A concave mirror with a focal length of 10 cm will form a virtual, upright image that is 11.43 cm away from the mirror. The magnification of the image will be -0.301.
Explanation:A concave mirror with a focal length of 10 cm will form an image of an object that is 38 cm away. To determine the characteristics of the image, we can use the mirror equation: 1/f = 1/di + 1/do, where f is the focal length, di is the image distance, and do is the object distance. Rearranging the equation, we get di = 1 / (1/f - 1/do). Plugging in the given values, di = 1 / (1/10 - 1/38) = 11.43 cm.
The negative sign indicates that the image is virtual and upright. Furthermore, to determine the magnification of the image, we can use the formula: magnification = -di / do. Plugging in the values, magnification = -11.43 / 38 = -0.301.
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What is the net force in the x-direction? 30 N 34 N 55 N 65 N
Answer
34 N
Explanation.
I think the question is not complete.. It should be "A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"
We should find the horizontal component of the force 65 N.
Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.
cosФ = adjacent/hypotenuse
let x be the net required (the component of 65N)
cos 58 = x/65
x = 65 × cos 58
= 34.44 N
Answer:
The answer is 34 N
Explanation:
Hope this helped!!!
How long does it take a 1.51 × 104 W steam engine to do 8.72 × 106 J of work? Round your answer to three significant figures.
It would take 9 minutes and 37 seconds for a 1.51 × 10⁴ Watts steam engine to do 8.72 × 10⁶ J of work.
What is the efficiency of an engine?The efficiency of an Indian can be defined as the ratio of the total useful work done by the engine to the total heat absorbed by the engine.
It can be represented in the form of percentages or in terms of fractions as well.
As given in the problem we have to find out how long it takes a 1.51 × 10⁴ Watts steam engine to do 8.72 × 10⁶ J of work,
Power of the steam engine = work done by the engine/time
=8.72 × 10⁶ / 1.51 × 10⁴
Thus, It would take 9 minutes and 37 seconds for a 1.51 × 10⁴ W steam engine to do 8.72 × 10⁶ J of work.
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Periodic Motion Problem, how to tackle this beast?
A small fish is dropped by a pelican that is rising steadily at 0.50 m/s. How far below the pelican is the fish after 2.5 s?
A) 61 m
B) 29.3 m
C) 30.6 m
D) 1.1 m
Can you tell me the formula in order to find this?
Which of the following is an accurate description of relationship demonstrated in ohms law
Answer:
The electric potential (volts) divided by the current (amperes) equals the resistance (ohms).
Explanation: That is the formula to find the resistance based on the Ohm's laws.
1. If the spring of a jack-in-the-box is compressed a distance of 8.00 cm from its relaxed length and then released, what is the speed of the toy head when the spring returns to its natural length? Assume the mass of the toy head is 50.0 g, the spring constant is 80.0 N/m and the toy head moves only in the vertical direction. Also disregard the mass of the spring. (Hint: Remember that there are two forms of potential energy in the problem.)
The speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s. This is found by equating the potential energy stored in the spring to the kinetic energy of the toy head and solving for the speed.
Explanation:The question is regarding the use of the principles of conservation of energy and Hooke's Law in the context of a jack-in-the-box toy. Consider that energy is conserved, we can set the potential energy equal to the kinetic energy. The potential energy stored in the spring while it is compressed is given by the formula PE = 0.5*k*x², where k is the spring constant and x is the distance the spring is compressed. In this case, PE = 0.5*80N/m*(0.08m)² = 0.256 J.
When the spring is released and returns to its natural length, this energy is converted into kinetic energy for the toy head. The kinetic energy is given by KE = 0.5*m*v² where m represents mass and v stands for speed. Setting this equal to the potential energy from above and solving for v, we get v = sqrt((2*0.256J)/(0.05kg)) = sqrt(10.24) m/s = approximately 3.2 m/s.
Therefore, the speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s.
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What is a bright streak of light that results when a meteoroid burns up in earth's atmosphere?
A meteor is the bright streak of light observed when a meteoroid enters and burns up in Earth's atmosphere, due to friction and heat, often colloquially referred to as a shooting star. Larger pieces that reach the ground are known as meteorites. These events are quite common as countless cosmic dust particles enter the atmosphere daily.
A bright streak of light that results when a meteoroid burns up in the Earth's atmosphere is known as a meteor. This phenomenon occurs because as a meteoroid enters the atmosphere at high speeds, often up to 30,000 meters per second, the air in front of it is compressed. The intense heat from this compression and the resulting friction causing the meteoroid to incandesce, creating the visible streak of light we see in the sky, often described as a shooting star.
Most meteoroids are small pieces of rocky or metallic debris from asteroids or comets that enter Earth's atmosphere and burn up completely before reaching the ground. On occasion, larger pieces survive their fiery journey through the atmosphere and land on Earth, which are then called meteorites. It's fascinating to note that meteor sightings are quite common, as millions of these tiny particles enter the Earth's atmosphere daily, producing the brief flashes of light known as meteors.
two or more velocities add by
The more particles that are hitting each other in a fluid, the less pressure is created. true of false
Challenge: a sound wave with a frequency of 100.0 Hz travels in water with a speed of 1,500 m/s and then travels in air with a speed of 340 m/s. Approximately how many times larger is the wavelength in water than in air?
The wavelength in water is approximately 4.41 times larger than the wavelength in air.
Explanation:In order to calculate the ratio of the wavelengths in water and in air, we need to use the formula:
ratio = speed of sound in water / speed of sound in air
Given that the speed of sound in water is 1500 m/s and the speed of sound in air is 340 m/s, we can substitute these values into the formula: ratio = 1500 m/s / 340 m/s = 4.41
Therefore, the wavelength in water is approximately 4.41 times larger than the wavelength in air.
The wavelength in water is approximately 4.4 times larger than in air.
To find the wavelength of a sound wave in a given medium, one can use the formula:
[tex]\[ \lambda = \frac{v}{f} \][/tex]
where [tex]\( \lambda \)[/tex] is the wavelength, [tex]\( v \)[/tex] is the speed of sound in the medium, and [tex]\( f \)[/tex] is the frequency of the sound wave.
Given that the frequency [tex]\( f \)[/tex] of the sound wave is 100.0 Hz, we can calculate the wavelength in water and in air using their respective speeds.
First, calculate the wavelength in water:
[tex]\[ \lambda_{\text{water}} = \frac{v_{\text{water}}}{f} = \frac{1,500 \text{ m/s}}{100.0 \text{ Hz}} = 15 \text{ m} \][/tex]
Next, calculate the wavelength in air:
[tex]\[ \lambda_{\text{air}} = \frac{v_{\text{air}}}{f} = \frac{340 \text{ m/s}}{100.0 \text{ Hz}} = 3.4 \text{ m} \][/tex]
To find out how many times larger the wavelength in water is compared to the wavelength in air, we divide the wavelength in water by the wavelength in air:
[tex]\[ \text{Ratio} = \frac{\lambda_{\text{water}}}{\lambda_{\text{air}}} = \frac{15 \text{ m}}{3.4 \text{ m}} \approx 4.4 \][/tex]
Compare rhyolite to basalt (answer in one word only):
a. which has a lower density?
b. which has a lighter color?
c. which has a more mafic composition?
d. which has a greater percentage of biotite in it?
e. which contains quartz? 13. name a felsic, intrusive rock. 14. name a light-colored, plutonic igneous rock.
Rhyolite has a lower density
Average density of Rhyolite is 2.5 g/cm³ whereas the average density of basalt is 3 g/cm³ So we can say that Rhyolite is less denser.
Rhoylite is more lighter
Rhyolite is either pink or grey whereas basalt is usually grey or black so we can say that Rhyolite has lighter color
Answer C:Basalt is more melfic
Rhyolite is usually considered as felsic, while basalt is mafic. Generally felsic rocks make the bulk of the continental plates, while mafic basalt forms the seafloor.
Answer D:Basalt has more amount of biotite
Basalt has 5% biotite in it whereas Thyloite has very rare amount of biotite in it so we can say that greater amount of biotite is present in Basalt
Answer E:Quartz in Rhyolite may be present in amounts of 25% to 30%. whereas basalt has 20% - 60% quartz amount in it.
Answer 13:Granodiorite is an example of felsic intrusive rock.
Answer 14:Name of a very hard plutonic, igneous rock is Granite.
Astronauts in orbit are not truly weightless. Please select the best answer from the choices provided T F
Answer:
true
Explanation:
true
Read the scenario and solve these two problems. When traveling at top speed, a roller coaster train with a mass of 12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed isJ. Given this kinetic energy, what is the tallest hill this roller coaster train can reach the top of? The train can climb a hill that ism high.
1. The kinetic energy of the train is 5400000 J
2. The tallest hill the train can climb is 45.92 m
1. Determination of kinetic energy of the train
Mass (m) = 12000 Kg
Velocity (v) = 30 m/s
Kinetic energy (KE) =?The kinetic energy of the train can be obtained as follow:
KE = ½mv²
KE = ½ × 12000 × 30²
KE = 6000 × 900
KE = 5400000 J2. Determination of the height of the hill the train can climb
Energy (E) = 5400000 J
Mass (m) = 12000 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?E = mgh
5400000 = 12000 × 9.8 × h
5400000 = 117600 × h
Divide both side by 117600
h = 5400000 / 117600
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How many days are between the first quarter and full moon phases
Roman citizenship guaranteed Paul:
protection from injustices
speedy passport to any distant land under Grecian rule
freedom to preach the gospel
quick transport to lands under Roman rule
The tangential speed at the outer rim of a Ferris wheel is 10 m/s. What is the tangential speed of a position halfway from the center to the outer rim?
In rotational motion, tangential speed is proportional to the radius. Thus, if you're halfway between the center and the rim of a Ferris wheel, your speed would be half that of the rim's speed. So, the tangential speed halfway to the center from the rim would be 5 m/s assuming the outer rim speed is 10 m/s.
Explanation:The concept you're asking about is related to tangential speed and its relationship to the radius in rotational motion. In the case of a Ferris wheel, or any rotating body, the tangential speed is defined as the angular velocity times the radius. Therefore, if the radius is halved (a point halfway from the center to the outer rim), the tangential speed at the new point will also be halved assuming a constant angular velocity. Thus, in your example, if the tangential speed at the outer rim is 10 m/s, the speed halfway to the center will be 5 m/s.
This is because the properties of a rotating body dictate that the tangential speed increases linearly with the radius from the axis of rotation, in the case of a constant angular velocity. Hence, the farther away from the center of rotation, the faster the tangential speed, and vice versa.
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The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel with an outer rim speed of 10 m/s would be 5 m/s.
The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel is half of the tangential speed at the outer rim. In this case, the initial tangential speed at the outer rim is given as 10 m/s, so the tangential speed at halfway to the rim would be 5 m/s. This is because tangential speed is directly proportional to the radius in uniform circular motion, and if the radius is halved, so is the tangential speed.
A certain wave has a wavelength of 35 meters and a frequency of 4.0 Hz. What is the speed of the wave? 8.8 m/s 31 m/s 39 m/s 140 m/s
Answer:
Speed, v = 140 m/s
Explanation:
It is given that,
Wavelength, λ = 35 meters
Frequency of the wave, υ = 4 Hz
The speed of the wave is the product of the frequency and the wavelength of the wave.
Mathematically, it can be written as :
v = υ λ
v = 35 m × 4 Hz
v = 140 m/s
So, the speed of the wave is 140 m/s
Hence, this is the required solution.
During an investigation a scientist heated 2.76 g of silver carbonate till it decomposed to leave a silver residue. The total mass of the silver residue formed was 2.16 g. Does the law of conservation of mass hold true in this case? Use complete sentences to justify your answer based on numerical calculations.
No, the law of conservation of mass does not hold true in this case.
The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction. However, in this case, the mass of the silver residue (2.16 g) is less than the mass of the silver carbonate (2.76 g). This means that some mass was lost during the reaction.
The most likely explanation for the lost mass is that it was converted into carbon dioxide gas. When silver carbonate decomposes, it produces silver metal and carbon dioxide gas. The carbon dioxide gas is not visible, so it is easy to miss.
We can calculate the amount of mass that was lost by subtracting the mass of the silver residue from the mass of the silver carbonate.
Mass lost = 2.76 g - 2.16 g = 0.6 g
This calculation shows that 0.6 g of mass was lost during the reaction. This is a violation of the law of conservation of mass.
The law of conservation of mass does not hold true in this case because some mass was lost during the reaction. The most likely explanation for the lost mass is that it was converted into carbon dioxide gas.
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A dry cleaner throws a 20 kg bag of laundry onto a stationary 8.3 kg cart. the cart and laundry bag begin moving at 2.6 m/s to the right. find the velocity of the laundry bag before the collision. answer in units of m/s. answer
Final answer:
Using the conservation of momentum, the velocity of the 20 kg laundry bag before the collision is calculated to be approximately 3.689 m/s to the right.
Explanation:
To find the velocity of the laundry bag before the collision, we can use the conservation of momentum, which states that the total momentum before an event is equal to the total momentum after the event, provided no external forces act on the system. Since the cart is initially stationary, its initial momentum is 0. After the bag is thrown onto the cart, both move together with a certain velocity, so the final momentum is the combined mass times the final velocity. We can set up the equation as follows:
Momentum before collision (p₁) = Momentum after collision (p₂)
Since the cart is stationary before the collision, this simplifies to:
Velocity of the bag before collision (v) × Mass of the bag [tex](m_{bag)[/tex] = (Mass of the bag [tex](m_{bag)[/tex] + Mass of the cart [tex](m_{cart)[/tex]) × Final velocity [tex](v_f)[/tex]
Inserting the given values, we get:
v × 20 kg = (20 kg + 8.3 kg) × 2.6 m/s
Now we solve for the velocity (v):
v = (28.3 kg × 2.6 m/s) / 20 kg
v = 3.689 m/s
Therefore, the velocity of the laundry bag before the collision was approximately 3.689 m/s to the right.
How can the creation of ice result in physical weathering? view available hint(s) how can the creation of ice result in physical weathering? ice dissolves the surrounding container. ice scrapes the sides of the container, making it bigger. ice contracts as it forms, allowing a container to collapse. water expands in volume when freezing, exerting pressure on a container. liquid water carries talus into a fracture, which wedges the container open?
The creation of ice can result in physical weathering by expanding and exerting pressure on its surroundings, causing rocks to break apart or structures to crack or collapse.
Explanation:When water freezes, it expands in volume and exerts pressure on its surroundings. This expansion can cause physical weathering by breaking down rocks or damaging structures such as containers or pipes. For example, when water seeps into the cracks of a rock and freezes, the expanding ice can widen the cracks and eventually break apart the rock. Similarly, water that freezes in a container can exert enough pressure to cause it to crack or even collapse.
Determine the Kinetic energy of a 1000 kg roller coaster car that is moving with speed of 20.0 m/s
Final answer:
The kinetic energy of a 1000 kg roller coaster car moving at a speed of 20.0 m/s is calculated using the formula KE = ½ mv², resulting in KE = 200,000 J or 2.00 × 10⁵ J.
Explanation:
The question requires us to calculate the kinetic energy of a 1000 kg roller coaster car that is moving with a speed of 20.0 m/s. The kinetic energy (KE) of an object can be found using the formula KE = ½ mv², where m is the mass of the object and v is its velocity. Inserting the given values into the formula, we get:
KE = ½ (1000 kg) (20.0 m/s)
KE = ½ (1000 kg) (400 m²/s²)
KE = (500 kg) (400 m²/s²)
KE = 200,000 J or 2.00 × 10⁵ J
The roller coaster car possesses 200,000 joules of kinetic energy at the given speed.
A car is moving with a speed of 22 m/s. The driver then brakes, and the car comes to a halt after 6.5 s. What is the distance covered by the car after the driver brakes, until it comes to a stop?
The distance covered by the car until it comes to a stop is 71.6 m.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given parameters:
Initial speed of the car; v = 22 m/s.
The car stops after time t = 6.5 s.
The distance covered by the car after the driver brakes, until it comes to a stop; s = ?
So, deceleration of the car = ( initial speed - final speed)/time
= ( 22 m/s - 0 m/s )/6.5 s
= 3.38 m/s².
So, by using v² = u² - 2as in this decelerated motion; we get:
⇒ 0² = 22² - 2×3.38×s
⇒ s = 22²/(2×3.38) = 71.6 m.
Hence, the distance covered by the car after the driver brakes, until it comes to a stop is 71.6 m.
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An instrument that can detect the presence of an electric charge is a
a.
magnet.
b.
electroscope.
c.
generator.
d.
conductor.
Answer:
b. electroscope.
Explanation:
-A magnet is an object that creates a magnetic field around it and has two poles.
-An electroscope is an instrument that helps to find out if there is a charge in an object.
-A generator is an object that produces electrical energy.
-A conductor is an object that allows to transmit energy.
According to this, the answer is that an instrument that can detect the presence of an electric charge is an electroscope.
A shot hitting the birdie high and deep to the backcourt is called what
Final answer:
In badminton, a shot that sends the birdie high and deep to the backcourt is called a clear. It's a defensive move to create more playing space and opportunities.
Explanation:
A shot in badminton that is hit high and deep into the opponent’s backcourt is known as a clear. This type of shot is a defensive move, intended to give the player hitting the clear more time to return to a ready position and to push the opponent to the rear of their court, potentially creating opportunities for future aggressive plays. The clear can be performed as either a forehand or backhand stroke depending on the player's position and the shuttlecock's trajectory.
19. Water that flows downhill along Earth's surface is called A. beach hydraulics. B. cycles. C. runoff. D. rain.
What is the electric force between a glass ball with 3.5 µc of charge and a rubber ball with -4.5 µc of charge when they are separated by 5 cm?
To find the electric force between the charged glass and rubber balls, we use Coulomb's Law with Coulomb's constant, the charges in Coulombs, and the distance in meters to calculate the force.
The student has asked to find the electric force between a glass ball with a charge of 3.5 µC and a rubber ball with a charge of -4.5 µC when they are 5 cm apart. To calculate this, we can use Coulomb's Law, which states that the electric force (F) between two point charges is directly proportional to the product of the magnitudes of the charges (q1 and q2), and inversely proportional to the square of the distance (r) between them. The formula is represented as:
F = k * |q1 * q2| / r₂
Here, k is Coulomb's constant (8.988 x 10^9 N·m^2/C²), q1 and q2 are the charges in Coulombs, and r is the distance in meters. For the glass and rubber ball, q1 is 3.5 µC (or 3.5 x 10^-6 C) and q2 is -4.5 µC (or -4.5 x 10⁻⁶ C), and the distance r is 5 cm (or 0.05 m). Plugging in these values, we get:
F = (8.988 x 10⁹ N·m²/C₂) * |(3.5 x 10⁻⁶ C) * (-4.5 x 10⁻⁶ C)| / (0.05 m)²
After calculation, the result is the magnitude of the electric force exerted between the two charges.
Compare a cup of hot coffee with the Pacific Ocean. Which statement about thermal energy and temperature is correct?
Water in the Pacific Ocean has more thermal energy and a higher temperature.
Water in the Pacific Ocean has less thermal energy and a lower temperature.
Water in the Pacific Ocean has less thermal energy and a higher temperature
Water in the Pacific Ocean has more thermal energy and a lower temperature.
Answer:
The Answer Is (D.)
Explanation:
Lana does her homework as soon as she can after class, but she still doesn't undertand everything she suppose to learn. what could Lana do to get more out of her hhomework
Explanation:
Since Lana is unable to understand everything while doing her homework it means that she has doubts about some of the topics given in her homework.
Therefore, in that case she should take the help of her teacher or instructor the very next day because her doubts are new and she should consult about then as soon as possible.
Thus, by doing so she can clear her doubts on time.
Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
What is the mechanical advantage of the simple machine?
A) 0.2
B) 1
C) 5
D) 50000
An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus at the end of his out-stretched arm so that the discus reaches a velocity of 5.0 m/s. What is the centripetal force acting on the discus?
A.9.4 N
B.14 N
C.27 N
D.66 N
Answer:
I am pretty sure the answer is "66N"
Explanation:
I've seen a lot of results on the internet saying the same thing
If this is not the answer, I am truly sorry and you can message me so that I can delete the question.
Have a good day!