determine the range of the function f (x) = x-4 when the domain is (1,5,6

Answer:

The increase was exponential

After three months his expense was: $133.1

Step-by-step explanation:

The increase was exponential, because if we call x the initial price, then after the first month the new price p is:

[tex]p = x (1 + \frac{10\%}{100\%})\\\\p=x(1+0.1)[/tex]

After the second month, the new price is 10% of the price of the previous month, that is:

[tex]p = [x (1 + 0.1)](1 + 0.1)\\\\p = x (1 + 0.1) ^ 2[/tex]

After month n, the price is:

[tex]p = x (1 + 0.1) ^ n[/tex]

Note that the equation has the form of an exponential growth function, where x is the initial price and n is the number of months elapsed.

In this case [tex]x = 100[/tex] and [tex]n = 3[/tex]. So:

[tex]p = 100 (1 + 0.1) ^ 3\\\\p=\$133.1[/tex]

Answer with explanation:

A function is said to attain maximum in the interval , if you consider any two points on the curve suppose (a,b) and (c,d)

if , c>a

Then , f(d) > f(a).

A function is said to attain minimum in the interval,

if ,c>a

Then,f(d)< f(a).

A function can have more than one relative Maximum and more than one relative Minimum.

The function whose graph is given here has following Characteristics

    •Two relative minima

     •Two relative maxima

is True .

To find the coordinates of point C, divide the x- and y-coordinates of AB in the ratio 2:1.

To find the coordinates of point C, we can use the concept of dividing a line segment in a given ratio. Given that AC:CB is 2:1, we can divide the x- and y-coordinates of the line segment AB in the same ratio.

The x-coordinate of point C is calculated by dividing the difference between the x-coordinates of points A and B by the sum of the ratio (2+1).

The y-coordinate of point C is calculated by dividing the difference between the y-coordinates of points A and B by the sum of the ratio (2+1).

Therefore, the coordinates of point C are (-2, 3).

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The correct option is d. [tex]\((4, 0)\)[/tex]. The coordinates of point [tex]\(C\)[/tex] are [tex]\((4, 0)\)[/tex].

To find the coordinates of point [tex]\(C\)[/tex] that partitions the segment [tex]\(AB\)[/tex] in the ratio [tex]\(AC:CB = 2:1\)[/tex], we use the section formula. Given points [tex]\(A(x_1, y_1)\)[/tex] and [tex]\(B(x_2, y_2)\)[/tex] with a ratio [tex]\(m:n\)[/tex], the coordinates [tex]\((x, y)\)[/tex] of the point dividing the segment in the ratio [tex]\(m:n\)[/tex] are given by:

[tex]\[x = \frac{mx_2 + nx_1}{m + n}, \quad y = \frac{my_2 + ny_1}{m + n}\][/tex]

For this problem:

- [tex]\(A(-8, 4)\)[/tex]

- [tex]\(B(10, -2)\)[/tex]

- Ratio [tex]\(m:n = 2:1\)[/tex]

Plugging in the values:

[tex]\[x = \frac{2 \cdot 10 + 1 \cdot (-8)}{2 + 1} = \frac{20 - 8}{3} = \frac{12}{3} = 4\][/tex]

[tex]\[y = \frac{2 \cdot (-2) + 1 \cdot 4}{2 + 1} = \frac{-4 + 4}{3} = \frac{0}{3} = 0\][/tex]

Thus, the coordinates of point [tex]\(C\)[/tex] are [tex]\((4, 0)\)[/tex].

The complete question is:

What are the coordinates of point C on the directed segment from A(−8,4) to B(10,−2) that partitions the segment such that AC:CB is 2:1 ?

A. (1,1)

B. (−2,2)

C. (2,−2)

D. (4,0)

Answer:

Option B. The value of x is 20

Step-by-step explanation:

we know that

The intersecting chords theorem  states that the products of the lengths of the line segments on each chord are equal.

so

In this problem

[tex](x)(x-11)=(x-8)(x-5)\\x^{2}-11x=x^{2}-5x-8x+40\\-11x=-13x+40\\2x=40\\x=20[/tex]

[tex](f+g)(x)=3x+\sqrt{x-4}[/tex]

Answer:

1 = 2

3 = 14

10 = 56

Step-by-step explanation:

y = 6x - 4

y = 6 - 4

y = 18 - 4

y = 60 - 4

Step-by-step explanation:

In first there is 2

ln second there is 14

ln third there is 56

I hope this is right answer!

Answer:

5 boxes

Step-by-step explanation:

Given:

Total crayons : 98

Capacity of each box : 24

Number of boxes of 24 crayons needed to hold 98 crayons,

= 98 ÷ 24

= 4.08 boxes.

However since we cannot have 0.08 of a box, we must round this up to the next larger whole number of boxes.

4.08 rounded up to next whole number = 5

Hence he will need 5 boxes to hold all 98 crayons

Firstly see what they are in mixed fraction form:

[tex]7 \frac{9}{7} = \frac{58}{7} [/tex]

therefore, 7 9/7 is equal to 58/7

[tex]8 \frac{2}{7} = \frac{58}{7} [/tex]

[tex]\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\bf \cfrac{10}{10^{\frac{3}{4}}}\implies \cfrac{10^1}{10^{\frac{3}{4}}}\implies \cfrac{10^{\frac{4}{4}}}{10^{\frac{3}{4}}}\implies 10^{\frac{4}{4}}\cdot 10^{-\frac{3}{4}}\implies 10^{\frac{4}{4}-\frac{3}{4}}\implies 10^{\frac{1}{4}}\implies \sqrt[4]{10}[/tex]

Answer:

The correct answer would be 34

Step-by-step explanation:

When solving an expression, we would first solve the operator with the highest precedence. In mathematics, there are four basic operators. Addition, subtraction, multiplication and division. The precedence of Division and multiplication is higher than the precedence of Addition and subtraction. So by solving this with the precedence, we would first solve the multiplication operator which is 25 * 2, it will give 50, then we will subtract 16 from it like 50-16, which will give us 34.

Answer:

(5x+4)(5x-4)

Step-by-step explanation:

The product expression can be obtained by factorizing the expression 25x²-16 provided in the question.

The expression is a difference of two squares whose factors are generally

(a-b)(a+b)

√25x² is 5x

√16 is 4

Therefore the product required is (5x+4)(5x-4)

25x²-16 is equivalent to (5x+4)(5x-4)

For this case we must solve [tex]x + 2 <5[/tex]intersected with [tex]x-7> -6[/tex]

So, we have:

[tex]x + 2 <5\\x <5-2\\x <3[/tex]

The solutions are given by all strict minor numbers to 3.

[tex]x-7> -6\\x> -6 + 7\\x> 1[/tex]

The solutions are given by all the major strict numbers to 1.

If we intersect the solutions of both equations we have [tex]x <3[/tex] ∩ [tex]x> 1[/tex].

The intersection is given by [tex]1 <x <3[/tex]

Answer:

 The solution interval is (1,3)

Answer:

[tex]y-6=-\frac{5}{4}(x+2)[/tex]

[tex]y-1=-\frac{5}{4}(x-2)[/tex]

[tex]y-3.5=-1.25x[/tex]

Step-by-step explanation:

step 1

Find the slope of the linear equation

with the points (-2,6) and (2,1)

The formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

substitute

[tex]m=\frac{1-6}{2+2}[/tex]

[tex]m=-\frac{5}{4}[/tex]

step 2

Find the equation of the line into point slope form

The equation of the line in slope point form is equal to

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=-\frac{5}{4}[/tex]

1) with the point (-2,6)

substitute

[tex]y-6=-\frac{5}{4}(x+2)[/tex]

2) with the point (2,1)

substitute

[tex]y-1=-\frac{5}{4}(x-2)[/tex]

3) with the point (0,3.5)

substitute

[tex]y-3.5=-\frac{5}{4}(x-0)[/tex]

[tex]y-3.5=-\frac{5}{4}x[/tex] -------> [tex]y-3.5=-1.25x[/tex]

Answer:

A, D, E

Step-by-step explanation:

Answer:

195

Step-by-step explanation:

9 times 10 is 90 and 7 times 15 is 105  

so 105+90=195

Answer:

195 cm

Step-by-step explanation:

The area of ABCD is 195 cm.

Multiply the sides together:

9 ⋅ 10 = 90

7 ⋅ 15 = 105

Add them together:

105 + 90 = 195

Therefore, the area of ABCD is 195 cm.

The solutions to the linear equations in variable x and unknown constant [tex]\alpha[/tex] are [tex]\frac{-\alpha}{6}[/tex], [tex]\frac{3}{\alpha}[/tex] and [tex]\frac{-6}{\alpha}[/tex].

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

We are given linear equations in variable x with an unknown constant [tex]\alpha[/tex] and we have to solve for x.

[tex]4 = \frac{6}\alpha}x + 5\\\\\frac{6}{\alpha}x = - 1\\\\x = \frac{-\alpha}{6}[/tex].

[tex]7 + 2\alpha{x} = 13.\\\\2\alpha{x} = 6.\\\\x = \frac{3}{\alpha}[/tex]

[tex]-\alpha{x} - 20 = -14.\\\\-\alpha{x} = 6.\\\\x = \frac{-6}{\alpha}[/tex]

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Answer:

[tex]\large\boxed{10x^2-5x+10\ -\ \bold{quadratic\ trinomial}}[/tex]

Step-by-step explanation:

[tex]\text{quadratic trinomial}\ -\ ax^2+bx+c\\\\\text{cubic monomial}\ -\ ax^3\\\\\text{not a polynomial}\ -\ \dfrac{a}{x}\\\\\text{fourth-degree binomial}\ -\ ax^4+bx[/tex]

[tex]10x^2-5x+10\\\\\text{the highest power of variable (x) is 2}\to \boxed{x^2}\ \to\ \bold{quadratic}\\\\\text{polynomial has 3 terms}\ \to\ \boxed{10x^2,\ -5x,\ 10}\ \to\ \bold{trinomial}[/tex]

Answer:

26.6 degrees

Step-by-step explanation:

Use the converting formula:

(-3°C × 9/5) + 32 = 26.6°F

-3 degrees to Fahrenheit would be 26.6

The formula is attached in the image below

-3 × 1.8 = -5.4

-5.4 + 32 = 26.6

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

[tex]V=\frac{1}{3}BH[/tex]

where

B is the area of the base

H is the height of the pyramid

we have

[tex]V=40\ units^{3}[/tex]

[tex]H=6\ units[/tex]

substitute and solve for B

[tex]40=\frac{1}{3}B(6)[/tex]

[tex]120=B(6)[/tex]

[tex]B=120/6=20\ units^{2}[/tex]

step 2

Find the volume of the rectangular prism with the same base area and height

we know that

The volume of the rectangular prism is equal to

[tex]V=BH[/tex]

we have

[tex]B=20\ units^{2}[/tex]

[tex]H=6\ units[/tex]

substitute

[tex]V=(20)(6)=120\ units^{3}[/tex]

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

Answer:

C

Step-by-step explanation:

Got it right one the test! <3

Answer:

(-1,-1)

The square needs to be all side with the same value when you graph the vertices on x-y plot, you obtain (x is the dot that correspond a vertice and y the forth vertice )

                            x       2 |                        x

                                      1 |

                                       |                                  

      -2                  -1         |          1              2

                            y        -1|                       x

                                     -2 |

If you draw a line between vertices the value it will be 2 +  (-1) so the forth vertice has to be (-1,-1)

Answer:

Ar = ¼√3 As

Step-by-step explanation:

Area of an equilateral triangle is:

Ar = ¼√3 s²

Area of a square is:

As = s²

Substituting:

Ar = ¼√3 As

For this case we must factor the following equation:

[tex]x ^ 2 + x-6 = 0[/tex]

We must find two numbers that, when multiplied, obtain -6 and when summed, obtain +1. These numbers are: +3 and -2

So, we have to:

[tex](x + 3) (x-2) = 0[/tex]

The roots are:

[tex]x_ {1} = - 3\\x_ {2} = 2[/tex]

ANswer:

[tex](x + 3) (x-2) = 0[/tex]

Answer:

A''(1,-1) B''(3,2) C''(3,2)

Step-by-step explanation:

A(−5,0) B(−3,3) C(−3,0)

reflection over x=-2

Perpendicular distance between points y-coordinates of points (A, B and C) and y=-1 are 3,1 and 1

after reflections, the perpendicular distance will be 6,2,2, and the points will be at

A'(1,0) B'(−1,3) C'(−1,0)

again  reflection over x=1

Perpendicular distance between points y-coordinates of points (A', B' and C') and y=1 are 0,2,2

after reflections, the perpendicular distance will be 0,4,4 and the points will be at

A''(1,-1) B''(3,2) C''(3,2)!

Answer:

Table B

Vertex is (3,-5)

Step-by-step explanation:

We are given with an equation of a parabola [tex]y=x^2-6x+4[/tex]

Let is convert it into standard form of a parabola

[tex]y=x^2-6x+4[/tex]

adding and subtracting 9 in the right hand side of the =

[tex]y=x^2-6x+9-9+4[/tex]

[tex]y=x^2-2\times 3\times x+ 3^2-9+4[/tex]

the first three terms of the right hand side forms the expression of square of difference

[tex]a^2-2 \times a \times b+b^2 = (a-b)^2[/tex]

Hence

[tex]y=(x-3)^2-5[/tex]

adding 5 on both sides we get

[tex](y+5)=(x-3)^2[/tex]

Comparing it with the standard equation of a parabola

[tex]X^2=4\times \frac{1}{4} \times Y[/tex]

where [tex]X=x-3[/tex] and [tex]Y=y+5[/tex]

The vertex of [tex]X^2=4\times \frac{1}{4} \times Y[/tex] will be (0,0)

and thus vertex of

[tex](y+5)=(x-3)^2[/tex] will be (3,-5)

Hence the Table B is our right answer

Answer:

answer is a,b

Step-by-step explanation:

I have answered ur question

The mid-point of AC is (a, b). So, option D is correct. In a rectangle, the two diagonals bisect each other at their mid-point.

The given rectangle is ABCD

Its vertices have coordinates as

A - (0, 0)

B - (0, 2a)

C - (2a, 2b)

D - (2a, 0)

The diagonals are AC and BD.

Finding their mid-points:

Mid-point of the diagonal AC = ((0 + 2a)/2 , (0 + 2b)/2)

⇒ (2a/2, 2b/2)

⇒ (a, b) ... (1)

Mid-point of the diagonal BD = ((0 + 2a)/2, (2a+0)/2)

⇒ (2a/2, 2b/2)

⇒ (a, b)  ...(2)

From (1) and (2), the midpoints of both the diagonals are equal. So, the diagonals of the rectangle ABCD bisect each other.

Hence, proved.

Therefore, the mid-point of the diagonal AC is (a, b).

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Answer:

Third choice

Step-by-step explanation:

They are asking us to find the inverse of y=5x. To do this you just switch x and y and then remake y the subject of the equation (solve for y.)

y=5x

x=5y (I switch x and y)

x/5=y ( I divided both sides by 5)

Then you just replace y with the f^-1(x) thing

f^-1(x)=x/5

or

f^-1(x)=1/5x

If f(x) = 5x, then the inverse of the function, f⁻¹(x) is x/5.

Given that :

f(x) = 5x

Let y = f(x).

So, y = 5x

Now, interchange the values for x and y.

Then,

x = 5y

Now, solve for y.

Divide both sides of the equation by 5.

x/5 = y

So, the inverse of the function is x/5.

Hence f⁻¹(x) = x/5.

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The distance between the points (2, 8) and (-7, -4) is 15 units.

Using the distance formula derived from the Pythagorean theorem, the distance between the points (2, 8) and (-7, -4) is found to be 15 units.

The distance between two points in the coordinate plane can be found using the distance formula, which is derived from the Pythagorean theorem. For points (2, 8) and (-7, -4), the distance can be calculated as follows:

Therefore, the distance between the points (2, 8) and (-7, -4) is 15 units.

Answer:

The answer should be the last one.

Step-by-step explanation:

Answer:

=2√2 the fourth choice.

Step-by-step explanation:

We can use the Pythagoras theorem to calculate the value of y.

a²+b²=c²

a=1

b=y

c=3

Therefore substituting for the values in the theorem above we get:

1²+y²=3²

Leave y on one side.

y²=3²-1²

y²=9-1

y²=8

y=±2√2 in surd form.

Since we expressing length, a scalar quantity, we take the modulus of our answer. Thus y=2√2

Answer:

C. 24

Step-by-step explanation:

In a right triangle, the sum of the squares of the two legs of the triangle is equivalent to the square of the  hypotenuse.

a²+b²=c²

a=10

b=?

c=26

Let us substitute with the values given in the question.

10²+b²=26²

100+b²=676

b²=676-100

b²=576

b=√576

=24

The other leg of the triangle is 24 units long.

Answer: option c.

Step-by-step explanation:

You need to use the Pythagorean Theorem. This is:

[tex]a^2=b^2+c^2[/tex]

Where "a" is the hypotenuse and "b" and "c" are legs of the triangle.

In this case you know that:

[tex]a=26\\b=10[/tex]

Then, you need  to substitute values into  [tex]a^2=b^2+c^2[/tex] and then solve for "c".

So, this is:

[tex]26^2=10^2+c^2\\\\26^2-10^2=c^2\\\\576=c^2\\\\\sqrt{576}=c\\\\c=24[/tex]

Step-by-step explanation:

range is all the y values

{y|y=-9, -3, 0, 5, 7}

The range of a function are all the ys included in the graph. In this case that would be:

(-2, 0), (-4,-3), (2, -9), (0,5), (-5, 7)

Remember to order it from least to greatest:

{yly = -9, -3, 0,5,7}

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer:

1.35 or 27/20

Step-by-step explanation:

(2/5) + (1/4) + (7/10)

= 0.4 + 0.25 + 0.7

= 1.35 or 27/20

Answer:

Option C) b=6

Step-by-step explanation:

we know that

If two linear equations of a system of equations have an infinite of solutions, then both equations are identical

we have

[tex]y=6x-b[/tex] -----> equation A

[tex]-3x+(1/2)y=-3[/tex]

Multiply by 2 both sides

[tex]-6x+y=-6[/tex]

Adds 6x both sides

[tex]y=6x-6[/tex] ------> equation B

equate equation A and equation B

[tex]6x-b=6x-6[/tex]

solve for b

[tex]b=6[/tex]