Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99​% of all males.​ (Accommodating 100% of males would require very wide seats that would be much too​ expensive.) Men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 0.9 in. Find Upper P 99. That​ is, find the hip breadth for men that separates the smallest 99​% from the largest 1​%.

Answer:

69%

Step-by-step explanation:

If Motor Works is selected, the probability that the worker is a female is 70%. If City Bank is selected, the probability is 68%.

But we don't know what company will be selected, we only know that they have the same probability, 50-50.

So, with 50% of probability the worker will be female with a 70% of probability (because they selected from Motor Works) and with 50% of probability the worker will be female with a 68% of probability (they selected from City Bank).

We express this as 50%*70% + 50%*68% = 69%

The multiplication means that both probabilities happen together and the sum means that happens one thing or the other (they select Motor Works or City Bank)

Final answer:

The probability that a randomly selected worker from either Motor Works or City Bank is female is 0.69, or 69%.

Explanation:

To calculate the probability that a randomly selected worker is female, we need to consider the probability of selecting each company and then the probability of selecting a female worker from that company. We are given that the probability of selecting Motor Works or City Bank is equal, hence it is 1/2 for each. Now, let's calculate the overall probability using the following steps:

Calculate the probability of selecting a female from Motor Works: P(Female at Motor Works) = Probability of Motor Works times Probability of female at Motor Works = 1/2 times 70% = 0.35.

Calculate the probability of selecting a female from City Bank: P(Female at City Bank) = Probability of City Bank times Probability of female at City Bank = 1/2 times 68% = 0.34.

The total probability of selecting a female from either company is the sum of these individual probabilities: P(Female) = P(Female at Motor Works) + P(Female at City Bank) = 0.35 + 0.34 = 0.69.

The probability that a randomly selected worker from either company is female is therefore 0.69, or 69%.

[tex]\Sigma[/tex] should have parameterization

[tex]\vec r(\varphi,\theta)=a\sin\varphi\cos\theta\,\vec\imath+a\sin\varphi\sin\theta\,\vec\jmath+a\cos\varphi\,\vec k[/tex]

if it's supposed to capture the sphere of radius [tex]a[/tex] centered at the origin. ([tex]\sin\theta[/tex] is missing from the second component)

a. You should substitute [tex]x=a\sin\varphi\cos\theta[/tex] (missing [tex]\cos\theta[/tex] this time...). Then

[tex]x^2+y^2+z^2=(a\sin\varphi\cos\theta)^2+(a\sin\varphi\sin\theta)^2+(a\cos\varphi)^2[/tex]

[tex]x^2+y^2+z^2=a^2\left(\sin^2\varphi\cos^2\theta+\sin^2\varphi\sin^2\theta+\cos^2\varphi\right)[/tex]

[tex]x^2+y^2+z^2=a^2\left(\sin^2\varphi\left(\cos^2\theta+\sin^2\theta\right)+\cos^2\varphi\right)[/tex]

[tex]x^2+y^2+z^2=a^2\left(\sin^2\varphi+\cos^2\varphi\right)[/tex]

[tex]x^2+y^2+z^2=a^2[/tex]

as required.

b. We have

[tex]\vec r_\varphi=a\cos\varphi\cos\theta\,\vec\imath+a\cos\varphi\sin\theta\,\vec\jmath-a\sin\varphi\,\vec k[/tex]

[tex]\vec r_\theta=-a\sin\varphi\sin\theta\,\vec\imath+a\sin\varphi\cos\theta\,\vec\jmath[/tex]

[tex]\vec r_\varphi\times\vec r_\theta=a^2\sin^2\varphi\cos\theta\,\vec\imath+a^2\sin^2\varphi\sin\theta\,\vec\jmath+a^2\cos\varphi\sin\varphi\,\vec k[/tex]

[tex]\|\vec r_\varphi\times\vec r_\theta\|=a^2\sin\varphi[/tex]

c. The surface area of [tex]\Sigma[/tex] is

[tex]\displaystyle\iint_\Sigma\mathrm dS=a^2\int_0^\pi\int_0^{2\pi}\sin\varphi\,\mathrm d\theta\,\mathrm d\varphi[/tex]

You don't need a substitution to compute this. The integration limits are constant, so you can separate the variables to get two integrals. You'd end up with

[tex]\displaystyle\iint_\Sigma\mathrm dS=4\pi a^2[/tex]

# # #

Looks like there's an altogether different question being asked now. Parameterize [tex]\Sigma[/tex] by

[tex]\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k[/tex]

with [tex]\sqrt2\le u\le\sqrt6[/tex] and [tex]0\le v\le2\pi[/tex]. Then

[tex]\|\vec s_u\times\vec s_v\|=u\sqrt{1+4u^2}[/tex]

The surface area of [tex]\Sigma[/tex] is

[tex]\displaystyle\iint_\Sigma\mathrm dS=\int_0^{2\pi}\int_{\sqrt2}^{\sqrt6}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv[/tex]

The integrand doesn't depend on [tex]v[/tex], so integration with respect to [tex]v[/tex] contributes a factor of [tex]2\pi[/tex]. Substitute [tex]w=1+4u^2[/tex] to get [tex]\mathrm dw=8u\,\mathrm du[/tex]. Then

[tex]\displaystyle\iint_\Sigma\mathrm dS=\frac\pi4\int_9^{25}\sqrt w\,\mathrm dw=\frac{49\pi}3[/tex]

# # #

Looks like yet another different question. No figure was included in your post, so I'll assume the normal vector points outward from the surface, away from the origin.

Parameterize [tex]\Sigma[/tex] by

[tex]\vec t(u,v)=u\,\vec\imath+u^2\,\vec\jmath+v\,\vec k[/tex]

with [tex]-1\le u\le1[/tex] and [tex]0\le v\le 2[/tex]. Take the normal vector to [tex]\Sigma[/tex] to be

[tex]\vec t_u\times\vec t_v=2u\,\vec\imath-\vec\jmath[/tex]

Then the flux of [tex]\vec F[/tex] across [tex]\Sigma[/tex] is

[tex]\displaystyle\iint_\Sigma\vec F\cdot\mathrm d\vec S=\int_0^2\int_{-1}^1(u^2\,\vec\jmath-uv\,\vec k)\cdot(2u\,\vec\imath-\vec\jmath)\,\mathrm du\,\mathrm dv[/tex]

[tex]\displaystyle\iint_\Sigma\vec F\cdot\mathrm d\vec S=-\int_0^2\int_{-1}^1u^2\,\mathrm du\,\mathrm dv[/tex]

[tex]\displaystyle\iint_\Sigma\vec F\cdot\mathrm d\vec S=-2\int_{-1}^1u^2\,\mathrm du=-\frac43[/tex]

If instead the direction is toward the origin, the flux would be positive.

Answer:  0.0136

Step-by-step explanation:

Given : Mean : [tex]\mu=\ 25[/tex]

Standard deviation : [tex]\sigma= 3.2[/tex]

Sample size : [tex]n=50[/tex]

The formula to calculate the z-score :-

[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

For x = 24

[tex]z=\dfrac{24-25}{\dfrac{3.2}{\sqrt{50}}}=-2.20970869121\aprox-2.21[/tex]

The P-value =[tex]P(z\leq24)=0.0135526\approx0.0136[/tex]

Hence, the probability that the sample mean age for 50 randomly selected women to marry is at most 24 years = 0.0136

Answer: 8

Step-by-step explanation:

The formula to calculate the simple interest is given by :-

[tex]S.I. =Prt[/tex], where P is the principal amount , r is rate of interest and t is time.

Given: The principal amount : P = $225

The rate of interest : r = 3.5% =0.035

Simple Interest : SI = $63

Put these value in the above formula , we get

[tex] 63=225\times0.035t\\\\\Rightarrow\ t=\dfrac{63}{225\times0.035}\\\\\Rightarrow\ t=8[/tex]

Hence, the term of loan = 8

Answer: [tex]y=\dfrac{1}{3}x+4[/tex]

Step-by-step explanation:

The equation of a line passing through (a,b) and (c,d) is given by :_

[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]

The given points :  (3,5) and (9,6)

Then , the equation of a line passing through (3,5) and (9,6)  will be :-

[tex]y-5=\dfrac{6-5}{9-3}(x-3)\\\\\Rightarrow\ y-5=\dfrac{1}{3}(x-3)\\\\\ y=\dfrac{1}{3}x-1+5\\\\\Rightarrow\ y=\dfrac{1}{3}x+4[/tex]

Hence, the equation of the line in slope -intercept form :  [tex]y=\dfrac{1}{3}x+4[/tex]

Final answer:

The answer provides the equation of the line passing through the points (3,5) and (9,6) in slope-intercept form.Using the points (3,5) and (9,6), the change in [tex]\( y \) is \( 6 - 5 = 1 \) and the change in \( x \) is \( 9 - 3 = 6 \). So, the slope is \( \frac{1}{6} \).[/tex]

Explanation:

Equation of the line:

The slope of a line represents the rate of change between two points on the line. It indicates how much the dependent variable (y-coordinate) changes for a given change in the independent variable (x-coordinate).

In this case, given the two points (3,5) and (9,6), we can calculate the slope using the formula:

[tex]\[ \text{slope} = \frac{{\text{change in } y}}{{\text{change in } x}} \][/tex]

Using the points (3,5) and (9,6), the change in [tex]\( y \) is \( 6 - 5 = 1 \) and the change in \( x \) is \( 9 - 3 = 6 \). So, the slope is \( \frac{1}{6} \).[/tex]

The slope of the tangent line to the curve defined by x = 6 + ln(t), y = t^2 + 6 at the point (6,7) can be found by differentiating x and y with respect to t and then substituting t = 1. The equation of the tangent line is y = 2x -5.

To find the equation of the tangent to the curve at the given point, we will first need to find the derivative (slope) at the given point. The equations given are x = 6 + ln(t) and y = t2 + 6. Given point is (6, 7).

Without eliminating the parameter, we differentiate both x and y with respect to t. This allows us to find dx/dt = 1/t and dy/dt = 2t. The slope of the tangent line at (6, 7) is then (dy/dt) / (dx/dt) = 2t * t = 2*t2.

Substitute the given point (6,7) into x = 6 + ln(t), to obtain t = e0 = 1. Therefore, the slope of the tangent line is 2*12 = 2.

The equation of the tangent line can be written as: (y - y1) = m*(x - x1), where m = 2 is the slope, and (x1, y1) is the given point (6, 7).Substitute these into the equation, gets us: y-7 = 2*(x - 6), which can be simplified to: y = 2x -5.

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The equation of the tangent to the curve at the point (6, 7) is y = 2x - 5.

To find the equation of the tangent to the curve without eliminating the parameter, we can use the parametric equations: x = 6 + ln(t) and y = t^2 + 6.

First, we need to find the derivative of y with respect to x and evaluate it at the given point (6, 7).

The derivative of y with respect to x is dy/dx = (dy/dt)/(dx/dt).

From the given equations, we can calculate dx/dt = 1/t and dy/dt = 2t.

Substituting these values into the derivative expression, we have dy/dx = (2t)/(1/t) = 2t^2.

Now, substitute the given x-coordinate (6) into the equation for x to find the corresponding t-value: 6 = 6 + ln(t) => ln(t) = 0 => t = 1.

Now, substitute the t-value (1) into the equation for y to find the corresponding y-coordinate: y = 1^2 + 6 = 7.

Therefore, the slope of the tangent at the point (6, 7) is 2(1)^2 = 2.

Using the point-slope form of a line, we can write the equation of the tangent line: y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope of the tangent.

Plugging in the values, we have y - 7 = 2(x - 6).

Simplifying the equation, we get y = 2x - 5.

Therefore, the equation of the tangent to the curve at the point (6, 7) is y = 2x - 5.

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Answer:

The value of Cp (measure of potential capability) is 6.33.

Step-by-step explanation:

Given information: Process average = 2 inches, process standard deviation = 0.05 inches, lower engineering specification limit = 1.6 inches and upper engineering specification limit =3.5 inches.

The formula for Cp (measure of potential capability) is

[tex]CP=\frac{USL-LSL}{6\sigma}[/tex]

Where, USL is upper specification limit, LSL is specification limit, σ is process standard deviation.

Substitute USL=3.5, LSL=1.6 and σ=0.05 in the above formula.

[tex]CP=\frac{3.5-1.6}{6(0.05)}[/tex]

[tex]CP=\frac{1.9}{0.3}[/tex]

[tex]CP=6.3333[/tex]

[tex]CP\approx 6.33[/tex]

Therefore the value of Cp (measure of potential capability) is 6.33.

We're looking for a solution of the form

[tex]y=\displaystyle\sum_{n=0}^\infty a_nx^n=a_0+a_1x+a_2x^2+\cdots[/tex]

Given that [tex]y(0)=1[/tex], we would end up with [tex]a_0=1[/tex].

Its first derivative is

[tex]y'=\displaystyle\sum_{n=0}^\infty na_nx^{n-1}=\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n[/tex]

The shifting of the index here is useful in the next step. Substituting these series into the ODE gives

[tex]\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n-\sum_{n=0}^\infty a_nx^n=x[/tex]

Both series start with the same-degree term [tex]x^0[/tex], so we can condense the left side into one series.

[tex]\displaystyle\sum_{n=0}^\infty\bigg((n+1)a_{n+1}-a_n\bigg)x^n=x[/tex]

Pull out the first two terms ([tex]x^0[/tex] and [tex]x^1[/tex]) of the series:

[tex]a_1-a_0+(2a_2-a_1)x+\displaystyle\sum_{n=2}^\infty\bigg((n+1)a_{n+1}-a_n\bigg)x^n=x[/tex]

Matching the coefficients of the [tex]x^0[/tex] and [tex]x^1[/tex] terms on either side tells us that

[tex]\begin{cases}a_1-a_0=0\\2a_2-a_1=1\end{cases}[/tex]

We know that [tex]a_0=1[/tex], so [tex]a_1=1[/tex] and [tex]a_2=1[/tex]. The rest of the coefficients, for [tex]n\ge2[/tex], are given according to the recurrence,

[tex](n+1)a_{n+1}-a_n=0\implies a_{n+1}=\dfrac{a_n}{n+1}[/tex]

so that [tex]a_3=\dfrac{a_2}3=\dfrac13[/tex], [tex]a_4=\dfrac{a_3}4=\dfrac1{12}[/tex], and [tex]a_5=\dfrac{a_4}5=\dfrac1{60}[/tex]. So the 5th degree approximation to the solution to this ODE centered at [tex]x=0[/tex] is

[tex]y\approx1+x+x^2+\dfrac{x^3}3+\dfrac{x^4}{12}+\dfrac{x^5}{60}[/tex]

Answer: 0.965

Step-by-step explanation:

Given : Water use in the summer is normally distributed with

[tex]\mu=311.4\text{ million gallons per day}[/tex]

[tex]\sigma=40 \text{ million gallons per day}[/tex]

Let X be the random variable that represents the quantity of water required on a particular day.

Z-score : [tex]\dfrac{x-\mu}{\sigma}[/tex]

[tex]\dfrac{350-311.4}{40}=0.965[/tex]

Now, the probability that a day requires more water than is stored in city reservoirs is given by:-

[tex]P(x>350)=P(z>0.965)=1-P(z<0.965)[/tex]

We can see that on comparing the above value to the given P(X > 350)= 1 - P(Z < b) , we get the value of b is 0.965.

Answer:

Probability from Urban Area = [tex]\frac{55}{89}[/tex]

Probability NOT from Rural Area = [tex]\frac{83}{89}[/tex]

Step-by-step explanation:

Total 178

Urban 110

Suburban 56

Rural 12

Hence, probability of x is number of x divided by total.

So, probability that she is from an urban area = 110/178 = 55/89

And

probability NOT a rural area (means urban and suburban which is 110+56=166) = 166/178 = 83/89

To calculate the probability of selecting a participant from an urban area, divide the number of urban participants (110) by the total number of participants (178), yielding approximately 0.61798. For the probability of not a rural area, sum the urban and suburban participants (110 + 56) and divide by the total, which gives approximately 0.93258.

The question asks about finding the probability of a participant being from an urban area and not from a rural area in a sample of young women in a STEM program.

The total number of participants is 178. Of these, 110 are from urban areas. To find the probability of selecting a participant from an urban area, we divide the number of urban participants by the total number of participants:

Probability (Urban) = Number of Urban Participants / Total Number of Participants = 110 / 178 ≈ 0.61798

Similarly, to find the probability of not selecting a participant from a rural area, we need to first find the number of participants who are not from rural areas. This is the sum of urban and suburban participants, or 110 + 56. Then we calculate:

Probability (Not Rural) = Number of Non-Rural Participants / Total Number of Participants = (110 + 56) / 178 ≈ 0.93258

Answer:

Skewed to the Right

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced problems.

Since the mean household income is  $64,424 and the median was $50,303 then the mean is larger than the median. When this occurs then the constructed histogram is always Skewed to the Right. This is because there are a couple of really large values that affect the mean but not the middle value of the data set.

This in term leads to the graph dipping in values the farther right you go and increasing the farther left you go, as shown in the example picture below.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer:

1. The values of |PQ|, |QR| and |RP| are 3, 3√5 and 6 respectively.

2. No.

3. No.

Step-by-step explanation:

The vertices of given triangle are P(0, 1, 5), Q(2, 3, 4), R(2, −3, 1).

Distance formula:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}[/tex]

Using distance formula we get

[tex]|PQ|=\sqrt{(2-0)^2+(3-1)^2+(4-5)^2}=\sqrt{9}=3[/tex]

[tex]|QR|=\sqrt{(2-2)^2+(-3-3)^2+(1-4)^2}=\sqrt{45}=3\sqrt{5}[/tex]

[tex]|RP|=\sqrt{(0-2)^2+(1-(-3))^2+(5-1)^2}=\sqrt{36}=6[/tex]

The values of |PQ|, |QR| and |RP| are 3, 3√5 and 6 respectively.

In a right angled triangle the sum of squares of two small sides is equal to the square of third side.

[tex](3)^2+(3\sqrt{5})^2=54\neq 6^2[/tex]

Therefore PQR is not a right angled triangle.

In an isosceles triangle, the length of two sides are equal.

The measure of all sides are different, therefore PQR is not an isosceles triangle.

Answer:

  (x, y, z) = (-4, 29, 17)

Step-by-step explanation:

These three equations have a unique solution. If you want "z arbitrary", you need to write a system of two equations with three variables (or, equivalently, a set of dependent equations).

It is convenient to let a graphing calculator, scientific calculator, or web site solve these.

_____

You can reduce the system to two equations in y and z by ...

  subtracting the last equation from the first:

     3y -7z = -32

  subtracting twice the last equation from the second:

     3y -2z = 53

Subtracting the first of these from the second, you get ...

  5z = 85

  z = 17

The remaining variable values fall out:

  y = (53+2z)/3 = 87/3 = 29

  x = -9 +2z -y = -9 +2(17) -29 = -4

These equations have the solution (x, y, z) = (-4, 29, 17).

Answer:

  DB = 13 cm

Step-by-step explanation:

ΔCAB ≅ ΔDBA by ASA, so CA ≅ DB by CPCTC.

CA = 13 cm, so DB = 13 cm.

Answer:

Step-by-step explanation:

Given : m(∠DAB) = m(∠CBA)

            m (CAB) = m(∠DBA)

            and CA = 13 cm

To find : measure of DB

In ΔCAB and ΔDAB

m(∠DAB) = m(∠CBA)     [given]

m(∠CAB) = m(∠DBA)     [given]

and AD is common in both the triangles.

Therefore, ΔCAB and ΔDAB will be congruent.    [By ASA property]

Therefore, CA = DB = 13 cm.

Answer:

1) [tex]y=2(1+0.081)^x[/tex]

2) 6.4 billion.

Step-by-step explanation:

1) Let the model that is used to find online jewelry sales ( in billions ) after x years,

[tex]y=a(1+r)^x[/tex]

Let 2003 is the initial year,

That is, for 2003, x = 0,

The sales on 2003 is 2 billion, y = 2,

⇒ [tex]2=a(1+r)^0\implies a=2[/tex]

Now, in 2013 they were approximately 5.5 1 billion

i.e. if x = 13 then y = 5.51,

[tex]\implies 5.51 = a(1+r)^{13}[/tex]

[tex]5.51=2(1+r)^{13}[/tex]

With help of graphing calculator,

r = 0.081,

Hence, the model that represents the given scenario is,

[tex]y=2(1+0.081)^x[/tex]

2) For 2015, x = 15,

Hence, online jewelry sales for 2015 would be,

[tex]y=2(1+0.081)^{15}=6.43302745602\approx 6.4\text{ billion}[/tex]

Answer:

-28 is the answer.

Step-by-step explanation:

84-56=28

56+28=84

-56+-28=-84

Answer:

[tex] - 56 + x = - 84 \\ x = 56 - 84 \\ \boxed{ x = - 28}[/tex]

Answer:

Step-by-step explanation:

Mean = 14

Std deviation of sample s = 0.64

n = sample size =7

Std error = [tex]\frac{s}{\sqrt{n} } =0.2419[/tex]

t critical for 95% two tailed = 2.02

Margin of error = 2.02*SE = 0.4886

a)Conf interval lower bound = 14-0.4886 = 13.5114

b)Upper bound = 14+0.4886 = 14.4886

c)Assumption

the data need to follow a normal distribution

Answer:

[tex]P=775[/tex]

Step-by-step explanation:

The Simple Interest Equation is [tex]A = P(1 + rt)[/tex]

where

A = Total Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

t = Time Period involved in months or years

In this case, we do not know the values ​​of the equation (A and P), but we know the amount of interest accrued

If we define our principal whit this formula, we are able to know the rest of the values:

[tex]A-P= interest[/tex]

clearing

[tex]A=interest+P[/tex]

replacing

[tex]426.25 + P = P (1+(0.11(5))[/tex]

Solving

[tex]426.25+P=1.55P[/tex]

[tex]P-1.55P=-426.25[/tex]

[tex]-0.55P=-426.65[/tex]

[tex]P=\frac{-426.25}{-0.55}[/tex]

[tex]P=775[/tex]

Answer:

Step-by-step explanation:

S.NO    QUATERS       PRICE ($)                 PRICE RELATIVES

                                                           [tex]I = \frac{q_i}{q_4} *100[/tex]

1                 q_1               10450                           104.51

2                q_2               10800                           108.01

3                 q_3               11450                            114.51

4                 q_2                9999                           100.00

Price Index is given as [tex]= \frac{\sum I}{n}[/tex]

                            [tex] = \frac{104.51+108.01+114.51+100}{4}[/tex]

                                       = 106.75

b) percentage point rise

[tex]for q_1 = \frac{q_2 -q_1}{q_1}*100[/tex]

          [tex]= \frac{108.01-104.51}{104.51}[/tex]

          = 3.34%

[tex]for q_2 = \frac{q_3 -q_2}{q_2}[/tex]

      [tex]= \frac{114.51-108.01}{108.01} *100[/tex]

          = 6.01%

[tex]for q_3 = \frac{q_4 -q_3}{q_3}[/tex]

         [tex]= \frac{100-114.51}{114.51} *100[/tex]

          = 12.67%

Answer:

  29.5 m 64° west of north

Step-by-step explanation:

A suitable vector calculator can add the vectors for you. (See attached.) Here, we have used North as the 0° reference and positive angles in the clockwise direction (as bearings are measured).

___

You can also use a triangle solver (provided by many graphing calculators and stand-alone apps). For this, and for manual calculation (below) it is useful to realize the angle difference between the travel directions is 70°.

___

Using the Law of Cosines to find the distance from start (d), we have (in meters) ...

  d² = 28.6² + 22² -2·28.6·22·cos(70°) ≈ 871.561

  d ≈ √871.561 ≈ 29.52 . . . . meters

The internal angle between the initial travel direction and the direction to the end point is found using the Law of Sines:

  sin(angle)/22 = sin(70°)/29.52

  angle = arcsin(22/29.52×sin(70°)) ≈ 44.44°

This angle is the additional angle the destination is west of the initial travel direction, so is ...

  20° west of north + 44.44° farther west of north = 64.44° west of north

__

In the second attachment, North is to the right, and West is down. This is essentially a reflection across the line y=x of the usual map directions and angles. Reflection doesn't change lengths or angles, so the computations are valid regardless of how you assign map directions to x-y coordinates.

Answer:

so Lester receive money is $13762.5  

Step-by-step explanation:

Given data in question

principal = $15000

discount = 8* 1/4 % i.e. = 8.25% = 0.0825

to find out

Lester receive money ?

solution

we know ordinary interest formula i.e.

receive money = principal ( 1 - discount )  ...........1

we all value principal and discount in equation 1 and we get receive money

receive money = principal ( 1 - discount )

receive money = $15000 ( 1 - 0.0825)

receive money = $ 13762.5  

so Lester receive money is $13762.5  

Lester received a total of $14,417.50 as proceeds when he discounted the note at Brome Bank.

Lester accepted a $15,000, 7 3/4%, 180-day note from Ryan O'Flynn on July 18. On October 5, Lester discounted the note at Brome Bank at 8 1/4%.

To calculate the proceeds Lester received, we need to find the simple interest earned on the note for 180 days. First, find the interest earned:

Principal x Rate x Time = Interest

$15,000 x 7.75% x (180/360) = $582.50

Next, subtract the interest earned from the face value of the note to find the proceeds Lester received:

$15,000 - $582.50 = $14,417.50

Therefore, Lester received $14,417.50.

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Answer:

it will be x=(AC-B+D)/A

Step-by-step explanation:

AX+B=AC+D

AX+B-B=AC+D-B

AX/A=(AC+D-B)/A

X=(AC+D-B)/A

Answer:

11.

Step-by-step explanation:

N = Nadia.

P = Pete.

S = postcards that Nadia gives to Pete.

N = 20 + P

P + S = 2+N-S

To calculate S, we replaces N of the first equation in the second equation:

P + S = 2 + 20 + P-S

2S = 2 + 20 + P - P

2S = 22

S = 22/2 = 11.

Answer:

monthly payment=$322.52

Step-by-step explanation:

cost of house=$290,000

down payment= 20%

interest  monthly = 4.2%

interest rate compounded monthly so (i)=4.2/12=0.35%

months= [tex]30\times 12[/tex]=360 months

down payment = [tex]0.2\times 290000[/tex]

                         =$58000

amount to be paid(P)=$232,000

[tex]P=R\frac{(1+r)^n-1}{i}\\232000=R\frac{(1+0.0035)^{360}-1}{0.0035}\\232000=R\times 719.33[/tex]

R=$322.52

sara's monthly payment will be $322.52

The solution to the separable initial value problem is [tex]\( y = \tan(x \ln(x) - x + 1 + \arctan(3)) \).[/tex]

A differential equation is a mathematical equation that relates a function to its derivatives. It describes how a function's rate of change is related to its current value and possibly other variables. Differential equations are used to model various physical, biological, and social phenomena in fields such as physics, engineering, biology, and economics.

To solve the differential equation [tex]\( y' = \ln(x)(1 + y^2) \)[/tex] with the initial condition [tex]\( y(1) = 3 \)[/tex], we separate variables and integrate both sides.

After integration, we get [tex]\( \tan(y) = x\ln(x) - x + C \)[/tex], where [tex]\( C \)[/tex] is the constant of integration. Using the initial condition, we find [tex]\( C = 1 + \arctan(3) \)[/tex].

Substituting this value back into the equation, we obtain the solution[tex]\( y = \tan(x \ln(x) - x + 1 + \arctan(3)) \).[/tex]This function satisfies the given differential equation and initial condition.

Step-by-step explanation:

i think the answer is 42 to be exacr

Answer:

 The candle has a height of 21.4 cm after burning for 22 hours.

Step-by-step explanation:

let x=hours, m=rate of change,  and  y= candle height

First you have to find the slope or, rate of change using the slope formula.  y2-y1 divided by x2-x1   .        

Here is our points    (9,     17.5)   and   (24,    22)

                                    x1       y1                 x2     y2

Now we put these into the equation and solve

[tex]\frac{22-17.5}{24-9}[/tex]   =[tex]\frac{3}{10}[/tex]

Now that we have the slope of 3/10 we can use this to find the y-intercept using the point-slope equation.

[tex]y-y_{1} =m(x-x_{1} )[/tex]                 y-17.5= .3(x-9) Solve

y-17.5=.3x-2.7                                        y  -14.8=      .3x

 +2.7         +2.7                                         +14.8               +14.8

y=.3x+14.8                     the y-intercept is 14.8

Now we use this equation to  plug in the 22 hours.

y=.3(22) +14.8

y=6.6+14.8

y= 21.4    The candle has a height of 21.4 cm after burning for 22 hours.

Answer: No, A and B are not independent events.

Step-by-step explanation:

Since we have given that

Number of outcomes that a die comes up with = 6

A be the event that the red die comes up even.

A={2,4,6}

B be the event that the sum on the two dice is 8.

B={(2,4),(4,2),(5,3),(3,5),(44)}

P(A) = [tex]\dfrac{3}{6}=\dfrac{1}{2}[/tex]

P(B) = [tex]\dfrac{5}{36}[/tex]

P(A∩B) = [tex]\dfrac{3}{36}[/tex]

But,

P(A).P(B) ≠ P(A∩B)

[tex]\dfrac{1}{2}\times \dfrac{5}{36}\neq \dfrac{3}{36}\\\\\dfrac{5}{72}\neq\dfrac{1}{12}[/tex]

Hence, A and B are dependent events.

Answer: There are 32 pints of first type and 128 pints of second type in mixture.

Step-by-step explanation:

Since we have given that

Percentage of pure fruit juice in first type = 60%

Percentage of pure fruit juice in second type = 85%

Percentage of pure fruit juice in mixture = 80%

We will use "Mixture and Allegation" to find the ratio of first and second type in mixture:

          First type          Second type

               60%                    85%

                              80%

------------------------------------------------------------------------

     85-80               :              80-60

       5%                  :                 20%

        1                     :                   4

so, the ratio of first and second type is 1:4.

Total number of pints of mixture = 160

Number of pints of mixture of  first type in mixture  is given by

[tex]\dfrac{1}{5}\times 160\\\\=32\ pints[/tex]

Number of pints of mixture of second type in mixture is given by

[tex]\dfrac{4}{5}\times 160\\\\=4\times 32\\\\=128\ pints[/tex]

Hence, there are 32 pints of first type and 128 pints of second type in mixture.

Answer:

The cost of sweatshirt is 12$

Step-by-step explanation:

so we are going to make 3 equations and solve it using the substation method

First- We know the price of the shirt is two times more so w = 2h

Second we know that the the tee shirt is 4 dollars less then the pair of shoes so t = h − 4

Third we take the combined of Brads purchases 3w + 5t + 2h =136

w = 2h

t = h − 4

3w + 2h + 5t = 136

So to solve we are going to to the sub method

3(2h) + 2h + 5(h-4) = 136 - just re written, now we get rid of the ( )

6h + 2h + 5h -20 = 136 - Now we need to move the -20 and add it too 136

6h + 2h + 5h = 156 - Now sum up the H's

13h = 156 - Now divide 13 by 156

h= 12

so the Cost of a sweatshirt is 12 dollars

The cost of a sweatshirt is $24.

The cost of a t shirt is $8

The cost of shorts is $12

Let w represent the price of one sweatshirt

Let t represent the price of one Tshirt

Let h represent the price of one pair of shorts

The price of a sweatshirt at a local shop is twice the price of a pair of shorts.

[tex]w=2h[/tex]    ...(1)

The price of a T-shirt at the shop is $4 less than the price of a pair of shorts.

[tex]t=h-4[/tex]    ....(2)

Brad purchased 3 sweatshirts, 2 pairs of shorts, and 5 T-shirts for a total cost of $136.

[tex]3w+2h+5t=136[/tex]    .....(3)

Substituting the values of w and t in (3)

[tex]3(2h)+2h+5(h-4)=136[/tex]

=> [tex]6h+2h+5h-20=136[/tex]

=> [tex]13h=136+20[/tex]

=> [tex]13h=156[/tex]

h = 12

t = h-4

[tex]t=12-4=8[/tex]

t = 8

w = 2h

[tex]w=2\times12=24[/tex]

w = 24

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So, the cost of a sweatshirt is $24.

The cost of a t shirt is $8

The cost of shorts is $12