Answer:
A. case studies, because it's one of the 5 groups that are part of the qualitative methods
What variable is represented on the y-axis?
Question 1 options:
Position
Velocity
Distance
Time
Question 2 (Mandatory) (1 point)
What variable is represented on the x-axis?
Question 2 options:
Distance
Time
Position
Velocity
Question 3 (Mandatory) (1 point)
What variable is the dependent variable?
Question 3 options:
Velocity
Position
Distance
Time
Question 4 (Mandatory) (1 point)
What variable is the independent variable?
Question 4 options:
Position
Time
Velocity
Distance
Question 5 (Mandatory) (1 point)
What is the starting position of the object in the graph?
Question 5 options:
The object starts at position 0 at time 0.
The object starts south of position 0 at time 0.
The object starts slightly north of position 0 at time 0.
The object starts far north of position 0 at time 0
Question 6 (Mandatory) (1 point)
What is the direction of motion of the object in the graph?
Question 6 options:
The object moves in a northward direction away from the starting position.
The object moves in a positive direction away from position 0.
The object moves in a southward direction toward position 0.
The object moves in a northeast direction away from the starting position.
Question 7 (Mandatory) (1 point)
What is the type of motion and the relative speed of the object in the graph?
Question 7 options:
At first, the object is not moving. Then, the object begins to gain speed.
First the object begins slowing down at a slow rate. Then, the object begins slowing down at a fast rate.
First the object is moving at a slow and constant speed. Then, the object begins moving at a fast and constant speed.
First, the object is speeding up at a slow rate. Then, the object beings speeding up at a fast rate.
Question 8 (Mandatory) (1 point)
What is the starting position of the object in the graph?
Question 8 options:
The object starts far north of position 0 at time 0.
The object starts south of position 0 at time 0.
The object starts at position 0 at time 0.
The object starts slightly north of position 0 at time 0.
Question 9 (Mandatory) (1 point)
What is the direction of motion of the object in the graph?
Question 9 options:
At first, the object is not moving, then the object begins moving in a southward direction toward position 0. Finally, the object is not moving, again.
At first, the object is moving toward the right, then the object begins moving in a northward direction away from position 0. Finally, the object begins moving toward the right, again.
At first, the object is not moving, then the object begins moving in a negative direction toward position 0. Finally, the object is not moving again.
At first, the object is moving in an eastward direction, then the object begins moving southward toward position 0. Finally, the object begins moving in an eastward direction, again.
Question 10 (Mandatory) (1 point)
What is the type of motion and relative speed of the object in the graph?
Question 10 options:
At first, the object is moving at a slow and constant speed. Then, the object begins moving at a fast and constant speed. Finally, the object moves at a slow and constant speed, again.
At first, the object is moving at a constant speed. Then, the object begins gaining speed. Finally, the object is moving at a constant speed, again.
At first, the object is not moving. Then, the object begins moving at a fast and constant. Finally, the object is not moving again.
At first, the object is moving at a constant speed. Then, the object begins slowing down. Finally, the object begins moving at a constant speed, again.
Question 11 (Mandatory) (4 points)
Compare and contrast a scalar quantity and a vector quantity. Match each description to the correct term.
Question 11 options:
Speed
Has magnitude and direction
Velocity
Has magnitude only.
1.
Scalar Quantity
2.
Vector Quantity
Question 12 (Mandatory) (6 points)
Compare and contract speed and velocity. Match each description to the correct term.
Question 12 options:
The rate at which an object changes its position with respect to time
Equation: Change in position / elapsed time
The slope of a Position vs. Time graph
Equation: Distance traveled / elapsed time
A measure of how fast an object travels
The slope of a Distance vs. Time graph
1.
Speed
2.
Velocity
Question 13 (Mandatory) (2 points)
An object travels with a speed of 30 meters in 10 seconds. If average speed is calculated using the equation, "distance traveled / elapsed time," what is the speed of the object?
Question 13 options:
3 speed
3 seconds
3 meters per second
3 meters
Distance/ Time which means Distance is on horizontal and time is on vertical
If Galileo's experiment did not measure the speed of light, what did it measure?
the speed of light using large distances
man's reaction time
actual speed of light in the air
the speed of light over a short distance
If Galileo's experiment did not measure the speed of light, it measures man's reaction time.
Option B
Explanation:
Galileo was very keen to find out speed of light, however there were some obstacles which he was facing. Before going ahead, let us understand his experiment.He asked his assistant to stand 3 miles away in night, and light a lantern, and both receded time - when assistant started lantern, and when Galileo saw the lantern light up. However, the timing was same. They tried with 6 miles. Again same timings. Let us look at obstacles. First was as the speed is very high, the calculations were sensitive in micro and Nano units. Considering that he need to maintain the accuracy of even micro and Nano seconds, he have to take account in man's reaction time. As there is some time gap in receiving the signal, and processing by brain, and then transmitting the signal to react accordingly, which is known as reaction time. So if he is able to add/subtract reaction time.Answer:
Galileo's experiment measured mans reaction time.
Explanation:
An idea that is supported by some evidence, but is not yet the basis for a field of study is called a
An idea that is supported by some evidence, but is not yet the basis for a field of study is called a working theories.
Explanation:
The combined form of one’s skills, the work experiences from testing to reveal some truth about the issues or being involved one’s work in an experiment usually called as working theory.
These type of theories are more elaborate, interconnected, make some experiences with the solution to sort out the issues and seems to be useful in event monitoring. These can be supported with certain evidences but still not acting as the basement for the field study.
Final answer:
A hypothesis based on evidence that requires further investigation and testing before becoming a field of study.
Explanation:
A hypothesis is a suggested explanation based on evidence that can be tested through observation or experimentation. This idea is supported by some evidence but is not yet the basis for a field of study. Multiple strands of evidence are needed to potentially develop a verified theory.
All of the following would be questions that could be scientifically investigated except:
Answer:
"What is the best advice a parent can give a child?"
Explanation:
The other answers have one clear response. Ex: Orange popsicles melt faster than grape popsicles. That would be a fact.
But parental advice can vary, depending on your opinion. I may say that all parents must teach their children not to talk to strangers, while someone else may say that parents should advice their kids to treat everyone fairly. Nothing can be proven as the only appropriate response.
Hope this helps!
The resistance of several materials are shown in the table. Based on this, which material has the best conductivity? Material Resistance (ohms) Aluminum 0.0000000282 Carbon (Graphite) 0.000035 Germanium 0.46 Silicon 640
A. aluminum
B.Carbon (Graphite)
C.Germanium
D.Silicon
Answer:
it is A aluminum
Explanation:
Answer:
Aluminium has best conductivity
So option (a) will be correct answer
Explanation:
We have given material resistance of of different material
Aluminium = 0.0000000282 ohm
Carbon = 0.000035
Germanium = 0.46 ohm
And silicon = 640 ohm
We know that resistance is the opposition in flow of current and conductivity of the material is inversely proportional to the resistance
So the material which has less Resistance will have high conductivity
As aluminium has less resistance so it will have high conductivity
So option (a) will be correct answer
If angle between two plane mirrors is 120 degrees then how many images were formed
Explanation:
The number of images formed by a pair mirrors kept at an angle [tex]\alpha[/tex] is
[tex]n=\frac{360}{\alpha } -1[/tex] if [tex]\frac{360}{\alpha }[/tex] comes even.
[tex]n=\frac{360}{\alpha }[/tex] if [tex]\frac{360}{\alpha }[/tex] comes odd.
where [tex]n[/tex] is the number of images formed.
In our question,
[tex]\alpha =120^{0}[/tex]
[tex]\frac{360}{\alpha } =\frac{360}{120}=3[/tex]
It is odd,so [tex]n=\frac{360}{120}=3[/tex]
A 0.614mole sample of ideal gas at 12degree occupies a volume of 4.32.what is the pressure of the gas
Answer:
336.9520 atm
Explanation:
The Gas Equation is as follows;-
Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)
Given Parameters
Number of moles-0.614 mol
Temperature 12°C or 12+273.15 ie 285.15°F
Volume-4.32 L
Universal Gas Constant-8.314 J/mol·K
Pressure -?(in atm)
Plugging in all the values in the Gas Equation:-
Pressure=[tex]\frac{0.614 × 8.314× 285.15}{4.32} atm[/tex]
Pressure=336.9520 atm
Robert lifts a 150-newton bucket of water 0.5 meters in 3 seconds. What is the amount of work done on the
bucket?
a. 25 joules
b. 25 watts
c. 75 joules
d. 75 watts
Answer:
c. 75 joules
Explanation:
Work done(joules)=Force(newton)×Distance(meters)
Given: force=150-newton, Distance=0.5 meters
∴Work done=150×0.5=75 joules.
The amount of work done on the bucket will be 75 joules. Option C is correct.
What is work done?Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.
The given data in the problem is;
F is the force lift = 150-
d is the displacement = 0.5 meters
t is the time = 3 second
W is the amount of work done
The amount of work done on the bucket is found as;
[tex]\rm W = F \times d \\\\ W = 150 \times 0.5 \\\\ W=75 \ Joule[/tex]
Hence the amount of work done on the bucket will be 75 joules. Option C is correct.
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A bowling ball of mass 9 kg moves in a straight
line at 3.28 m/s.
How fast must a Ping-Pong ball of mass
3.638 g move in a straight line so that the two
balls have the same momentum?
Answer in units of m/s.
The velocity of the ping-pong ball must be 8109 m/s
Explanation:
The momentum of an object is given by
[tex]p=mv[/tex]
where
m is the mass of the object
v is its velocity
For the bowling ball, we have
m = 9 kg
v = 3.28 m/s
so its momentum is
[tex]p=(9)(3.28)=29.5 kg m/s[/tex]
We want the ping-pong ball to have the same momentum, so:
p' = 29.5 kg m/s
And the mass of the ping-pong ball is
m = 3.638 g = [tex]3.638\cdot 10^{-3} kg[/tex]
Therefore, its velocity must be:
[tex]v=\frac{p}{m}=\frac{29.5}{3.638\cdot 10^{-3}}=8109 m/s[/tex]
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The velocity of the Ping-Pong ball can be found by setting the momentum of the bowling ball equal to the momentum of the Ping-Pong ball and solving for its velocity. Using the given masses and velocities, we can calculate the velocity of the Ping-Pong ball in m/s.
Explanation:In order for two balls to have the same momentum, the momentum of the bowling ball must be equal to the momentum of the Ping-Pong ball. The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, to find the velocity of the Ping-Pong ball, we can use the equation: momentum of bowling ball = momentum of Ping-Pong ball.
Given: mass of bowling ball = 9 kg, velocity of bowling ball = 3.28 m/s, mass of Ping-Pong ball = 3.638 g = 0.003638 kg (convert g to kg)
Momentum of bowling ball = mass of bowling ball × velocity of bowling ball
Momentum of Ping-Pong ball = mass of Ping-Pong ball × velocity of Ping-Pong ball
Setting the two momentum equations equal to each other, we can solve for the velocity of the Ping-Pong ball:
(9 kg) × (3.28 m/s) = (0.003638 kg) × (velocity of Ping-Pong ball)
Dividing both sides of the equation by 0.003638 kg will give us the velocity of the Ping-Pong ball:
velocity of Ping-Pong ball = (9 kg × 3.28 m/s) / 0.003638 kg
Calculating this expression will give us the velocity of the Ping-Pong ball in m/s.
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Block mountains are caused by faults in the crust, where rocks can move past each other in a rift and rise. The uplifted blocks become block mountains (also known as horsts) while the intervening dropped blocks are known as graben (i.e. depressed regions). Which mountain range is formed this way
Answer : A, The Sierra Nevada mountain range of western North America, running along the eastern edge of the U.S. state of California.
Answer:
"The Sierra Nevada mountain range of western North America, running along the eastern edge of the U.S. state of California."
Explanation:
Block Mountains:
Due, to stress created in side the crust of the earth the blocks or pieces of land or mass of land is created. In the past due to natural disaster and events that occurred in the ancient world, left us with some natural phenomenons called as block mountains. As the natural forces like seismic waves and other volcanic eruptions leads to such a disastrous amount of force that uplifts the mass of land on which it is acted upon.
Characteristics of the Block Mountains:
The Block mountain have very sharp and jagged peaks.Types:
There are two main types of the block mountains,which are as below:
Lifted Mountain: Those mountains which are characterized by having two steps, as they are created by ancient and disastrous faults inside the earth crust. Tilted Mountains: These mountains or ranges are basically characterized by having a gentle slope at one side while also having a steep side on its other face.The tendency of a physical object to remain still or continue moving, unless a force is applied is called
Consider this situation: A baseball player dives head-first into second base and slows down while sliding on the infield dirt.
Of the forces listed, identify which act upon the player.can be more then one answer
a. Normal Force
b. Gravity Force
c. Applied Force
d. Friction Force
e. Tension Force
f. Air Resistance Force
The forces that act upon a baseball player diving head-first into second base and sliding on the infield dirt are the Normal Force, Gravity Force, and Friction Force.
Explanation:When a baseball player dives head-first into second base and slows down while sliding on the infield dirt, several forces act upon the player. These forces include:
Normal Force: The ground exerts an upward force on the player, preventing them from sinking into the ground.Gravity Force: The force that pulls the player downward towards the center of the Earth.Friction Force: The force between the player and the infield dirt that opposes their motion and slows them down.Air Resistance Force: This force is negligible in this situation because the player is sliding on the ground.Therefore, the correct answers would be a. Normal Force, b. Gravity Force, d. Friction Force.
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A particle is moving in a straight line.at t second, it acceleration is (4-kt), where k is a constant. when t=6, the acceleration of a particle is zero determine its velocity as a function of time
Answer:
v = 4t - t²/3
Explanation:
4 - k*6 = 0
k = 4/6 = 2/3
dv/dt = 4- 2/3 t
integral of dv = integral of (4-2/3 t) dt
v = 4t - t²/3
A nucleus in a transition from an excited state emits a gamma-ray photon with an energy of 2.5 MeV. (a)
What is the photon frequency? (b) What is the photon wavelength? (c) How does the wavelength compare
with typical nuclear radii (of the order 10−15 m)?
a) The frequency of the photon is [tex]7.16\cdot 10^{20}Hz[/tex]
b) The wavelength of the photon is [tex]4.19\cdot 10^{-13} m[/tex]
c) The wavelength of the photon is about 100 times larger than the nuclear radius
Explanation:
a)
The energy of a photon is given by
[tex]E=hf[/tex] (1)
where:
[tex]h=6.63\cdot 10^{-34} Js[/tex] is the Planck constant
f is the frequency of the photon
The photon in this problem has an energy of
[tex]E=2.5 MeV = 2.5\cdot 10^6 eV[/tex]
And keeping in mind that
[tex]1eV = 1.6\cdot 10^{-19} J[/tex]
we can convert to Joules:
[tex]E=(2.5\cdot 10^6)(1.9\cdot 10^{-19})=4.75\cdot 10^{-13} J[/tex]
And now we can use eq.(1) to find the frequency of the photon:
[tex]f=\frac{E}{h}=\frac{4.75\cdot 10^{-13}}{6.63\cdot 10^{-34}}=7.16\cdot 10^{20}Hz[/tex]
b)
The wavelength of a photon is related to its frequency by the equation
[tex]c=f\lambda[/tex]
where
[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light
f is the frequency
[tex]\lambda[/tex] is the wavelength
For the photon in this problem,
[tex]f=7.16\cdot 10^{20}Hz[/tex]
Re-arranging the equation, we find its wavelength:
[tex]\lambda=\frac{c}{f}=\frac{3\cdot 10^8}{7.16\cdot 10^{20}}=4.19\cdot 10^{-13} m[/tex]
c)
The size of the nuclear radius is approximately
[tex]d \sim 10^{-15} m[/tex]
While we see that the wavelength of this photon is
[tex]\lambda=4.19\cdot 10^{-13} m[/tex]
Therefore, the ratio between the wavelength of the photon and the nuclear radius is
[tex]\frac{\lambda}{d}=\frac{\sim 10^{-13}}{\sim \cdot 10^{-15}}=100[/tex]
So, the wavelength of the photon is approximately a factor 100 times larger than the nuclear radius.
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Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speec
up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
m/s2
Answer:
The acceleration of the train is 5 m/s².
Explanation:
Given:
let the initial velocity of a train = 5 m/s and
final velocity of a train = 45 m/s
time taken = 8 s
To find:
acceleration: ?
Solution:
We define acceleration as change in velocity per unit time that is the difference between the final velocity and initial velocity divided by time.
[tex]Acceleration = \frac{\textrm{final velocity} - \textrm{initial velocity}}{time} \\[/tex]
On substituting the above values we get the required acceleration
[tex]Acceleration = \frac{45 - 5}{8}\\ =\frac{40}{8}\\ =5\ m/s^{2}[/tex]
Therefore,the acceleration of the train is 5 m/s².
A mass of 5kg accelerates at 3m/s/s, how much force was put on it?
Answer:
15N
Explanation:
According to Newton's Second Law of Motion
F = m*a
mass = m = 5Kg
acceleration = a = 3m/s^2
=> F = 5kg * 3m/s^2
=> F = 15 N
F = m a
The force is (5kg)x(3 m/s^2)= 15 Newtons, and it's still there.
If the force stops, the acceleration stops.
Would anybody be able to help me complete this sentence?
Thanks
Answer:
x-axis
Explanation:
when it is at rest, horizontal, on a graph it is the x-axis.
Hope this helped!
A car is moving with a constant velocity of 25 m/s. Which of the following is true?
a) the force from the engine is greater than all the forces of friction.
b) the net force on the car is zero.
c) the inertia is changing.
d) the forces of friction are proportional to the acceleration of the car.
e) All of the above.
b) the net force on the car is zero.
Explanation:
Let's analyze each option one by one:
a) the force from the engine is greater than all the forces of friction. --> FALSE. In fact, the car is moving at constant velocity: this means that its acceleration is zero,
a = 0
and so Newton's second law becomes
[tex]\sum F = ma = 0[/tex]
where [tex]\sum F[/tex] is the net force on the car and m is its mass. This means that the net force on the car is zero: so, the force from the engine cannot be greater than all the forces of friction, otherwise the net force cannot be zero.
b) the net force on the car is zero. --> TRUE, for what we said at point A)
c) the inertia is changing. --> FALSE. The inertia of an object just depend on the mass and the velocity of the object: as neither the mass nor the velocity are changing in this problem, then the inertia of the car is not changing.
d) the forces of friction are proportional to the acceleration of the car. --> FALSE. Generally, the force of friction acting on an object moving on a flat surface is
[tex]F_f = \mu mg[/tex]
where [tex]\mu[/tex] is the coefficient of friction, m is the mass, and g the acceleration of gravity. Therefore, the force of friction does not depend on the acceleration of the car.
e) All of the above. --> FALSE
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Find the velocity of a turtle who swims 100 meters toward the shore in 25 seconds
Answer:
The speed of a turtle is 4m/s
Explanation:
speed = distance/time
distance = 100m
time = 25s
s = 100/25
= 4m/s
Answer: 20m/s
Explanation:
Data;
Distance (s) = 100m
Time (t) = 25s
Velocity (v) = s/t
v = 100/25
v = 20m/s
A 17.5 kg block is dragged over a rough, horizontal surface by a constant force of 88.2 N
acting at an angle of 26.9*
above the horizontal. The block is displaced 44 m, and the
coefficient of kinetic friction is 0.168.Find the work done by the 88.2 N force.
The acceleration of gravity is 9.8 m/s
2.
Answer in units of J
Find the magnitude of the work done by the
force of friction.
Answer in units of J.
Answer:
Part 1.: Work done by the force is 3461 J
Part 2: Work done by the force of friction is 972.8 J
Explanation:
part 1.
Since the displacement is horizontal, the only component of the 88.2 N force applied on the block is the horizontal component (which carries the cos(26.9) (the cosine of the angle with the horizontal). Then the component of the force acting on the 44 m displacement is: 88.2 * cos(26.9) . Then the work done by this component can be found by multiplying this quantity times the displacement (44 m), which gives:
88.2 * cos (26.9) * 44 = 3460.8878 J
which we can round to the nearest whole number as: 3461 J
Part 2.
The force of kinetic friction is the product of the normal force exerted by the surface on the block, times the coefficient of kinetic friction. Now the surface reacts with the normal force opposing the net vertical force applied by the block on the surface. Notice that in this case, the normal force doesn't just oppose the weight (m * g) of the object, since there is a vertical component of the external 88.2 N force ( the one that uses the sin(26.9) ) that is acting opposite to the gravitational force. This pointing upwards force component is going to subtract from the weight, thus making the normal force smaller than what it would be if just the object's weight was acting vertically. In magnitude, this is the normal force calculation:
Normal = Weight - 88.2 * sin(26.9)
Normal = [17.5 * 9.8 - 88.2 * sin(26.9) ] N
Normal = 131.6 N
At this point, we can calculate the value of the force of kinetic friction (product between the normal force and the coefficient of kinetic friction):
Kinetic friction force: 0.168 * 131.6 N = 22.1088 N
Now the product of this force times the displacement will give us the magnitude of the work done by the force of friction:
22.1088 N * 44 m = 972.7872 J
that we can round to 972.8 J
It is important to notice that the work done by the force of friction is negative due to the fact that the force acts opposite to the displacement of the block.
how does a metal leaf electroscope work
Answer: An electroscope is a device that detects static electricity by using thin metal or plastic leaves, which separate when charged. ... Electrical charges move to the metal and down to the foil leaves, which then repel each other. Since each leaf has the same charge (positive or negative), they repel each other.
Answer:
An object with a suspected static electric charge is brought near the metal plate or ball of the electroscope. Electrical charges move to the metal and down to the foil leaves, which then repel each other. Since each leaf has the same charge (positive or negative), they repel each other.
A baseball has a mass of 0.45 kg and is thrown with a speed of 25 m/s. What is the momentum of the baseball?
0.018 kg • meters squared per second
11 kg • meters per second
56 kg • meters per second
140 kg • meters per second
Answer:
The second option: 11 kg * m/s
Explanation:
Recall that linear momentum is defined as the product of the mass times its velocity, therefore in this case, the mass is 0.45 kg , and the speed is 25 m/s, therefore the linear momentum is:
P = m * v = 0.45 Kg * 25 m/s = 11.25 kg * m/s
So roundng the answer to the nearest whole number, you get 11 kg * m/s, which is the second option they give you.
Answer:
11 kg • meters per second
Explanation:
If a car is traveling at an average speed of 60 kilometers per hour how long does it take to travel 12 kilometers
Answer:
The time taken to travel is, t = 12 minutes
Explanation:
Given data,
The speed of the car, v = 60 km/h
The distance of travel, d = 12 km
The time taken for the travel is t = ?
The speed is defined as the distance divided by the time taken to travel. The formula for speed is,
v = d/t
∴ t = d/v
t = 12 km / 60 km/h
t = 0.2 h
t = 12 minutes
Hence, the time taken to travel is, t = 12 minutes.
Given that the average speed of the car is 60 km/hr and it needs to travel a distance of 12 km, it will take the car around 0.2 hours, which is equivalent to 12 minutes, to travel this distance.
Explanation:This problem is related to the concept of speed, which in physics, is the distance covered per unit time. Here, we are asked to find the time so, we will use the formula for calculating time which is Time = Distance / Speed.
Given:
Average speed of the car = 60 km/hrDistance to be covered = 12 kmSo, time needed can be calculated as:
Time = Distance / Speed
Time = 12 km / 60 km/hr
This gives Time = 0.2 hr.
But as we generally count time in minutes, we can convert hours into minutes. Since 1 hour = 60 minutes, therefore, 0.2 hr = 0.2 x 60 = 12 minutes.
So, it takes 12 minutes to travel 12 kilometers with an average speed of 60 kilometers per hour.
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How does energy change (transforms) as the mass is dropping?
Answer:
Mass has total mechanical energy, which is the sum of kinetic and potential energy. as the mass is dropping, potential energy is converted into kinetic energy so mechanical energy is preserved If there is no friction. If there is friction, some of the mechanical energy is lost as heat energy so it changes.
Explanation:
150c passes through cell in 30 seconds. cell has a potential difference of 12v. what is current in the circuit
The current in the circuit is 5 A
Explanation:
The intensity of current is given by the equation:
[tex]I=\frac{q}{t}[/tex]
where
I is the current
q is the amount of charge passing through a given point of the circuit in a time interval of t
For the cell in this problem, we have
q = 150 C is the charge
t = 30 s is the time interval
Substituting into the equation, we f ind
[tex]I=\frac{150}{30}=5 A[/tex]
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what is not a component of skill related fitness
Answer:
flexibility
Explanation:
2) What are the directions of the velocity and acceleration of an object in
uniform circular motion?
if you push a 4-kg mass...
Answer:
B
Explanation:
F = ma , a = F/m
a1 = F/10 and a2 = F/4
Since Force is constant, a2 will we greater than a1
A racing car’s velocity is increased from 44 m/s to 66 m/s in 11 seconds. What is the acceleration? and what is the displacement?
The acceleration of the racing car is 2 m/s² and the displacement over the 11 seconds is 605 m.
Explanation:The given physics problem involves calculating the acceleration and the displacement of a racing car that has increased its velocity from 44 m/s to 66 m/s in a time interval of 11 seconds.
To find the acceleration, we use the formula for average acceleration, which is the change in velocity divided by the time taken. The change in velocity (Δv) is 66 m/s - 44 m/s = 22 m/s. So, the acceleration (a) is 22 m/s divided by 11 s, which equals 2 m/s².
For the displacement, we can use the kinematic equation s = ut + 0.5at², where u is the initial velocity, a is the acceleration, and t is the time. With u = 44 m/s, a = 2 m/s², and t = 11 s, we get the displacement s = 44 m/s * 11 s + 0.5 * 2 m/s² * (11 s)², resulting in 484 m + 121 m, or a total displacement of 605 m.
The acceleration of the racing car is [tex]\( 2 \text{ m/s}^2} \)[/tex] and the displacement of the racing car during this time is [tex]\( 605 \text{ m}} \)[/tex].
To find the acceleration and displacement of the racing car, we will use the following kinematic equations:
1. Acceleration [tex](\(a\))[/tex]:
[tex]\[ a = \frac{\Delta v}{\Delta t} \][/tex]
2. Displacement [tex](\(s\))[/tex]:
[tex]\[ s = v_i t + \frac{1}{2} a t^2 \][/tex]
Step 1: Calculate the Acceleration
Given:
Initial velocity [tex](\(v_i\))[/tex]: 44 m/s
Final velocity [tex](\(v_f\))[/tex]: 66 m/s
Time interval [tex](\(\Delta t\))[/tex]: 11 s
The change in velocity [tex](\(\Delta v\))[/tex] is:
[tex]\[ \Delta v = v_f - v_i = 66 \text{ m/s} - 44 \text{ m/s} = 22 \text{ m/s} \][/tex]
Using the acceleration formula:
[tex]\[ a = \frac{\Delta v}{\Delta t} = \frac{22 \text{ m/s}}{11 \text{ s}} = 2 \text{ m/s}^2 \][/tex]
Step 2: Calculate the Displacement
Using the kinematic equation for displacement:
[tex]\[ s = v_i t + \frac{1}{2} a t^2 \][/tex]
Given:
Initial velocity [tex](\(v_i\))[/tex]: 44 m/s
Time [tex](\(t\))[/tex]: 11 s
Acceleration [tex](\(a\))[/tex]: [tex]2 m/s^2[/tex]
Substitute the values into the equation:
[tex]\[ s = 44 \text{ m/s} \times 11 \text{ s} + \frac{1}{2} \times 2 \text{ m/s}^2 \times (11 \text{ s})^2 \][/tex]
[tex]\[ s = 484 \text{ m} + \frac{1}{2} \times 2 \text{ m/s}^2 \times 121 \text{ s}^2 \][/tex]
[tex]\[ s = 484 \text{ m} + 1 \times 121 \text{ m} \][/tex]
[tex]\[ s = 484 \text{ m} + 121 \text{ m} \][/tex]
[tex]\[ s = 605 \text{ m} \][/tex]
The temperature of the liquid in a container decreases as the liquid evaporates. Use kinetic theory to explain why.
Answer:
Temperature decreases because the number of collision of the molecules decreases as they escape or evaporate. Molecules are in constant motion. Increase in temperature leads to increase in average kinetic energy of the molecules.
The kinetic theory of matter states that all matter is made up of tiny particles that are constantly moving. The faster the particles are moving, the higher the temperature of the matter.
Why is The temperature of the liquid in a container decreases as the liquid evaporates?When a liquid evaporates, the fastest-moving particles are the ones that are most likely to escape from the surface of the liquid. This leaves behind the slower-moving particles, which means that the average temperature of the liquid decreases.
Another way to think about it is that evaporation is a cooling process because it removes the fastest-moving particles from the liquid. These particles have the most kinetic energy, so their removal lowers the average kinetic energy of the remaining particles and thus lowers the temperature of the liquid.
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