The AH for the reaction is 1043 kJ/mol and the reaction is endothermic.
Explanation:The reaction you provided:
2NaHCO3(s) → Na2CO3(s) + H2O(l) + CO2(g)
AH = -948 kJ/mol - (-1311 kJ/mol + -286 kJ/mol + -394 kJ/mol)
AH = -948 kJ/mol + 1311 kJ/mol + 286 kJ/mol + 394 kJ/mol
AH = 1043 kJ/mol
The value of AH is 1043 kJ/mol, which means the reaction is endothermic. This is because the AH value is positive, indicating that energy is absorbed from the surroundings during the reaction.
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To find the ΔH for the decomposition of sodium bicarbonate, we subtract the sum of the enthalpies of formation of the reactants from those of the products, which results in -95 kJ. This indicates the reaction is exothermic.
Explanation:To determine the enthalpy change (ΔH) for the decomposition of sodium bicarbonate (baking soda), we use the given enthalpies of formation for the reactants and products in the reaction:
2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(l)
The enthalpy (ΔH) for the reaction is calculated as follows:
ΔH = { ΔHf(products) - ΔHf(reactants) }
For this reaction, the enthalpy change is:
ΔH = [(-1311 kJ/mol for Na2CO3) + (-394 kJ/mol for CO2) + (-286 kJ/mol for H2O)] - [2 x (-948 kJ/mol for NaHCO3)]
ΔH = (-1311 - 394 - 286) - (2 x -948)
ΔH = -1991 + 1896
ΔH = -95 kJ
Since the enthalpy change is negative, we can classify this reaction as exothermic. An exothermic reaction is one that releases heat to the surroundings, as evidenced by the negative sign of ΔH.
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If 16 grams of sugar, C12H22O11, are in a spoonful, how many molecules of sugar are in the spoonful?
Answer:
If 16 grams of sugar are in a spoonful, 2.83*10²² molecules of sugar are in the spoonful
Explanation:
Avogadro's Number or Avogadro's Constant is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.
So you need to know how many moles are 16 grams of sugar, C₁₂H₂₂O₁₁. For that you must know the molar mass of sugar. Being:
C: 12 g/moleH: 1 g/moleO: 16 g/molethe molar mass of sugar is:
C₁₂H₂₂O₁₁= 12 *12 g/mole + 22 * 1 g/mole + 11* 16 g/mole= 342 g/mole
Then the following rule of three applies: if 342 grams of sugar are present in 1 mole of substance, 16 grams in how many moles will they be?
[tex]moles=\frac{16 grams*1 mole}{342 grams}[/tex]
moles= 0.047
Now, knowing Avogadro's number, you can apply the following rule of three: if 1 mole of sugar contains 6.023 * 10²³ molecules, 0.047 moles how many molecules does it have?
[tex]molecules=\frac{0.047 moles*6.023*10^{23} }{1 mole}[/tex]
molecules= 2.83*10²²
If 16 grams of sugar are in a spoonful, 2.83*10²² molecules of sugar are in the spoonful
Answer:
2.82x10^22 molecules.
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules.
The above hypothesis implies that 1 mole of sugar, C12H22O11 also contains 6.02x10^23 molecules.
1 mole of C12H22O11 = (12x12) + (22x1) + (16x11) = 144 + 22 + 176 = 342g
Now, if 342g of C12H22O11 contains 6.02x10^23 molecules,
Therefore 16g of C12H22O11 will contain = (16x6.02x10^23)/342 = 2.82x10^22 molecules.
Therefore, 2.82x10^22 molecules of the sugar are in the spoon
Choose all of the statements below that are true about Avogadro's number and the mole:
A) A mole is a counting unit
B) Avogadro's number is to the mole what "12" is to a "dozen" or what "2" is to a "pair"
C) We can use a conversion factor with Avogadro's number in it to determine the number of particles, atoms and/or molecules in a substance of given moles.
D) A mole simply means 6.022 x 10^23 of something (atoms, molecules, particles)
E) Avogadro's number is 6.022
A, B, C, D
Explanation:
Avogadro number is a constant at 6.022 x 10^23. The number is equivalent to a mole in Chemistry. It stipulates the number of particles expected in a mole of a substance. This unit of measurement is named after its inventor, Amedeo Avogadro, an Italian scientist.
It is also used to derive the molar mass of a substance. Dalton is used in expressing the mass of a mole of a substance– atomic mass unit (AMU) * Mass Number.
Carbon monoxide and chlorine gas react to produce COCl2 gas. The Kp for the reaction is 1.49 × 108 at 100.0 °C: In an equilibrium mixture of the three gases, PCO, = PCl2 = 7.70 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is ________ atm. Use the assumption that change in x is small so you do not have to use the quadratic.
Answer:
Explanation:
Solution:
For the equilibrium
The equilibrium constant is defined in terms of partial pressure:
Introducing the numerical data given for partial pressureof carbon monoxide 0 and chlorine 12, also the value for equilibrium constant:
Answer:
The partial pressureof the product, phosgene (COCl2), is 29.4atm
Answer:
88.34 atm
Explanation:
At equilibrium, carbon monoxide (CO) would react with chlorine gas according to the equation below:
CO (g) + Cl₂ (g) ⇒ COCl₂ (g)
The equilibrium constant Kp, which is a ratio of the partial pressure of the product to that of the reactants is obtained from the equation below:
Kp = PCOCL / PCO.PCl₂
From the question given,
Kp = 1.49 x 10⁸ t 100° C
PCO = 7.70 X 10⁻⁴ atm
PCl₂ = 7.70 x 10⁻⁴ atm
It therefore implies that,
1.49 x 10⁸ = P(COCl₂) / (7.70 x 10⁻⁴). (7.70 x 10⁻⁴)
P(COCl₂) = 1.49 x 10⁸) . (7.70 x 10⁻⁴) . (7.70 x 10⁻⁴)
P (COCl₂) = 88.34 atm
The partial pressure P(COCl₂) of the product phosgene (COCl₂) is 88.34 atm
Percent yield for sodium bromide if 3.87 moles of iron 3 bromide yielded 10.4 moles of sodium bromide
Answer:
89.57 %
Explanation:
Don't have one just thought id help <3
Answer: 89.6
Explanation:
Nitrifiers are bacteria
a. capable of living in symbiosis in the roots of some plants.
b. capable of oxidizing NH3 using NO.
c. that convert N2 to NH3.
d. that generate nitrites or nitrates.
e. capable of using NH3 as an electron donor.
Answer:
(D.) Nitrifiers are bacteria that generate nitrites or nitrates.
Explanation:
In the nitrogen cycle which occurs in nature, ammonia and ammonium compounds in the soil from organic sources and are converted to nitrites and nitrates by aerobic microorganisms.
Nitrifiers, as the name implies, are these such aerobic bacteria which oxidize inorganic constituents in the soil to generate energy. Examples of these nitrifiers are nitrobacter and nitrosomonas.
How many elements are in the following equation?
CH3COCH3
Answer:
3
Explanation:
Answer:
3
Explanation:
the 3 elements are carbon hydrogen and oxygen
When 189.6 g of ethylene (C2H4) burns in oxygen to give carbon dioxide and water, how many grams of CO2 are formed? C2H4(g) + O2(g) → CO2(g) + H2O(g) (unbalanced)
Answer:
596 g of CO₂ is the mass formed
Explanation:
Combustion reaction:
C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)
We determine moles of ethylene that has reacted:
189.6 g . 1mol / 28g = 6.77 moles
We assume the oxygen is in excess so the limiting reagent will be the ethylene.
1 mol of ethylene produce 2 moles of CO₂ then,
6.77 moles will produce the double of CO₂, 13.5 moles.
We convert the moles to mass: 13.5 mol . 44 g /1mol = 596 g
El succinato de butilo es un repelente de insecto utilizado en la casa contra hormigas y cucarachas. Su composicion es de 65.28 por ciento de C, 9,63 por ciento de H y de 27,79 por ciento de O. Su masa molecular determinada experimentalmente es de 230 u, ¿cuales son las formulas empiricas y molecular del succinato de butilo?
Answer:
what is the English translation, id like to help
Explanation:
what is the mass of one mole of oxygen gas?
Answer:
32 grams
Explanation:
To find the molar mass of oxygen gas, you need to take a look at it's molecular formula. Oxygen is O2, and since each oxygen molecule has a molar mass of 16, 2 of them together have a molar mass of 32 grams. Hope this helps!
A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the chromium sulfide.
Answer: The empirical formula for the given compound is [tex]Cr_2S_3[/tex]
Explanation : Given,
Mass of product = 0.963 g
Mass of Cr = 0.500 g
Mass of S = 0.963 g - 0.500 g = 0.463 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Cr =[tex]\frac{\text{Given mass of Cr}}{\text{Molar mass of Cr}}=\frac{0.500g}{52g/mole}=0.00962moles[/tex]
Moles of S = [tex]\frac{\text{Given mass of S}}{\text{Molar mass of S}}=\frac{0.463g}{32g/mole}=0.0145moles[/tex]
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00962 moles.
For Cr = [tex]\frac{0.00962}{0.00962}=1[/tex]
For S = [tex]\frac{0.0145}{0.00962}=1.5[/tex]
To make in a whole number we are multiplying the ratio by 2, we get:
The ratio of Cr : S = 1 : 1.5
The ratio of Cr : S = 2 : 3
Step 3: Taking the mole ratio as their subscripts.
The ratio of Cr : S = 2 : 3
Hence, the empirical formula for the given compound is [tex]Cr_2S_3[/tex]
Se toman 200 ml de una disolución de un frasco de ácido clorhídrico ClH en cuya etiqueta se lee: Pureza: 35 % en peso; densidad = 1,15 g/ml. ¿Cuál es su concentración en g/l?
Answer:
Concentration of solution is 402g/mL
Explanation:
The HCl solution has a purity of 35% w/w. That means there are 35g of HCl per 100g of solution. As density of solution is 1.15g/mL, volume of the solution is:
100g solution × (1mL / 1.15g) = 86.96mL. Thus concentration of solution in g/mL is:
35g of HCl / 86.96mL = 0.402g/mL. As 1L contains 1000mL:
[tex]0.402\frac{g}{mL} \frac{1000mL}{1L}[/tex] = 402g/mL
Concentration of solution is 402g/mL
nitrogen + oxygen → nitrogen dioxide
Which of these is a reactant in this chemical reaction?
A) H2O
B) N2
C) N2O
D) NO2
Answer:
no2
Explanation:
Nitrogen N and Oxygen O2 combine to form NO2
What are the 3 advantages and uses of polyester fabric
Answer:
Synthetic fiber fabric has good heat resistance and thermoplasticity.
Good light resistance, light resistance is second only to acrylic.
Good chemical resistance. ...
High strength and elastic recovery. ...
Good water absorption. ...
you can choose any three from here
hope that was helpful.Thank you!!!
Final answer:
Polyester fabric has three main advantages: it is highly stain-resistant, has excellent wrinkle resistance, and is used in various industrial applications.
Explanation:
Advantages and Uses of Polyester Fabric:
Polyester fabric is highly stain-resistant, making it a durable option for apparel and home furnishings. It can resist spills and stains, making it easier to clean and maintain.Polyester fabric has excellent wrinkle resistance due to the cross-linking of polymer strands. This makes it a popular choice for permanent-press clothing that requires minimal ironing or maintenance.Industrial polyester fibers, yarns, and ropes are used in various applications such as car tire reinforcements, conveyor belts, safety belts, and coated fabrics. Polyester's high-energy absorption properties make it suitable for these industrial uses.An atom has the following electron configuration.
1s22s22p63s23p3
How many valence electrons does this atom have?
3
5
8
15
Answer:
5 electrons
Explanation:
Valence electrons are electrons located in the outermost energy shell, so you want to count the number of electrons in the last energy shell.
You can divide the configuration into 1s2 / 2s22p6 / 3s23p3 to see the energy shells in this atom. There are 3 shells occupied by the atom's electrons, so you need to count the electrons in the third shell as those are its valence electrons.
2 + 3 = 5 valence electrons total
Note: you don't count the 3 before the letter because that only indicates the shell level, not the number of electrons. Count only the exponents.
An atom that has the following electron configuration.
1s22s22p63s23p3 contains only 5 valence electrons in its outermost shell.
Electronic configuration of chemical elements is the classification and ordering of electrons around the nucleus of an atom in reference to their energy levels.
Electrons can be ordered and classified using Aufbau's principle.
Aufbau's principle posits that in the ground state of an atom, electrons are ordered to the subshell of the lowest energy levels before filling the higher energy level subshell.
The valence electron of a chemical element is the outermost electron participating actively in a chemical bonding.
From the given electronic configuration, we will first determine the total atomic number (total electrons) before we determine the valence electrons in the outermost shell.
Given that
1s² 2s² 2p⁶ 3s² 3p³
There are (2 + 2 + 6 + 2 + 3) total electrons in the elctronic configuration.
= 15 total electrons
The maximum number of electrons in the energy levels is determined by using the formula is [tex]\mathbf{2n^2}[/tex]
where;
n = 1, 2, 3 ....
In the first energy level, we have the maximum number of electrons to be:
= 2(1)²
= 2 electrons
In the second energy level, we have:
= 2(2)²
= 2(4) electrons
= 8 electrons
Since we have only 15 electrons, the number of the valence electrons in the atom is:
= 15- (2 + 8 ) electrons
= 15 electrons - 10 electrons
= 5 valence electrons left in the outermost shell.
In conclusion, an atom that has the following electron configuration 1s22s22p63s23p3 contains only 5 valence electrons in its outermost shell.
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A balloon containing helium gas expands from 230
mL to 860 mL as more helium is added. What was
the initial quantity of helium present if the
expanded balloon contains 3.8 x 10-4 mol,
assuming constant temperature and pressure?
Which of the variables are known?
Answer:
1.0 *10^(-4) mol
Explanation:
For gases:
n1/n2 = V1/V2
n1/3.8*10^(-4) mol = 230 mL/ 860 mL
n1 = 3.8*10^(-4)*230/860 = 1.0 *10^(-4) mol
A balloon containing gas expands from 230 mL to 860 mL as more helium is added. 1.0 × 10⁻⁴ mole was the initial quantity of helium present if the expanded balloon contains 3.8 × 10⁻⁴ mole assuming constant temperature and pressure.
Ideal Gas LawThe ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.
PV = nRT
where,
P = Pressure
V = Volume
n = number of moles
R = Ideal gas constant
T = Temperature
Now, calculating the ratio between the initial and the final numbers of moles of gas
PV = nRT
or, [tex]\frac{V}{n} = \frac{(RT)}{P}[/tex]
or, [tex]\frac{V}{n} = k[/tex]
or, [tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]
or, [tex]\frac{n_1}{n_2} = \frac{V_1}{V_2}[/tex] [Avogadro's Law]
Here, Volume and number of moles are the variables which are known.
Now put the values in above formula we get
⇒ [tex]\frac{n_1}{n_2} = \frac{V_1}{V_2}[/tex]
⇒ [tex]\frac{n_1}{3.8 \times 10^{-4}} = \frac{230}{860}[/tex]
⇒ [tex]n_{1} = \frac{3.8 \times 10^{-4} \times 230}{860}[/tex]
⇒ n₁ = 1.0 × 10⁻⁴ mole
Thus, we can say that 1.0 × 10⁻⁴ mole was the initial quantity of helium present if the expanded balloon contains 3.8 × 10⁻⁴ mole assuming constant temperature and pressure. Volume and number of moles are the variables which are known.
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Which element in period 3 has both metallic and non metalik properties
Answer:
Si is the answer I hope this help
17. A gas tank holds 2785 L of propane, C3H8, at 830. mm
Hg. What is the
volume of the propane at standard pressure?
Answer:
3041.5L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 2785 L
P1 (initial pressure) = 830mmHg
P2 (final pressure) = stp = 760mmHg
V2 (final volume) =?
Applying the Boyle's law equation P1V1 = P2V2, the final volume propane can be achieved by as illustrated below:
P1V1 = P2V2
830 x 2785 = 760 x V2
Divide both side by 760
V2 = (830 x 2785)/760
V2 = 3041.5L
Therefore, the volume of the propane at standard pressure is 3041.5L
By applying Boyle's Law and using the given initial conditions, the volume of propane at standard pressure is calculated to be 3041.71 L.
The question involves applying the gas law to determine the volume of propane at standard pressure. The given conditions are 2785 L of propane at 830 mmHg, and we need to find the volume at standard pressure (760 mmHg). Using Boyle's Law, which states that P1V1 = P2V2 where P is pressure and V is volume, we can calculate the new volume at standard pressure.
First, convert the initial pressure to the same units as the standard pressure, which is already in mmHg. Then, set up the equation with P1 = 830 mmHg, V1 = 2785 L, P2 = 760 mmHg, and solve for V2:
V2 = (P1 × V1) / P2 = (830 mmHg × 2785 L) / 760 mmHg
V2 = 3041.71 L
So, the volume of propane at standard pressure is 3041.71 L.
Sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is changed to 11.5°C, and the pressure is changed to 1.50 atm?
Answer: 2.34 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 0.850 atm
[tex]P_2[/tex] = final pressure of gas = 1.50 atm
[tex]V_1[/tex] = initial volume of gas = 4.25 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]23.0^oC=273+23.0=293.0K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]11.5^oC=273+11.5=284.5K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.850\times 4.25}{293.0K}=\frac{1.50\times V_2}{284.5}[/tex]
[tex]V_2=2.34L[/tex]
Thus the final volume will be 2.34 L
Air was put into an automobile tire when the tire was cold, at 5.00 C. The tire's air pressure was 3.04 atm. Later, the weather warms up. Also, the automobile is driven, further warming the tire. What will the tire's pressure be when the temperature is 25.0 C?
Answer:
[tex]P_{2} = 3.259\,atm[/tex]
Explanation:
Let suppose that air inside the tire behaves ideally. The equation of state for ideal gases is:
[tex]P\cdot V = n\cdot R_{u}\cdot T[/tex]
As tire can be modelled as a closed and rigid container, there are no changes in volume and number of moles. Hence, the following relationship is constructed:
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]
The final pressure is:
[tex]P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}[/tex]
[tex]P_{2} = \frac{298.15\,K}{278.15\,K}\cdot (3.04\,atm)[/tex]
[tex]P_{2} = 3.259\,atm[/tex]
Answer:
P2=3,26 atm
Explanation:
Considering that this gas behaves like an ideal gas, the equation used in noble gases is:
PxV = nxrxT
p is pressure, v is volume, n is number of moles, r is a constant of noble gases whose value is 0.082x10exp23 as long as you use it in the equations it has the same value (that is why it is called constant) and t would be the temperature.
Because v, r and n are values that did not change throughout the reaction of the gas, we are only going to take into account the p and t that did change throughout the reaction and that is why there is an initial and final pressure and a final and initial temperature.
So:
P1 / T1 = P2 / T2 (where value 1 refers to start, and 2 to end)
Regarding this equation, since we want to know the value of P2, which is the FINAL pressure of the gas, that is, what pressure did it achieve with the reaction, the equation that we would use would be solving for P2:
P2 = (T2 / T1) xP1 = 3.26 atm
The ingredient label for a fruit drink reads: water, sugar, orange juice, high fructose corn syrup, vitamin C, sodium benzoate (preservative), Red 40, Blue 1.
What can you conclude about the fruit drink’s contents?
A) The product contains no preservatives
B) The product contains more juice than water.
C) The product contains more sugar than juice.
D) The product contains more sugar than any other ingredient.
Answer:
C
Explanation:
C is the only one that is true. Because sugar comes before juice in the ingredients listed, there is more of it.
A chemist needs 225 ml of 2.4 m hcl. What volume of 12 m hcl must be mixed with water to form this solution?
To determine the volume of 12 M hydrochloric acid (HCl) needed to prepare 225 mL of 2.4 M HCl, you apply the dilution equation C1V1 = C2V2 and solve for V1.
The subject of this question is determining the volume of a concentrated hydrochloric acid (HCl) solution needed to prepare a more dilute solution of HCl.
We use the equation C1V1 = C2V2 where C1 is the concentration of the starting solution (12 M HCl), V1 is the volume of the starting solution we need to find, C2 is the concentration of the final solution (2.4 M HCl), and V2 is the volume of the final solution (225 mL).
Plugging the values into the equation gives us: (12 M)V1 = (2.4 M)(225 mL).
Therefore, V1 = (2.4 M)(225 mL) / (12 M).
By calculating V1, we get the volume of 12 M HCl needed to make 225 mL of 2.4 M HCl.
Jorge inflates a beach ball to a volume of 4L in his air-conditioned house where the temperature is 18℃. That afternoon he takes the beach ball to the beach with some friends. The temperature at the beach is 32℃, and the air pressure at the beach is the same as it was at Jorge's house. What will happen to Jorge's beach ball when he is at the beach? Choose the claim that best answers the question: * 1 point The beach ball will get smaller at the beach because the molecules are moving slower. The beach ball will stay the same size at the beach because the pressure is constant. The beach ball will get larger at the beach because the molecules are moving faster. The beach ball will get larger at the beach because the pressure will cause it to expand. The beach ball will get smaller at the beach because the molecules will collide less often.
Answer:
The beach ball will get larger at the beach because the molecules are moving faster.
Explanation:
We can answer this problem by using Charle's Law, which states that:
"For a constant mass of an ideal gas kept at constant pressure, the volume of the gas is directly proportional to its temperature"
Mathematically:
[tex]V\propto T[/tex]
where
V is the volume of the gas
T is the absolute temperature of the gas
Here, we are analyzing the air inside the ball (the gas). We are also told that when the ball is brought to the beach, the pressure does not change: therefore, we can apply Charle's Law.
We are told that when the ball is brought to the beach, the temperature increases from 18℃ to 32℃: therefore, since the volume of the air (and the ball) is proportional to the temperature, this means that the volume of the ball will increase as well.
The reason for this is that the ball is not thermally isolated, so the molecules of the air inside the ball reach soon the same temperature of the surroundings, and so they will move faster (higher temperature means higher average kinetic energy of the molecules, so the molecules move faster, and therefore the ball will expand).
So the correct option is
The beach ball will get larger at the beach because the molecules are moving faster.
Jorge's beach ball when he is at the beach should be beach ball will get larger at the beach because the molecules are moving faster.
What should be happening for beach ball?Here we applied Charle law, in this the volume of the gas is directly proportional to its temperature. Here the ball should not be isolated due to this it moved faster i.e. if there is high temperature that means there should be high kinetic energy so the molecules should be moved quicker due to this the ball should be expanded.
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The stopcock connecting a 1.30 L bulb containing xenon gas at a pressure of 6.15 atm, and a 4.25 L bulb containing oxygen gas at a pressure of 3.53 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is 8.33 atm. True or false?
Answer: False.
The final pressure in the system is 4.14 atm
Explanation: Please see the attachments below
A 2.425 g sample of a new organic material is combusted in a bomb calorimeter. The temperature of the calorimeter and its contents increase from 24.91 ∘ C to 30.28 ∘ C. The heat capacity (calorimeter constant) of the calorimeter is 28.81 kJ / ∘ C, what is the heat of combustion per gram of the material?
Answer:
-63.79 kJ/g
Explanation:
According to the law of conservation of energy, the sum of the heat released by the combustion of the new organic material (Qcomb) and the heat absorbed by the bomb calorimeter (Qbc) is zero.
Qcomb + Qbc = 0
Qcomb = -Qbc [1]
We can calculate the heat absorbed by the bomb calorimeter using the following expression.
Qbc = C × ΔT
where,
C: calorimeter constantΔT: change in the temperatureQbc = C × ΔT
Qbc = 28.81 kJ/°C × (30.28°C - 24.91°C) = 154.7 kJ
From [1],
Qcomb = -154.7 kJ
The heat of combustion per gram of the material is:
-154.7 kJ / 2.425 g = -63.79 kJ/g
Answer:
The heat of combustion per gram of the material is -63.8 kJ/ gram
Explanation:
Step 1: Data given
Mass of a ew organic material = 2.425 grams
The initial temperature of the calorimeter = 24.91 °C
The final temperature of the calorimeter = 30.28 °C
The heat capacity (calorimeter constant) of the calorimeter is 28.81 kJ /°C
Step 2: Calculate heat
Q = c*ΔT
⇒with c = the heat capacity (calorimeter constant) of the calorimeter is 28.81 kJ /°C
⇒with ΔT = The change of temperature = T2 - T1 = 30.28 - 24.91 = 5.37 °C
Q = 28.81 kJ/ °C * 5.37 °C
Q = 154.7 kJ
Step 3: Calculate the heat of combustion per gram of the material
heat of combustion per gram = -Q / mass (negative since it's exothermic)
heat of combustion per gram = -154.7 kJ / 2.425 grams
heat of combustion per gram = -63.8 kJ/ gram
The heat of combustion per gram of the material is -63.8 kJ/ gram
Stoichiometry!
Please note:
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
- Keep it to 1 decimal place.
Hey there!
C₃H₆O(l) + O₂(g) => CO₂(g) + H₂O(g)
First thing I want to do is balance the equation. Balance C:
C₃H₆O(l) + O₂(g) => 3CO₂(g) + H₂O(g)
Balance H:
C₃H₆O(l) + O₂(g) => 3CO₂(g) + 3H₂O(g)
Balance O:
C₃H₆O(l) + 4O₂(g) => 3CO₂(g) + 3H₂O(g)
Now we can properly solve the problem.
a.)
Density of acetone is 0.800 g/mL, we need to form 67.2 L of CO₂ at STP.
For every one mole of acetone reacted, 3 moles of CO₂ is produced.
Let's convert 67.2 L to moles: At STP, one mole of a gas takes up 22.4 liters.
67.2 ÷ 22.4 = 3 moles
So turns out we want to produce 3 moles of CO₂, which means we need one mole of acetone.
The molar mass of acetone is 58.08 g/mol. The density of acetone is 0.800 g/mL. We need the volume of one mole.
58.08 ÷ 0.800 = 72.6
72.6 mL of acetone is needed.
b.)
For every one molecule of acetone reacted, 3 molecules of water is produced.
We are combusting 3.011 x 10²² molecules of acetone.
3.011 x 10²² x 3 = 9.033 x 10²²
Find the number of moles:
(9.033 x 10²²) ÷ (6.022 x 10²³) = 0.15 moles
The molar mass of water is 18.015 g/mol.
0.15 x 18.015 = 2.7 grams
2.7 grams of water vapor is formed.
Hope this helps!
An ionic precipitation reaction takes place when aqueous solutions of potassium phosphate and aluminum nitrate are combined in a beaker.
K3PO4(aq) + Al(NO3)3(aq) →
i. Predict the products and write a balanced chemical equation for the reaction,
including state symbols.
K3PO4(aq) + Al(NO3)3(aq) →
ii. Write the complete balanced ionic equation, including state symbols.
iii. Write the complete balanced net ionic equation, including state symbols.
Answer:
I hope you can get a good answer
Explanation:
What class is this for?
how do scientist determine weather a cell from cancerous tissue is a cancer stem cell
Answer:
Researchers take samples of tumors removed from patients during surgery, always with the patient's informed consent. The cells within the tumor are then sorted based on their expression of certain cell markers on their surface.
Explanation:
The middle ear converts sound from what into vibrations that can be sent through what?
Answer:
The vibrations are then passed to 3 tiny bones in the middle ear called the ossicles. The ossicles amplify the sound. They send the sound waves to the inner ear and into the fluid-filled hearing organ (cochlea). Once the sound waves reach the inner ear, they are converted into electrical impulses.
Consider the equation for the combined gas law. If T1, and T2, are constant, you are left with whose
law?
Answer:
Boyels law
Explanation:
The general gas equation is p1v1/T1=p2v2/T2 and T1 and T2 are constant so all that is left is p1v2=p2v2
If temperatures T₁ and T₂ are constant in the combined gas law, the remaining relationship is Boyle's Law, defined as P₁V₁ = P₂V₂.
When we consider the equation for the combined gas law and keep the temperatures T₁ and T₂ constant, we are left with Boyle's Law. Boyle's Law states that the pressure of a gas varies inversely with its volume when temperature is held constant.
This can be represented mathematically as P₁V₁ = P₂V₂, assuming the number of moles (n) and the temperature (T) are constant. This law is named after the English scientist Robert Boyle who first described it in 1662.
A scientist is comparing two cells.
One cell, cell A, is from a unicellular organism, and the other cell, cell B, is from a multicellular organism.
What functional differences will the scientist most likely see when comparing the two cells?
A. Cell A performs all of the organism's necessary functions, while cell B only performs one or a few functions.
B. Cell A is very large and has many organelles, while cell B is very small and has only a few organelles
C. Cell A performs only one or a few functions, while cell B performs all of the organism's necessary functions.
D. Cell A is very small and has only a few organelles, while cell B is large and has many organelles
Answer: Cell A performs all of the organism's necessary functions, while cell B performs only one or a few functions.