Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.

Answer:

price ($) Au = $ 19183.94

Explanation:

april 15,2000:

∴ price Au = $ 282/t.oz

∴ 1.00 t.oz = 28.4 g

∴ V Au = 100.0 cm³  ⇒  price ($) = ?

∴ δ Au = 19.32 g/cm³

⇒ mass Au = (100.0 cm³)*(19.32 g/cm³)

⇒ m Au = 1932 g

⇒ price ($) = (1932 g Au)*(1.00 t.oz/28.4 g Au)*( $ 282/t.oz)

⇒ price ($) = $ 19183.94

To calculate the cost of 100.0cm3 of gold on April 15, 2000, convert the volume to grams, then to troy ounces, and multiply by the price per troy ounce.

To calculate the cost of 100.0cm3 of gold on April 15, 2000, we need to convert the volume of gold to grams and then to troy ounces. First, convert 100.0cm3 to grams by multiplying it by the density of gold (19.3 g/cm3). This gives us 1930 grams. Next, convert grams to troy ounces by dividing by the conversion factor of 28.4 grams per troy ounce. This gives us approximately 67.96 troy ounces. Finally, multiply the number of troy ounces by the price per troy ounce to find the cost. Therefore, 100.0cm3 of gold on April 15, 2000 would have cost $19,191.12.

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Answer:

Ksp FeS = 5.2441 E-18

Explanation:

         S          S           S

∴ Ksp = [Fe2+]*[S2-].....solubility product constant

∴ [S2-] = 2.29 E-9 M = S

⇒ Ksp = (S)(S) = S²

⇒ Ksp = (2.29 E-9)²

⇒ Ksp = 5.2441 E-18

The pH of an aqueous solution at 25.0°C with [H+] = 0.0025 M is calculated using the pH formula and results in a pH of 2.60, which is answer option B.

The pH of an aqueous solution at 25.0°C with a hydrogen ion concentration [H+] of 0.0025 M can be found using the pH formula:

pH = -log [H3O+]

By substituting the given concentration into the formula, the calculation would be:

pH = -log(0.0025) = -log(2.5 x 10-3)

Using a scientific calculator:

pH = 2.60

Therefore, the correct answer is B) 2.60.

Answer:6.0 ML

Explanation:

Answer:

The chemical equation is given as:

[tex]4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)[/tex]

Explanation:

When gaseous ammonia reacts with gaseous oxygen it gives nitrogen monoxide gas and water vapors as product.

The chemical equation is given as:

[tex]4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)[/tex]

According to reaction, 4 moles of ammonia reacts with 5 moles of oxygen gas to give 4 moles of nitrogen monoxide gas and 6 moles of water vapor.

To write the skeletal equation, begin by writing the chemical formula for each reactant and product.

Reactants:

1. Ammonia's chemical formula is given as  NH3.

2. Gaseous oxygen exists as a diatomic molecule with the chemical formula  O2.

Products:

1. Nitrogen monoxide has the chemical formula of  NO.

2. The chemical formula for water is  H2O.

Therefore, the skeletal equation is written as:

NH3(g)+O2(g)→NO(g)+H2O(g)

Now count the number of each atom on each side of the equation to determine if the equation is balanced.

Reactants

1N atom

3H atoms

2O atoms

Products

1N atom

2H atoms

2O atoms

Begin by balancing the number of hydrogen atoms by adding a coefficient of 2 to  NH3 and a coefficient of 3 to  H2O. Next, balance the number of nitrogen atoms by adding a coefficient of 2 to  NO. Now there are two oxygen atoms on the reactant's side and five oxygen atoms on the product's side of the reaction. Since only whole number coefficients should be used, all coefficients need to be increased by a factor of two to balance the oxygen atoms. Thus the coefficient for  NH3 is 4, the coefficient for  H2O is 6, and the coefficient for  NO is 4. Finally, balance the oxygen atoms by adding a coefficient of 5 to  O2. The balanced equation is:

4NH3(g)+5O2(g)→4NO(g)+6H2O(g)

Answer:

For N₂F₂:

Molar fraction = 0.84

Partial pressure = 1.12 atm

For SF₄:

Molar fraction = 0.16

Partial pressure = 0.208 atm

Explanation:

It seems your question is missing the values required to solve the problem. However, an internet search showed me the following values for your question. If the values in your problem are different, your answer will be different as well, however the solving method will remain the same:

" A 5.00L tank at 0.7°C is filled with 16.5g of dinitrogen difluoride gas and 5.00g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. "

First we calculate the moles of each gas, using their molar mass:

Total mol number = 0.25 + 0.0463 = 0.2963 mol

Now we use PV=nRT to calculate the partial pressure of each gas:

P = ?

V = 5.00 L

T = 0.7 °C ⇒ 0.7 + 273.16 = 273.86 K

For N₂F₂:

For SF₄:

Final answer:

To calculate the mole fraction, you divide the number of moles of a gas by the sum of the moles of all gases in the mixture. The partial pressure of a gas is the pressure that the gas would exert if it were alone in the container. The total pressure in the tank is the sum of the partial pressures of each gas.

Explanation:

The mole fraction of a gas is the ratio of the moles of that gas to the total moles of all gases in the mixture. To calculate the mole fraction of dinitrogen difluoride (N2F2), divide the moles of N2F2 by the sum of the moles of N2F2 and CO2:

Mole fraction of N2F2 = moles of N2F2 / (moles of N2F2 + moles of CO2)

To calculate the mole fraction of carbon dioxide (CO2), divide the moles of CO2 by the sum of the moles of N2F2 and CO2:

Mole fraction of CO2 = moles of CO2 / (moles of N2F2 + moles of CO2)

The partial pressure of a gas is the pressure that the gas would exert if it were alone in the container. To calculate the partial pressure of N2F2, multiply its mole fraction by the total pressure in the tank:

Partial pressure of N2F2 = mole fraction of N2F2 * total pressure

To calculate the partial pressure of CO2, multiply its mole fraction by the total pressure in the tank:

Partial pressure of CO2 = mole fraction of CO2 * total pressure

The total pressure in the tank is the sum of the partial pressures of N2F2 and CO2:

Total pressure = partial pressure of N2F2 + partial pressure of CO2

Answer:

Aldol condensation is possible only when their is alpha Hydrogen atom is present. It ia present only in the acetophenone and not in benzaldehyde.

Explanation:

Answer:

instantaneous rate at 40 s= 0.0035 M /s.

Explanation:

Instantaneous rate at 40 s is the slope of the line (tangent to the curve)

=  Δp/Δt

From, the straight orange line

ΔP = (0.48 - 0.16) M.

Δt = (92 -0) s

Now, instantaneous rate at 40 s

=  0.48 - 0.16/92 - 0

instantaneous rate at 40 s= 0.0035 M /s.

Answer:

0.0035

Explanation:

check the picture

Answer:

(B) ethyl-propyl-ether

Explanation:

ethyl-propyl-ether

a step by step explanation

As the compound has ether as functional group the name of the compound is ethyl propyl ether.

Functional group is defined as a substituent or group of toms or an atom which causes chemical reactions.Each functional group will react similarly regardless to the parent carbon chain to which it is attached.This helps in prediction of chemical reactions.

The reactivity of functional group can be enhanced by making modifications in the functional group .Atoms present in functional groups are linked to each other by means of covalent bonds.They are named along with organic compounds according to IUPAC nomenclature.

The compound has ether as functional group,thus  the name of the compound is ethyl propyl ether.

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Answer:

New volume is 271 mL

Explanation:

To determine the volume for a gas, when the pressure remains constant we follow this ratio:

V₁ / T₁ = V₂ / T₂

Remember the Ideal Gases Law → P . V = n . R . T

That's why we propose V / T

We need to determine the Absolute T°

25°C + 273 = 298 K

50°C + 273 = 323 K

We convert the volume from mL to L → 250 mL . 1L / 1000 mL = 0.250L

Now we replace: 0.250L / 298K = V₂ / 323K

V₂ = (0.250L / 298K) . 323K  → 0.271 L

In conclussion volume of a gas will be increased, while the temperature is also increased and the pressure remains constant.

Answer:

The final volume is 271 mL

Explanation:

Step 1: Data given

The initial pressure = 2 atm

The pressure will be kept constant

The initial volume = 250 mL = 0.250 L

The initial temperature = 25°C = 298 K

The final temperature = 50 °C = 323 K

Step 2: Calculate the final volume

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.250 L

⇒with T1 = the initial temperature = 25 °C = 298 K

⇒with V2 = the final volume = TO BE DETERMINED

⇒with T2 = the final temperature = 50 °C = 323 K

0.250 L / 298 K = V2 / 323 K

V2 = (0.250 /298) *323

V2 = 0.271 L = 271 mL

The final volume is 271 mL

Answer: Please see answer below

Explanation:

Mecury vapor lamp is better to use than Sodium vapor light, this is because  because

---The Filaments of the lamp in sodium  emit fast moving electrons, which causes valence electrons of the sodium atoms to excite to higher energy levels which when electrons after being excited, relax by emitting yellow light which concentrates on the the  monochromatic bright yellow part of the visible spectrum which is about  580-590 or about (589nm) which will fall incident on the calibrations making it difficult to see

While

In Mercury vapor lamp, The emitted  electrons from the filaments, after having been excited  by high voltage, hit the mercury atoms but the excited electrons of mercury atoms relax and emits an  ultraviolet  uv invisible lights falling on the mecury vapour lamp to produce white light  covering  a wide range of  (380-780 nm) which is visible that is why it is used for calibrations purposes in  lightening applications.

The scaling factor is determined by dividing the compound's actual molar mass (150 g/mol) by the molar mass of its empirical formula CH2O (30 g/mol), which results in a factor of 5. The molecular formula of the compound is C5H10O5.

The student's question is asking about the scaling factor of a compound's molar mass based on its empirical formula. The empirical formula is CH2O, which has a molar mass of 30 g/mol (C = 12, H = 1 x 2 = 2, O = 16). If the compound's actual molar mass is 150 g/mol, we divide the actual molar mass by the empirical formula's molar mass to find the scaling factor.

Scaling factor = Actual molar mass / Empirical formula molar mass

= 150 g/mol / 30 g/mol

= 5

Thus, the actual compound's formula is obtained by multiplying each subscript in the empirical formula by the scaling factor of 5. Therefore, the molecular formula of the compound is C5H10O5.

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Answer:

Weak Acid solution

Explanation:

Acidic substances usually have a pH of 0.1-6.9 or it is usually less than 7. Acidic substances too have a very unique sour taste.

However it is understood that it conducts electricity poorly which means the acid doesn’t readily dissociate in water. This makes it a weak acid and an example is Acetic acid.

Answer : The final concentration of ONGP is, 0.47 mM

Explanation :

Formula used :

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume

[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume

We are given:

[tex]M_1=3.3mM\\V_1=1.42mL\\M_2=?\\V_2=10mL[/tex]

Now put all the given values in above equation, we get:

[tex]3.3mM\times 1.42mL=M_2\times 10mL\\\\M_2=0.47mM[/tex]

Hence, the final concentration of ONGP is, 0.47 mM

Answer:

The most appropriate structure given the sparse spectral data is 4-acetyl benzoic acid (see attached).

Explanation:

It is difficult to accurately elucidate the structure of this compound without its chemical formula. But from the 1H NMR spectral data shows a total of 8 hydrogen atoms:

The attached files show the structure and the neighboring hydrogen atoms.

The most likely structure i 4-acetyl benzoic acid

Ideal gas law is valid only for ideal gas not for vanderwaal gas. The equation used for ideal gas is PV=nRT. The  number of molecule-wall collisions per unit area per unit time will remain the same.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

If the volume of the gas sample is decreased to 15.7 L holding the temperature constant, the number of molecule-wall collisions per unit area per unit time will remain the same.

Therefore, the number of molecule-wall collisions per unit area per unit time will remain the same.

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Answer:

Explanation:

find the solution below

Answer :  The value of standard free energy is, -152.4 kJ/mol

Explanation :

The given balanced cell reaction is:

[tex]FADH_2+\frac{1}{2}O_2\rightarrow FAD+H_2O[/tex]

The half reaction will be:

Reaction at anode (oxidation) : [tex]FADH_2\rightarrow FAD+2H^++2e^-[/tex]     [tex]E^0_{Anode}=+0.03V[/tex]

Reaction at cathode (reduction) : [tex]\frac{1}{2}O_2+2H^++2e^-\rightarrow H_2O[/tex]     [tex]E^0_{Cathode}=+0.82V[/tex]

First we have to calculate the standard electrode potential of the cell.

[tex]E^o=E^o_{cathode}-E^o_{anode}[/tex]

[tex]E^o=(+0.82V)-(+0.03V)=+0.79V[/tex]

Relationship between standard Gibbs free energy and standard electrode potential follows:

[tex]\Delta G^o=-nFE^o_{cell}[/tex]

where,

[tex]\Delta G^o[/tex] = standard free energy = ?

n = number of electrons transferred = 2

F = Faraday constant = [tex]96.48kJ.mol^{-1}V^{-1}[/tex]

[tex]E^o_{cell}[/tex]  = standard electrode potential of the cell = 0.79 V

Now put all the given values in the above formula, we get:

[tex]\Delta G^o=-(2)\times (96.48kJ.mol^{-1}V^{-1})\times (0.79V)[/tex]

[tex]\Delta G^o=-152.4kJ/mol[/tex]

Therefore, the value of standard free energy is, -152.4 kJ/mol

To calculate the standard free energy change for the reduction of O2 with FADH2, we first calculate the difference in reduction potentials to find ΔE0′. We then substitute the values into the relation ΔG∘′ = −nFΔE0′, with n=2 and Faraday constant F=96.48 kJ⋅mol‾¹⋅V‾¹. The calculated ΔG∘′ is -152.4384 kJmol‾¹.

The standard free energy change, ΔG∘′, is related to the change in reduction potential, ΔE0′, by the equation ΔG∘′ = −nFΔE0′. To find the standard free energy released by the reduction of O2 with FADH2, we first need to find ΔE0′.

ΔE0′ is given by the difference in reduction potentials of the two half reactions involved. In this case, the reduction of O2 to H2O (+0.82 V) and the reduction of FAD to FADH2 (+0.03 V). Therefore, ΔE0′ = E(O2/H2O) - E(FAD/FADH2) = +0.82 V - (+0.03 V) = +0.79 V.

Inserting the values into the equation, and knowing that the number of transferred electrons (n) is 2 and the Faraday constant (F) is 96.48 kJ⋅mol‾¹⋅V‾¹, we get ΔG∘′ = −2 * 96.48 kJ⋅mol‾¹⋅V‾¹ * (+0.79 V) = -152.4384 kJmol‾¹. Thus, the standard free energy released by reducing O2 with FADH2 is -152.4384 kJmol‾¹.

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Answer:

Explanation:

the solution is solved below

When ethers react with HI, treatment with one equivalent of HI produces an alcohol and an alkyl iodide as major products. Treatment with excess HI yields both alkyl iodides as major products.

Ethers react with HI to form two cleavage products. When treated with one equivalent of HI, the major products that could be recovered are an alcohol and an alkyl iodide. The alcohol is formed by the substitution of the ether oxygen with a hydrogen atom from HI, and the alkyl iodide is formed by the substitution of one of the alkyl groups of the ether with iodine.

When treated with excess HI, the major products that could be recovered are both alkyl iodides. The initial products from the first step do not further react but are still recovered.

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Answer:

57.5%

Explanation:

The mass percent of copper in malachite (Cu2(OH)2CO3) can be determined as follow:

Molar Mass of malachite (Cu2(OH)2CO3) = (2x63.5) + 2(16 +1) + 12 + (16x3) = 127 + 2(17) + 12 + 48 = 127 + 34 + 12 + 48 = 221g/mol

Mass of Cu in Cu2(OH)2CO3 = 2 x 63.5 = 127g

The percentage by mass of Cu in Cu2(OH)2CO3 is given by:

Mass of Cu/Molar Mass of Cu2(OH)2CO3 x 100

=> 127/221 x 100

=> 57.5%

Therefore, 57.5% by mass of Cu is contained in malachite Cu2(OH)2CO3

The distraction during Kinetic Trial 2 will not affect the slope of the log (rate) vs log [I-]0. The relationship between the log of the rate and the log of the initial concentration of I- is determined by the reaction kinetics and is not influenced by external factors like distractions.

The distraction that Alicia experienced when the color change occurred during Kinetic Trial 2 will not affect the slope of the log (rate) vs log [I-]0.

This is because the distraction only affected the timing of the color change, not the actual reaction rate.

The relationship between the log of the rate and the log of the initial concentration of I- is determined by the reaction kinetics and is not influenced by external factors like distractions.

Answer:

10.8 ml

Explanation:

The BOD is an empirical test to determine the molecular oxygen used during a specified incubation period (usually five days), for the biochemical degradation of organic matter (carbonaceous demand) and the oxygen used to oxidise inorganic matter.

See attached file

The maximum volume of treated wastewater that will be in the bottle is 10.8 mL.

The given parameters;

The dilution factor (P) is calculated as follows;

[tex]200 \ mg/L= \frac{9.2 \ mg/L \ - \ 2\ mg/L}{P} \\\\P = \frac{7.2 \ mg/L}{200 \ mg/L} \\\\P = 0.036[/tex]

The maximum  volume of treated wastewater that will be in the bottle to have at least 2.0 mg/L DO;

[tex]0.036 = \frac{V_w}{300 \ mL} \\\\V_w = 0.036 \times 300 \ mL\\\\V_w = 10.8 \ mL[/tex]

Thus, the maximum volume of treated wastewater that will be in the bottle is 10.8 mL.

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Answer:

PLATO Answer

Explanation:

Underneath Photosynthesis Is Carbon Sink

Underneath Animals Is Carbon Sink

Underneath Combustion Is Carbon Source

Among the given options, only the title 'a' correctly identifies the processes as carbon sources and sinks. Burning fossil fuels is a carbon source, while oceans are a carbon sink. The other titles misinterpret the roles of various processes in the carbon cycle.

The correct title to location identifications for each process as carbon source or sink are as follows:

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Answer:

A pH greater than 7 is basic. The pH scale is logarithmic and as a result, each whole pH value below 7 is ten times more acidic than the next higher value. For example, pH 4 is ten times more acidic than pH 5 and 100 times (10 times 10) more acidic than pH 6.

The Question is incomplete here is the complete question " Suppose an iron atom in the oxidation state +3 formed a complex with three hydroxide anions and three water molecules. Write the chemical formula of this complex.

Answer:

{Fe(OH)3(H20)3}

Explanation:

Oxidation state is the electron gained or lost by and atom, So if iron is in +3 state in formula it must have lost three electron.

We know that OH posses the oxidation state of -1 and water have zero oxidation state. SO, Let's take iron equal to y and find its oxidation state in the formula

y + 3 ( - 1 ) + 3 ( 0 ) = 0

y - 3 + 0 = 0

y-3=0

y= + 3

Hence it's proved that iron has +3 oxygen state.

Answer:1 2 4

Explanation:

Answer: 1.3.5.6.

Explanation:

Answer: mole fractions are

For n-pentane = 0.965

For n-octane = 0.035

Explanation: pressure exerted by each gas is,

n-pentane = 1.92atm

n-octane = 0.07atm

Total pressure exerted = 1.92 + 0.07

= 1.99atm.

Recall that the partial pressure exerted by each gas is the product of its mole fraction and the total pressure, that is,

Pres. n-pentane = n x pressure(total)

1.92 = n x 1.99

n = 1.92/1.99 = 0.965 for n-pentane

For n-octane,

n = 1 - 0.965 = 0.035 for n-octane.

Answer : The correct option is, (D) [tex]9.0\times 10^9J[/tex]

Explanation :

As we are given that the energy require for decomposition is, [tex]9.0\times 10^6kJ[/tex].

Now we have to calculate the energy in joules.

Conversion used :

1 kJ = 1000 J

As, 1 kJ of energy = 1000 J

So, [tex]9.0\times 10^6kJ[/tex] of energy = [tex]\frac{9.0\times 10^6kJ}{1kJ}\times 1000J[/tex]

                                          = [tex]9.0\times 10^9J[/tex]

Therefore, the energy in joules is, [tex]9.0\times 10^9J[/tex]

Thermal decomposition of 5.0 metric tons of limestone to lime and carbon dioxide requires 9.0 × 10⁹ Joules of heat.

Enegy is the quantitative property which is used by any system to perform any work.

Chemical reactions generally involves energy in the form of heat energy and given amount of energy is 9.0 × 10⁶ kJ.

We know that:

1 kJ = 1000 J

So, 9.0 × 10⁶ kJ = 9.0 × 10⁶ kJ  × 1000

9.0 × 10⁶ kJ = 9.0 × 10⁹ J

Hence, option (D) is correct i.e. 9.0 × 10⁹ J.

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