Calculate the momentum of a 953kg elephant running at a rate of 3.85 m/s.

Answers

Answer 1
Hi!
So we got 953kg = mass
And we also got 3.85 = speed
M/S = 953/3.85
953/3.85= 247.532468
ANSWER: 247.532468
Hope I helped! :D

Related Questions

Elements may have similar properties and we can use the periodic table to help us determine what they are. These three elements are alike in many ways but they do not share ALL properties. What property do these elements NOT have in common? Mg, K, and Ca A) Same phase at room temperature. B) Good conductors of electricity. C) Same number of valence electrons. D) They form cations (positive ions).

Answers

C is the answer
potassium(K)has one electron in the valence shell
Ca and Mg has two

The properties that Mg, Ca and K do not have in common is "same number of valence electrons."

In the periodic table, elements are classified into groups and periods. The groups of elements show the relationships between them in terms of reactivity, valence electrons and physical properties.

Elements in the same group have the same number of valence electrons. However, Ca, K and Mg are not in the same group so they can not have the same number of valence electrons. Ca and Mg has two valence electrons while K has only one valence electron.

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A 0.450-kg hammer is moving horizontally at 7.00 m/s when it strikes a nail and comes to rest after driving the nail 1.00 cm into a board. (a) calculate the duration of the impact. (b) what was the average force exerted on the nail?

Answers

(a) The duration of impact of the hammer is [tex]\fbox{\begin\\1.43 \times {10^{ - 3}}\,{\text{s}}\end{minispace}}[/tex] .

(b) The average force exerted on the nail is [tex]\fbox{\begin\\2205\,{\text{N}}\end{minispace}}[/tex].

Further explanation:

When hammer hit the nail it got impacted by the hit and get into the board. This insertion in the board take time which is called duration of impact. The force exerted on the nail is directly proportional to the acceleration of the nail.

Given:

The speed of hammer is [tex]7\,{\text{m/s}}[/tex].

The distance of nail which is inserted in the board is [tex]1\,{\text{cm}}[/tex].

The mass of the hammer is [tex]0.450\,{\text{Kg}}[/tex].

Concept used:

The rate of change of displacement of a body in unit time is called speed of the body. It is a scalar quantity.

The expression for the speed of the body is given as.

[tex]v = \dfrac{s}{t}[/tex]

Rearrange the above expression for the time.

[tex]t=\dfrac{s}{v}[/tex]                                               …… (1)

Here, [tex]s[/tex]  is the distance covered, [tex]v[/tex]  is the speed of body and [tex]t[/tex]  is the time.

According to Newton’s second law of motion “the rate of change of momentum is equal to the force applied on the body.”

The expression for the newton’s law is given as.

[tex]F = ma[/tex]                                          ……. (2)

The expression for the acceleration of the body is given as.

[tex]\fbox{\begin\\a = \dfrac{{\left( {v - u} \right)}}{t}\end{minispace}}[/tex]                                           …… (3)

Here, [tex]u[/tex]  is the initial velocity and [tex]v[/tex]  is the final velocity.

Substitute [tex]1\,{\text{cm}}[/tex] for [tex]s[/tex] and [tex]7\,{\text{m/s}}[/tex]  for [tex]v[/tex] in equation (1).

[tex]\begin{aligned}t&=\frac{{1\,{\text{cm}}}}{{7\,{\text{m/s}}}}\\&=\frac{{1\,{\text{cm}}\left( {\frac{{1\,{\text{m}}}}{{100\,{\text{cm}}}}} \right)}}{{7\,{\text{m/s}}}}\\&=1.43 \times {10^{ - 3}}\,{\text{s}} \\ \end{aligned}[/tex]

Substitute [tex]1.43 \times {10^{ - 3}}\,{\text{s}}[/tex] for [tex]t[/tex], for[tex]0\,{\text{m/s}}[/tex]  and [tex]v[/tex]  for  in equation (3).

[tex]\begin{gathered}a= \frac{{\left( {0\,{\text{m/s}} - 7\,{\text{m/s}}} \right)}}{{\left( {1.43 \times {{10}^{ - 3}}\,{\text{s}}} \right)}} \\= \left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right) \\ \end{gathered}[/tex]

Substitute[tex]\left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)[/tex] for [tex]a[/tex]  and [tex]0.450\,{\text{Kg}}[/tex]  for [tex]m[/tex]  in equation (2).

[tex]\begin{aligned}F&=\left( {0.450\,{\text{Kg}}} \right)\left( { - 4900\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)\\&=- 2209\,{\text{N}} \\ \end{aligned}[/tex]

Thus, the duration of impact is[tex]1.43 \times {10^{ - 3}}\,{\text{s}}[/tex]  and the force exerted on the nail is [tex]2209\,{\text{N}}[/tex]  in the opposite direction.

Learn more:

1.  Motion under friction https://brainly.com/question/7031524.

2.  Conservation of momentum https://brainly.com/question/9484203.

3. Force on a body https://brainly.com/question/6125929.

Answer Details:

Grade: College

Subject: Physics

Chapter: Kinematics

Keywords:

Acceleration, force, acceleration due to gravity, friction, normal, weight, mass, motion, impact, nail, hammer, acceleration, duration of impact, 0.450 kg, 7 m/s, 2205 N,1.429*10^-3 sec, 1.43*10^-3 sec.

The duration of the impact is 0.133 seconds.

The average force exerted on the nail was 5800 N.

(a) Let's use the following equations to solve this problem:

m = 0.450 kg

v_i = 7.00 m/s

v_f = 0 m/s

d = 0.01 m

where:

m is the mass of the hammer

v_i is the initial velocity of the hammer

v_f is the final velocity of the hammer (after it strikes the nail)

d is the distance that the nail is driven into the board

We know that the hammer comes to rest after it strikes the nail, so v_f = 0. We can also set the kinetic energy of the hammer before the impact equal to the work done by the force exerted by the nail on the hammer during the impact.

[tex]KE_i = W\dfrac{1}{2}mv_i^2 = Fd\dfrac{1}{2}(0.450 kg)(7.00 m/s)^2 = F(0.01 m)F = 5800 N[/tex]

The duration of the impact can be calculated using the following equation:

[tex]t = \dfrac{d}{v_i}t = \dfrac{0.01 m}{7.00 m/s}t = 0.0133 s[/tex]

(b) The average force exerted on the nail is equal to the force exerted by the hammer on the nail divided by the duration of the impact.

F_avg = F / t

F_avg = 5800 N / 0.0133 s

F_avg = 5800 N

Therefore, the average force exerted on the nail was 5800 N.

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If it takes a ball dropped from rest 2.069 s to fall to the ground, from what height h was it released?

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i dont know the answer im sorry

Explain how the lenses in refracting telescopes help scientists to see enlarged images of celestial objects

Answers

The objective lens makes a small real image of the object so that the eyepiece lens can act as a magnifying glass and produce an enlarged image of the objective lens's image. This is how

What is Refracting telescopes  ?

Refracting telescopes typically use two convex lenses one is objective lenses and the other is an eyepieces.

Enlargement is related to the magnification and magnification is directly proportional to the focal length of the objective lens. The objective have large focal length in order to see distant objects as enlarged .The objective  lens collects light from a distant object and brings that light to a focal point to create an image. Hence it ensures large magnification of the distant object

The refracting telescope works by bending light with lenses. The objective lens makes a small real image of the object so that the eyepiece lens can act as a magnifying glass and produce an enlarged image of the objective lens's image

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You hop on the carousel horse. The attendant flips the switch and you move up and down, around and around. When the ride ends, the attendant again flips the switch. The up and down motion stops, as you continue to move in a circular motion, gradually slowing to a stop. Why?

Answers

The reason why we gradualy slow untill we stop is acceleration. In this example we have two types of movement: vertical and circular.

The vertical movement does not have great speed. So when  we stop moving we do not experience great acceleration. Newton's second law states: F=m*a. This means that we do not experience great force.

The circular movement is a bit different. No matter where we stand on the carousel we have same angular speed. This means that we pass same angle in the same amount of time. But we also have linear speed. This speed depends on the distance from the center of carousel. If we are close to the center we have smaller speed than when we stand at the far end of carousel. If we stopped without slowing gradually we would experience great acceleration thus meaning we would experience great force. Sometimes this force could cause injuries.

A thermometer is taken from an inside room to the outside, where the air temperature is 30° f. after 1 minute the thermometer reads 80° f, and after 5 minutes it reads 55° f. what is the initial temperature of the inside room? (round your answer to two decimal places.)

Answers

Final answer:

To determine the initial temperature of the inside room, we can convert the given temperatures from Fahrenheit to Celsius and calculate the temperature change. By using the temperature change and the final temperature in Celsius, we can find the initial temperature in Celsius. The initial temperature of the inside room is approximately 27.22°C.

Explanation:

To find out the initial temperature of the inside room, we can use the relationship between Fahrenheit and Celsius scales. We know that 30°F is equal to -1.11°C, and 80°F is equal to 26.67°C. By converting these temperatures to Celsius, we can determine the temperature change. Then, using the final temperature of 55°F, we can calculate the initial temperature using the temperature change.



To convert Fahrenheit to Celsius, we use the formula:



TC = (TF - 32) × (5/9)



By plugging in the given temperatures, we find:



TC1 = (30 - 32) × (5/9) ≈ -1.11°C



TC2 = (80 - 32) × (5/9) ≈ 26.67°C



Next, we calculate the temperature change:



ΔT = TC2 - TC1 = 26.67 - (-1.11) = 27.78°C



Finally, we use ΔT and the final temperature (TC=55°C) to find the initial temperature:



Initial temperature = final temperature - ΔT



Initial temperature ≈ 55 - 27.78 ≈ 27.22°C

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Which resistor dissipates the most power, the one with the greatest resistance or the one with the least resistance? explain why this should be?

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Final answer:

The resistor that dissipates the most power varies depending on the configuration of the circuit. In a series circuit, the resistor with the greatest resistance dissipates the most power due to the greater voltage drop across it. In a parallel circuit with a constant voltage source, the resistor with the smallest resistance dissipates the most power because it allows for the greatest current.

Explanation:

In a circuit, power dissipation is based on the formula, P = IV, also known as Joule's law. Substituting Ohm's law (V = IR) into this formula gives us a better understanding of how resistance affects power. This results in the formula P = I²R, meaning that power is directly proportional to the resistance when current is constant.

Therefore, a higher resistor value would, in theory, dissipate more power. However, in a series circuit where every resistor has the same current flowing through them, the resistor providing the greatest resistance will have the highest voltage (V) drop, hence dissipating more power.

Conversely, if the resistors are connected in parallel, the smallest resistor dissipates more power because it allows for the greatest current, provided the voltage source remains constant.

The discussion on power dissipation in resistors links to the P = V²/R equation, suggesting that lower resistance yields higher power when voltage is consistent. Therefore, your circuit configuration and the constants in the equation play crucial roles in determining which resistor dissipates the most power.

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The power dissipated by a resistor depends on whether the voltage or current is constant. With constant voltage, a lower resistance dissipates more power. With constant current, a higher resistance dissipates more power.

To determine which resistor dissipates the most power, we need to consider the power dissipation formulas. Power in a resistor can be calculated using two key formulas:

P = V² / R and P = I² R.

P = V² / R: When the voltage (V) across the resistor is constant, power decreases as resistance (R) increases. Therefore, with the same voltage applied, a resistor with a lower resistance will dissipate more power.

P = I² R: When the current (I) through the resistor is constant, power increases as resistance increases. Therefore, with the same current, a resistor with a higher resistance will dissipate more power.

These two formulas may seem contradictory at first, but they apply in different scenarios. In a circuit where voltage is constant, a lower resistance leads to higher power dissipation. In contrast, in a circuit where current is constant, a higher resistance leads to higher power dissipation.

Therefore, whether a resistor with the greatest or least resistance dissipates the most power depends on whether the voltage across the resistor or the current through the resistor is constant.

Bats use ultrasound in echolocation. This sound is characterized by _____.

A. low frequency
B. low amplitude
C. high frequency
D. high amplitude

Answers

High frequency, as humans cannot hear the sound of the bats using echolocation because of it's such high frequency.
Hope this helps :)

Answer:

C. high frequency  

Explanation:

Bats use high frequency sound waves -ultra sound (20 to 200 kHz) to locate their prey via a technique -echolocation. The produce these sound waves and when the waves reflect from a prey nearby, they are able to estimate the size, position and speed of their prey. The human hearing range is up to 20 kHz, so we can hear the sound produced by some of the bats.

People are able to hear footsteps because the sound made by a foot hitting the floor travels through the air to reach their ears. is this absorption or transmission

Answers

The answer is transmission.

Answer: The correct answer is transmission.

Explanation:

Sound is a form of energy. The energy that survives the transfer is called the sound transmission. If the energy gets absorb then the sound is not heard to the listener. In this case, the absorption will occur.

People are able to hear footsteps because the sound made by a foot hitting the floor travels through the air to reach their ears.  In this case, the sound transmission will occur as the footsteps can be heard. It means that the energy is transferred here.    

A proton and an electron have the same kinetic energy upon entering a region of constant magnetic field. What is the ratio of the radii or their circular paths?

Answers

The Lorentz force on a particle of charge q produced by a magnetic field is
[tex]F=qvB[/tex]
where v is the velocity of the particle and B the intensity of the magnetic field.
Due to this force, the particle will acquire a circular motion, so this force will be the centripetal force of the motion:
[tex]m \frac{v^2}{r} = qvB[/tex]
where m is the mass of the particle, and [tex]r[/tex] the radius of the trajectory.
Re-arranging we have
[tex]r= \frac{mv}{qB} [/tex]

So, we have to find r for both the proton and the electron. We know that the two particles have same kinetic energy:
[tex]K_p = K_e[/tex]
and so
[tex] \frac{1}{2} m_p v_p^2 = \frac{1}{2}m_e v_e^2 [/tex]
The mass of the proton is 1833 times the mass of the electron ([tex]m_p = 1.67 \cdot 10^{-27} kg[/tex], [tex]m_e = 9.11 \cdot 10^{-31}kg[/tex]), i.e.
[tex]m_p = 1833 m_e[/tex]
and so from the relationship between the kinetic energies we find:
[tex]v_p = v_e \sqrt{ \frac{m_e}{m_p} }= v_e \sqrt{ \frac{m_e}{1833 m_e} } = \frac{v_e}{42.8} [/tex]

Now we can calculate the ratio between the radius of the proton and electron trajectories. Keeping in mind that q is the same for proton and electron, and the field B is the same, we have
[tex] \frac{r_p}{r_e} = \frac{m_p v_p}{m_e v_e}= \frac{(1833 m_e)( \frac{v_e}{42.8}) }{m_e v_e}=42.8 [/tex]
So, the radius of the proton trajectory is 42.8 times the radius of the electron trajectory.
Final answer:

The ratio of the radii of the circular paths of a proton and an electron with the same kinetic energy in a constant magnetic field can be determined using the formula for the radius of curvature of a charged particle in a magnetic field.

Explanation:

The ratio of the radii of the circular paths of a proton and an electron with the same kinetic energy in a constant magnetic field can be determined using the formula for the radius of curvature of a charged particle in a magnetic field. The formula is:

r = mv / (qB)

Where:

r is the radius of curvature m is the mass of the particle v is the velocity of the particle q is the charge of the particle B is the magnetic field strength

Since the kinetic energy of the proton and electron is the same, their velocities will be different due to their different masses. This means that the ratio of their radii of curvature will be different. To find the ratio, we can use the formula:

r_proton / r_electron = (m_electron / m_proton) * (v_proton / v_electron)

Where:

r_proton is the radius of curvature of the proton r_electron is the radius of curvature of the electron m_electron is the mass of the electron m_proton is the mass of the proton v_proton is the velocity of the proton v_electron is the velocity of the electron

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You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible internal resistance. find the time constant of the circuit. what is the charge of the capacitor 1.95 time constants after the circuit is closed? what is the charge after a long time?

Answers

In a RC-circuit, with the capacitor initially uncharged,  when we connect the battery to the circuit the charge on the capacitor starts to increase following the law:
[tex]Q(t) = Q_0 (1-e^{-t/\tau})[/tex]
where t is the time, [tex]Q_0 = CV[/tex] is the maximum charge on the capacitor at voltage V, and [tex]\tau = RC[/tex] is the time constant of the circuit.
Using this law, we can answer all the three questions of the problem.

1) Using [tex]R=39.1 \Omega[/tex] and [tex]C= 65.7 mF=65.7\cdot 10^{-3}F[/tex], the time constant of the circuit is:
[tex]\tau = RC=(39.1 \Omega)(65.7 \cdot 10^{-3}F)=2.57 s[/tex]

2) To find the charge on the capacitor at time [tex]t=1.95 \tau[/tex], we must find before the maximum charge on the capacitor, which is
[tex]Q_0 = CV=(65.7 \cdot 10^{-3}F)(9 V)=0.59 C[/tex]
And then, the charge at time [tex]t=1.95 \tau[/tex] is equal to
[tex]Q(1.95 \tau) = Q_0 (1-e^{-t/\tau})=(0.59 C)(1-e^{-1.95})=0.51 C[/tex]

3) After a long time (let's say much larger than the time constant of the circuit), the capacitor will be fully charged, this means its charge will be [tex]Q_0 = 0.59 C[/tex]. We can see this also from the previous formule, by using [tex]t=\infty[/tex]:
[tex]Q(t) = Q_0 (1-e^{-\infty})=Q_0(1-0) = 0.59 C[/tex]

Which law of motion accounts for the following statement?

"The gravity of the Sun causes the planets to move in a circular path."

first law
second law
third law

Answers

i know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...

Answer:

First law

Explanation:

The gravity of the Sun causes the planets to move in a circular path. This is due to first law of motion. The first law states that an object will be at rest and an object will be in motion until no external force acts on it.

It is possible due to sun's gravity pull that the planets move in a circular path. Without sun's gravity the planet would move in a straight line. Hence, the correct option is (a) " first law of motion".

What current flows through a 2.62 cm diameter rod of pure silicon that is 23.5 cm long, when 1000 v is applied to it? (such a rod may be used to make nuclear particle detectors, for example.) the resistivity of pure silicon is 2.30 103 ω · m?

Answers

resistivity = resistance * Area / Length
resistance = ??
rho = 2.30 * 10^3 ohms meters.
l = 23.5 cm = 0.235 meters.
diameter = 2.62 cm = 0.0262 m
Radius = diameter / 2 = 0.0131 m
Area = pi r^2 where pi = 3.14
Area = 3.14 * 0.0131^2 = 0.000539 m^2

2.30 * 10^3 = R * 0.000539 /0.235
2.30 * 10^3 * 0.235/0.000539 = R
R = 1002783 which is about 1 meg ohm, but I'll use the calculation here.

E = 1000 V
R = 1 002 783 ohms
I = ???

E = I * R
1000 = I * 1002783 We should really round that resistor to 1 megohm or 1 * 10^6 ohms.

I = 1*10^3 / 1 * 10^6
I = 1 * 10^-3 amp = 1 milliamp. Pretty reasonable all things considered. 

During the forging process for a steel sword, the blacksmith places a hot iron blank into a cold bucket of water. Which of the following happens? A. The water molecules move faster. B. The steel molecules move faster. C. The water molecules move slower. D. The steel molecules do not change speed

Answers

Hello!

During the forging process for a steel sword, when the blacksmith places a hot iron blank into a cold bucket water A) The water molecules move faster. 

The iron blank molecules are at a higher temperature and move faster than the water molecules, which are colder. When the blacksmith places the hot iron blank into the water bucket, heat is transferred from the hot iron blank to the cold water causing water molecules to move faster, as their temperature (and kinetic energy) increases. This is described by the Second Law of Thermodynamics.

When two notes are played simultaneously, creating a discordant sound, it is called _____.

A. Acoustics
B. Consonance
C. Timbre
D. Dissonance

Answers

Answer:

The correct answer is option D.

Explanation:

Acoustic : A branch of physics which study the properties of sound.

Consonance: Combination of notes occurring simultaneously due to relationship between their respective frequencies.

Timbre: A characteristic of a musical note which makes it distinct from another wave which also have same pitch and intensity.

Dissonance :When combination of two notes are played simultaneously with lack of harmony in between them.

Hence, the correct answer is option D.

Answer:

D. DISSONANCE

Explanation:

A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.02t3 (a) find the velocity at time t (in ft/s). v(t) = .04t3−.06t2 (b) what is the velocity after 1 second(s)? v(1) = -.02 ft/s (c) when is the particle at rest? t = s (smaller value) t = s (larger value) (d) when is the particle moving in the positive direction? (enter your answer using interval notation.) (e) find the total distance traveled during the first 12 seconds. (round your answer to two decimal places.) ft (f) find the acceleration at time t (in ft/s2). a(t) = find the acceleration after 1 second(s). a(1) = ft/s2

Answers

Final answer:

The velocity function can be found by differentiating the position function. The velocity after 1 second is -0.02 ft/s. The particle is at rest at t = 0 and t = 1.5 seconds.

Explanation:

(a) To find the velocity at time t, we can differentiate the position function. The derivative of f(t) = 0.01t^4 - 0.02t^3 is v(t) = 0.04t^3 - 0.06t^2. So, the velocity function is v(t) = 0.04t^3 - 0.06t^2 ft/s.

(b) To find the velocity after 1 second, we substitute t = 1 into the velocity function. v(1) = 0.04(1)^3 - 0.06(1)^2 = -0.02 ft/s.

(c) The particle is at rest when its velocity is equal to zero. To find the time(s) the particle is at rest, we set v(t) = 0 and solve for t. So, the particle is at rest at t = 0 and t = 1.5 seconds.

(d) The particle is moving in the positive direction when its velocity is positive. To find the time(s) the particle is moving in the positive direction, we look for the intervals where v(t) > 0. The particle is moving in the positive direction when 0 < t < 1.5 seconds.

(e) The total distance traveled during the first 12 seconds can be found by finding the area under the velocity-time graph. We integrate v(t) from 0 to 12 seconds. The total distance traveled during the first 12 seconds is approximately 96 ft.

(f) To find the acceleration at time t, we differentiate the velocity function. The derivative of v(t) = 0.04t^3 - 0.06t^2 is a(t) = 0.12t^2 - 0.12t ft/s^2.

(g) To find the acceleration after 1 second, we substitute t = 1 into the acceleration function. a(1) = 0.12(1)^2 - 0.12(1) = 0 ft/s^2.

When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What type of learning is Ian demonstrating?

Answers

This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.

ANSWER: Ian is demonstrating a typical example of Observational Learning. An observational learning is a learning pattern which happens by observing the behavior of others. People generally follows a role model such as parent, sibling, relative or teachers and imitate them while they are doing their work, particularly in childhood. There are four steps of observational learning which are Attention, Memory, Initiation and Motivation.

A switch that connects a battery to a 30μf capacitor is closed. several seconds later you find that the capacitor plates are charged to ±30μc. part a what is the emf of the battery?

Answers

You can find the emf of the battery by using:

Q = CV.

Q = Charge in capacitor plates = 30μC
C = Capacitance of the capacitor = 30μF

V = Q/C = 30/30 = 1V

Ans: The emf of the battery = 1V.
Final answer:

Using the formula for the voltage across a capacitor (V = Q/C), and given the charge on the capacitor (Q) and its capacitance (C), we find that the emf of the battery is 1 Volt.

Explanation:

The question is asking for the electromotive force (emf) of the battery. To determine this, we apply the formula for voltage across a capacitor: V = Q/C, where V is the voltage (or in this case, the emf of the battery), Q is the charge on the capacitor, and C is the capacitance of the capacitor.

Given Q = ±30µC (or 30x10^-6 C) and C = 30µF (or 30x10^-6 F), we substitute these values into the formula:  

V = (30x10^-6) / (30x10^-6)  

Therefore, the emf of the battery is 1 Volt.

This means that when the battery is fully charged, the voltage across the capacitor is also 1 Volt.

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A common cylindrical copper wire used in a lab is 841 m long. Find the radius (in mm) of a wire necessary to have 0.5 Ohms of resistance. (The resistivity of copper at room temperature is 1.68×10-8 Ohm × meter). Express the answer (only numerical value) to one decimal place.

Answers

The relationship between the resistance R of a wire and its resistivity [tex]\rho[/tex] is given by
[tex]R= \frac{\rho L}{A} [/tex]
where L is the length of the wire and A is its cross sectional area.

In the problem, we have [tex]R=0.5 \Omega[/tex], [tex]\rho = 1.68 \cdot 10^{-8} \Omega m[/tex] and [tex]L=841 m[/tex]. So we can solve the find the area A:
[tex]A= \frac{\rho L}{R}=2.83 \cdot 10^{-5} m^2 [/tex]

For a cylindrical wire, the cross sectional area is given by
[tex]A= \pi r^2[/tex]
where r is the radius. We know the value of the area A, so now we can find the radius of the wire:
[tex]r= \sqrt{ \frac{A}{\pi} }= \sqrt{ \frac{2.83 \cdot 10^{-5}m^2}{\pi} }=0.003 m=3.0 mm [/tex]

A 9cm diameter spherical ball whose surface is maintained at a temperature of 110c is

Answers

Final answer:

The question involves concepts of heat transfer and thermal equilibrium in physics, where two spheres reach thermal equilibrium through the transfer of heat, and how a spherical object equilibrates with its ambient temperature.

Explanation:

The question appears to be related to the concept of heat transfer and thermal equilibrium in Physics, specifically involving spherical objects and changes in their temperatures when placed in different environments or in contact with each other.

When considering two spheres of the same material but at different initial temperatures brought into thermal contact, the process involves the transfer of thermal energy from the hotter sphere to the cooler one until they reach a state of thermal equilibrium. This principle is grounded in the second law of thermodynamics, which states that heat energy flows from areas of high temperature to areas of low temperature until thermal equilibrium is achieved. The final temperature reached by both spheres depends on their masses and specific heat capacities, as well as their initial temperatures.

The phenomenon of thermal equilibrium is also apparent when exposing a spherical object to a different ambient temperature, as mentioned in parts of the question. The rate of heat transfer and the time taken for the sphere to reach the temperature of its surroundings can be analyzed using thermodynamics and heat transfer equations, including concepts like conduction, convection, and radiation.

an expert is someone who

Answers

Google's definition: A person that has a prolonged or intense experience through practice and education in a particular field.
My words: I would say an expert is someone who knows something really well. About it and how to do it. They could be an expert on any subject.

Answer: D

expends the least amount of energy for the greatest result

Explanation:

edge 2020

How fast (in rpm) must a centrifuge rotate if a particle 6.00 cm from the axis of rotation is to experience an acceleration of 113000 g's? if the answer has 4 digits or more, enter it without commas,
e.g. 13500?

Answers

The acceleration experienced by the particle is given by
[tex]a=113000 g=113000 \cdot 9.81 m/s^2[/tex]
This corresponds to the centripetal acceleration of the motion, which is related to the angular speed [tex]\omega[/tex] of the particle and its distance r from the axis by the relationship
[tex]a= \omega ^2 r [/tex]
In our problem, [tex]r=6 cm=0.06 m[/tex], so we can solve for [tex]\omega[/tex]:
[tex]\omega = \sqrt{ \frac{a}{r} } = \sqrt{ \frac{113000 \cdot 9.81 m/s^2}{0.06 m} }=4298 rad/s [/tex]
However, we must convert it into rpm (revolution per minute).
We know that 1 rad corresponds to [tex]( \frac{1}{2 \pi} )[/tex] revolutions, while [tex]1 s = \frac{1}{60} min[/tex]. So we the conversion is[tex]\omega = 4298 rad/s \cdot ( \frac{1}{2\pi} rev/rad )( 60 s/min)=41067 rpm[/tex]

Which term is used to describe water that is evaporated, polluted, or used by crops? A. degenerated B. consumptive C. controlled D. processed

Answers

The correct answer is (B) Consumptive.

Explanation:
"Consumptive use" is the term used in the field of Water Science to define "the part of water withdrawn that is evaporated, given off by plants, used by crops, consumed by humans or livestock, or otherwise removed from the immediate water environment. It is also referred as water consumed." Hence the correct answer is (b) Consumptive.

In a heat engine, if 500 j of heat enters the system, and the piston does 300 j of work, what is the final internal (thermal) energy of the system if the initial energy is 1500 j ?

Answers

The answer is 1,700 J.

Use the diagram to answer the question. What happens at night?


Answers

The return flow goes to the right and instead of sea breeze, there's land breeze.

Answer:

Land breeze occurs at night

Explanation:

Land breeze is usually defined as the wind that blows from the land areas to the ocean surface. It occurs during the night time. It is because the land areas have the ability to release heat at a faster rate, in comparison to the ocean water bodies. When the land areas cools, the wind carries the cold and denser prevailing air and reaches the ocean surface in order to balance the warm rising air from the oceans. This is how the heat on earth is being balanced by the simultaneous occurrence of land and sea breeze.

in gas exchange, oxygen passes from the alveoli into the blood . True or false ?

Answers

the answer is True .

A woman wearing snowshoes stands safely in the snow. If she removes her snowshoes, she quickly begins to sink. Explain what happens in terms of force and pressure.

Answers

The purpose of snowshoes is to widen the area pressure is applied on. When you wear plain shoes, the area of distribution of force is concentrated into a small area, namely the area of the shoes you are wearing. Now when pressure is applied on snow surface, it tends to crumble. The force of you standing is concentrated on the space your shoe occupies, increasing the pressure on that specific area. 

Now when you wear snowshoes, you widen the area and the pressure is then distributed over that area lessening the force on specific points. 


A tungsten wire is 4.5 m long and 0.55 mm in diameter. what is its resistance?

Answers

First you need to know the formula for resistance, which is:

[tex]R=[/tex] ρ  [tex]\frac{L}{A} [/tex]    --- (A)

Where,
ρ = Resistivity 
L = length 
A = Area

ρ = Resistivity of tungsten = 5.28 x [tex]10^{-8}[/tex] Ωm
L = Length = 4.5 m
A = Area = 0.55 * [tex]10^{-3}[/tex] * π

Plug-in the values in equation(A), you would get:

[tex]Resistance = \frac{5.28 *10^{-8} * 4.5}{0.55 * 10^{-3} * \pi } [/tex]

[tex]Resistance = 1.375 * 10^{-4} [/tex]Ω

A terrorist throws a grenade with a 6.00 second fuse off a building 150.0 m high at a speed of 10.0 m/s. If the angle at which the grenade is thrown is 30° below the horizontal, will the grenade explode before hitting the ground? What is the horizontal distance from the building at which the grenade will land.

Answers

Here we have a projectile motion. It is type of motion that is made of a vertical shot and a horizontal shot. This is how we will solve it.

Firste step is to find horizontal and vertical component of a speed.
[tex] v_{0x} =v_{0} * cos \alpha [/tex] \\ v_{0y} = v_{0} * sin \alpha [/tex]

We are given this information:
[tex]v_{0} = 10 m/s \\ h=150m \\ \alpha =-30°[/tex]
Angle is negative because it is below the horizontal.

VERTICAL SHOT
Time needed for a grenade to fall to the bottom of a building is given by a formula:
[tex]t= \frac{ v_{0y} }{g} \\ t= \frac{v_{0} * sin \alpha}{g} \\ t= \frac{-10*sin(-30)}{9.81} \\ t=0.51s[/tex]
We used negative value for a speed because it is considered that upwards shot has positive value and downwards shot has negative value.

The grenade will not explode before it hits the ground.


HORIZONTAL SHOT
The horizontal distance from the building at which the grenade will land is called range. The formula for a range is given by:
[tex]R= v_{0x} * \sqrt{ \frac{2h}{g} } \\ R=v_{0} * cos \alpha* \sqrt{ \frac{2h}{g} } \\ R=10*cos(-30)* \sqrt{ \frac{2*150}{9.81} } \\ R=47.89m[/tex] 

The grenade will hit the ground at distance of 47.89m.

Consider a space pod somewhere between earth and the moon, at just the right distance so that the gravitational attractions to earth and the moon are equal. IS this location nearer earth or the moon?

Answers

look up   Lagrange points
there  are 5 of them
L1  is closer to the moon than earth
L3   and L4    are equal distance    from the earth to moon


Final answer:

The location in space where Earth's and the Moon's gravitational attractions are equal is closer to the Moon due to its significantly lesser mass compared to Earth. By applying Newton's law of universal gravitation, it can be deduced that this point must be nearer the Moon, as Earth's stronger gravitational force diminishes with increasing distance.

Explanation:

The gravitational attraction between two objects depends on both their masses and the distance between them, according to Newton's law of gravitation. The force of gravity is proportional to the product of the two masses and inversely proportional to the square of the distance between their centers of mass. Based on the data provided, the Earth's gravitational force is much stronger than that of the Moon due to its greater mass. However, as the distance from the Earth increases, its gravitational pull weakens.

Given that the mass of the Moon is about 1/81 of the Earth's mass and the distance from the Earth to the Moon is approximately 3.80×105 km, there exists a point where the gravitational forces exerted by Earth and the Moon on an object are equal, known as the Lagrange point L1. This point is closer to the Moon than to Earth because the Moon's weaker gravitational force requires a shorter distance to match the stronger gravitational force of the Earth. To find this exact point, one would use the formula from Newton's law of gravitation and set the forces equal to each other, solving for the distance from Earth at which this equilibrium occurs.

Considering the information provided about the distances and gravitational forces, we can infer that the space pod mentioned in the question, at the point where Earth's and the Moon's gravity cancel each other out, would indeed be closer to the Moon. This is a consequence of the vast difference in mass between the Earth and the Moon and the inverse-square law of gravity.

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