Rhyolite has a lower density
Average density of Rhyolite is 2.5 g/cm³ whereas the average density of basalt is 3 g/cm³ So we can say that Rhyolite is less denser.
Rhoylite is more lighter
Rhyolite is either pink or grey whereas basalt is usually grey or black so we can say that Rhyolite has lighter color
Answer C:Basalt is more melfic
Rhyolite is usually considered as felsic, while basalt is mafic. Generally felsic rocks make the bulk of the continental plates, while mafic basalt forms the seafloor.
Answer D:Basalt has more amount of biotite
Basalt has 5% biotite in it whereas Thyloite has very rare amount of biotite in it so we can say that greater amount of biotite is present in Basalt
Answer E:Quartz in Rhyolite may be present in amounts of 25% to 30%. whereas basalt has 20% - 60% quartz amount in it.
Answer 13:Granodiorite is an example of felsic intrusive rock.
Answer 14:Name of a very hard plutonic, igneous rock is Granite.
find the mass of a flying discus that has a net force of 1.05 newtons and accelerates at 3.5 m/s^2
Animals, including humans, need shelter, food, water, air, and space in order to survive. How do animals satisfy their basic needs?
if you come from study island then its all of them
Food, shelter and clothes are basic need of the humans. Animals like tiger hunt the animals in the jungle, some animals leaves on green grass which are abundantly present in the jungle. for shelter they live in the group at suitable place.
What is Animal ?Animals belong to the biological kingdom Animalia and are multicellular, eukaryotic creatures. Animals generally ingest organic matter, breathe oxygen, can reproduce sexually, and form from a hollow ball of cells called a blastula during early development. There are an estimated 7.77 million animal species in existence as of 2022, but only 2.16 million of them have been described, including 1.05 million insects, over 36,000 fish, over 11,700 reptiles, over 11,100 birds, and 6,596 mammals. Animals can be as little as 8.5 micrometres (0.00033 in) or as large as 33.6 metres (110 ft). They construct extensive food webs through their complex interactions with one another and their surroundings. Zoology is the study of animals from a scientific perspective.
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A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg, which initially is at rest as a result of the collision, 'A' is deflected and moves in a speed of 2.1m/s in a direction which is at an angle of 30 degree below the X-axis. 'B' is set in motion at an angle Φ above the X-axis. calculate the velocity of 'B' after the collision.
Which ions are most abundant in an acid?
The hydrogen ion is the most abundant in an acid for it is a bare proton that associates with any water in the molecule, solution or reaction so the H+ ions produced by an acid exist as H3O+ ions.
Moreover, in the Arrhenius theory, an acid is a substance that dissociates to produce H+ ions in solution and a base as a substance that dissociates to produce OH- ions in solution. Meanwhile, in the Bronsted-Lowery theory, an acid is considered as a proton donor.
A uniform bridge 20.0m long and weighing 4.00 x 10^5 N is supported by two pillars located 3.00m from each end. If a 1.96 x 10 ^4N car is parked 8.00m from one end of the bridge. How much force does each pillar exert?
The left support exerts a force of 2.0392 x 10⁵ N and the right support exerts a force of 2.1568 x 10⁵ N on the bridge. This is calculated by considering the total weight supported by the bridge and the location of the car.
Explanation:The problem you are asking about relates to static equilibrium, a concept in Physics. To find the force exerted by each pillar, we must first find the total weight supported by the bridge. The total weight is the sum of the weight of the bridge itself (4.00 x 10⁵ N) and the weight of the car (1.96 x 10^4 N), which gives us a total of 4.196 x 10⁵ N.
The location of the car changes the balance of these forces. The first pillar is 8m from the car and the second pillar is 12m from the car. To find the force on each pillar, we apply the principle that the sum of the moments about any point in a system in equilibrium is zero. Using the left pillar as the point, the moments of the bridge's weight and the car's weight are counterbalanced by the force of the right pillar:
Force_right_pillar = (Bridge_weight * Bridge_mid_point + Car_weight * Distance_from_left_pillar) / Total_bridge_length = ((4.00 x 10⁵ N * 10m) + (1.96 x 10⁴ N * 8m)) / 20m = 2.1568 x 10⁵ N.
The force exerted by the left pillar is then the total weight minus the force on the right pillar: Force_left_pillar = Total_weight - Force_right_pillar = 4.196 x 10⁵ N - 2.1568 x 10⁵ N = 2.0392 x 10⁵ N. So, the left support exerts a force of 2.0392 x 10⁵ N, and the right one exerts a force of 2.1568 x 10⁵ N.
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The forces exerted by the pillars supporting a 20.0m long and [tex]4.00 * 10^5 N[/tex] bridge with a [tex]1.96 * 10^4 N[/tex] car parked 8.00m from one end are approximately [tex]2.13 * 10^5 N[/tex] and [tex]2.07 * 10^5 N[/tex].
To find the forces exerted by each pillar on the uniform bridge, we need to consider the torque (moment of force) and the equilibrium conditions of the bridge.
Here is the step-by-step solution:
Given Data:
Length of the bridge (L) = 20.0 mWeight of the bridge [tex](W_{bridge}) = 4.00 * 10^5 N[/tex]Weight of the car [tex](W_{car}) = 1.96 * 10^4 N[/tex]Distance of each pillar from the end = 3.00 mPosition of the car from one end = 8.00 mThe two pillars provide upward forces labeled as [tex]F_L[/tex] and [tex]F_R[/tex].
1. Identify the distances to center of mass:
Center of mass of bridge from left end = 10.0 mPosition of car from left end = 8.0 m2. Set up equilibrium equations:
Since the bridge is in static equilibrium, the sum of the forces and the sum of the torques must be zero.
Sum of Vertical Forces:
[tex]F_L + F_R - W_{bridge} - W_{car} = 0\\F_L + F_R = 4.00 * 10^5 N + 1.96 * 10^4 N\\F_L + F_R = 4.196 * 10^5 N[/tex]
Sum of Torques about the left pillar (taking counterclockwise as positive):
[tex]-(W_{bridge} * 7.0 m) - (W_{car} * 5.0 m) + (F_R * 14.0 m) = 0\\-(4.00 * 10^5 N * 7.0 m) - (1.96 * 10^4 N * 5.0 m) + (F_R * 14.0 m) = 0\\-2.8 * 10^6 Nm - 9.8 * 10^4 Nm + 14 F_Rm = 0\\14 F_R = 2.898 **10^6 Nm\\F_R = 2.898 * 10^6 Nm / 14 m\\F_R = 2.07 * 10^5 N\\[/tex]
Substitute F_R back into the sum of the forces equation:
[tex]F_L + 2.07 * 10^5 N = 4.196 * 10^5 N\\F_L = 4.196 * 10^5 N - 2.07 * 10^5 N\\F_L = 2.126 * 10^5 N\\[/tex]
Result:
The forces exerted by the pillars are approximately:
[tex]F_L = 2.13 * 10^5 N\\F_R = 2.07 * 10^5 N[/tex]
every 24 hours, about how many hours are spent socializing and watching tv?
Answer:
16+ hours
Explanation:
because they have a job and jobs are long so they would take as much time as they can get
A bullet is fired at a speed of 2434 ft/s. what is this speed expressed in millimeters per minute?
2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?
3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?
As per the first question we have to calculate the height at which the boulder is present.
we have been given the mass of the boulder [m] as 200 kg.
The gravitational potential energy is given as 39,000 Joule.
The gravitational potential energy at a height ' h' from the surface earth is given as P.E= mass×height×acceleration due to gravity
The value of g=9.8 m/s^2
Hence height [h][tex]=\frac{P.E}{mg}[/tex]
=[tex]\frac{39000}{200*9.8} metre[/tex]
=19.8979 metre
As per the second question we have to calculate the sped and height of the model airplane.
the mass of model airplane is 1 kg
The kinetic energy [K.E] of the airplane is 12.5 joule
we have K.E[tex]=\frac{1}{2} mass*speed^2[/tex]
K.E[tex]=\frac{1}{2}mv^2[/tex]
[tex]v^2=\frac{2K.E }{m}[/tex]
[tex]v^2=\frac{2*12.5}{1}[/tex]
[tex]v=\sqrt{25}[/tex]
v=5 m/s
Again we have to calculate the height [h]
The potential energy is given as 98 Joule.
we know that P.E= mgh
tex]h=\frac{P.E}{mg}[/tex]
=[tex]\frac{98}{1*9.8} metre[/tex]
=10 metre
Binary ionic compounds are: Check all that apply.
A.Compounds with very different electronegativities
B.Made from two metals
C.Compounds that share electrons
D.Metals and nonmetal ions
Compounds with very different electronegativities AND metals and non metals.
A 92-kg astronaut and a 2000-kg satellite are at rest relative to a space station. the astronaut pushes on the satellite, giving it a speed of 0.14 m/s directly away from the station. seven and a half seconds later the astronaut comes into contact with the station. part a what was the initial distance from the station to the astronaut?
Answer:
22.8 s
Explanation:
First we calculate the change in momentum of the satellite.
ΔP = 2000 kg (0.14 m/s 0 m/s) = 280 kg·m/s
The change in momentum of the satellite is equal to the change in momentum of the astronaut as a result of Newton's Third law. Therefore:
280 kg·m/s = 92kg * v
v = 3.04 m/s
d = speed * time = 3.04 m/s * 7.5 s = 22.8 m
A weightlifter raises a 200-kg barbell through a height of 2 m in 2.2 s. the average power he develops during the lift is
Answer:
Power, P = 1781.81 watts
Explanation:
It is given that,
Mass of the barbell, m = 200 kg
It is lifted to a height of, h = 2 m
Time taken, t = 2.2 s
We need to find the develops during the lift. We know that the pwer developed by an object is equal to the rate of doing work. Mathematically, it is given by :
[tex]P=\dfrac{W}{t}[/tex]
[tex]P=\dfrac{mgh}{t}[/tex]
[tex]P=\dfrac{200\times 9.8\times 2}{2.2}[/tex]
P = 1781.81 watts
So, the average power developed during the lift is 1781.81 watts. Hence, this is the required solution.
Why can an object still be seen when it is at absolute zero?
HELP!! Physical or chemical property? For the questions..
Sam boards a ski lift, and rides up the mountain at 6 miles per hour. once at the top, sam immediately begins skiing down the mountain, averaging 54 miles per hour, and does not stop until reaching the entrance to the lift. the whole trip, up and down, takes 40 minutes. assuming the trips up and down cover the same distance, how many miles long is the trip down the
A college student holds a pail full of water by the handle and whirls it around in a vertical circle at a constant speed. the radius of this circle is 0.95 m. what is the minimum speed that the pail must have at the top of its circular motion if the water is not to spill out of the upside-down pail
You are given two carts, a and
b. they look identical and you are told that they are made of the same material. you place a at rest on an air track and give b a constant velocity directed to the right so that it collides elastically with
a. after the collision, both carts move to the right, the velocity of b being smaller than what it was before the collision. what do you conclude?
In the described collision, the momentum of cart B is partially transferred to cart A due to the conservation of momentum principle. Hence, cart A starts moving and cart B slows down but continues to move to the right.
Explanation:The scenario you described relates to the physics principle of conservation of momentum. In the collision of the carts, the total momentum before the collision equals the total momentum after the collision. This is because in an elastic collision, both kinetic energy and momentum are conserved. Initially, only cart B had momentum (since it was moving), and cart A was at rest. After the collision, both carts moved to the right, indicating that some of cart B's momentum was transferred to cart A. The fact that cart B moved slower after the collision indicates that it transferred some of its initial momentum to cart A. Hence, we can conclude that cart A gained momentum while cart B lost some but kept enough to continue moving to the right.
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What does the index of refraction directly measure? the angle between the incident ray and the normal line the angle between the refracted ray and the normal line the bending of light in a medium the reflection of light in a medium
Answer:
The answer is The bending of light in a medium.
Explanation:
The refractive index is the dimensionless number that expresses the relationship between the speed of light in the air and the speed of light in the densest medium, that is, the refractive index directly measures the ratio of the velocity of the light in a vacuum and the speed of light in a medium. This phenomenon occurs because the light rays follow a rectilinear path, but when they pass from one means of transport to another, it is refracted, because the light has a velocity distance according to the density of the material it passes through. The refractive index has variables that affect the measurement, which are temperature, wavelength and pressure.
What is the average speed of a human that runs a distance of 5 miles in 1 hour?
Calculate the kinetic energy of an 86-kg scooter moving at 16 m/s
The kinetic energy of an 86 - kilogram scooter moving at 16 m / s would be 11008 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem, we have to calculate the kinetic energy of an 86 - kilogram scooter moving at 16 m / s ,
The mass of the scooter = 86 kilogram
The velocity fo the scooter = 16 meters per second
The kinetic energy of the scooter = 0.5 × m × v²
= 0.5 × 86 × 16²
= 11008 Joules
Thus , the kinetic energy of an 86 - kilogram scooter moving at 16 m / s would be 11008 Joules .
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The kinetic energy of an 86-kg scooter moving at 16 m/s is calculated using the formula KE = ½ mv², resulting in 10,976 Joules or 10.976 kJ of kinetic energy.
To calculate the kinetic energy of an 86-kg scooter moving at 16 m/s, you can use the kinetic energy formula KE = ½ mv², where m is mass and v is velocity. Substituting the given values, we get KE = ½ (86 kg) (16 m/s)². After performing the calculation, the kinetic energy of the scooter is found to be 10,976 Joules or 10.976 kJ.
on Earth, how many grams of mass does it take to produce a force of 1 newton?
A long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point? a long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point? upward west north south downward east
The magnetic field is due east of a long, straight, vertical wire carrying a current upward points downward.
Explanation:The magnetic field created by a long, straight, vertical wire carrying a current upward can be determined using the right-hand rule. According to the right-hand rule, if you point your right thumb in the direction of the current in the wire, your fingers will curl in the direction of the magnetic field.
Since the wire is carrying current upward, the magnetic field will point in the clockwise direction when viewed from above. Therefore, the magnetic field due east of the wire will point downward.
The 2779-m Brooklyn-Battery Tunnel, connecting Brooklyn and Manhattan, is one of the world's longest underwater vehicular tunnels. (a) Determine its fundamental frequency of vibration. (b) What harmonic must be excited so that it resonates in the audio region at 20 Hz or greater?
______________ is a measure of the force of gravity pulling on an object of a given mass.
Describe the image of an object that is 38 cm from a concave mirror that has a focal length of 10 cm.
A concave mirror with a focal length of 10 cm will form a virtual, upright image that is 11.43 cm away from the mirror. The magnification of the image will be -0.301.
Explanation:A concave mirror with a focal length of 10 cm will form an image of an object that is 38 cm away. To determine the characteristics of the image, we can use the mirror equation: 1/f = 1/di + 1/do, where f is the focal length, di is the image distance, and do is the object distance. Rearranging the equation, we get di = 1 / (1/f - 1/do). Plugging in the given values, di = 1 / (1/10 - 1/38) = 11.43 cm.
The negative sign indicates that the image is virtual and upright. Furthermore, to determine the magnification of the image, we can use the formula: magnification = -di / do. Plugging in the values, magnification = -11.43 / 38 = -0.301.
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explain the role that the ant and the acacia tree play in their symbiotic relationships
A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empty space? The Stefan-Boltzmann constant is 5.67 × 10-8 W/(m2 ∙ K4).
A.) 9.9 mW
B.) 3.7 W
C.) 7.1 W
D.) 1.4 kW
How far away from the sun would a planet mercury's size have to be before it would have an atmosphere?
Planet B has a tilt of 45 degrees. What seasonal changes would be expected on this planet?
A. Extreme temperature changes between seasons
B. Little to no change in temperatures between seasons
C. Seasonal changes along the equator only
D. Seasonal changes at the poles only
Answer:
Extreme temperature changes between seasons
Explanation:
If our Earth is at a rotational degree of 23 degrees, then the planet is going to experience bigger changes between how hot and how cold it is going to be.
The work input = _____. Fi × di Fi ÷ di Fo × do Fo ÷ do
a doghouse has a mass of 98 kg, and the coefficient of friction between it and the ground is 0.95. what is the maximum force of friction between the doghouse and the ground?
Answer:
Maximum force of friction, F = 912.38 N
Explanation:
It is given that,
Mass of doghouse, m = 98 kg
Coefficient of friction between doghouse and the ground, μ = 0.95
We have to find the maximum force of friction between the doghouse and the ground. It is given by :
F = μ N
N = normal force = mg
F = μmg
F = 0.95 × 98 kg × 9.8 m/s²
F = 912.38 N
Hence, this is the required solution.