Answer:
Succinate oxidation to fumarate The following reactions transform succinate to regenerate oxalacetate. The first of these reactions is carried out by an oxidation catalyzed by succinate dehydrogenase. The hydrogen acceptor is FAD, since the free energy change is insufficient to allow NAD to interact. The final product is fumarate.
Explanation:
The condensation reaction of GDP + Pi and the hydrolysis of Succinyl-CoA involve the H2O necessary to balance the equation.
The stopcock connecting a 1.30 L bulb containing xenon gas at a pressure of 6.15 atm, and a 4.25 L bulb containing oxygen gas at a pressure of 3.53 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is 8.33 atm. True or false?
Answer: False.
The final pressure in the system is 4.14 atm
Explanation: Please see the attachments below
Consider the equation for the combined gas law. If T1, and T2, are constant, you are left with whose
law?
Answer:
Boyels law
Explanation:
The general gas equation is p1v1/T1=p2v2/T2 and T1 and T2 are constant so all that is left is p1v2=p2v2
If temperatures T₁ and T₂ are constant in the combined gas law, the remaining relationship is Boyle's Law, defined as P₁V₁ = P₂V₂.
When we consider the equation for the combined gas law and keep the temperatures T₁ and T₂ constant, we are left with Boyle's Law. Boyle's Law states that the pressure of a gas varies inversely with its volume when temperature is held constant.
This can be represented mathematically as P₁V₁ = P₂V₂, assuming the number of moles (n) and the temperature (T) are constant. This law is named after the English scientist Robert Boyle who first described it in 1662.
A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the chromium sulfide.
Answer: The empirical formula for the given compound is [tex]Cr_2S_3[/tex]
Explanation : Given,
Mass of product = 0.963 g
Mass of Cr = 0.500 g
Mass of S = 0.963 g - 0.500 g = 0.463 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Cr =[tex]\frac{\text{Given mass of Cr}}{\text{Molar mass of Cr}}=\frac{0.500g}{52g/mole}=0.00962moles[/tex]
Moles of S = [tex]\frac{\text{Given mass of S}}{\text{Molar mass of S}}=\frac{0.463g}{32g/mole}=0.0145moles[/tex]
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00962 moles.
For Cr = [tex]\frac{0.00962}{0.00962}=1[/tex]
For S = [tex]\frac{0.0145}{0.00962}=1.5[/tex]
To make in a whole number we are multiplying the ratio by 2, we get:
The ratio of Cr : S = 1 : 1.5
The ratio of Cr : S = 2 : 3
Step 3: Taking the mole ratio as their subscripts.
The ratio of Cr : S = 2 : 3
Hence, the empirical formula for the given compound is [tex]Cr_2S_3[/tex]
Choose all of the statements below that are true about Avogadro's number and the mole:
A) A mole is a counting unit
B) Avogadro's number is to the mole what "12" is to a "dozen" or what "2" is to a "pair"
C) We can use a conversion factor with Avogadro's number in it to determine the number of particles, atoms and/or molecules in a substance of given moles.
D) A mole simply means 6.022 x 10^23 of something (atoms, molecules, particles)
E) Avogadro's number is 6.022
A, B, C, D
Explanation:
Avogadro number is a constant at 6.022 x 10^23. The number is equivalent to a mole in Chemistry. It stipulates the number of particles expected in a mole of a substance. This unit of measurement is named after its inventor, Amedeo Avogadro, an Italian scientist.
It is also used to derive the molar mass of a substance. Dalton is used in expressing the mass of a mole of a substance– atomic mass unit (AMU) * Mass Number.
A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.10 M Sn(NO3)2. The electrolyte in B is 0.87 M Sn(NO3)2. Which half-cell houses the cathode? What is the voltage of the cell? Cathode: half-cell A half-cell B Voltage of cell: V
Answer:
In compartment A, the solution will be concentrated with respect to compartment B, however, over time both compartments will have the same concentration. In compartment B it houses the cathode.
the voltage of the cell is 0.0315 V
Explanation:
Given:
Electrolyte in compartment A is 0.10 M
Electrolyte in compartment B is 0.87 M
Questions:
Which half-cell houses the cathode?
What is the voltage of the cell, V = ?
In both compartments, the reactions are:
A: Sn → Sn²⁺ + 2e⁻
B: Sn²⁺ + 2e⁻ → Sn
In compartment A, the solution will be concentrated with respect to compartment B, however, over time both compartments will have the same concentration. In compartment B it houses the cathode.
The voltage of the cell
[tex]V=E_{in} -\frac{0.0592}{nlog(C_{A} /C_{B} )}[/tex]
Here
n = 2 due the two electrons transferred
Ein = 0
Substituting values:
[tex]V=0-\frac{0.0592}{2*log(0.1/0.87)} =0.0315V[/tex]
If the reactants of a reaction are HCI and NaOH, what could be a product? A. NO2,B.HCIO4,C.NaCl,D.Na2CO3
Answer:
C. NaCl
Explanation: The answer is C because the products are water and salt. Hydrochloric acid is a strong acid and NaOH ( sodium hydroxide is also a strong acid) are the reactants.
Answer:
NaCI
Explanation:
Stoichiometry!
Please note:
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
- Keep it to 1 decimal place.
Hey there!
C₃H₆O(l) + O₂(g) => CO₂(g) + H₂O(g)
First thing I want to do is balance the equation. Balance C:
C₃H₆O(l) + O₂(g) => 3CO₂(g) + H₂O(g)
Balance H:
C₃H₆O(l) + O₂(g) => 3CO₂(g) + 3H₂O(g)
Balance O:
C₃H₆O(l) + 4O₂(g) => 3CO₂(g) + 3H₂O(g)
Now we can properly solve the problem.
a.)
Density of acetone is 0.800 g/mL, we need to form 67.2 L of CO₂ at STP.
For every one mole of acetone reacted, 3 moles of CO₂ is produced.
Let's convert 67.2 L to moles: At STP, one mole of a gas takes up 22.4 liters.
67.2 ÷ 22.4 = 3 moles
So turns out we want to produce 3 moles of CO₂, which means we need one mole of acetone.
The molar mass of acetone is 58.08 g/mol. The density of acetone is 0.800 g/mL. We need the volume of one mole.
58.08 ÷ 0.800 = 72.6
72.6 mL of acetone is needed.
b.)
For every one molecule of acetone reacted, 3 molecules of water is produced.
We are combusting 3.011 x 10²² molecules of acetone.
3.011 x 10²² x 3 = 9.033 x 10²²
Find the number of moles:
(9.033 x 10²²) ÷ (6.022 x 10²³) = 0.15 moles
The molar mass of water is 18.015 g/mol.
0.15 x 18.015 = 2.7 grams
2.7 grams of water vapor is formed.
Hope this helps!
A chemist needs 225 ml of 2.4 m hcl. What volume of 12 m hcl must be mixed with water to form this solution?
To determine the volume of 12 M hydrochloric acid (HCl) needed to prepare 225 mL of 2.4 M HCl, you apply the dilution equation C1V1 = C2V2 and solve for V1.
The subject of this question is determining the volume of a concentrated hydrochloric acid (HCl) solution needed to prepare a more dilute solution of HCl.
We use the equation C1V1 = C2V2 where C1 is the concentration of the starting solution (12 M HCl), V1 is the volume of the starting solution we need to find, C2 is the concentration of the final solution (2.4 M HCl), and V2 is the volume of the final solution (225 mL).
Plugging the values into the equation gives us: (12 M)V1 = (2.4 M)(225 mL).
Therefore, V1 = (2.4 M)(225 mL) / (12 M).
By calculating V1, we get the volume of 12 M HCl needed to make 225 mL of 2.4 M HCl.
Which equation should you use to find the final
concentration?
Answer:
Mf = MiVi / Vf
Explanation:
To obtain the answer to the question given, let us obtain the equation for the final concentration.
This can be obtained from the dilution equation as shown below :
MiVi = MfVf
Mi is the initial concentration
Mf is the final concentration
Vi is the initial volume
Vf is the final volume.
Making Mf the subject of the above equation, we can obtain the equation which can be used to calculate the final concentration. This is illustrated below:
MiVi = MfVf
Divide both side by Vf
Mf = MiVi / Vf
Therefore, the equation which can be used to calculate the final concentration is Mf = MiVi / Vf
The first part to this question is:
What is the final volume? 150.0
the second part:
Which equation should you use to find the final concentration? 3rd option
The 3rd part:
What is the new concentration? 0.125 M NaCl
Explanation:
On edg.. Good Luck!!
The middle ear converts sound from what into vibrations that can be sent through what?
Answer:
The vibrations are then passed to 3 tiny bones in the middle ear called the ossicles. The ossicles amplify the sound. They send the sound waves to the inner ear and into the fluid-filled hearing organ (cochlea). Once the sound waves reach the inner ear, they are converted into electrical impulses.
The molar enthalpy of vaporization of water is 40.79 kJ/mol, and the molar enthalpy of fusion of ice is 6.009 kJ/mol. The molar mass of water is 18.02 g/mol. How much energy is absorbed when 30.3 g of liquid water boils
Answer : The amount of energy absorbed is, 81.2 kJ
Explanation :
The process involved in this problem are :
[tex](1):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(2):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)[/tex]
The expression used will be:
[tex]Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{vap}][/tex]
where,
[tex]Q[/tex] = heat required for the reaction = ?
m = mass of liquid = 30.3 g
[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]4.18J/g^oC[/tex]
[tex]\Delta H_{vap}[/tex] = enthalpy change for vaporization = [tex]40.79kJ/mol=\frac{40790J/mol}{18.02g/mol}=2263.6J/g[/tex]
Now put all the given values in the above expression, we get:
[tex]Q=[30.3g\times 4.18J/g^oC\times (100-0)^oC]+[30.3g\times 2263.6J/g][/tex]
[tex]Q=81252.48J=81.2kJ[/tex]
Therefore, the amount of energy absorbed is, 81.2 kJ
Jorge inflates a beach ball to a volume of 4L in his air-conditioned house where the temperature is 18℃. That afternoon he takes the beach ball to the beach with some friends. The temperature at the beach is 32℃, and the air pressure at the beach is the same as it was at Jorge's house. What will happen to Jorge's beach ball when he is at the beach? Choose the claim that best answers the question: * 1 point The beach ball will get smaller at the beach because the molecules are moving slower. The beach ball will stay the same size at the beach because the pressure is constant. The beach ball will get larger at the beach because the molecules are moving faster. The beach ball will get larger at the beach because the pressure will cause it to expand. The beach ball will get smaller at the beach because the molecules will collide less often.
Answer:
The beach ball will get larger at the beach because the molecules are moving faster.
Explanation:
We can answer this problem by using Charle's Law, which states that:
"For a constant mass of an ideal gas kept at constant pressure, the volume of the gas is directly proportional to its temperature"
Mathematically:
[tex]V\propto T[/tex]
where
V is the volume of the gas
T is the absolute temperature of the gas
Here, we are analyzing the air inside the ball (the gas). We are also told that when the ball is brought to the beach, the pressure does not change: therefore, we can apply Charle's Law.
We are told that when the ball is brought to the beach, the temperature increases from 18℃ to 32℃: therefore, since the volume of the air (and the ball) is proportional to the temperature, this means that the volume of the ball will increase as well.
The reason for this is that the ball is not thermally isolated, so the molecules of the air inside the ball reach soon the same temperature of the surroundings, and so they will move faster (higher temperature means higher average kinetic energy of the molecules, so the molecules move faster, and therefore the ball will expand).
So the correct option is
The beach ball will get larger at the beach because the molecules are moving faster.
Jorge's beach ball when he is at the beach should be beach ball will get larger at the beach because the molecules are moving faster.
What should be happening for beach ball?Here we applied Charle law, in this the volume of the gas is directly proportional to its temperature. Here the ball should not be isolated due to this it moved faster i.e. if there is high temperature that means there should be high kinetic energy so the molecules should be moved quicker due to this the ball should be expanded.
Learn more about molecule here: https://brainly.com/question/19531144
An atom has the following electron configuration.
1s22s22p63s23p3
How many valence electrons does this atom have?
3
5
8
15
Answer:
5 electrons
Explanation:
Valence electrons are electrons located in the outermost energy shell, so you want to count the number of electrons in the last energy shell.
You can divide the configuration into 1s2 / 2s22p6 / 3s23p3 to see the energy shells in this atom. There are 3 shells occupied by the atom's electrons, so you need to count the electrons in the third shell as those are its valence electrons.
2 + 3 = 5 valence electrons total
Note: you don't count the 3 before the letter because that only indicates the shell level, not the number of electrons. Count only the exponents.
An atom that has the following electron configuration.
1s22s22p63s23p3 contains only 5 valence electrons in its outermost shell.
Electronic configuration of chemical elements is the classification and ordering of electrons around the nucleus of an atom in reference to their energy levels.
Electrons can be ordered and classified using Aufbau's principle.
Aufbau's principle posits that in the ground state of an atom, electrons are ordered to the subshell of the lowest energy levels before filling the higher energy level subshell.
The valence electron of a chemical element is the outermost electron participating actively in a chemical bonding.
From the given electronic configuration, we will first determine the total atomic number (total electrons) before we determine the valence electrons in the outermost shell.
Given that
1s² 2s² 2p⁶ 3s² 3p³
There are (2 + 2 + 6 + 2 + 3) total electrons in the elctronic configuration.
= 15 total electrons
The maximum number of electrons in the energy levels is determined by using the formula is [tex]\mathbf{2n^2}[/tex]
where;
n = 1, 2, 3 ....
In the first energy level, we have the maximum number of electrons to be:
= 2(1)²
= 2 electrons
In the second energy level, we have:
= 2(2)²
= 2(4) electrons
= 8 electrons
Since we have only 15 electrons, the number of the valence electrons in the atom is:
= 15- (2 + 8 ) electrons
= 15 electrons - 10 electrons
= 5 valence electrons left in the outermost shell.
In conclusion, an atom that has the following electron configuration 1s22s22p63s23p3 contains only 5 valence electrons in its outermost shell.
Learn more about electronic configuration here:
https://brainly.com/question/16762037?referrer=searchResults
Which element in period 3 has both metallic and non metalik properties
Answer:
Si is the answer I hope this help
What are the 3 advantages and uses of polyester fabric
Answer:
Synthetic fiber fabric has good heat resistance and thermoplasticity.
Good light resistance, light resistance is second only to acrylic.
Good chemical resistance. ...
High strength and elastic recovery. ...
Good water absorption. ...
you can choose any three from here
hope that was helpful.Thank you!!!
Final answer:
Polyester fabric has three main advantages: it is highly stain-resistant, has excellent wrinkle resistance, and is used in various industrial applications.
Explanation:
Advantages and Uses of Polyester Fabric:
Polyester fabric is highly stain-resistant, making it a durable option for apparel and home furnishings. It can resist spills and stains, making it easier to clean and maintain.Polyester fabric has excellent wrinkle resistance due to the cross-linking of polymer strands. This makes it a popular choice for permanent-press clothing that requires minimal ironing or maintenance.Industrial polyester fibers, yarns, and ropes are used in various applications such as car tire reinforcements, conveyor belts, safety belts, and coated fabrics. Polyester's high-energy absorption properties make it suitable for these industrial uses.nitrogen + oxygen → nitrogen dioxide
Which of these is a reactant in this chemical reaction?
A) H2O
B) N2
C) N2O
D) NO2
Answer:
no2
Explanation:
Nitrogen N and Oxygen O2 combine to form NO2
The ingredient label for a fruit drink reads: water, sugar, orange juice, high fructose corn syrup, vitamin C, sodium benzoate (preservative), Red 40, Blue 1.
What can you conclude about the fruit drink’s contents?
A) The product contains no preservatives
B) The product contains more juice than water.
C) The product contains more sugar than juice.
D) The product contains more sugar than any other ingredient.
Answer:
C
Explanation:
C is the only one that is true. Because sugar comes before juice in the ingredients listed, there is more of it.
How many elements are in the following equation?
CH3COCH3
Answer:
3
Explanation:
Answer:
3
Explanation:
the 3 elements are carbon hydrogen and oxygen
what is the mass of one mole of oxygen gas?
Answer:
32 grams
Explanation:
To find the molar mass of oxygen gas, you need to take a look at it's molecular formula. Oxygen is O2, and since each oxygen molecule has a molar mass of 16, 2 of them together have a molar mass of 32 grams. Hope this helps!
how do scientist determine weather a cell from cancerous tissue is a cancer stem cell
Answer:
Researchers take samples of tumors removed from patients during surgery, always with the patient's informed consent. The cells within the tumor are then sorted based on their expression of certain cell markers on their surface.
Explanation:
Calculate the ph of the solution resulting from the addition of 85.0 ml of 0.35 m hcl to 30.0 ml of 0.40 m aniline (c6h5nh2). kb (c6h5nh2) = 3.8 x 10-10
Answer:
pH = 0.81
Explanation:
HCl reacts with aniline, thus:
C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻
Moles of HCl are:
0.085L × (0.35mol HCl / L) = 0.02975mol HCl
Moles of aniline are:
0.030L × (0.40mol HCl / L) = 0.012mol aniline
Thus, after reaction, will remain:
0.02975mol - 0.012mol = 0.01775mol HCl
Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: 0.01775mol H⁺
As total volume is 85.0mL + 30.0mL = 115.0mL ≡ 0.115L
0.01775mol / 0.115L = 0.1543M
pH of solution = -log[H⁺]
pH = -log 0.1543M
pH = 0.81
Answer:
pH = 0.81
Explanation:
Step 1: Data given
Volume of a 0.35 M HCl solution = 85.0 mL
Volume of a 0.40 M aniline solution = 30.0 mL
Kb of aniline = 3.8 * 10^-10
Step 2: The balanced equation
C6H5NH2 + HCl → C6H5NH3+ + Cl-
Step 3: Calculate moles
Moles = molarity * volume
Moles HCl = 0.35 M * 0.085 L
Moles HCl = 0.02975 moles
Moles aniline = 0.40 M * 0.030 L
Moles aniline = 0.012 moles
Step 4: Calculates limiting reactant
Aniline is the limiting reactant. It will completely be consumed (0.012 mole)
HCl is in excesS. There will react 0.012 moles. There will remain 0.02975 - 0.012 = 0.01775 moles
Step 5: Calculate molarity HCl
Molarity HCl = moles HCl / total volume
Molarity HCl = 0.01775 moles / 0.115 L
Molarity HCl = 0.154 M
Step 6: Calculate pH
pH = -log[H+]
pH = -log[0.154]
pH = 0.81
El succinato de butilo es un repelente de insecto utilizado en la casa contra hormigas y cucarachas. Su composicion es de 65.28 por ciento de C, 9,63 por ciento de H y de 27,79 por ciento de O. Su masa molecular determinada experimentalmente es de 230 u, ¿cuales son las formulas empiricas y molecular del succinato de butilo?
Answer:
what is the English translation, id like to help
Explanation:
An ionic precipitation reaction takes place when aqueous solutions of potassium phosphate and aluminum nitrate are combined in a beaker.
K3PO4(aq) + Al(NO3)3(aq) →
i. Predict the products and write a balanced chemical equation for the reaction,
including state symbols.
K3PO4(aq) + Al(NO3)3(aq) →
ii. Write the complete balanced ionic equation, including state symbols.
iii. Write the complete balanced net ionic equation, including state symbols.
Answer:
I hope you can get a good answer
Explanation:
What class is this for?
Carbon monoxide and chlorine gas react to produce COCl2 gas. The Kp for the reaction is 1.49 × 108 at 100.0 °C: In an equilibrium mixture of the three gases, PCO, = PCl2 = 7.70 × 10-4 atm. The partial pressure of the product, phosgene (COCl2), is ________ atm. Use the assumption that change in x is small so you do not have to use the quadratic.
Answer:
Explanation:
Solution:
For the equilibrium
The equilibrium constant is defined in terms of partial pressure:
Introducing the numerical data given for partial pressureof carbon monoxide 0 and chlorine 12, also the value for equilibrium constant:
Answer:
The partial pressureof the product, phosgene (COCl2), is 29.4atm
Answer:
88.34 atm
Explanation:
At equilibrium, carbon monoxide (CO) would react with chlorine gas according to the equation below:
CO (g) + Cl₂ (g) ⇒ COCl₂ (g)
The equilibrium constant Kp, which is a ratio of the partial pressure of the product to that of the reactants is obtained from the equation below:
Kp = PCOCL / PCO.PCl₂
From the question given,
Kp = 1.49 x 10⁸ t 100° C
PCO = 7.70 X 10⁻⁴ atm
PCl₂ = 7.70 x 10⁻⁴ atm
It therefore implies that,
1.49 x 10⁸ = P(COCl₂) / (7.70 x 10⁻⁴). (7.70 x 10⁻⁴)
P(COCl₂) = 1.49 x 10⁸) . (7.70 x 10⁻⁴) . (7.70 x 10⁻⁴)
P (COCl₂) = 88.34 atm
The partial pressure P(COCl₂) of the product phosgene (COCl₂) is 88.34 atm
You use energy to heat your home. What ultimately happens to the energy that you pay for in your heating bill?
1. The energy escapes your home and heats the outside.
2. The energy heats your home.
3. The energy disappears as it never exists.
4. The energy changes to mass.
Answer:
1. The energy escapes your home and heats the outside.
Explanation:
Final answer:
The energy used to heat your home ultimately dissipates into the environment, adhering to the First Law of Thermodynamics, which states that energy is neither created nor destroyed. Thus, we can say option A is correct.
Explanation:
When you pay for energy to heat your home, the energy initially heats your home. Over time, this energy eventually dissipates into the environment, resulting in what we perceive as loss of heat. Contrary to the idea of energy vanishing or turning into mass, the First Law of Thermodynamics assures us that energy is neither created nor destroyed but simply changes form. For instance, the heat produced by your furnace or heat pump eventually escapes to the outside. This process is an inherent part of nearly all energy usage; energy used for work or heating almost always winds up as thermal energy in the end.
A scientist is comparing two cells.
One cell, cell A, is from a unicellular organism, and the other cell, cell B, is from a multicellular organism.
What functional differences will the scientist most likely see when comparing the two cells?
A. Cell A performs all of the organism's necessary functions, while cell B only performs one or a few functions.
B. Cell A is very large and has many organelles, while cell B is very small and has only a few organelles
C. Cell A performs only one or a few functions, while cell B performs all of the organism's necessary functions.
D. Cell A is very small and has only a few organelles, while cell B is large and has many organelles
Answer: Cell A performs all of the organism's necessary functions, while cell B performs only one or a few functions.
When 38.0 g of N2 is reacted with H2 and 40.12 g of NH3 are produced, what is the percent yield?
Answer:
52.80 % is the percent yield of the reaction.
Explanation:
Mass of nitrogen gas = 38.0 g
Moles of nitrogen = [tex]\frac{38.0g}{17 g/mol}=2.235 mol[/tex]
[tex]3H_2+N_2\rightarrow 2NH_3[/tex]
According to reaction, 1 moles of nitrogen gas gives 2 moles of ammonia, then 2.235 moles of nitrogen will give:
[tex]\frac{2}{1}\times 2.235mol=4.470 mol[/tex] ammonia
Mass of 4.470 moles of ammonia
= 4.470 mol × 17 g/mol = 75.99 g
Theoretical yield of ammonia = 217.8 g
Experimental yield of ammonia = 40.12 g
The percentage yield of reaction:
[tex]=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]
[tex]=\frac{40.12 g}{75.99 g}\times 100=52.80\%[/tex]
52.80 % is the percent yield of the reaction.
Se toman 200 ml de una disolución de un frasco de ácido clorhídrico ClH en cuya etiqueta se lee: Pureza: 35 % en peso; densidad = 1,15 g/ml. ¿Cuál es su concentración en g/l?
Answer:
Concentration of solution is 402g/mL
Explanation:
The HCl solution has a purity of 35% w/w. That means there are 35g of HCl per 100g of solution. As density of solution is 1.15g/mL, volume of the solution is:
100g solution × (1mL / 1.15g) = 86.96mL. Thus concentration of solution in g/mL is:
35g of HCl / 86.96mL = 0.402g/mL. As 1L contains 1000mL:
[tex]0.402\frac{g}{mL} \frac{1000mL}{1L}[/tex] = 402g/mL
Concentration of solution is 402g/mL
A balloon containing helium gas expands from 230
mL to 860 mL as more helium is added. What was
the initial quantity of helium present if the
expanded balloon contains 3.8 x 10-4 mol,
assuming constant temperature and pressure?
Which of the variables are known?
DONE
The answer for the following problem is mentioned below.
Therefore the final moles of the gas is 14.2 × [tex]10^{-4}[/tex] moles.Explanation:
Given:
Initial volume ([tex]V_{1}[/tex]) = 230 ml
Final volume ([tex]V_{2}[/tex]) = 860 ml
Initial moles ([tex]n_{1}[/tex]) = 3.8 ×[tex]10^{-4}[/tex] moles
To find:
Final moles ([tex]n_{2}[/tex])
We know;
According to the ideal gas equation;
P × V = n × R × T
where;
P represents the pressure of the gas
V represents the volume of the gas
n represents the no of the moles of the gas
R represents the universal gas constant
T represents the temperature of the gas
So;
V ∝ n
[tex]\frac{V_{1} }{V_{2} }[/tex] = [tex]\frac{n_{1} }{n_{2} }[/tex]
where,
([tex]V_{1}[/tex]) represents the initial volume of the gas
([tex]V_{2}[/tex]) represents the final volume of the gas
([tex]n_{1}[/tex]) represents the initial moles of the gas
([tex]n_{2}[/tex]) represents the final moles of the gas
Substituting the above values;
[tex]\frac{230}{860}[/tex] = [tex]\frac{3.8 * 10^-4}{n_{2} }[/tex]
[tex]n_{2}[/tex] = 14.2 × [tex]10^{-4}[/tex] moles
Therefore the final moles of the gas is 14.2 × [tex]10^{-4}[/tex] moles.
Answer:
1.0 × 10-4 mol
Or just A. The first one
Explanation:
Just did it on eg
Sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is changed to 11.5°C, and the pressure is changed to 1.50 atm?
Answer: 2.34 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 0.850 atm
[tex]P_2[/tex] = final pressure of gas = 1.50 atm
[tex]V_1[/tex] = initial volume of gas = 4.25 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]23.0^oC=273+23.0=293.0K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]11.5^oC=273+11.5=284.5K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.850\times 4.25}{293.0K}=\frac{1.50\times V_2}{284.5}[/tex]
[tex]V_2=2.34L[/tex]
Thus the final volume will be 2.34 L