Drag the titles to the boxes to form correct pairs .not all titles will be used. Match the pairs of equation that represents concentric circles. Pleaseeeeeeee help

Drag The Titles To The Boxes To Form Correct Pairs .not All Titles Will Be Used. Match The Pairs Of Equation

Answers

Answer 1

Answer:

The concentric circles are

[tex]3x^{2}+3y^{2}+12x-6y-21=0[/tex]  and [tex]4x^{2}+4y^{2}+16x-8y-308=0[/tex]

[tex]5x^{2}+5y^{2}-30x+20y-10=0[/tex]  and [tex]3x^{2}+3y^{2}-18x+12y-81=0[/tex]

[tex]4x^{2}+4y^{2}-16x+24y-28=0[/tex]  and [tex]2x^{2}+2y^{2}-8x+12y-40=0[/tex]

[tex]x^{2}+y^{2}-2x+8y-13=0[/tex]  and  [tex]5x^{2}+5y^{2}-10x+40y-75=0[/tex]

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]

where

(h,k) is the center and r is the radius

Remember that

Concentric circles, are circles that have the same center

so

Convert each equation in standard form and then compare the centers

The complete answer in the attached document

Part 1) we have

[tex]3x^{2}+3y^{2}+12x-6y-21=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](3x^{2}+12x)+(3y^{2}-6y)=21[/tex]

Factor the leading coefficient of each expression

[tex]3(x^{2}+4x)+3(y^{2}-2y)=21[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex]3(x^{2}+4x+4)+3(y^{2}-2y+1)=21+12+3[/tex]

[tex]3(x^{2}+4x+4)+3(y^{2}-2y+1)=36[/tex]

Rewrite as perfect squares

[tex]3(x+2)^{2}+3(y-1)^{2}=36[/tex]

[tex](x+2)^{2}+(y-1)^{2}=12[/tex]

therefore

The center is the point (-2,1)                                  

Part 2) we have

[tex]5x^{2}+5y^{2}-30x+20y-10=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](5x^{2}-30x)+(5y^{2}+20y)=10[/tex]

Factor the leading coefficient of each expression

[tex]5(x^{2}-6x)+5(y^{2}+4y)=10[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex]5(x^{2}-6x+9)+5(y^{2}+4y+4)=10+45+20[/tex]

[tex]5(x^{2}-6x+9)+5(y^{2}+4y+4)=75[/tex]

Rewrite as perfect squares

[tex]5(x-3)^{2}+5(y+2)^{2}=75[/tex]

[tex](x-3)^{2}+(y+2)^{2}=15[/tex]

therefore

The center is the point (3,-2)      

Part 3) we have

[tex]x^{2}+y^{2}-12x-8y-100=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](x^{2}-12x)+(y^{2}-8y)=100[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex](x^{2}-12x+36)+(y^{2}-8y+16)=100+36+16[/tex]

[tex](x^{2}-12x+36)+(y^{2}-8y+16)=152[/tex]

Rewrite as perfect squares

[tex](x-6)^{2}+(y-4)^{2}=152[/tex]

therefore

The center is the point (6,4)      

Part 4) we have

[tex]4x^{2}+4y^{2}-16x+24y-28=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](4x^{2}-16x)+(4y^{2}+24y)=28[/tex]

Factor the leading coefficient of each expression

[tex]4(x^{2}-4x)+4(y^{2}+6y)=28[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex]4(x^{2}-4x+4)+4(y^{2}+6y+9)=28+16+36[/tex]

[tex]4(x^{2}-4x+4)+4(y^{2}+6y+9)=80[/tex]

Rewrite as perfect squares

[tex]4(x-2)^{2}+4(y+3)^{2}=80[/tex]

[tex](x-2)^{2}+(y+3)^{2}=20[/tex]

therefore

The center is the point (2,-3)  

Part 5) we have

[tex]x^{2}+y^{2}-2x+8y-13=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](x^{2}-2x)+(y^{2}+8y)=13[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex](x^{2}-2x+1)+(y^{2}+8y+16)=13+1+16[/tex]

[tex](x^{2}-2x+1)+(y^{2}+8y+16)=30[/tex]

Rewrite as perfect squares

[tex](x-1)^{2}+(y+4)^{2}=30[/tex]

therefore

The center is the point (1,-4)  

Part 6) we have

[tex]5x^{2}+5y^{2}-10x+40y-75=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](5x^{2}-10x)+(5y^{2}+40y)=75[/tex]

Factor the leading coefficient of each expression

[tex]5(x^{2}-2x)+5(y^{2}+8y)=75[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex]5(x^{2}-2x+1)+5(y^{2}+8y+16)=75+5+80[/tex]

[tex]5(x^{2}-2x+1)+5(y^{2}+8y+16)=160[/tex]

Rewrite as perfect squares

[tex]5(x-1)^{2}+5(y+4)^{2}=160[/tex]

[tex](x-1)^{2}+(y+4)^{2}=32[/tex]

therefore

The center is the point (1,-4)  

Part 7) we have

[tex]4x^{2}+4y^{2}+16x-8y-308=0[/tex]

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](4x^{2}+16x)+(4y^{2}-8y)=308[/tex]

Factor the leading coefficient of each expression

[tex]4(x^{2}+4x)+4(y^{2}-2y)=308[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex]4(x^{2}+4x+4)+4(y^{2}-2y+1)=308+16+4[/tex]

[tex]4(x^{2}+4x+4)+4(y^{2}-2y+1)=328[/tex]

Rewrite as perfect squares

[tex]4(x+2)^{2}+4(y-1)^{2}=328[/tex]

[tex](x+2)^{2}+(y-1)^{2}=82[/tex]

therefore

The center is the point (-2,1)  

Part 8) Part 9) and Part 10)  in the attached document


Related Questions

sin y +cos y + tan y sin y = sec y +cos y tan y. Verify the Identity. Show all Steps!

Answers

[tex]\bf sin(y)+cos(y)+tan(y)sin(y)=sec(y)+cos(y)tan(y) \\\\[-0.35em] ~\dotfill\\\\ sin(y)+cos(y)+tan(y)sin(y)\implies sin(y)+cos(y)+\cfrac{sin(y)}{cos(y)}\cdot sin(y) \\\\\\ sin(y)+cos(y)+\cfrac{sin^2(y)}{cos(y)}\implies \stackrel{\textit{using the LCD of cos(y)}}{\cfrac{sin(y)cos(y)+cos^2(y)+sin^2(y)}{cos(y)}} \\\\\\ \cfrac{sin(y)cos(y)+\stackrel{cos^2(y)+sin^2(y)}{1}}{cos(y)}\implies \cfrac{sin(y)cos(y)+1}{cos(y)} \\\\\\ \cfrac{sin(y)}{cos(y)}\cdot cos(y)+\cfrac{1}{cos(y)}\implies tan(y)cos(y)+sec(y)[/tex]

Find the final amount for a $750 investment at 5.25% interest compound semiannually for 25 years

Answers

Answer:

=$2739.81

Step-by-step explanation:

To find the total amount if the interest is compounded, we use the compound interest formula.

A=P(1+R/100)ⁿ

A is the amount, P- principal, is the invested amount R is the % interest rate, n is the number if periods.

If compounded semi-annually, it means we have two periods in 1 year

The rate is also divided by 2

Thus 25 years have (25×2) = 50 periods.

A= 750(1+5.25/200)⁵⁰

=750(1.02625)⁵⁰

=$2739.81

3
[tex]( - x + 12) - ( - 4x + 2)[/tex]

Answers

Answer:

3x+10

Step-by-step explanation:

( - x + 12) - (  - 4x + 2)

Distribute the minus sign

( - x + 12) + 4x - 2

Combine like terms

3x +10

classify XYZ.

A. Scalene triangle
B. Right triangle
C. Isosceles triangle
D. Equilateral triangle ​

Answers

Answer:

Scalene Triangle

Step-by-step explanation:

By definition, scalene triangles have 3 sides of unequal length.

FYI,

Right Triangle : triangle with one of the angles = 90°

Isosceles Triangles: Triangle with 2 sides of the same length.

Equilateral triangle: Triangle with 3 sides of the same length.

Find the equation in slope-intercept form that describes a line through (4, –2) with slope –3

Answers

Answer:

y = - 3x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here slope m = - 3, hence

y = - 3x + c ← is the partial equation

To find c substitute (4, - 2) into the partial equation

- 2 = - 12 + c ⇒ c = - 2 + 12 = 10

y = - 3x + 10 ← equation of line

Answer:   [tex]y=-3x+10[/tex]

Step-by-step explanation:

The equation of a line in intercept form: [tex]y=mx+c[/tex]

The equation of a line passing through (a,b) and has slope m is given by :_

[tex](y-b)=m(x-a)[/tex]

Similarly, the  equation in slope-intercept form that describes a line through (4, -2) with slope -3 will be :_

[tex](y-(-2))=-3(x-4)\\\\\Rightarrow\ y+2=-3x+12\\\\\Rightarrow\ y=-3x+12-2\\\\\Rightarrow\ y=-3x+10\ \ \text{In intercept form}[/tex]

Hence, the equation in slope-intercept form that describes a line through (4, -2) with slope -3 = [tex]y=-3x+10[/tex]

Simplify the following algebraic expression: 6(2y + 8) - 2(3y - 2)

Answers

Answer:

[tex]\large\boxed{6y+52}[/tex]

Step-by-step explanation:

In this question, we're going to simplify the expression.

We would do this by distributing and solving after.

Solve:

[tex]6(2y + 8) - 2(3y - 2)\\\\\text{Distribute the 6 to the 2y and 8}\\\\12y+48- 2(3y - 2)\\\\\text{Distribute the -2 to the 3y and -2}\\\\12y+48-6y+4\\\\\text{Combine like terms}\\\\6y+48+4\\\\\boxed{6y+52}[/tex]

When you're done solving, you should get 6y+52

This means that the simplified version would be 6y+52

I hope this helped you out.Good luck on your academics.Have a fantastic day!
The answer is 6y+52
Always show ur work

Solve: ( Brainliest ) -- TIME LIMIT: 8:00 minutes

2/3·z=10/9

Answer in proper and improper

Answers

Answer:

z = 5/3 or 1 2/3

Step-by-step explanation:

2/3·z=10/9

Multiply each side by 3/2

3/2*2/3·z=10/9*3/2

z = 30/18

We can simplify by dividing the top and bottom by 6

z = 5/3

Changing to a mixed number

z =1 2/3

Answer:

1⅔ [OR 5⁄3]

Step-by-step explanation:

2 × ? = 10

---------------

3 × ? = 9

That would be 1⅔.

I am joyous to assist you anytime.

What is the inverse of the function f(x) = 2x + 17

Answers

To find the inverse of a function switch the place of y (aka f(x) ) with x. Then solve for y.

Original equation:

y = 2x + 17

Switched:

x = 2y + 17

Solve for y by isolating it:

x - 17 = 2y + 17 - 17

x - 17 = 2y

(x - 17)/2 = 2y/2

[tex]\frac{1}{2}x-\frac{17}{2}= y[/tex]

Hope this helped!

~Just a girl in love with Shawn Mendes

Determine if parallel, perpendicular, or neither.

3y+4x=12
-6y=8x+1

Answers

They are parallel

You have to put the two equations into slope-intercept form to figure out if they are parallel or perpendicular.

Slope-intercept: y=mx+b

The first equation in slope intercept form is: y = -4/3x + 4
Slope of -4/3

The second equation in slope intercept form is: y = -4/3x - 6
Slope of -4/3

Since the slopes are equal and the y-intercepts are different, the two lines are parallel

~~hope this helps~~

The longer base of an isosceles trapezoid measures 18 ft. The nonparallel sides measure 8 ​ft, and the base angles measure 75 degrees.
​a) Find the length of a diagonal.
​b) Find the area.

Answers

Answer:

a) The length of the diagonal is 17.71 feet

b)  The area of the trapezoid is 123.14 feet²

Step-by-step explanation:

* Lets explain how to solve the problem

- Look to the attached figure

- ABCD is an isosceles trapezoid

∵ DC is the longer base with length 18 feet

∵ AD and BC are the two non-parallel sides with length 8 feet

∵ ∠ ADC and ∠ BCD are the bases angles with measure 75°

- AE and BF are ⊥ DC

# In Δ BFC

∵ m∠BFC = 90° ⇒ BF ⊥ CD

∵ m∠C = 75°

∵ BC = 8

∵ sin∠C = BF/BC

∴ sin(75) = BF/8 ⇒ multiply both sides by 8

BF = 8 × sin(75) = 7.73

∵ cos∠C = CF/BC

∴ cos(75) = CF/8 ⇒ multiply both sides by 8

CF = 8 × cos(75) = 2.07

# In Δ BFD

∵ m∠BFD = 90°

∵ DF = CD - CF

DF = 18 - 2.07 = 15.93

∵ BD = √[(DF)² + (BF)²] ⇒ Pythagoras Theorem

BD = √[(15.93)² + (7.73)²] = 17.71

a)

∵ BD is the diagonal of the trapezoid

* The length of the diagonal is 17.71 feet

b)

- The area of any trapezoid is A = 1/2 (b1 + b2) × h, where b1 and b2

  are the barallel bases and h is the height between the two bases

∵ b1 is CD

∴ b1 = 18

∵ b2 is AB

∵ AB = CD - (CF + DE)

∵ ABCD is an isosceles trapezoid

∴ CF = DE

AB = 18 - (2.07 + 2.07) = 13.86

- BF is the perpendicular between AB and CD

∴ BF = h

h = 7.73

∵ A = 1/2 (18 + 13.86) × 7.73 = 123.14

* The area of the trapezoid is 123.14 feet²

r=2sec(theta) converted into a cartesian equation

Answers

[tex]\bf r=2sec(\theta )\qquad \begin{cases} x=rcos(\theta )\\ \frac{x}{r}=cos(\theta ) \end{cases}\qquad \implies r=2\cdot \cfrac{1}{cos(\theta )}\implies r=\cfrac{2}{~~\frac{x}{r}~~} \\\\\\ r=\cfrac{\frac{2}{1}}{~~\frac{x}{r}~~}\implies r=\cfrac{2r}{x}\implies x=\cfrac{2~~\begin{matrix} r \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} r \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies x=2[/tex]

Which equation shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation 3x-5=-2+10

Answers

Final answer:

To isolate the variable terms on one side and the constant terms on the other side of the equation 3x - 5 = -2 + 10, add 2 to both sides, simplify to 3x - 3 = 10, then add 3 to both sides to get the final simplified equation 3x = 13.

Explanation:

The equation 3x - 5 = -2 + 10 needs to be rearranged to isolate the variable terms on one side and the constant terms on the other. To do this, follow these steps:

Add 2 to both sides to move the constant term from the right to the left side: 3x - 5 + 2 = 10.Simplify both sides: 3x - 3 = 10.Add 3 to both sides to completely isolate the constant terms on one side: 3x = 10 + 3.Simplify the equation: 3x = 13.

Now, we have successfully isolated the variable terms (3x) on one side of the equation and the constant terms (13) on the other side.

About 95% of sixth-grade students will have heights between ______ inches and ______inches.

Answers

Answer:

53.4 and 62.6

Step-by-step explanation:

Answer:

53.4 and 62.6

Step-by-step explanation:

Got it right :/

All rhombuses are. Parallelograms square rectangules quadrilaterals

Answers

Step-by-step explanation:

Look at the picture.

All rhombuses are

parallelograms

quadrilaterals

(50 Points)

Drag each description to the correct location on the table. Each description can be used more than once.

Some systems of equations and their graphs are given in the table. For each system, place the description(s) in the box that correctly describe the type of system shown.

Please helppppp :((((​

Answers

3x+y=3 is the red line and
6x+2y=-4 is the blue line
I don’t know what descriptions you were given but these two equations are in standard form. They are also parallel to one another and have a negative slope
3x+y=3 in slope form is y=-3x+3
6x+2y=-4 in slope form is y=-3x-2
Hope this helps

Answer:3x+y=3 is the red line.

6x+y=-4 is the blue line.

Step-by-step explanation:I answer it on the test it is right..

rectangle with a side length of 11" and a diagonal of 14" what is the perimeter

Answers

Answer:

10sqrt3+22

Step-by-step explanation:

Ok, let us imagine it as a sort of rectangle split upon its diagonal.

Using that, we can Pythag it out,

11^2+b^2=14^2

121+b^2=196

b^2=75

b=sqrt75

b=5sqrt3

Ok, using this info, we find the perimeter,

5sqrt3+5sqrt3+11+11

10sqrt3+22

The answer is 10sqrt3+22

Hello!

The answer is:

The perimeter of the rectangle is equal to 39.32".

[tex]Perimeter=39.32in[/tex]

Why?

Since we are working with a rectangle, we can use the Pythagorean theorem to find the missing side of the rectangle and calculate its perimeter. We must remember that we can divide a rectangle into two equal right triangles.

According to the Pythagorean Theorem, we have:

[tex]a^{2}=b^{2}+c^{2}[/tex]

Where:

a, represents the hypotenuse of the triangle which is equal to the diagonal of the given rectangle (14")

b and c are the other sides of the triangle.

Now, let be "a" 14" and "b" 11"

So, solving we have:

[tex]a^{2}=b^{2}+c^{2}[/tex]

[tex]14^{2}=11^{2}+c^{2}[/tex]

[tex]14^{2}-11^{2}=c^{2}[/tex]

[tex]14^{2}-11^{2}=c^{2}\\\\c=\sqrt{14^{2} -11^{2} }=\sqrt{196-121}=\sqrt{75}=8.66in[/tex]

Now, that we already know the the missing side of the rectangle, we can calculate the perimeter using the following formula:

[tex]Perimeter=2base+2length\\\\Perimeter=2*11in+2*8.66in=22in+17.32in=39.32n[/tex]

Hence, we have that the perimeter of the rectangle is equal to 39.32".

Have a nice day!

a line passes through (3,-2) and (6,2). write an equation in point-slope form. rewrite the equation in standard form ​

Answers

again, bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

[tex]\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-(-2)}{6-3}\implies \cfrac{2+2}{6-3}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=\cfrac{4}{3}(x-3)\implies y+2=\cfrac{4}{3}x-4 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf y=\cfrac{4}{3}x-6\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y)=3\left( \cfrac{4}{3}x-6 \right)}\implies 3y=4x-18 \\\\\\ -4x+3y=-18\implies \stackrel{\textit{standard form}}{4x-3y=18}[/tex]

the area of this rectangle is 4x^2.what does the coefficient 4 mean in terms of the problem?

Answers

Answer:

If the width of the rectangle is x than the length is 4x because 4x*x is 4x^2

Step-by-step explanation:

PLEASE HELP!!!

The following table shows a proportional relationship between A and B.


A= 8, 24, 40 B= 3, 9, 15


Write an equation to describe the relationship between A and B.

Answers

Answer:

b=3/8a

Step-by-step explanation:

Have a good night/day<3

To find the equation describing the proportional relationship between A and B, we divide B by A and find that the constant of proportionality is 3/8. Thus, the equation is B = (3/8)A.

To find the equation that describes the proportional relationship between A and B, we can start by examining the given pairs of values. For A = 8, B = 3; for A = 24, B = 9; and for A = 40, B = 15. We observe that as A increases, B increases at a constant rate. This suggests a direct proportionality between A and B.

To determine the constant of proportionality (the rate at which B changes with respect to A), we can divide the values of B by the corresponding values of A. Doing so, we find:

B/A for (8, 3) = 3/8B/A for (24, 9) = 9/24B/A for (40, 15) = 15/40

All these ratios reduce to 3/8, which is the constant of proportionality. Therefore, B is 3/8 times A, which we can express as:

B = (3/8)A

This equation represents the proportional relationship between A and B, with the constant of proportionality being 3/8.

a^3b^-2c^-1d if a=2 b=4 c=10 d=15 express as a reduced fraction

Answers

[tex]\bf a^3b^{-2}c^{-1}d\implies \cfrac{a^3d}{b^2c}\qquad \begin{cases} a=2\\ b=4\\ c=10\\ d=15 \end{cases}\implies \cfrac{2^3\cdot 15}{4^2\cdot 10}\implies \cfrac{120}{160}\implies \cfrac{3}{4}[/tex]

What is the solution to the system of equations graphed below?

А.(6, 0)
B.(1, 5)
С.(0.3)
D.(0,6)

Answers

Answer:

B

Step-by-step explanation:

The solution to a system of equations given graphically is at the point of intersection of the 2 lines, that is

Solution = (1, 5 ) → B

[tex]\huge{\boxed{\text{(1, 5)}}}[/tex]

All you need to do is find where the intersection of the lines is located.

Count how many units to the right. [tex]1[/tex] This is our [tex]x[/tex] value.

Count how many units up. [tex]5[/tex] This is our [tex]y[/tex] value.

Which of the following is the equation of a line that passes through (-2,1) and (-4,-3)?

Answers

Points [tex]X(-2,1)[/tex] and [tex](-4,-3)[/tex] are defined therefore we have all data we need to construct equation.

Linear function has a form of,

[tex]y=ax+b[/tex]

First calculate the slope a.

[tex]a=\dfrac{dy}{dx}=\dfrac{-3-1}{-4-1}=\dfrac{-4}{-5}=\dfrac{4}{5}[/tex]

Now plug in the coordinates of either one of the points into the linear function. I'll pick point X.

[tex]y=ax+b\Longrightarrow1=\dfrac{4}{5}\cdot(-2)+b[/tex]

Now just solve for b.

[tex]1=-\dfrac{8}{5}+b\Longrightarrow b=\dfrac{13}{5}[/tex]

The equation is therefore,

[tex]\boxed{y=\dfrac{4}{5}x+\dfrac{13}{5}}[/tex]

Hope this helps.

r3t40

Which is a perfect square?

Answers

Answer:

121

Step-by-step explanation:

THIS IS BECAUSE 11*11 = 121

Answer:

121

Step-by-step explanation:

121= 11x11, that is the only option

140 has no square

168 is close, but still isn't a square

195 is 1 away from a square, but not a square

What does h(40)=1820 mean in terms of the problem ? Help please

Answers

Final answer:

The notation h(40)=1820 means that the function h produces an output of 1820 when the input is 40, although additional context is needed to determine what h represents specifically in this scenario.

Explanation:

The expression h(40)=1820 typically means that a function h is being evaluated at the input value of 40, and the output is 1820. This could represent a variety of contexts, such as the height of a rocket in meters at 40 seconds after launch, the amount of money saved after 40 weeks, or any other situation described by a function where the variable h depends on the number 40. Without additional context, it's impossible to say precisely what 1820 refers to, but it is the result of the function h when the input is 40.

Which numbers are irrational? Check all that apply

Answers

Final answer:

Irrational numbers cannot be expressed as a fraction or ratio of two integers and have decimal representations that go on forever without repeating.

Explanation:

Irrational numbers are numbers that cannot be expressed as a fraction or ratio of two integers. They are decimal numbers that go on forever without repeating. Examples of irrational numbers include π, √2, and √3. These numbers cannot be expressed as a simple fraction or as a terminating or repeating decimal.

Do you guys know the answer for number 4

Answers

Answer:

G !!! Have a good day BLOODY

can someone help with this question?

Answers

Answer:

y ≤ ¼x + 1

Step-by-step explanation:

Starting from the y-intercept of course, use rise\run until you hit another endpoint [finding the rate of change (slope)]. That means me we go up north one block, then go over four blocks east, and since the slope is already simplified, we do not need to go any further. Now all we have left is to determine the correct inequality symbol, and since we know that the bottom portion of the graph is shared, we automatically know it is less than, but to check this, we need to do what is called a zero-interval test [do not recall the actual term], meaning that we plug in 0 for both y and x, getting 0 < 1, which is a GENUINE statement, so the bottom portion stays shaded, otherwise we would have had to shade the top portion if it were a false statement. Finally, we have to determine if we have to add an equivalence line under the inequality symbol, and we DO because as you can see, the line is SOLID BLACK. If it were DASHED BLACK, then it would stay "<" instead of "≤".

I am joyous to assist you anytime.

Given the system of equations, match the following items.

x + 3y = 5
x - 3y = -1

Answers

To solve the system of equations x + 3y = 5 and x - 3y = -1, we add both equations to get 2x = 4, solve for x to find x = 2, and then substitute x back into one of the equations to find y = 1, resulting in the solution (2, 1).

The solution of the system of linear equations given by x + 3y = 5 and x - 3y = -1 involves manipulating the equations to find the values of x and y that satisfy both equations simultaneously. One common method to solve these is to add or subtract the equations, which eliminates one variable, making it possible to solve for the other.

Starting with the addition method, we align the equations and add them together:

x + 3y = 5

x - 3y = -1

Adding these equations, we get 2x = 4, and solving for x gives us x = 2. We can substitute x = 2 back into one of the original equations to find the value of y, yielding y = 1.

The solution to the system is the intersection point of the two lines represented by the equations, which is the point (2, 1).

Solve for x. Write the smaller solution first, and the larger solution second. (x-10)^2-1=0

Answers

Answer:

[tex]x_1 = 9[/tex] and [tex]x_2 = 11[/tex].

Step-by-step explanation:

Start by adding 1 to both sides of this equation.

[tex](x - 10)^{2} = 1[/tex].

The square of what number or numbers will lead to the number "1"? It turns out that not only [tex]1^{2} = 1[/tex], but [tex](-1)^{2}= 1[/tex] as well. In other words, the value [tex](x - 10)[/tex] can be either 1 or -1. Either way, the equation is still going to hold. That's the reason why there are two solutions to this equation.

Consider the case when [tex]x - 10 = 1[/tex]. Add 10 to both sides of the equation. [tex]x = 11[/tex].

Now, consider the case when [tex]x - 10 = -1[/tex]. Again, add 10 to both sides of the equation, [tex]x = 9[/tex].

Order the two solutions in an increasing order:

[tex]x_1 = 9[/tex],[tex]x_2 = 11[/tex].

Help!!
Which of the following options is the cheapest per month over all? Assume a month has 30 days
A. rent 11.95 a day
B Lease 149.00 a month 3180 due at signing
C. Buying 16,000.00
D Finance 389.00 /month

Answers

Answer:

The correct option is A.

Step-by-step explanation:

We need to find the cheapest per month over all.

Assume a month has 30 days.

In option A:

Rent = 11.95 a day

Monthly rent = 11.95 × 30 = 358.5

Total renting amount is 358.5.

In option B:

Lease = 149.00 a month 3180 due at signing

Total amount = 149 + 3180 = 3329

Total leasing amount is 3329.

In option C:

Buying = 16,000

In option D:

Finance = 389.00 /month

The cheapest amount for a month is 358.5 .Therefore the correct option is A.

Answer: renting a car

Step-by-step explanation:

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