Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. There is a Fischer projection for D-tagatose. The carbon chain is depicted vertically, with a CH2OH group bonded to a CO group at the top and a CH2OH group at the bottom, while the three remaining carbon atoms are represented by the center of crossing lines. The tagatose molecule has all hydroxyls but the third one (from top to bottom) on the left and hydrogens opposite to them.

Answers

Answer 1

Final answer:

Tagatose is a ketohexose, a type of carbohydrate with a ketone group in the middle of its six-carbon chain and considered to be a D-sugar due its hydroxyl group orientation on the fifth carbon.

Explanation:

The carbohydrate tagatose can be classified by both the type of carbonyl group present and the number of carbon atoms in the molecule. Since tagatose has a carbonyl group in the middle of the carbon chain, it is classified as a ketose. Furthermore, because tagatose has six carbon atoms, it is called a hexose.

In the Fischer projection of D-tagatose, the presence of the carbonyl group linked to two other carbon atoms indicates that it is a ketonic sugar, hence a ketose. Additionally, since the molecule is a six-carbon sugar, it can further be categorized as a hexose. The D- configuration designation comes from the orientation of the hydroxyl group on the fifth carbon, and in the case of D-tagatose, this group is positioned on the right, confirming its D-configuration.


Related Questions

A solution containing 1.0 M NiCl2 and 1.0 M SnBr2 undergoes electrolysis by passing a current between two platinum electrodes. What are the most likely first products to be formed? Cl2 (aq) + 2e- → 2Cl- (aq) ℰ°= 1.36 V Br2 (aq) + 2e- → 2Br- (aq) ℰ° =1.08 V Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V Ni2+ (aq) + 2e- → Ni(s) ℰ°= -0.24 V

Answers

Answer:

Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V

Explanation:

A close look at all the options shows that the most feasible first reaction is the reduction of tin II ion to ordinary metallic tin.

Given the two half cells, nickel is oxidized in one half cell to Ni II while in the second half cell, tin II ion is reduced to metallic tin. The platinum electrodes simply act as electron conduits in the cell.

18.53 For CaO, the ionic radii for Ca2 and O2 ions are 0.100 and 0.140 nm, respectively. If an externally applied electric field produces a 5% expansion of the lattice, compute the dipole moment for each Ca2O2pair. Assume that this material is completely unpolarized in the absence of an electric field.

Answers

Answer:

[tex] = 1.92*10^-^3^0 C.m[/tex]

Explanation:

Given:

[tex] r_ca_^2_^+ = 0.100 nm[/tex]

[tex] r_o_^2_^- = 0.14 nm [/tex]

Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:

[tex] d = r_ca_^2_^+ + r_o_^2_^- [/tex]

d = 0.100 nm + 0.140 nm

= 0.240 nm

Let's also calculate the distance of separation between anion and cation when there is an applied electric field.

We use the formula:

∆d = 5%d => 0.05d

= 0.05 * 0.024 nm

∆d = 0.0120 nm

[tex]0.120* 10^-^9m[/tex]

[tex]= 1.20*10^-^1^1m[/tex]

Given magnitude of each dipole= [tex]1.602*10^-^1^9 C [/tex]

Let's find the dipole moment, with the formula:

p = q∆d

Substituting figures in the formula, we have:

[tex]p = 1.602*10^-^1^9 * 12*10^-^2^1 [/tex]

[tex] = 1.92*10^-^3^0 C.m[/tex]

Answer:

Explanation:

Answer:

= 1.92*10^-^3^0 C.m

Explanation:

Given:

r_ca_^2_^+ = 0.100 nm

r_o_^2_^- = 0.14 nm

Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:

d = 0.100 nm + 0.140 nm = 0.240 nm

Let's also calculate the distance of separation between anion and cation when there is an applied electric field.

We use the formula:

∆d = 5%d => 0.05d

= 0.05 * 0.024 nm

∆d = 0.0120 nm

0.120* 10^-^9m

= 1.20*10^-^1^1m

Given magnitude of each dipole= 1.602*10^-^1^9 C

Let's find the dipole moment, with the formula:

p = q∆d

Substituting figures in the formula, we have:

p = 1.602*10^-^1^9 * 12*10^-^2^1

= 1.92*10^-^3^0 C.m

When the system is at equilibrium, it contains NO 2 at a pressure of 0.817 atm , and N 2 O 4 at a pressure of 0.0667 atm . The volume of the container is then reduced to half its original volume. What is the pressure of each gas after equilibrium is reestablished

Answers

Final answer:

When the system is at equilibrium with specific initial pressures and the volume of the container is reduced by half, the pressure of each gas changes accordingly.The pressure of NO₂ will be 1.634 atm, and the pressure of N₂O₄ will be 0.1334 atm.

Explanation:

When the system is at equilibrium, it contains NO₂at a pressure of 0.817 atm, and N₂O₄ at a pressure of 0.0667 atm. If the volume of the container is reduced to half its original volume, the pressure of each gas will change.

According to the ideal gas law, the pressure of each gas will double when the volume is reduced by half. So, after re-establishing equilibrium, the pressure of NO₂ will be 1.634 atm, and the pressure of N₂O₄ will be 0.1334 atm.

what equation represents a chemical equilibrium?

Answers

The equation which represents the chemical equilibrium is  2 NO₂ ⇄ N₂0₄

Explanation:

The equation which represents the chemical equilibrium is

           2 NO₂ ⇄ N₂0₄.

A chemical reaction is in equilibrium at the combinations of reactants and products are even  and their ratio does not change In other words, the equilibrium can be defined as the system is in equilibrium when the forward and backwards reactions happen at regular rates.The idea of chemical equilibrium was formed after Berthollet found that some chemical reactions are reversible.

It is common for students to overshoot the endpoint, meaning they add too much NaOH(aq) from the buret, which causes the solution to turn bright pink. What specific impact does this mistake have on the percent of acetic acid result?

Answers

Answer: the percentage of acetic acid will be low.

Explanation: The major aim during titration of acids and bases is to  determine the endpoint , that is exact point where the acid  in the beaker changes colour, (in this case, pink )with an additional  drop from the burette containing the base, since it is usually difficult to mark the equivalence point that tells us when  all the substrate in the beaker has been neutralized completely with the buretted substance.

Overshooting the end point is  an error which can occur when the person involved in the  the titration accidently goes beyond this  endpoint by adding too much of the substance(base) from the burette into the beaker missing the exact endpoint.

This implies that the person  has  added too much of the burreted liquid, ie the base than required  , making the acid in the beaker to continue to react resulting  to a lower concentration of the acid (acetic acid)  with excess base.(NaOH)

A chemistry student needs 75 g of thiophene foran experiment. He has available 0.50 kg of a 29.3% w/w solution of thiophene in carbon tetrachloride.
Calculate the mass of solution the student should use. Ifthere's not enough solution, press the "No solution" button.

Answers

Answer: The mass of solution the student should use is 256 g

Explanation:

Given : 29.3 % w/w which means that 29.3 g of solute is present in 100 g of solution

Thus 100 g of solution contains = 29.3 g of solute

0.50 kg or 500 g of solution contains = [tex]\frac{29.3}{100}\times 500=146.5[/tex] g of solute   (1kg=1000g)

146.5 g of solute is available in = 500 g of solution

Thus 75 g of solute is available in = [tex]\frac{500}{146.5}\times 75 g=256g[/tex] of solution

Thus the mass of solution the student should use is 256 g

A student went to the dentist and found out that he had a cavity. He always brushes his teeth twice a day, so he didn't understand how he got a cavity. The dentist told him that drinking things every day that are acidic, such as lemonade, can contribute to cavities. He didn't drink lemonade but does drink a variety of other drinks.



The next day he brought in a sample of each drink and asked his science teacher to borrow a pH probe to test each liquid. The pH of Drink A is 11.9, Drink B is 7.0, Drink C is 5.3, Drink D is 9.8, Drink E is 2.4. Explain which drink(s) the student should avoid if he wants to protect his teeth from further damage.



In your response, be sure to include:

1. an explanation of what pH measures

2. which drinks are acidic, basic, and neutral.

Answers

Answer:E is an acidic

Explanation:

Soo he should avoid the drink E and in pH measurement the more acidic is below 7 and the the more alkali is above 7 and the neutral drink is B and it may a water ...

what was the purpose of running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot (an overlay of ferrocene and the product mixture) prior to conducting the column chromatography portion of the experiment?a. All of the belowb. To determine the elution in a chromatography column of the starting material and productsc. To determine if there was starting material still present in the reactiond. To identify the number of products of the reaction

Answers

Answer:

a. All of the below

Explanation:

Column chromatography in chemistry is a chromatography method used to isolate a single chemical compound from a mixture.

TLC can be used to analyze a chemical reaction to determine if the reactants have been consumed and a new product has formed. Running a tlc of ferrocene, the acetylferrocene product mixture, and co-spot, when you view the TLC plate under a UV light, you will notice that acetylferrocene product is on the right-most lane, this shows that the reaction appears to be a success: the higher spot of ferrocene has been consumed), and a new product spot is present. From these we can observe that the we can use this to identify the number of products of the reaction, determine if the starting material is still present in the reaction and the elution in a chromatography column of the starting material and products. Therefore, all the choices are correct.

Assuming that there is a constant partial pressure for oxygen, according to Le Châtelier’s Principle which of the following occurs when body temperature decreases during hypothermia?

Answers

Answer:

B. The amount of oxygen will decreases

Explanation:

According to Le Châtelier’s Principle, when the condition of the system changes the equilibrium will shift to compensate for the changes. When temperature decrease, the pressure will also decrease and this will shift the equilibrium to the side with exothermic reaction or less molecule count.

The question is not giving the equilibrium reaction of oxygen, so I assume its

O2 + Hb = HbO2

Since the number of molecules in the right side is lower, then the number of oxygen will decrease since the reaction will shift to the right.

How much heat is required to vaporize a 3 g ice cube initially at 0◦C? The latent heat of fusion of ice is 80 cal/g and the latent heat of vaporization of water is 540 cal/g. The specific heat of water is 1 cal/(g · ◦ C). Answer in units of cal.

Answers

Answer : The amount of heat required is, 2160 cal.

Explanation :

The process involved in this problem are :

[tex](1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(3):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)[/tex]

The expression used will be:

[tex]Q=[m\times \Delta H_{fusion}]+[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{vap}][/tex]

where,

[tex]Q[/tex] = heat required for the reaction = ?

m = mass of ice = 3 g

[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]1cal/g^oC[/tex]

[tex]\Delta H_{fusion}[/tex] = enthalpy change for fusion = [tex]80cal/g[/tex]

[tex]\Delta H_{vap}[/tex] = enthalpy change for vaporization = [tex]540cal/g[/tex]

Now put all the given values in the above expression, we get:

[tex]Q=[3g\times 80cal/g]+[3g\times 1cal/g^oC\times (100-0)^oC]+[3g\times 540cal/g][/tex]

[tex]Q=2160cal[/tex]

Therefore, the amount of heat required is, 2160 cal.

Final answer:

To vaporize a 3 g ice cube initially at 0°C, a total heat of 2160 cal is required. This includes the heat required to melt the ice, heat the melted ice to water's boiling point, and vaporize the water.

Explanation:

The process to vaporize a 3 g ice cube at 0°C consists of three steps. First, the ice cube needs to melt. This requires an amount of heat given by Q = mass x latent heat of fusion. i.e., Q = 3 g x 80 cal/g = 240 cal.`

Then, the water obtained from melted ice at 0°C needs to be heated up to 100°C. The required heat is Q = mass x specific heat x ΔT, i.e., Q = 3 g x 1 cal/g°C x (100°C-0°C) = 300 cal.

Finally, the 100°C water needs to be vaporized. This requires an amount of heat given by Q = mass x latent heat of vaporization. i.e., Q = 3 g x 540 cal/g = 1620 cal.

So, the total heat required to vaporize a 3 g ice cube initially at 0°C is 240 cal + 300 cal + 1620 cal = 2160 cal.

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If'substance X is a liquid, substance Y is a gas, and substance Z is a solid, and all are at the
same temperature and pressure, then the order of increasing strength of their intermolecular
forces would be

Answers

The answer is Y < X < Z

Final answer:

The order of increasing strength of intermolecular forces for substance X (liquid), Y (gas), and Z (solid) is: Y < X < Z, with the gas having the weakest and the solid having the strongest intermolecular forces.

Explanation:

If we consider substances X, Y, and Z, which are a liquid, a gas, and a solid respectively, and they are all at the same temperature and pressure, the order of increasing strength of their intermolecular forces can be determined based on their states of matter. Given that substances with stronger intermolecular forces are more likely to be a solid at room temperature and will have a higher boiling point, it follows that the solid will have the strongest forces, followed by the liquid, and then the gas. Consequently, substance Z (the solid) would have the strongest intermolecular forces, substance X (the liquid) would have intermediate forces, and substance Y (the gas) would have the weakest forces.

What is the best method for removing water from a hydrated compound?

Answers

Answer:

Heating is the best method

Explanation:

When a mass of crystals containing Water of crystallization is heated sufiiciently to a high temperature, water vapor may be driven off the crystals by the action of heat alone.

Answer:

Heating to remove water of crystallizationPassing through a drying agent (deliquescent or hygroscopic substances)

Explanation:

If solid/crystals, compound can be dried by applying heat to remove the water of crystallization.

Drying agents are also utile in removing moisture from compounds in a dessicator. Substances which absorb water from air can be used as drying agents for gases. For instance, [tex]CaCl_{2}[/tex], CaO or silica gel is suitable for drying gases, depending on reactivity of the substance.

Nascar fans love race day when they get a chance to cheer on there favorite racer if a driver was able to travel 600 miles in 3 hours what was his average speed ( in miles per hour

Answers

Answer:

200 mph

Explanation:

600/3=200

The volume of a sample of N2 gas was decreased from 13.81 to 3.63 L. If the final pressure exerted by the N2 sample was 261.1 kPa, what pressure did the N2 exert before its volume was decreased?

Answers

Answer: 68.6 kPa

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=?\\V_1=13.81L\\P_2=261.1kPa\\V_2=3.63L[/tex]

Putting values in above equation, we get:

[tex]P_1\times 13.81L=261.1\times 3.63L\\\\P_1=68.6kPa[/tex]

Thus pressure  before its volume was decreased was 68.6 kPa

A container holds 20.4 L of CO2 at 1.58 atm, what is the volume at STP?


Answers

Answer:

32.232 L

Explanation:

-Given the volume at 1.58atm is 20.4 L

-At standard pressure, the pressure is 1.00atm

-We apply Charle's Law to find the volume at STP:

[tex]P_1V_1=P_2V_2\\\\\\1.58\ atm\times 20.4\ L=1.00\ atm\times V_2\\\\V_2=\frac{1.58\times 20.4}{1.00}\\\\\\\\=32.232\ L[/tex]

Hence, the volume of the gas at STP is 32.232 L

HELP PLEASE (If you cant answer all, that okay! First to answer all will be mark BRAINLIEST!)
(They need to be matched to the correct definition!)
~~~~~~~~~~~~~~
Periodic table
~~~~~~~~~~~~~~
Antoine Lavoisier ~ used patterns to predict undiscovered elements
Dmitri Mendeleev ~ Divided elements into four categories
John Newlands ~created groups of three elements, each based on
Johann Wolfgang Dobereiner similar properties
~Arranged elements according to their atomic
mass

Answers

Final answer:

Antoine Lavoisier divided elements into four categories. Dmitri Mendeleev arranged elements by atomic mass and predicted undiscovered elements. Johann Wolfgang Dobereiner created groups of three elements based on similar properties, whereas John Newlands also arranged elements by atomic weights and predicted some properties of missing elements.

Explanation:

The Periodic Table has been created thanks to several scientists who categorized elements by different methods. Antoine Lavoisier, known as the father of modern chemistry, divided elements into four categories: gases, non-metals, metals, and earths. Consequently, the scientist who divided elements into four categories was Antoine Lavoisier. Dmitri Mendeleev arranged elements according to their atomic mass and used this order to predict the properties of undiscovered elements. Hence, Dmitri Mendeleev is the scientist who used patterns to predict undiscovered elements. Johann Wolfgang Dobereiner, suggested a law of triads, where patterns among groups of three elements were identified based on their properties. Thus, Dobereiner is the scientist who created groups of three elements, each based on similar properties. Lastly, John Newlands arranged elements in order of atomic weights, predicting some properties of missing elements.

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The pressure on a 200 milliliter sample of CO2 (g) at constant temperature is increased from
600 mmHg to 1200 mmHg. What is the new volume?
(1 Point)
100 mL
300 mL
400 ml
600 mL

Answers

The answer for the following problem is mentioned below.

Therefore the final volume of the gas is 100 ml.

Explanation:

 Given:

Initial pressure ([tex]P_{1}[/tex]) = 600 mm of Hg

Final pressure ([tex]P_{2}[/tex]) = 1200 mm of Hg

Initial volume ([tex]V_{1}[/tex]) = 200 ml      

To find:

Final volume ([tex]V_{2}[/tex])

We know;

According to the ideal gas equation,

    P × V = n × R × T

Where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So,

 From the above mentioned equation,

        P × V = constant

[tex]\frac{P_{1} }{P_{2} }[/tex] = [tex]\frac{V_{1} }{V_{2} }[/tex]

Where,

([tex]P_{1}[/tex]) represents the initial pressure of the gas

([tex]P_{2}[/tex]) represents the final pressure of the gas

([tex]V_{1}[/tex])  represents the initial volume of the gas

([tex]V_{2}[/tex])  represents the final volume of the gas

So;

[tex]\frac{600}{1200}[/tex] = [tex]\frac{V_{2} }{200}[/tex]    

[tex]V_{2}[/tex] = 100 ml

Therefore the final volume of the gas is 100 ml.                                                                                                                                                                              

Final answer:

Using Boyle's Law, which states that the product of pressure and volume for a gas is constant at a fixed temperature, it is calculated that the new volume of the CO2 (g) sample when the pressure is doubled to 1200 mmHg at constant temperature is 100 mL.

Explanation:

The question asks about the change in volume of a gas sample when the pressure is increased while keeping the temperature constant. This scenario is described by Boyle's Law, which states that for a given mass of gas at constant temperature, the volume of the gas varies inversely with the pressure. The initial condition for the CO2 (g) is 200 mL at 600 mmHg, and after the pressure is increased to 1200 mmHg, we want to find the new volume.

Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively. Using this relationship, when P1 = 600 mmHg, V1 = 200 mL, P2 = 1200 mmHg, we need to solve for V2. When we plug these values into the equation, we get V2 = (P1 * V1) / P2 = (600 mmHg * 200 mL) / 1200 mmHg = 100 mL.

Therefore, the new volume of the CO2 (g) sample when the pressure is increased to 1200 mmHg at constant temperature is 100 mL.

Which of the following best defines an acid?
An acid has a pH of 7.
An acid has hydroxide ions.
An acid has fewer positive ions in solution.
An acid has more hydrogen ions in solution.

Answers

Answer: An acid has more hydrogen ions in solution.

Explanation: Acids increase hydrogen/hydronium ion concentration in a solution, have pH's less than seven, have a low hydroxide concentration, and increase positive ions in a solution.

The correct definition of an acid is: An acid has more hydrogen ions in solution. Thus, the correct answer is option with 'An acid has more hydrogen ions in solution'.

An acid is characterized by its ability to increase the concentration of hydrogen ions (H⁺) when dissolved in water. This results in a pH lower than 7, indicating increased acidity. The pH scale measures the acidity or basicity of a solution; acids have pH values less than 7.

For example, hydrochloric acid and vinegar are common acids, and they taste sour.

Let's understand other options given:

An acid has a pH of 7:

Incorrect. A pH of 7 is neutral. Acids have a pH less than 7.

An acid has hydroxide ions:

Incorrect. Hydroxide ions (OH⁻) are associated with bases, not acids.

An acid has fewer positive ions in solution:

Incorrect. This is not a defining characteristic of acids. Acids specifically have more hydrogen ions (H⁺), which are positive ions.

Therefore, the defining characteristic of an acid is the presence of more hydrogen ions (H⁺) in solution.

A shallow river dries up is an example of


Condensation
Evaporation
Precipitation
Runoff

Answers

Answer:

Evaporation

Explanation:

Evaporation is when liquid becomes a gas which is how the river dried up

A balloon is filled to a volume of 600 mL at a temperature of 20°C . The balloon is been called to a temperature of 100 K. What is the final volume of the balloon

Answers

Answer:

204.78 mL

Explanation:

- use Charle's law and rearrange formula

- change C to K

- Hope this helped! Let me know if you need further explanation.

14.2 grams of Na2 so4 is dissolved in water to make a 2.50 L solution.What is molarity of solution?

Answers

Answer:

The answer to your question is 0.04 M

Explanation:

Data

mass of Na₂SO₄ = 14.2 g

volume = 2.50 l

Molarity = ?

Process

1.- Calculate the molar mass of Na₂SO₄

Na₂SO₄ = (23 x 2) + (32 x 1) + (16 x 4) = 46 + 32 + 64 = 142 g

2.- Calculate the number of moles of Na₂SO₄

                    142 g of Na₂SO₄ ------------------- 1 mol

                     14.2 g of Na₂SO₄ ------------------  x

                                   x = (14.2 x 1) / 142

                                   x = 0.1 moles

3.- Calculate the molarity

Molarity = moles /volume

-Substitution

Molarity = 0.1 / 2.5

-Result

Molarity = 0.04

What is the acronym used to remember if the anode/cathode are negative or positive (Acronym is like L.E.O says G.E.R) *

Answers

Answer:

Explanation:

The terms 'anode' and 'cathode' are applied to electrodes based on the chemistry occurring at a specified electrode. That is, the anode is ALWAYS the site of oxidation and the cathode is ALWAYS the site of the reduction reaction in electrochemical process. The charge (+ or -) results from the chemistry. In Voltaic Cells the anode is always the site of oxidation and is negative (-) and the cathode is the site of reduction and is always positive (+). However, in 'Electrolytic Cells' the charges are opposite at the electrodes. That is, at the electrode where oxidation is taking place in the electrolytic cell the charge on the electrode will be positive (+) and the charge on the electrode where reduction is taking place the charge will be negative (-).

As far as acronyms (or memory devices) one might consider each type cell separately...

Voltaic Cells

Anode => A Negative -ode (always site of oxidation) ... the other electrode is positive and site of reduction.                  

Electrolytic Cells

For electrolytic cells, just remember the electrode charges are opposite those of the Voltaic Cell but the chemistry is always the same. Charge is due to chemistry and type of cell, but anode is always oxidation and cathode is always reduction.      

How would you describe an electron

Answers

Answer:

an electron is part of the 3 things that are in an atom, it has a negative charge

Briefly describe the solvation of sodium chloride to form aqueous solution.

Answers

There are two possibilities

First, they may want you to say that NaCl is bound in a crystal with the Na+’s attracting all the cl-s. Then water comes along and hydrates the ions enabling them to leave one another and enter the solution.

Second, you may be talking about a so called born haver diagram which considers melting and boiling NaCl so that you have a gas of Na+’s and Cl-‘s then you calculate the amount of energy you get when putting the gas ions in water.

What type of reaction occurs between amines and carboxylic acids at room temperature?

Answers

Answer:

Acid-base equilibrium.

Explanation:

At low temperatures the amines react with carboxylic acids as bases and not as nucleophiles. This acid-base reaction is disadvantageous on heating, with the nucleophilic attack that will form the amide prevailing under these conditions.

In these solutions, identify the solute and the solvent. Sea water, a solution composed of a variety of salts dissolved in water. The salt is the . Soda water, a solution composed of carbon dioxide gas dissolved in water. The water is the Air, a solution composed of 78% nitrogen and 21% oxygen. The nitrogen is the .

Answers

Answer:

The solvent is Nitrogen and the solute is oxygen

Explanation:

Normally the solvent always contains higher amount of substance than the solute in a particular solution

Answer:

Sea water, a solution composed of a variety of salts dissolved in water. The salt is the SOLUTE

Soda water, a solution composed of carbon dioxide gas dissolved in water. The water is the SOLVENT

Air, a solution composed of 78% nitrogen and 21% oxygen. The nitrogen is the  SOLVENT

Explanation:

its right on EDGE



1. What mass of the following chemicals is needed to make the solutions indicated?

a. 1.0 liter of a 1.0 M mercury (II) chloride (HgCl2) solution



b. 2.0 liters of a 1.5 M sodium nitrate (NaNO3) solution



c. 5.0 liters of a 0.1 M Ca(OH)2 solution



d. 100 mL of a 0.5 M (NH4)3PO4 solution



2. Calculate the molarity of the following solutions.

a. 12 g of lithium hydroxide (LiOH) in 1.0 L of solution



b. 198 g of barium bromide (BaBr2) in 2.0 L of solution



c. 54 g of calcium sulfide (CaS) in 3.0 L of solution



3. Calculate the volume of each solution, in liters.

a. a 1.0 M solution containing 85 g of silver nitrate (AgNO3)



b. a 0.5 M solution containing 250 g of manganese (II) chloride (MnCl2)



c. a 0.4 M solution containing 290 g of aluminum nitrate (Al(NO3)3)

Answers

The following questions are answered below

Explanation:

1.a. 1.0 liter of a 1.0 M mercury (II) chloride (HgCl2) solution

  1.0 L 1 mol 271.49 g

    L        1 L    1 mol

= 271.49 g

= HgCl₂ = 271.49 g HgCl₂

1.b. 2.0 liters of a 1.5 M sodium nitrate (NaNO3) solution

[tex]\frac{2.0 L}{1}[/tex][tex]\frac{1.5 mol}{L}[/tex][tex]\frac{85.01 g}{1 mol}[/tex]

= 255.03 g

= 255 g NaNo₃

1.c. 5.0 liters of a 0.1 M Ca(OH)2 solution

= 37 g Ca(OH)2

1.d. 100 mL of a 0.5 M (NH4)3PO4 solution

= 7.5 g (NH₄)₃PO₄

2. To find the molarity of the following solutions

2.a. 12 g of lithium hydroxide (LiOH) in 1.0 L of solution

= 0.50 m (LiOH)

2.b. 198 g of barium bromide (BaBr2) in 2.0 L of solution

= 0.33 m (BaBr₂)

2.c. 54 g of calcium sulfide (CaS) in 3.0 L of solution

= 0.25 m (CaS)

3. To find the volume of each solution

3.a. 1.0 M solution containing 85 g of silver nitrate (AgNO3)

= 0.50 L (AgNO₃)

3.b. 0.5 M solution containing 250 g of manganese (II) chloride (MnCl2)

= 4.0 L MnCl2

3.c. 0.4 M solution containing 290 g of aluminum nitrate (Al(NO3)3)

= 3.4 L (Al(NO₃)₃)

Complete the following two statements regarding quantum-mechanical concepts associated with the Bohr model of the atom and refinements that resulted from the wave-mechanical atomic model. " Two important quantum-mechanical concepts associated with the Bohr model of the atom are that electrons are particles moving in _______
Enter your answer for the missing word between words "moving in" and "orbitals" in accordance to the question statement discrete orbitals, and electron energy is quantized into
Enter your answer for the missing word after words "quantized in" in accordance to the question statement levels .
(b) Two important refinements resulting from the wave-mechanical atomic model are that the electron position is described in terms of a Enter your answer for the missing words after words "in terms of a" in accordance to the question statement electron cloud , and electron energy is quantized into both shells and subshells--each electron is characterized by Enter your answer for the missing word after words "is characterized by" in accordance to the question statement quantum numbers."

Answers

Answer:

Two important quantum-mechanical concepts associated with the Bohr model of the atom are (1) that electrons are particles moving in discrete orbitals, and (2) electron energy is quantized into shells. (b) Two important refinements resulting from the wave-mechanical atomic model are (1) that electron position is described in terms of a probability distribution, and (2) electron energy is quantized into both shells and subshells--each electron is characterized by four quantum numbers.

Explanation:

Part A:

The two important quantum-mechanical concepts associated with the Bohr model of the atom are:

(1) Electrons are particles moving in discrete orbitals.

(2) Electron energy is quantized into shells.

Part B:

The two important refinements resulting from the wave-mechanical atomic model are:

That electron position is described in terms of a probability distribution.The electron energy is quantized into both shells and subshells each electron is characterized by four quantum numbers.

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What is the only force that acts between particles of helium gas?

Answers

Answer: The only force that acts between particles of helium gas is Vanderwaal forces.

Explanation:

When molecules are uncharged in nature but still combined together due to the dipole moment of elements then this force holding the molecules together is known as Vanderwaal forces.

This force is weak in nature.

For example, particles of helium gas has Vanderwaal force between its atoms.

Thus, we can conclude that the only force that acts between particles of helium gas is Vanderwaal forces.

__________ is a numerical value assigned to each element to indicate the number of electrons that might be lost, gained, or shared by an atom of that element when it bonds with an ion or an atom of another element to form a compound.

Answers

Answer:

oxidation number

Explanation:

Describes the degree of oxidation of an atom in a chemical compound.

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