Consider slicing the cube with a plane. What are all the different-shaped slices we can get? One slice, for example, could be a rectangular. What other shaped slices cane we get. Sketch both the shape of the slice and show how it is a slice of the cube?

Final answer:

To find the dimensions of the poster with the smallest area, subtract the margins from the total dimensions of the poster. Set up an equation using the area of the printed material and find the dimensions that result in the smallest area. By substituting different values into the equation, the dimensions are approximately 30 cm by 56 cm.

Explanation:

To find the dimensions of the poster with the smallest area, we need to subtract the margins from the total dimensions of the poster and then find the dimensions that result in the smallest area. Let's assume the width of the poster is x cm and the height of the poster is y cm.

Using the information given, we can set up the following equations:

x - 2(6) = x - 12 cm (effective width)

y - 2(8) = y - 16 cm (effective height)

The area of the printed material is fixed at 390 square centimeters, so we have:

(x - 12) × (y - 16) = 390

To find the dimensions with the smallest area, we can find the derivative of the area equation with respect to either x or y, set it equal to zero, and solve for x or y. However, this is a complicated process. So, we can use a graphing calculator to find the minimum area. By substituting different values for x and y into the area equation, we can find the dimensions that result in the smallest area.

After substituting different values, we find that the dimensions of the poster with the smallest area are approximately 30 cm by 56 cm.

Answer:

  The substitution and addition properties of equality.

Step-by-step explanation:

The substitution property tells you that equals may be substituted for each other at any time.

The addition property of equality tells you that the same quantity can be added to both sides of an equation without violating the equal sign.

So, if you start with the equation ...

  a = b

and you add c to both sides (addition property), you get

  a + c = b + c

and if c = d, this can become (substitution property) ...

  a + c = b + d . . . . . d substituted for c

In other words, we have added the equations

  a = b

  c = d

to get ...

  a + c = b + d

The addition and substitution properties of equality make this valid.

it is b cuz im smart and i know t

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

The probability that a woman has none of the three risk factors, given that she does not have risk factor A, is calculated to be 0.54.

To find the probability that a woman has none of the three risk factors, given that she does not have risk factor A, we will use the given probabilities and apply the principles of probability. Let's denote the probabilities of having only the risk factors as P(A), P(B), and P(C), the probabilities of having exactly two risk factors as P(A and B), P(A and C), and P(B and C), and the probability of having all three risk factors as P(A and B and C).

Given:

P(A) = P(B) = P(C) = 0.1
P(A and B) = P(A and C) = P(B and C) = 0.12
P(A and B and C | A and B) = 1/3

We can calculate P(A and B and C) using the conditional probability:

P(A and B and C) = P(A and B) × P(A and B and C | A and B) = 0.12 × 1/3 = 0.04

To find the probability of not having A, denoted as P(A'), we can use the complement rule:

P(A') = 1 - P(A) - P(A and B) - P(A and C) - P(A and B and C) = 1 - 0.1 - 0.12 - 0.12 - 0.04 = 0.62

Since P(A') includes probabilities of women with neither of the risk factors or only with B or C, we need to subtract the probabilities of having only risk factors B and C:

P(None | A') = P(A') - P(B) - P(C) + P(B and C) = 0.62 - 0.1 - 0.1 + 0.12 = 0.54

The probability that a woman has none of the three risk factors, given that she does not have risk factor A, is thus 0.54.

Answer: 70676

Step-by-step explanation:

First we draw a diagram representing the problem, which can be found in the picture uploaded,

Point a is the point of the plane, you can see where the angle of depression is imputed in the diagram, point C is the point where the gateway arch is, and drawing a vertical line to the ground from the point of the plane, point Blank is where that vertical line touches the ground

So we can tell the the angle of depression from the plane to the arch is the same as the angel of elevation from the arch to the plane

And we are to look for the distance between B and C which is labeled x in the diagram

So looking at the right angle triangle made from this question, we can see we have the opposite length which the angle of elevation from the arch is looking at, and we are looking for the adjacent length, so we use SOH, CAH, TOA, to solve

Choosing TOA which means

Tan(angle) = (opposite length)/(adjacent length)

Tan 23 = 30000/x

Multiplying both sides by x

xtan23 = 30000

Dividing both sides by tan23

x = 30000/tan23

x = 70675.57

Approximately 70676

Answer:

26 million

Step-by-step explanation:

8200000 / 0.32 = 25625000

25625000 rounded to nearest million = 26 million

The total number of college students is 26 million.

Given that, in a recent year, 32% of all college students were enrolled part-time and 8.2 million college students were enrolled part-time that year.

A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.

Let the total number of college students be x.

Now, 32% of x=8.2 million

⇒ 0.32 x=8200000

⇒ x = 8200000/3.2

⇒ x = 2562500

2562500 rounded to nearest million = 26 million

Therefore, the total number of college students is 26 million.

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Answer:

  8.1 hours

Step-by-step explanation:

A model of the fraction remaining can be ...

  f = (1/2)^(t/37) . . . . t in hours

So, for the fraction remaining being 86%, we can solve for t using ...

  0.86 = 0.5^(t/37)

  log(0.86) = (t/37)log(0.5)

  t = 37·log(0.86)/log(0.5) ≈ 8.0509 ≈ 8.1 . . . hours

It takes about 8.1 hours to decay to 86% of the original concentration.

Answer:

The probability that only 1 letter will be put into the envelope with its correct address is [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Given:

Number of Letters=4

Number of addresses= 4

To Find:

The probability that only 1 letter will be put into the envelope with its correct address=?

Solution:

Let us assume first letter goes in correct envelope and others go in wrong envelopes, then

=> Probability putting the first letter in correct envelope =[tex]\frac{1}{4}[/tex]

=>  Probability putting the second letter in correct envelope =[tex]\frac{2}{3}[/tex]

=>  Probability putting the third letter in correct envelope= [tex]\frac{1}{2}[/tex]

=> Probability putting the fourth letter in correct envelope = 1;  

( only 1 wrong addressed envelope is left);

This event can occur with other 3 envelopes too.

Hence total prob. = [tex]4\times(\frac{1}{4}\times\frac{2}{3}\times\frac{1}{2}\times1)[/tex]

=> [tex]\frac{1}{3}[/tex]

Answer:

  1188 in²

Step-by-step explanation:

The area of a parallelogram is the product of its base length and height.

  A = bh = (36 in)(33 in) = 1188 in²

Answer:

Plot the point (3, -5)

Step-by-step explanation:

Recall that the general number a+bi can be plotted on a complex plane with the x axis as the real part and the y axis as the imaginary part.

In short,

a = real part = x

b = imaginary part = y

So (a,b) = (x,y)

In this case, a = 3 and b = -5 which is how I got (3, -5).

It might help to rewrite 3 - 5i into 3 + (-5)i

Answer:

-75.955 kilometers

Step-by-step explanation:

multiply the speed by the time to get distance

the spacecraft is descending, so change in height will most likely be answered as a negative number

13.81 × 5.5 = 75.955

The required change in the height of the spacecraft will be 76 kilometers down.

Given that, an astronaut is returning to earth in a spacecraft. If the spacecraft is descending at a rate of 13.81 kilometers per minute, what will its change be in height after 5 1/2 minutes is to be determined.

Distance is defined as the object traveling at a particular speed in time from one point to another.

Here,
Speed = 13.81 km/s
Time =  5 1 /2 minute = 5+0.5 minute = 5.5 minutes
Distance traveled = speed * time
Distance traveled = 13.81 * 5.5 ≈ 76 km (down)

Thus, the required change in the height of the spacecraft will be 76 kilometers down.

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Answer:Problem 1. Let G be a group and let H, K be two subgroups of G. Dene the set HK = {hk : h ∈ H,k ∈ K}.

a) Prove that if both H and K are normal then H ∩ K is also a normal subgroup of G.

b) Prove that if H is normal then H ∩ K is a normal subgroup of K.

c) Prove that if H is normal then HK = KH and HK is a subgroup of G.

d) Prove that if both H and K are normal then HK is a normal subgroup of G.

e) What is HK when G = D16, H = {I,S}, K = {I,T2,T4,T6}? Can you give geometric description of HK?

Solution: a) We know that H ∩ K is a subgroup (Problem 3a) of homework 33). In order to prove that it is a normal subgroup let g ∈ G and h ∈ H ∩ K. Thus h ∈ H and h ∈ K. Since both H and K are normal, we have ghg−1 ∈ H and ghg−1 ∈ K. Consequently, ghg−1 ∈ H ∩ K, which proves that H ∩ K is a normal subgroup.

b) Suppose that H G. Let K ∈ k and h ∈ H ∩ K. Then khk−1 ∈ H (since H is normal in G) and khk−1 ∈ K (since both h and k are in K), so khk−1 ∈ H ∩ K. This proves that H ∩ K K.

c) Let x ∈ HK. Then x = hk for some h ∈ H and k ∈ K. Note that x = hk = k(k−1hk). Since k ∈ K and k−1hk ∈ H (here we use the assumption that H G), we see that x ∈ KH. This shows that HK ⊆ KH. To see the opposite inclusion, consider y ∈ KH, so y = kh for some h ∈ H and k ∈ K. Thus y = (khk−1)k ∈ HK, which proves that KH ⊆ HK and therefoere HK = KH. To prove that HK is a subgroup note that e = e · e ∈ HK. If a,b ∈ HK then a = hk and b = h1k1 for some h,h1 ∈ H and k,k1 ∈ K. Thus ab = hkh1k1. Since HK = KH and kh1 ∈ KH, we have kh1 = h2k2 for some k2 ∈ K, h2 ∈ H. Consequently,

ab = h(kh1)k1 = h(h2k2)k1 = (hh2)(k2k1) ∈ HK

(since hh2 ∈ H and k2k1 ∈ K). Thus HK is closed under multiplication. Finally,

Step-by-step explanation:

Answer:

The degrees of freedom for the denominator on this case is given by [tex]df_{den}=df_{between}=N-K=3*15-3=42[/tex].

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have [tex]3[/tex] groups and on each group from [tex]j=1,\dots,15[/tex] we have [tex]15[/tex] individuals on each group we can define the following formulas of variation:  

[tex]SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 [/tex]  

[tex]SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 [/tex]  

[tex]SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 [/tex]  

And we have this property  

[tex]SST=SS_{between}+SS_{within}[/tex]  

The degrees of freedom for the numerator on this case is given by [tex]df_{num}=df_{within}=k-1=3-1=2[/tex] where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by [tex]df_{den}=df_{between}=N-K=3*15-3=42[/tex].

And the total degrees of freedom would be [tex]df=N-1=3*15 -1 =44[/tex]

And the F statistic to compare the means would have 2 degrees of freedom on the numerator and 42 for the denominator.  

To minimize the paper used for a poster with a specific print area and margin size, we derive a formula for total paper area, take its derivative with respect to the print width, solve for the width, and then find the matching height.

To find the dimensions of the page that will minimize the amount of paper used for a rectangular poster that contains 81 square inches of print with 5-inch margins on all sides, we need to set up a function to minimize. Let the width of the print area be x inches, and the height be y inches. Therefore, the total dimensions of the poster will be (x + 10) inches wide and (y + 10) inches high due to the margins on each side.

The area of print is given, so x*y = 81. We will minimize the total area of the page, A = (x+10)(y+10). Substituting the value of y from the print area equation, y =[tex]\frac{81}{x}[/tex], we get A(x) = (x+10)([tex]\frac{81}{x}[/tex]+10).

Now, to find the dimensions that minimize the paper used, we will take the derivative of A(x) with respect to x, set it to zero, and solve for x. From there, we can find the corresponding value of y to get the dimensions that will use the least amount of paper while still fitting the print area and margins.

To determine the number of sellable apples, we subtract the number of apples with defects from the total, but add back the ones counted twice due to having multiple defects. The calculation reveals that 75 out of 100 apples can be sold.

To calculate the number of apples that can be sold from the bushel, we need to consider those without worms or bruises. We have 20 apples with worms and 15 with bruises. However, since there are 10 apples that have both worms and bruises, these are counted twice in our total of defective apples.

First, we'll subtract the number of apples with worms (20) and those with bruises (15) from the total number of apples (100), but then we need to add back the ones we subtracted twice, those with both worms and bruises (10). Here's the calculation:

Total apples = 100

Apples with worms = 20

Apples with bruises = 15

Apples with both worms and bruises = 10

Apples that can be sold = Total apples - (Apples with worms + Apples with bruises - Apples with both worms and bruises)

Apples that can be sold = 100 - (20 + 15 - 10) = 100 - 25 = 75 apples can be sold.

75 of the 100 apples can be sold.

To find out how many apples can be sold, we need to determine the number of apples that are neither bruised nor have worms.

Given:

- Total number of apples = 100

- Number of apples with worms = 20

- Number of apples with bruises = 15

- Number of bruised apples with worms = 10

First, let's find the number of apples that have both bruises and worms. We are given that there are 10 bruised apples that have worms, so these apples are counted in both the bruised and worms categories. Therefore, we need to subtract these from the total number of bruised apples to avoid double-counting:

[tex]\[ \text{Number of apples with both bruises and worms} = 10 \][/tex]

Next, let's find the number of apples that have either bruises or worms. This can be done by adding the number of apples with bruises and the number of apples with worms and then subtracting the number of apples with both bruises and worms:

[tex]\[ \text{Number of apples with either bruises or worms} = 15 + 20 - 10 = 25 \][/tex]

Now, to find the number of apples that can be sold (i.e., the number of apples that are neither bruised nor have worms), we subtract the number of apples with either bruises or worms from the total number of apples:

[tex]\[ \text{Number of apples that can be sold} = 100 - 25 = 75 \][/tex]

So, 75 of the 100 apples can be sold.

Answer:c

Step-by-step explanation:

Profit maximization happens with marginal revenue is equal to marginal cost, so if Grant's assumption was right before selling the extra unit, when he actually sells the extra unit, this will increase his revenue

That's why the answer is c

Marginal revenue will exceed marginal cost

Step-by-step explanation:

Let the speed of plane be p and speed of wind be w.

Flying against the wind, an airplane travels 5760 kilometers in 6 hours.

Here

            Speed = (p-w) kmph

            Time = 6 hours

            Distance = 5760 kmph

            Distance = Speed x Time

            5760 = (p-w) x 6

               p-w = 960 -----eqn 1  

Flying with the wind, the same plane travels 6300 kilometers in 5 hours.

Here

            Speed = (p+w) kmph

            Time = 5 hours

            Distance = 6300 kmph

            Distance = Speed x Time

            6300 = (p+w) x 5

               p+w = 1260 -----eqn 2    

eqn 1 + eqn 2

                p-w + p +w =  960 + 1260

                  2p = 2220

                    p = 1110 kmph

Substituting in eqn 2

                1110 + w = 1260

                         w = 150 kmph

Speed of plane = 1110 kmph

Speed of wind = 150 kmph

Answer:

5 (strawberries / hours)

Step-by-step explanation:

calculation fro morning

strawberries / minutes  x   minutes / hours =   strawberries / hours

 so after adding the value in above equation

3/4* 60/1  = 45 strawberries / hours

 calculation in the afternoon

strawberries / minutes  x   minutes / hours =   strawberries / hours

 2/3 x 60/1  =  40 strawberries / hours

 so now by calculating difference between morning and afternoon packing rates,  you can easily calculate

 45-40 = 5 (strawberries / hours)

To find a line parallel to another, determine the slope of the original line, which is 2 in this case, and then use the point-slope form with a given point and the same slope to find the equation, resulting in y = 2x + 9.

To find an equation of the line that is parallel to another, we must first determine the slope of the given line. The line passing through the points (-3, -4) and (1, 4) has a slope calculated by the formula ∆y/∆x = (4 - (-4))/(1 - (-3)) = 8/4 = 2.

Since parallel lines have the same slope, our new line will also have a slope of 2. We can use the point-slope form of a line's equation, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting our known point (-1, 7) and the slope 2, we get y - 7 = 2(x - (-1)). Simplified, the equation of our parallel line is y = 2x + 9.

Answer:

  3/4

Step-by-step explanation:

It can be helpful to use a common denominator for comparison. That denominator can be 100, meaning we can make them all decimal fractions. Approximate (2 digit) values are good enough for the purpose.

  2/3 ≈ 0.67 . . . . left end of the range

  7/9 ≈ 0.78 . . . . right end of the range

  3/5 = 0.60

  6/9 ≈ 0.67 . . . . = 2/3, so is not greater than 2/3

  3/4 = 0.75

  6/7 ≈ 0.86

The only decimal value between 0.67 and 0.78 is 0.75, corresponding to the fraction 3/4.

  2/3 < 3/4 < 7/9

There is no Graph to go in response to this question

Answer:

15

Step-by-step explanation:

to find area you need to do height times base and divide by 2 or multiply it by 1/2.

10 x 3 = 30

30/2 = 15

Answer:

6 miles shorter

Step-by-step explanation:

Right now, Jimmy walked 21 miles. If he had gone diagonally, he would've walked only 15 miles. This is 6 miles shorter than before.

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked [tex]1\frac{1}{5} \text{ or } \frac{6}{5}[/tex] miles.

Solution:  

Given that,

To find total distance walked by Julian we have to add the above stated values. That is, [tex]\frac{6}{10} +\frac{35}{100} +\frac{1}{4}[/tex]

Factors of 10 = [tex]5\times2[/tex]

Factors of 100 = [tex]5\times2\times5\times2[/tex]

Factors of 4 = [tex]2\times2[/tex]

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

[tex]\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}[/tex]

[tex]\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}[/tex]

Which can also be written as [tex]1\frac{1}{5}[/tex].

So, from the above calculation it can be said that Julian walked [tex]1\frac{1}{5} \text{ miles }[/tex].

Julian did not walk 1/5 mile. He actually walked 1.2 miles.

To determine whether Julian's sister's claim is accurate, we need to add up the distances Julian walked. He walked 6/10 mile to his friend's house, 35/100 mile to the store, and 1/4 mile back home. Using a common denominator of 100, we can add the fractions: 6/10 + 35/100 + 25/100 = 60/100 + 35/100 + 25/100 = 120/100 = 1.2 miles. Therefore, Julian walked 1.2 miles, not 1/5 mile as his sister claimed. So, I do not agree with his sister's statement.

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Answer:

The answer to your question is (6, 0)

Step-by-step explanation:

Solve the system of equations by elimination

                                  x -  4y = 6             (I)

                                2x + 2y = 12            (II)

Multiply (II) by 2

                                  x  - 4y =   6

                                4x + 4y = 24

Simplify

                                5x  + 0  = 30

Find x

                                5x = 30

                                  x = 30/ 5

                                  x = 6

Find "y"

                              6 - 4y = 6

                              -4y = 6 - 6

                              -4y = 0

                                 y = 0/-4

                                 y = 0

Answer:

(6,0)

Step-by-step explanation:

Given equations are:

\[x - 4y = 6\]         -------------------- (1)

\[2x + 2y = 12\]    -------------------- (2)

Multiplying (1) by 2 :

\[2x - 8y = 12\]     -------------------- (3)

Calculating (2) - (3) :

\[2x + 2y -2x + 8y = 12 - 12\]

=> \[10y =0\]

=> \[y = 0\]

Substituting the value of y in (1):

\[ x  = 6 \]

So the required solution of the system of equations is x=6,y=0. This can be alternatively expressed in coordinate notation as (6,0).

Answer:  A

Step-by-step explanation:

The sum to infinity of a geometric series is

S (∞ ) = \frac{a}{1-r} ( - 1 < r < 1 )

where a is the first term 8 and r is the common ratio, hence

S(∞ ) = {8}{1-\{1}{2} } = {8}{1}{2} } = 16

Answer:

Step-by-step explanation:

32 i think

Answer:

  1.00 inches

Step-by-step explanation:

The distance from vertex to focus is "p" in the quadratic equation ...

  x^2 = 4py

In the given equation, p=1. Since units are inches, ...

the bulb should be placed 1.00 inches from the vertex.

Answer: 1.15 pounds

Step-by-step explanation:

For uniform distribution.

The standard deviation is  :

[tex]\sigma=\sqrt{\dfrac{(b-a)^2}{12}}[/tex]

, where a = Lower limit of interval [a,b].

b = Upper limit of interval [a,b].

Given : The changes in water weight are uniformly distributed between minus two and plus two pounds in a day.

i.e. Interval =  [-2 , +2]

Here , a= -2 and b= 2

Then, the standard deviation is  :

[tex]\sigma=\sqrt{\dfrac{(2-(-2))^2}{12}}[/tex]

[tex]\sigma=\sqrt{\dfrac{(2+2)^2}{12}}[/tex]

[tex]\sigma=\sqrt{\dfrac{16}{12}}=\sqrt{1.3333}=1.15468610453\approx1.15[/tex]

Hence, the standard deviation of your weight over a day =  1.15 pounds

The standard deviation of the uniform distribution representing an adult's daily change in weight due to water is around 1.155 pounds.

The question is about the standard deviation of the adult weight changes due to gain or loss in water content which is uniformly distributed between minus two and plus two pounds in a day.

To calculate the standard deviation for this uniform distribution, you need to follow these steps:

So, the standard deviation of your weight changes over a day due to the water flux is approximately 1.155 pounds.

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Answer:

Option 4 - 0.8508

Step-by-step explanation:

Given : A multiple choice test consists of 60 questions. Each question has 4 possible answers of which one is correct. If all answers are random guesses.

To find : Estimate the probability of getting at least 20% correct ?

Solution :

20% correct out of 60,

i.e. [tex]20\%\times 60=\frac{20}{100}\times 60=12[/tex]

Minimum of 12 correct out of 60 i.e. x=12

Each question has 4 possible answers of which one is correct.

i.e. probability of answering question correctly is [tex]p=\frac{1}{4}=0.25[/tex]

Total question n=60.

Using a binomial distribution,

[tex]P(X\geq 12)=1-P(X\leq 11)[/tex]

[tex]P(X\geq 12)=1-[P(X=0)+P(X=1)+P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)+P(X=11)][/tex]

[tex]P(X\geq 12)=1- [^{60}C_0(0.25)^0(1-0.25)+^{60-0}+^{60}C_1(0.25)^1(1-0.25)^{60-1}+^{60-1}+^{60}C_2(0.25)^2(1-0.25)^{60-2}+^{60}C_3(0.25)^3(1-0.25)^{60-3}+^{60}C_4(0.25)^4(1-0.25)^{60-4}+^{60}C_5(0.25)^5(1-0.25)^{60-5}+^{60}C_6(0.25)^6(1-0.25)^{60-6}+^{60}C_7(0.25)^7(1-0.25)^{60-7}+^{60}C_8(0.25)^8(1-0.25)^{60-8}+^{60}C_9(0.25)^9(1-0.25)^{60-9}+^{60}C_{10}(0.25)^{10}(1-0.25)^{60-10}+^{60}C_{11}(0.25)^{11}(1-0.25)^{60-11}][/tex]

[tex]P(X\geq 12)\approx 0.8508 [/tex]

Therefore, option 4 is correct.

The 11 kilometer road will be 1.1 cm long on the map

Step-by-step explanation:

Scale is used on maps to show large locations or roads as small representatives of the larger objects.

The scale factor is usually in proportion to the original length or dimensions.

Given that

1 cm = 10 km

Then, we will divide the number of kilometers by 10 to find the length of road on map

11 km on map = [tex]\frac{11}{10}[/tex]

Hence,

The 11 kilometer road will be 1.1 cm long on the map

Keywords: Maps, Scales

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