Answer:
Explanation:
The epithelial tissues cover the body surfaces, forms a lining over the body cavities and hollow organs. These tissues also forms a protective barrier between the external environment and the body.
The epithelial tissues are the tissues which performs various functions. These tissues are composed of cells that are laid close to each other with the cells that lies in the close association with each other. The structure and function of the epithelial cells vary from both upper and lower surfaces. Due to variety in the functions of the epithelial tissues like protection, secretion, cellular transportation, filtration, selective absorption and sensing, these are called as the versatile tissues.
True or False: Once the object hits the water, the forces are balanced and the object will stop. Support your answer with reasoning
Answer:
False
Explanation:
When the object hits the water, it's not adding weight to the object, but is changing the force of the waves in the water. They wouldn't be balanced and this wouldn't determine if the object would stop. However, with more informational variables with precise measurements the answer may alter.
If water in a bath is at 104°F then what is the temperature of the water in degree Celsius?
Your answer is 40 degrees Celsius
104f in celsius is 40c
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance of 2.7 meters. Calculate the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard.A.
0.08 meters
B.
0.16 meters
C.
0.32 meters
D.
1.8 meters
Answer:
vertical distance, s = 0.16 meters
Explanation:
It is given that,
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard.
Dashboard is placed at a distance of 2.7 meters.
Calculating time from velocity and distance i.e. [tex]t=\dfrac{d}{s}=\dfrac{2.7}{15}\ s=0.18\ s[/tex]
Using second equation of motion for finding vertical distance :
[tex]s=ut+0.5gt^2[/tex]
Here, u = 0 (for vertical velocity )
[tex]s=0.5gt^2[/tex]
[tex]s=0.5\times 10\times (0.18)^2[/tex]
s = 0.162 meters
or s = 0.16 meters
Hence, the vertical distance by which the player will miss the target if he throws the dart horizontally, in line with the dartboard is 0.16 meters.
How much force is needed to accelerate a 68 kilogram skier at a rate of 1.2 m/sec^2?
f=ma is newton's second law ...68x1.2=68+2/10x68 = 68+13.6=81.6n
Answer:
81.6N
Explanation:
Force = Mass x Acceleration
Force = 68 x 1.2
Force = 81.6
Units = Newtons
81.6 N
(81.6 Newtons)
If Emily throws the ball at an angle of 30∘ below the horizontal with a speed of 14m/s, how far from the base of the dorm should Allison stand to catch the ball? Assume the vertical distance between where Emily releases the ball and Allison catches it is 4.0m.
To determine how far from the base of the dorm Allison should stand to catch the ball, principles of projectile motion are applied using the known angle, speed, and vertical distance. The time of flight for the vertical motion is calculated first, then used to find the horizontal distance where Allison should be positioned.
Explanation:To solve the problem of where Allison should stand to catch the ball thrown by Emily, we need to apply the principles of projectile motion. The ball is thrown at an angle of 30° below the horizontal with a speed of 14 m/s, and it falls a vertical distance of 4.0 m. We can use these parameters to calculate the time of flight for the vertical motion and then apply that time to the horizontal component of motion to find how far from the base of the dorm Allison should stand to catch the ball.
First, we calculate the time taken for the ball to drop 4.0 m using the equation of motion: s = ut + (1/2)gt², where u is the initial velocity in the vertical direction, g is the acceleration due to gravity (approximated as 9.8 m/s²), and s is the vertical displacement.
Since the vertical component of the initial velocity (u_y) is negative in this case (as the ball is thrown below the horizontal), we must consider u_y = 14sin(-30°) = -7 m/s. The vertical displacement is -4.0 m (downwards). Plugging these values into the equation, we can solve for t.
Once we've found the time t, we then calculate the horizontal distance using the horizontal component of the initial velocity (u_x): u_x = 14cos(30°). The horizontal distance (x) can be found using the equation: x = u_x * t.
Through these calculations, we will be able to determine the distance at which Allison should stand to catch the ball.
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Why is water considered to be a complex compound
Answer:
Water is a simple compound.
Explanation:
Water, from first glance, is a simple compound. This is because it is made up of two atoms - hydrogen and oxygen. This gives the formula:
[tex]H_{2}O[/tex]
In the simple compound, one atom of oxygen is bound to two hydrogen atoms like this:
[tex]H - O - H[/tex]
The bonding in water is hydrogen bonding. This is a bonding that takes place between the oxygen atom and a hydrogen atom of the next water molecule.
This makes the water molecule an interesting molecule.
If the velocity of a car is 45 km/h west, how far can it travel in 0.5 hours?
(45 km/hour west) · (0.5 hour) =
(45 · 0.5) · (km · hour west/hour) =
22.5 km west
why don’t trade winds blow straight toward the equator
Apex
Trade winds near equator blows in curve path instead of straight path. This is because of earth rotation. This effect of earth rotation that cause wind to move in curve motion is called Coriolis effect. These kind of wind blows at the northeast of the North hemisphere and southeast of the South hemisphere. The trade wind are warm and it blows due to rising of hot air from equator.
Final answer:
Trade winds don't blow straight toward the equator because the Coriolis effect causes deflection to the right in the northern hemisphere, forming northeast trade winds, and to the left in the southern hemisphere, forming southeast trade winds.
Explanation:
The trade winds don't blow straight toward the equator due to the influence of the Coriolis effect, which is caused by the rotation of the Earth. In the northern hemisphere, air moving toward the equator is deflected to the right, creating the northeast trade winds. Conversely, in the southern hemisphere, air moving toward the equator is deflected to the left, resulting in the southeast trade winds. These winds converge near the equator in the Intertropical Convergence Zone (ITCZ), leading to very wet conditions and the formation of the world's great rainforests.
Hillary is walking to school at 1.3 m/s. She looks at her watch and realizes she is going to be late. She starts to hurry by increasing her rate by 0.090 m/s squared. What is Hillary's speed after 10 seconds?
initial speed by which Hilary is walking = 1.3 m/s
Now the rate of increase in her speed that is her acceleration is given by
[tex]a = 0.090 m/s^2[/tex]
now we need to find her final speed after t = 10 s
so here we can use the kinematics equation in order to find the final speed
[tex]v_f = v_i + at[/tex]
now plug in all data in the above equation
[tex]v_f = 1.3 + (0.090 * 10)[/tex]
[tex]v_f = 1.3 + 0.90[/tex]
[tex]v_f = 2.2 m/s[/tex]
so here the final speed will be 2.2 m/s after she accelerates
The former Sears Tower in Chicago is 443m tall. Suppose a book is dropped from the top of the building. What would be the book's velocity a point 221m above the ground?
here we can use energy conservation
like initial kinetic + potential energy is always conserved and it will be same at all points
so we can say
[tex]KE_i + PE_i = KE_f + PE_f[/tex]
[tex]\frac{1}{2}mv_i^2 + mgh_1 = \frac{1}{2}mv_f^2 + mgh_2[/tex]
now we can plug in all the given values in it
[tex]v_i = 0[/tex]
[tex]h_1 = 443 m[/tex]
[tex]h_2 = 221 m[/tex]
[tex]\frac{1}{2}m*0 + m*9.8*443 = \frac{1}{2} m*v_f^2 + m*9.8*221[/tex]
now divide whole equation by mass "m"
[tex]9.8*443 = \frac{1}{2} v_f^2 + 9.8*221[/tex]
[tex]2175.6 = \frac{1}{2}v_f^2[/tex]
[tex]v_f = 65.96 m/s[/tex]
so final speed will be 65.96 m/s
Which latitude receives the most direct rays of the sun year round
A. 0 degrees
B.30 degrees
C.60 degrees
D.90 degrees
Zero latitude gets the most direct sun all year around. That's the equator.
The picture you attached has nothing to do with this question.
The Equator (0 degrees latitude) receives the most direct rays of the sun year-round due to being at the midpoint of the Earth's surface. As we move towards poles, the sunlight becomes less direct.
Explanation:The latitude that receives the most direct rays of the sun year-round is 0 degrees, also known as the Equator. The rays of the sun hit the equator directly because it is the midpoint of the Earth's surface. As you move away from the Equator, either towards the North or South Pole (which are 90 degrees latitude), the sun's rays hit the Earth's surface at increasingly oblique angles, resulting in less direct sunlight. Hence, options B, C, and D (30 degrees, 60 degrees, 90 degrees respectively) receive less direct sunlight compared to the Equator (0 degrees).
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Select the correct words from the drop-down menus to complete the sentence. The work of a machine can never exceed the work because uses some of the work.
Answer: The work OUTPUT of a simple machine can never exceed the work INPUT because FRICTION uses some of the work.
Explanation:
This concept is related to ideal machines and efficiency.
Only ideal machines can convert all the work input into useful work (work ouput).
The efficiency is a concept that tells you the proportion of input work that is transformed into output work.
Efficiency = (output work / input work) × 100
Ideal machines, those where friction does not exist, have a 100% efficiency, and so ideal machines convert all the input work into useful output work.
Real machines have a efficiency less than 100%. Friction lowers the efficiency and the work outpu is less than the work input, because friction uses work which is converted, mostly, into heat energy or sound energy.
You push on a large box with 120 N of force, but it doesn’t move. How large is the friction force?
The friction force is equal to 120 N. This is based on Newton's First Law. The friction force balances the pushing force, thus keeping the box stationary.
Explanation:When you push on a large box with 120 N of force and it does not move, it means that the friction force opposing your push is equal to the pushing force. This is based on Newton's First Law of Motion which states that an object in motion tends to stay in motion and an object at rest tends to stay at rest unless acted upon by an unbalanced external force. Friction is the resisting force that occurs between two surfaces in contact when one or both of the surfaces are moved or attempt to move. In this case, the friction force is 120 N because it precisely offsets the applied force, keeping the box stationary.
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What property of the sound wave determine the volume of sound
the amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 10.2 sound C is louder than sound B. hope i helped!
(sorry if wrong)
Pure substances can be classified as blank or compounds
i believe it is element or compound
A truck undergoes two consecutive displacements, the first is 75 km due 30.0 degrees west of north, and the second is 155 km due 60.0 degrees due east of north. What is the total displacement of the truck?
here we need to write the two components of the displacement and then we need to add them
first displacement is given as
[tex]d_1 = 75 km[/tex] 30 degree West of North
[tex]d_1 = - 75 sin30 \hat i + 75 cos 30 \hat j[/tex]
[tex]d_1 = - 37.5 \hat i + 64.9\hat j[/tex]
Other displacement is given as
[tex]d_2 = 155 km[/tex] 60 degree due East of North
[tex]d_2 = 155 sin60 \hat i + 155 cos60 \hat j[/tex]
[tex]d_2 = 134.2 \hat i + 77.5 \hat j[/tex]
now we need to find the net displacement
[tex]d = d_1 + d_2[/tex]
[tex]d = (-37.5 + 134.2)\hat i + (64.9 + 77.5)\hat j[/tex]
[tex]d = 96.7\hat i + 142.4\hat j[/tex]
so it is given as
[tex]d = \sqrt{96.7^2 + 142.4^2}[/tex]
[tex]d = 172.1 km[/tex]
and its direction is given as
[tex]\theta = tan^{-1}\frac{96.7}{142.4} = 34.1 degree[/tex]
so it will displace by 172.1 km at 34.1 Degree East of North
what is apples here in this next thing
Blueberries is the correct answer
The atomic mass of an element is A. the sum of the protons and electrons in one atom of the element. B. twice the number of protons in one atom of the element. C. a ratio based on the mass of a carbon-12 atom. D. a weighted average of the masses of an element’s isotopes.
Answer:imagine Bohr coming up to you and saying i have 2 atoms; it sticks together and becomes a compound.
Explanation:
What causes different colors to appear in the sky?
The different colors in the sky are caused by the scattering of sunlight in Earth's atmosphere. Blue light scatters more efficiently than other colors, resulting in the blue color of the sky.
Explanation:The different colors that appear in the sky are caused by the scattering of sunlight. When sunlight enters Earth's atmosphere, it scatters from the molecules of air. The small size of the air molecules causes blue light to scatter more efficiently than other colors, such as greens, yellows, and reds. Therefore, the blue light is scattered all over the sky, resulting in the blue color of the sky.
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Which of the folllowing properties of matter is independent of its location.
A.Mass
B. Volume
C.Pressure
D.Weight
Im not sure about this one but the one i will go for is a.
A hockey player hits a puck so that it comes to rest in 9 s after sliding 30 m on the ice. Determine (a) the acceleration in terms of ,(4 marks) (b) the initial velocity and acceleration of the puck.(5 marks)
Answer:
a) Acceleration, a = -u/9, where u is the initial velocity
b) Acceleration = 0.741 m/s², Initial velocity = 6.67 m/s
Explanation:
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
a) We have v = 0 m/s, t = 9 s
So, 0 = u + a x 9
Acceleration, a = -u/9, where u is the initial velocity
b) We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
s = 30 m , u = -9a, t =9 s
So, [tex]30= -9a*9+\frac{1}{2} *a*9^2\\ \\ 30=-40.5a\\ \\ a=-0.741m/s^2[/tex]
u = -9a = 6.67 m/s
So acceleration = 0.741 m/s², Initial velocity = 6.67 m/s
Final answer:
The answer explains how to calculate the acceleration of the puck given the distance it traveled and the time taken. It further details how to find the initial velocity of the puck using the acceleration obtained earlier.
Explanation:
A. To determine the acceleration of the puck, we can use the equation:
a = 2x / t^2
Substitute the values given: x = 30m and t = 9s.
b. To find the initial velocity of the puck, we first calculate the acceleration using the formula a = Δv / t, where Δv = final velocity - initial velocity.
Then, knowing the acceleration from part (a), we can calculate the initial velocity using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
If you drive your 1000 kg car from sea level up to the Nu’uanu Pali lookout,which is 366m above sea level, how much will you have increased your car’s potential energy?
Final answer:
The potential energy gained by driving the car from sea level to Nu’uanu Pali lookout is approximately 3,589,260 joules.
Explanation:
To calculate the potential energy gained by driving your car from sea level up to the Nu’uanu Pali lookout, we can use the formula: PE = mgh, where m is the mass of the car, g is the acceleration due to gravity, and h is the change in height. In this case, the mass is 1000 kg, g is approximately 9.81 m/s², and h is 366 m. Plugging in the values, we get:
PE = 1000 kg * 9.81 m/s² * 366 m = 3,589,260 joules
So, driving your car up to the Nu’uanu Pali lookout increases its potential energy by approximately 3,589,260 joules.
a force of 45 N isvexerted on an object, resulting in an acceleration of 5 m/s^2 for the object what will the objects acceleration be if the force doubles
Answer:
the acceleration will be 10 m/s^2
Explanation:
the force applied to an object and the acceleration of the object are directly proportional, as Newton's second law states:
[tex]F=ma[/tex]
where
F is the net force applied to the object
m is the object's mass
a is the object's acceleration
in the first example, a force F=45 N is applied to the object, giving it an acceleration of a=5 m/s^2. Therefore, the mass of the object is
[tex]m=\frac{F}{a}=\frac{45 N}{5 m/s^2}=9 kg[/tex]
In the second example, the force is doubled, so it will be F=90 N. The mass is still m=9 kg, so the acceleration will be
[tex]a=\frac{F}{m}=\frac{90 N}{9 kg}=10 m/s^2[/tex]
what causes a objects to move or stay still? claim and evidence
Any object which is in state or rest is made to change its by applying the external force. An object is made to move or stay still due to its inertia.
What is inertia?Mass is the measure of inertia . Greater the mass, greater will be the inertia.
Inertia is the opposition caused to the motion of an object whether it is still or moving. It is a tendency to do nothing or remain unchanged.
Hence, Inertia causes an object to move or stay still.
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Objects move or stay still based on Newton's first law of motion or the law of inertia, which states that an object will continue its current state of rest or constant motion unless an external force acts upon it.
Explanation:What causes objects to move or stay still can be explained by Newton's first law of motion, also known as the law of inertia. This law states that every object will continue to be in a state of rest or move at a constant speed in a straight line unless it is compelled to change by an outside force. For example, if you slide a book on a table, it eventually stops because of the friction (an outside force) between the book and the table.
Similarly, an object moving in an elliptical path, such as a planet, must be subjected to a constant force that keeps changing its direction. Newton proposed this force to be gravity. So, if you throw a ball (a small scale example), it eventually drops to the ground because of the gravitational pull of the earth.
Therefore, without an external force, a stationary object stays put, and a moving object keeps moving at the same speed and in the same direction.
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Which of the following is NOT an example of a transmutation?
A. Uranium-238 emits an alpha particle forms thorium-234
B. Uranium-238 is bombarded with a neutron to produce uranium-239
C. Potassium-38 emits a beta particle and forms argon-38
D. Plutonium-239 is bombarded with two neutrons to produce americium-241 and a beta particle
The right option is (C).
ExplanationThe potassium-40 is the isotope of potassium which has the half-life of 1.251×109 years to reduce its half quantity. There are rare elements present on earth which follow the two type of beta decay. Potassium-40 is one of them which can decay as beta decay to convert into Ca-40 or electron capture decay to convert into the Ar-40. In this second decay, they also emit gamma rays. So, the right option is (C) which wrong regarding the transmutation.
In the examples given, the transmutation process either involves the emission of particles or the bombardment with neutrons, which leads to a change in the atomic number and transforms the element into a different one. The exception is option C) where Potassium-38's release of a beta particle results in its transformation into Argon-40, not Argon-38 as stated.
Explanation:Transmutation in chemistry refers to the process wherein an atom of one element is changed into an atom of another element through a nuclear reaction. Of the options provided: A) Uranium-238 emitting an alpha particle to form Thorium-234, B) Uranium-238 being bombarded with a neutron to produce Uranium-239, and D) Plutonium-239 bombarded with two neutrons to produce Americium-241 and a beta particle, are all examples of transmutations. These include the emission of particles or bombardment with neutrons leading to change in the atomic number and forming a different element. However, option C) Potassium-38 releasing a beta particle to form Argon-38 is not an example of a transmutation. In this case, Potassium-38 release of a beta particle results in a change in atomic number from 19 to 18, transforming into Argon-40, not Argon-38 as stated.
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a 10kg flowerpot is suspended from the end of a horizontal strut by a cable attached at 30° above the horizontal. If the strut has no mass what is tension in the cable
T = tension force in the cable
m = mass of the flowerpot = 10 kg
θ = angle cable makes with the horizontal = 30 deg
there are horizontal and vertical components of tension force . The vertical component of tension force in cable is in opposite direction of the weight of the flowerpot. hence vertical component of tension balances the weight of flowerpot. so we can write
T Sinθ = mg
inserting the above value
T Sin30 = 10 x 9.8
T(0.5) = 98
T = 98/0.5
T = 196 N
Sound waves
a.
have an irregular vibration pattern.
b.
do not require a medium for transmission.
c.
are a change of pressure that moves through matter.
d.
move at the same rate at any given temperature.
Please select the best answer from the choices provided
Sound waves are a change of pressure that moves through matter. (C)
Amelia is driving her car down a residential street. She approaches a stop sign and applies her brakes. It takes the car a few seconds to come to a complete stop. Which of the following terms best explains why Amelia's car does not stop instantaneously when she applies the brakes?
A.
friction
B.
inertia
C.
magnetism
D.
gravity
When Amelia apply brakes the car will start reducing its speed and then finally stop
So here as per Newton's First law we can say all object continue its state of motion until and unless some unbalanced external force act upon its.
This property is due to inertia of the object which is the property of mass. Here inertia is the property which resist the change in state of motion of an object.
If brakes are applied and an object stops after some time (let say t = 5 s) and on applying brakes other object stop in other time (let say t = 10 s) then if other object took longer time to stop then it means its inertia will be more.
So its all depends on inertia of object that how much time it will take to stop after applying brakes
So correct answer is
B. inertia
Answer:
B
Explanation:
Inertia
Determine what is the angle labeled 6 is called
'6' is the angle of incidence.
'7' is the angle of reflection.
Use Kepler’s laws and the period of the Moon (27.4 d) to determine the period of an artificial satellite orbiting very near the Earth’s surface.
Answer:
[tex]T_2 = 1.40 hours[/tex]
Explanation:
As per kepler's law of time period we know that
square of time period is proportional to the cube of the distance
so here we can say
[tex]\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}[/tex]
so we know that
for moon
[tex]T_1 = 27.4 days[/tex]
[tex]r_1 = 384,400 km[/tex]
[tex]r_2 = 6370 km[/tex]
now from above formula we have
[tex]\frac{27.4^2}{T_2^2} = \frac{384,400^3}{6370^3}[/tex]
[tex]T_2 = 0.058 days[/tex]
[tex]T_2 = 1.40 hours[/tex]
Using Kepler's third law and the period of the Moon, we find that an artificial satellite very close to Earth has a period of approximately 1.41 hours. This involves comparing the orbital radii and periods using the proportional relationship given by Kepler's law. Substituting values and simplifying yields the final period.
To determine the period of an artificial satellite orbiting very near the Earth’s surface using Kepler’s laws, we will use Kepler's third law, which states that the square of the orbital period (T) is proportional to the cube of the average orbital radius (r). Given the following:
The Moon’s orbital period, [tex]T_1[/tex] = 27.3 daysThe Moon’s average orbital radius, [tex]r_1[/tex] = 3.84 × 108 mThe radius of the Earth, rE = 6,380 km = 6.38 × 106 mThe altitude of the artificial satellite above the Earth’s surface = 0 m (since it is very near)Now, add the radius of the Earth to get the orbital radius of the satellite, r2 = rE + 0 = 6.38 × 106 m. According to Kepler’s third law ([tex]T_2[/tex] ∝ [tex]r_3[/tex]), we have:
([tex]T_1[/tex] / [tex]T_2[/tex])2 = ([tex]r_1[/tex] / [tex]r_2[/tex])3Substitute the known values:
(27.3 / [tex]T_2[/tex])2 = (3.84 × 108 m / 6.38 × 106 m)3Simplifying the right side:
(27.3 / [tex]T_2[/tex])2 = (60.19)3(27.3 / [tex]T_2[/tex])2 = 217,000Taking the square root of both sides to solve for [tex]T_2[/tex] :
27.3 / [tex]T_2[/tex] = 465.76[tex]T_2[/tex] = 27.3 / 465.76[tex]T_2[/tex] ≈ 0.0586 daysConverting days to hours (1 day = 24 hours):
[tex]T_2[/tex] ≈ 1.41 hoursTherefore, the period of an artificial satellite orbiting very near the Earth’s surface is approximately 1.41 hours.