Difference between polarized and unpolarized light

Answer:

294.11 N

Explanation:

F1 = 200 N

Let the other force is F2 = F = ?

Resolve the components of F1 and F2.

As the object is in equilibrium in y direction, it means the net force in y direction is zero.

So, F1 Sin 30 = F2 Sin 20

200 x 0.5 = F x 0.34

F = 294.11 N

The magnitude of force is 294.11 N

Explanation:

According to classical physics, a magnetic field always has two associated magnetic poles (north and south), the same happens with magnets. This means that if we break a magnet in half, we will have two magnets, where each new magnet will have a new south pole, and a new north pole. However, the magnetic force of each magnet will be less than that of the original magnet.

This is because for classical physics, naturally, magnetic monopoles can not exist.

Nevertheless,  according to quantum physics, magnetic monopoles do exist, which was predicted by Paul Dirac in 1981. This has led to several experiments and investigations, among which the most recent one so far (year 2014), is the experiment led by a group of scientists from the Amherst College (United States) and the University of Aalto (Finland), that reported having synthesized for the first time in a laboratory a magnet of a single magnetic pole.

Answer:

6.7 kg

Explanation:

V = 5000 L = 5000 x 10^-3 m^3 = 5 m^3

T = 0.2 degree C = 273.2 K

P = 1.04 atm = 1.04 x 1.01 x 10^5 Pa = 1.0504 x 10^5 Pa

R = 8.314 in SI system of units

Use the ideal gas equation. Let n be the moles of air occupied in the lungs of whale.

P V = n R T

n = P V / R T

n = (1.0504 x 10^5 x 5) / (8.314 x 273.2) = 231.22

the mass of one mole of air is 28.98 g

So, the mass of 231.22 moles of air = 231.22 x 28.98 = 6700 .88 g = 6.7 kg

Calculate the mass of air in an adult blue whale's lungs using the ideal gas law with provided values for lung capacity, temperature, pressure, and molar mass.

The mass of air contained in an adult blue whale’s lungs can be calculated using the ideal gas law:

Given:
Lung capacity (V) = 5.0 x 10^3 L
Temperature (T) = 0.2°C = 273.2 K
Pressure (P) = 1.04 atm
Molar mass (m) = 28.98 g/mol

Using the ideal gas law equation: PV = nRT, you can find the number of moles of air, and then calculate the mass of air using the molar mass.

Example Calculation:
n = PV / RT
n = (1.04 atm x 5.0 x 10^3 L) / (0.0821 L.atm/mol.K x 273.2 K)

Answer:

B. upper end

Explanation:

An engine's upper end contains the cylinder head, the valves, the valve train components, the manifolds, and the engine covers.

Final answer:

The upper end of an engine contains important components such as the cylinder head, valves, and valve train components.

Explanation:

The answer to the question is B. upper end. The upper end of an engine refers to the components located above the engine block. This includes the cylinder head, valves, valve train components, manifolds, and engine covers. These components are responsible for controlling the flow of air and fuel into the cylinders and the expulsion of exhaust gases.

Answer:

Part (a): The goods must be dropped 422.812 meters advance of the recipients.

Part (b): The supplies must be given with ascendent vertical velocity of V=0.147 m/s to make they arrive precisely at the climbers position.

Explanation:

h= 235m

g= 9.8 m/s²

V= 61.1 m/s

Part a:

fall time of supplies:

[tex]t=\sqrt{\frac{2.h}{g} }[/tex]

t= 6.92 sec

d= V*t

d= 61.1 m/s * 6.92 s

d= 422.812 m

Part b:

d= 425m

d=V*t

t=d/V

t= 6.95 sec

Δt= 6.95 sec - 6.92 sec

Δt=0.03 sec

The supplies must be given ascendent vertical velocity to compensate that difference of time Δt. the half of the difference must be used to the ascendent part and the other half will be used to descendent part of the supplies.

To calculate the vertical velocity:

Vo= g * Δt/2

Vo= 9.8 m/s² * (0.03 sec/2)

Vo= 0.147 m/sec

Part (a) The horizontal distance in advance the goods should be dropped is approximately 422.812 meters

Part (b) The velocity to be given to the supplies is approximately 0.394 m/s up

The reason the above values are correct is as follows:

The known parameters are;

The vertical distance of the climbers below the airplane, h = 235 m

The horizontal velocity of the airplane, v = 61.1 m/s

Acceleration due to gravity, g ≈ 9.81 m/s²

Part (a) Required:

The distance in advance of the recipients the goods must be dropped

Solution:

The time, t, it will take the goods to drop is given by the following formula for free fall;

[tex]t =\mathbf{ \sqrt \dfrac{2 \times h }{g }}[/tex]

[tex]t =\ \sqrt {\dfrac{2 \times 235 }{9.81 } } \mathbf{\approx 6.92}[/tex]

The time it will take the goods to drop, t ≈ 6.92 seconds

The distance in advance the goods should be dropped, d, is given as follows;

Distance , d = Velocity, v × Time, t

∴ d = Velocity of the airplane, v × The time it will take the goods to drop, t

Which gives;

d ≈ 61.1 m/s × 6.92 s = 422.812 meters

The horizontal distance in advance the goods should be dropped, d ≈ 422.812 meters

Part (b) Given:

The horizontal distance in advance the airplane releases the supplies, d = 425 meters

Required:

The vertical velocity (up or down) to be given the to supplies so they arrive at the climbers position

Solution:

The time the  supplies spend in the air, t, is given as follows;

t = d/v

Where;

v = The horizontal velocity of the airplane  = 61.1 m/s

∴ t = 425 m/(61.1 m/s) =  6.95581015 s ≈ 6.96 s

The vertical distance of travel, s, is given by the following kinematic equation of motion

s = u·t + (1/2)·g·t²

Where;

u = The vertical velocity downwards

s = The distance = 235 meters (below)

g = +9.81 m/s² (downward motion)

Plugging in the values gives;

235 = u·6.96 + (1/2)×9.81×6.96² = 6.96·u + (1/2)×9.81×6.96 = 237.606048

u·6.96 = 237.606048- 240.345 = -2.738952

u = -2.738952/6.96 ≈ -0.394

The velocity to be given to the supplies, u ≈ -0.394 m/s down ≈ 0.394 m/s up (wards)

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Answer:3.884

2.136

2.563

Explanation:

Given

[tex]Length\ of\ simple\ pendulum\left ( L\right )=0.65m[/tex]

[tex]mass\ of\ the\ bob\left ( m\right )=0.34 kg[/tex]

angle of deflection =[tex]9.4^{\circ}[/tex]

[tex]\left ( a\right )[/tex]

[tex]Angular frequency\left ( \omega \right )[/tex]

[tex]\omega =\sqrt{\frac{g}{L}}=3.884 rad/s[/tex]

[tex]\left ( b\right )[/tex]

[tex]Total\ mechanical\ energy\ of\ the\ bob =mgh\left ( at highest point\right )[/tex]

[tex]M.E.=mgL\left ( 1-cos\theta \right )=0.34\times 9.8\times \0.65\left ( 1-cos\left ( 9.4\right )\right )[/tex]

M.E.=2.136 J

[tex]\left ( c\right )[/tex]

Bob's velocity at lowest point

Equating top most point energy =Bottom point energy

[tex]mgh=\frac{1}{2}mv^2[/tex]

[tex]v^2=2.563 m/s[/tex]

The angular frequency of the pendulum's motion is approximately 3.87 rad/sec. The total mechanical energy of the pendulum is approximately 0.034 J. The speed of the pendulum bob at the lowest point of its swing is approximately 0.83 m/s.

The subject in question pertains to the physics of simple harmonic motion as exhibited by a simple pendulum. Given the length of the pendulum (L = 0.65 m), the mass of the pendulum bob (m = 0.34 kg), and the initial displacement angle (9.4°), we are to find: (a) the angular frequency, (b) the total mechanical energy, and (c) the speed at the lowest point of the swing.

(a) The angular frequency (ω) of the pendulum's motion can be calculated using the formula ω = sqrt(g/L), where g is the acceleration due to gravity (9.8 m/s²). Substituting the given values, we get ω ≈ 3.87 rad/sec.

(b) The total mechanical energy (E) of the pendulum is given by E = mgh, where h = L(1 - cosθ). Substituting the given values, we get E ≈ 0.034 J.

(c) The speed (v) of the pendulum bob at the lowest point of the swing can be calculated using the concept of energy conservation. As the pendulum is initially released from rest and assuming no dissipation, the total mechanical energy at any point is the same. Thus, the bob's speed at the lowest point is given by v = sqrt(2*g*h), yielding v ≈ 0.83 m/s.

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Answer: Alex traveled a distance of 27.0 km in 2.25 hours.  

Further Explanation:

Speed is how fast an object moves or how far an object travels per unit time. If the distance traveled and the total time of travel are known, the speed can be calculated using the formula:

[tex]speed \ = \frac{distance}{time}[/tex]

In the problem, we are given:

speed = 12.0 km/hr

time = 2.25 hr

We are looking for the distance traveled by Alex which can be represented by the variable d.

We can solve for d by manipulating the speed formula to get the equation:

distance, d \ = \ (speed)(time)[/tex]

Plugging in our values for speed and time, we get the equation:

[tex]distance \ = \ (12.0 \ \frac{km}{hr})(2.25 \ hr)\\ \boxed {distance,d\ = \ 27.0 \ km}[/tex]

Since the number of significant figures of the given is 3, the answer must be expressed with 3 significant figures, too.

Thus, the distance Alex traveled for 2.25 hours at a speed of 12.0 km/hr is 27.0 km.

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Keywords: speed, distance, kinematics

Explanation:

There are three ways in which the thermal transfer (heat) occurs:

1. By Conduction, when the transmission is by the direct contact.  

2. By Convection, heat transfer in fluids (like water or the air, for example).  

3. By Radiation, by the electromagnetic waves (they can travel through any medium and in vacumm or empty space)

Since outter space is vacuum (sometimes called "empty"), energy cannot be transmitted by convection, nor conduction. It must be transmitted by electromagnetic waves that are able to travel with or without a medium.

Answer: The volume of balloon when it reaches the surface is 7.5 L.

Explanation:

The normal pressure at the surface of sea is 1 atm.

To calculate the volume of balloon, we use the equation given by Boyle's law.

This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature. The equation for this law follows:

[tex]P_1V_1=P_2V_2[/tex]

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=2.5atm\\V_1=3.00L\\P_2=1atm\\V_2=?L[/tex]

Putting values in above equation, we get:

[tex]2.5atm\times 3L=1atm\times V_2\\\\V_2=7.5L[/tex]

Hence, the volume of balloon when it reaches the surface is 7.5 L.

Answer:

a)  1.301 kg/s

b) 0.001301 m³/s

c) V₁ = 6.505 m/s, V₂ = 1.626 m/s

d) 118.93 kPa

Explanation:

Given:

The number of cans  = 220

The volume of can, V = 0.355 L = 0.355 × 10⁻³ m³

time = 1 minute = 60 seconds

gauge pressure at point 2, P₂ = 152 kPa

b) Thus, the volume flow rate, Q = Volume/ time

Q = (220 × 0.355 × 10⁻³)/60 = 0.001301 m³/s

a) mass flow rate = Volume flow rate × density

since it is mostly water, thus density of the drink = 1000 kg/m³

thus,

mass flow rate = 0.001301 m³/s × 1000 kg/m³ = 1.301 kg/s

c) Given:

Cross section at point 1 = 2.0 cm² = 2 × 10 ⁻⁴ m²

Cross section at point 2 = 8.0 cm² = 8 × 10 ⁻⁴ m²

also,

Q = Area × Velocity

thus, for point 1

0.001301 m³/s = 2 × 10 ⁻⁴ m² × velocity at point 1 (V₁)

or

V₁ = 6.505 m/s

for point 2

0.001301 m³/s = 8 × 10 ⁻⁴ m² × velocity at point 1 (V₂)

or

V₂ = 1.626 m/s

d) Applying the Bernoulli's theorem between the points 1 and 2 we have

[tex]P_1+\rho gV_1 + \frac{\rho V_1^2}{2}=P_2+\rho gV_2 + \frac{\rho V_2^2}{2}[/tex]

or

[tex]P_1=P_2+\rho\timesg(y_2-y_1)+\frac{\rho}{2}(V_2^2-V_1^2))[/tex]

on substituting the values in the above equation, we get

[tex]P_1=152+1000\times 9.8(1.35)+\frac{1000}{2}(1.626^2-6.505^2))[/tex]

it is given that point 1 is above point 2 thus, y₂ -y₁ is negative

or

[tex]P_1=118.93\ kPa[/tex]

thus, gauge pressure at point 1 is 118.93 kPa

Answer:

Check the first and the third choices:

Explanation:

Rewrite the table for better understanding:

Temperature of gas (K)     Volume of gas (L)

     298                                     4.55

     315                                      4.81

     325                                     4.96

     335                                        ?

Calculate the ratios temperature to volume with 3 significant figures:

Then, those numbers show a constant temperature-to-volume ratio, which may be expressed in a formula as:

Hence, the correct choices are:

The data provided by the student supports the formulation of a tentative law that aligns with Charles's law, indicating that the temperature of a gas is directly proportional to its volume, and the temperature-to-volume ratio of a gas is constant when pressure is held constant.

The student's measurements of the volume of a gas sample at different temperatures demonstrate a principle in chemistry known as Charles's law. According to this law, the volume of a gas is directly proportional to its temperature when pressure is held constant. Given the data provided, we can infer that as the temperature of the gas increases, so does its volume. This observation can be used to tentatively declare a law based on the student's measurements.

From the answer choices provided:

These explanations are consistent with the observed data that show the volume of the gas increases with increasing temperature. Thus, choices (a) and (c) are the correct interpretations of the experimental data.

Answer:

B) 1.2 N, toward the center of the circle

Explanation:

The circumference of the circle is:

C = 2πr

C = 2π (0.70 m)

C = 4.40 m

So the velocity of the ball is:

v = C/t

v = 4.40 m / 0.60 s

v = 7.33 m/s

Sum of the forces in the radial direction:

∑F = ma

T = m v² / r

T = (0.015 kg) (7.33 m/s)² / (0.70 m)

T = 1.2 N

The tension force is 1.2 N towards the center of the circle.

Answer:

1.2 N, toward the center of the circle

Explanation:

It is given that,

Mass of the ball, m = 0.015 kg

The radius of the circle, r = 0.7 m

Time taken by the ball to complete complete circle, t = 0.6 s

We need to find the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. Here, tension in the string balances the centripetal force so that the ball moves in circular path. So,

[tex]T=\dfrac{mv^2}{r}[/tex]

Since, [tex]v=\dfrac{2\pi r}{t}=\dfrac{2\pi \times 0.7}{0.6}=7.33\ m/s[/tex]

So, [tex]T=\dfrac{0.015\times (7.33)^2}{0.7}[/tex]

T = 1.15 N

or

T = 1.2 N

The direction of centripetal force is toward the center of circle. So, the correct option is (b).

Answer:

.864 M

Explanation:

For first order decomposition,

rate constant k = 1/t x ln a / (a - x )

given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x  = ? = b( let )

6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b

ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315

1.33 / b = e⁰ ⁴³¹⁵ = 1.5395

b = 1.33 / 1.5395 = .864 M.

Answer:

D) Synthesizers have always had a well-established presence in standard ensembles

Explanation:

Identify the false statement: Select one:

A) Synthesis refers to creating sounds electronically from electronically generated waveforms.

B) The synthesizer generates sounds electronically.

C) On the synthesizer, timbre and volume depend on the waveform.

D) Synthesizers have always had a well-established presence in standard ensembles.

A synthesizer is an electronic musical instrument that generates audio signals. Synthesizers generate audio through the following means: subtractive synthesis, additive synthesis, and frequency modulation synthesis. .

,they generate sounds electronically by the virtue of the oscillator

c. on the synthesizer , timbre and volume depend on the waveform , which is true

D is absolutely not correct

The false statement is that synthesizers have always had a well-established presence in standard ensembles. This is not true because synthesizers became more common in ensembles during the mid-20th century, revolutionizing music with their electronic sound generation and waveform manipulation capabilities. So the correct option is D.

The false statement among the options provided is:

D) Synthesizers have always had a well-established presence in standard ensembles.

This statement is false because synthesizers were not part of standard ensembles until the mid-20th century when electronic instruments became more prevalent in various music genres. Prior to that, ensembles typically consisted of acoustic instruments. Synthesizers, which generate sounds electronically and allow for the manipulation of timbre and volume depending on the waveform, brought a new dimension to music that was not always present or well-established in traditional ensembles.

Sound from an electronic speaker is produced when the cone of the speaker vibrates, creating small changes in the pressure of the air, not the temperature or volume. Timbre is not the pitch or wavelength of the sound but refers to the quality of a sound that distinguishes one source or musical instrument from another.

Answer: the creect answer is 10^-4

Explanation:

CGS stands for Cetimetre-Gram-Metre system and Gaussian units constitute a metric system of physical units.  

One gauss (G) is equivalent to 1x10^-4 tesla (T) and is used as a unit for measuring magnetic field strength.

The cgs unit for magnetic field strength is the gauss (G), which is a smaller unit compared to the SI unit of tesla (T). When converting from gauss to tesla, the relation is that 1 gauss is equal to ×10-4 tesla. For reference, the Earth's magnetic field at its surface is about 0.5 G, or 5 × 10-5 T.

Answer:

1.9 m.

Explanation:

Three complete waves in the length of 5.7 m

The distance traveled by one complete wave is called wavelength.

Thus, the distance traveled by one wave = 5.7 / 3 = 1.9 m

Thus, the wavelength is 1.9 m.

Answer:

wavelength = 3.8 m

Explanation:

As we know that linear mass density is defined as the ratio of mass and length

so here we have

[tex]\mu = \frac{m}{L}[/tex]

[tex]\mu = \frac{0.180}{5.70}[/tex]

now we have

[tex]\mu = 0.0315 kg/m[/tex]

Now it is given that string contains three complete waves

length of one segment on string is half of the wavelength

so here we have

[tex]3\frac{\lambda}{2} = 5.70 m[/tex]

[tex]\lambda = 3.8 m[/tex]

So wavelength of the wave on string is 3.8 m

(a) -83.6 Hz

Due to the Doppler effect, the frequency of the sound of the train horn appears shifted to the observer at rest, according to the formula:

[tex]f' = (\frac{v}{v\pm v_s})f[/tex]

where

f' is the apparent frequency

v = 343 m/s is the speed of sound

[tex]v_s[/tex] is the velocity of the source of the sound (positive if the source is moving away from the observer, negative if it is moving towards the observer)

f is the original frequency of the sound

Here we have

f = 350 Hz

When the train is approaching, we have

[tex]v_s = -40.4 m/s[/tex]

So the frequency heard by the observer on the platform is

[tex]f' = (\frac{343 m/s}{343 m/s - 40.4 m/s})(350 Hz)=396.7 Hz[/tex]

When the train has passed the platform, we have

[tex]v_s = +40.4 m/s[/tex]

So the frequency heard by the observer on the platform is

[tex]f' = (\frac{343 m/s}{343 m/s + 40.4 m/s})(350 Hz)=313.1 Hz[/tex]

Therefore the overall shift in frequency is

[tex]\Delta f = 313.1 Hz - 396.7 Hz = -83.6 Hz[/tex]

And the negative sign means the frequency has decreased.

(b) 0.865 m

The wavelength and the frequency of a wave are related by the equation

[tex]v=\lambda f[/tex]

where

v is the speed of the wave

[tex]\lambda[/tex] is the wavelength

f is the frequency

When the train is approaching the platform, we have

v = 343 m/s (speed of sound)

f = f' = 396.7 Hz (apparent frequency)

Therefore the wavelength detected by a person on the platform is

[tex]\lambda' = \frac{v}{f'}=\frac{343 m/s}{396.7 Hz}=0.865m[/tex]

To solve these problems, use the Doppler Shift formula to calculate the change in frequency as the train moves from approaching to receding. Then, use the relationship between speed, frequency, and wavelength to find the wavelength of the sound as the train approaches.

To solve part (a) of the question regarding the overall change in frequency, we need to apply the formula for the Doppler Shift. Since the train passes the observer with a velocity of 40.4 m/s, and the speed of sound in air is about 343 m/s we can utilize these values. Add in the frequency of the horn, 350 Hz, once when the train is approaching (+ velocity) and again while receding (- velocity). This will give us the observed frequency in both scenarios. Subtract the frequency of the horn when it is receding from the frequency when it is approaching to get the overall change in frequency.

For part (b), we already know that the speed of sound v is 343 m/s and the frequency f (Doppler Shift) is 350 Hz from the given. We just need to apply these values into the equation relating speed, frequency, and wavelength (v = fλ). Solving for λ (wavelength) will give us the wavelength of the sound as it reaches the person on the platform.

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Answer:

709 kg/m³

Explanation:

Applying the expression obtained from Archimedes Principle as:

[tex]\% of\ the\ fraction\ submerged=\frac {\rho_{object}}{\rho_{liquid}}\times 100[/tex]

Given :

Percentage of the log above water = 29.1%

Percentage of the log of the water submerged = 100-29.1 % = 70.9%

Density of water = 1000 kg/m³

So,

[tex]70.9 \% =\frac {\rho_{object}}{1000}\times 100[/tex]

The average density of the log = 709 kg/m³

Answer:

The way to produce things in an assembly line

Explanation:

He created assembly line production, which was quite popular in the Industrial Revolution

Answer:

1.2/4.5=4/15=2.666 m/s^2

Explanation:

f=ma

The bird's acceleration is approximately 0.2667 m/s² in the direction opposite to its motion (westward).

To calculate the bird's acceleration, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

Mathematically, Newton's second law can be expressed as:

Net Force = mass x acceleration

Given:

Mass of the pelican (m) = 4.5 kg

Net force (F) = 1.2 N (acting to the west)

We want to find the acceleration (a).

Now, let's rearrange the formula to solve for acceleration:

acceleration = Net Force / mass

Substitute the given values:

acceleration = 1.2 N / 4.5 kg

Now, calculate the acceleration:

acceleration = 0.2667 m/s² (rounded to four decimal places)

So, the bird's acceleration is approximately 0.2667 m/s² in the direction opposite to its motion (westward).

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Explanation:

The Drag Force equation is:

[tex]F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}[/tex] (1)

Where:

[tex]F_{D}[/tex] is the Drag Force

[tex]C_{D}[/tex] is the Drag coefficient, which depends on the material

[tex]\rho[/tex] is the density of the fluid where the bicycle is moving (air in this case)

[tex]A_{D}[/tex] is the transversal area of the body or object

[tex]V[/tex] the bicycle's velocity

Now, if we assume [tex]C_{D}[/tex], [tex]\rho[/tex] and [tex]A_{D}[/tex] are constant (do not change) we can rewrite (1) as:

[tex]F_{D}=C.V^{2}[/tex] (2)

Where [tex]C[/tex] groups all these coefficients.

So, if we have a new velocity [tex]V_{n}[/tex] , which is the double of the former velocity:

[tex]V_{n}=2V[/tex] (3)

Equation (2) is written as:

[tex]F_{D}=C.(V_{n})^{2}=C.(2V)^{2}[/tex]

[tex]F_{D}=4CV^{2}[/tex] (4)

Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.

(a) [tex]18.4^{\circ}[/tex]

We know that the horizontal distance travelled by the arrow is

d = 75.0 m

We also know that the horizontal range of a projectile is given by

[tex]d=\frac{v^2}{g} sin 2\theta[/tex]

where

v is the speed of the projectile

g = 9.8 m/s^2 is the acceleration of gravity

[tex]\theta[/tex] is the angle of the projectile

Here we have

v = 35.0 m/s

Substituting into the equation and solving for [tex]\theta[/tex], we find

[tex]\theta=\frac{1}{2}sin^{-1} (\frac{dg}{v^2})=\frac{1}{2}sin^{-1} (\frac{(75.0 m)(9.8 m/s^2)}{(35.0 m/s)^2})=18.4^{\circ}[/tex]

(b) 6.2 m

In order to answer this part of the problem, we have to calculate what is the maximum height reached by the projectile in its trajectory.

First of all, we can calculate the vertical component of the velocity, which is given by:

[tex]u_y = u sin \theta = (35.0 m/s) sin 18.4^{\circ} = 11.0 m/s[/tex]

The motion along the vertical direction is a uniformly accelerated motion with constant acceleration

g = -9.8 m/s^2

(negative since it points downward). So we can write

[tex]v_y^2 - u_y^2 = 2gh[/tex]

where

[tex]v_y = 0[/tex] is the vertical velocity at the point of maximum height

h is the maximum height

Solving for h, we find

[tex]h=\frac{v_y^2 - u_y^2}{2g}=\frac{0-(11.0 m/s)^2}{2(-9.8 m/s^2)}=6.2 m[/tex]

Therefore, the arrow will go over the branch (which is located 3.50 m above the ground).

Projectile motion principles can be used to solve this problem. θ can be calculated by substituting the given values into the kinematic equation. To know if the arrow goes over or under the branch, calculate the arrow's height at halfway point and compare with the height of the branch.

The subject of this question pertains to projectile motion in physics. In order to solve this, we must apply kinematic equations, specifically the equation for horizontal projectile motion which is θ = arctan[(v² ± √(v⁴ - g*(g*x² + 2*y*v²)) / (g*x)], where v is the initial speed, g is the acceleration due to gravity, x is the horizontal distance, and y is the vertical distance.

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True IF the engine is 25% efficient. False otherwise.

Answer: the answer is c (apex)

Explanation: ya welcome....

At maximum displacement (amplitude) in simple harmonic motion, the speed of the object is zero and the restoring force is at its maximum. This is because the object has momentarily stopped before changing direction to move back towards the equilibrium.

When an object in simple harmonic motion is at its maximum displacement from the equilibrium position, its speed is zero and the magnitude of the restoring force is at its maximum. This is because at maximum displacement, the object has stretched the spring to its limit and hence the spring force (the restoring force) is at its peak. This force aims to pull the object back to the equilibrium position. However, at this point, the object has not yet started moving back, so its speed is zero.

Consider a scenario with a spring-object system: if the object is pulled max away from the equilibrium position (max displacement or amplitude), the spring force is at max (Hooke's law: F = -kx where F is the restoring force, k is the spring constant, and x is the displacement). Since the object is momentarily at rest before it starts moving back towards the equilibrium, its velocity or speed is zero.

Consequently, at maximum displacement (amplitude), the speed is zero while the restoring force is maximum.

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Answer:

The angular momentum and angular velocity are 1.134 kg.m²/s and 174.5 rad/s.

Explanation:

Given that,

Moment of inertia [tex]I= 6.5\times10^{-3}\ kg.m^2[/tex]

Torque = 21 N.m

Time dt = 54 ms

(a). We need to calculate the angular momentum

Using formula of torque

[tex]\tau=\dfrac{dL}{dt}[/tex]

[tex]dL =\tau\times t[/tex]

Where, dL = angular momentum

t = time

[tex]\tau[/tex] = torque

Put the value into the formula

[tex]dL=21\times0.054[/tex]

[tex]dL=1.134\ kg.m^2/s[/tex]

(b). We need to calculate the angular velocity of the disk

Using formula of angular velocity

[tex]dL=I\omega[/tex]

[tex]\omega=\dfrac{dL}{I}[/tex]

[tex]\omega=\dfrac{1.134}{6.5\times10^{-3}}[/tex]

[tex]\omega=174.5\ rad/s[/tex]

Hence, The angular momentum and angular velocity are 1.134 kg.m²/s and 174.5 rad/s.

Explanation:

1. Average acceleration is change in velocity over change in time.

a = Δv / Δt

a = (12 m/s - 9.6 m/s) / 0.8 s

a = 3 m/s²

2. a = Δv / Δt

9.8 m/s² = (14.7 m/s - 0 m/s) / Δt

Δt = 1.5 s

3. Force is mass times acceleration.

F = ma

F = (1250 kg) (40 m/s²)

F = 50,000 N

4. F = ma

500 N = m (9.8 m/s²)

m ≈ 51 kg

The problems are solved by applying physics concepts and formulas: acceleration (`(final velocity - initial velocity)/time`), time (`velocity/acceleration`), force (`mass x acceleration`), and weight (`mass x gravity`), thereby finding the acceleration as 3 m/s², the time as 1.5s, the force as 50,000N, and the person's mass as 51kg.

The questions are related to fundamental concepts in Physics; namely acceleration, time, force, and mass.

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Answer:

D.very slowly (centuries to a million years) when it forms a deep pluton.

Explanation:

Magma is a molten rock that forms within the earth crust. It is sometimes called melt. When it reaches the earth surface, it is called lava.

Only D is correct. Magma would cool slowly in a very deep pluton. In such an enviroment, access to circulating ground water is cut off and the temperature would be close to that by which the melt forms.

When magma cools and solidifies, it forms a wide variety of igneous rocks.

In the presence of circulating ground water, magma would cool and crystallize very rapidly. The ground water would provide more fluid phase for the movement of ions within the very thick and viscous melt thereby facilitating crystallization of minerals in the melt. Due to the temperature of the water, it serves as a coolant for the melt. The ground water takes heat away and returns with a more cold water.

Magma cools faster if the surface area of the intrusion is very large. A larger surface area would help more heat to dissipate and leave the body of the melt.

Magma cooling and crystallization form solid igneous rocks, with the rate of cooling influencing crystal size. Slowly cooling magma forms large crystals in intrusive igneous rocks like granite, while rapidly cooling magma forms fine-grained rocks. Deep plutons may take centuries to a million years to cool, resulting in coarse-grained textures.

Magma may cool and crystallize to form solid igneous rock. This process can occur at variable rates depending on several factors. When magma cools slowly, typically deep within the Earth, the resulting crystals are larger, forming coarse-grained intrusive or plutonic igneous rocks such as granite. Conversely, magma that cools quickly, often at or near the Earth's surface, forms rocks with much smaller crystals, known as fine-grained igneous rocks.

Cooling and forming crystals happen when the molten magma begins to cool. The slower the cooling process, the larger the crystals that can grow, since ions have more time to arrange into a crystal lattice. For example, a deep pluton, which is a large body of intrusive igneous rock that crystallized from magma cooling beneath the Earth's surface, can take from centuries to a million years to cool.

Like any other wave, the speed of the wave on the rope is

Speed = (frequency) x (wavelength)

Speed = (4 Hz) x (0.5 m)

Speed = 2 m/s

Answer:

No, the net force on the skydiver is zero

Explanation:

According to Newton's Second Law, the net force on an object is equal to the product between the mass of the object and its acceleration:

[tex]F=ma[/tex]

where

F is the net force

m is the mass of the object

a is the acceleration

In this problem, the acceleration of the skydiver is zero:

a = 0

This implies that also the net force on the skydiver is zero, according to the previous equation:

F = 0

So, the net force on the skydiver is zero. This occurs because the air resistance, which points upward, exactly balances the force of gravity on the skydiver, acting downwards.