Explain how you can tell the function f (x) = |x + 4| is not linear by using points on its graph.

That would be four times 88 passengers:  352 passengers per day.

Answer: 352

Step-by-step explanation:

88x4

The equation of the given line, y = 3x - 2, is written in slope-intercept form:

... y = mx + b

where m represents the slope and b is the y-intercept.

Matching the form to the given equation, you see m = 3, and b = -2. The slope of the given line is 3.

The slope of a line perpendicular to it will be the negative reciprocal of this value

... slope of perpendicular line = -1/m = -1/3

For some new value of b, the equation of the perpendicular line can be written

... y = (-1/3)x + b

Filling in the values of the point coordinates, we can find the appropriate value of b.

... 4 = (-1/3)(3) +b

... 4 = -1 + b . . . . . . . simplify

... 5 = b . . . . . . . . . . add 1

Then the equation you want is ...

... y = (-1/3)x + 5

y = [tex]\frac{1}{2}[/tex] x + 2

the equation of a line in slope-intercept form is

y = mx + c (m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 2 ) and (x₂, y₂ ) = (- 4, 0 ) ← points from graph

m = [tex]\frac{0-2}{-4-0}[/tex] = [tex]\frac{-2}{-4}[/tex] = [tex]\frac{1}{2}[/tex]

from the graph the y-intercept = (0, 2 ) → c = 2

y = [tex]\frac{1}{2}[/tex] x + 2 ← is the equation

The equation of the line is [tex]y = \frac{1}{2}x + 2[/tex]

The equation of a line in slope-intercept form is

y = mx + c

Here m is the slope and c is the y-intercept  

Now  

[tex]m = ( y_2 - y_1 ) \div (x_2 - x_1 )[/tex]

Here

[tex](x_1, y_1 )[/tex]= (0, 2 ) and [tex](x_2, y_2 )[/tex] = (- 4, 0 )  

Now  

[tex]m = (0-2) \div (-4-0)\\\\= -2\div -4\\\\= \frac{1}{2}[/tex]

From the graph the y-intercept = (0, 2 ) i.e. c = 2

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Put your number into the half-angle formula and simplify.

[tex]\displaystyle\sin{\frac{\theta}{2}}=\pm\sqrt{\frac{1-\cos{\theta}}{2}}=\sqrt{\frac{1-\frac{1}{3}}{2}}\\\\=\sqrt{\frac{1}{3}}=\sqrt{\frac{3}{9}}\\\\=\frac{\sqrt{3}}{3}[/tex]

The appropriate selection is ...

[tex]A)\quad\dfrac{\sqrt{3}}{3}[/tex]

ANSWER

The correct answer is A

{[tex]x|-5<\:x<\:5[/tex]}

EXPLANATION

[tex]|x|<5[/tex]

This implies that

[tex]x<5\:or\:-x<5[/tex]

We solve the compound inequality to obtain,

[tex]x<5\:or\:x>-5[/tex]

Remember that, dividing through by negative 1 reverses the inequality sign

The solution set is

{[tex]x|-5<\:x<\:5[/tex]}

The sine function is an odd function, so the sine of -30° is the opposite of the sine of 30°.

sin(30°) = 1/2

sin(-30°) = -1/2

The sine of 30° is greater than the sine of -30°.

1 and a half is the correct answer (1 1/2) for the first one, for the second one it is D, and for the third one it is A.

Let's add both of the fractions together. They at 2 slices of pumpkin pie, and 3 slices of pecan pie. The fractions of these is 2/8 and 3/8. Added together, this is 5/8, so I believe this is your answer.

For this one, we can simply multiply the total acres by the cost per acre. 1240*52 is 64,480, so your land is worth a total of $64,480.

For this question, all we need to do is multiply the number of gallons Shelly's car can hold by the price per gallon. 14*3.56 is 49.84, so she'll be spending $49.84 to fill up her tank.

ANSWER

The correct answer is B

EXPLANATION

The first function is

[tex]x^2-2x+y-3=0[/tex]

We make y the subject to obtain;

[tex]y=-x^2+2x+3[/tex]

Let us quickly write this in the vertex form.

[tex]y=-(x^2-2x)+3[/tex]

[tex]y=-(x^2-2x+(-1)^2)+3+(-1)^2[/tex]

[tex]y=-(x-1)^2+4[/tex]

Since the [tex]a[/tex] is negative, the graph opens up.

The vertex is at [tex](1,4)[/tex]

The y-intercept is [tex]-3[/tex]

The x-intercept is found by equating the function to zero.

[tex]-(x-1)^2+4=0[/tex]

[tex]\Rightarrow (x-1)^2=4[/tex]

[tex]\Rightarrow (x-1)=\pm 2[/tex]

[tex]\Rightarrow x=1 \pm2[/tex]

[tex]\Rightarrow x=-1,3[/tex]

With these information we can quickly sketch the graph as shown in the attachment(the red graph).

For the second function,

[tex]x^2+y=0[/tex]

we again make y the subject to obtain,

[tex]y=-x^2[/tex]

This is a basic quadratic function that can be graphed easily. Note that it is also a maximum graph.

From the graph the solution to the two functions is

[tex](-1.5,-2.25)[/tex]

Answer:

B.(–1.5, –2.25)

Step-by-step explanation:

The sum of the given expressions will be 6x-18.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression is (2x−6)+4(x−3). The summation will be calculated as

Sum = (2x-6)+4(x-3)

Sum = (2x-6)+4x-12

Then we combine like terms.

Sum = (2x-6)+4x-12

Sum = 6x-6-12

Sum = 6x-18

Therefore, the sum of the given expressions will be 6x-18.

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#SPJ2

slope = - [tex]\frac{2}{3}[/tex]

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = - 12 into this form

subtract 2x from both sides

3y = - 2x - 12 ( divide all terms by 3 )

y = - [tex]\frac{2}{3}[/tex] x - 4 ← in slope- intercept form

with slope m = - [tex]\frac{2}{3}[/tex]

[tex]\text{The slope-intercept form:}\ y=mx+b\\m-slope,\ b-y-intercept\\\\2x+3y=-12\qquad|\text{subtract 2x from both sides}\\\\3y=-2x-12\qquad|\text{divide both sides by 3}\\\\y=-\dfrac{2}{3}x-4\\\\Answer:\ \boxed{m=-\dfrac{2}{3}}[/tex]

We are given that

point C lies on AB

Let's assume AC=x

we know that

CB=AB-AC

[tex]CB=30-x[/tex]

Point C is 1.5 times farther from point A than from point B

so, we get

[tex]\frac{AC}{CB} =1.5[/tex]

now, we can plug values

[tex]\frac{x}{30-x} =1.5[/tex]

now, we can solve for x

[tex]x=1.5\left(30-x\right)[/tex]

[tex]x=18[/tex]

so, we get

[tex]AC=18[/tex]

now, we can find CB

[tex]CB=30-18[/tex]

[tex]CB=12[/tex]

so, we get

[tex]AC=18[/tex]

[tex]CB=12[/tex]...............Answer

A=h/2(a+b) solver for h

2A=h(a+b)

2A/(a+b)=h   (Solution)

There are a total of 312 cartons or ice cream in total.

A number and its absolute value are not equal when the number is less than zero. Since subtracting 2 makes the number less than zero, we know ...

... the number is a non-negative number less than 2. (0 ≤ n < 2)

The lateral area of the prism is the area of the three rectangles in the middle of the net. (The two triangles are the bases of the prism, which don't count toward lateral area.) The total length of the three rectangular prism faces is (8 +15 +17) cm = 40 cm. The width of those rectangles is 11 cm. The lateral area will be the product of this length and width:

... lateral area = (40 cm)(11 cm) = 440 cm²

Answer:

The answer is B

Step-by-step explanation:

Simple use P.E.M.D.A.S

Parentheses are always first, you add 13+10 then evaluate everything else.

Have a great day.

Answer:

(-1,-6) , (7,0) and (11,3)

Step-by-step explanation:

3x - 4y = 21

4y = 3x - 21

y = 3/4x - 21/4 , the slope(m) of this line is 3/4

The x and y intercepts are (0,-5.25) and (7,0)

Taking a point (-3,3):

Slope(m) = change in y ÷ change in x

Slope = (3 - 0) ÷ (-3 - 7) = -0.3

Since the slope here is not 3/4 then point (-3,3) is not on the line.

Taking a point (-1,-6)

Slope = (-6 - 0 ) ÷ (-1 - 7) = -6/-8 = 3/4

The point (-1,-6) is on the line.

Taking a point (7,0):

This point is the x - intercept and so its on the line.

Taking a point (11,3):

Slope = (3 - 0) ÷ (11 - 7) = 3/4

Therefore the point (11,3) is on the line.

Answer:

wut that dude said is correct i verified it

Step-by-step explanation:

Simplify. Divide the number

300/2 = 150

150 is your answer (it is a whole number, no need to change to improper, unless you want 150/1)

hope this helps

How does the $100 gift card affect the measure of center of the data?

It increases the mean value of the prizes.

It decreases the mean value of the prizes.

It increases the median value of the prizes.

It decreases the median value of the prizes.

Angle BEC is the unmarked angle in the middle of the figure. Its value is the difference between straight angle AED (180°) and the two marked angles, 57° and 33°. That difference is ...

... 180° - 57° -33° = 90°

∠BEC is a right angle.

Answer:

Right angle

Step-by-step explanation:

We are given that

Angle AEB=[tex]57^{\circ}[/tex]

Angle CED=[tex]33^{\circ}[/tex]

We have to find  the classification of angle BEC

We know linear sum =[tex]180^{\circ][/tex]

Angle AEB +Angle BEC+Angle CED=180

Substitute the values then we get

[tex]57+33+\angle BEC=180^{\circ}[/tex]

[tex]90+\angle BEC=180[/tex]

[tex]\angle BEC=180-90[/tex]

[tex]\angle BEC=90^{\circ}[/tex]

Hence, the angle BEC is right angle

Answer:

Step-by-step explanation:

Any equation with a product of variables, or with a variable in an exponent or denominator, is not a linear equation. Here, "product of variables" includes powers and roots—any expression with an exponent other than 1, or a total of exponents other than 1.

The equations x^2 + y = 4 and x/2 - y^3 = 1 are not linear equations because they contain terms with variables raised to powers other than one, whereas - x - y = 2 and x = 5 are linear.

The question involves identifying which equations from the given list are not linear equations. Linear equations are of the form y = mx + b, where m and b are constants. Non-linear equations can include terms with variables raised to powers other than one, variables in the denominator, or variables under a radical.

The given equations are - x - y = 2, x^2 + y = 4, x/2 - y^3 = 1, and x = 5. The second equation, x^2 + y = 4, is not linear because it has a term x squared. The third equation, x/2 - y^3 = 1, is also not linear due to the term y cubed. Both of these equations contain expressions that disqualify them from being linear, as linear equations cannot have variables with exponents other than one. Therefore, these two are examples of a non-linear system of equations.

On the other hand, the first equation - x-y = 2 and the fourth equation, x = 5 are both linear. The first is in the standard linear form after being rearranged, and the fourth represents a vertical line in the xy-plane, which is a special case of a linear equation.

The answer is (-5,-6)

Answer:

Option D is correct.

(-5, -6)

Step-by-step explanation:

Ordered pair states that a pair of number that is locate a point on a coordinate plane i.,e (x, y)

Given the line: [tex]2x-3y = 8[/tex]              .....[1]

Option A:

(12, -73)

Substitute the value of x = 12 and y = -73 in [1] we have;

2(12) - 3(-73) = 8

24 + 219 = 8

243 = 8        False.

Similarly for;

Option B

(-2, 4)

2(-2) - 3(4) = 8

-4 -12 = 8

-20 = 8        False.

Option C

(2, 43)

2(2) - 3(43) = 8

4-129= 8

-125= 8        False.

Option D

(-5, -6)

2(-5) - 3(-6) = 8

-10 +18 = 8

8 = 8      True.

Therefore, only (-5, -6) ordered pair is on the line 2x-3y = 8

because the leading coefficient is positive and the highest degree is odd (9) the function is negative for (-inf, -6). Then it crosses the -6 root to become positive until it crosses again the root -2. (it crosses because both roots have an odd multiplicity). then it touches on root 0 (does not cross due to an even multiplicity there), so function remains negative from -2 till root 4 where it crosses into the positive.

Given the above, only the first choice is a correct statement.

The true statement about the graph is: (a) the graph of the function is positive on [tex]\mathbf{(-6,-2)}[/tex]

The given parameters are:

[tex]\mathbf{Root = -6, Multiplicity = 1}[/tex]

[tex]\mathbf{Root = -2, Multiplicity = 3}[/tex]

[tex]\mathbf{Root = 0, Multiplicity = 2}[/tex]

[tex]\mathbf{Root = 4, Multiplicity = 3}[/tex]

Add up the multiplicities, to calculate the degree of the polynomial function

[tex]\mathbf{Degree = 1 + 3 + 2 + 3}[/tex]

[tex]\mathbf{Degree = 9}[/tex] --- odd number

The interval of the first root is:

[tex]\mathbf{Interval = (-\infty,-6)}[/tex]

The interval of the second root is:

[tex]\mathbf{Interval = (-6,-2)}[/tex]

A polynomial function with an odd degree, and a positive leading coefficient will start with negative values, until it reaches the smallest root, before it switched to positive values.

This means that, the function increases at: [tex]\mathbf{Interval = (-6,-2)}[/tex]

Hence, option (a) is correct.

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Its A i did the test

We are given function F(x) = x^3 +3x^2.

Leading term is the term that has highest power of a variable.

For the given function we have highest power 3 of x.

Therefore, leading term is x^3. We don't have any sign in front of x^3. Therefore, it's a positive leading term.

And degree of the is highest power, that is 3.

Therefore, degree is an odd number.

According to problem,  we need to make the leading term as a negative number.

So, we need to find a rule for end behaviour of the graph with:

Leading coefficent = Negative.

Degree : Odd.

Please note the rule, when leading coefficent a negative number and degree is odd.

x--> + ∞   f(x) ---> - ∞

x--> - ∞   f(x) ---> + ∞

We can see option D has  f(x) ---> - ∞ for x--> + ∞ and  f(x) ---> + ∞ for x--> - ∞.

Answer: graph D

Step-by-step explanation: just took the test

We are given table

Month :         1     2        3         4         5

Shoppers:   50  250   1250   6250  3250

so, we have

first term =50

[tex]a_1=50[/tex]

Second term =250

[tex]a_2=250[/tex]

Third term =1250

[tex]a_3=1250[/tex]

[tex]a_4=6250[/tex]

[tex]a_5=31250[/tex]

now, we can find ratios

[tex]\frac{a_2}{a_1} =\frac{a_3}{a_2}=\frac{a_4}{a_3}=\frac{a_5}{a_4}=5[/tex]

we can see that all ratios are same and 5

so, this is exponential

so, option-D..........Answer

The table below shows the number of shoppers at Jacob's store over a period of five months:  

Month 1 2 3 4 5  

Shoppers 50 250 1,250 6,250 31,250  

Did the number of people at Jacob's store increase linearly or exponentially?

Answer:

D.Exponentially, because the table shows the number of shoppers increases by an equal factor for an equal increase in months

Answer: The equation is of line "b"

Step-by-step explanation:

First we find the slope of the given line by using slope intercept form.

Converting the equation into slope intercept form

[tex] 5y=-2x+10 [/tex]

Divide both side by 5 we get

[tex] y= \frac{-2}{5} x+ 2 [/tex]

On comparing with

[tex] y =mx+c [/tex]

We get slope [tex] m=\frac{-2}{5} [/tex]

as the slope of line is negative therefore the line will be either line "b" or line "d"

As line "b" pass from (0,2)

On putting point [tex] x=0 &y=2[/tex] in given equation we get

[tex] 2(0)+5(2)=0+10=10 [/tex]

Which is equal to RHS of the line

Therefore the given equation is of line "b"

Now putting point (0,-2)

We get [tex] 2(0)+5(-2)=-10 [/tex]

Which is not equal to RHS and therefore line "d" is not the required line

Therefore the given equation is of line "b"

Answer:

Option C

Step-by-step explanation:

A coin has two outcomes Head (H) and tail (T).

So, the number of outcomes when a coin is tossed = 2

A coin has six outcomes [tex]\left \{ 1,2,3,4,5,6 \right \}[/tex]

So, the number of outcomes when a coin is tossed = 6

Therefore, possible outcomes when Jo flips a coin and then rolls a 6-sided die are [tex]\left \{ H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6 \right \}[/tex]

So, the number of possible outcomes = 12

Option C. is correct.

Using the concept of sample space, it is found that the number of possible outcomes in the experiment is given by:

C. 12

The sample space of an experiment is the set that contains all possible outcomes.

In this problem:

The coin and the dice are independent, thus, there are 2 x 6 = 12 possible outcomes, which means that the correct option is:

C. 12

A similar problem is given at https://brainly.com/question/15006554

I believe you only need to know one angle.

For example, if you know angle 1, you can calculate angle 3. Angle 2 = angle 3 and angle 4 = angle 1.

Also, Angle 5= angle 1 and so on...