Differentiated animal cells and tissues include _____.

cuboidal cells
columnar cells
bone cells
fat cells
neurons
all of the above

Explanation:

It is known that number of moles present in a substance is equal to the mass divided by molar mass.

Mathematically,      No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

As it is given that number of moles are 0.432 moles and molar mass of [tex]C_{8}H_{9}O_{4}[/tex] is 169.15 g/mol.

Hence, calculate the mass of [tex]C_{8}H_{9}O_{4}[/tex] is as follows.

                 No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                     0.432 mol = [tex]\frac{mass}{169.15 g/mol}[/tex]

                         mass = 73.072 g

Thus, we can conclude that the mass of 0.432 moles of [tex]C_{8}H_{9}O_{4}[/tex] is 73.072 g.

The activation energy can be determined using the Arrhenius equation. To find the activation energy at a different temperature, rearrange the equation and plug in the given rate constant. The frequency factor is approximately 1.529 * 10^9 /s.

The activation energy can be determined using the Arrhenius equation:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

To find the activation energy at a different temperature, we can rearrange the equation as:

Ea = -ln(k/A) * RT

Using the given rate constant at 683 K and the activation energy of 212 kJ, we can calculate the frequency factor as follows:

A = k * e^(Ea/RT)

Plugging in the values:

A = (6.06×10^(-4) /s) * e^(212000 J / (8.3145 J/mol*K * 683 K))

A = 1.529 * 10^9 /s

Therefore, the frequency factor is approximately 1.529 * 10^9 /s.

The activation energy for a reaction is the minimum amount of energy required for the reaction to occur. To find the activation energy at a different temperature, we can use the Arrhenius equation. The activation energy will be 2.71 kJ/mol at the desired condition.

The activation energy for a reaction is the minimum amount of energy required for the reaction to occur. It represents the energy barrier that the reactants must overcome before they can form products. In the given question, the activation energy for the gas phase decomposition of 2-bromopropane is 212 kJ.

To find the activation energy at a different temperature, we can use the Arrhenius equation:

k = A * e^(-Ea/RT)

where:
- k is the rate constant
- A is the frequency factor
- Ea is the activation energy
- R is the gas constant (8.314 J/(mol·K))
- T is the temperature in Kelvin

By rearranging the equation, we can solve for the activation energy at a different temperature:

Ea2 = -ln(k2/k1) * (R/T2 - R/T1)

Substituting the given values:

Ea2 = -ln(5.06x10^-3 / 6.06x10^-4) * (8.314 J/(mol·K) / 683 K - 8.314 J/(mol·K) / 298 K)

Ea2 = -ln(8.333) * (0.0122 - 0.0278) = -ln(8.333) * (-0.0156) = 0.1739 * 0.0156 = 0.00271 J/mol = 2.71 kJ/mol

Therefore, the activation energy will be 2.71 kJ/mol at the desired condition.

Answer : The correct option is, 0.2 mole Y left over .

Explanation : Given,

Moles of X = 4.8 mole

Moles of Y = 3.4 mole

The balanced chemical reaction is,

[tex]3X+2Y\rightarrow X_3Y_2[/tex]

From the balanced reaction, we conclude that

As, 3 moles of X react with 2 moles of Y

So, 4.8 moles of X react with [tex]\frac{2}{3}\times 4.8=3.2[/tex] moles of Y

From this we conclude that, the reactant Y is an excess reagent and X is a limiting reagent.

The moles of excess reagent left over at the end of the reaction = Given moles of X - Required moles of X

The moles of excess reagent left over at the end of the reaction = 3.4 - 3.2 = 0.2 mole

Therefore, the moles of excess reagent left over at the end of the reaction is, 0.2 mole Y left over.

Answer:

The correct answer is : '0.2 mol Y left over'.

Explanation:

[tex]3X + 2Y \rightarrow  X_3Y_2[/tex]

Moles of X = 4.8 moles

Moles of Y = 3.4  moles

According to reaction, 3 moles of X react with 2 moles of Y .

Then 4.8 moles of X react with :

[tex]\frac{2}{3}\times 4.8=3.2 [/tex]moles of Y

Moles of Y reacted = 3.2 moles

Moles of Y left unreacted = 3.4 moles - 3.2 moles = 0.2 moles

As we can see that X is in limiting amount and y is present in an excessive amount.And the left over amount of Y is 0.2 moles.

Ionic compounds are generally formed from a metal cation (positively charged ion) and a nonmetal anion (negatively charged ion), so the correct answer to your question is option C.

Ionic compounds are typically composed of a metal cation and nonmetal anion. This means the correct answer to your question is option C. A cation is a positively charged ion, and in this context, it is typically formed by an element from the left side of the periodic table, or a metal. An anion, on the other hand, is a negatively charged ion, usually formed by an element from the right side of the periodic table, or a nonmetal. When these ions combine, they create an ionic compound, such as NaCl (sodium chloride), where sodium is the metal cation and chloride is the nonmetal anion.

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Answer: [tex]Rate=k[A]^1[B]^5[C]^6[/tex]

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.

[tex]A+5B+6C\rightarrow 3D+3E[/tex]

[tex]Rate=k[A]^1[B]^5[C]^6[/tex]

k= rate constant

1 = order with respect to A

5 = order with respect to B

6 = order with respect to C

Thus rate law is [tex]Rate=k[A]^1[B]^5[C]^6[/tex]

Answer: The formation of water is a chemical change.

Explanation:

Physical change is defined as the change in which change in shape and size takes place. The chemical composition of a substance remains the same. No new substance is formed during this.

For Example: Melting of ice

Chemical change is defined as the change in which change in chemical composition takes place. A new substance is formed in this.

For Example: Formation of water molecule.

The chemical equation for the formation of water molecule follows:

[tex]2H_2+O_2\righatarrow 2H_2O[/tex]

Hence, the formation of water is a chemical change.

This question involves the application of the Arrhenius equation in chemistry, particularly in calculating the temperature dependence of reaction rates. Given the rate constant and the activation energy at a certain temperature, one can find the rate constant at a different temperature

The question pertains to the use of the Arrhenius equation, which calculates the temperature dependence of reaction rates. The equation is k = A * e^(-Ea/RT), where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

The given reaction has a rate constant (k) of 1.35 x 10² s-1 at 25.0°C (or 298.15K). The activation energy (Ea) is given as 85.6 kJ/mol. To find the rate constant at another temperature, rearrange the Arrhenius equation to solve for A, substitute the given values for Ea, k, R and T to find A. Then, plug the calculated A, given Ea, the new temperature in Kelvin (75.0°C or 348.15K), and R into the Arrhenius equation to solve for the new rate constant, k.

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[H⁺]=3.608.10⁻¹²

Weak acid ionization reaction occurs partially (not ionizing perfectly as in strong acids)

The ionization reaction of a weak acid is an equilibrium reaction

HA (aq) ---> H⁺ (aq) + A⁻ (aq)

The equilibrium constant for acid ionization is called the acid ionization constant, which is symbolized by Ka

The values ​​for the weak acid reactions above:

[tex]\rm Ka=\dfrac{[H][A^-]}{[HA]}[/tex]

The greater the Ka, the stronger the acid, which means the reaction to the right is also greater

Where Kb is the base ionization constant

LOH (aq) ---> L⁺ (aq) + OH⁻ (aq)

[tex]\rm Kb=\dfrac{[L][OH^-]}{[LOH]}[/tex]

Kb of Ethylamine (C₂H₅NH₂) : 6.4.10⁻⁴

The ethylamine ionization reactions occur in water as follows:

C₂H₅NH₂ + H₂O ⇒ C₂H₅NH₃⁺ + OH⁻

with a Kb value:

[tex]\rm Kb=\dfrac{[C_2H_5NH_3^+][OH^-]}{[C_2H_5NH_2]}[/tex]

for example x = number of moles / concentration that reacts

Initial concentration of  Ethylamine (C₂H₅NH₂) : 1.2.10⁻²

Concentration at equilibrium = 1.2.10⁻²  -x

Initial concentration of C₂H₅NH₃ = 0

Concentration at equilibrium = x

Initial concentration OH⁻ = 0

Concentration at equilibrium = x

so the value of Kb =

[tex]\rm Kb=\dfrac{[x][x]}{[1.2.10^{-2}-x]}\\\\assumption\:x=so\:small\:then\\\\6.4.10^{-4}=\dfrac{x^2}{1.2.10^{-2}}\\\\x^2=7.68.10^{-6}\\\\x=2.771.10^{-3}[/tex]

x = [OH⁻] = 2.771.10⁻³

Ka x Kb = [H⁺] [OH-]

a water equilibrium constant value (Kw) of 1.10⁻¹⁴ at 25 °C

Ka x Kb = [H +] [OH-] = 1.10⁻¹⁴

1.10⁻¹⁴ = [H⁺] . 2.771.10⁻³

[H⁺]=3.608.10⁻¹²

an equilibrium constant https://brainly.com/question/9173805

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Calculate the value of the equilibrium constant, Kc

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Concentration of hi at equilibrium

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Final answer:

In gas chromatography, compounds elute based on their boiling points, with those having lower boiling points eluting first. Since anisole has a lower boiling point than d-limonene, anisole is expected to elute first.

Explanation:

The question asks which compound, anisole or d-limonene, would elute first in gas chromatography (GC) based on their boiling points. In gas chromatography, compounds generally elute in order of increasing boiling points because compounds with lower boiling points have lower retention times on the GC column. Also, the elution order correlates with the strength of intermolecular forces (IMFs) affecting the compounds; compounds with stronger IMFs tend to have higher boiling points and adhere more to the stationary phase, thus eluting later. Although the specific boiling points of anisole and d-limonene are not provided in this answer, it is known that anisole has a boiling point of about 154°C, and d-limonene has a boiling point around 176°C. Therefore, one would expect anisole to elute first in gas chromatography due to its lower boiling point compared to d-limonene.

Final answer:

Rubbing alcohol molecules as a gas have the same structure as in the liquid but with more kinetic energy and less intermolecular attraction, which upon evaporation causes a cooling effect through evaporative cooling.

Explanation:

When rubbing alcohol evaporates from your hand, it leaves a cooling sensation because the molecules in the liquid state require a certain threshold of kinetic energy to overcome intermolecular forces and escape into a gas state. The correct statement regarding how the molecules of gas compare to the molecules as a liquid is:

In the gaseous state, particles move faster and are further apart compared to when they are in the liquid state, where particles are closer together and have stronger intermolecular attractions. This process of evaporation involves evaporative cooling, where the molecules with higher kinetic energy escape, leaving behind those with lower kinetic energy, which results in a decrease in temperature.

Answer:

The percentage of potassium in the given complex is 35.54 %.

Explanation:

Mass of potassium in [tex]K_3Fe(CN)_6[/tex] = 3 × 39.10 g mol=117.3 g/mol

Molar mass of [tex]K_3Fe(CN)_6[/tex] =329.15 g/mol

Percentage of potassium (K) in the the complex:

[tex]\% K=\frac{\text{mass of potassium}}{\text{molar mass of complex}}\times 100[/tex]

[tex]\%K=\frac{117.3 g/mol}{329.15 g/mol}\times 100=35.54\%[/tex]

The percentage of potassium in the given complex is 35.54 %.

Answer:

No triplet.

Explanation:

A triplet is observed in proton nmr when the neighboring, chemically non equivalent, carbon atoms bear two hydrogen atoms.

Let us examine the structure of o-chlorotoluene [shown in figure].

As shown in the figure there is no carbon bearing two equivalent hydrogen.

There are five non equivalent kind of hydrogen on the molecule

Three hydrogen are equivalent (Ha)

So we will observe only

a) Singlet

b) Doublet

c) Double doublet (split doublet)

The order of the reaction with respect to clo2 is 1.

The order of the reaction with respect to clo2 can be determined by comparing the initial rates of different experiments and analyzing the effect of changing the concentration of clo2 on the reaction rate. By comparing the rates of Experiment 1 and Experiment 2, we can see that when the concentration of clo2 is halved, the rate of the reaction is also halved. This indicates that the reaction rate is directly proportional to the concentration of clo2. Therefore, the order of the reaction with respect to clo2 is 1.

The biggest elctronegative difference is between silicon and sulfur. So  Si-S will be most polar bond.

The polarity between the two atoms is determined by their relative difference in electronegativity.

The Electronegativity of ,

Silicon= 1.9

Phosphorus= 2.19

Sulfur= 2.58

The direction of polarity,

[tex]\rm \bold{ \delta^+Si\rightarrow \delta^-P}\\\rm \bold{ \delta^+Si\rightarrow \delta^-S}\\\rm \bold{ \delta^+P\rightarrow \delta^-S}[/tex]

Since, the biggest elctronegative difference is between silicon and sulfur (Si-S).

Hence we can say that Si-S will be most polar bond.

To know more about  electronegativity, refer to the link:

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Answer:

The amount of water that evaporates from the earth is approximately equal to the amount that falls as precipitation.

Explanation:

Water evaporation is critical to climate because it is directly related to precipitation formation. Water that evaporates from rivers, lakes, oceans and even our bodies helps to form rain. This occurs when the temperature cools. Under these climatic conditions, water vapor returns to its liquid form (condensation) and falls through rainfall. The amount of water evaporated is basically equal to the amount of water that comes back to land in precipitation.

Final answer:

Sodium hydride donates a hydride ion to ethanol, resulting in the formation of hydrogen gas and the ethoxide ion in a sodium ethoxide complex.

Explanation:

The proton transfer reaction between sodium hydride (NaH) and ethanol (CH3CH2OH) involves sodium hydride acting as a base, donating a hydride ion (H-) to the proton (H+) of the ethanol. This reaction results in the formation of hydrogen gas (H2) and the ethoxide ion (CH3CH2O-), which remains in the solution complexed with the sodium ion (Na+). The balanced equation for this reaction is NaH + CH3CH2OH → H2 + Na+ + CH3CH2O-. This reaction utilizes the hydride ion from the sodium hydride as a nucleophile that abstracts a proton from the ethanol, leading to the evolution of hydrogen gas.