Explain how the molar mass of a gas affects the rate at which the gas diffuses and effuses

Answers

Answer 1
Diffusion  is defined as spreading of molecules of a substance, away from each other, throughout the space.

Effusion is the phenomena of escape of gas molecules through a very small orifice into an evacuated area. 

According to Graham's Law, rate of diffusion and effusion is inversely proportional to molecular mass.

Thus, with increase in molecular mass, rate of diffusion and effusion will decrease. 
Answer 2
Final answer:

The molar mass of a gas influences its diffusion and effusion rates, according to Graham's law of effusion. Lighter gas molecules diffuse and effuse faster than heavier ones due to their movement speed. The ratios of diffusion and effusion rates, both dependent on the molar mass, remain constant.

Explanation:

The molar mass of a gas significantly affects its diffusion and effusion rates due to the principles identified in Graham's law of effusion. According to this law, the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. Hence, lighter gas molecules will effuse and diffuse at a faster rate as compared to heavier ones.

Furthermore, the average speed of gas molecules impacts the rate of effusion. As a consequence, heavier gas molecules, which move more slowly due to their larger mass, will diffuse and effuse slower compared to lighter molecules. This is because it is more challenging for heavier molecules to move between the molecules of the substance they are moving through.

Lastly, diffusion and effusion rates both depend on the molar mass of the gas involved. Although their rates are not identical, the ratios of their rates remain consistent. This is another way the molar mass of a gas influences its diffusion and effusion rates.

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Related Questions

How much 0.85 M HCl solution can be made by diluting 250 mL of 10 M HCl?

Answers

Answer is:  2940 mL of the HCL solution.

c₁(HCl) = 10.0 M.

V₂(AgNO₃) = ?.
c₂(AgNO₃) = 0.85 M.
V₁(AgNO₃) = 250 mL ÷ 1000 mL/L = 0.25 L.

c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - volume to be diluted.
V₂ - final volume after dilution.
c₁ · V₁ = c₂ · V₂.
V₂(HCl) = c₁ · V₁ ÷ c₂.

V₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.

V₂(HCl) = 2.94 L · 1000 mL = 2940 mL.

The amount of 0.85M HCl solution that can  be made  by diluting 250 ml of 10M HCl is calculated using

M1V1=M2V2  formula

M1=0.85M
V1=?
M2= 10M
V2= 250 ml

by making the V1 the subject of the formula
V1 = M2V2/M1

V1 = (10 Mx250 ml)/ 0.85 M =2941.2 ml

What is the total number of atoms contained in 2.00 moles of nickel?

Answers

  The number of  atoms  that are contained in  2.00 moles  nickel  is calculated  by use of Avogadro  law  constant

that is  1 mole  =  6.02  x10^23   atoms

what  about 2 moles = ?  atoms

= ( 2moles /1mole)  x 6.02 x10^23  atoms = 1.204  x10^24  atoms   of nickel  are there in  2 moles  of nickel

The total number of atoms contained in 2.00 moles of nickel is 1.204 × 10²⁴ atoms

HOW TO CALCULATE NUMBER OF ATOMS:

The number of atoms in an element can be calculated by multiplying the number of moles by Avogadro's number. That is;

no. of atoms = no. of moles × 6.02 × 10²³

According to this question, there are 2 moles of nickel (Ni). The number of atoms can be calculated as follows:

no. of atoms = 2 × 6.02 × 10²³

no. of atoms = 12.04 × 10²³

no. of atoms = 1.204 × 10²⁴ atoms

Therefore, the total number of atoms contained in 2.00 moles of nickel is 1.204 × 10²⁴ atoms.

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Describe what a polar covalent bond is and name a common compound that has a polar covalent bond holding it together

Answers

Polar covalent are type of covalent bond ( sharing of electrons)  in which the electrons shared by the atoms spend a greater amount of time, on the average closer to one atom's nucleus. An example of a compound that has a polar covalent bond is water (H2O). The electrons are unequally shared, with the oxygen atom spending more time with electrons than the hydrogen atoms. Since electrons spend more time with the oxygen atom, it carries a partial negative charge.

sphingomyelin contains a fatty acid linked by an ________ bond and phosphocholine linked via the c-3 hydroxyl group of sphingosine.

Answers

the answer is amide



your welcome

How many moles of naf must be dissolved in 1.00 liter of a saturated solution of pbf2 at 25°c to reduce the [pb2+] to 1.0 × 10–6 m? the ksp for pbf2 at 25 °c is 4.0 × 10–8?

Answers

The reaction involved in the given question is 
[tex] PbF_{2} [/tex] → [tex] Pb^{2+} [/tex] + [tex] 2F^{-} [/tex]

Ksp= [[tex] Pb^{2+} [/tex]] [[tex] F^{-}[/tex]]^2
4.0 ×[tex] 10^{-8} [/tex] = 1×[tex] 10^{-6} [/tex] [[tex] F^{-}[/tex]]^2

 ∴[[tex] F^{-} [/tex]] = 0.2 mole

Thus, 0.2 mole of NaF must be dissolved in 1l of sat. solution of [tex] PbF_{2} [/tex] to reduce [tex] Pb^{2+} [/tex] to 1 X 10^(-6) M
Final answer:

To reduce the [Pb2+] to 1.0 × 10⁻⁶ M in a 1.00 liter solution of saturated PbF2, 26.45 grams of NaF should be added, as the Ksp for PbF2 is 4.0 × 10⁻⁸ at 25°C.

Explanation:

To determine how many moles of NaF must be added to a 1.00 liter solution of saturated PbF2 to reduce the [Pb2+] concentration to 1.0 × 10−6 M, we need to consider the Ksp of PbF2 and the common ion effect. The Ksp expression for PbF2 is Ksp = [Pb2+][F−]2, and the Ksp value given is 4.0 × 10−8 at 25°C. As we add NaF, which is a source of fluoride ions, F−, this will affect the equilibrium according to Le Chatelier's principle.

Since NaF fully dissociates in solution, each mole of NaF will provide one mole of F−. Our target is to maintain the [Pb2+] at 1.0 × 10−6 M while knowing the Ksp. From this, we can derive that:

[F−] = √(Ksp / [Pb2+]) = √(4.0 × 10⁻⁸ / 1.0 × 10⁻⁶ M) = √(4.0 × 10⁻² M) = 6.3 × 10⁻¹ M

Since the concentration of F− should be approximately 0.63 M to maintain the [Pb2+] at the desired level, and we want to achieve this in a 1-liter solution, we need to dissolve 0.63 moles of NaF:

0.63 moles × 41.99 g/mol = 26.45 grams of NaF.

This is the mass of NaF that should be dissolved to achieve the desired [Pb2+] in the solution.

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Which of the following is a correct description of a double bond between two carbon atoms?

A double bond will produce four single bonds to form a tetrahedral shape.
A double bond between carbon atoms will eventually form a ring of carbons.
A double bond between carbon atoms is longer than a triple bond between carbon atoms.
A double bond will quickly reduce to single bonds to create three-dimensional tetrahedra.

Answers

Correct answer is: A double bond between carbon atoms is longer than a triple bond between carbon atoms.

Reason:
In a carbon-carbon double bonded system, each carbon has undergoes sp2 hybridization. Thus, it bond order of system is 2. While in case of carbon-carbon bonded system via triple bond, each carbon atom undergoes sp hybridization. The bond order in this case is 3. Further, extent of overlap in sp hybridized orbitals is more as compared to sp2 hybridized orbitals. Hence, a double bond between carbon atoms is longer than a triple bond between carbon atoms.
From the following,the correct description of a double bond between two carbon atoms is that A double bond will produce four single bonds to form a tetrahedral shape. A carbon to carbon bond is an example of nonpolar covalent bonding.

How does the total volume of gas particles compare to the volume of the space between gas particles?

Answers

Answer:
             There is more space between gas particles than the size of the particles.

Explanation:
                   This scenario can be understand by taking a very simple example. As we know that 1 mole of any gas at standard temperature and pressure occupy 22.4 liters of volume. Lets take Hydrogen gas and Oxygen gas, 1 mole of each gas will occupy same volume. Why it is so? Why same volume although Oxygen is 16 times more heavier? This is because the space between gas molecules is very large. Approximately the distance between gas molecules is 300 times greater than their own diameter from its neighbor molecules. 

Which statement best describes the oxidation numbers of the atoms found in magnesium chloride?
A. Magnesium has a 2+ oxidation number and chlorine has a 1- oxidation number. B. Magnesium has a 2- oxidation number and chlorine has a 2+ oxidation number. C. Magnesium has a 2- oxidation number and chlorine has a 1+ oxidation number. D. Magnesium has a 1+ oxidation number and chlorine has a 1- oxidation number.

Answers

Answer is: A. Magnesium has a 2+ oxidation number and chlorine has a 1- oxidation number. 
Magnesium is metal from second group of Periodic table of elements and it lost two electrons to have electron configuration as closest noble gas neon (₁₀Ne), chlorine is nonmetal from 17. group of Periodic table and it gains one electron to have electron configuration as argon (₁₈Ar).
I believe Magnesium has a 2+ oxidation number and chlorine has a 1- oxidation number.  An oxidation number is a number that is assigned to an atom in a substance. It could be positive, negative, or zero, and it indicates if electrons are lost or gained. Oxidation number helps in keeping track of electrons in an atom. 

A solution is prepared by dissolving 27.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the concentration of cacl2 is __________% by mass.

Answers

The concentration of [tex]{\text{CaC}}{{\text{l}}_{\text{2}}}[/tex] is [tex]\boxed{6.88\;\%}[/tex] by mass.

Further Explanation:

The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:

1. Molarity (M)

2. Molality (m)

3. Mole fraction (X)

4. Parts per million (ppm)

5. Mass percent ((w/w) %)

6. Volume percent ((v/v) %)

Mass percent:

It is the ratio of the mass of a component divided by the total mass of the solution, multiplied by 100.

The formula to calculate the mass percent of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] is as follows:

[tex]{\text{Mass}}\;{\text{percent of CaC}}{{\text{l}}_2} = \left( {\frac{{{\text{Mass of CaC}}{{\text{l}}_{\text{2}}}}}{{{\text{Mass of CaC}}{{\text{l}}_2}\;{\text{solution}}}}} \right)\left( {100} \right)[/tex]           …… (1)

The formula to calculate the mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] solution is as follows:

[tex]{\text{Mass of CaC}}{{\text{l}}_{\text{2}}}{\text{ solution}} = {\text{Mass of CaC}}{{\text{l}}_{\text{2}}} + {\text{Mass of water}}[/tex]       …… (2)

The mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] is 27.7 g.

The mass of water is 375 g.

Substitute these values in equation (2).

[tex]\begin{aligned}{\text{Mass of CaC}}{{\text{l}}_{\text{2}}}{\text{ solution}}&=27.7{\text{ g}}+{\text{375 g}}\\&={\text{402}}{\text{.7 g}}\\\end{aligned}[/tex]

The mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex] is 27.7 g.

The mass of [tex]{\text{CaC}}{{\text{l}}_2}[/tex]solution is 402.7 g.

Substitute these values in equation (1).

[tex]\begin{aligned}{\text{Mass}}\;{\text{percent of CaC}}{{\text{l}}_2}&=\left( {\frac{{{\text{27}}{\text{.7 g}}}}{{{\text{402}}{\text{.7 g}}}}} \right)\left( {100} \right)\\&=6.8785\;\%\\&\approx 6.8{\text{8 \% }}\\\end{aligend}[/tex]

Therefore the mass percent of [tex]{\mathbf{CaC}}{{\mathbf{l}}_{\mathbf{2}}}[/tex] is 6.88 %.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: mass percent, 6.88 %, mass of CaCl2, mass of water, mass of CaCl2, concentration, CaCl2, 27.7 g, 375 g, 402.7 g.

Final answer:

The concentration of CaCl2 in the solution is approximately 6.88% by mass.

Explanation:

The concentration of a solution is usually expressed as a percent by mass. In order to calculate this, we need to determine the mass of the solute (CaCl2) and the mass of the solution (cacl2 + water).


Given that 27.7g of CaCl2 is dissolved in 375g of water, the total mass of the solution would be 27.7g + 375g = 402.7g.


The concentration of CaCl2 is then calculated by dividing the mass of CaCl2 by the mass of the solution and multiplying by 100%: (27.7g / 402.7g) x 100% ≈ 6.88%.

What is the number of electrons in an atom of 23v that have an quantum number of 2?

Answers

I=2 d orbital 
v has confiduration of 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^3
so it has 3 electrons 

Study the following two reactions. Select all that apply.
C(graphite) + O2(g) → CO2(g) + 94.05 kcal
C(diamond) + O2(g) → CO2(g) + 94.50 kcal
What could you infer from the information given above?
a The enthalpy of CO2 is greater than the reactants.
b E2 - E1 is negative.
c Graphite and diamond have equal enthalpy.
d Diamond must have lower internal energy.

Answers

Answer:

Option B only

Explanation:

First to all, we have the same reaction in both equations, the difference between the two of them, is the fact one is Carbon in the form of graphite, and the other is carbon in the form of diamond.

Now, both reactions release energy in the form of heat, and it appears in the side of the products, this means that both reactions are exothermic (An exothermic reaction is when energy is released as product in the equation).

If energy is released in the reaction, (Which is enthalpy), this value is negative. As this value is negative, means that the internal energy of CO2 has to be lower than the energy of the reactants, so, option A can be discarted.

If we do E2 - E1:

-94.5 - (-94.05) = -0.45 kcal

Therefore, option B is correct.

As we can see the energy released in both equations, is different for both, so, graphite and diamond do not have equal enthalpy.

Finally, as the combustion of diamond releases more energy that the combustion of graphite (94.5 > 94.05), means that diamond has a higher internal energy than graphite. and Option D can be discarted.

A chemical reaction that absorbs heat from the surroundings is said to be ________ and has a ________ δh at constant pressure.

Answers

A chemical reaction that absorbs heat from the surroundings is said to be endothermic and has a positive ΔH at constant pressure.
There are two types of reaction: endothermic reaction (chemical reaction that absorbs more energy than it releases) and exothermic reaction (chemical reaction that releases more energy than it absorbs).
For example, sublimation is an endothermic process, dry ice (carbon(IV) oxide in solid state) is used because of sublimation in nightclubs, fog machines, at theaters, haunted house attractions.

Final answer:

An endothermic process is a chemical reaction or physical change that absorbs heat, with a positive change in enthalpy. An example is the reaction in a cold pack, where heat is absorbed, resulting in a sensation of cold. In contrast, an exothermic process releases heat, such as the combustion reaction in a Bunsen burner.

Explanation:

An endothermic process is a chemical reaction or physical change that absorbs heat from the surroundings. It is represented by a positive change in enthalpy, which is the sum of a system's internal energy and the mathematical product of its pressure and volume.

An example of an endothermic process is the reaction that occurs in a cold pack used to treat muscle strains. When the substances in the cold pack are brought together, heat is absorbed, resulting in a sensation of cold.

In contrast, an exothermic process releases heat. An example of an exothermic process is the combustion reaction that occurs when using a Bunsen burner. The heat given off during this reaction is equal to the enthalpy change of the methane combustion reaction.

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What bonds are broken during the combustion of methane (CH4) to form water and carbon dioxide?


C–H bonds in methane and O–O bonds in oxygen

C–O bonds in carbon dioxide and O–O bonds in oxygen

C–H bonds in methane and H–O bonds in water

H–O bonds in water and C–O bonds in carbon dioxide

Answers


C–H bonds in methane and O–O bonds in oxygen.

CH4 +2O2--->CO2 + 2H2O

CH4 has only C-H bonds. 
O2 has only O=O bond.

Answer:

The correct answer is: C–H bonds in methane and O–O bonds in oxygen.

Explanation:

During the combustion of methane, methane react with oxygen molecule to give carbon dioxide and water molecule.

[tex]2CH_4+3O_2\rightarrow 2CO_2+2H_2O[/tex]

During the course of reaction :

Bond between C-H atom in methane will be broken down Bond between O-O bond will be broken down.

During course of formation of products:

Bonds between oxygen and carbon atom will formed Bonds between oxygen ah hydrogen at will be formed.

A 3.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific test site. The half-life of the radioactive element is 28 years. How much of the original sample will remain in the year 2030? Show your work.

Answers

The answer is 0.62g.
Solution:
From year 1960 to year 2030, it has been 
     2030-1960 = 70 years

The half-life of the radioactive element is 28 years, then the sample will go through
     70 years * (1 half-life/28 years) = 2.5 half-lives

Starting with a 3.5 gram sample, we will have
     3.5*(1/2) after one half-life passes
     3.5*(1/2) * (1/2) = 3.5*(1/4) after two half-lives pass
     3.5*(1/4) * (1/2) = 3.5*(1/8) after three half-lives pass and so on

Therefore, we can write the remaining amount of the sample after the number n of half-lives have passed as
     mass of sample = initial mass of sample/2^n

The mass of the remaining sample for n = 2.5half-lives can be now calculated as
     mass of sample = 3.5 grams / 2^2.5 = 0.62 g

Complete each reaction for strong electrolytes in water.
a. cacl2(s) →
b. mg(no3)2 →
c. al2(so4)3 →

Answers

Chemical reaction a: CaCl₂(s) → Ca²⁺(aq) + 2Cl⁻(aq).
Chemical reaction b: Mg(NO₃)₂(s) → Mg²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction c: Al₂(SO₄)₃(s) → 2Al³⁺(aq) + 3SO₄²⁻(aq).
This compounds are ionic, in water dissociate on metal cations (Ca²⁺, Mg²⁺ and Al³⁺) and anions of conjugate base of acids (Cl⁻, NO₃⁻ and SO₄²⁻).
Final answer:

Strong electrolytes dissociate completely into ions in water. The resulting ions for CaCl2 are Ca2+ and Cl-; for Mg(NO3)2 are Mg2+ and NO3-; and for Al2(SO4)3 are Al3+ and SO4−2.

Explanation:

In water, strong electrolytes dissociate completely into their ions.

For CaCl2(s) in water: CaCl2(s) → Ca2+(aq) + 2Cl-(aq)For Mg(NO3)2 in water: Mg(NO3)2(s) → Mg2+(aq) + 2NO3-(aq) For Al2(SO4)3 in water: Al2(SO4)3(s) → 2Al3+(aq) + 3SO4−2(aq)

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How many moles of nitrogen, n, are in 83.0 g of nitrous oxide, n2o?

Answers

The  moles  of  nitrogen n  in  83.0 g  of N2O  is calculated  as  below

find the  moles  of N2O
moles =  mass/molar  mass

= 83 g/44g/mol=  1.886  moles
the  moles of Nitrogen  in N2O  is therefore 

=1.886  moles  x2(since there are two   atom of N  in N2O) =3.772  moles

There are approximately [tex]3.772[/tex] moles of nitrogen in [tex]83.0 g[/tex] of nitrous oxide [tex](N\(_2\)O)[/tex]

To determine the number of moles of nitrogen in [tex]83.0 g[/tex] of nitrous oxide [tex](N\(_2\)O)[/tex], we need to follow these steps:

1. Calculate the molar mass of [tex]N\(_2\)O[/tex]:

Nitrogen ([tex]N[/tex]) has a molar mass of approximately [tex]14.01 g/mol.[/tex]

Oxygen ([tex]O[/tex]) has a molar mass of approximately [tex]16.00 g/mol.[/tex]

The molar mass of [tex]N\(_2\)O[/tex] is:

[tex]\[\text{Molar mass of N}_2\text{O} = 2 \times 14.01 \, \text{g/mol} + 16.00 \, \text{g/mol} = 28.02 \, \text{g/mol} + 16.00 \, \text{g/mol} = 44.02 \, \text{g/mol}\][/tex]

2. Calculate the number of moles of [tex]N\(_2\)O[/tex] in [tex]83.0 g[/tex]:

[tex]\[\text{Number of moles of N}_2\text{O} = \frac{83.0 \, \text{g}}{44.02 \, \text{g/mol}} = 1.886 \, \text{moles}\][/tex]

3. Determine the number of moles of nitrogen atoms in [tex]N\(_2\)O[/tex]

Each molecule of [tex]N\(_2\)O[/tex] contains [tex]2[/tex] nitrogen atoms. Therefore, the number of moles of nitrogen atoms is twice the number of moles of [tex]N\(_2\)O.[/tex]

[tex]\[\text{Number of moles of nitrogen atoms} = 2 \times 1.886 \, \text{moles} = 3.772 \, \text{moles}\][/tex]

Which general formula can be used to identify carbohydrates?

Answers

I believe its (CH20)n

Explanation:

Carbohydrates are the organic compounds that contain a carbon, hydrogen and oxygen atoms which are chemically combined together.

Their general formula is [tex](CH_{2}O)_{x}[/tex] where x is any integer.

For example, lactose has chemical formula [tex]C_{12}H_{22}O_{11}[/tex] and it is a carbohydrate.

A carbohydrate can be monosaccharide, disaccharide, oligosaccharide or polysaccharide.

How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?
a.1.46 g strike reset
b.2.93 g strike reset
c.29.3 g strike reset
d.58.5 g strike reset?

Answers

molarity is the number of moles of solute in 1 L solution.
molarity of solution to be prepared is 0.100 M
volume of solution to be prepared is 500.0 mL 
the number of moles in 1 L - 0.100 mol 
therefore number of moles in 500.0 mL - 0.100 mol/L x  500.0 x 10⁻³ L = 0.0500 mol
mass of NaCl required - 0.0500 mol x 58.5 g/mol = 2.925 g
mass of NaCl needed is therefore 2.93 g
answer is B. 2.93 g

In order to prepare 500.0 mL of a 0.100 M NaCl solution, 2.93 g of sodium chloride are required (Option b).

What is molarity?

Molarity is the number of moles of solute per liters of solution.

We have 500.0 mL of a 0.100 M NaCl solution. First, we will calculate the moles of solute using the definition of molarity.

M = moles solute / liters solution

moles solute = M × liters solution

moles solute = 0.100 mol/L × 0.5000 L = 0.0500 mol

Next, we will convert 0.0500 moles of NaCl to grams using its molar mass.

0.0500 mol × 58.5 g/mol = 2.93 g

In order to prepare 500.0 mL of a 0.100 M NaCl solution, 2.93 g of sodium chloride are required (Option b).

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Which is true about the numerical value of the gibbs free-energy change for a spontaneous reaction?

Answers

 The truth  about the numerical value of the gibb  free-energy change for a spontaneous reaction is that


gibbs free energy  (delta G) negative

that is delta G<0
when the value of gibbs free energy is negative (less than zero) the  reaction is spontaneous , while the value of gibbs free energy is positive ( greater than than zero) the reaction is  non spontaneous, and when the gibbs  free  energy is  equal to zero the reaction is at equilibrium.


Answer:

It is negative

Explanation:

For every molecule of glucose, how many molecules of co2 are released in the citric acid cycle

Answers

Since glycolysis of one glucose molecule generates two acetyl CoA molecules, the reactions in the glycolytic pathway and citric acid cycle produce six CO2 molecules , 10 NADH molecules, and FADH2 molecules per glucose molecule.

What will happen to the pressure if another mole of gas is added to the cylinder but the temperature and volume do not change?

Answers

Answer:  The pressure will increase.

Note:   " PV = nRT " .

R is a gas constant; 

If V and R remain constant,  an increase in "n" will result in an increase in "P" .
__________________________________________________________

A gas occupies a volume at 34.2 mL at a temperature of 15.0 C and a pressure of 800.0 torr. What will be the volume of this gas at STP?

Answers

The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
     P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
     (800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
     V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
     V2 = 34.1 mL
the ideal gas law equation can be used to find the number of moles of the gas at given conditions
PV = nRT
where 
P - pressure - 800.0 torr x 133.3 Pa/torr = 106 640 Pa
V - volume - 34.2 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 15 °C + 273 = 288 K
substituting these values in the equation
106 640 Pa x 34.2 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 288 K 
n = 1.52 mol

molar volume is where 1 mol of any gas occupies a volume of 22.4 L at STP
therefore if 1 mol occupies - 22.4 L
then 1.52 mol occupies - 22.4 L/mol x 1.52 mol = 34.05 L
volume of the gas at STP is 34.05 L

Elements of group 4a do not commonly form ions. generally form negative ions. do not combine with other elements. generally form positive ions.

Answers

Final answer:

Elements of Group 4A typically do not form ions readily, but when they do, they generally form positive ions or cations with a +4 charge.

Explanation:

Group 4A elements, also known as the carbon group, typically do not form ions easily. This is because the elements in this group generally have a balance between the energy required to lose or gain electrons, making the formation of ions less favorable. When these elements do form ions, they generally form positive ions or cations. Looking at the periodic table, main-group elements to the left tend to form cations with a positive charge equal to the group number. Conversely, elements to the right, particularly nonmetals, often form anions with a negative charge corresponding to the number of groups they are left of the noble gases. Group 4A elements would thus be expected to form 4+ cations if they were to form ions, which is a high charge and not commonly observed due to the energy involved in removing four electrons.

if 1.20 moles of copper react with mercuric nitrate how many moles of mercury form

Answers

Final answer:

To determine the number of moles of mercury formed when 1.20 moles of copper react with mercuric nitrate, you need to examine the balanced chemical equation. For every 2 moles of copper that react, 2 moles of mercury are formed. Therefore, if you have 1.20 moles of copper, you will also have 1.20 moles of mercury formed.

Explanation:

In order to determine the number of moles of mercury formed when 1.20 moles of copper react with mercuric nitrate, you need to examine the balanced chemical equation for the reaction. The balanced equation is:

2Cu + Hg(NO3)2 → 2Hg + 2Cu(NO3)2

From this equation, you can see that for every 2 moles of copper (Cu) that react, 2 moles of mercury (Hg) are formed. Therefore, if you have 1.20 moles of copper, you will also have 1.20 moles of mercury formed in the reaction.

Given the balanced equation for the reaction of copper with mercuric nitrate, 1.20 moles of copper will produce 1.20 moles of mercury.

Given the reaction between copper and mercuric nitrate, we can use stoichiometry to determine the moles of mercury produced. The balanced chemical equation for this type of reaction is:

Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg

From this equation, we see that 1 mole of copper (Cu) reacts with 1 mole of mercuric nitrate (Hg(NO₃)₂) to produce 1 mole of mercury (Hg).

Since we have 1.20 moles of copper reacting, we can directly infer that:

1.20 moles of Cu → 1.20 moles of Hg

Identify the balanced chemical reaction: Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + HgDetermine the mole ratio between copper and mercury from the balanced equation (1:1).Using this ratio, 1.20 moles of copper will produce 1.20 moles of mercury.

Which of the following are advantages of the SI system?

(Select all that apply).

A) It is easy to change from one unit to another.
B) It allows scientists to compare experimental results.
C) All its units are based on the number 100.
D) It is based on inches and pounds.

Answers

A      b                                              c                     ar e the correect ones

The advantage of the SI system is that It is easy to change from one unit to another. Hence Option (A) is correct.

What is SI Unit ?

SI unit is a global system of measurements that ar used universally in technical and research to avoid the confusion with the units.

Having a typical unit system is vital as a result of it helps the complete world to grasp the measurements in one set of unit systems.

The SI covers units for each style of measuring, however at the guts of the SI could be a set of seven units called the 'base units'.

This Systeme International d'Unites of Units is critical to confirm that our everyday measurements stay comparable and consistent worldwide.

Therefore, The advantage of the SI system is that It is easy to change from one unit to another. Hence Option (A) is correct.

Learn more about SI Unit here ;

https://brainly.in/question/37187746

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What happens in an acid-base reaction according to the arrthenius defintion?

Answers

The acid yields H+ ions while the base yields OH- ions

Final answer:

The Arrhenius definition of acid-base reactions states that an acid is a substance that dissociates in water to produce H+ ions, while a base is a substance that dissociates in water to produce OH- ions. Acid-base reactions involve the transfer of a proton from the acid to the base, resulting in the formation of water and a salt.

Explanation:

The Arrhenius definition of acid-base reactions states that an acid is a substance that dissociates in water to produce H+ ions, while a base is a substance that dissociates in water to produce OH- ions.

According to Arrhenius, an acid-base reaction involves the reaction of a proton (H+) from the acid with a hydroxide ion (OH-) from the base, resulting in the formation of water.

For example, in the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), HCl donates a proton (H+) to NaOH, which accepts the proton, forming water (H2O) and sodium chloride (NaCl) as a salt.

How many grams of solute are in 1.00 liter of 0.200m na2so4 solution?

Answers

Molarity can be defined as the number of moles of solute in 1 L solution.
Molarity of Na₂SO₄ solution - 0.200 M
this means there are 0.200 moles in 1 L solution 
Molar mass of Na₂SO₄ - 142 g/mol 
therefore mass of Na₂SO₄ in 1.00 L - 0.200 mol x 142 g/mol = 28.4 g
a mass of 28.4 g of Na₂SO₄ is present in 1.00 L
Final answer:

There are 28.42 grams of Na2SO4 in 1.00 liter of a 0.200M solution by first finding the number of moles in one liter and then multiplying by the molar mass of Na2SO4.

Explanation:

To determine the mass of solute in 1.00 liter of a 0.200M Na2SO4 solution, we need to follow these steps:

Calculate the number of moles of Na2SO4 in 1.00 L of the solution using the molarity. Since molarity is moles per liter, we have 0.200 moles of Na2SO4 because 0.200M means 0.200 moles per liter.Find the molar mass of Na2SO4. The molar mass of Na2SO4 is (2 × 23.0) + 32.1 + (4 × 16.0) = 142.1 g/mol.Multiply the number of moles by the molar mass to get the mass in grams. So, 0.200 moles × 142.1 g/mol = 28.42 grams of Na2SO4.

Therefore, there are 28.42 grams of Na2SO4 in 1.00 liter of a 0.200M solution.

How many moles of water h2o are present in 75.0 g h2o?

Answers

4.17 moles. Good luck! :)

A student conducted an experiment and was interested in the mass of the product of the chemical reaction. some results are shown above. what is the mass of the nacl?

Answers

NOTE: Above question is incomplete. Complete question is attached as an image file along with this question.
..............................................................................................................................

The reaction involved in present question is:

NaHCO3(s) + HCl(aq)                 →           NaCl(s)     +    CO2(g)    + H2O(g)

From the above reaction, it can be seen that sodium bicarbonate on reacting with HCl gets converted into NaCl (s), CO2(g)  and H2O(g).

CO2(g)  and H2O(g) being gas will be lost from evaporating disk and watch glass, therefore there will be lost in mass.

Thus mass let in evaporating disk and watch glass will be only due to NaCl,
= 44.45 - 42.70 = 1.75 g

The correct answer is option B

What mass of h2o is formed when h2 reacts with 384 grams of o2?

Answers

Answer is: mass of water is 432 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(O₂) = 384 g.
M(O₂) = 2 · 16 g/mol = 32 g/mol, molar mass.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 384 g ÷ 32 g/mol.
n(O₂) = 12 mol, amount of substance.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 12 mol · 2 = 24 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 24 mol · 18 g/mol.
m(H₂O) = 432 g.
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