Enrollment in a school has grown exponentially since the school opened. A graph depicting this growth is shown. Determine the percentage rate of growth.

Enrollment In A School Has Grown Exponentially Since The School Opened. A Graph Depicting This Growth

Answers

Answer 1
Final answer:

To find the percentage rate of growth, calculate the percentage change in enrollment from one year to the next using the graph. Perform these calculations for each pair of consecutive years to determine the overall percentage rate of growth.

Explanation:

To determine the percentage rate of growth, we need to analyze the graph showing the enrollment growth of the school. Exponential growth is represented by a curve that increases more and more steeply over time. To find the rate of growth, we can calculate the percentage change in enrollment from one year to the next.

For example, if the enrollment was 100 in Year 1 and 200 in Year 2, the percentage change would be (200-100)/100 * 100 = 100%. This means the enrollment doubled from Year 1 to Year 2.

By performing similar calculations for each pair of consecutive years, we can find the percentage rate of growth over the entire period represented by the graph.

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Answer 2
Final answer:

The percentage rate of growth for the school's enrollment is approximately 24% per year.

Explaination:

To determine the percentage rate of growth, we need to find the common ratio and the common difference in the exponential function that represents the school's enrollment. From the given graph, we can see that the enrollment doubles approximately every three years. This means that the common ratio is 2. The initial enrollment is 500, which is represented by the value "a" in the exponential function. The final enrollment, which is approximately 4000, is represented by "an". Using these values, we can write the exponential function as follows:

[tex]an = a * 2^(n-1)[/tex]

Substituting the initial enrollment and final enrollment in this equation, we get:

[tex]4000 = 500 * 2^(n-1)[/tex]

Dividing both sides by 500 and simplifying, we get:

[tex]8 = 2^(n-1)[/tex]

Taking the logarithm of both sides with base 2, we get:

(n-1) = log2(8)

(n-1) = 3

Adding 1 to both sides, we get:

n = 4

This means that it takes approximately four years for the school's enrollment to double. To find the percentage rate of growth per year, we need to find the common difference in the exponential function. The common difference is calculated as follows:

Common difference =[tex]ln(y2 / y1) / (x2 - x1)[/tex]

Here, x1 and x2 are two consecutive years, and y1 and y2 are their corresponding enrollments. Using this formula, we can calculate the common difference as follows:

Common difference = ln(4000 / 3200) / (7 - 4) = 0.263975 (approximately 24%) per year. This means that every year, the school's enrollment grows by approximately 24%.


Related Questions

You estimate that you have completed 1/4 of the work your boss expects this week. What precent if your work is complete?

Answers

1/4x%%%%%%%%%%%%%%%%%%%%%%%%%

Answer:

You have completed 25% of your work.

Step-by-step explanation:

Consider the provided information.

You estimate that you have completed 1/4 of the work.

To find the percentage of work complete simplify the fraction and multiply it with 100.

[tex]\frac{1}{4}=0.25[/tex]

Now multiply it by 100.

[tex]0.25\times 100=25\%[/tex]

Hence, you have completed 25% of your work.

Please Help! I don't know where to start with this, please show all work!

What is the vertex form of the equation?

y = -x^2 + 12x - 4

Answers

Hey!

-------------------------------------

Formula's:

x_v = -b/2a

y_v = ax² + bx + c

-------------------------------------

Parabola Params:

a = -1

b = 12

c = 4

-------------------------------------

Solve for [tex]x_{v}[/tex]

[tex]x_{v} = \frac{-b}{2a}[/tex]

[tex]x_{v} = \frac{-12}{2(-1)}[/tex]

[tex]x_{v} = -6[/tex]

-------------------------------------

Solve for [tex]y_{v}[/tex]

Use -6 for [tex]x_{v}[/tex]

[tex]y_{v} = -6^2 + 12(6) - 4\\[/tex]

[tex]y_{v} = -36 + 72 - 4[/tex]

[tex]y_{v} = 32[/tex]

-------------------------------------

Answer:

(6, 32)

-------------------------------------

Hope This Helped! Good Luck!

Billy estimates that they will sell approximately 250 burgers thisweekend how much burger meat and fries (in pounds) should he order to be prepared for this weekend

Answers

Answer:

300 Burgers

Step-by-step explanation:

Since the question gives us an approximation of 250 burgers, we can round the number to 300. This is only because they had a estimation of 250 and would like to be prepared for the weekend. Being prepared would consist of ordering more than expected to make sure the burgers do not run out.

-7y-4x=1
7y-2x=53
solve for system of equations ​

Answers

Answer:

x = -9

y = 35/7

Step-by-step explanation:

Given equations :-

-7y - 4x = 1 ....... ( i )

7y - 2x = 53 ........ ( ii )

From ( i )

-7y = 1 + 4x

[tex]y = \frac{ - (1 + 4x)}{7} [/tex]

..........( iii )

From ( ii )

7y - 2x = 53

7y = 53 + 2x

[tex]y = \frac{53 + 2x}{7} [/tex]

.......( iv )

Equating both ( iii ) & ( iv )

y = y

[tex] \frac{ - (1 + 4x)}{7} = \frac{53 + 2x}{7} [/tex]

-(1 + 4x ) = 53 + 2x

-1 -4x = 53 + 2x

-1 - 53 = 2x + 4x

-54 = 6x

-54/6 = x

-9 = x

Also,

[tex]y = \frac{ - (1 + 4x)}{7 } \\ \\ y = - \frac{(1 + 4( - 9))}{7} [/tex]

[tex]y = - \frac{ (1 - 36)}{7} \\ \\ y = - \frac{( - 35)}{7} \\ \\ y = \frac{35}{7} [/tex]

4. Corrupt professor Z has a class of 50 students. He needs to give exactly 10 A's. However five students already have a special deal (they are professor Z's nephews and nieces) and will get A's for sure. How many ways can the 10 A's be distributed?

Answers

Answer:

Step-by-step explanation:

Given that the professor Z has a class of 50 students is corrupt.   However five students already have a special deal (they are professor Z's nephews and nieces) and will get A's for sure.

Thus out of 10 students 5A's are reserved

Remaining 5 can be distributed in

I 5 to any one of the 45, II to any one of the 44....

i.e. 45P5 ways

no of ways = 45P5 == 146611080

| A retiree invests $8,000 in a savings plan that pays
4% per year. What will the account balance be at
the end of the first year?

Answers

Answer:

8320

Step-by-step explanation:

(100%+4%)8000=8320

Final answer:

The balance at the end of the first year of the investment will be $8320, which includes the initial investment of $8000 and the interest earned, calculated as 4% of the initial investment.

Explanation:

This is a basic interest problem in mathematics. To calculate the balance at the end of the first year, we need to add the initial investment to the amount earned through interest. The interest earned is the product of the initial investment and the interest rate.

In this case, the initial investment is $8000 and the interest rate is 4% per year or 0.04 in decimal form. So, the interest earned would be the product of $8000 and 0.04, which equals $320.

Therefore, the balance at the end of the first year would be the initial investment plus the interest earned, which is $8000 + $320 = $8320.

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What is the geometric relationship between u, minusv, and uminusv?
A. The vectors u, minusv, and uminusv form a right triangle.
B. The vectors u, minusv, and uminusv form a parallelogram whose other vertex is at 0.
C. The vectors u, minusv, and uminusv form an equilateral triangle.
D. The vectors u, minusv, and uminusv form a parallelogram whose other vertex is at uplusv.

Answers

Answer:

C. The vectors u, minusv, and uminusv form a parallelogram whose other vertex is at 0.

Step-by-step explanation:

We draw the vector u=A at the origin of a Cartesian plane. then at the same point, we draw -v = -B. To find the vector that represents u-v = A-B, straight lines are drawn parallel to each vector, forming a parallelogram. The resulting vector will be the diagonal of the parallelogram that begins at the origin of the plane.

A bag contains 99 red marbles and 99 blue marbles. Taking two marbles out of the bag, you:
• put a red marble in the bag if the two marbles you drew are the same color (both red or both
blue), and
• put a blue marble in the bag if the two marbles you drew are different colors.
Repeat this step (reducing the number of marbles in the bag by one each time) until only one
marble is left in the bag. What is the color of that marble?

Answers

The final marble left in the bag will be red.

Let, analyze the process step by step:

Initially, the bag contains 99 red marbles and 99 blue marbles.

When you take two marbles out of the bag, there are two possibilities: either you get two red marbles or two blue marbles, or you get one red and one blue marble.

a. If you get two marbles of the same color (both red or both blue), you put a red marble in the bag.

b. If you get one red and one blue marble, you put a blue marble in the bag.

After putting a marble back in the bag, you have one less marble in the bag.

You repeat this process, reducing the number of marbles in the bag by one each time, until only one marble is left in the bag.

Now, let's think about the outcomes at each step:

If the bag contains an odd number of marbles (99 red + 99 blue = 198), the final marble will be red because at each step, you are adding a red marble back to the bag.

If the bag contains an even number of marbles (e.g., 100 red + 100 blue = 200), the final marble will be blue because at each step, you are adding a blue marble back to the bag.

In this case, the bag contains 99 red marbles and 99 blue marbles, which is an odd number (198 marbles).

Therefore, the final marble left in the bag will be red.

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Assume that a procedure yields a binomial distribution with a trial repeated n = 20 times. Use either the binomial probability formula (or technology) to find the probability of k = 14 successes given the probability p = 0.72 of success on a single trial.

Answers

Answer:

the probability is 0.1879

Step-by-step explanation:

If a procedure yields a binomial distribution, the probability of having k successes is given by:

[tex]P(k)=nCk*p^{k} *(1-p)^{n-k}[/tex]

Where nCk is calculated as:

[tex]nCk=\frac{n!}{k!(n-k)!}[/tex]

Additionally, n is the number of trials and p is the probability of success in every trial.

Replacing, k by 14, n by 20 and p by 0.72 we get:

[tex]20C14=\frac{20!}{14!(20-14)!}=38,760[/tex]

[tex]P(k)=20C14*0.72^{14} *(1-0.72)^{20-14}[/tex]

[tex]P(k)=38,760*0.72^{14} *(1-0.72)^{20-14}\\P(k)=0.1879[/tex]

So, the probability is 0.1879

Final answer:

To find the probability of 14 successes given a binomial distribution with a trial repeated 20 times and a probability of success of 0.72 on a single trial, use the binomial probability formula.

Explanation:

To find the probability of 14 successes given a binomial distribution with a trial repeated 20 times and a probability of success of 0.72 on a single trial, we can use the binomial probability formula. The formula is:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

Plugging in the values, we get:

P(X = 14) = C(20, 14) * 0.72^14 * (1 - 0.72)^(20 - 14)

Calculating this expression will give you the probability of 14 successes out of 20 trials.

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What value of x makes the equation true?
1/2 (4x−5)+5/2=10 (Btw, the numbers 1/2 and 5/2 are fractions)

A. 5

B. 8

C. 12

D. 20

Answers

Answer:

x= 5 fam trust

Step-by-step explanation:

plug it in brainliest plzzzzzzzzzzzzzzzzz

​ A sample of n = 9 college students is used to evaluate the effectiveness of a new Study Skills Workshop. Each student’s grade point average (GPA) is recorded for the semester before the workshop and for the semester after the workshop. The average GPA improved by MD = 0.60 points with s2 = 0.09. The researcher would like to use the sample to estimate how much effect the workshop would have for the entire college population. Which of the following is the 80% confidence interval for these data?
A) μD = 0.60 ± 0.09( 1.860)
B) μD = 0.60 ± 0.10(1.397)
C) μD = 0.60 ± 0.01(1.397)
D) μD = 0.60 ± 0.10( 1.860)

Answers

Answer:

B) μD = 0.60 ± 0.10(1.397)

Step-by-step explanation:

The confidence interval is given by:

[tex]MD±t_{\alpha/2, n-1} \frac{s}{\sqrt{n} }[/tex]

Where

MD=60

n=9

df=n-1=8

[tex]t_{\alpha/2, n-1}=1.397[/tex]

[tex]s=\sqrt{0.09} =0.3[/tex]

Then the confidence interval is

μD=0.60±1.397*(0.3/√9)

μD=0.60±0.10*(1.397)

Write the equation of the line perpindicular to the graph of 2x-5y=0 that passes through the point (-2,3)

Answers

Answer:

5x-2y=-4

Step-by-step explanation:

2x-5y=0

eq. of line perpendicular to ax+by=c is bx-ay=d,d is calculated by the given condition.

line perpendicular to 2x-5y=0 is 5x+2y=c

if it passes through (-2,3) ,then

5*-2+2*3=c

c=-10+6=-4

reqd. eq. is 5x+2y=-4

What is the least angle measure by which this figure can be rotated so that it maps onto itself?


45°

90°

180°

360°





Answers

Answer:

The correct answer is 90

Step-by-step explanation:

Choose all of the angles that are coterminal with -150°.

-510°
-210°
150°
210°
570°

Answers

Answer:

210, 150

Step-by-step explanation:

Answer:

-510, 210 and 570.

Step-by-step explanation:

I'm on the same assignment right now! If you draw them you will see that those are the answers.


What are the coordinates of the hole in the graph of the function?

Answers

Answer:

The answer to your question is: (5/2, -6)

Step-by-step explanation:

Given    f(x) = (6x - 36) / (2x² - 17x + 30)

Factorize both, numerator and denominator

Numerator = 6(x - 6)

Denominator =    2x² - 12x - 5x + 30

                      =   2x(x - 6) - 5(x - 6)

                      = (x - 6) (2x - 5)

Now     f(x) = 6(x - 6) / (x - 6) (2x - 5)     Cancel (x - 6)

            f(x) = 6 / 2x - 5

Find the hole           2x - 5 = 0

                                2x = 5

                                x = 5/2

In 5/2 there is a hole, in y is approximately -6

Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle, or a parallelogram. Then find the perimeter of the quadrilateral. A(6, –4), B(11, –4), C(11, 6), D(6, 6)

Answers

Answer:

The answer to your question is: it's a rectangle

perimeter = 30 u

Step-by-step explanation:

d = √((x2.x1)² + (y2-y1)²)

Now, calculate the distances AB, BC, CD, AD

dAB = √((11-6)² + (-4+4)² = √5² = 5

dBC = √((11-11)² + (-4-6)² =√10 = 10

dCD = √((6-11)² + (6-6)² = √5² = 5

dAD = √((6-6)² + (6+4)² = √10² = 10

From the results we conclude that is a rectangle because two sides have the same length and the other two also measure the same. We can draw it to confirm this.

Perimeter = dAB + dBC + dCD + dAD

                 = 5 + 10+ 5 + 10 = 30 units

Final answer:

To determine the shape of the quadrilateral, calculate the distances between the vertices and check for equal side lengths and 90-degree angles. The given quadrilateral is a parallelogram since the opposite sides are parallel and equal. The perimeter of the quadrilateral is 30 units.

Explanation:

To determine whether the given quadrilateral is a square, a rectangle, or a parallelogram, we can use the properties of each shape. A square is a quadrilateral with all sides equal in length and all angles equal to 90 degrees. A rectangle is a quadrilateral with opposite sides equal in length and all angles equal to 90 degrees. A parallelogram is a quadrilateral with opposite sides parallel and equal in length. To find the perimeter of the quadrilateral, we can calculate the sum of the lengths of all four sides.

Calculating the distances between each pair of given points:

Distance between A and B: √[(11-6)² + (-4-(-4))²] = √(5² + 0) = √25 = 5Distance between B and C: √[(11-11)² + (6-(-4))²] = √(0 + 100) = 10Distance between C and D: √[(6-11)² + (6-6)²] = √((-5)² + 0) = √25 = 5Distance between D and A: √[(6-6)² + (6-(-4))²] = √(0 + 100) = 10

The distances between the vertices are: AB = 5, BC = 10, CD = 5, and DA = 10. Therefore, the perimeter of the quadrilateral is 5 + 10 + 5 + 10 = 30 units.

Use the discriminant to describe the roots of each equation. Then select the best description.

x^2 - 4x + 4 = 0


double root
real and rational root
real and irrational root
imaginary root

Answers

Answer:

Hello My Friend! The correct answer its double root.

Step-by-step explanation:

In this equation, if we applie the a, b and c coefficients (a=1, b=4, c=4) ind the Bhaskara, the final result will be 4 for both cases. x'=4 and x''=4. It happens because the number of theta is equal to 0. So, both roots will be the same number.

Use differentiation rules to find the values of a and b that make the function f(x) = ( x 2 if x ≤ 2, ax3 + bx if x > 2 differentiable at x = 2.

Answers

Final answer:

To make the function differentiable at x = 2, we must ensure continuity by matching function values and differentiability by equating derivatives from both sides at x = 2. Solving the system of equations obtained from these conditions will give the values of a and b.

Explanation:

To find the values of a and b that make the function f(x) = { x² if x ≤ 2, ax³ + bx if x > 2 } differentiable at x = 2, we need to ensure both continuity and differentiability of f(x) at this point. First, continuity at x = 2 requires that the limits from the left and the right are the same, meaning f(2) = 2² = 4 should equal a(2)³ + b(2). Second, for differentiability, the derivatives from the left and right at x = 2 must also be equal. The derivative of is 2x, so f'(2) = 4. Differentiating ax³ + bx gives 3ax² + b, so f'(2) = 12a + b must also equal 4. Solving these equations:

4 = 8a + 2b4 = 12a + b

gives us a system of equations that when solved, will provide the exact values of a and b required.

At the end of year X, automobile installment credit accounted for 36 percent of all outstanding consumer installment credit. At that time automobile finance companies extended $57 billion of credit, or \small \frac{1}{3} of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time?A. 62B. 171C. 475D. 513E. 684

Answers

Answer:

option (c) 475

Step-by-step explanation:

let the automobile installment credit be 'C'

Given:.

Automobile installment credit accounted for 36 percent of all outstanding consumer installment credit

Now,

57 billion is [tex]\frac{1}{3}[/tex] of automobile installment credit

or

57 billion = [tex]\frac{1}{3}[/tex] × C

or

C = 57 × 3

or

C = 171 billion

now,

installment credit accounted = 36% of all outstanding consumer installment credit

or

171 billion = 0.36 × all outstanding consumer installment credit

or

All outstanding consumer installment credit = $475 billion

Hence, the correct answer is option (c) 475

A blueprint shows a house with two fences. Fence A is 1 4/5 inches long on the blueprint and is to be 1 1/2 feet long. How long is Fence B on the blueprint?

Answers

Final answer:

The problem is about finding a length on a blueprint using scale factor. A ratio is established between blueprint measurements and real-life measurements. However, information about Fence B's actual size is needed to calculate its blueprint length.

Explanation:

The subject of this question is mathematics, more specifically proportionality and scale factor. To solve this problem, you need to establish the ratio or scale represented by the blueprint to the actual size. In the given problem, 1 4/5 inches on the blueprint represents 1 1/2 feet in real life. First, convert the measures to improper fractions to easily manage the computations. Hence, 1 4/5 becomes 9/5 inches and 1 1/2 feet becomes 3/2 feet. The scale becomes 9/5 inches:3/2 feet on blueprint:real life. Now, we need additional information about the actual size of Fence B to calculate its length on the blueprint.

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Britney is going to the candy store to buy 20 pieces of candy. She is going to buy chocolate candy and caramel candy. Each piece of chocolate candy costs 50 cents, and each piece of caramel candy costs 10 cents. You know that Britney spent $6.80 and bought 20 pieces of candy. She bought ______ pieces of chocolate.

Answers

to start off, you want to make the equations. first, we will make x = chocolate candy and y=caramel candy since thats the order they come in the problem. we know she bought 20 pieces of candy, so we now know our first equation, x+y=20. next, if each chocolate candy costs $.50, that now makes x in our second equation .5x. the y will then be .1y. they then total up to equal $6.80, so our second equation is .5x+.1y=6.8. to then find x, subtract the y from the first equation to get x=20-y. then in the second equation, replace x with y and solve. you then get y=8, so we know britney has 8 caramels. now in the first equation, replace the y to get x+8=20. and now x=12

Keira and Javier are grouping equations based on the number of operations needed to solve them in order to solve them in order to solve the equation -5(2+x)=53

Answers

-10-5x=-265
+10 +10
-——————
-5x =-255
X = 51
Final answer:

To solve the equation -5(2+x)=53, we need to use the order of operations and follow the steps mentioned in the detailed answer. The solution to the equation is x=-12.6.

Explanation:

In order to solve the equation -5(2+x)=53, we need to use the order of operations. Let's break it down step by step:

First, we need to distribute the -5 to both 2 and x. This gives us -10-5x=53.Next, we combine like terms by adding 10 to both sides of the equation, which gives us -5x=63.Finally, we divide both sides of the equation by -5 to isolate the variable x. This gives us x=-12.6.

So, the solution to the equation -5(2+x)=53 is x=-12.6.

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The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 circuits is tested, revealing 14 defectives. Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool. Round the answers to 4 decimal places.

Answers

Answer: [tex](0.0228\ ,0.0706)[/tex]

Step-by-step explanation:

Given : Sample size : n= 300

The sample proportion of defectives : [tex]\hat{p}=\dfrac{14}{300}=0.0467[/tex]

Significance level for 95% confidence level =[tex]\alpha=1-0.95=0.05[/tex]

Critical z-value:[tex]z_{\alpha/2}=\pm1.96[/tex]

Confidence interval for population proportion :

[tex]\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

[tex]= 0.0467\pm (1.96)\sqrt{\dfrac{0.0467(1-0.0467)}{300}}[/tex]

[tex]\approx\ 0.0467\pm 0.0239\\\\=(0.0467-0.0239\ , \ 0.0467-0.0239)\\\\=(0.0228\ ,0.0706)[/tex]

Hence, a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool= [tex](0.0228\ ,0.0706)[/tex]

An irrational number is a real number and an integer.

True
False

Answers

Answer:

A real number is a number that is somewhere on a number line, so any number on a number line that isn't a rational number is irrational. The square root of 2 is an irrational number because it can't be written as a ratio of two integers

hope it helps!!

Step-by-step explanation:

Three parking attendants are required to park cars for each blue lot , while two can handle each red lot. Of the 15 lots that will be used for tonight, 60% are blue and 40% are red. How many parking attendants are required for tonight's event

Answers

Answer:

[tex]39\ parking\ attendants[/tex]

Step-by-step explanation:

Let

x -----> the number of blue lots

y-----> the number of red lots

we know that

[tex]x+y=15[/tex] ------> equation A

we have that

[tex]x=0.60(15)=9\ blue\ lots[/tex]

[tex]y=0.40(15)=6\ red\ lots[/tex]

The total parking attendants required for tonight's event is equal to the product of the number of blue lots by three plus the product of the number of red lots by two

so

[tex]9(3)+6(2)=39\ parking\ attendants[/tex]

Answer:

39

Step-by-step explanation:

During the​ year, FastDry Corporation has $ 340,000 in​ revenues, $ 155,000 in​ expenses, and $ 12,000 in dividend declarations and payments. Net income for the year​ was:

Answers

Answer:

$185,000

Step-by-step explanation:

We have been been given that during the​ year, Fast Dry Corporation has $ 340,000 in​ revenues, $ 155,000 in​ expenses, and $ 12,000 in dividend declarations and payments.

We will use following formula to solve our given problem.

[tex]\text{Net income}=\text{Revenues}-\text{Expenses}[/tex]

[tex]\text{Net income}=\$340,000-\$155,000[/tex]

[tex]\text{Net income}=\$185,000[/tex]

Therefore, the net income for the year was $185,000.

Marc is decorating 60 cupcakes for a school fund-raiser. He starts working at 1:00 P.M. In the afternoon, first setting up his supplies and then starting to decorate. At 1:05 P.M. He has 5 cupcakes decorated. At 1:08 P.M. He has 10 cupcakes decorated. If he decorates cupcakes at a constant rate, at what time that afternoon will he finish decorating the 60 cupcakes?

Answers

Answer:

1.38 pm.

Step-by-step explanation:

After 1.05 PM the rate at which he decorates the cakes is 10 - 5 = 5 cakes per 3 minutes = 5/3 cakes per minute. At 1.08 pm he has made 10 cupcakes.

At 1.08 he has to decorate another 50 cakes so the time he will take to do these is  50 / 5/3  = 50 * 3/5 =   30 minutes.

So the time when he finishes 60 cupcakes is  1.08 + 30

= 1.38 pm.

The 60 cupcakes will be decorated at 1.38 pm.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

After 1.05 PM the rate at which he decorates the cakes is 10 - 5 = 5 cakes per 3 minutes = 5/3 cakes per minute. At 1.08 pm he made 10 cupcakes.

At 1.08 he has to decorate another 50 cakes so the time he will take to do these is  50 / 5/3  = 50 * 3/5 =   30 minutes.

The time when he finishes 60 cupcakes is:-

1.08 + 30 = 1.38 pm.

Therefore, 60 cupcakes will be decorated at 1.38 pm.

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PLEASE HELP What is the equation in standard form of a parabola with a focus of (-3,2) and a directrix of y=4.

Answers

Graphing y = 4 and the focus, we clearly see that the equation we need has the form (x - h)^2 = 4a(y - k).

We need to find a, h and k.

The focus is half way between the vertex and directrix.

You know that y = 4 is 2 units away from the focus and the focus is 2 units down from the focus. So, our vertex is (-3, 0).

From the vertex to the directrix, there are 4 units. Half that distance is the value of a. So, a = 2.

We have all that is needed to form our equation.

(x - (-3))^2 = 4(2)(y - 0)

(x + 3)^2 = 8y

Done.

Answer:

i think this will help (x - (-3))^2 = 4(2)(y - 0)

(x + 3)^2 = 8y

Step-by-step explanation:

PLEASE HELP!!!!

WILL GIVE BRAINLY

Which statements are true?

Select each correct answer.




9g3+12=3(3g3+4)

35g5−25g2=5g2(7g3−5)

24g4+18g2=6g2(4g2+3g)

4g2−g=g2(4−g)

Answers

The third one is the correct answer

What is the degree of the polynomial 5a6bc2+8d5+7e6f2−10g4h7 ? Enter your answer in the box.+

Answers

Answer:

11

Step-by-step explanation:

The degree of a polynomial is he highest of the degrees of its monomials (individual terms) with non-zero coefficients.

You are given the polynomial

[tex]5a^6bc^2+8d^5+7e^6f^2-10g^4h^7[/tex]

It consists of 4 terms:

[tex]5a^6bc^2[/tex][tex]8d^5[/tex][tex]7e^6f^2[/tex][tex]-10g^4h^7[/tex]

The degrees are:

of the first term is [tex]6+1+2=9[/tex]of the second term is [tex]5[/tex]of the third term is [tex]6+2=8[/tex]of the fourth term is [tex]4+7=11[/tex]

The greatest degree is 11.

Answer:

11

Step-by-step explanation:

I did the quiz

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