91.681125 × 0.001 L = 0.091681125 L

We did the above step to convert the volume of block into Liter.

Mass of block is given as 155.147 gram = 155.147 × 0.001 kg = 0.155147 kg

We converted the mass of block into kilograms because we need density in Kg/L.

Density is defined as mass per unit volume

Density = [tex]\frac{Mass}{Volume}[/tex]

             = [tex]\frac{0.155147 }{0.091681125}[/tex]]

             = 1.69224581396 Kg/L

The density is found to be approximately 1.688 kg/L.

To find the density of the block, we need to use the density formula:

Density = Mass / Volume

The given dimensions of the block are:

Length = 4.45 cmWidth = 3.35 cmHeight = 6.15 cm

First, calculate the volume:

Volume = Length × Width × Height

Volume = 4.45 cm × 3.35 cm × 6.15 cm

Volume ≈ 91.88925 cubic centimeters (cm)

Next, convert mass to kilograms and volume to liters:

Mass = 155.147 g = 0.155147 kg (since 1 kg = 1000 g)Volume = 91.88925 cm³ × 0.001 L/cm³ ≈ 0.09188925 L (since 1 cm³ = 0.001 L)

Finally, calculate the density in kg/L:

Density = Mass / Volume

Density ≈ 0.155147 kg / 0.09188925 L

Density ≈ 1.688 kg/L

Thus, the density of the block is approximately 1.688 kg/L.

Solve the Following Initial Value Problem: 2XYY'+Y^2-4X^3=0. where Y(1)=2

The answer is y= sqrt((x^4+3)/x)

Answers

[tex]2xyy'+y^2-4x^3=0[/tex]

Let [tex]z(x)=y(x)^2[/tex], so that [tex]z'(x)=2y(x)y'(x)[/tex] (which appears in the first term on the left side):

[tex]xz'+z=4x^3[/tex]

This ODE is linear in [tex]z[/tex], and we don't have to find any integrating factor because the left side is already the derivative of a product:

[tex](xz)'=4x^3\implies xz=x^4+C\implies z=\dfrac{x^4+C}x[/tex]

[tex]\implies y(x)=\sqrt{\dfrac{x^4+C}x}[/tex]

With [tex]y(1)=2[/tex], we get

[tex]2=\sqrt{1+C}\implies C=3[/tex]

so the solution is as given in your post.

there are 3 times as many boys as girls. If there are 24 more boys than girls, how many children are there?

How would I put this into a bar diagram? I can do it with algebra but I am having trouble drawing a bar diagram to help represent this problem.

Answers

Answer:

There are 48 children.

Step-by-step explanation:

Given :There are 3 times as many boys as girls.

            There are 24 more boys than girls,

To Find : how many children are there?

Solution:

Let the number of girls be x

Now we are given that there are 3 times as many boys as girls.

So, no. of boys = 3x

Now we are given that there are 24 more boys than girls.

So, [tex]3x-x=24[/tex]

[tex]2x=24[/tex]

[tex]x=12[/tex]

So, no. of girls = 12

No. of boys = 3x = 3(12) = 36

Now the total no. of children = 12+36 = 48

Hence there are 48 children.

Prove that x-1 is a factor of x^n-1 for any positive integer n.

Answers

Answer:    

[tex]x-1[/tex] is a factor of [tex]x^n - 1[/tex]

Step-by-step explanation:

[tex]x-1[/tex] is a factor of [tex]x^n - 1[/tex]

We will prove this with the help of principal of mathematical induction.

For n = 1, [tex]x-1[/tex] is a factor [tex]x-1[/tex], which is true.

Let the given statement be true for n = k that is [tex]x-1[/tex] is a factor of [tex]x^k - 1[/tex].

Thus, [tex]x^k - 1[/tex] can be written equal to  [tex]y(x-1)[/tex], where y is an integer.

Now, we will prove that the given statement is true for n = k+1

[tex]x^{k+1} - 1\\=(x-1)x^k + x^k - 1\\=(x-1)x^k + y(x-1)\\(x-1)(x^k + y)[/tex]

Thus, [tex]x^k - 1[/tex] is divisible by [tex]x-1[/tex].

Hence, by principle of mathematical induction, the given statement is true for all natural numbers,n.


What of the following basic rules is true about geometry?

A. Opposite angles are equal when two straight lines intersect

B. Supplementary angles total 180°

C. Complementary angles total 90°

D. A, B, and C

E. None of the above

Answers

Answer:

D. A, B, and C

Step-by-step explanation:

Option (A) is true because when two straight lines intersect to each other we get two pair of vertically opposite angles and the angles opposite to each other is always equal.

Option (B) is also correct as If the sum of two angles is equal to 180°, then they are supplementary to each other.

Option (C) is also correct as If the sum of the two angles is equal to 90°, then they are Complementary to each other.

Hence, Option (D) is correct.

A hemispherical bowl of radius 12 inches is filled to a depth of h​ inches, where 0less than or equalshless than or equals12. Find the volume of water in the bowl as a function of h.​ (Check the special cases hequals0 and hequals12​.)

Answers

Answer:

Suppose the bowl is situated such that the rim of the bowl touches the x axis, and the semicircular cross section of the bowl lies below the x-axis (in (iii) and (iv) quadrant ). Then the equation of the cross section of the bowl would be [tex]x^2+y^2=144[/tex], where y≤ 0,

⇒ [tex]y=-\sqrt{144-x^2}[/tex]

Here, h represents the depth of water,

Thus, by using shell method,

The volume of the disk would be,

[tex]V(h) = \pi \int_{-12}^{-12+h} x^2 dx[/tex]

[tex]= \pi \int_{-12}^{-12+h} (144-y^2) dy[/tex]

[tex]= \pi |144y-\frac{y^3}{3}|_{-12}^{-12+h}[/tex]

[tex]=\pi [ (144(-12+h)-\frac{(-12+h)^3}{3}-144(-12)+\frac{(-12)^3}{3}}][/tex]

[tex]=\pi [ -1728 + 144h - \frac{1}{3}(-1728+h^3+432h-36h^2)+1728-\frac{1728}{3}][/tex]

[tex]=\pi [ 144h - \frac{1}{3}(h^3+432h-36h^2}{3}][/tex]

[tex]=\pi [ 144h - \frac{h^3}{3} - 144h + 12h^2][/tex]

[tex]=\pi ( 12h^2 - \frac{h^3}{3})[/tex]

Special cases :

If h = 0,

[tex]V(0) = 0[/tex]

If h = 12,

[tex]V(12) = \pi ( 1728 - 576) = 1152\pi [/tex]

Help! BRANLIEST and 300 points!!! Plz show ALL your steps.

PB is a line segment on a number line. It has endpoints at -2 and 12. What is the coordinate of its midpoint?

Answers

Step-by-step explanation:

(12 + -2 )/2

10/2

5 im pretty sure

The midpoint is 5.

Explanation:

in the following ordinary annuity, the interest is compounded with each payment, and the payment made at the end of the compounding period. find the accumulated amount of the annuity. (round your answer to the nearest cent)

$2000 monthy at 6.3% for 20 years

Answers

Answer: $957646.07

Step-by-step explanation:

The formula we use to find the accumulated amount of the annuity is given by :-

[tex]FV=m(\frac{(1+\frac{r}{n})^{nt})-1}{\frac{r}{n}})[/tex]

, where m is the annuity payment deposit, r is annual interest rate , t is time in years and n is number of periods.

Given : m= $2000 ; n= 12   [∵12 in a  year] ;   t= 20 years ;   r= 0.063

Now substitute all these value in the formula , we get

[tex]FV=(2000)(\frac{(1+\frac{0.063}{12})^{12\times20})-1}{\frac{0.063}{12}})[/tex]

i.e. [tex]FV=(2000)(\frac{(1+0.00525)^{240})-1}{0.00525})[/tex]

i.e. [tex]FV=(2000)(\frac{(3.51382093497)-1}{0.00525})[/tex]

i.e. [tex]FV=(2000)(\frac{2.51382093497}{0.00525})[/tex]

i.e. [tex]FV=(2000)(478.823035232)[/tex]

i.e. [tex]FV=957646.070464\approx957646.07\ \ \ \text{ [Rounded to the nearest cent]}[/tex]

Hence, the accumulated amount of the annuity= $957646.07

Final answer:

The future value or accumulated amount of an ordinary annuity is calculated using the formula where P is the periodic payment, r is the interest rate per period, n is the number of compounding periods per year, and t is the time in years. Given P = $2000, r = 6.3%, n = 12 and t =  20 years, substituting these values into the formula gives the accumulated amount

Explanation:

To find the future value or accumulated amount of an ordinary annuity, we use the formula: FV = P * (((1 + r)^nt - 1) / r), where P is the periodic payment, r is the interest rate per period, n is the number of compounding periods per year, and t is the time in years.

In the given problem, P = $2000, r = 6.3% or 0.063 (in decimal), n = 12 (since the payments are monthly), and t =  20 years.

Substituting these into the formula, FV = $2000 * (((1 + 0.063 /12)^(12*20) - 1) / (0.063/12)).

Calculating the equation, we'll get the accumulated amount to the nearest cent.

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In a particular game, a fair die is tossed. If the number of spots showing is six you win $6, if the number of spots showing is five you win $3, and if the number of spots showing is four you win $1. If the number of spots showing is one, two, or three you win nothing. You are going to play the game twice. Each game is independent. The probability that you will win nothing on the two plays of the game is

Answers

Answer: Our required probability is 0.194.

Step-by-step explanation:

Since we have given that

Amount win for showing 6 = $6

Amount win for showing 5 = $3

Amount win for showing 4 = $1

Amount win for showing 1, 2, 3 = $0

So,we need to find the probability that he will win nothing on the two plays of the game.

so, the outcomes would be

(1,1), (1,2), (1,3), (2,1), (3,1),(2,2), (3,3)

So, Number of outcomes = 7

total number of outcomes = 36

So, Probability of wining nothing = [tex]\dfrac{7}{36}=0.194[/tex]

Hence, our required probability is 0.194.

Determine whether the following possible responses should be classified as ratio, interval, nominal or ordinal data.

? Ratio Ordinal Nominal Interval 1. The college (Arts and Science, Business, etc.) you are enrolled in

? Ratio Ordinal Nominal Interval 2. The number of students in a statistics course

? Ratio Ordinal Nominal Interval 3. The age of each of your classmates

? Ratio Ordinal Nominal Interval 4. Your hometown

Answers

Answer:

1. The college (Arts and Science, Business, etc.) you are enrolled in

Nominal

2. The number of students in a statistics course  Ratio

3. The age of each of your classmates  Ratio

4. Your hometown  Nominal

Step-by-step explanation:

Nominal, ordinal, interval, or ratio data are the four fundamental levels of measurement scales that are used to capture data.

Nominal, are used for labeling variables, without any quantitative value.

Ordinal, the order of the values is what is significant, but the differences between each one is not really known.

Interval, we know both, the order and the exact differences between the values

Ratio, they have the order, the exact value between units, and have an absolute zero

Jay said that by the quotient of powers property zero to the fifth power divided by zero to the second power equals zero to the fifth power -2 equals zero to the third power which equals zero is this correct explain

Answers

Answer:

No, Jay is not correct.

Step-by-step explanation:

Quotient of powers property:

For any non-zero number a and any integer x and y:

[tex]\frac{a^x}{a^y}=a^{x-y}[/tex]

According to by the quotient of powers property

[tex]\frac{0^5}{0^2}=0^{5-2}\Rightarrow 0^3=0[/tex]

We need to check whether Jay is correct or not.

No, Jay is not correct because quotient of powers property is used for non-zero numbers.

[tex]\frac{0^m}{0^n}=\frac{0}{0}=unde fined[/tex]

Therefore, Jay is not correct.

In the xy plane, a quadrilateral has vertices at (-1, 4), (7,4), (7,5), and (-1. 5). What is the perimeter of the quadrilateral? (A) 17 (B) 18 (C) 19 (1) 32 (E) 34

Answers

Answer:

(B) 18.

Step-by-step explanation:

We are asked to find the perimeter of a quadrilateral with vertices at (-1, 4), (7,4), (7,5), and (-1. 5).

First of all, we will draw vertices of quadrilateral on coordinate plane and connect the vertices as shown in the attached photo.

We can see that our quadrilateral is a parallelogram, whose parallel sides are equal.

[tex]\text{Perimeter of quadrilateral}=8+1+8+1[/tex]

[tex]\text{Perimeter of quadrilateral}=16+2[/tex]

[tex]\text{Perimeter of quadrilateral}=18[/tex]

Therefore, the perimeter of the given quadrilateral is 18 units.

Find the values of x1 and x2 where the following two constraints intersect.

1) 9x1 + 7x2 ≥ 57

(2) 4x1 + 6x2 ≥ 13

Answers

Constraints are simply the subjects of an objective function.

The point of intersection is:  [tex]\mathbf{(x_1,y_1) = (9.54,-4.19)}[/tex]

The constraints are given as:

[tex]\mathbf{9x_1 + 7x_2 \ge 57}[/tex]

[tex]\mathbf{4x_1 + 6x_2 \ge 13}[/tex]

Express [tex]\mathbf{4x_1 + 6x_2 \ge 13}[/tex] as an equation

[tex]\mathbf{4x_1 + 6x_2= 13}[/tex]

Subtract 6x2 from both sides

[tex]\mathbf{4x_1 = 13 - 6x_2}[/tex]

Divide through by 4

[tex]\mathbf{x_1 = \frac{1}{4}(13 - 6x_2)}[/tex]

Substitute [tex]\mathbf{x_1 = \frac{1}{4}(13 - 6x_2)} \\[/tex] in [tex]\mathbf{9x_1 + 7x_2 \ge 57}[/tex]

[tex]\mathbf{9 \times \frac{1}{4}(13 - 6x_2) + 7x_2 \ge 57}[/tex]

Open brackets

[tex]\mathbf{29.25 - 13.5x_2 + 7x_2 \ge 57}[/tex]

[tex]\mathbf{29.25-6.5x_2 \ge 57}[/tex]

Collect like terms

[tex]\mathbf{-6.5x_2 \ge 57 - 29.25}[/tex]

[tex]\mathbf{-6.5x_2 \ge 27.25}[/tex]

Divide both sides by -6.5

[tex]\mathbf{x_2 \ge -4.19}[/tex]

Substitute -4.19 for x2 in [tex]\mathbf{4x_1 + 6x_2 \ge 13}[/tex]

[tex]\mathbf{4x_1 + 6 \times -4.19 \ge 13}[/tex]

[tex]\mathbf{4x_1 - 25.14 \ge 13}[/tex]

Add 25.14 to both sides

[tex]\mathbf{4x_1 \ge 38.14}[/tex]

Divide both sides by 4

[tex]\mathbf{x_1 \ge 9.54}[/tex]

Hence, the values are:

[tex]\mathbf{(x_1,y_1) = (9.54,-4.19)}[/tex]

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Final answer:

The solution of the problem involves finding the values of x1 and x2 which satisfy both inequalities when plotted on a graph. This can be done by simplifying  the equations and comparing them.

Explanation:

To solve this problem, we need to find where the two inequalities intersect. This means that we need to find the values of x1 and x2 which satisfy both inequalities.

Let's start with the first inequality '9x1 + 7x2 ≥ 57'. This means that the sum of 9 times x1 and 7 times x2 should be greater than or equal to 57. You can simplify this inequality by dividing the entire expression by the smallest coefficient which is 9, getting 'x1 + (7/9)x2 ≥ 57/9'.

Similarly, simplifying the second inequality '4x1 + 6x2 ≥ 13' by dividing by the smallest coefficient which is 4, we get 'x1 + (3/2)x2 ≥ 13/4'.

By comparing these two simplified inequalities, you should be able to identify the values of x1 and x2 where both inequalities are satisfied.

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The local pet store surveyed 50 people about pets. Eleven of these people owned dogs, 13 owned cats, and 6 owned fish. One person owned all three types of pets, 2 people owned only fish and dogs, 3 people only fish and cats, and 5 people owned only cats and dogs. How many people owned none of these pets?

Answers

Answer:   29

Step-by-step explanation:

Let S denotes the total number of people surveyed, A denotes the event of having dog , B denotes the event of having cats and C denotes the event of having fish.

Given :     n(S)=50  ;n(A)=11  ;  n(B) =13  and  n(C)=6

Also, n(A∩B)=5 ;  n(A∩C) = 2 and n(B∩C)=3 and n(A∩B∩C)=1

We know that,

[tex]n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A \cap B)-n(A \cap C)-n(B \cap C)-n(A \cap B\cap C)\\\\=11+13+6-5-2-3+1=21[/tex]

Now, the number of people owned none of these pets :-

[tex]n(S)-n(A\cup B\cup C)\\\\=50-21=29[/tex]

Hence, the number of people owned none of these pets =29


You have decided to invest $1000 in a savings bond that pays 4% interest, compounded semi-annually. What will the bond be worth if you cash it in 10 years from now?

N= I/Y= PV= PMT= FV= P/Y=

Answers

Answer:

$2191.12

Step-by-step explanation:

We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.

[tex]FV=C_0\times (1+r)^n[/tex], where,

[tex]C_0=\text{Initial amount}[/tex],

r = Rate of return in decimal form.

n = Number of periods.

Since interest is compounded semi-annually, so 'n' will be 2 times 10 that is 20.

[tex]4\%=\frac{4}{100}=0.04[/tex]

[tex]FV=\$1,000\times (1+0.04)^{20}[/tex]

[tex]FV=\$1,000\times (1.04)^{20}[/tex]

[tex]FV=\$1,000\times 2.1911231430334194[/tex]

[tex]FV=\$2191.1231430334194[/tex]

[tex]FV\approx \$2191.12[/tex]

Therefore, the bond would be $2191.12 worth in 10 years.

what is the value of x if the average of 10, 11, 12 and x is 9?

Answers

Answer: The value of x is 3.

Step-by-step explanation:

Since we have given that

10,11, 12 and x

Average of above numbers = 9

As we know that

Average is given by

[tex]\dfrac{\text{Sum of observation}}{\text{Number of observation}}\\\\\\\dfrac{10+11+12+x}{4}=9\\\\10+11+12+x=9\times 4\\\\33+x=36\\\\x=36-33\\\\x=3[/tex]

Hence, the value of x is 3.

d) Find the 5th degree Taylor polynomial centered at x = 0 for the function y = \tiny \frac{x}{1+x}

Answers

Answer:

[tex]P(x) = x - x^2 + x^3 - x^4+x^5[/tex]

Step-by-step explanation:

Let us first remember how a Taylor polynomial looks like:

Given a differentiable function [tex]f[/tex] then we can find its Taylor series to the [tex]nth[/tex] degree as follows:

[tex]P(x) = f(x_{0}) + f'(x_{0}).(x-x_{0}) + \frac{f''(x_{0})}{2!}.(x-x_{0})^2+.....+\frac{f^n(x_{0})}{n!}.(x-x_{0})^n + R_{n}(x).(x-x_{0})^n[/tex]

Where [tex]R_{n}(x)[/tex] represents the Remainder and [tex]f^n(x)[/tex] is the [tex]nth[/tex] derivative of [tex]f[/tex].

So let us find those derivatives.

[tex]f(x) = \frac{x}{1+x}\\f'(x) = \frac{1}{(1+x)^2}\\f''(x) = \frac{-2}{(1+x)^3}\\f'''(x) = \frac{6}{(1+x)^4}\\f''''(x) = \frac{-24}{(1+x)^5}\\f'''''(x) = \frac{120}{(1+x)^6}[/tex]

The only trick for this derivatives is for the very first one:

[tex]f'(x) = \frac{1}{1+x} - \frac{x}{(1+x)^2}\\f'(x) = \frac{(1+x) - x}{(1+x)^2} = \frac{1}{(1+x)^2}\\[/tex]

Then it's only matter of replacing on the Taylor Series and replacing [tex]x_{0}=0[/tex]

the forecast calls for a 30% chance of snow today and a 40% chance of snow tomorrow. what are the chances it will rain two days in a row?

Answers

Answer:

The chances it will rain two days in a row is 12%

Step-by-step explanation:

The forecast calls for a 30% chance of snow today

So, chance of snowfall today = 30% = 0.3

A 40% chance of snow tomorrow.

So, chance of snowfall tomorrow= 40% = 0.4

The chances it will rain two days in a row = [tex]0.4  \times 0.3[/tex]

                                                                    = [tex]0.12[/tex]  

So, percent  it will rain two days in a row = [tex]0.12 \times 100 = 12\%[/tex]

Hence the chances it will rain two days in a row is 12%

Dr. Fitzgerald has graded 15 of 26 exams for Epi 501. (a) What proportion of all exams has Dr. Fitzgerald graded? (b) What was the ratio of graded to ungraded tests?

Answers

Answer: a) 15:26, and b) 15:11.

Step-by-step explanation:

Since we have given that

Number of graded tests = 15

Number of total tests = 26

Number of ungraded tests is given by

[tex]26-15\\\\=11[/tex]

a) Proportion of all exams has Dr. Fitxgerald graded is given by

15:26.

b) Ratio of graded to ungraded tests is given by 15:11

Hence, a) 15:26, and b) 15:11.

(a) The proportion of all exams graded by Dr. Fitzgerald is [tex]\(\frac{15}{26}\)[/tex].

(b) The ratio of graded to ungraded tests is [tex]\(\frac{15}{26 - 15}\) or \(\frac{15}{11}\)[/tex].

(a) To find the proportion of exams graded by Dr. Fitzgerald, we divide the number of exams graded by the total number of exams. This gives us the fraction:

[tex]\[ \text{Proportion graded} = \frac{\text{Number of exams graded}}{\text{Total number of exams}} = \frac{15}{26} \][/tex]

This fraction represents the part of the whole set of exams that has been graded.

(b) To find the ratio of graded to ungraded tests, we take the number of exams that have been graded and divide it by the number of exams that have not been graded. The number of ungraded exams is the total number of exams minus the number of graded exams:

[tex]\[ \text{Number of ungraded exams} = \text{Total number of exams} - \text{Number of exams graded} = 26 - 15 = 11 \][/tex]

Now, we can find the ratio:

[tex]\[ \text{Ratio of graded to ungraded tests} = \frac{\text{Number of exams graded}}{\text{Number of exams ungraded}} = \frac{15}{11} \][/tex]

This ratio tells us how many times greater the number of graded exams is compared to the number of ungraded exams.

The charge to rent a trailer is $15 for up to 2 hours plus $8 per additional hour or portion of an hour. Find the cost to rent a trailer for 2.8 hours, 3 hours, and 8.5 hours. Then graph al ordered pairs, (hours, cost), for the function a. What is the cost to rent a trailer for 2.8 hours?

Answers

Answer:

The cost to rent a trailer for 2.8 hours is $21.4.

The cost to rent a trailer for 3 hours is $23.

The cost to rent a trailer for 8.5 hours is $67.

Step-by-step explanation:

Let x be the number of hours.

It is given that the charge to rent a trailer is $15 for up to 2 hours plus $8 per additional hour or portion of an hour.

The cost to rent a trailer for x hours is defined as

[tex]C(x)=\begin{cases}15 & \text{ if } x\leq 2 \\ 15+8(x-2) & \text{ if } x>2 \end{cases}[/tex]

For x>2, the cost function is

[tex]C(x)=15+8(x-2)[/tex]

We need to find the cost to rent a trailer for 2.8 hours, 3 hours, and 8.5 hours.

Substitute x=2.8 in the above function.

[tex]C(2.8)=15+8(2.8-2)=15+8(0.8)=21.4[/tex]

The cost to rent a trailer for 2.8 hours is $21.4.

Substitute x=3 in the above function.

[tex]C(3)=15+8(3-2)=15+8(1)=23[/tex]

The cost to rent a trailer for 3 hours is $23.

Substitute x=8.5 in the above function.

[tex]C(8.5)=15+8(8.5-2)=15+8(6.5)=67[/tex]

The cost to rent a trailer for 8.5 hours is $67.

Written all the ordered pairs in the form of (hours, cost).

(2.8,21.4), (3,23) and  (8.5,67)

Plot these points on coordinate plane.

Final answer:

To find the cost to rent a trailer for 2.8 hours, we consider the flat fee of $15 for the first 2 hours and add the additional cost of $8 for the partial hour beyond 2 hours, resulting in a total cost of $23.

Explanation:

The cost to rent a trailer for a given number of hours is determined by a flat fee of $15 for the first 2 hours and an additional cost of $8 for each extra hour or partial hour. For 2.8 hours, since this exceeds the initial 2-hour period, we calculate the cost as follows:

Flat fee for the first 2 hours: $15Extra time: 0.8 hours, which counts as an additional full hour for charging purposesAdditional cost for 0.8 hours (rounded up to 1 hour): $8Total cost = Flat fee + cost for additional hoursTotal cost = $15 + $8 = $23

Therefore, the cost to rent a trailer for 2.8 hours is $23.

What is the lenght of a diagonal of a square with sides 16feet
long ? Round to the nearest tenth.

Answers

Answer:

The length of the diagonal is 22.6 ft.

Step-by-step explanation:

To find the length of the diagonal of a square, multiply the length of one side by the square root of 2:

If the length of one side is x, [tex]length = x\sqrt{2}[/tex] as you can see in the image attached.

This fact is a consequence of applying the Pythagoras' Theorem to find the length of the diagonal if we know the side length of the square.

[tex]length^{2}  = x^{2}+x^{2}  \\ length=\sqrt{x^{2}+x^{2}} \\ length=\sqrt{2x^{2} } \\ length=x\sqrt{2}[/tex]

We know that the length of one side is 16 ft so [tex]length = 16\sqrt{2}=22.627[/tex] and round to the nearest tenth is 22.6 ft

Employment data at a large company reveal that 74% of the workers are married, 42% are college graduates, and that 56% are married, given that they are college graduates. Which of the following statements are true about the events married and college graduate?

(A) These events are pairwise disjoint.
(B) These events are independent events.
(C) These events are both independent and pairwise disjoint.
(D) A worker is either married or a college graduate always.
(E) None of these above are true.

Answers

Answer:

(E) None of these above are true.

Step-by-step explanation:

Married = 74% or 0.74

College graduates = 42% or 0.42

pr(married | college graduates) = 0.56

(A) These events are pairwise disjoint. This is false. Pairwise disjoint are also known as mutually exclusive events. Here we can see that both events are occurring at same time.

(B) These events are independent events. This is also false.

(C) These events are both independent and pairwise disjoint. False

(D) A worker is either married or a college graduate always. False

Here Probability(A or B) shall be 1

= Pr(A) + Pr(B) - Pr( A and B) = 0.74 + 0.42 - 0.56 * 0.42 = 0.9248

This is not equal to 1.

(E) None of these above are true. This is true.


The cost, in dollars, of making x items is given by the function C(x)=25x+300

. Find C(1500), the cost of making 1500 items.

Question 6 options:

a)

$4050

b)

$25,300

c)

$30,300

d)

$37,800

e)

none

Answers

Answer:

d) $37800

Step-by-step explanation:

Cost of making x items = [tex]C(x)=25x + 300[/tex]

Cost of making [tex]1500[/tex] items = [tex]C(1500)=25(1500) + 300\\C(1500)= 37500 + 300\\C(1500)= 37800[/tex]

Cost of making [tex]1500[/tex] items = $37800

d) $37800 is the correct answer

The CEO of a company that sells car stereos has determined the profit of selling x number of stereos to be: P(x) = –.04x2 + 1000x – 16,500 How much profit should the company expect from selling 12,500 stereos?

Answers

Answer:

6233500

Step-by-step explanation:

We are given that CEO of a company that sells car stereos has determined the profit x number of stereos.

The profit of selling x number of stereos is given by

[tex]P(x)=-0.04x^2=100x-16500[/tex]

We have to find the value of profit when the company selling 12500 stereos.

Substitute the value of x=12500

Then, we get

[tex]P(12500)=-.04(12500)^2+1000(12500)-16500[/tex]

[tex]P(12500)=-6250000+12500000-16500=-6266500+12500000[/tex]

[tex]P(12500)=6233500[/tex]

Hence, the company should expect profit 6233500 from selling 12500 stereos.

Tour players Harry, Ron, Harmione and Ginny are playing a card game. A deck of 52 cards are dealt out equally. If Harmione and Ginny have a total of 8 spades among them, what is the probability that Harry has 3 of the remaining 5 spades?

Answers

Answer: 0.339

Step-by-step explanation:

Given : Tour players Harry, Ron, Harmione and Ginny are playing a card game.

. A deck of 52 cards are dealt out equally.

Then, the number of card each person has = [tex]\dfrac{52}{4}=13[/tex]

If Harmione and Ginny have a total of 8 spades among them, then the total cards the total spades left = 13-8=5

Now, the number of ways to get 3 of 5 spades : [tex]^5C_3=\dfrac{5!}{3!2!}=10[/tex]

Number of ways to draw remaining 10 cards :  [tex]^{21}C_{10}=\dfrac{21!}{10!11!}=352716[/tex]

Also, the total cards Harmione and Ginny have = 13+13=26

Then the total cards left = 26

The number of ways to get 13 cards for Harry :

[tex]^{26}C_{13}=\dfrac{26!}{13!(26-13)!}\\\\=\dfrac{26!}{13!13!}=10400600[/tex]

Now, the probability that Harry has 3 of the remaining 5 spades :_

[tex]\dfrac{^5C_3\times ^{21}C_{10}}{^{26}C_{13}}\\\\=\dfrac{10\times352716}{10400600}\\\\=0.339130434783\approx0.339[/tex]

Hence, the probability that Harry has 3 of the remaining 5 spades= 0.339 (approx)

Cantwell Associates, a real estate developer, is planning to build a new apartment complex consisting of one-bedroom units, two-bedroom townhouses, and three-bedroom townhouses. A total of 216 units is planned. The total number of two- and three-bedroom townhouses will equal the number of one-bedroom units. If the number of one-bedroom units will be 3 times the number of three-bedroom townhouses, find how many units of each type will be in the complex. one-bedroom units units two-bedroom townhouses units three-bedroom townhouses units

Answers

Answer:

108 one-bedroom units

72 two-bedroom units

36 three-bedroom units

Step-by-step explanation:

Let x, y, z the number of one-bedroom, two-bedroom and three-bedroom units respectively. Then  

1) x+y+z = 216

2)     y+z = x

3)         x = 3z

Multiplying equation 1) by -1 and adding it to 2), we get

-x = x-216 so, x = 216/2 = 108

x = 108

Replacing this value in 3) we get

z = 108/3 = 36

z = 36

Replacing now in 2)

y+36 = 108, y = 108-36 and

y = 72

Final answer:

In the planned apartment complex, there will be 0 one-bedroom units, 216 two-bedroom townhouses, and 0 three-bedroom townhouses.

Explanation:

Let x be the number of one-bedroom units. Since the number of two- and three-bedroom townhouses equals the number of one-bedroom units, let y be the number of two-bedroom townhouses and z be the number of three-bedroom townhouses. We know that x + y + z = 216. Additionally, x = 3z because the number of one-bedroom units will be 3 times the number of three-bedroom townhouses. Substituting x = 3z into the first equation gives 3z + y + z = 216. Simplifying this equation, we get 4z + y = 216.

Now, we can solve this system of equations to find the values of x, y, and z. Subtracting y from both sides of the equation 4z + y = 216 gives 4z = 216 - y. Let's call this equation (1). Substituting x = 3z and y = 216 - 4z into the equation x + y + z = 216 gives 3z + (216 - 4z) + z = 216. Simplifying this equation, we get 4z + 216 = 216. Subtracting 216 from both sides of the equation gives 4z = 0. Let's call this equation (2).

Since equation (1) and equation (2) both have 4z on the left side, we can equate the right sides of the equations. This gives 216 - y = 0. Solving for y, we find y = 216. Plugging this value of y into equation (1), we get 4z = 216 - 216, which simplifies to 4z = 0. Solving for z, we find z = 0. Finally, plugging the value of z into the equation x = 3z, we get x = 3(0), which simplifies to x = 0.

Therefore, there are 0 one-bedroom units, 216 two-bedroom townhouses, and 0 three-bedroom townhouses in the complex.

At a grocery store, Daniel wants to buy 3 lb of ham.
What decimal should the digital scale show?
Write 3 as a fraction and then divide.
The scale should read

Answers

Final answer:

The digital scale should display 3.0 when weighing 3 lbs of ham. This is because 3 pounds exactly can be displayed as the decimal 3.0 after converting the number into a fraction, 3/1, and dividing the numerator by the denominator.

Explanation:

When Daniel wants to buy 3 lb of ham, the digital scale at the grocery store should display the decimal 3.0. This is because 3 pounds exactly translates to 3.0 in decimal terms.

The process of converting a number like 3 into a fraction would begin by writing it as 3/1 (as any number can be written over 1).

To convert that into decimal form, you would divide the top number (numerator) by the bottom number (denominator), so 3 ÷ 1 = 3.0.

Thus, the digital scale should read 3.0 when Daniel weighs out his 3 lbs of ham.

Learn more about Decimal Conversion here:

https://brainly.com/question/34390573

#SPJ1

Sixty-seven percent of adults have looked at their credit score in the past six months. If you select 31 customers, what is the probability that at least 20 of them have looked at their score in the past six months? 0.450 0.550 0.692 0.142

Answers

Answer:

0.692.

Step-by-step explanation:

This is a Binomial Probability of Distribution  with P(success) = 0.67.  Prob  success  >= 20) , 31 trials.

From  Binomial Tables we see that the required probability  = 0.692.

An airplane left airport A flying on a course of 72 degrees.
After flying 495 km, the plane was just able to pick up
communication signals from airport B which is due east of airport
A. If airport B's communication signals can be picked up within a
radius of 300 km from airport B, for how many kilometers can the
airplane fly and still be in contact with airport B? Give you
answer to one decimal place.

Answers

Answer:

Distance for which Aeroplane can be in contact with Airport B is = 396.34 km

Step-by-step explanation:

In the question,

We have an Airport at point A and another at point B.

Now,

Airplane flying at the angle of 72° with vertical catches signals from point D.

Distance travelled by Airplane, AD = 495 km

Now, Let us say,

AB = x

So,

In triangle ABD, Using Cosine Rule, we get,

[tex]cos(90-72) =cos18= \frac{AB^{2}+AD^{2}-BD^{2}}{2.AD.AB}[/tex]

So,

On putting the values, we get,

[tex]cos18 = \frac{x^{2}+495^{2}-300^{2}}{2(495)(x)}\\0.951(990x)=x^{2}+245025-90000\\x^{2}-941.54x+155025=0\\[/tex]

Therefore, x is given by,

x = 212.696, 728.844

So,

The value of x can not be 212.696 as the length of LB (radius) itself is 300 km.

So,

x = 728.844 km

So,

AL = AB - BL

AL = x - 300

AL = 728.844 - 300

AL = 428.844 km

Now, in the circle from a property of secants we can say that,

AL x AM = AD x AC

So,

428.844 x (728.844 + 300) = 495 x AC

441213.576 = 495 x AC

AC = 891.34 km

So,

The value of CD is given by,

CD = AC - AD

CD = 891.34 - 495

CD = 396.34 km

Therefore, the distance for which the Aeroplane can still be in the contact with Airport B is 396.34 km.

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