factor the following polynomial completely 30y^6+25y^5-10y^4

Answers

Answer 1
5y^4 * (6y^2 + 5y-2)

Related Questions

MEDAL!
This Chinese painting is composed small cliffs in the background and a small building with trees in the foreground. This composition reflects what Taoist and Buddhists principle or philosophy?
a) simplicity
b) perseverance
c) harmony
or...
d) balance

btw- I know this is in the wrong section but no one was answering it in the art history section

Answers

This Chinese painting represents the Taoist and Buddhists principle of balance. People who practice Taoism and Buddhism are more attuned to balance and synchronized energy. Social influence and mental distortions are not present. The natural pulse of the universe is all around.

PLEASE HELP ASAP
EXTRA POINTS
Sheila places a 54 square inch photo behind a 12-inch-by-12-inch piece of matting.

The photograph is positioned so that the matting is twice as wide at the top and bottom as the sides.

Write an equation for the area of the photo in terms of x.

Answers

1. The area of the photograph is:
 
 A=LxW
 
 A is the area of the photograph (A=54 in²).
 L is the lenght of the photograph (L=12-4x).
 W is the widht of the photograph (W=12-2x)
 
 2. When you substitute these values into the formula A=LxW, you obtain:
 
 A=LxW
 54=(12-4x)(12-2x)
 
 3. When you apply the distributive property, you have:
 
 54=144-24x-48x+8x²
 8x²-72x+144-54=0
 
 4. Finally, you obtain a quadratic equation for the area of the photo:
 
 8x²-72x+90=0
 
 5. Therefore, the answer is:
 
 8x²-72x+90=0

need help so much ...

Answers

If this die (singular -- plural "dice"!) were the ordinary kind you find in board games,  it would be a six-sided cube and all the faces would be equally likely to come up when the die is rolled. The die would be "fair."

The die in this problem is not fair.  The sides are coming up with frequencies that are far from being equal. In an actual experiment with a fair die, you would expect each face to come up a NEARLY equal number of times. You would not expect the frequencies to be so different that one of them is 20 and another one is 2.

What is the circumference of a circle with a radius of 6.1 centimeters? Enter your answer as a decimal in the box. Use 3.14 for pi. Round your answer to the nearest tenth. cm

Answers

We must use a certain formula to find the circumference. The formula for circumference of a circle is:

C = 2 * pi × r

Substitute:

C = 3.14 × 6.1 × 2

C = 38.303

Round to the nearest tenth:

38.3.

ANSWER:

The circumference of the circle is about 38.3 centimetres.

It is 38.308 or 38.3
:D

Write the quadratic equation whose roots are −4 and 3 , and whose leading coefficient is 1 .

Answers

we know that
the roots are
x=-4
x=3
leading coefficient=1 
therefore
(1)*(x+4)*(x-3)=0-----------------> x²-3x+4x-12=0
 x²+x-12=0

the answer is 
 x²+x-12=0

Final answer:

To write a quadratic equation with roots −4 and 3 and a leading coefficient of 1, we start with the factored form (x - root1)(x - root2) = 0, substitute the given roots, and simplify to x² + x - 12 = 0.

Explanation:

The question asks us to write the quadratic equation whose roots are −4 and 3, and whose leading coefficient is 1. To find a quadratic equation given its roots, we can use the factored form of a quadratic equation, which is (x - root1)(x - root2) = 0, where root1 and root2 are the roots of the equation.

Given that the roots are −4 and 3, we substitute these values into the equation to get (x - (−4))(x - 3) = 0. Simplifying this, we first eliminate the double negative to get (x + 4)(x - 3) = 0. Multiplying these two binomials gives us the expanded form, which is x² + x - 12 = 0. This is the quadratic equation with roots −4 and 3, and a leading coefficient of 1.

Use the Remainder Theorem to find the remainder: (–6x3 + 3x2 – 4) ÷ (2x – 3).

23

-17.5

-4.4444444...

-0.8888888...

Answers

we have that
(–6x³ + 3x² – 4) ÷ (2x – 3)
----------------------║--------------------------
   +6x³+9x²              -3x²+6x+9
---------------------
12x²-4
-------------------
-12x²+18x
-------------------
18x-4
-----------------
-18x+27
----------------
23-----------------> the remainder

the answer is 23

The remainder obtained when we carry out the operation (-6x³ + 3x² - 4) ÷ (2x - 3) is -17.5 (2nd option)

How do i determine the remainder?

The following data were obtained from the question:

Expression = (-6x³ + 3x² - 4) ÷ (2x - 3)Remainder =?

Using the remainder theorem, we can obtain the remainder as illustrated below:

Let

f(x) = -6x³ + 3x² - 4

2x - 3 = 0

From 2x - 3 = 0, make x the subject as shown below:

2x - 3 = 0

x = 3/2

Substitute the value of x into f(x). We have:

f(x) = -6x³ + 3x² - 4

f(3/2) = -6(3/2)³ + 3(3/2)² - 4

= -6(27/8) + 3(9/4) - 4

= -20.25 + 6.75 - 4

= -17.5

Thus, we can conclude that the remainder obtained when (-6x³ + 3x² - 4) is divided by (2x - 3) is -17.5 (2nd option)

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A car travels 3 times around a traffic circle whose radius is 80 feet. What is the distance the car will travel? Use 3.14 for π . Enter your answer in the box. ft

Answers

Answer : Distance will be 1507.2 feet .

Explanation :

Since we have given that

Radius of circle = 80 feet

So,

Circumference of circle is given by

[tex]2\pi r=2\times 3.14\times 80=502.4 \text{ feet}[/tex]

Since , a car travels 3 times around a traffic circle.

So,

[tex]\text{ Distance covered by the car will travel}= 3\times 502.4= 1507.2 \text{ feet }[/tex]

So, Distance will be 1507.2 feet .

Write the first five terms of a sequence. Don’t make your sequence too simple. Write both an explicit formula and a recursive formula for a general term in the sequence. Explain in detail how you found both formulas.

Answers

Answer: The answer is 5, 10, 20, 40 and 80.

Step-by-step explanation:  We are to write the first five terms of a sequence, along with the explicit and recursive formula for the general term of the sequence.

Let the first five terms of a sequence be  5, 10, 20, 40 and 80. These terms are taken from a geometric sequence with first term [tex]a_1 5[/tex] and common ratio [tex]r=2.[/tex]

Therefore, we have

[tex]a_2=a_1\times r,\\\\a_3=a_2\times r,\ldots[/tex]

Therefore, the recursive formula is

[tex]a_{n+1}=2a_n,~~a_1=5.[/tex]

And explicit formula is

[tex]a_n=a_1r^{n-1}.[/tex]

Answer:

Let the first five terms of a sequence be, 4,8,12,20,24

Ok, let me explain the meaning of term explicit and Recursive formula.

Explicit formula ,is the general formula to find any  term of the sequence.

And, Recursive formula, is the method by which, we can find the nth term of the sequence if (n-1)th term of the sequence is known.

So,the explicit formula for the sequence is,

y = 4 n, where , n is any natural number.

And the recursive formula is .

y = 4 (n-1), with the help of (n-1)th term we can find nth term.

First term =4=4 × 1

Second term =8 =4 × 2

Third term =12=4×3

Fourth term =16 =4 × 4

.....................

...........................

.................................

(n-1) th term =4 × (n-1)

nth term =4 × n

Applying the simple procedure by looking at the first , second and the way the next term goes , the general and recursive formula is obtained.

As, you said you don't want simpler sequence

Consider the first five terms of the sequence, 0, 3,8,15, 24.

Explicit formula =n² + 2 n

Recursive formula=(n-1)²+2(n-1)

If,you will look at the sequence, it is neither Arithmetic nor geometric .

First term =0=0²+0×0

Second term =3=1+2=1²+2 × 1

Third term =8=4+4=2²+2×2

Fourth term =15=9+6=3²+2×3

Fifth term =24=16 +8=4²+2×4

So, Explicit formula= n²+ 2 n, where n is a whole number.

If a < 0 and b > 0, then the point (a, b) is in Quadrant A) I. B) II. C) III. D) IV.

Answers

Answer:

The actual answer is D

The point (a, b) lies in the second quadrant. Then the correct option is B.

What is coordinate geometry?

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.

If a < 0 and b > 0.

Then the point (a, b) is in Quadrant will be given as,

If a > 0 and b > 0, then the points is in first quadrant.If a < 0 and b > 0, then the points is in second quadrant.If a < 0 and b < 0, then the points is in third quadrant.If a > 0 and b < 0, then the points is in fourth quadrant.

Thus, the point (a, b) lies in the second quadrant.

Then the correct option is B.

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Look at the data in the table below

X Y

4. 9

12. 28

7. 14

9. 20

5. 9

12. 30

10. 22


Which graph shows the best fit for this data

Answers

First Graph!
I hope this helps.

Check my answers? GIving medal:

7. What is the slope of the line that passes throught the pair of points (1, 7) and (10, 1)?

a. 3/2
b. -2/3
c. -3/2
d. 2/3 <--

8. What is the slope of the line that passes through the points (-5.5, 6.1) and (-2.5, 3.1)?

a. -1
b. 1
c. -3 <--
d. d

9. what is the slope of the line that passes through the pair of points (-7/3, -3) and (-5, 5/2)?

a. 6/22 <--
b. -6/22
c. 22/6
d. -22/6,

Answers

Slope is calculate by dividing the change in y-values by the change in x-values between a pair of points. For 7: (7-1)/(1-10) = 6/-9 = -2/3 For 8: (6.1-3.1)/(-5.5 - -2.5) = 3/-3 = -1 For 9: (5/2 - -3) / (-5 - -7/3) = 11/2 / -8/3 = -33/16. This is not an answer option, so double check the problem.

Number seven  Is B. -2/3

Which foundation drawing matches this orthographic drawing? ( just tell me what picture) 

Answers

The picture with a 3 by 2 square, the middle one uploaded. Orthographic drawings are two-dimensional representations of a three-dimensional figure from different viewing points. This shape would make a two by three by six unit figure.

What is the area of the composite figure whose vertices have the following coordinates? (−1, 5) , (3, 5) , (7, 3) , (3, 0) , (−1, 1)

Answers

Answer:

28

Step-by-step explanation:

Square: 4 * 4 = 16

Small Triangle: 1 * 4 = 4  / 2 = 2

Large Triangle: 5 * 4 = 20  / 2 = 10

16 + 2 + 10 = 28

An inscribed angle has a measure of 48°. Determine the measure of the intercepted arc.
24° 48° 72° 96°

Answers

An inscribed angle has a measure of 1/2 of the intercepting arc.  Since our angle is 48°, we can set up the equation [tex]48=\frac{1}{2}x[/tex] to represent this.  Divide both sides by 1/2:
[tex]\frac{48}{\frac{1}{2}}=\frac{\frac{1}{2}x}{\frac{1}{2}} \\ 48 \div \frac{1}{2} = x \\ \frac{48}{1} \div \frac{1}{2} = x \\ \frac{48}{1}*\frac{2}{1} = x \\ \frac{96}{1}=x \\ 96=x[/tex]
The measure of the intercepted arc is 96°.

solve for t. use the quadratic formula.

d=−16t^2+12t

Answers

Answer:

[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{3+\sqrt{9+4d}}{8}[/tex]

Step-by-step explanation:

Given: d = -16t² + 12t

To find: t using quadratic formula

If we have quadratic equation in form ax² + bx + c = 0

then, by quadratic formula we have

[tex]x\,=\,\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Rewrite the given equation,

-16t² + 12t - d = 0

from this equation we have,

a = -16 , b = 12 , c = d

now using quadratic formula we get,

[tex]t\,=\,\frac{-12\pm\sqrt{12^2-4\times(-16)\times d}}{2\times(-16)}[/tex]

[tex]t\,=\,\frac{-12\pm\sqrt{144+64d}}{-32}[/tex]

[tex]t\,=\,\frac{-12\pm\sqrt{16(9+4d)}}{-32}[/tex]

[tex]t\,=\,\frac{-12\pm4\sqrt{9+4d}}{-32}[/tex]

[tex]t\,=\,\frac{4(-3\pm\sqrt{9+4d})}{-32}[/tex]

[tex]t\,=\,\frac{-3\pm\sqrt{9+4d}}{-8}[/tex]

[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:,\:\:\frac{-3-\sqrt{9+4d}}{-8}[/tex]

[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{-(3+\sqrt{9+4d})}{-8}[/tex]

[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{3+\sqrt{9+4d}}{8}[/tex]

Therefore, [tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{3+\sqrt{9+4d}}{8}[/tex]

Answer:

[tex]\frac{3-\sqrt{9-d}} {8}\text{ or }t=\frac{3+\sqrt{9-d}} {8}[/tex]

Step-by-step explanation:

Here, the given expression,

[tex]d= -16t^2+12t[/tex]

[tex]\implies -16x^2+12t-d=0[/tex] ------(1)

Since, if a quadratic equation is,

[tex]ax^2+bx+c=0[/tex] ------(2)

By using quadratic formula,

We can write,

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

By comparing equation (1) and (2),

We get, a = -16, b = 12, c = -d,

[tex]t=\frac{-12\pm \sqrt{12^2-4\times -16\times -d}}{2\times -16}[/tex]

[tex]t = \frac{-12\pm \sqrt{16\times 9-16\times d}}{-32}[/tex]

[tex]t = \frac{-12\pm \sqrt{16}\times \sqrt{9-d}} {-32}[/tex]

[tex]t = \frac{-12\pm 4\sqrt{9-d}} {-32}[/tex]

[tex]t = \frac{4(-3\pm \sqrt{9-d})} {4(-8)}[/tex]

[tex]t = \frac{-3\pm \sqrt{9-d}} {-8}[/tex]

[tex]t = \frac{-3+\sqrt{9-d}} {-8}\text{ or }t=\frac{-3-\sqrt{9-d}} {-8}[/tex]

[tex]\implies t = \frac{3-\sqrt{9-d}} {8}\text{ or }t=\frac{3+\sqrt{9-d}} {8}[/tex]

Which is the required solution.

The function graphed approximates the height of an acorn, in meters, x seconds after it falls from a tree.

After about how many seconds is the acorn 5 m above the ground?

Answers

For this case, the first thing to do is observe the vertical axis.
 We look for a height of 5 meters on the vertical axis.
 When finding the height of 5 meters we must observe for what time value this height belongs.
 For this, we observe the horizontal axis.
 The value of time is approximately:
 t = 1.7 seconds
 Answer:
 
t = 1.7 seconds
 
option 3

The equation of the parabola is y = – 5x² + 20. The time when an acorn is 5 m above the ground in 1.7 seconds. Then the correct option is C.

What is the parabola?

It is the locus of a point that moves so that it is always the same distance from a non-movable point and a given line. The non-movable point is called focus and the non-movable line is called the directrix.

The function graphed approximates the height of an acorn, in meters, x seconds after it falls from a tree.

We know that the equation of the parabola will be given as

y = a(x - h)² + k

where (h, k) is the vertex of the parabola and a is the constant.

We have

(h, k) = (0, 20)

Then

y = ax² + 20

The parabola is passing through (2, 0), then we have

0 = 4a + 20

a = -5

Then we have

y = – 5x² + 20

The time in seconds when the acorn is 5 m above the ground.

–5x² + 20 = 5

       –5x² = –15

             x = 1.7

More about the parabola link is given below.

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A square is cut out of a circle whose diameter is approximately 14 feet. What is the approximate area of the remaining portion of the circle in square feet?

Answers

   see the attached figure to better understand the problem

we know that
the side of square=2*[r*√2/2]=r*√2
r=14 ft
the side of square=14*√2=19.80 ft

[area of the remaining portion of the circle]=[ area of a circle]-[area of a square]

[area of a square]=(14√2)²=392 ft²
[ area of a circle]=pi*14²=615.75 ft²
therefore
[area of the remaining portion of the circle]=615.75-392=223.75 ft²

the answer is 223.75 ft²

A square is cut from a circle with a 14-foot diameter. Remaining circle area ≈ 53.86 sq ft here nearest round off option is c. 50 square feet.

To find the area of the remaining portion of the circle after a square with a side of 10 feet is cut out,

Find the area of the square:

Area of square

= side × side

= 10 feet × 10 feet

= 100 square feet

Find the radius of the circle:

The diameter is approximately 14 feet, so the radius is half of that:

Radius = 14 feet / 2 = 7 feet

Find the area of the entire circle:

Area of circle = π × radius²

Area of circle

= π × (7 feet)²

≈ 153.86 square feet (using π ≈ 3.14)

Subtract the area of the square from the area of the circle to find the remaining portion:

Remaining area = Area of circle - Area of square

Remaining area

≈ 153.86 square feet - 100 square feet

≈ 53.86 square feet

Therefore, the approximate area of the remaining portion of the circle is approximately 53.86 square feet nearest option is c. 50 square feet.

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The above question is incomplete , the complete question is:

A square is cut out of a circle whose diameter is approximately 14 feet. What is the approximate area of the remaining portion of the circle in square feet?

Attached figure

WILL GIVE A BRAINLESTTTT

What is the solution of 3x+8/x-4 >= 0

Answers

Solution: (-Infinite, -8/3] U (4, Infinite)

Using that a fraction is greater than or equal to zero when the numerator and denominator have the same sign:
a/b>=0. Then we have two cases:
Case 1) If the numerator is positive, the denominator must be positive too (at the same time):
if a>=0 ∩ b>0

Or (U)

Case 2) If the numerator is negative, the denominator must be negative too (at the same time):
if a<=0 ∩ b<0

In this case a=3x+8 and b=x-4, then:

Case 1):
if 3x+8>=0 ∩ x-4>0
Solving for x:
3x+8-8>=0-8 ∩ x-4+4>0+4
3x>=-8 ∩ x>4
3x/3>=-8/3 ∩ x>4
x>=-8/3 ∩ x>4
Solution Case 1: x>4 = (4, Infinite)

Case 2):
if 3x+8<=0 ∩ x-4<0
Solving for x:
3x+8-8<=0-8 ∩ x-4+4<0+4
3x<=-8 ∩ x<4
3x/3<=-8/3 ∩ x<4
x<=-8/3 ∩ x<4
Solution Case 2: x<=-8/3 = (-Infinite, -8/3]

Solution= Solution Case 1 U Solution Case 2
Solution = (4, Infinite) U (-Infinite, -8/3]
Solution: (-Infinite, -8/3] U (4, Infinite)

Answer:

The inequality is given to be :

[tex]\frac{3x+8}{x-4}\geq 0[/tex]

The inequality will be greater than or equal to 0 if and only if both the numerator and denominator of the left hand side will have same sign either both positive or both negative.

CASE 1 : Both positive

3x + 8 ≥ 0

⇒ 3x ≥ -8

[tex]x\geq \frac{-8}{3}[/tex]

Also, x - 4 ≥ 0

⇒ x ≥ 4

Now, Taking common points of both the values of x

⇒ x ∈ [4, ∞)

CASE 2 :  Both are negative

3x + 8 ≤ 0

⇒ 3x ≤ -8

[tex]x\leq \frac{-8}{3}[/tex]

Also, x - 4 ≤ 0

⇒ x ≤ 4

So, Taking common points of both the values of x we have,

[tex]x=(-\infty,-\frac{8}{3}][/tex]

So, The solution of the equation will be the union of both the two solutions

So, Solution is given by :

[tex]x=(-\infty,-\frac{8}{3}]\:U\:[4,\infty)[/tex]

Which quotient is equivalent to the mixed number
      2
2----------                  = 
       3 
                                              answer in fractions

Answers

To answer this question you will convert the mixed number into an improper fraction. To do this you have to understand that The two wholes in the mix number each equal 3/3. This would give you 6/3 for the two wholes. Add the 6/3 to the 2/3 that are there in the fraction, and you will have 8/3. the quotient(answer to a division problem) is 8/3 as a fraction.

Final answer:

To convert 2 2/3 to an improper fraction, multiply the whole number by the denominator and add the numerator, resulting in 8/3. The question lacks details to provide another specific quotient to compare this with. In dividing fractions, multiplication by the reciprocal is used to find equivalent quotients.

Explanation:

To find which quotient is equivalent to the mixed number 2 2/3, we must first convert the mixed number to an improper fraction. A mixed number is composed of a whole number and a fraction, which can be converted into an improper fraction by multiplying the denominator by the whole number and then adding the numerator to this product.

For the mixed number 2 2/3, we multiply the whole number 2 by the denominator 3, giving us 6, and then add the numerator 2, resulting in 8. Therefore, 2 2/3 as an improper fraction is 8/3.

However, without context, it's unclear what other quotient we are being asked to compare with the mixed number 2 2/3. Quotients can refer to the result of any division. Nonetheless, in contexts of dividing fractions, we use the multiplication of the inverse to find equivalent quotients. For example, if dividing by 3/1 (which is the same as dividing by 3), we would multiply by its reciprocal, 1/3.

In cases of conversion factors, we could use a factor that equals 1 to convert units without changing the value. For instance, 1 m / 100 cm is a conversion factor that equals 1, allowing us to convert meters to centimeters without changing the quantity.

Remember, multiplication and division in fractions can be seen as interconnected operations, where dividing by a number is the same as multiplying by its reciprocal.

Dominik paid three-quarters of a dollar for a newspaper. Which amount is equivalent to the cost of the newspaper?

Answers

The answer is 75 cents

if you received an annual salary of 33500 paid monthly what would your gross pay be each pay period

Answers

Come buddy you got this , Just divide 33500 / 12 Months = 2,791.66667

A new car is purchased for 20700 dollars. The value of the car depreciates at 13.75% per year. What will the value of the car be, to the nearest cent, after 12 years?

Answers

Answer:

USD 3,508.16

Step-by-step explanation:

Hello

Let´s see what happens the first year when the car depreciates 13.75% of 20700 USD

[tex]depreciation=20700*\frac{13.75}{100} =2846.25 USD\\[/tex]

at the end of the first year the car will have a price of 20700-2486.25=17853.75 USD,  and this will be the price at the beginning of the second year.

completing the data for the 12 years with the help of excel you get

                                          depreciation           New Value

end of year 1  USD 20,700.00   USD 2,846.25   USD 17,853.75  

end of year 2  USD 17,853.75   USD 2,454.89   USD 15,398.86  

end of year 3  USD 15,398.86   USD 2,117.34   USD 13,281.52  

end of year 4  USD 13,281.52   USD 1,826.21   USD 11,455.31  

end of year 5  USD 11,455.31   USD 1,575.10   USD 9,880.20  

end of year 6  USD 9,880.20   USD 1,358.53   USD 8,521.68  

end of year 7  USD 8,521.68   USD 1,171.73            USD 7,349.94  

end of year 8  USD 7,349.94   USD 1,010.62   USD 6,339.33  

end of year 9  USD 6,339.33   USD 871.66           USD 5,467.67  

end of year 10 USD 5,467.67   USD 751.80       USD 4,715.87  

end of year 11  USD 4,715.87   USD 648.43     USD 4,067.43  

end of year 12 USD 4,067.43   USD 559.27   USD 3,508.16

after 12 years the car will ha a value of USD 3508.16

you can verify this by applying the formula

[tex]v_{2} =v_{1} (1-\frac{depreciatoin}{100} )^{n} \\\\v_{2} =20700 (1-\frac{13.75}{100} )^{12} \\v_{2} = 20700*0.1694\\v_{2} = 3508.16 USD[/tex].

Have a great day.

Final answer:

The value of a new car, originally priced at $20,700 and depreciating at 13.75% per year will be approximately $1446.63 after 12 years. This is calculated using a compound interest formula with a negative rate.

Explanation:

In order to solve this, we are going to use the formula for compound interest. Although we're actually dealing with depreciation, the calculation is the same as for interest, we just use a negative rate. The formula is P(t) = P0 * (1 + r) ^t, where P(t) is the value of the car after time t, P0 is the initial price of the car, r is the rate of depreciation, and t is time.

Here P0 = $20,700, r = -13.75% = -0.1375 (remember to convert rate from percentage to a proportion), and t = 12 years.

Substituting these values into the formula, we get: P(t) = 20700 * (1 - 0.1375)^12. Using a calculator, the value of the car after 12 years, to the nearest cent, is approximately $1446.63.

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Find the area of the given triangle. Round the answer to the nearest tenth.


A.
7.9 square units
B.
149.4 square units
C.
2,055.6 square units
D.
2,071.8 square units

Answers

Using Heron's formula:
A = √(p(p-a)(p-b)(p-c)) where a,b,c are the sides of the triangle and p is half the perimeter.
The answer is B. 149.4 square units.

Answer:

B) Area of triangle =  149.4 square units.

Step-by-step explanation:

Given : A triangle with sides 16 , 19, 27 .

To find : Area of a triangle.

Solution : We have given that triangle with sides 16 , 19, 27 .

Using heron's formula :

Area of triangle:  [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex].

Where, s = [tex]\frac{a+b+c}{2}[/tex] and a,b,c are sides of triangle.

Then s = [tex]\frac{16+19+27}{2}[/tex].

s = 31 units.

Area of triangle =  [tex]\sqrt{31(31-16)(31-19)(31-27)}[/tex].

Area of triangle =  [tex]\sqrt{31(15)(12)(4)}[/tex].

Area of triangle =  [tex]\sqrt{22320)}[/tex].

Area of triangle =  149.39 square units.

Area of triangle =  149.4 square units. ( nearest tenth)

Therefore, B) Area of triangle =  149.4 square units.

***mathtest timed***
Given the data set for the length of time a person has been jogging and the person's speed, hypothesize a relationship between the variables.

A) I would expect the data to be positively correlated.
B)I would expect the data to be negatively correlated.
C) I would expect no correlation.
D) There is not enough information to determine correlation.

Answers

The answer is option A

PLEASE HELP ME ASAP 40 POINTS AND BRAINLIEST SHOW WORK


Find the variables and the lengths of the sides of this kite

Answers

X = 7 
Y = 16

Since we know that the bottom two sides are congruent we can make an equation to solve for that X first [2x + 5 = x + 12] .  (since we cannot make an equation with the two congruent sides at the top because there are different variables). 
Now that we've solved for X which is 7, we can plug it into the top equation [y - 4 = x + 5] which would simplify to [ y - 4 = 12] which would give us 16 for Y

If the expected adult of a 2 week old puppy is 20 pounds how many grams per day should they gain?

Answers

That will be 20-25 grams

A $250,000 home loan is used to purchase a house. The loan is for 30 years and has a 5.4% APR. Use the amortization formula to determine the amount of the monthly payments.

Answers

[tex]\bf ~~~~~~~~~~~~ \textit{Amortized Loan Value} \\\\ pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right] \\\\\\ ~~~~~~ \begin{cases} P= \begin{array}{llll} \textit{original amount deposited}\\ \end{array}\to &250000\\ pymt=\textit{periodic payments}\\ r=rate\to 5.4\%\to \frac{5.4}{100}\to &0.054\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{since the payments are}\\ \textit{monthly, then twelve} \end{array}\to &12\\ t=years\to &30 \end{cases} [/tex]

[tex]\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right] \\\\\\ pymt=250000\left[ \cfrac{0.0045}{1-\left( 1.0045\right)^{-360}} \right] \\\\\\ pymt\approx 250000\left[ \cfrac{0.0045}{0.80138080852472389274} \right][/tex]

In a parking lot of 240 red and blue cars, the ratio of red cars to blue cars is 3 : 5.

How many red cars are in the parking lot?

Answers

3+5 = 8

240/8 = 30

30*3 = 90 red cars


An ellipse has vertices along the major axis at (0, 1) and (0, −9). The foci of the ellipse are located at (0, −1) and (0, −7). The equation of the ellipse is in the form below.

Answers

so, with those points provided, notice the vertices are lying along the y-axis, check the picture below, thus is a vertical ellipse.

now, the center is half-way between the vertices, therefore it'd be at 0, -4, like in the picture in red.

the distance from the center to either foci, is "c", and that's c = 3.

the "a" component of the major axis is 5 units, now let's find the "b" component,

[tex]\bf \textit{ellipse, vertical major axis} \\\\ \cfrac{(x- h)^2}{ b^2}+\cfrac{(y- k)^2}{ a^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h, k\pm a)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2- b ^2} \end{cases}\\\\ -------------------------------[/tex]

[tex]\bf \begin{cases} a=5\\ c=3 \end{cases}\implies c=\sqrt{a^2-b^2}\implies c^2=a^2-b^2\implies b^2=a^2-c^2 \\\\\\ b=\sqrt{a^2-c^2}\implies b=\sqrt{5^2-3^2}\implies b=4\\\\ -------------------------------\\\\ \begin{cases} h=0\\ k=-4\\ a=5\\ b=4 \end{cases}\implies \cfrac{(x- 0)^2}{ 4^2}+\cfrac{[y-(-4)]^2}{ 5^2}=1 \\\\\\ \cfrac{(x- 0)^2}{ 16}+\cfrac{(y+4)^2}{25}=1[/tex]

The equation of the ellipse is required.

The required equation is [tex]\dfrac{x^2}{16}+\dfrac{(y+4)^2}{25}=1[/tex]

It can be see that the major axis is parallel to the y axis.

The major axis points are

[tex](h,k+a)=(0,1)[/tex]

[tex](h,k-a)=(0,-9)[/tex]

[tex]k+a=1[/tex]

[tex]k-a=-9[/tex]

Subtracting the equations

[tex]2a=10\\\Rightarrow a=5[/tex]

The foci are

[tex](h,k+c)=(0,-1)[/tex]

[tex](h,k-c)=(0,-7)[/tex]

[tex]k+c=-1[/tex]

[tex]k-c=-7[/tex]

Subtracting the equations

[tex]2c=6\\\Rightarrow c=3[/tex]

[tex]k+c=-1\\\Rightarrow k=-1-c\\\Rightarrow k=-1-3\\\Rightarrow k=-4[/tex]

Foci is given by

[tex]c^2=a^2-b^2\\\Rightarrow b=\sqrt{a^2-c^2}\\\Rightarrow b=\sqrt{5^2-3^2}=4[/tex]

The equation is

[tex]\dfrac{(x-h)^2}{b^2}+\dfrac{(x-k)^2}{a^2}=1\\\Rightarrow \dfrac{(x-0)^2}{4^2}+\dfrac{(y+4)^2}{5^2}=1\\\Rightarrow \dfrac{x^2}{16}+\dfrac{(y+4)^2}{25}=1[/tex]

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Bill and Greg are walking in opposite directions with speeds of 45 and 75 feet per minute. When they started, the distance between them was 20 feet. What will be the distance between them in 2.5 min?

Answers

Bill moves at 45 feet per minute and Greg 75 per minute and starts with a constant of 20 feet from them.

Let X be the number of minutes

Bill*Minutes +Greg*Minutes +20 = total distnce between

45x + 75x +20 = d

Plug in 2.5 for both values of x

45(2.5) + 75(2.5) + 20 =d

Multiply values by 2.5

112.5 + 165 + 20 = d

add together 

Distance = 297.5 feet apart




Answer:

320 ft

Step-by-step explanation:

I'm not sure how the other person was awarded brainliest answer because that answer is pretty far off. But the work was good just they messed up. Also kinda sad he is a brainly teacher and still has incorrect answers.

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