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A fan is connected to a battery in a series circuit. What kind of energy transfer occurs if the circuit is closed?
A
Light energy changes to chemical energy
Thermal energy changes to mechanical energy
Chemical energy changes to mechanical energy!
D)
Mechanical energy changes to chemical energy
Help!!!

Answer:

pH range =  2.74-4.74

Explanation:

The pH range of a buffer falls in between one unit on either side of pKa.

The given weak acid is HF and its Ka = 1.8X10⁻⁴

pKa = -log(Ka)

pKa = -log(1.8X10⁻⁴)

pKa = 3.74

The pH range is 3.74-1 = 2.74 to 3.74+1 =4.74

pH range =  2.74-4.74

Answer:

When we decrease temprature and increase pressure on a gas. It liquifies.

when we increase temprature and decrease pressure on liquid gas. It becomes gas again

HOPE IT HELPS U ....

Answer:

B. when volume and the number of particles are constant

Explanation:

According to Gay Lussac law,

For a given amount of gas at constant volume (V) and the number of particles are constant (n)

Pressure is directly proportional to the temperature of the gas.

It is given by the expression  

[tex]P \propto T[/tex] ( at constant V and n)

[tex]\frac {P}{T} =k[/tex] (k is a constant )

When there is a change in the pressure or temperature

The expression is [tex]\frac {P_1}{T_1} =\frac {P_2}{T_2}[/tex]

Where                                

[tex]P_1[/tex] and [tex]P_2[/tex] are initial pressure and final pressure respectively

[tex]T_1[/tex] and [tex]T_2[/tex] are initial and final temperatures respectivley

Please Note:

Directly proportional means when one increases the other one too will increase that is when pressure increases temperature too will increases if volume and number of particles are constant.

Answer:

A base.

Explanation:

Basic solutions give OH- ions.

From the provided options, Na (sodium) is the strong reducing agent because it more readily donates its valence electron to reduce other substances.

The element that would be a strong reducing agent from the list provided is Na (sodium). A reducing agent is a substance that donates electrons to another substance in a chemical reaction, thereby reducing the oxidation state of that substance.

The four options given are two halogens, F2 and Cl2, which are strong oxidizing agents rather than reducing agents, and two metals, Ba (barium) and Na.

Between the metals, sodium is more active and thus a stronger reducing agent. This is because sodium is more willing to lose its single valence electron to form the Na+ ion, facilitating the reduction of other substances.

Answer:

your answer may be found on a website called "Thought.co"

once you get there just search "Examples of Chemical Reactions in Everyday Life" and it will give you some ideas  :)

Answer:

Form a chemical bond between two different substances.

Liquid nitrogen boils at -196°c, the temperature on kelvin scale is 77 kelvin.

Liquid nitrogen (LN) is an inert cryogenic fluid with a temperature of − 196 °C [− 320 °F]. LN is injected directly into the batch water storage tank, aggregate, or mixer via lances to lower the temperature of the concrete as much as practical without freezing.

Solid nitrogen melts to form liquid nitrogen at 63.17 Kelvin, which boils at 77.36 Kelvin. Liquid nitrogen is used in many cryogenic cooling systems.

Liquid nitrogen has also been used as a method for cooling concrete for over twenty years. Liquid nitrogen (LN) is an inert cryogenic fluid with a temperature of − 196 °C [− 320 °F].

LN is injected directly into the batch water storage tank, aggregate, or mixer via lances to lower the temperature of the concrete as much as practical without freezing.

LN can be stored at the batch plant or on the project site and if used on the project site itself, then repeated cooling of the concrete and greater control of the concrete temperature is possible.

LN can be set up at a project or plant within a few days and can supplement other cooling methods to achieve a reduction in concrete temperature when necessary

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Answer:

=242.47 g of HF

Explanation:

From the equation One mole of SiO₂ (Silicon (IV) Oxide) react with 4 moles of HF (Hydrogen fluoride).

This is because the reaction ratio is 1:4

The number of moles in182 grams of SiO₂ is:

Number of moles= Mass/RMM

RMM of SiO₂ is 60.08 g/mol

No. of moles=182g/60.08g/mol

=3.0293 moles.

The reaction ratio of SiO₂ to HF is 1:4

Thus the number of moles of HF required to react with  3.0293 moles of SiO₂ is:

(4×3.0293)/1= 12.1172 moles

The mass of 12.1172 moles of HF is.

12.1172 moles× RMM of HF

=12.1172 moles×20.01 g/mol

=242.47 g of HF

Answer:

increasing the number of hydrogen ions.

Explanation:

pH = -log[H⁺].

Answer:

2 M.

Explanation:

I mole of NaCl reacts with 1 mole of HCl ( from the equation).

2 Liters of 5 molar contains 2 * 5 =  10 moles of NaCl so this will neutralise 10 moles of HCl.

So  the concentration of 5 liters of HCl must be 10/5 = 2M.

Answer:

2 M

Explanation:

If it takes 2.0 L of 5.0 M NaOH to neutralize 5.0 of an HCl solution, the concentration of the HCI is 2 M.

2 Liters of 5 molars = 2 x 5 =  10 moles

Answer:

Explanation:

1) Convert the mass of water into number of moles

        n = 255 g / 18.015 g/mol = 14.15 mol

2) Use the formula E = n × ΔH vap

This is, you have to multiply the molar ΔH vaporization by the number of moles to find the total energy to boil the given amount of water.

3) Round to the correct number of significant figures.

The mass of water is the measurement with the least number of significant figures (3), so you must report the answer with 3 significant figures,

Answer:

Yes. Since they have more than the required reactants.

Explanation:

Zinc reduces silver nitrate to silver metal according to the following equation.

2AgNO₃ + Zn → 2Ag + Zn(NO₃)₂

From the equation 2 moles of AgNO₃ produce 2 moles of silver.

If we consider the zinc to be used number of moles=mass/RAM

RAM of zinc =65.38

No. of moles=500/65.38

=7.6476moles

To produce 800 grams of silver they require:

800/107.868 moles=7.4165 moles of silver nitrate since the ratio of silver nitrate to silver produced is 1:1

The number of moles of silver nitrate available=1500/169.872

=8.83 moles.

As the amount of reactants available is more than the required the company will make it in producing the 800 grams of silver required.

Answer:

A.) Yes, there will be extra left over.

Explanation:

Got it correct on founders edtell.

Answer:

The correct answer would be CH2O,

Explanation:

Empirical Formula of any chemical compound gives us the information about the proportion of the element present in the compound but doesn't tell us about the actual numbers or arrangement of atoms.

C6H12O6 is the formula of Glucose. The empirical formula of Glucose is CH2O. This means that there is one atom of Carbon, 2 atoms of Hydrogen and 1 atom of oxygen is present. It tells us about the ratio of the atoms present in the molecules, like empirical formula of CH2O tells us that the ratio of carbon, hydrogen and oxygen is 1:2:1

e.18 mol S. In the given chemical reaction, 3 moles of sulfur is needed to produce one mole of aluminum sulfide. Therefore, to produce 6 moles of aluminum sulfide, 18 moles of sulfur are needed.

In the given chemical reaction, aluminum (Al) reacts with sulfur (S) to produce aluminum sulfide (Al2S3). The mole ratio of aluminum to sulfur to aluminum sulfide in this reaction is 2:3:1. This means that for every one mole of aluminum sulfide produced, three moles of sulfur are required.

So, calculating for six moles of aluminum sulfide, we multiply the required moles of sulfur for one mole of aluminum sulfide (which is three) by the six moles: 3 * 6 = 18. Hence, to produce 6 moles of aluminum sulfide, 18 moles of sulfur are needed.

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In the reaction 2 Al (s) + 3 S (s) → Al2S3 (s), three moles of sulfur are needed to produce one mole of aluminum sulfide. Therefore, to produce 6 moles of aluminum sulfide, you would need 18 moles of sulfur.

In the given reaction, 2 Al (s) + 3 S (s) → Al2S3 (s), we see that three moles of sulfur (3 S) are needed to produce one mole of aluminum sulfide (Al2S3). So, to find out how many moles of sulfur are needed to produce 6 moles of aluminum sulfide, we can perform a simple multiplication: 3 sulfur moles/mole of aluminum sulfide * 6 moles of aluminum sulfide = 18 moles of sulfur. Hence, the correct answer is (e) 18 mol S.

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People on one side of a room can smell air freshener sprayed on the opposite side due to the diffusion of molecules and the increase in entropy. Olfactory receptors in our noses detect these molecules, which allows us to perceive the scent as it spreads throughout the room.

The reason people on one side of a room can smell an air freshener sprayed on the opposite side is due to the diffusion of air freshener molecules from an area of higher concentration to an area of lower concentration. This happens because the entropy of the molecules increases, meaning they spread out to evenly fill the available space, which is why the scent diffuses throughout the room. Since molecules are always in motion, the ones released from the air freshener bottle will move around and mix with air molecules until they are distributed throughout the entire room.

Olfaction, or the sense of smell, allows us to detect these molecules. Humans have many olfactory receptors that can sense a wide range of odors. When molecules from the air freshener reach the receptors in our noses, they bind to them and trigger a signal to the brain, allowing us to perceive the scent. Therefore, although the air freshener is sprayed on one side of the room, the molecules eventually reach and are detected by people on the other side as well.

Answer:

=67.65 grams of sodium chloride.

Explanation:

In this explanation, we shall assume that the limiting reagent was NaOH only and the amount of HCl used was sufficient.

NaOH + HCl → NaCl + H₂O

In the equation, the ratio of NaOH used to the NaCl produced will be 1:1

The number of moles of NaOH in 46.3 g.

Number of moles = mass/RMM

=46.3g/40g/mol

=1.1575 moles.

Since the reaction ratio is 1:1, the Number of moles of NaCl produced is also 1.1575 moles.

The mass of 1.1575 moles of NaCl is: 1.1575 moles ×  58.443g/mol

=67.65 grams of sodium chloride.

46.3 grams of sodium hydroxide can theoretically produce 67.64 grams of sodium chloride, based on a 1:1 mole ratio and molar masses from the balanced chemical reaction NaOH + HCl → NaCl + H₂O.

To determine how many grams of sodium chloride can be produced from 46.3 grams of sodium hydroxide, we must first write a balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl), which typically produces sodium chloride (NaCl) and water (H₂O):

NaOH + HCl → NaCl + H₂O

This equation shows that one mole of sodium hydroxide reacts with one mole of hydrochloric acid to produce one mole of sodium chloride and one mole of water. The molar masses of these compounds are approximately:

Sodium hydroxide (NaOH): 40.00 g/mol

Sodium chloride (NaCl): 58.44 g/mol

To find the amount of sodium chloride produced from 46.3 g of sodium hydroxide, use the mole ratio from the balanced equation and the molar masses:

Calculate the moles of NaOH: (46.3 g NaOH) / (40.00 g/mol) = 1.1575 mol NaOH

Use the 1:1 mole ratio between NaOH and NaCl to find moles of NaCl: 1.1575 mol NaOH ⇒ 1.1575 mol NaCl

Convert moles of NaCl to grams: (1.1575 mol NaCl) ⇒ (1.1575 mol) ⇒ (58.44 g/mol) = 67.64 g NaCl

Therefore, 46.3 grams of sodium hydroxide can theoretically produce 67.64 grams of sodium chloride.

Answer:

It would have to be C: the first species to populate an uninhabited area

Explanation:

The meaning of Pioneer species is: the first species to populate an uninhabited area

A pioneer species is the first species to populate an uninhabited area. Therefore, the correct option is option C.

A species is indeed the basic unit of categorization and taxonomic ranking of an organism, in addition to a unit of biodiversity, in biology. A species is frequently described as the biggest group of creatures that includes any two persons of the right sexes or mating types may create viable offspring, most commonly by sexual reproduction.

Species can also be defined by their karyotype, Chromosomal dna, appearance, behavior, or ecological niche. Moreover, because fossil reproduction can indeed be studied, paleontologists employ the idea of chrono species.  A pioneer species is the first species to populate an uninhabited area.

Therefore, the correct option is option C.

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Answer:

Explanation:

(NH4)3 PO4 +NaOH arrow Na3PO4 +3NH3 +3H2O

Start by seeing what happens with the Na. You need 3 on the left, so put a 3 in front of NaOH

(NH4)3 PO4 +3NaOH arrow Na3PO4 +3NH3 +3H2O  Next work with the nitrogens. YOu have 3 on the left and 3 on the right, so they are OK. Next Go to the stray oxygens.

You have 3 on left in (NaOH) and three on the right in 3H2O so they are fine as well. The last thing you should look at are hydrogens.

There are 12 + 3 on the left which is 15. There are 9 (in 3NH3) and 6 more in the water. They seem fine.

Why didn't I do something with the PO4^(-3)? The reason is a deliberately stayed away from them and balanced everything else. Since they were untouched with 1 on the left and 1 on the right, they are balanced.

Species      Na        H        O         N       PO4

Left             3          15        3         3          1

Right           3         15         3         3          1

Answer:

(NH₄)₃PO₄ + 3NaOH ⟶ Na₃PO₄ + 3NH₃ + 3H₂O

Explanation:

Your unbalanced equation is

(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + NH₃ + H₂O

A method that usually works for balancing by inspection is

1. Pick the most complicated-looking formula [(NH₄)₃PO₄].

Put a 1 in front of it.

1(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + NH₃ + H₂O

2. Balance N.

We have fixed 3N on the left. We need 3N on the right.

Put a 3 in front of NH₃.

1(NH₄)₃PO₄ + NaOH ⟶ Na₃PO₄ + 3NH₃ + H₂O

3. Balance P.

We have fixed 1P on the left. We need 1P on the right.

Put a 1 in front of Na₃PO₄.

1(NH₄)₃PO₄ + NaOH ⟶ 1Na₃PO₄ + 3NH₃ + H₂O

4. Balance Na

We have fixed 3Na on the right. we need 3Na on the left.

Put a 3 in front of NaOH.

1(NH₄)₃PO₄ + 3NaOH ⟶ 1Na₃PO₄ + 3NH₃ + H₂O

5. Balance O.

We have fixed 7O on the left and 4O on the right. We need three more O atoms on the right.

Put a 3 in front of H₂O.

1(NH₄)₃PO₄ + 3NaOH ⟶ 1Na₃PO₄ + 3NH₃ + 3H₂O

All species have a coefficient. The equation should now be balanced.

6. Check that all atoms are balanced

[tex]\begin{array}{ccc}\textbf{Atom} & \textbf{On the left} & \textbf{On the right}\\\text{N} & 3 & 3\\\text{H} & 15 & 15\\\text{P} & 1 & 1\\\text{O} & 7 & 7\\\text{Na} & 3 & 3\\\end{array}[/tex]

The balanced equation is

(NH₄)₃PO₄ + 3NaOH ⟶ Na₃PO₄ + 3NH₃ + 3H₂O

Answer:

The egg is changed from liquid to solid

Explanation:

The law of conservation of mass states that "Matter/mass can neither be created nor destroyed but can be converted from one form to another".

Inside of the Egg is liquid in nature and during the process of cooking the egg the liquid changes to solid.

THAT IS HOW MATTER IS CONSERVED WHILE COOKING AN EGG

The mass is conserved when cooking an egg because no mass is lost or gained during the process.

When cooking an egg, the mass is conserved because no mass is lost or gained during the process. The egg goes through a physical and chemical change, but the total mass remains the same. For example, when boiling an egg, the water in the pot evaporates but becomes part of the surrounding gas in the air, so no mass is lost. Additionally, the proteins in the egg denature and solidify, but their mass remains the same.

The conservation of mass principle, also known as the law of conservation of mass, is a cornerstone of chemistry. It is derived from the understanding that atoms are neither created nor destroyed in chemical reactions; they are merely rearranged into different combinations. This means that the total mass of substances involved in a chemical reaction remains constant before and after the reaction.

In the context of cooking an egg, this principle holds true. While physical and chemical changes occur during the cooking process, the total mass of the egg, including its components such as water, proteins, fats, and minerals, remains unchanged. Even though water evaporates from the egg during cooking, the total mass of the system (egg + surroundings) remains constant.

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Answer:

a. 1/3

In the picture- D. 4

Explanation:

The product of the gradients of perpendicular lines =-1

m1m2=-1

Given an equation of a line in the form y=mx+c, m is the gradient of the line.

For y= -3x-9, m=-3

m1m2=-1

-3×m2=-1

m2=1/3

The gradient of the perpendicular line is 1/3

For the question in the picture, y=-1/4x-9, m=-1/4

m1×m2=-1

-1/4m2=-1

m2=4

The slope of the line perpendicular to y=-1/4x-9 is 4

Answer:

The correct answer option is D. 4.

Explanation:

We are given that a line is perpendicular to another line with the equation [tex]y=-\frac{1}{4} x-9[/tex]. We are to find the slope of this perpendicular line.

We know that the in the standard equation of a line, [tex]y=mx+c[/tex], m is the slope of the line.

Also, the slope of a line perpendicular to another is the negative reciprocal of that line.

Therefore, the slope of this perpendicular line is 4.

Answer:

1.uv light not required

The condition that is not required for the formation of ammonia using nitrogen and hydrogen is UV light. Instead, high temperature, high pressure, and an iron catalyst are used in the process.

The reaction of nitrogen with hydrogen to form ammonia gas, also known as the Haber process, typically involves high temperature, high pressure, and the use of an iron catalyst. This reaction process includes a high-pressure condition (~150-250 atm), to favor ammonia production. It also needs a temperature of around 400-500 °C, although lower temperature favors the exothermic reaction, a compromise is reached to achieve a reasonable reaction rate. The iron catalyst is used to accelerate the reaction.

However, the one condition that is not required for the formation of ammonia from nitrogen and hydrogen is the exposure to ultraviolet (UV) light. UV light is not needed to trigger or maintain the reaction, rather the combination of pressure, heat, and the catalyst does the job. Therefore, among the given options, UV light is not necessary for the production of ammonia in the Haber process.

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Answer:

C. 2.4 M

Explanation:

Because you started with 12M solution of KCl, that means that there was a concentration of 12 mols of KCl per Liter of solution. (12mol/1L =12 M). Since there was only 0.5L of solution, there was only 6 mols of KCl because there is only 12 mols per 1 Liter, so half of that volume would have half the amount of solute to keep that true. (6mol/.5L = 12 M). With the new water added, the formula becomes (6mols KCl/ 2.5L of water =2.4 M)

After diluting 0.5 L of a 12 M potassium chloride (KCl) solution with 2 L of distilled water, the final concentration will be 2.4 M.So,option C is correct.

The final concentration of potassium chloride (KCl) after dilution, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Starting with 0.5 L of a 12 M KCl solution and adding 2 L of distilled water, the final volume (V2) is 0.5 L + 2 L = 2.5 L.

Using the formula, we get:

12 M times 0.5 L = M2 times 2.5 L

So, the final concentration (M2) is:

M2 = (12 M times 0.5 L) / 2.5 L = 2.4 M

Therefore, the final concentration of the KCl solution would be 2.4 M.

25.6 L of carbon dioxide gas will be produced when 12.8 L of oxygen gas react with excess carbon monoxide. The stoichiometric ratio for oxygen gas and carbon dioxide gas is 1:2. For every mole of O2 consumed, 2 moles of CO2 are formed.

Further Explanation:

The balanced chemical equation for this reaction is:

O2 + 2 CO → 2 CO2

To get the amount of CO2 produced, the following steps must be followed:

Solving the problem,

STEP 1: Convert liters to moles

[tex]moles \ of \ O_{2} \ = given \ volume \ O_{2} \ (\frac{1 \ mole \ O_{2}}{22.4 \ L} )\\moles \ of \ O_{2} \ = 12.8 \ L \ O_{2} \ (\frac{1 \ mole \ O_{2}}{22.4 \ L} )\\\boxed {moles \ of \ O_{2} \ = 0.57143 \ mol}[/tex]

STEP 2: Get the moles of CO2 formed

[tex]moles \ of\ CO_{2} \ = \ given \ moles \ O_{2} \ (\frac{2 \ mol \ CO_{2}}{1 \ mol \ O_{2}})\\moles \ of\ CO_{2} \ = \ 0.57143 \ mol \ O_{2} \ (\frac{2 \ mol \ CO_{2}}{1 \ mol \ O_{2}})\\\\\boxed {moles \ of\ CO_{2} \ = \ 1.14286 \ mol}[/tex]

STEP 3: Convert moles to liters

[tex]liters \ CO_{2} \ = given \ moles \ CO_{2} \ (\frac{22.4 \ L}{1 \ mol \ CO_{2}})\\liters \ CO_{2} \ = 1.14286 \ mol \ CO_{2} \ (\frac{22.4 \ L}{1 \ mol \ CO_{2}})\\\\\boxed {liters \ CO_{2} \ = 25.6 \ L}[/tex]

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Keywords: stoichiometry, STP, gases

Answer:

25.6 liters of [tex]CO_2[/tex] will be produced.

Explanation:

We are given that 12.8 liters of Oxygen gas is reacted with excess Carbon Monoxide to produce of Carbon Dioxide gas, keeping all the volume measurements at the same temperature.

We are to find the number of liters of Carbon Dioxide used in the reaction.

The equation for this reaction will be:

[tex]2 CO + O_2\implies 2 CO_2[/tex]

From the equation, we can see that the mole ratio of Oxygen to Carbon Dioxide is 1:2. Therefore, the number of liters of [tex]CO_2[/tex] will be double the number of liters of Oxygen.

[tex]12.8 \times 2 = 25.6[/tex]

So, 25.6 liters of [tex]CO_2[/tex] will be produced.

Answer:

They all belong in the same period, thus they have the same energy levels which is 2.

In the periodic table, elements are categorized by group and period. Periods are arranged in rows. Below is a picture of the periodic table and where these elements are.

As you can see, they all belong in the same period (row). Elements in the same period have the same number of atomic orbitals, or in other words, they have the same electron energy level. The period number tells you the energy level. Lithium (Li), Carbon (C), and Fluorine (F) are in period 2, so they all have two energy levels.

Answer:

The seasons are caused by the tilt of the Earth's rotational axis away or toward the sun as it travels through its year-long path around the sun

Answer:

Rotation of the Earth.

As the Earth rotates, places on Earth get farther from the Sun and make seasons.

Physical properties, such as density and color, can be observed without changing the substance's composition, while chemical properties, like flammability, involve changing the substance's chemical structure through reactions.

Physical and chemical properties are two fundamental ways to describe matter, each highlighting different aspects of the substances around us. Physical properties include characteristics that can be observed or measured without changing the substance's chemical composition. Examples of physical properties are density, color, hardness, melting and boiling points, and electrical conductivity. Observing these properties doesn't alter the identity of the material. For instance, measuring the melting point of ice or observing the color of copper involves no chemical alteration of the substance.

On the other hand, chemical properties involve how a substance interacts with other substances to form new materials, revealing its behavior in chemical reactions. Traits like flammability and the ability to corrode are examples of chemical properties because observing them involves changing the substance’s chemical structure. When a piece of wood burns, transforming into ash and smoke, it undergoes a chemical change that alters its identity, showcasing its flammability — a key chemical property.

Answer:electrons will be equally attracted to both

Explanation:

e2020

Answer:

Electrons will be equally attracted to both atoms.

Explanation:

Answer:

Approximately [tex]83\%[/tex].

Explanation:

How many moles of [tex]\mathrm{CO_2}[/tex] gas are released?

The volume of each mole of of an ideal gas is approximately [tex]\rm 24\;L[/tex] under room temperature and pressure (r.t.p, [tex]\rm 20\;^{\circ}C[/tex], [tex]\rm 1\; \right. atm[/tex].) That's the same as [tex]\rm 24,000\;cm^{2}[/tex].

Assume that [tex]\mathrm{CO_2}[/tex] acts like an ideal gas.

[tex]\displaystyle n(\mathrm{CO_2}) = \rm \frac{100\; cm^{3}}{24,000\; cm^{3}} \approx 0.00416667\; mol[/tex].

[tex]\rm HCl[/tex] is in excess. How many moles of [tex]\mathrm{CaCO_3}[/tex] formula units will produce that [tex]\rm 0.00416667\; mol[/tex] of [tex]\mathrm{CO_2}[/tex]?

Consider the ratio between the coefficient of [tex]\mathrm{CaCO_3}[/tex] and that of [tex]\mathrm{CO_2}[/tex].

[tex]\displaystyle \frac{n(\mathrm{CaCO_3})}{n(\mathrm{CO_2})}=1[/tex].

In other words,

[tex]\displaystyle n(\mathrm{CaCO_3})= n(\mathrm{CO_2})\cdot \frac{n(\mathrm{CaCO_3})}{n(\mathrm{CO_2})} = \rm 0.00416667\; mol[/tex].

What's the mass of that many [tex]\mathrm{CaCO_3}[/tex]?

Relative atomic mass data from a modern periodic table:

Formula mass of [tex]\mathrm{CaCO_3}[/tex]:

[tex]M(\mathrm{CaCO_3}) = 40.078+12.011 + 3\times 15.999 =\rm 100.086\; g\cdot mol^{-1}[/tex].

Mass of that [tex]\rm 0.00416667\; mol[/tex] of [tex]\mathrm{CaCO_3}[/tex]:

[tex]m = n \cdot M = \rm 0.00416667 \times 100.086 = 0.417025\; g[/tex].

Percentage mass of [tex]\mathrm{CaCO_3}[/tex] in this sample of chalk:

[tex]\displaystyle \frac{\text{Mass of }\mathrm{CaCO_3}}{\text{Mass of Chalk}} \times 100\%= \rm \frac{0.417025\; g}{0.5\; g} \times 100\%\approx 83\%[/tex].

The mass of 1.6 mol of aluminum atom is 43.1712.

What is aluminum atom?

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