Calcium carbonate can break down to form calcium oxide and carbon dioxide. CaCO3 → CaO + CO2 The oxygen atoms on the product side are

Answers

Answer 1
balanced because the total number of oxygen atoms is 3.
Answer 2

Answer: the answer is C balanced because the total number of oxygen atoms is 3.

Explanation: I know this cause I did the assignment and got it correct.


Related Questions

The weight of an ice sheet can cause continental lithosphere to sink into the underlying asthenosphere due to ____.

Answers

Answer: Isostatic rebound

The weight of an ice sheet imposed on lithosphere in the continental block will cause the continent to sink in the asthenosphere due to isostatic rebound. The thickness of the ice sheet change with time as the sea level rise and the sinking of the lithosphere will continue until isostatic equilibrium is reached.

 

Challenge: a sound wave with a frequency of 100.0 Hz travels in water with a speed of 1,500 m/s and then travels in air with a speed of 340 m/s. Approximately how many times larger is the wavelength in water than in air?

Answers

Final answer:

The wavelength in water is approximately 4.41 times larger than the wavelength in air.

Explanation:

In order to calculate the ratio of the wavelengths in water and in air, we need to use the formula:

ratio = speed of sound in water / speed of sound in air

Given that the speed of sound in water is 1500 m/s and the speed of sound in air is 340 m/s, we can substitute these values into the formula: ratio = 1500 m/s / 340 m/s = 4.41

Therefore, the wavelength in water is approximately 4.41 times larger than the wavelength in air.

The wavelength in water is approximately 4.4 times larger than in air.

To find the wavelength of a sound wave in a given medium, one can use the formula:

[tex]\[ \lambda = \frac{v}{f} \][/tex]

where [tex]\( \lambda \)[/tex] is the wavelength, [tex]\( v \)[/tex] is the speed of sound in the medium, and [tex]\( f \)[/tex] is the frequency of the sound wave.

Given that the frequency [tex]\( f \)[/tex] of the sound wave is 100.0 Hz, we can calculate the wavelength in water and in air using their respective speeds.

First, calculate the wavelength in water:

[tex]\[ \lambda_{\text{water}} = \frac{v_{\text{water}}}{f} = \frac{1,500 \text{ m/s}}{100.0 \text{ Hz}} = 15 \text{ m} \][/tex]

Next, calculate the wavelength in air:

[tex]\[ \lambda_{\text{air}} = \frac{v_{\text{air}}}{f} = \frac{340 \text{ m/s}}{100.0 \text{ Hz}} = 3.4 \text{ m} \][/tex]

To find out how many times larger the wavelength in water is compared to the wavelength in air, we divide the wavelength in water by the wavelength in air:

[tex]\[ \text{Ratio} = \frac{\lambda_{\text{water}}}{\lambda_{\text{air}}} = \frac{15 \text{ m}}{3.4 \text{ m}} \approx 4.4 \][/tex]

An oil storage tank ruptures at time t = 0 and oil leaks from the tank at a rate of r(t) = 105e−0.04t liters per minute. how much oil leaks out during the first hour? (round your answer to the nearest liter.)

Answers

65 liters of oil leaks out during the first hour.

What is Oil leaks?

When the oil filter gradually becomes looser or the oil gasket is improperly tightened, car or engine oil leaks happen.

These are also known as oil filter leaks, and generally speaking, the filter gasket should be tightened in accordance with the manufacturer's instructions.

Sometimes, a gasket and bolts are used to secure an external oil pump to the engine block. These parts are prone to wear and leakage. Lack of oil in the oil pump can result in severe damage, including early wear of the pump and oil starvation of the engine.

Therefore, 65 liters of oil leaks out during the first hour.

To learn more about oil, refer to the link:

https://brainly.com/question/29530758

#SPJ5

A dry cleaner throws a 20 kg bag of laundry onto a stationary 8.3 kg cart. the cart and laundry bag begin moving at 2.6 m/s to the right. find the velocity of the laundry bag before the collision. answer in units of m/s. answer

Answers

The total momentum before and after the collision must be conserved.

- Let's start from the end: at this point, both cart and laundry bag are moving together, with a total mass of (m1+m2) and velocity 2.6 m/s. Therefore, the total momentum is
[tex]p_f = (m_1+m_2) v_f =(20 kg+8.3 kg)(2.6 m/s)=73.6 kg \cdot m/s[/tex]

- The momentum must be conserved, so the initial momentum must be equal to this value:
[tex]p_i = p_f = 73.6 kg \cdot m/s[/tex]

- At the beginning, the cart is stationary, so its momentum is zero. There is only one momentum, the one of the bag, which has a mass of 20 kg and unknwon velocity vi:
[tex]p_i = m_1 v_i[/tex]

- So, using the conservation of momentum we find
[tex]m_1 v_i = 73.6 kg \cdot m/s[/tex]
and from this, the initial velocity of the laundry bag:
[tex]v_i = \frac{p_f}{m_1}= \frac{73.6 kg \cdot m/s}{20 kg}=3.7 m/s [/tex]

Final answer:

Using the conservation of momentum, the velocity of the 20 kg laundry bag before the collision is calculated to be approximately 3.689 m/s to the right.

Explanation:

To find the velocity of the laundry bag before the collision, we can use the conservation of momentum, which states that the total momentum before an event is equal to the total momentum after the event, provided no external forces act on the system. Since the cart is initially stationary, its initial momentum is 0. After the bag is thrown onto the cart, both move together with a certain velocity, so the final momentum is the combined mass times the final velocity. We can set up the equation as follows:

Momentum before collision (p₁) = Momentum after collision (p₂)

Since the cart is stationary before the collision, this simplifies to:

Velocity of the bag before collision (v) × Mass of the bag [tex](m_{bag)[/tex] = (Mass of the bag [tex](m_{bag)[/tex] + Mass of the cart [tex](m_{cart)[/tex]) × Final velocity [tex](v_f)[/tex]

Inserting the given values, we get:

v × 20 kg = (20 kg + 8.3 kg) × 2.6 m/s

Now we solve for the velocity (v):

v = (28.3 kg × 2.6 m/s) / 20 kg

v = 3.689 m/s

Therefore, the velocity of the laundry bag before the collision was approximately 3.689 m/s to the right.

Compare rhyolite to basalt (answer in one word only):


a. which has a lower density?


b. which has a lighter color?


c. which has a more mafic composition?


d. which has a greater percentage of biotite in it?


e. which contains quartz? 13. name a felsic, intrusive rock. 14. name a light-colored, plutonic igneous rock.

Answers

Rhyolite is a fine-grained igneous rock which is rich in silica while basalt is a common extrusive igneous rock formed by the rapid cooling of basaltic lava exposed at or very near the surface of Earth.
The density of Basalt is higher than that of Rhyolite. Rhyolite has a density that ranges between 2.4-2.6 g/cm^3, while that of Basalt ranges from 2.9-3.1 g/cm^3.

b) Rhyolite is a Grey, white, light black rock, while Basalt is Black, Brown, Light to Dark Grey. Rhyolite appears to be banded while the apperance of Basalt is Dull and soft.

c) Basalt is more mafic; most mafic minerals are dark in color, and common rock-forming mafic minerals include olivine, Pyroxene, amphibole, and biotite. Common mafic rocks include basalt, diabase and gabbro. Mafic rocks often also contain calcium-rich varieties of plagioclase feldspar.

d) Rhyolite has a higher percentage of biotite. Rholite contains a higher percentange of sodium and potassium oxides which can reach up to 5%. Quartz, feldspar and biotite are the most common minerals found in rhyolite. In some cases , thick rhyolitic lavas will cool as glassy obsidian flows.

e) Rhyolite contains quartz. The chemical composition of rhyolite is similar to that of granite.  The phenocrysts or rhyolite may include quartz, alkali feldspar, oligoclase feldspar, biotite, amphibole, or pyroxene. 

13. I think it is plutonic rocks. Intrusive rocks that were formed deep in the earth's crust are called plutonic rocks and are generally coarse gained (minerals grains greater than 1 millimeter in diameter), large, and often associated with mountain building. Mafic felsic, and intermediate intrusive rocks.

14. Anorthosite. It is the light-colored plutonic rock composed mostly of feldspar, labradorite, with very little pyroxene. The felsic plutonic rocks usually have quartz, large proportions of potassium feldspar, and lesser amounts of plagioclase and mafic minerals. On the other hand, intermediate and mafic rocks have increasingly larger proportions of dark iron-rich minerals.
Answer A:

Rhyolite has a lower density

Average density of Rhyolite is 2.5 g/cm³ whereas the average density of basalt is 3 g/cm³ So we can say that Rhyolite is less denser.


Answer B:

Rhoylite is more lighter

Rhyolite is either pink or grey whereas basalt is usually grey or black so we can say that Rhyolite has lighter color

Answer C:

Basalt is more melfic

Rhyolite is usually considered as felsic, while basalt is mafic. Generally felsic rocks make the bulk of the continental plates, while mafic basalt forms the seafloor.

Answer D:

Basalt has more amount of biotite

Basalt has 5% biotite in it whereas Thyloite has very rare amount of biotite in it so we can say that greater amount of biotite is present in Basalt

Answer E:

Quartz in Rhyolite may be present in amounts of 25% to 30%. whereas basalt has 20% - 60% quartz amount in it.

Answer 13:

Granodiorite is an example of felsic intrusive rock.

Answer 14:

Name of a very hard plutonic, igneous rock is Granite.




An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus at the end of his out-stretched arm so that the discus reaches a velocity of 5.0 m/s. What is the centripetal force acting on the discus?

A.9.4 N
B.14 N
C.27 N
D.66 N

Answers

the centripetal force would be mv^2/r
which is then equal to 2*5*5/0.75
that's 66 N

Answer:

I am pretty sure the answer is "66N"

Explanation:

I've seen a lot of results on the internet saying the same thing

If this is not the answer, I am truly sorry and you can message me so that I can delete the question.

Have a good day!

Determine the Kinetic energy of a 1000 kg roller coaster car that is moving with speed of 20.0 m/s

Answers

Final answer:

The kinetic energy of a 1000 kg roller coaster car moving at a speed of 20.0 m/s is calculated using the formula KE = ½ mv², resulting in KE = 200,000 J or 2.00 × 10⁵ J.

Explanation:

The question requires us to calculate the kinetic energy of a 1000 kg roller coaster car that is moving with a speed of 20.0 m/s. The kinetic energy (KE) of an object can be found using the formula KE = ½ mv², where m is the mass of the object and v is its velocity. Inserting the given values into the formula, we get:

KE = ½ (1000 kg) (20.0 m/s)

KE = ½ (1000 kg) (400 m²/s²)

KE = (500 kg) (400 m²/s²)

KE = 200,000 J or 2.00 × 10⁵ J

The roller coaster car possesses 200,000 joules of kinetic energy at the given speed.

A shot hitting the birdie high and deep to the backcourt is called what

Answers

I think it would be "Clear"

Final answer:

In badminton, a shot that sends the birdie high and deep to the backcourt is called a clear. It's a defensive move to create more playing space and opportunities.

Explanation:

A shot in badminton that is hit high and deep into the opponent’s backcourt is known as a clear. This type of shot is a defensive move, intended to give the player hitting the clear more time to return to a ready position and to push the opponent to the rear of their court, potentially creating opportunities for future aggressive plays. The clear can be performed as either a forehand or backhand stroke depending on the player's position and the shuttlecock's trajectory.

19. Water that flows downhill along Earth's surface is called A. beach hydraulics. B. cycles. C. runoff. D. rain.

Answers

the answer is most likely C
Water that flows downhill along Earth's surface is called "Runoff". When water is left to 'run' 'off' the side of roads and other surfaces. So the answer is C.

Match the following vocabulary words with their definitions:

Question 1 options:

rate of change in velocity, which is the change in velocity divided by the change in time


the rate at which an object changes position when traveling in a certain direction


force of attraction between all masses in the universe


an object´s resistance to a change in motion


force of resistance acting between objects in contact and tending to dampen their motion


the rate at which an object changes position

1.
acceleration

2.
speed

3.
friction

4.
gravity

5.
inertia

6.
velocity

Save

Answers

Correct matching:


1 acceleration --> rate of change in velocity, which is the change in velocity divided by the change in time

2. speed --> the rate at which an object changes position when traveling in a certain direction

4. gravity --> force of attraction between all masses in the universe

5. Inertia --> an object´s resistance to a change in motion

3. friction --> force of resistance acting between objects in contact and tending to dampen their motion

6. velocity --> the rate at which an object changes position


You hop on the carousel horse. The attendant flips the switch and you move up and down, around and around. When the ride ends, the attendant again flips the switch. The up and down motion stops, as you continue to move in a circular motion, gradually slowing to a stop. Why? A) All the mechanical energy of the carousel is lost. B) All of the kinetic energy is converted to potential energy. C) The external energy source overcomes the internal energy of the carousel. D) Mechanical systems need an external energy source to maintain their

Answers

The correct answer is:
A) All the mechanical energy of the carousel is lost. 

In fact, all the mechanical energy of the carousel is lost because of the friction between the carousel and the ground. The carousel loses its energy little by little because of the friction, and it gradually slows down until it stops: all the initial energy of the carousel has been dissipated into thermal energy due to the friction between the carousel surface and the ground.

Answer:

D) Mechanical systems need an external energy source to maintain their

Explanation:

Mechanical systems need an external energy source to maintain their motion.

In this case, electrical energy is transformed to mechanical energy. Without electrical energy, the carousel slows due to friction and eventually stops.

An antique carousel that’s powered by a large electric motor undergoes constant angular acceleration from rest to full rotational speed in 5.00 seconds. When the ride ends, a brake causes it to decelerate steadily from full rotational speed to rest in 11.0 seconds. Compare the torque that starts the carousel to the torque that stops it. τstart/τstop = the tolerance is +/-2%

Answers

1) For a rotating object, we can write the analogous of Newton's second law as
[tex]\tau = I \alpha[/tex]
where [tex]\tau[/tex] is the torque applied to the object, I is the moment of inertia and [tex]\alpha [/tex] is the angular acceleration.

2) We can write the ratio between the starting torque and the stopping torque as:
[tex] \frac{\tau _{start}}{\tau _{stop}} = \frac{I \alpha _{start}}{I \alpha _{stop}} = \frac{ \alpha _{start}}{\alpha _{stop}} [/tex]

3) Then, we can rewrite the two angular accelerations. The general formula is
[tex]\alpha = \frac{\omega _f - \omega _i}{t} [/tex]
where [tex]\omega _f [/tex] and [tex]\omega _i[/tex] are the final and initial angular velocities, while t is the time. 

4) Let's start by calculating the starting acceleration. In this case, the initial velocity is zero, while the final velocity is the full rotational speed (let's call it [tex]\omega _{max}[/tex], and the time is t=5.0 s:
[tex]\alpha _{start} = \frac{\omega_{max}-0}{5 s}= \frac{\omega_{max}}{5 s}=[/tex]
When the carousel stops, instead, the initial velocity is [tex]\omega _{max}[/tex] while the final velocity is 0, and the time is t=11.0 s:
[tex]\alpha _{stop} = \frac{0-\omega _{max}}{11 s}= \frac{-\omega _{max}}{11 s} [/tex]
Therefore, if we replace the two angular accelerations that we found into the formula of the torque ration written at step 2), we find:
[tex] \frac{\tau _{start}}{\tau _{stop}} = - \frac{11}{5} [/tex]
where the negative sign simply means that the two torques have opposite direction. Therefore, the ratio between starting and stopping torque is 11:5.

if a cannon is fired from the front of a boat, the boat will drift backward. which on of Newton's laws best describes this motion?

Newton's second law of motion: force is equal to mass time acceleration

Newton's third law of motion: for every action, there is a equal and opposite reaction

Newton's first law of motion: an object in motion stays in motion unless acted on by another force

Answers

Newton's Third Law: For every action, there is an equal and opposite reaction. 

The cannon jumps back which pushes the boat backwards. 

what information does a free-body diagram show?

Answers

Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation. A free-body diagram is a special example of the vector diagrams

Answer:

All of the force vector acting on an object

Explanation:

That's what a free-body diagram does, and ayepecks

can someone help me with the physics problem?:

if you do 144 J of work to elevate a bucket of water, what is it’s final gravitational potential energy relative to its starting position?

Answers

The work you put into something is the energy it has afterward (neglecting friction and other so-called non-conservative forces).  This is called the work-energy theorem.  Think of objects in a gravitational field as "energy piggy banks".  If you put X joules of energy into it, that energy will be there as potential energy, stored for later.  So if you do 144J of work to elevate the bucket from an initial position, what ever it is initially, the final gravitational energy is 144J greater than before.



As the wave interacts with a wall, which kind of wave interaction is shown?


absorption

diffraction

refraction

reflection





































Answers

reflection thats the answer bois

Term Definition
Match the correct term to the right definition

Elliptical galaxy A) Forms a perfect sphere or an ellipse and is flattened to some degree

Irregular galaxy B) Has a large flattened core

Lens galaxy C) Does not have a distinct regular shape

Spiral galaxy D) Has a central core from which curved arms spiral outward

Answers

Elliptical galaxies are given a classification that corresponds to their elongation from a perfect circle, otherwise known as their ellipticity

Answer,

Elliptical Galaxy/ Forms a perfect sphere or an ellipse and is flattened to some degree

Irregular galaxy/Does not have a distinct regular shape

Lens galaxy/ Has a large flattened core

Spiral galaxy/ Has a central core from which curved arms spiral outward

I'm %500 sure this is correct :-)

Apply Newton's three laws of motion to everyday situations.

Answers

Hey there!

We'll start with the first law, the law of inertia, which states:

"an object in motion will stay in motion moving at the same speed in the same direction unless acted on by an outside force".

Let's imagine you're playing soccer with your friends. You kick the ball at them really hard, and they're the goalie. It goes in the same direction in  a straight line, and then they catch it - the unbalanced force. There's a change in motion there, and that change in motion depends on the inertia of an object- it's tendency to resist change in motion. Inertia even applies to planets. Wonder why out Earth's orbit is an ellipse? By natural standards of physics, the Earth goes straight when it's not pulled into orbit when here it is. It still has that tendency to go straight, but the Sun pulls it towards itself, creating a motion in which the Earth is trying to go straight, but the Sun's more powerful.

The second law is pretty much summarized by the famous equation f = ma. The law, summed up, states,

"The net force of an object is equal to the mass of the object times its acceleration."

If you tried to give a push to a small box with efficient wheels, it'd go pretty far. This is because it has not a lot of mass, and the force required isn't a lot. However, if we had a large box on the ground, the force required to move it would be larger, as it's more massive and doesn't have any acceleration. Imagine a shopping cart filled to the ceiling with cereal. It would require a lot of force, wouldn't it? Be sure to think about that.

Last one. Newton's third law is perhaps the most famous. It states,
 
"For every action, there is an equal and opposite reaction".

This is probably the hardest one to understand. Let's try an example. Have you ever accidentally not tightened your balloon, and it started to fly up? That's an application of Newton's third law. The air comes out from the bottom, and the balloon flies up - that's an opposite reaction; up and down. It's the same thing with a rocket. The same force to propel it up is exerted on the ground - an equal reaction.

Hope this helps! Be sure to let me know if you have any questions :)


A certain wave has a wavelength of 35 meters and a frequency of 4.0 Hz. What is the speed of the wave? 8.8 m/s 31 m/s 39 m/s 140 m/s

Answers

35
4.0 Hz
*______
   1.40 Hz
+ 8.8m/s
_______
=10.2 Hz m/s(31)m/s(39)m/s(140)m/s

Answer:

Speed, v = 140 m/s      

Explanation:

It is given that,

Wavelength, λ = 35 meters

Frequency of the wave, υ = 4 Hz

The speed of the wave is the product of the frequency and the wavelength of the wave.

Mathematically, it can be written as :

v = υ λ

v = 35 m × 4 Hz

v = 140 m/s

So, the speed of the wave is 140 m/s

Hence, this is the required solution.

(this question is just for fun)(at least try to answer it) If I was driving 272mph in a koenigsegg one:1 And I was traveling 50 miles across the country how long will it take me to arrive without no obstacles

Answers

The speed of the koenigsegg one is 272 mph ,  the distance that the car must travel is 50 miles

Speed = distance/time

Time = distance/speed = 50miles/272miles per hour = 0.1838 hours 

Time = 
0.1838 hours = 11.028 minutes = 661.68 seconds


USE THE AGERA RS, also it would run out of gas:)   Im a car enthusiast

Using a simple machine, a student is able to lift a 500N weight by applying only 100N.

What is the mechanical advantage of the simple machine?

A) 0.2

B) 1

C) 5

D) 50000

Answers

Hey there!

[tex] a \ student \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\ \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer![/tex]

Hope this helps you!

When the IMA is compared to AMA in the real world, _____.
(A)the value of the IMA is always larger than the AMA
(B)the value of the AMA is always larger than the IMA
(C)the value of the AMA is larger than the IMA when there is no resistance
(D)the value of the IMA is larger than the AMA when there is no resistance

Answers

AMA is actual mechanical advantage in where it would compare the force in as well as out in using actual measurements in the real life or with friction while in IMA which is the ideal mechanical advantage no friction then is needed. The answer then is a. the value of IMA is larger than AMA.


I believe the answer is A.) the value of the IMA is always larger than the AMA
(Not 100% on this, not my strongest topic, so I would double check)

Calculate the water pressure in the pipes at the bottom of a high-rise building that is fed by reservoir 60 m above the roof top. Please help and explain

Answers

In order to solve the problem, we can use Stevin's law. The pressure at the bottom of a column of fluid with density [tex]\rho[/tex] and height h is:
[tex]p=\rho g h[/tex]
In our problem, the fluid is water, so its density is [tex]\rho = 1000 Kg/m^3[/tex]. The height of the column of water is h=60 m, and [tex]g=9.81 m/s^2[/tex], therefore
[tex]p=(1000 Kg/m^3)(9.81 m/s^2)(60 m)=5.89 \cdot 10^5 Pa[/tex]

) with the box still on the truck, the truck attains its maximum velocity. as the truck comes to a stop at the next stop light, what is the magnitude of the maximum deceleration the truck can have without the box sliding?

Answers

When the truck starts decelerating a force starts acting on a box. In order for the box to start sliding force acting on it has to be bigger than a static force of friction. 
If the trucks declaration is we have the following force acting on the box:
[tex]F=ma[/tex]
This force has to be smaller than static friction force:
[tex]F_f=mg\mu[/tex]
Where [tex]\mu[/tex] is static friction coefficient.
Now we can find an answer:
[tex]ma\leq mg\mu\\ a\leq g\mu[/tex]

Final answer:

The magnitude of the maximum deceleration to keep the box from sliding is determined by the coefficient of static friction and gravity; it can be calculated as 2.352 m/s² for a coefficient of 0.24.

Explanation:

The question deals with the concept of friction and deceleration in the context of a box placed on a truck that is coming to a halt. To prevent the box from sliding, the maximum deceleration is dictated by the coefficient of static friction.

This coefficient, multiplied by the acceleration due to gravity, gives us the maximum deceleration the truck can have without the box beginning to slide.

To calculate this, we can use the formula maximum deceleration (a_max) = coefficient of static friction (μ_s) × acceleration due to gravity (g), where μ_s is 0.24 and g is approximately 9.8 m/s².

Thus, a_max = 0.24 × 9.8 m/s², which results in a maximum deceleration of 2.352 m/s² without causing the box to slide.

Which of the following is an accurate description of relationship demonstrated in ohms law

Answers

There is no accurate description in the list of choices that you provided.

Answer:

The electric potential (volts) divided by the current (amperes) equals the resistance (ohms).

Explanation: That is the formula to find the resistance based on the Ohm's laws.

Select the volume units that are greater than one liter.

a.) kiloliter
b.) milliliter
c.) megaliter
d.) centiliter
e.) deciliter
f.) nanoliter

Answers

a.) kiloliter. 1 kiloliter = 1,000 liters
c.) megaliter. 1 megaliter =  1,000,000 liters


hope this helps

Answer: The correct answers are option (a)and(c).

Explanation:

1) In ,1 kilo Liter = 1,000 Liter

1 liter = 0.001 kilo Liter

2) In ,1 Mega Liter = 1,000,000

1 Liter = [tex]10^{-6}[/tex] Mega Liter

Where as milliliter, centiliter, deciliter and nano liters are smaller units that 1 liter

1 Liter = 1000 milliliter

1 Liter = 100 centiliter

1 Liter = 10 deciliter

1 Liter = [tex]10^9[/tex] nano liter

Hence, the correct answers are option (a)and(c).

If a steel, thin-shelled wheel of radius r and mass M is moving along the road at 2 m/s, what is the total kinetic energy?

1) 2M
2) 3M
3) 1M
4) 5M
5) 4M

Answers

The moment of inertia for rolling motion is
I = Mr²

The linear velocity is v = 2 m/s. The rotational velocity is
ω = 2/r 

The total KE (kinetic energy) is
KE = (1/2)Mv² + (1/2) I ω²
     = (1/2)(M)(4) + (1/2)(Mr²)(4/r²)
    = 2M + 2M
    = 4M

Answer:  4M

Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what could Lana do to get more out of her hhomework

Answers

I added a screenshot with the complete question

Answer:
D. Ask her instructor questions about it the next day

Explanation:
We are given that Lana doesn't understand everything she's supposed to learn from the homework.

Let's check the options:
1- start working on it eve earlier
We know that she works on the homework as soon as she can. Working on it even earlier will not help her understand the difficult parts

2- put it off until she's ready to work on it
This is not the best option as it wont help her understand difficult parts. On the contrary, she might lose the time she has to practice the parts she understands and gain as much knowledge as possible

3- Only work on it directly before going to class.
this is the same as option 2. She might not even be able to finish it before the class

4- Ask her instructor questions about it the next day
This is the best solution as it will help her recap what she needs to learn and understand any difficult concepts as soon as possible which will help optimize her benefits

Hope this helps :)

Explanation:

Since Lana is unable to understand everything while doing her homework it means that she has doubts about some of the topics given in her homework.

Therefore, in that case she should take the help of her teacher or instructor the very next day because her doubts are new and she should consult about then as soon as possible.

Thus, by doing so she can clear her doubts on time.

Astronauts in orbit are not truly weightless. Please select the best answer from the choices provided T F

Answers

That's true. There's plenty of gravity in Earth orbit, and things have plenty of weight there.

Answer:

true

Explanation:

true

The tangential speed at the outer rim of a Ferris wheel is 10 m/s. What is the tangential speed of a position halfway from the center to the outer rim?

Answers

Final answer:

In rotational motion, tangential speed is proportional to the radius. Thus, if you're halfway between the center and the rim of a Ferris wheel, your speed would be half that of the rim's speed. So, the tangential speed halfway to the center from the rim would be 5 m/s assuming the outer rim speed is 10 m/s.

Explanation:

The concept you're asking about is related to tangential speed and its relationship to the radius in rotational motion. In the case of a Ferris wheel, or any rotating body, the tangential speed is defined as the angular velocity times the radius. Therefore, if the radius is halved (a point halfway from the center to the outer rim), the tangential speed at the new point will also be halved assuming a constant angular velocity. Thus, in your example, if the tangential speed at the outer rim is 10 m/s, the speed halfway to the center will be 5 m/s.

This is because the properties of a rotating body dictate that the tangential speed increases linearly with the radius from the axis of rotation, in the case of a constant angular velocity. Hence, the farther away from the center of rotation, the faster the tangential speed, and vice versa.

Learn more about Tangential Speed here:

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The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel with an outer rim speed of 10 m/s would be 5 m/s.

The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel is half of the tangential speed at the outer rim. In this case, the initial tangential speed at the outer rim is given as 10 m/s, so the tangential speed at halfway to the rim would be 5 m/s. This is because tangential speed is directly proportional to the radius in uniform circular motion, and if the radius is halved, so is the tangential speed.

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