Determine the simple interest. the rate is an annual rate. Assume 360 days in a year. p= $460 r= 2.75% t= 3.25 years

Answer: 46%

Step-by-step explanation:

The height of the building seen by both Jack and Jill is 37m to the nearest whole metre.

Let the distance of Jill from the base of the building be represented with x while the height of the building be y so that by observation we get two right triangles with same opposite sides to the angles formed by Jack and Jill. We can solve for x and y using tangent of the angles as follows:

tan 40 = y/x {opposite/adjacent}

y = xtan40 {cross multiplication}

tan 30 = y/(20 + x)

y = tan30(20 + x)

Thus;

xtan40 = tan30(20 + x)

xtan40 = 20tan30 + xtan30

xtan40 - xtan30 = 20tan30 {collect like terms}

x(tan40 - tan30) = 20tan30

x = 20tan30/(tan40 - tan30)

x = 44.1230m

Putting the 44.1230m for x in y = xtan40 we have;

y = 44.1230m × tan40

y = 37.0236m.

Therefore, the height of the building approximately to the nearest whole metre is 37.

Answer:

the answer is 12.75

Step-by-step explanation:

btw if you need the median is 12 :>

Answer

C.

2.8x + 8.7                  

Answer:

Step-by-step explanation:

common ratio of a Geometric series can be found by dividing the second term by first term of the series .

we are given that first term a1= -125 and second term a2 =-25

so the common ratio must be

[tex]r=\frac{a2}{a1}[/tex]

[tex]r=\frac{-25}{-125}[/tex]

[tex]r= \frac{1}{5}[/tex]

Hence the common ratio is 1/5.

In this question, you have to solve the equation.

5z – 9 = 36

You transpose the 9 to other side so the equation would look like this:

5z = 36 + 9

5z = 45

Divide 5 in both sides to solve the value of z:

z = 9

Answer:

I believe you meant to put " log10 (0.001)= -3

10^-3=0.001

The expression log100.001 = -3 in exponential form is 10^-3 = 0.001. This demonstrates that 10 raised to the power of -3 equals 0.001, showing the inverse relationship between logarithms and exponents.

To express log100.001 = -3 in exponential form, recall that the logarithm is the exponent to which the base, in this case, 10, must be raised to produce the given number. The equation log10(0.001) = -3 tells us that the base 10 raised to the power of -3 equals 0.001.

In exponential form, this can be written as 10-3 = 0.001.The concept of converting a decimal to a negative power of 10 involves moving the decimal point to make the number into a whole number, and the negative exponent indicates how many places the decimal point needs to move to the left. In our case, 10-3 means we move the decimal three places to the left: 1 becomes 0.001.

We can use the z-score formula with the known z-score corresponding to a probability of 0.01 to calculate the exhaust NOx emission level. This gives us approximately 0.001 g/mi.

In this scenario, we're dealing with a normal distribution problem wherein we use the formula for z-score to answer it. The z-score formula is =(−)/(/√), where x is the data point, μ is the population mean, n is the size of the data set, and σ is the standard deviation.

In this case, we want to find x, or the NOx emission level, such that the probability of finding an automobile with a level greater than x is 0.01. So, we need to find the z-score that corresponds to a probability of 0.01 and then use it in our formula to solve for x.

Using standard z-score tables or an online z-score calculator, we find that a probability of 0.01 corresponds to a z-score of approximately -2.33 (p and z have opposite signs). We then substitute this z-score, along with the given mean μ=0.03 and standard deviation σ=0.01 into the z-score formula, solving for x. The value of n is 64 (number of vehicles in the fleet).

Inserting these values into the formula gives us = + z/√ =0.03 + (-2.33)*(0.01/√64), which simplifies to =0.03 - (2.33/80) = 0.03 - 0.029125= 0.000875 g/mi. Therefore, the NOx emission level, such that the probability of finding an automobile with a level greater than it, is 0.01 for this fleet is approximately 0.001 g/mi when rounded to three decimal places.

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To find the level l such that the probability that the average NOx level x for the fleet is greater than l is only 0.01, we can use the z-score formula and the properties of the normal distribution. The z-score formula allows us to convert a probability into a corresponding value on the distribution. Rearranging the z-score formula, we can find the value of l.

To find the level l such that the probability that the average NOx level x for the fleet is greater than l is only 0.01, we can use the z-score formula and the properties of the normal distribution. The z-score formula is z = (x - µ) / (σ / √n), where x is the average NOx level, µ is the mean, σ is the standard deviation, and n is the sample size. We want to find the value of l such that the area to the right of l under the normal curve is 0.01.

First, we need to find the z-score corresponding to a right-tail probability of 0.01. This can be done using a z-table or a calculator. In this case, the z-score is approximately 2.326. Now we can use the z-score formula to find the value of l. Rearranging the formula, we have l = µ + (z * σ / √n). Substituting the given values, l = 0.03 + (2.326 * 0.01 / √64). Calculating this, we get l ≈ 0.031.

Therefore, the level l such that the probability that the average NOx level x for the fleet is greater than l is only 0.01 is approximately 0.031 g/mi.

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Answer:

To make the function a decay function the rate of change in the function A(x) is r<0.              

Step-by-step explanation:

Given : The exponential function [tex]A(x)=P(1+r)^x[/tex]

To find : What value for r will make the function a decay function?

Solution :

The exponential function is [tex]A(x)=P(1+r)^x[/tex],

where,  P is the initial value

and r is the rate of change

The condition of rate of change is

1) The function is an exponential growth if their is positive rate of change i.e r>0.

2) The function is an exponential decay if their is negative rate of change i.e. r<0.

Therefore, To make the function a decay function the rate of change in the function A(x) is r<0.

The real roots of a function are the rational and the irrational roots of the function

The real roots are: [tex]\mathbf{x = -2}[/tex], [tex]\mathbf{x = \frac 14}[/tex], [tex]\mathbf{x = -3 - 2\sqrt{5}}[/tex] and [tex]\mathbf{x = -3 + 2\sqrt{5}}[/tex]

The equation is given as:

[tex]\mathbf{ 4x^4+31x^3-4x^2-89x+22=0}[/tex]

Factorize

[tex]\mathbf{(x + 2) (4 x - 1) (x^2 + 6 x - 11) = 0}[/tex]

Split

[tex]\mathbf{x + 2 = 0\ or\ 4 x - 1 = 0 \ or\ x^2 + 6 x - 11 = 0}[/tex]

Solve for x

[tex]\mathbf{x = -2\ or\ x = \frac 14 \ or\ x^2 + 6 x - 11 = 0}[/tex]

Solve

[tex]\mathbf{x^2 + 6 x - 11 = 0}[/tex] using the following quadratic formula:

[tex]\mathbf{x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}[/tex]

So, we have:

[tex]\mathbf{x = \frac{-6 \pm \sqrt{6^2 - 4 \times 1 \times -11}}{2 \times 1}}[/tex]

[tex]\mathbf{x = \frac{-6 \pm \sqrt{80}}{2}}[/tex]

[tex]\mathbf{x = \frac{-6 \pm 4\sqrt{5}}{2}}[/tex]

[tex]\mathbf{x = -3 \pm 2\sqrt{5}}[/tex]

Hence, the real roots are:

[tex]\mathbf{x = -2}[/tex], [tex]\mathbf{x = \frac 14}[/tex], [tex]\mathbf{x = -3 - 2\sqrt{5}}[/tex] and [tex]\mathbf{x = -3 + 2\sqrt{5}}[/tex]

Read more about real roots at:

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The best prediction of the number of gold earrings Prudence will pull out is 5 pairs.

To predict the number of pairs of gold earrings Prudence will randomly pull out of her drawer, we need to find the probability of selecting gold earrings from the total number of options.

Prudence has 20 pairs of gold earrings and 4 pairs of silver earrings, making a total of 24 pairs of earrings in her drawer.

The probability of selecting a gold earring is given by:

Number of gold earrings / Total number of earrings =  20 / 24= 5 / 6.

Therefore, the best prediction of the number of pairs of earrings that will be gold is 5 pairs.

To test if a safety net can absorb the proper amount of force, you would need to determine the weight of the sand bag. This can be done by using the concept of Newton's second law and calculating the mass of the sand bag using the equation F = mg, where F is the force required and g is the acceleration due to gravity.

To test if a safety net can absorb the proper amount of force, you would need to determine the weight of the sand bag. This can be done by using the concept of Newton's second law, which states that force equals mass times acceleration. You would first need to calculate the acceleration of the sand bag using the formula F = ma, where F is the force required to be absorbed by the safety net and a is the acceleration. Once you know the required force and acceleration, you can calculate the mass of the sand bag using the equation F = mg, where g is the acceleration due to gravity (approximately 9.8 m/s²).

For example, if the required force is 500 N and the acceleration is 5 m/s², you would calculate the mass of the sand bag as follows:

F = ma

500 N = m * 5 m/s²

m = 500 N / 5 m/s²

m = 100 kg

Therefore, the sand bag must weigh 100 kilograms (or approximately 220 pounds) to test if the safety net can absorb the proper amount of force.

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