Answer:
M = 16.8 M
Explanation:
Data: HNO3
moles = 12.6 moles
solution volume = 0.75 L
Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.
[tex]M=\frac{moles}{solution volume}[/tex]
The data is replaced in the given equation:
[tex]M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}[/tex]
Answer:
The correct answer is 16.8 M
Explanation:
The molarity (M) of a solution is the number of moles of solute in 1 liter of solution. The HNO₃ solution contains 12.6 moles of solute (in this case the solute is HNO₃) in 0.75 liters. In order to find the molarity, we have to divide the number of moles into the volume in liters as follows:
M = 12.6 moles/0.75 L = 16.8 moles/L = 16.8 M
• A gas occupies what volume at a pressure of 5.4
atm, 3.5 moles of gas, at 333 K?
Answer: 17.71L
Explanation:
The volume can be calculated by using the ideal gas equation which is given as:
PV =nRT
Where P = Pressure, V= Volume, n= number of moles, R= gas constant and T = Temperature
From the above question :
P =5.4 ATM, V= ? n = 3.5 , R =0.082057 L atm /mol/K, T= 333K
PV = nRT
Make V subject of the formula we then have:
V= nRT/P
= 3.5 x 0.082507 L x 333 / 5.4
= 95.64 / 5.4 = 17.7L
How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the molecules in dry air.) (Enter your answer using either standard or scientific notation. For scientific notation, 6.02 x 10^{23} is written as 6.02E23.)
To determine the number of moles of O2 molecules in the given sample of dry air, we need to use the ideal gas law equation PV = nRT. We are given the pressure (P), volume (V), and temperature (T) of the sample, and we can calculate the number of moles (n) of oxygen molecules.
Explanation:To determine the number of moles of O2 molecules in the given sample of dry air, we need to use the ideal gas law equation PV = nRT. We are given the pressure (P), volume (V), and temperature (T) of the sample, and we can calculate the number of moles (n) of oxygen molecules.
First, we need to calculate the partial pressure of oxygen in the air using the percent content in the mixture. Oxygen constitutes 20.94% of the molecules in dry air, so the partial pressure of oxygen (PO2) is calculated as PO2 = (Patm) X (percent content of oxygen). Given that the atmospheric pressure (Patm) is 0.0395 atm, the partial pressure of oxygen is PO2 = (0.0395 atm) X (0.2094).
Once we have the partial pressure of oxygen, we can use PV = nRT to calculate the number of moles of oxygen molecules (n). Rearranging the equation, n = PV / RT, where P is the partial pressure of oxygen, V is the volume of the sample, R is the ideal gas constant, and T is the temperature in Kelvin. Plugging in the values, we get n = (PO2)(V) / (RT).
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Benzene, C6H6, reacts with nitric acid, HNO3. Two products are formed, one of which is water. The second product has a molar mass of 213 grams. The second product is composed of 33.8% carbon, 1.42% hydrogen, 19.7% nitrogen, and 45.1% oxygen. Write a balanced chemical equation for this reaction:
Answer:
C₆H₆ + 3HNO₃ → C₆H₃N₃O₆ + 3H₂O
Explanation:
The reaction is:
Benzene + Nitric acid → Water + ?
Let's determine the ? compound
Molar mass 213 g/mol
33.8g of C in 100 g of compound |
1.42 g of H in 100g of compound | _ Percent composition
19.7 g of N in 100g of compound |
45.1 g of O in 100g of compound |
We propose these rule of three:
In 100 g of compound we have 33.8 g C, 1.42 g H, 19.7g N and 45.1g O
Therefore in 213g of compound we must have:
(213 . 33.8) / 100 = 72 g of C
(213 . 1.42) / 100 = 3 g of H
(213 . 19.7) / 100 = 42 g of N
(213 . 45.1) / 100 = 96 g of O
Now, we convert the mass to moles:
72 g of C . 1 mol / 12g = 6 C
3 g of H . 1 mol / 1g = 3 H
42 g of N . 1 mol / 14 g = 3 N
96 g of O . 1 mol / 16 g = 6 O
Molecular formula is C₆H₃N₃O₆. So the balanced reaction will be:
C₆H₆ + 3HNO₃ → C₆H₃N₃O₆ + 3H₂O
Chemistry: Gas Laws Problems!
Answer : The final volume at STP is, 1000 L
Explanation :
According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 1520 mmHg = 2 atm (1 atm = 760 mmHg)
[tex]P_2[/tex] = final pressure at STP = 1 atm
[tex]V_1[/tex] = initial volume = 500.0 L
[tex]V_2[/tex] = final volume at STP = ?
Now put all the given values in the above formula, we get:
[tex]2atm\times 500.0L=1atm\times V_2[/tex]
[tex]V_2=1000L[/tex]
Therefore, the final volume at STP is, 1000 L
The volume of the gas at STP is [tex]\(1000.0 \, \text{L}\)[/tex].
1. Convert initial pressure to atm:
[tex]\[ P_1 = \frac{1520 \, \text{mm Hg}}{760 \, \text{mm Hg/atm}} = 2 \, \text{atm} \][/tex]
2. Apply the Combined Gas Law:
[tex]\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \][/tex]
Given:
[tex]\[ V_1 = 500.0 \, \text{L} \][/tex]
[tex]\[ P_1 = 2 \, \text{atm} \][/tex]
[tex]\[ P_2 = 1 \, \text{atm} \][/tex]
[tex]\[ T_1 = T_2 \][/tex] (temperature does not change)
Substituting the values, we get:
[tex]\[ \frac{(2 \, \text{atm} \cdot 500.0 \, \text{L})}{T} = \frac{(1 \, \text{atm} \cdot V_2)}{T} \][/tex]
3. Solve for [tex]\(V_2\)[/tex]:
Cross-multiply and solve for [tex]\(V_2\)[/tex]:
[tex]\[ 2 \cdot 500.0 = 1 \cdot V_2 \][/tex]
[tex]\[ V_2 = \frac{2 \cdot 500.0}{1} \][/tex]
[tex]\[ V_2 = 1000.0 \, \text{L} \][/tex]
11. A wasp lays its eggs on a caterpillar. When the wasp eggs hatch, the larva will eat the caterpillar
and kill it. *
(2 Points)
O
A. Parasitism
O
B. Mutualism
O
C. Commensalism
Answer:
A
Explanation:
That is the only one that makes sense. Parasitism harms the the host while the parasite gains.
Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat is absorbed (3) reaction is exothermic (4) reaction is endothermic (5) products have higher enthalpy content than reactants (6) reactants have higher enthalpy content than products A) 1, 3, and 5 B) 1, 3, and 6 C) 2, 4, and 6 D) 2, 4, and 5
Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
Answer:
D
Explanation:
A unicellular, prokaryotic organism is discovered by scientists. Are these characteristics enough to place it in a domain, or is more information needed?
PLZ HELP!!! WILL GIVE YOU BRAINLIEST 100 POINTS!!!
Answer:
yes
Explanation:
Which element will have the following property in the periodic table 1)Largest atomic size 2) Highest electron affinity 3) lowest ionisation enthalpy in group II 4) gaseous form at room temperature
In the periodic table, Francium has the largest atomic size, Chlorine has the highest electron affinity, Barium has the lowest ionization enthalpy in Group II, and gaseous elements at room temperature include noble gases and some non-metals like Fluorine and Oxygen.
The periodic table organizes elements in such a way that we can predict their properties based on their position. These properties, including atomic size, electron affinity, and ionization enthalpy, show clear patterns or trends within the table. As a tutor from the Brainly platform, let's address the specific properties asked in the question.
The element with the largest atomic size is typically found at the bottom left of the periodic table. Francium (Fr) is generally considered to have the largest atomic radius because it belongs to Group 1 and is the heaviest alkali metal. The atomic size increases down a group and decreases across a period from left to right.Highest electron affinity is generally observed in halogens. Chlorine (Cl), being very eager to gain an electron to achieve a noble gas electron configuration, has one of the highest electron affinities.The element with the lowest ionization enthalpy in Group II is expected to be at the bottom of the group. Barium (Ba), being at the lower part of Group II, has lower ionization energy compared to its counterparts up the group.Gases at room temperature from Group II are notable as they are non-existent; however, elements that are in gaseous form at room temperature from the periodic table include the noble gases such as Radon (Rn), Xenon (Xe), Krypton (Kr), Argon (Ar), Neon (Ne), Helium (He), and some non-metals like Fluorine (F), Chlorine (Cl), Oxygen (O), Nitrogen (N), and Hydrogen (H).Which process is used to determine the concentration of an acid?
Answer:
testing
Explanation:
some scientist somewhere made acid and probably forgot the recipe/ingredients so they kept making it and used plastic to see if it would melt it
The diagram shows a pump. Which labels can replace
X and the Y in the diagram?
X: potassium, Y: sodium
X: sodium, Y potassium
X: sodium, Y: calcium
X: calcium, Y: potassium
Answer: The Answer is B. X: Sodium, Y: Potassium
Explanation: No Explanation I just Guessed. Hope This Help's Someone
Answer:
The answer is
X:Sodium Y:Potassium
Explanation:
I took the course and got it right
C. Describe ONE way in which relocation diffusion resulted in the cultural landscapes shown in both photographs.
D. Explain how the cultural landscapes shown in the photographs represent more than one culture,
Answer:
Explanation:
THIS IS THE COMPLETE QUESTION
A)Identify TWO cultural traits shown in one or both of the photographs that are indicative of ethnicity.
B)Describe the process of relocation diffusion.
C)Describe ONE way in which relocation diffusion resulted in cultural landscapes shown in both photographs.
D)explain how the cultural landscapes shown in the photographs represent more than one culture.
EXPLANATION:
A)the two cultural traits shown in the photographs that are indicative of ethnicity are;
1) the torri
2)the logograms
B)The process of relocation diffusion provide an idea as a result of people moving from one place to another especially the adopters, they move from their base to new place.
C)Relocation diffusion resulted in the cultural landscapes that is shown in both photographs just gave the intance of migration process.
for instance, those that migrated to CALI and UK from china came along with their cultural trait too. As well as their custom
D)The cultural landscapes that is shown in the photographs gives the representation of multiple culture through displaying of
architectural styles from different culture.
Cultural landscapes display a linguistic features of more than one languages.
Relocation diffusion contributes to cultural landscapes by introducing new cultural elements through migration. Such landscapes often represent multiple cultures, as both local and migrated cultures can leave their imprint on the environment.
Explanation:Relocation diffusion refers to the spread of a cultural trait by individuals who migrate and carry this trait with them to new locales. For example, when individuals who practice a particular religion migrate to a new location, they might build places of worship resembling those in their homeland, thus altering the cultural landscape of their new locale.
Cultural landscapes can often represent more than one culture because both the local and migrated cultures influence the landscapes. For example, in a cultural landscape where a McDonald's (representing American fast food culture) is situated next to a Buddhist temple (representing Asian religious culture), it is evident that more than one culture is influencing the setting.
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If 35 mL of 0.10 Macid solution is neutralized by 21.8 mL of a basic solution, what is the molarity
of the base? MaVa = MbVb
2. If 6.0g of carbon is heated in air, the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of air present. Show that this verifies the law of multiple proportions.
3. Alaxin, (C5H8)nO5, is a new malaria drug. Determine the molecular formula of alaxin if its relative molecular mass is 284.
(H = 1, C = 12, O = 16)
i dont seem to remeber
2 . The ratio of 1:2 in the mass of second element, oxygen in CO and CO2 verifies the law of proportion.
3. [tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the new malaria drug given.
Explanation:
Balanced chemical reaction:
C + O ⇒ C0
C + O2 ⇒ CO2
law of multiple formulation states that when two elements combine to form a compound the ratio of the mass of elements is a whole number.
Carbon reacts with oxygen to produce:
Mass of carbon mass of oxygen ratio of O in CO2 to O in CO
CO = 12 16 3:4
CO2 = 12 32 3:8
CO 6 gm 8 3:4
CO2 6 16 3:8
The ratio of the mass of the second element i.e oxygen is CO:CO2 is 1:2, hence it shows law of multiple proportions.
3. given,
(C5H8)nO5 = emperical formula
relative molecular mass = 284
molecular formula= ?
The value of n will be calculated as:
(12x5)+ (1x8)n + (16x5) = 284
(60 +8)n + 80 = 284
68n + 80 = 284
68n = 284 - 80
68n = 204
n = 3
Multiplying the emperical formula by n
(C5H8)3O5
[tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the drug.
The formation of different carbon oxide compounds with differing masses of oxygen that combine with a fixed mass of carbon demonstrates the law of multiple proportions with a small whole number ratio. To find the molecular formula of Alaxin, the relative molecular mass is divided by the mass of its empirical formula, yielding a molecular formula of C10H16O10.
Explanation:The law of multiple proportions states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in the ratio of small whole numbers. To verify this with carbon and oxygen, we consider the two cases: carbon dioxide (CO2) and carbon monoxide (CO).
When 6.0g of carbon reacts with oxygen, we can get either 22.0g of carbon dioxide or 14.0g of carbon monoxide. The mass of oxygen that combines with the 6.0g of carbon can be calculated for each compound:
For carbon dioxide: Mass of oxygen = 22.0g (total mass) - 6.0g (carbon) = 16.0gFor carbon monoxide: Mass of oxygen = 14.0g (total mass) - 6.0g (carbon) = 8.0gThe ratio of the mass of oxygen in carbon dioxide to the mass of oxygen in carbon monoxide is 16.0g : 8.0g = 2:1, which is a small whole number ratio, thus verifying the law of multiple proportions.
To determine the molecular formula of Alaxin, given its relative molecular mass is 284:
Calculate the relative molecular mass of the empirical formula (C5H8O5): (12*5) + (1*8) + (16*5) = 60 + 8 + 80 = 148 g/mol.Divide the relative molecular mass of Alaxin by the empirical formula mass to find n: 284 / 148 = 1.92, approximately 2.The molecular formula is (C5H8O5)2, or C10H16O10.
How many liters of H2 gas, collected over water at an atmospheric pressure of 752 mm Hg and a temperature of 21.0°C, can be made from 3.566 g of Zn and excess HCl? The partial pressure of water vapor is 18.65 mm Hg at 21.0°C.
Final answer:
To find the volume of H2 gas generated, first calculate the partial pressure of H2 using the ideal gas law equation PV = nRT. Then, convert moles of H2 to grams using the molar mass of H2. Finally, convert grams of H2 to liters using the molar volume of gas at STP.
Explanation:
When collecting a gas over water, the total pressure is equal to the sum of the partial pressure of the gas and the vapor pressure of water. To find the volume of H2 gas generated, we need to calculate the partial pressure of H2 gas. We can use the ideal gas law equation PV = nRT to solve for the number of moles of H2, and then use the molar mass of H2 to convert moles to grams. Finally, we can convert grams to liters using the molar volume of gas at STP. First, we need to calculate the partial pressure of H2 gas. The total pressure is given as 752 mm Hg, and the vapor pressure of water at 21.0°C is 18.65 mm Hg. So, the partial pressure of H2 gas is 752 mm Hg minus 18.65 mm Hg, which equals 733.35 mm Hg.
Next, we can use the ideal gas law equation PV = nRT to solve for the number of moles of H2 gas:
n = PV / RT = (733.35 mm Hg / 760 mm Hg/atm) * (1 atm / 760 mm Hg) * (3.566 g Zn / 65.38 g/mol) = 0.072 mol H2
Finally, we can convert moles to liters using the molar volume of gas at STP:
V = n * (22.4 L/mol) = 0.072 mol * (22.4 L/mol) = 1.6136 L
how many moles are in 10.0 grams of sodium hydroxide?
Name this compound please
Answer:
Ethanol
Explanation:
2 C atoms and a single OH group.
Formula: C2H5OH
Aqueous silver nitrate (AgNO₃) and aqueous sodium bromide (NaBr) react to produce solid silver bromide (AgBr) and aqueous sodium nitrate (NaNO₃). The reaction that occurs is as follows: [tex]AgNO3(aq) + NaBr(aq) \rightarrow AgBr(s) + NaNO3(aq)[/tex]If the reaction was carried out, what would the mass of the precipitate tell you _________.
Answer:
The mass of the precipitate will give the amount/concentration of Bromide ion present in the reaction setup, thereby indirectly giving the amount/concentration of NaBr (aq) that we started with.
Explanation:
[tex]AgNO3(aq) + NaBr(aq) \rightarrow AgBr(s) + NaNO3(aq)[/tex]
From the mass of AgBr precipitate formed, we can obtain the mass of Br originally in the NaBr sample we started with, using the percentage by mass of Br in the AgBr precipitate multiplied by the mass of precipitate obtained.
This answer can then be used in a similar method to obtain the mass of NaBr we started with.
Mass of Br in AgBr = (Mass of precipitate obtained) × [(molar mass of Br)/(molar mass of AgBr)]
Mass of NaBr we started with = (Mass of Br in precipitate) × [(Molar Mass of NaBr)/(Molar mass of Br)]
The mass of the precipitate will give the amount/concentration of Bromide ion present in the reaction setup, thereby indirectly giving the amount/concentration of NaBr (aq) that we started with.
Hope this Helps!!!
The mass of the silver bromide (AgBr) precipitate in a reaction with silver nitrate (AgNO₃) and sodium bromide (NaBr) gives an indication of the reaction’s efficiency and how much of the reactants have reacted due to the principle of conservation of mass.
Explanation:In the given chemical reaction, the mass of the precipitate, which is silver bromide (AgBr), gives an indication of how much of the reactants have reacted. This is due to the principle of conservation of mass which states that mass cannot be created or destroyed in a chemical reaction. Therefore, the total mass of reactants before the reaction will equal the total mass of the products after the reaction.
If you knew the initial amounts of silver nitrate (AgNO₃) and sodium bromide (NaBr), you could calculate the theoretical yield of silver bromide (AgBr) using stoichiometry. Then, by comparing this theoretical yield with the actual mass of the precipitate formed, you could calculate the percentage yield of the reaction, which is a common measure of reaction efficiency.
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What is the concentration of hydronium in each of the following cases:
[OH-] = 10-12 M ?
[OH-] = 10-2 M ?
1. For [tex]\([OH^-] = 10^{-12} \, M\)[/tex], the concentration of [tex]\([H_3O^+]\)[/tex] is [tex]\(10^{-2} \, M\)[/tex].
2. For [tex]\([OH^-] = 10^{-2} \, M\)[/tex], the concentration of [tex]\([H_3O^+]\)[/tex] is [tex]\(10^{-12} \, M\)[/tex].
Relationship Between [tex]\([H_3O^+]\) and \([OH^-]\)[/tex]:
The ion-product constant for water [tex](\(K_w\))[/tex] at 25 °C is [tex]\(1 \times 10^{-14} \, M^2\)[/tex].
[tex]\[ [H_3O^+] \times [OH^-] = K_w = 1 \times 10^{-14} \, M^2 \][/tex]
Case 1: [tex]\([OH^-] = 10^{-12} \, M\)[/tex]
[tex]\[ [H_3O^+] = \dfrac{K_w}{[OH^-]} = \dfrac{1 \times 10^{-14} \, M^2}{10^{-12} \, M} = 10^{-2} \, M \][/tex]
Case 2: [tex]\([OH^-] = 10^{-2} \, M\)[/tex]
[tex]\[ [H_3O^+] = \dfrac{K_w}{[OH^-]} = \dfrac{1 \times 10^{-14} \, M^2}{10^{-2} \, M} = 10^{-12} \, M \][/tex]
At room temperature, which answer is the most compressible?
one liter of water, a liquid
one liter of oxygen, a gas
one liter of iron, a solid
one liter of mercury, a liquid
Answer:
i think its 1 liter of oxygen , a gas
Final answer:
One liter of oxygen gas is the most compressible among the options given, due to the significant spaces between gas molecules allowing for easier compression.
Explanation:
When considering the compressibility of various substances at room temperature, gases such as oxygen are the most compressible due to the large spaces between their molecules. In comparison, liquids like water and mercury are less compressible because their molecules are closer together, but they still offer some degree of compressibility. Solids like iron, however, are much less compressible because their atoms are tightly packed in a lattice structure. Of the options provided, one liter of oxygen gas would be the most compressible, as the spacing between gas molecules allows them to be pushed closer together far more easily than molecules in a liquid or atoms in a solid.
A mixture of 8.0 mol Ne and 8.0 mol Xe are at STP in a rigid container. Which of the following statements is TRUE?
A) Both gases have the same average kinetic energy.
B) Both gases contribute equally to the density of the mixture under these conditions.
C) Both gases have the same molecular speed.
D) The mixture has a volume of 22.4 L
E) All of the above are TRUE.
OPTION A. A) Both gases have the same average kinetic energy.
In the given gas mixture of Neon (Ne) and Xenon (Xe) at Standard Temperature and Pressure (STP), both gases only share the same average kinetic energy. However, they do not contribute equally to the mixture's density, they do not share the same molecular speed, and the total volume of the mixture is not 22.4L.
Explanation:The TRUE statement among the options given is A) Both gases have the same average kinetic energy. The average kinetic energy of gas molecules is determined by temperature, not the type of gas, according to kinetic molecular theory. Therefore, since both gases are at the same temperature (Standard Temperature and Pressure, STP), they will have the same average kinetic energy.
B) is incorrect since each gas contributes to the mixture's density based on its own molar mass, and Xenon's molar mass is much greater than Neon's.
Option C is not correct because molecular speed is influenced by molar mass. Neon, having a smaller molar mass, will have a higher average speed than Xenon.
Statement D) is incorrect because according to Avogadro's law, one mole of any gas at STP occupies a volume of 22.4L, and we have a total of 16 moles of gas (8.0 mol of Ne and 8.0 mol of Xe) which will occupy a volume of 16 times 22.4L.
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how is temperature related to the physical change of a substance ?
Answer: Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.
Explanation:
NEED HELP WITH CHEM :)
What volume of a 3.70 M NaCl solution is needed for a reaction that requires 118 g of NaCl?
Answer:
volume of solution L =0.54 L
Explanation:
Given data:
Molarity of NaCl solution = 3.70 M
Mass of NaCl = 118 g
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 118 g/ 58.5 g
Number of moles = 2 mol
Now we will calculate the volume from molarity formula:
Molarity = number of moles / volume of solution L
3.70 M = 2 mol / volume of solution L
volume of solution L = 2 mol / 3.70 M
volume of solution L =0.54 L
how much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Answer:
13mL
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
HNO3 + KOH —> KNO3 + H2O
From the balanced equation above, we obtained the following data:
Mole ratio of the acid (nA) = 1
Mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question.
This includes the following:
Molarity of the acid (Ma) = 6M
Volume of the acid (Va) =?
Volume of the base (Vb) = 39mL
Molarity of the base (Mb) = 2M
Step 3:
Determination of the volume of the acid.
Using the equation:
MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:
MaVa/MbVb = nA/nB
6 x Va / 2 x 39 = 1/1
Cross multiply to express in linear form
6 x Va = 2 x 39
Divide both side by 6
Va = (2 x 39)/6
Va = 13mL
Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL
A propane torch is lit inside a hot air balloon during preflight preparations to inflate the balloon.
Which condition of the gas remains constant?
Answer: its pressure
Explanation: just trust me
If 2.87 g of aluminum are reacted with excess copper (II) sulfate and 9.2 g of copper are produced what is the percent yield
92.8 % is the percent yield when 2.87 g of aluminum are reacted with excess copper (II) sulfate and 9.2 g of copper are produced.
Explanation:
Mass of aluminum = 2.87 grams
mass of copper produced = 9.2 grams ( actual yield)
the balanced chemical reaction is given as:
2 Al + 3 CuSO4 ⇒ ( AL2(SO4)3 +3 Cu.
from the reaction it is found that
2 moles of aluminum reacted to give 3 moles of copper
so converting them in to mass.
number of moles of copper in 2.8 grams = [tex]\frac{2.8}{63.4}[/tex]
number of moles = 0.104 moles of copper
atomic mass of aluminum = 26.98 grams/mole
atomic mass of copper = 63.54 grams/mole
From the given data
2.87 grams Al gives 9.2 grams of Cu.
2 moles of aluminum reacted to give 3 moles of copper
0.104 moles of aluminum will give
[tex]\frac{3}{2}[/tex] =[tex]\frac{x}{0.104}[/tex]
2x = 0.132
x = 0.156 moles of Cu will be formed.
Hence theoretical yield should be = 0.156 x 63.54
= 9.91 grams
Percent yield = [tex]\frac{actual yield}{theoretical yield}[/tex] x 100
= [tex]\frac{9.2}{9.91}[/tex] x 100
percent yield = 92.8 % is the yield percent.
A neutral solution has a pH =
When a solution is basic, the pH is always greater than
When a solution is basic, the pOH is always less than
Answer:
7.
Explanation:
A neutral solution has a pH=7.
A basic solution has a pH>7.
An acidic solution has a pH<7.
Answer:
7,7,7
Explanation:
the amount of calcium hydroxide needed to react completely with a 100.0 g of nitric acid
Answer:
The answer to your question is 58.7 g of Ca(OH)₂
Explanation:
Data
mass of Ca(OH)₂ = ?
mass of HNO₃ = 100 g
Process
1.- Write the balanced chemical reaction
Ca(OH)₂ + 2HNO₃ ⇒ Ca(NO₃)₂ + 2H₂O
2.- Calculate the molar mass of the reactants
Ca(OH)₂ = 40 + 32 + 2 = 74 g
HNO₃ = 1 + 14 + 48 = 63 g
3.- Use proportions to calculate the mass of Ca(OH)₂
74 g of Ca(OH)₂ ----------------- 2(63) g of HNO₃
x ----------------- 100 g of HNO₃
x = (100 x 74) / 2(63)
x = 7400 / 126
x = 58.7 g
Carbon-14 is an element which loses exactly half of its mass every 5730 years. The mass of a sample of
carbon-14 can be modeled by a function, M, which depends on its age, t (in years).
We measure that the initial mass of a sample of carbon-14 is 741 grams.
Answer:
[tex]M=741\times (0.5)^{\frac{t}{5730}}[/tex]
Explanation:
by using well known formula for disintegration
[tex]M=M_0\times (0.5)^{\frac{t}{T}}[/tex]
Final answer:
To calculate the original mass of carbon-14 in an artifact aged 10,670 years, given it now contains 8.4 × 10⁽⁻⁹⁾ grams of carbon-14, we use the half-life of carbon-14 (5,730 years) and the formula for exponential decay. The original mass is found to be 33.6 × 10⁽⁻⁹⁾ grams.
Explanation:
The subject of the question involves using exponential decay to calculate the original mass of carbon-14 in an archaeological artifact, taking into account the half-life of carbon-14, which is 5,730 years. Given that a sample now contains 8.4 × 10-9 grams of carbon-14 and its age is 10,670 years, we can calculate the original amount of carbon-14 it contained. To find the original mass of carbon-14, we can use the formula for exponential decay, M = M0(1/2)t/T, where M is the final mass, M0 is the original mass, t is the time elapsed, and T is the half-life of the substance.
Since 10,670 years is exactly two half-lives of carbon-14 (2 × 5,730), we can calculate that the artifact originally contained 8.4 × 10-9 grams × 22 = 33.6 × 10-9 grams of carbon-14.
Heat transfer focuses on transfers between the system and _____
A. accessories
B. universe
C. phases
D. surroundings
Calculate the concentration of acetic acid (pka 54.76)and sodium acetate necessary to prepare a 0.2 m buffer solution at pH 5.0
Answer:
See explanation below
Explanation:
To solve this problem, we need to use the Henderson - Hasselbach equation which is the following:
pH = pKa + log ([A⁻] / [HA]) (1)
Where:
[A⁻] = concentration of the acetate
[HA] = concentration of the acetic acid.
With the above expression, we can calculate the ratio of [A⁻] / [HA]. This concentration ratio will be used to calculate the individual concentrations. We know that a buffer is made as a mix of the acid and it's ion, in other words:
[HA] + [A⁻] = [Buffer] (2)
So, with the concentration ratio, we can replace it here in (2) and then, we can calculate each concentration required.
First, let's use (1) to get the concentration ratio:
5 = 4.76 + log ([A⁻] / [HA])
5 - 4.76 = log ([A⁻] / [HA])
0.24 = log ([A⁻] / [HA])
[A⁻] / [HA] = 10⁰°²⁴
[A⁻] / [HA] = 1.7378
From this ratio, we can express either HA or A in function of the result. In this case, we will solve for A:
[A⁻] = 1.7378[HA]
With this expression, we can replace it in (2) to solve for [HA]:
[HA] + 1.7378[HA] = 0.2
2.7378[HA] = 0.2
[HA] = 0.0731 MNow all we have to do is replace this value in [A] to get the concentration:
[A⁻] = 1.7378 * 0.0731
[A⁻] = 0.1270 M