Answer : The freezing point of a solution is [tex]-0.454^oC[/tex]
Explanation : Given,
Molal-freezing-point-depression constant [tex](K_f)[/tex] for water = [tex]1.86^oC/m[/tex]
Mass of KCl (solute) = 15 g
Mass of water (solvent) = 1650.0 g = 1.650 kg
Molar mass of KCl = 74.5 g/mole
Formula used :
[tex]\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of KCl}}{\text{Molar mass of KCl}\times \text{Mass of water in Kg}}[/tex]
where,
[tex]\Delta T_f[/tex] = change in freezing point
[tex]\Delta T_s[/tex] = freezing point of solution = ?
[tex]\Delta T^o[/tex] = freezing point of water = [tex]0^oC[/tex]
i = Van't Hoff factor = 2 (for KCl electrolyte)
[tex]K_f[/tex] = freezing point constant for water = [tex]1.86^oC/m[/tex]
m = molality
Now put all the given values in this formula, we get
[tex]0^oC-T_s=2\times (1.86^oC/m)\times \frac{15g}{74.5g/mol\times 1.650kg}[/tex]
[tex]T_s=-0.454^oC[/tex]
Therefore, the freezing point of a solution is [tex]-0.454^oC[/tex]
Answer:
The freezing point of the solution containing 15 grams of KCl and 1650 grams of water is [tex]\rm -0.454^\circ\;C[/tex].
Explanation:
The freezing point of the solution can be calculated by:
Molarity = [tex]\rm \frac{mass\;of\;KCl\;}{molar\;mass\;of\;KCl\;\times\;Mass\;of\;water}[/tex]
Molarity = [tex]\rm \frac{15}{74.5;\times\;1650}[/tex]
Molarity = 1.2 [tex]\rm \times\;10^-^4[/tex] M
[tex]\rm \Delta\;T\;=\;i\;\times\;K_f\;\times\;Molarity[/tex]
[tex]\rm T^\circ\;\times\;T_f\;=\;i\;\times\;K_f\;\times\;Molarity[/tex]
[tex]\rm T_f=\;2\;\times\;1.86\;\times\;1.2\;\times\;10^-^4[/tex]
[tex]\rm T_f[/tex] = [tex]\rm -0.454^\circ\;C[/tex]
The freezing point of the solution containing KCl is [tex]\rm -0.454^\circ\;C[/tex].
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The key on a pie chart represents...
Answer:
data that adds up to 100%
Explanation:
how many moles are there in 78.3g of CO2?
Select all that apply. According to scientists, the distribution of volcanoes throughout the world… Is fairly even and widespread Forms a specific pattern across fault lines Corresponds to plate boundaries Is constantly changing and shifting
Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate the mass of helium that it would take to fill the balloon
Answer:
1.1 x 10-3 g
Explanation:
Write a net ionic equation to show that acetylsalicylic acid (aspirin), hc9h7o4, behaves as a brønsted-lowry acid in water.
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory:
An acid is defined as a substance which looses donates protons and thus forming conjugate base.A base is defined as a substance which accepts protons and thus forming conjugate acid.Acetylsalicylic acid when dissolved in water donates its proton to form conjugate base and water gains the proton to form conjugate acid.The net ionic equation is given as:
[tex]HC_9H_7O_4(0+H_2O\rightarrow (C_9H_7O_4)^{-}+H_3O^+[/tex]
Given the balanced equation 3H2(g)+N2(g)=2NH3(g), calculate the mass of NH3 produced by the complete reaction of 2.55g of H2
The mass of NH3 produced from the complete reaction of 2.55g of H2 is calculated to be 14.45 g, based on the molar masses of H2 and NH3 and the stoichiometry of the given balanced chemical equation.
Explanation:To calculate the mass of NH3 produced by the complete reaction of 2.55g of H2, we first need to determine the molar mass of H2. Knowing that the atomic mass of hydrogen is 1.0, we can say that the molar mass of H2 is 2.0 g/mol. Next, we need to find out how many moles of H2 are in 2.55 g:
Number of moles of H2 = mass (g) / molar mass (g/mol) = 2.55 g / 2.0 g/mol = 1.275 mol
Using the stoichiometry of the balanced equation (N2(g) + 3H2(g) → 2NH3(g)), we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, we can set up a proportion to find the number of moles of NH3 that would be produced from 1.275 moles of H2:
(1.275 mol H2) * (2 mol NH3 / 3 mol H2) = 0.85 mol NH3
Now, to find the mass of NH3, we need to know its molar mass. The atomic mass of nitrogen is 14.0 and hydrogen is 1.0, so the molar mass of NH3 is 14.0 + (3 * 1.0) = 17.0 g/mol. Finally, we can calculate the mass of NH3 produced:
Mass of NH3 = number of moles * molar mass = 0.85 mol * 17.0 g/mol = 14.45 g
What is the number “4” in SiCl4?
Determine the molecular formula of a compound that has a molar mass of 183.2 g/mol and an empirical formula of c2h5o2.
Answer:
[tex]C_6H_{15}O_6[/tex]
Explanation:
Hello,
In this case, one computes the molar mass for the given empirical formula as follows:
[tex]M_{empirical}=12*2+1*5+16*2=61g/mol[/tex]
In such a way, one computes how many times the molecular formula's molecular mass is contained into the empirical formula's molecular mass in order to determine the whole number relating them as shown below:
[tex]\frac{183.2g/mol}{61g/mol}=3[/tex]
Finally, the molecular formula is three times the empirical formula, hence:
[tex]C_6H_{15}O_6[/tex]
Best regards.
The thermodynamic law that explains the movement of heat energy during the refrigeration cycle is the first/zeroth/second.
What is the empirical formula of a substance that contains 5.28 g of c, 0.887 g of h, and 3.52 g of o?
Final answer:
The empirical formula of the compound is CH2O.
Explanation:
To determine the empirical formula of a substance, we need to find the ratio of the number of atoms of each element in the compound.
Step 1: Convert the given masses of each element to moles. Using the molar mass of each element (C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol), we have 5.28 g C = 0.44 mol C, 0.887 g H = 0.877 mol H, and 3.52 g O = 0.22 mol O.
Step 2: Divide each element's mole value by the smallest mole value to get the simplest ratio. In this case, the smallest mole value is 0.22 mol O. Dividing the other mole values by 0.22 gives us 0.44 mol C, 0.877 mol H, and 1 mol O.
The empirical formula of the compound is CH2O.
Consider the unbalanced equation for the combustion of hexane: αc6h14(g)+βo2(g)→γco2(g)+δh2o(g) part a balance the equation. give your answer as an ordered set of numbers α, β, γ, ... use the least possible integers for the coefficients. α, β, γ, δ = request answer part b determine how many moles of o2 are required to react completely with 6.4 moles c6h14. express your answer using two significant figures. n = mol
Answer :
Part A : The value of [tex]\alpha, \beta, \gamma \text{ and }\delta[/tex] are 2, 19, 12 and 14 respectively.
Part B : [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].
Solution :
Part A :
The given unbalanced equation is,
[tex]\alpha C_6H_{14}(g)+\beta O_2(g)\rightarrow \gamma CO_2(g)+\delta H_2O(g)[/tex]
The balanced equation is,
[tex]2C_6H_{14}(g)+19O_2(g)\rightarrow 12CO_2(g)+14H_2O(g)[/tex]
Part B :
From the balanced equation, we conclude that
2 moles of [tex]C_6H_{14}[/tex] react with 19 moles of [tex]O_2[/tex]
6.4 moles of [tex]C_6H_{14}[/tex] react with [tex]\frac{19moles}{2moles}\times 6.4moles=60.8moles=6.0\times 10^1moles[/tex] of [tex]O_2[/tex]
Therefore, [tex]6.0\times 10^1moles[/tex] of [tex]O_2[/tex] are required to react with 6.4 moles of [tex]C_6H_{14}[/tex].
The balanced equation is 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g), therefore the coefficients α, β, γ, δ are 2,9,6,7, respectively. And 29 moles of O2 are required to react completely with 6.4 moles of C6H14.
Explanation:For part a, to balance the equation for the combustion of hexane, we have to adjust the coefficients in the equation C6H14(g) + αO2(g) → βCO2(g) + γH2O(g) such that the number of atoms of each element on both sides of the equation are equal. The balanced equation becomes: 2C3H7(g) + 9O2(g) → 6CO2(g) + 7H2O(g) . It means that α, β, γ, δ = 2, 9, 6, 7 respectively.
For part b, according to the balanced equation, 9 moles of O2 are required to react completely with 2 moles of C6H14. So, if there are 6.4 moles of C6H14, you will need: (6.4 moles C6H14 * 9 moles O2) / 2 moles C6H14 = 28.8 ≈ 29 moles of O2. In this case 'n' equals 29 moles.
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If the apparent magnitude of a star increases,the star get brighter, true or false?
Wade thinks it would be really cool to become a radiologist. Which two skills are important for him to have in order to excel in this career?
A-leadership skills to help oversee the members of the staff within the hospital
B- physical strength to lift heavy equipment and machinery
C-interpersonal skills to talk to patients and help them feel comfortable
D-technical skills to know how to use the machinery and equipment needed for the jobE-public speaking skills to announce research findings in conferences
The stalk that holds the anther up so that pollination and fertilization can occur is the _______. :
stigma
style
filament
anther
The volume of an automobile air bag was 66.8 l when inflated at 25 °c with 77.8 g of nitrogen gas. what was the pressure in the bag in kpa
_____________ means that animals within a population have a variety of strengths.
A car travels 31.2 miles in 36.0 minutes. What is the average speed of the car during this trip, in miles per hour (mph)?
Answer:
0.8 mph
Explanation:
divide distance by time
31.2/ 36 = 0.866..
Determine the mass of lithium hydroxide produced when 0.83g of lithium nitride reacts with water
When 0.83g of lithium nitride reacts with water, 1.7g of lithium hydroxide is produced according to the balanced chemical equation and stoichiometry.
Explanation:To determine the mass of lithium hydroxide (LiOH) produced, we first need to understand the balanced chemical equation of the reaction.
Lithium nitride (Li₃N) reacts with water (H₂O) to form lithium hydroxide and ammonia (NH₃), which can be represented as:
Li₃N + 3H₂O → 3LiOH + NH₃
From the equation, we can see that 1 mole of lithium nitride reacts with 3 moles of water to produce 3 moles of lithium hydroxide.
Next, we need to convert the mass of lithium nitride to moles using the molar mass of lithium nitride, which is approximately 34.83 g/mol.
0.83 g Li₃N * (1 mol/34.83 g) = 0.0238 mol
Since the molar ratio of Li₃N to LiOH is 1:3, we multiply this mole by 3 to get the moles of lithium hydroxide produced.
Moles of LiOH = 0.0238 mol * 3 = 0.0714 mol
Finally, we convert the moles of LiOH to grams using the molar mass of LiOH, which is 23.95 g/mol.
Mass of LiOH = 0.0714 mol * 23.95 g/mol = 1.7 g
So, when 0.83g of lithium nitride reacts with water, 1.7g of lithium hydroxide is produced.
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Draw one of the isomeric c5h12o alcohols that can be prepared by lithium aluminum hydride reduction of a ketone.
Consider the fructose-1,6-bisphosphatase reaction. calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 24.3, and the temperature is 37.0 °c? δg°\' for the reaction is –16.7 kj/mol. the constant r = 8.3145 j/(mol·k)
What is the conjugate acid of hpo22− ? express your answer as a chemical formula?
The conjugate acid of HPO2- is H2PO4-.
Explanation:The conjugate acid of HPO2- is H2PO4-.
An analysis reveals that a substance consists of 26.7% of carbon, 2.24% of hydrogen and 71.1% of oxygen, If the molar mass of the compound is 270.1 g/mol, what is the MOLECULAR Formula?
Consider this reaction: 2al(s) + 3 cucl2(aq) → 2alcl3(aq) + 3 cu(s) if the concentration of cucl2 drops from 1.000 m to 0.655 m in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?
The average rate of reaction for CuCl₂ is found by dividing the concentration change (0.345 M) by the time interval (30.0 s), resulting in an average reaction rate of 0.0115 M/s for both the disappearance of CuCl₂ and the formation of Cu.
The student is asking about calculating the average rate of reaction using changes in the concentration of a reactant over a given time interval. The average rate of reaction can be calculated by dividing the change in concentration of a reactant by the time period over which the change occurred. In this case, the concentration of CuCl₂ drops from 1.000 M to 0.655 M over 30.0 seconds.
To find the average rate at which CuCl₂ has reacted, we can use the formula:
Calculate the change in concentration of CuCl₂:The average rate of reaction for the disappearance of CuCl₂ is 0.0115 M/s. Since the reaction stoichiometry shows 3 moles of CuCl₂ produces 3 moles of Cu, the average rate of formation of Cu is also 0.0115 M/s.
The part of the flower responsible for producing pollen (sperm) is the _______.
filament
anther
stigma
style
Write the atomic cores for potassium and chloride ions
The atomic core for a potassium ion (K+) is [Ar]4s¹ without the one electron it loses to become an ion. The atomic core for a chloride ion (Cl-) is [Ne]3s² 3p⁵ with an extra electron gained to fill its 3p orbital.
Explanation:The atomic cores for potassium and chloride ions are represented by their respective electron configurations and their charges after ion formation. Potassium (K) has an atomic number of 19, which means it has 19 electrons. The electron configuration is [Ar]4s¹. When potassium forms an ion, it loses one electron to achieve a noble gas configuration, making it a potassium ion with a charge of +1, represented as K⁺.
Chlorine (Cl) has an atomic number of 17, which means it has 17 electrons. The electron configuration is [Ne]3s² 3p⁵. When chlorine forms an ion, it gains one electron to fill its 3p orbital, becoming a chloride ion with a charge of -1, represented as Cl⁻.
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If the equilibrium constant kc for the reaction below is 1.71 × 10–1, what will be the equilibrium pressure of no if the initial partial pressures of the three gases are all 1.96 × 10–3 atm? $$
Final answer:
To determine the equilibrium pressure of NO, set up an ICE table using the values of the equilibrium constant (Kc) and initial partial pressures. Assume the increase in NO pressure is 'x' and the decrease in N2O and O2 pressures is '2x' and 'x', respectively. Calculate the equilibrium pressures by adding the initial pressures to their corresponding changes.
Explanation:
To determine the equilibrium pressure of NO, we need to set up an ICE table and use the values of the equilibrium constant (Kc) and initial partial pressures of the three gases. Let's assume the increase in the pressure of NO is 'x'. Since the stoichiometric coefficient of NO is 2, the decrease in the pressures of N2O and O2 will be '2x' and 'x', respectively. The equilibrium partial pressures of the three gases can be calculated by adding the initial pressures to their corresponding changes.
Initial pressures:
N2O: 1.96 × 10-3 atmO2: 1.96 × 10-3 atmNO: 1.96 × 10-3 atmChange in pressures:
N2O: -2xO2: -xNO: xEquilibrium pressures:
N2O: (1.96 × 10-3 - 2x) atmO2: (1.96 × 10-3 - x) atmNO: (1.96 × 10-3 + x) atmSince the equilibrium constant (Kc) is given as 1.71 × 10-1, which represents the ratio of the equilibrium concentrations of products to reactants, we can set up the following equation:
Kc = [NO]2 / ([N2O] * [O2])
Substituting the equilibrium pressures into this equation:
1.71 × 10-1 = ([1.96 × 10-3 + x]2 / ([1.96 × 10-3 - 2x] * [1.96 × 10-3 - x]))
Now, solve this equation to find the value of 'x', which represents the equilibrium increase in the pressure of NO.
Once 'x' is determined, substitute it back into the equations for the equilibrium pressures to calculate the final equilibrium pressures of N2O, O2, and NO.
Determine the limiting reactant. 2al(s)+3br2(g)→2albr3(s)
The limiting reactant in a chemical reaction is determined by calculating the amount of product (AlBr3 in this case) that would be produced from the complete reaction of each of the reactants separately. The reactant yielding the lesser amount of product is the limiting reactant.
Explanation:To determine the limiting reactant in a chemical reaction, you can use a method where you compare the amount of each reactant to the amount of product expected from its complete reaction. Taking the given equation, 2Al(s)+3Br2(g)→2AlBr3(s), we would calculate the amount of the product AlBr3 that would be formed from the complete reaction of each reactant, Al and Br2, separately. The reactant that yields the lesser amount of the product AlBr3 is the limiting reactant. This concept can be understood using a simple analogy. Let's think of making a sandwich: 2 slices of bread + 1 slice of cheese yields 1 sandwich. If you have an excess of bread but only one slice of cheese, you can only make one sandwich. The cheese is the limiting reactant as it limits the yield of sandwich and the amount of bread left unreacted is the excess reactant. Similarly, in the chemical reaction given above, the reactant that produces less amount of product (AlBr3) acts as the limiting reactant.
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During respiration, a plant uses glucose (sugar) and oxygen to give it the energy it needs to survive. During this process ______ and _____ are released.
Question 6 options:
hydrogen and oxygen
sunlight and water
water and carbon dioxide
nitrogen and carbon dioxide
Answer:
water carbon dioxide
Explanation:
_____ is the process where the female reproductive cell (egg) is united with the male reproductive cell (sperm).
growth
fertilization
pollination
germination
Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. for the combustion reaction 2h2(g)+o2(g)⇌2h2o(g) what is the likely magnitude of the equilibrium constant k?
The reaction tends to completion hence K should be in the order of K>103.
The equilibrium constant is a number that indicates the extent to which reactants are converted to products in a chemical reaction. A high value of equilibrium constant indicates that the system contains mostly products and few reactants at equilibrium. A low equilibrium constant indicates that the concentration of reactants is greater than the concentration of products at equilibrium.
For the reaction; 2H2(g) + O2(g) ⇌ 2H2O(g), we know the reaction to be explosive and tend to completion since it is a combustion reaction. This means that the reactants are mostly converted to products and the equilibrium constant will be large. Hence K should be in the order of K>103.
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Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. For the combustion reaction 2H2(g)+O2(g)⇌2H2O(g) what is the likely magnitude of the equilibrium constant K?
1. K<10−3
2. 10−3
3. K=0
4. K>103