m = mass of the bullet = 10 g = 10 x 10⁻³ kg = 0.01 kg (since 1 g = 10⁻³ kg)
M = mass of pendulum = 2 kg
h = height to which pendulum rises = 12 cm = 0.12 m
V = velocity of the pendulum-bullet combination after collision = ?
Using conservation of energy
kinetic energy of the combination just after collision = Potential energy gained due to raise in height of the center of mass
(0.5) (m + M) V² = (m + M) gh
V = sqrt(2gh)
inserting the values
V = sqrt(2 x 9.8 x 0.12)
V = 1.5 m/s
v = velocity of the bullet before the collision
using conservation of momentum
momentum of bullet before collision = momentum of bullet-pendulum combination after collision
m v = (m + M) V
(0.01) v = (0.01 + 2) (1.5)
v = 301.5 m/s
hence initial speed of the bullet is 301.5 m/s
The initial speed of the bullet is calculated using the conservation of momentum and conservation of mechanical energy by equating the kinetic energy after collision with the potential energy at the pendulum's highest point and then using the momentum conservation to get the bullet's initial velocity.
Explanation:To calculate the bullet's initial speed when it strikes a ballistic pendulum, we can use the principles of conservation of momentum and conservation of mechanical energy. First, we find the velocity of the bullet-pendulum system just after the collision using energy considerations. Since the bullet becomes embedded in the pendulum, this is an inelastic collision, and mechanical energy is not conserved during the collision. However, the system's mechanical energy is conserved as it swings upwards to its highest point.
As the pendulum rises to a height of 12 cm, all the kinetic energy of the system is converted into potential energy. The potential energy (PE) gained by the pendulum can be calculated using PE = mgh, where m is the total mass of the system (bullet plus pendulum), g is the acceleration due to gravity (9.81 m/s2), and h is the height (12 cm or 0.12 m). The kinetic energy (KE) just after the collision can be equated to this PE.
The total mass m after the bullet is embedded in the pendulum is (10 g + 2000 g). To find the velocity of the system after the collision, we can use the equation KE = 1/2 m v2 and solve for v. Then, by using the conservation of momentum, the initial velocity of the bullet u can be determined, since momentum before collision (bullet's momentum) is equal to the momentum after collision (system's momentum). The bullet's initial speed is found through the equation mu = (m + M)v, where M is the mass of the pendulum.
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what gas is most abundant greenhouse gas ? a) ozone b) chlorofluorocarbon c) carbon dioxide d) methane e) water vapor
i believe the answer is water vapor
hope this helps
Answer:
WATER VAPOR
Explanation:
I got a 100% on my test
The graph represents the distance a car travels over time while on the highway. What is the average velocity of the car? A) 28 km hr Eliminate B) 50 km hr C) 75 km hr D) 100 km hr
answer is C
slope= (y2-y1)/(x2-x1)=(300 km-0km)/(4h-0h)=(300km)/(0 h)=75km/h
v=d/t= 150/2=75
Average velocity is given as the total displacement of an object over a given time interval
Average velocity = total displacement /time interval
consider the time interval t₁ = 0 to t₂ = 4
at t₁ = 0 , d₁ = 0 km
at t₂ = 4 , d₂ = 300 km
Δd = total displacement = d₂ - d₁ = 300 - 0 = 300 km
Δt = time interval = t₂ - t₁ = 4 - 0 = 4 h
average velocity is given as
V = Δd/Δt = 300/4 = 75 km/h
Hence the correct choice is
C) 75 km/hr
a race car accelerates uniformly from 18.5m/s to 46.1m/s in 2.4 seconds. determine the acceleration of the car and the distance traveled
The car's (average) acceleration would be
[tex]a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]
The car's position over time would be given by
[tex]x=v_0t+\dfrac12at^2[/tex]
so that after 2.4 seconds, the car will have traveled a distance of
[tex]x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2[/tex]
[tex]\implies x=77.5\,\mathrm m[/tex]
Hello!
A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.
* Determine the acceleration of the car....
We have the following data:
V (final velocity) = 46.1 m/s
Vo (initial velocity) = 18.5 m/s
ΔV (speed interval) = V - Vo → ΔV = 46.1 - 18.5 → ΔV = 27.6 m/s
ΔT (time interval) = 2.4 s
a (average acceleration) = ? (in m/s²)
Formula:
[tex]\boxed{a = \dfrac{\Delta{V}}{\Delta{T^}}}[/tex]
Solving:
[tex]a = \dfrac{\Delta{V}}{\Delta{T^}}[/tex]
[tex]a = \dfrac{27.6\:\dfrac{m}{s}}{2.4\:s}[/tex]
[tex]\boxed{\boxed{a \approx 11.5\:m/s^2}}\longleftarrow(acceleration)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]
* The distance traveled ?
We have the following data:
Vi (initial velocity) = 18.5 m/s
t (time) = 2.47 s
a (average acceleration) = 11.5 m/s²
d (distance interval) = ? (in m)
By the formula of the space of the Uniformly Varied Movement, it is:
[tex]d = v_i * t + \dfrac{a*t^{2}}{2}[/tex]
[tex]d = 18.5 * 2.4 + \dfrac{11.5*(2.4)^{2}}{2}[/tex]
[tex]d = 44.4 + \dfrac{11.5*5.76}{2}[/tex]
[tex]d = 44.4 + \dfrac{66.24}{2}[/tex]
[tex]d = 44.4 + 33.12[/tex]
[tex]\boxed{\boxed{d = 77.52\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]
________________________________
[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]
How much work does an elephant do while moving a circus wagon 20 meters with a pulling force of 200n
Given:
s(distance)= 20 meters
F(force)=200N
Now we know that
work done= Force applied x distance
Substituting the given values in the above formula we get
Work done= 20 x 200= 4000J
The work done by an elephant while moving a circus wagon 20 meters with a pulling force of 200N is calculated using the formula: Work = Force x Distance. Plugging the values into the formula gives us 4000 Joules.
Explanation:The work done by the elephant pulling the circus wagon can be calculated using the formula for work, which is Work = Force x Distance. In this situation, the Force applied by the elephant is 200N and the Distance moved by the wagon is 20 meters.
So, the Work done would be: 200N x 20m = 4000 Joules.
This means the work done by the elephant is 4000 Joules.
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A velocity vs. time graph for an object is shown.
Which best describes the acceleration of the object?
constant and positive
constant and negative
changing and positive
changing and negative
The correct answer is constant and positive
Explanation:The velocity is changing with respect to time at constant rate and we know that the change in velocity is known as acceleration so a constant change in velocity with respect to time will give us a constant acceleration. Similarly the velocity is gradually increasing that is why we will take the acceleration as positive .
Answer: constant and positive
Explanation:
Acceleration is the rate of change of velocity. It can be measured in meter per second square.
[tex]a = \frac{dv}{dt}[/tex]
It can be measured from the slope of velocity - time graph.
In the given velocity vs. time graph, the slope is a straight line in the first quadrant. This means the acceleration is uniform (constant) and positive.
Acceleration from the given graph is:
a = change in velocity /time interval = (5-0)m/s/(5-0)s = 1 m/s².
The forces acting on a child sitting in a seat are described by the free-body diagram shown.
Fn=100N up and down Fg=-100N
What is the net force acting on the child?
A.–100 N
B.0 N
C.100 N
D.200 N
Answer:
B.0 N
Explanation:
Based on the description of the free-body diagram, there are only two forces acting on the child sitting on the seat:
- The force of gravity, Fg=-100 N, in the downward direction
- The normal reaction of the chair on the child, Fn=100 N, in the upward direction
The two forces have same magnitude but in opposite directions, so the net force (resultant of the two forces) is zero:
[tex]F_{net}=F_n+F_g=100 N-100 N=0 N[/tex]
A father lifts a toddler 1.5m up in the air. The child gains 187.5J of gravitational potential energy as a result. What is the mass of the toddler? (Assume that the gravitational field strength is 10N/kg.)
Answer:
Mass of toddler = 12.5 kg
Explanation:
The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.
Potential energy = 187.5 J
Height = 1.5 m
Substituting
187.5 = m * 10 * 1.5
m = 12.5 kg
So mass of toddler = 12.5 kg
what force does a window washer want acting on him when he is trying to keep the same position
The force he applies on himself is balanced force.
Explanation: Balanced force means the net forces applied on himself will be zero. Which is forces applied on right side will be equal to left side forces. And upward forces will be equal to downward forces. According to first law of motion, an object in rest can never be in motion except some force is exerted on it to do so. Hence if force on window washer will be balanced force ( Net force = 0 ), then there will be no motion and he will be in same position.Answer:a balanced force
Explanation:
NEED ANSWER NOW PLZ WILL MARK BRAINLIEST
Why is diffusion important to cells?
A. it permits the sorting of water molecules from solute molecules, such as sugar.
B. it regulates salt content in the cell, preventing bloating and shriveling.
C. it helps maintain the balance of materials needed for survival, such as oxygen and water.
D. The back and forth movement creates extra energy as ADP is transformed into ATP.
WILL MARK BRAINLIEST
it is the process by which important molecules enter the body cells and waste products are removed from cells. is why it is important because your body kills off the stuff that's not supposed to be in it and makes sure all the good cells are where they're supposed to be
What’s the kinetic energy of the roller coaster at the top and bottom of the hill? Use . A kiddie roller coaster car has a mass 100 kilograms. At the top of a hill, it’s moving at a speed of 3 meters/second. After reaching the bottom of the hill, its speed doubles. The car’s kinetic energy at the bottom is its kinetic energy at the top. The car has joules of kinetic energy at the bottom of the hill.
The kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.
The kinetic energy of the roller coaster at the bottom of the hill is twice its kinetic energy at the top of the hill.
To find the kinetic energy (KE) of the roller coaster, we use the formula:
[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]
where [tex]\( m \)[/tex] is the mass of the object and [tex]\( v \)[/tex] is its velocity.
Given that the mass [tex]\( m \)[/tex] of the roller coaster car is 100 kilograms, and its speed [tex]\( v \)[/tex] at the top of the hill is 3 meters/second, we can calculate the kinetic energy at the top of the hill as follows:
[tex]\[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times (3 \text{ m/s})^2 \] \[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 50 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 450 \text{ J} \][/tex]
Since the speed of the roller coaster car doubles at the bottom of the hill, its new speed [tex]\( v_{bottom} \)[/tex] is:
[tex]\[ v_{bottom} = 2 \times 3 \text{ m/s} = 6 \text{ m/s} \][/tex]
The kinetic energy at the bottom of the hill is:
[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times (6 \text{ m/s})^2 \] \[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 50 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 1800 \text{ J} \][/tex]
Therefore, the kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.
What did Rutherford’s model of the atom include that Thomson’s model did not have?
Answer:
Nucluas
Explanation:
The average mass of 1 baking soda compound is 84 amu After it reacts with 1 vinegar molecule the total mass of the product is 144 amu What is the mass of the one vinegar molecule
A 60 amu
B 84 amu
C 144 amu
D 228 amu
I think its 60. I think you would subtract 144-84 to get the mass of the vinegar molecule.
Answer:
m = 60 amu
Explanation:
As we know that total mass is always conserved
So here we know that compound is of mass 84 amu initially
after reaction with vinegar molecule the total mass is given as
[tex]M_{total} = M + m[/tex]
here we know that
[tex]M = 84 amu[/tex]
so we will have
[tex]M_{total} = 144 amu[/tex]
so we have
[tex]144 = 84 + m[/tex]
[tex]m = 60 amu[/tex]
________ fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.
Gasoline fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.
Answer:
Hydrogen fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.
Which of the following is plotted on the x-axis of a distance versus time graph (A)Distance (B)Time (C)Speed (D)Velocity
In a distance versus time graph, the distance is plotted on the y-axis, or vertical axis and the time is plotted on the x-axis (Option B).
What is plotted in distance versus time graph?In a distance versus time graph, the x-axis, which is the horizontal axis, represents time.
This means that time is plotted along the horizontal axis, and it shows how much time has passed as you move from left to right on the graph. The vertical y-axis represents distance, so the graph illustrates how distance changes over time.
Therefore, the answer is x- axis, represents time.
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Final answer:
Time is plotted on the x-axis of a distance versus time graph because it is the independent variable, while distance is dependent and is plotted on the y-axis.
Explanation:
On a distance versus time graph, time is typically plotted on the x-axis. This is because time is considered an independent variable. When analyzing motion, an object's distance or displacement depends on the elapsed time; hence, distance is plotted on the y-axis. The question mentions other variables like speed and velocity, which are related but represented differently in graphical form. For instance, a velocity vs. time graph has velocity on the y-axis and time on the x-axis, where the slope represents acceleration, and the area under the curve represents displacement. A graph of displacement vs. time would display a straight line if the velocity (v) is constant and time (t) is the independent variable on the x-axis.
Starting from rest, the Road Runner accelerates at 3 m/s for ten seconds. What is the final velocity of the Road Runner?
Answer
The answer to this question is [tex]30 ms^{-1}[/tex]
Explanation
As we know that accelartion is the rate of change of velocity. So, it can be write as
[tex]a = (V_f -V_i) /t[/tex]
where
[tex]V_f[/tex] is the final velocity
[tex]V_i[/tex] is the initial velocity
t is the time
a is the accelartion
as we konw
[tex]a = 3 ms^{-2}[/tex]
t = 10 s
From rest So,
[tex]V_i[/tex] = 0
[tex]V_f[/tex] = ?
Putting values
[tex]3 = (V_f - 0)/10[/tex]
[tex]3 * 10 = V_f[/tex]
[tex]30 = V_f[/tex]
[tex]V_f = 30 ms^{-1}[/tex]
So, the right answe is [tex]30 ms^{-1}[/tex]
(3 m/s²) x (10 s) = 30 m/s
His speed at the end of 10 sec is 30 m/s. We can't describe his velocity, because we have no information about the direction he's moving.
Eric decided to go for a walk from his home. He headed 6 meters east and x meters north. The angle formed by the displacement vector and the horizontal vector is 37°. What is the length of the displacement vector?
Answer:
Length of displacement vector = 7.51 m
Explanation:
Consider east as positive X axis and North as positive Y axis.
Eric headed 6 meters east, Displacement = 6 i
Then he headed X meters north, Displacement = X j
Total displacement = 6 i + X j
Angle it makes with horizontal axis, θ = tan⁻¹(X/6) = 37°
X/6 = tan 37
X = 4.52 m
Total displacement = 6 i + 4.52 j
Magnitude = [tex]\sqrt{6^2+4.52^2} =7.51m[/tex]
Length of displacement vector = 7.51 m
The answer is A. 7.5.
Just before snapping backup in the air, my speed is 50m/s. What is my kinetic energy just before snapping back up
Kinetic energy of anything is (1/2) (mass) (speed)² .
Your kinetic energy just before you snap back up (? ?) is
(1/2) (your mass in kilograms) (50 m/s)² =
(1/2) (your mass in kilograms) (2,500 m²/s²) =
(1,250 x your mass in kilograms) . The unit is Joules.
Alex, who has a mass of 100 kg, is skateboarding at
9.0 m/s when he smacks into a brick wall and comes
to a dead stop in 0.2 s.
a. Show that his deceleration is 45 m/sz.
b. Show that the force ofimpact is 4500 N. (Ouch!)
Part a)
acceleration is defined as rate of change in velocity
so we can write
[tex]a = \frac{v_f - v_i}{t}[/tex]
here we know that
finally it will stop so vf = 0
initial speed is given as 9m/s
and the time to stop is 0.2 s
[tex]a = \frac{0 - 9}{0.2}[/tex]
[tex]a = -45 m/s^2[/tex]
Part b)
Now by 2nd law of Newton
[tex]F = ma[/tex]
given that
m = 100 kg
a = 45 m/s^2
so now using above equation
[tex]F = 100 * 45[/tex]
[tex]F = 4500 N[/tex]
so it will exert 4500 N force to stop
A. The deceleration of Alex is 45 m/s²
B. The force of impact is 4500 N
A. How to determine the decelerationFrom the question given above, the following data were obtained:
Initial velocity (u) = 9 m/sFinal velocity (v) = 0 m/sTime (t) = 0.2 sDeceleration (a) =?a = (v – u) / t
a = (0 – 9) / 0.2
a = –9 / 0.2
a = –45 m/s²
The, negative sign indicate that the Alex is coming to rest.
B. How to determine the force Deceleration (a) = 45 m/s²Mass (m) = 100 KgForce (F) =?F = ma
F = 100 × 45
F = 4500 N
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What is the least functional sense at birth?
I think its either sight or its your hands/sensory limbs because it takes babie a while to figure out how to use their hands. i would say speech but it is not a sense. hope this helps!
The least functional sense at birth is vision. Newborn babies have limited visual acuity and are unable to see clearly or focus on objects that are far away. Their vision gradually improves as they grow older.
Explanation:The least functional sense at birth is vision. Newborn babies have limited visual acuity and are unable to see clearly or focus on objects that are far away. Their visual system is still developing, and it takes a few months for them to develop better visual skills.
Babies are born with the ability to hear, taste, and touch, but their vision is less developed at birth. They can detect light and motion, but their vision gradually improves as they grow older. By about 6 months of age, most babies have developed the ability to see more clearly.
During the early stages of development, babies rely on their other senses, such as touch and hearing, to explore and interact with the world. These senses are more functional at birth compared to vision.
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Calculate how much energy is needed to get a typical car with a mass of 1500 kg up to a speed of 40 mph ignoring friction or any other losses or inefficiencies. Show all work, and give your answer in kWh.
m = mass of the car = 1500 kg
we know that 1 mph = 0.45 m/s
hence
v = speed gained by the car = 40 mph = 40 x 0.45 m/s = 18 m/s
since the car is gaining speed here , hence the energy need is same as the kinetic energy gained by the car
kinetic energy is given as
KE = (0.5) m v² where m = mass , v = speed
inserting the above values in the formula
KE = (0.5) (1500) (18)²
KE = 2.43 x 10⁵ J
we know that , 1 J = 2.78 x 10⁻⁷ kwh
hence
KE = (2.43 x 10⁵) (2.78 x 10⁻⁷)
KE = 0.068 kwh
hence the energy needed is 0.068 kwh
Which physical properties of nylon and leather make them good choices for shoelaces?
durability and flexibility
look at you shoelaces they are not hard, don't move like a liquid, or have a high density.
Answer:
Flexibility and durability.
Explanation:
The material of leather and nylon is durable which means it can be used for a long period of time and the material is also flexible means it is not hard. The material which is used in shoe laces can be chosen on the basis of its flexibility and its long lasting nature because costumer do not want to invest on them more than one time or on the basis of easily use.
Therefore, due to the long lasting nature means durability and their flexibility nylon and leather is mostly used in shoe laces.
The colors of pigments is it a) are cyan,yellow,and magenta b) are the same as the secondary c) combine in equal amounts to provide black or d) all of the above
The answer would be A or D. The most appropriate answer would be D. Hope I helped :)
I NEED HELP IS URGENT PLEASE!!!
Which of the following statements applies to the motion of a ball rising and then falling in free fall?
I. The ball has constant acceleration as it moves upward.
II. The ball has constant acceleration at the top of its path.
III. The ball has constant acceleration as it moves downward.
a.
I only
b.
III only
c.
I and III
d.
I, II, and III
D. For any projectile motion, there is a constant downwards acceleration due to gravity at all instances. This not to be confused with velocity, which changes due to gravity at every moment along the object's path.
Who is faster: someone traveling a mile a minute or someone traveling 20 m/s.?
speed of first one is given as
[tex]v_1 = 1 mile \: in \: 1 min[/tex]
we also know that
1 mile = 1609 meter
also for time of motion
t = 1 min = 60 s
so in SI units the speed is given as
[tex]v = \frac{1609}{60}[/tex]
[tex]v = 26.82 m/s[/tex]
so 1 mile/min = 26.82 m/s
So here we will say that 1 mile per min is more speed than 20 m/s as we can see that 1 mile / min is 26.82 m/s in SI units after its conversion
Final answer:
Someone traveling at a mile a minute (26.67 m/s) is faster than someone traveling at 20 meters per second.
Explanation:
To determine who is faster between someone traveling a mile a minute and someone traveling at 20 meters per second, we need to convert one of the rates so that both are in the same units. First, let's convert a mile a minute to meters per second. Since one mile is equivalent to 1600 meters, and one minute is equivalent to 60 seconds, if you travel a mile in a minute, you're traveling 1600 meters in 60 seconds. Thus, the conversion is 1600 meters / 60 seconds = 26.67 meters per second.
Now, we compare:
A mile a minute = 26.67 m/s
Someone traveling at 20 m/s
It's clear that 26.67 m/s is faster than 20 m/s. Therefore, someone traveling a mile a minute is faster than someone traveling at 20 m/s.
A certain metal has a coefficient of linear expansion of 2.00 × 10-5 K-1. It has been kept in a laboratory oven at
325°C for a long time. It is now removed from the oven and placed in a freezer at ‐145°C. After it has reached
freezer temperature, the percent change in its density during this process is closest to
A) +2.90%.
B) ‐2.90%.
C) +2.74%.
D) ‐2.74%.
E) It is not possible to tell without knowing the mass and original volume of the metal.
Hi, the answer is A) +2.90%.
A person jogs 4.0 km in 32 minutes , then 2.0km in 22 minutes and finally 1.0km in 16 minutes . What is the joggers average speed in km per minute?
Average speed is defined as ratio of total distance covered and total time
now we will have
[tex]d_1 = 4 km[/tex]
[tex]t_1 = 32 min[/tex]
[tex]d_2 = 2 km[/tex]
[tex]t_2 = 22 min[/tex]
[tex]d_3 = 1 km[/tex]
[tex]t_3 = 16 min[/tex]
now total distance moved is
[tex]d = d_1 + d_2 + d_3[/tex]
[tex]d = 4 + 2 + 1 = 7 km[/tex]
total time is given as
[tex]t = 32 min + 22 min + 16 min[/tex]
[tex]t = 70 min[/tex]
now average speed is given as
[tex]v_{avg} = \frac{d}{t}[/tex]
[tex]v_{avg} = \frac{7}{70} = 0.1 km/min[/tex]
so its average speed is 0.1 km per minute
Answer:
[tex]0.1 \ km/min[/tex]
Explanation:
We know speed , s is given by [tex]s=\dfrac{distance}{time}.[/tex]
NOW,
Average speed , S is given by:
[tex]S=\dfrac{total \ distance\ covered}{total\ time \ taken }[/tex]. .....eqn 1.
Total distance covered , [tex]D=4+2+1 \ km=7 \ km[/tex].
Total time taken, [tex]T=32+22+16\ min=70 \ min.[/tex]
Putting these values in equation 1.
We get,
[tex]S=\dfrac{7}{70} \ km/min=0.1\ km/min.[/tex]
A resource (like the Sun) that essentially never "runs out" is said to be _____.
A. reusable
B. recyclable
C. inexhaustible
D. nonrenewable
asap please
the answer youre looking for is (C
A 32.5-kg rock is traveling at a constant velocity through space. Then a force of 140 N is exerted on the rock. What acceleration does the force produce?
3.31 m/s^2
2.32m/s^2
4.31 m/s^2
45.5 m/s^2
10.7 m/s^2
As per Newton's II law we can say force applied on an object is product of mass and acceleration
[tex]F = ma[/tex]
given that
Force = 140 N
mass = 32.5 kg
now we can use above formula
[tex]140 = 32.5* a[/tex]
[tex]a = \frac{140}{32.5}[/tex]
[tex]a = 4.31 m/s^2[/tex]
so its acceleration must be 4.31 m/s^2
What is the mass of a car that is going 2m/s2 and then hits a tree with a force of 6000N
Given that force applied due to tree on car is 6000 N
and during the stop the acceleration is given as 2 m/s^2.
So here we can say that As per Newton's II law
[tex]F = m*a[/tex]
here F = force on car = 6000 N
a = acceleration of car = 2 m/s^2
now we can plug in all values above in the given equation
[tex]6000 = 2*m[/tex]
[tex]m = 3000 kg[/tex]
So here the mass of the car will be 3000 kg
The mass of the car is 3000 kg.
Explanation:To calculate the mass of the car, we can use Newton's second law of motion: F = ma.
In this case, the force exerted on the car is 6000 N and the acceleration is 2 m/s².
So, using the formula F = ma, we can rearrange it to solve for mass (m). Therefore, m = F/a = 6000 N / 2 m/s² = 3000 kg.
PLEASE HELP!! When a box rests on a round sheet of wood on the ground, it exerts an average pressure p on the wood. If the wood is replaced by a sheet that has half the diameter of the original piece, what is the new average pressure? I think the answer is 4p but I don't know why.
The new average pressure will be four times the original pressure when the wood is replaced by a sheet with half the diameter, i.e p' = 4p.
The pressure exerted by an object is given by the force applied divided by the area over which it is distributed.
The formula for pressure (p) is (p = F/A).
If the box exerts a pressure (p) on the original round sheet of wood, and the wood is replaced by a sheet with half the diameter, the new area will be (1/4) of the original (since area is proportional to the square of the diameter).
Therefore, the new pressure (p') can be expressed as:
p' = F ÷ (1/4)A = 4p
So, the new average pressure will be four times the original pressure when the wood is replaced by a sheet with half the diameter.