Cereal plants gain chemical potential energy as they grow. Which form of energy is converted to create the chemical potential energy? A. gravitational potential energy B. kinetic energy C. light energy D. thermal energy

The answer would be A or D. The most appropriate answer would be D. Hope I helped :)

Gasoline fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

Answer:

Hydrogen fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

Answer:

analyzing what data means

diagram showing the correlation between two quantities

Explanation:

Graph is the plot of two physical quantities and it describes the relation between both quantities. It gives a specific relation between the two physical quantities which is used to analyze the result.

Thus, the following options are correct,

analyzing what data means

diagram showing the correlation between two quantities

Answer: Analyzing what data means, diagram showing the correlation between two quantities, and predicting outcomes and patterns.

The first, third, and forth.

Given:

Time taken for the travel: 40 mins=2400 secs

Velocity: 1.2m/s

Speed and velocity have the same magnitude. Speed is a scalar where as velocity is a vector quantity.

Distance traveled= speed x time.

Distance traveled: 1.2 x 2400=2880m

The kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.

The kinetic energy of the roller coaster at the bottom of the hill is twice its kinetic energy at the top of the hill.

To find the kinetic energy (KE) of the roller coaster, we use the formula:

[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]

where [tex]\( m \)[/tex] is the mass of the object and [tex]\( v \)[/tex] is its velocity.

Given that the mass [tex]\( m \)[/tex] of the roller coaster car is 100 kilograms, and its speed [tex]\( v \)[/tex] at the top of the hill is 3 meters/second, we can calculate the kinetic energy at the top of the hill as follows:

[tex]\[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times (3 \text{ m/s})^2 \] \[ KE_{top} = \frac{1}{2} \times 100 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 50 \text{ kg} \times 9 \text{ m}^2/\text{s}^2 \] \[ KE_{top} = 450 \text{ J} \][/tex]

Since the speed of the roller coaster car doubles at the bottom of the hill, its new speed [tex]\( v_{bottom} \)[/tex] is:

[tex]\[ v_{bottom} = 2 \times 3 \text{ m/s} = 6 \text{ m/s} \][/tex]

The kinetic energy at the bottom of the hill is:

[tex]\[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times (6 \text{ m/s})^2 \] \[ KE_{bottom} = \frac{1}{2} \times 100 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 50 \text{ kg} \times 36 \text{ m}^2/\text{s}^2 \] \[ KE_{bottom} = 1800 \text{ J} \][/tex]

Therefore, the kinetic energy of the roller coaster at the bottom of the hill is 1800 joules, which is indeed twice the kinetic energy at the top of the hill (450 joules). This confirms the statement that the car has joules of kinetic energy at the bottom of the hill, which is twice its kinetic energy at the top.

As per Newton's II law we can say force applied on an object is product of mass and acceleration

[tex]F = ma[/tex]

given that

Force = 140 N

mass = 32.5 kg

now we can use above formula

[tex]140 = 32.5* a[/tex]

[tex]a = \frac{140}{32.5}[/tex]

[tex]a = 4.31 m/s^2[/tex]

so its acceleration must be 4.31 m/s^2

Kinetic energy of anything is (1/2) (mass) (speed)² .

Your kinetic energy just before you snap back up (? ?) is

(1/2) (your mass in kilograms) (50 m/s)² =

(1/2) (your mass in kilograms) (2,500 m²/s²) =

(1,250 x your mass in kilograms) .  The unit is Joules.

The car's (average) acceleration would be

[tex]a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]

The car's position over time would be given by

[tex]x=v_0t+\dfrac12at^2[/tex]

so that after 2.4 seconds, the car will have traveled a distance of

[tex]x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2[/tex]

[tex]\implies x=77.5\,\mathrm m[/tex]

Hello!

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.

* Determine the acceleration of the car....

We have the following data:

V (final velocity) = 46.1 m/s

Vo (initial velocity) = 18.5 m/s

ΔV  (speed interval)  = V - Vo → ΔV  = 46.1 - 18.5 → ΔV  = 27.6 m/s

ΔT (time interval) = 2.4 s

a (average acceleration) = ? (in m/s²)

Formula:

[tex]\boxed{a = \dfrac{\Delta{V}}{\Delta{T^}}}[/tex]

Solving:  

[tex]a = \dfrac{\Delta{V}}{\Delta{T^}}[/tex]

[tex]a = \dfrac{27.6\:\dfrac{m}{s}}{2.4\:s}[/tex]

[tex]\boxed{\boxed{a \approx 11.5\:m/s^2}}\longleftarrow(acceleration)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

* The distance traveled ?

We have the following data:

Vi (initial velocity) = 18.5 m/s

t (time) = 2.47 s

a (average acceleration) = 11.5 m/s²

d (distance interval) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

[tex]d = v_i * t + \dfrac{a*t^{2}}{2}[/tex]

[tex]d = 18.5 * 2.4 + \dfrac{11.5*(2.4)^{2}}{2}[/tex]

[tex]d = 44.4 + \dfrac{11.5*5.76}{2}[/tex]

[tex]d = 44.4 + \dfrac{66.24}{2}[/tex]

[tex]d = 44.4 + 33.12[/tex]

[tex]\boxed{\boxed{d = 77.52\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

________________________________  

[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]

Given:

s(distance)= 20 meters

F(force)=200N

Now we know that

work done= Force applied x distance

Substituting the given values in the above formula we get

Work done= 20 x 200= 4000J

The work done by an elephant while moving a circus wagon 20 meters with a pulling force of 200N is calculated using the formula: Work = Force x Distance. Plugging the values into the formula gives us 4000 Joules.

The work done by the elephant pulling the circus wagon can be calculated using the formula for work, which is Work = Force x Distance. In this situation, the Force applied by the elephant is 200N and the Distance moved by the wagon is 20 meters.

So, the Work done would be: 200N x 20m = 4000 Joules.

This means the work done by the elephant is 4000 Joules.

https://brainly.com/question/35917320

#SPJ3

Object true weight is given as

[tex]mg = 123 N[/tex]

now we know that g = 9.8 m/s^2

[tex]m* 9.8 = 123 [/tex]

[tex] m = \frac{123}{9.8} = 12.55 kg[/tex]

now when it is complete submerged in water its apparent weight is given as 82 N

apparent weight = weight - buoyancy force

apparent weight = 82 N

weight = 123 N

now we have

82 = 123 - buoyancy force

buoyancy force = 123 - 82 = 41 N

now we also know that buoyancy force is given as

[tex]F_b = p_{liq}Vg[/tex]

[tex]41 = 1000*V*9.8[/tex]

[tex]V = \frac{41}{1000*9.8}[/tex]

[tex]V = 4.18 * 10^{-3} m^3[/tex]

now as we know that mass of the object is 12.55 kg

its volume is 4.18 * 10^-3 m^3

now we know that density will be given as mass per unit volume

[tex]density = \frac{m}{V}[/tex]

[tex]density = \frac{12.55}{4.18*10^{-3}[/tex]

[tex]density = 3002.4 kg/m^3[/tex]

so here density of object is 3002.4 kg/m^3

Answer:

3000 kg/m^3

Explanation:

True weight = weight in air = 123 N

Apparent weight = weight in water = 82 N

Loss in weight of the object = true weight - apparent weight

Loss in weight = 123 - 82 = 41 N

According to the Archimedes principle, the loss in weight of the object is equal to the buoyant force acting on the object.

Let V be the volume of the object an d be the density of the object.

Buoyant force = volume of the object x density of water x gravity

41 = V x 1000 x g

[tex]V = \frac{41}{1000 g}[/tex]       .... (1)

Now, true weight = Volume of the object x density of object x gravity

[tex]123 = \frac{41}{1000 g} \times d\times g[/tex]      from (1)

d = 3000 kg/m^3

here tennis ball is accelerated from initial speed zero to final speed 50 m/s

In this accelerated motion the distance moved by the ball is 0.5 m

So here we can use kinematics to find the acceleration of the ball during this distance

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

here given that

vf = 50 m/s

vi = 0

d = 0.5 m

[tex]50^2 - 0 = 2*a*0.5[/tex]

[tex]2500 m/s^2 = a[/tex]

now if we have acceleration during its motion so we can find the applied force by using Newton's II law

[tex]F = ma[/tex]

[tex]F = 0.06*2500[/tex]

[tex]F = 150 N[/tex]

now the applied force will be 150 N on the ball by racket

The "waning gibbous" begins immediately after the Full Moon and lasts about a week.

At the end of the week, the moon is no longer gibbous, but it's still waning.  At the instant it's exactly half-illuminated, it's called "Third Quarter", and then it continuous to wane for another week.

So 3 to 4 days after the END of the waning gibbous phase, it's a Waning Crescent. It still has another 3 to 4 days of waning to go, before it wanes away to nothing and we have the next New Moon.

The waning gibbous phase is the phase between the full and last quarter moon late at night or in the early morning . The waning crescent is the phase that occurs 3-4 days later a waning gibbous.

The waning gibbous phase is the phase between the full and last quarter moon late at night or in the early morning.

The waning gibbous phase moon appears more than half-lighted but less than the full moon. A full sunset is a time when the full moon rises. The rising time of the waning gibbous moon is late at night.

It looks red like a  full moon when it’s near the horizon.

To learn more about the waning gibbous refer to the link ;

https://brainly.com/question/15045629

The correct answer is constant and positive

The velocity is changing with respect to time at constant rate and we know that the change in velocity is known as acceleration so a constant change in velocity with respect to time will give us a constant acceleration. Similarly the velocity is gradually increasing that is why we will take the acceleration as positive .

Answer: constant and positive

Explanation:

Acceleration is the rate of change of velocity. It can be measured in meter per second square.

[tex]a = \frac{dv}{dt}[/tex]

It can be measured from the slope of velocity - time graph.

In the given velocity vs. time graph, the slope is a straight line in the first quadrant. This means the acceleration is uniform (constant) and positive.

Acceleration from the given graph is:

a = change in velocity /time interval = (5-0)m/s/(5-0)s = 1 m/s².

Answer:

THE ANSWER IS D

Explanation:

I DID THE TEST

m = mass of the car = 1500 kg

we know that 1 mph = 0.45 m/s

hence

v = speed gained by the car = 40 mph = 40 x 0.45 m/s = 18 m/s

since the car is gaining speed here , hence the energy need is same as the kinetic energy gained by the car

kinetic energy is given as

KE = (0.5) m v²                     where m = mass , v = speed

inserting the above values in the formula

KE = (0.5) (1500) (18)²

KE = 2.43 x 10⁵ J

we know that , 1 J = 2.78 x 10⁻⁷ kwh

hence

KE = (2.43 x 10⁵) (2.78 x 10⁻⁷)

KE = 0.068 kwh

hence the energy needed is 0.068 kwh

Answer:

Mass of toddler = 12.5 kg

Explanation:

 The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

 Potential energy = 187.5 J

 Height = 1.5 m

 Substituting

     187.5 = m * 10 * 1.5

     m = 12.5 kg

So mass of toddler = 12.5 kg

Answer

The answer to this question is [tex]30 ms^{-1}[/tex]

Explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

[tex]a = (V_f -V_i) /t[/tex]

where

[tex]V_f[/tex] is the final velocity

[tex]V_i[/tex] is the initial velocity

t is the time

a is the accelartion

as we konw

[tex]a = 3 ms^{-2}[/tex]

t = 10 s

From rest So,

[tex]V_i[/tex] = 0

[tex]V_f[/tex] = ?

Putting values

[tex]3 = (V_f - 0)/10[/tex]

[tex]3 * 10 = V_f[/tex]

[tex]30 = V_f[/tex]

[tex]V_f = 30 ms^{-1}[/tex]

So, the right answe is [tex]30 ms^{-1}[/tex]

(3 m/s²) x (10 s) = 30 m/s

His speed at the end of 10 sec is 30 m/s.  We can't describe his velocity, because we have no information about the direction he's moving.

the answer youre looking for is (C

Hi, the answer is A) +2.90%.

mass of car =700kg

Required acceleration =5m/s^2

According to newton's second law

F=ma

F=(700)(5)

F=3500 Kgm/sec^2

Answer:3500

Explanation: mass of car =700 kg

Required acceleration =5 m/s^2

According to newton's second law

F=ma

F=(700)(5)

F=3500 K gm/sec^2

Answer:

 Length of displacement vector = 7.51 m

Explanation:

 Consider east as positive X axis and North as positive Y axis.

 Eric headed 6 meters east, Displacement = 6 i

 Then he headed X meters north, Displacement = X j

 Total displacement = 6 i + X j

  Angle it makes with horizontal axis, θ = tan⁻¹(X/6) = 37°

  X/6 = tan 37

   X = 4.52 m

Total displacement = 6 i + 4.52 j

Magnitude = [tex]\sqrt{6^2+4.52^2} =7.51m[/tex]

 Length of displacement vector = 7.51 m

The answer is A. 7.5.

(D) decreases, inverse

Average speed of a body is defined as the ratio of the distance traveled to the time taken to travel the distance. The runner runs the same distance  of 400 m during each lap but takes 5 seconds more for each lap.

Since [tex]v_a_v_g=\frac{d}{t}[/tex], as time increases, the average speed for each lap increases.

Thus, [tex]v\alpha \frac{1}{t}[/tex] when the distance traveled is the same. This is an example of an inverse proportionality relationship.

given that initial speed of the car is

[tex]v_i = 8.9 m/s[/tex]

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

[tex]0 - 8.9^2 = 2 a d[/tex]

here we have

[tex]- 79.21 = 2*(18)*a[/tex]

[tex]a = -2.2 m/s^2[/tex]

net force applied due to brakes of car is given by Newton's II law

[tex]F = ma[/tex]

here we have

mass = 1.2 * 10^3 kg

[tex]F_{net} = 1.2 * 10^3 * 2.2[/tex]

[tex]F_{net} = 2.64 * 10^3 N[/tex]

now we can say

[tex]F_{net} = F_1 + F_2[/tex]

[tex]2.64 * 10^3 = 1.8 * 10^3 + F_2[/tex]

[tex]F_2 = 8.4 * 10^2 N[/tex]

So the force applied due to brakes is given as above

Pascal's law (also Pascal's principle or the principle of transmission of fluid-pressure) is a principle in fluid mechanics that states that a pressure change occurring anywhere in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere.

Answer: The pressure at two pistons within an enclosed fluid system is always the same.

Explanation:

-- reduce the length of a wire to 1/2 . . . cut the resistance in half

-- reduce the diameter to 1/4 . . . reduce the cross-section area by (1/4²) . . . increase the resistance by 16x .

-- R2 = (R1) · (1/2) · (16)  =  8 · R1

-- R2 / R1  =  8

Tension in the rope due to applied force will be given as

[tex]F = 142 N[/tex]

angle of applied force with horizontal is 37 degree

displacement along the floor = 6.1 m

so here we can use the formula of work done

[tex]W = F d cos\theta[/tex]

now we can plug in all values above

[tex]W = 142 * 6.1 * cos37[/tex]

[tex]W = 691.8 J[/tex]

So here work done to pull is given by 691.8 J

The primary energy exhibited is:

friction:  Heat energy

Due to friction. there is heat loss in mostly all machines.

nuclear power plant:  Nuclear energy

In nuclear power plant, fission or fusion of radio-active substances produces large amount of nuclear energy.

toaster element:  Heat energy

Heat energy is produced in the toaster when electricity passes through the element. This is used to heat the toasts.

welding torch:  Heat energy

The heat energy produced in the welding torch is used in welding.

eraser sitting on a desk edge:  Potential energy

Potential energy is possessed by a body due to virtue of its height.

light bulb:  Heat energy and light energy.

The element inside the bulb gets heated first and then light energy is produced.

campfire:  Heat energy

Heat is produced and then light energy in case of campfire.

moving car:  Kinetic energy

A moving body has kinetic energy.

lump of coal in a storage bin:  Potential energy

A lump of coal in a storage bin has potential energy.

stick of TNT: potential energy

Stick of TNT is formed of explosive mixture. It contains potential energy.

Answer:

• Friction ( heat )

• Nuclear power plant ( nuclear )

• Toaster element ( heat )

• welding torch ( heat )

• eraser sitting on a desk edge (potential)

• light bulb ( light )

• campfire ( heat )

• moving car ( kinetic )

• lump of coal in a storage bin ( potential )

• stick of tent ( potential)

Explanation: hope this helps !

The mass of the baking soda was 80 g

Answer: the mass is 80g

Explanation: In a solution of 140g, we knot that there are 60g of vinegar, the only other component in the solution is baking soda.

Now we want to find the mass of the baking soda in the solution.

Because there are only two components in the solution, if we remove the 60g of vinegar, the residue mass is the mass of the baking soda.

then we need to calculate:

Mass = 140g - 60g = 80g

So the mass of baking soda in the solution is 80g.

i believe the answer is water vapor

hope this helps

Answer:

WATER VAPOR

Explanation:

I got a 100% on my test