find and list the slope and y-intercept of the equation below. -2y=6(2x-2)

Answers

Answer 1

[tex]\text{Solve the equation to make it into slope intercept form}\\\\\text{Slope intercept form: y = mx + b}\\\\\text{Solve:}\\\\-2y=6(2x-2)\\\\\text{Distribute the 6 to the variables inside the parenthesis}\\\\-2y=12x-12\\\\\text{Divide both sides by -2}\\\\y=-6x+6\\\\\text{The slope would be -6 and the y intercept would be 6}\\\\\boxed{\text{Slope: -6 y-intercept: 6}}[/tex]


Related Questions

Bryce reads in the latest issue of Pigskin Roundup that the average number of rushing yards per game by NCAA Division II starting running backs is 50 with a standard deviation of 8 yards. If the number of yards per game (X) is normally distributed, what is the probability that a randomly selected running back has 64 or fewer rushing yards

Answers

Answer:

0.9599 is the probability that a randomly selected running back has 64 or fewer rushing yards.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50

Standard Deviation, σ = 8

We are given that the distribution of number of rushing yards per game is a bell shaped distribution that is a normal distribution.

Formula:

[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]

P(running back has 64 or fewer rushing yards)

[tex]P( x \leq 64) = P( z \leq \displaystyle\frac{64 - 50}{8}) = P(z \leq 1.75)[/tex]

Calculation the value from standard normal z table, we have,  

[tex]P(x \leq 64) = 0.9599[/tex]

0.9599 is the probability that a randomly selected running back has 64 or fewer rushing yards.

i need to find the length

Answers

Answer: I am pretty sure it is 7

Step-by-step explanation:

the smaller one is to smaller than the bigger one so you would just add two to the 5

Answer:

7.5

Step-by-step explanation:

The triangles are proportional, so 6/4=x/5

1.5=x/5

x=1.5*5=7.5

1 of 6
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Peter rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total of 11.

Answers

Answer:

1/18

Step-by-step explanation:

Total 11: (5,6) (6,5)

2/36

1/18

A number that is 12 times greater than -4

Answers

Answer:

My answer is not correct, do not read

Solve equation by using the quadratic formula.
8x^2+5x=3



Help plzzz​

Answers

Answer:

x=−1,  3/8

Step-by-step explanation:

Answer:

x= 3/8 or x=-1

Step-by-step explanation:

Step 1: Subtract 3 from both sides.

8x2+5x−3=3−3

8x2+5x−3=0

Step 2: Factor the left side of the equation.

(8x−3)(x+1)=0

Step 3: Set factors equal to 0.

8x−3=0 or x+1=0

x=3/8 or x=-1

Where are the negative rational numbers placed on a vertical number line?

Answers

Answer:

on the top the negative rational numbers are placed

Answer:

On a horizontal number line, the positive rational numbers are placed To the right of, To the left of, above or below zero, and the negative rational numbers are placed To the right of, To the left of, above or below zero.

Which of the following illustrates the product rule for logarithmic equations?
1.log2 (4x) = log2(4) / log2(x)
2.log2 (4x) = log2(4)x log2(x)
3.log2 (4x) = log2(4)-log2 (x)
4.log2 (4x) = log2(4)+log2 (x)

Answers

Answer:log2 (4x) = log2(4)+log2 (x) it is D

Step-by-step explanation:

Lucille has a collection of more than 500 songs on her phone that have a mean duration of 215 seconds and a standard deviation of 35 seconds. Suppose that every week she makes a playlist by taking an SRS of 49 of these songs, and we calculate the sample mean duration ë of the songs in each sample. Calculate the mean and standard deviation of the sampling distribution of ________. seconds L = seconds

Answers

Answer:

The mean of the sampling distribution is of 215 seconds and the standard deviation is 5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

All songs

Mean 215 seconds, standard deviation 35 seconds

Sample

49

Mean 215, standard deviation [tex]s = \frac{35}{\sqrt{49}} = 5[/tex]

The mean of the sampling distribution is of 215 seconds and the standard deviation is 5.

Answer:

The sample mean would be:

[tex]\mu_{\bar X} = 215 seconds[/tex]

And the deviation:

[tex]\sigma_{\bar X} = \frac{35}{\sqrt{49}}= 5 seconds[/tex]

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

We know the following info for the random variable X who represent the duration

[tex]\mu = 215, \sigma=35[/tex]

For this case we select a sampel size of n =49>30. So we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

The sample mean would be:

[tex]\mu_{\bar X} = 215 seconds[/tex]

And the deviation:

[tex]\sigma_{\bar X} = \frac{35}{\sqrt{49}}= 5 seconds[/tex]

A crate is 2 feet in length, 5 feet in height, and has a volume of 40 cubic feet. What is the width of the crate?

Answers

Answer: 4 feet

Step-by-step explanation:

The formula for volume is length x width x height

Answer:

The answer to your question is 4 ft

Step-by-step explanation:

Data

length = 2 ft

height = 5 ft

Volume = 40 ft³

width = ?

Process

A crate is a rectangular prism, so to calculate the volume we use

       Volume of a rectangular prism = height x length x width

-Solve for width

        width = Volume / height x length

-Substitution

        width = 40 / (5 x 2)

-Simplification

        width = 40/10

-Result

       width = 4 ft

If tan (k•90)=0 then k is an even integer true of false

Answers

Answer:

True

Step-by-step explanation:

Use the unit circle

tan(x) = 0 only when x is 0 or a multiple of 180 (in degrees)

Answer:

true

Step-by-step explanation:

2) 5, 28, 16, 32,5, 16, 48, 29, 5, 35
Mean:?
Median:?
Mode:?
Range:?

Answers

The mean is 21.9, the median is 22, the mode is 5 and the range is 43.

Important information:

The given data values are 5, 28, 16, 32,5, 16, 48, 29, 5, 35.Mean, Median, Mode, Range:

Mean of the data set is:

[tex]Mean=\dfrac{5+28+16+32+5+16+48+29+5+35}{10}[/tex]

[tex]Mean=\dfrac{219}{10}[/tex]

[tex]Mean=21.9[/tex]

Arrange the data set in asccending order.

5, 5, 5, 16, 16, 28, 29, 32, 35, 48

The number of observation is 10, which is an even number. So, the median is average of [tex]\dfrac{10}{2}=5th[/tex] term and [tex]\dfrac{10}{2}+1=6th[/tex].

[tex]Median=\dfrac{16+28}{2}[/tex]

[tex]Median=\dfrac{44}{2}[/tex]

[tex]Median=22[/tex]

Mode is the most frequent value.

In the given data set 5 has the highest frequency 3. So, the mode of the data is 5.

Range is the data set is:

[tex]Range=Maximum-Minimum[/tex]

[tex]Range=48-5[/tex]

[tex]Range=43[/tex]

Therefore, the mean is 21.9, the median is 22, the mode is 5 and the range is 43.

Find out more about 'Mean, Median, Mode, Range' here:

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additive inverse of −11/ −13

Answers

Answer: The additive inverse of -11/-13 is 11/13

Step-by-step explanation: The additive inverse is the opposite sign. (positive or negative). It's the amount that needs to be added or subtracted to get 0.

In 2011, a U.S. Census report determined that 71% of college students work. A researcher thinks this percentage has changed since then. A survey of 110 college students reported that 91 of them work. Is there evidence to support the reasearcher's claim at the 1% significance level? A normal probability plot indicates that the population is normally distributed.

a) Determine the null and alternative hypotheses.

H0: p =
Ha:P Select an answer (Put in the correct symbol and value)

b) Determine the test statistic. Round to two decimals.
c) Find the p-value. Round to 4 decimals.

P-value =

Answers

Answer:

(a) Null Hypothesis, [tex]H_0[/tex] : p = 71%   

    Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 71%  

(b) The test statistics is 3.25.

(c) The p-value is 0.0006.

Step-by-step explanation:

We are given that a U.S. Census report determined that 71% of college students work. A researcher thinks this percentage has changed since then.

A survey of 110 college students reported that 91 of them work.

Let p = proportion of college students who work

(a) Null Hypothesis, [tex]H_0[/tex] : p = 71%   {means that % of college students who work is same as 71% since 2011}

Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 71%   {means that % of college students who work is different from 71% since 2011}

The test statistics that will be used here is One-sample z proportion statistics;

                                 T.S.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of college students who reported they work = [tex]\frac{91}{110}[/tex] = 82.73%

           n = sample of students = 110

(b) So, test statistics  =  [tex]\frac{\frac{91}{110}-0.71}{\sqrt{\frac{\frac{91}{110}(1-\frac{91}{110})}{110} } }[/tex]

                                    =  3.25

The test statistics is 3.25.

(c) P-value of the test statistics is given by the following formula;

       P-value = P(Z > 3.25) = 1 - P(Z [tex]\leq[/tex] 3.25)

                                            = 1 - 0.99942 = 0.0006

So, the p-value is 0.0006.

The null and alternative hypotheses is [tex]\rm H_0:[/tex] p = 71% and [tex]\rm H_a[/tex] : p [tex]\neq[/tex] 71%, the value test statistics is 3.25, and the p-value is 0.0006.and this can be determined by using the given data.

Given :

In 2011, a U.S. Census report determined that 71% of college students work.A survey of 110 college students reported that 91 of them work.

a) The hypothesis is given by:

Null hypothesis --   [tex]\rm H_0:[/tex] p = 71%

Alternate Hypothesis --  [tex]\rm H_a[/tex] : p [tex]\neq[/tex] 71%

b) The statistics test is given by:

[tex]\rm TS = \dfrac{\hat{p}-p}{\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}} }[/tex]

[tex]\rm TS = \dfrac{\dfrac{91}{110}-0.71}{\sqrt{\dfrac{\dfrac{91}{110}(1-\dfrac{91}{110})}{110}} }[/tex]

Simplify the above expression.

TS = 3.25

c) The p-value is given by:

P-value = P(Z>3.25) = 1 - P(Z [tex]\leq[/tex] 3.25)

                                = 1 - 0.99942

                                = 0.0006

For more information, refer to the link given below:

https://brainly.com/question/17716064

"The CEO of a large electric utility claims that 80% of all his customers are very satisfied with the service they receive. To test this claim, the local newspaper surveyed 100 customers, using simple random sampling. Among the sampled customers, 73% say they are very satisfied. Were these surveyed customers less likely to be satisfied than all the CEO’s customers ( \alpha =0.05)?"

Answers

Answer:

The claim made by the CEO was correct.

Step-by-step explanation:

The CEO of a large electric utility claims that 80% of all his customers are very satisfied with the service they receive.

A one-proportion z-test can be used to determine whether the claim made by the CEO of a large electric utility  is correct or not.

The hypothesis can be defined as:

H₀: The proportion of customers that are very satisfied with the service they receive is 80%, i.e. p = 0.80.

Hₐ: The proportion of customers that are very satisfied with the service they receive is not 80%, i.e. p ≠ 0.80.

The information provided is:

[tex]\hat p[/tex] = 0.73

n = 100

α = 0.05

Compute the test statistic as follows:

[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.73-0.80}{\sqrt{\frac{0.80(1-0.80)}{100}}}=-1.75[/tex]

The test statistic value is -1.75.

The decision rule is:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the two-tailed test as follows:

[tex]p-value=2\times P(Z<-1.75)\\=2\times [1-P(Z<1.75)]\\=2\times [1-0.95994]\\=0.08012 \\\approx 0.08[/tex]

*Use a z-table for the probability.

The p-value of the two-tailed test is 0.08.

p-value = 0.08 > α = 0.05

The null hypothesis was failed to be rejected at 5% level of significance.

Thus, it can be concluded that the claim made by the CEO was correct. The proportion of customers that are very satisfied with the service they receive is 80%.

Find the quotient of 4/7 and 3/5
Give your answer as a fraction in its simplest form.

Answers

You’re essentially doing (4/7) / (3/5). To do this, first find the reciprocal of the second fraction, 3/5 (You can find a reciprocal of a fraction by switching the numerator with the denominator.) The reciprocal of 3/5 is 5/3. Now you can simple multiply 4/7 by 5/3 which is 20/21.

Answer=20/2q

The quotient of [tex]\frac{4}{7} $ and $ \frac{3}{5}[/tex] is [tex]\frac{20}{21}[/tex]

Recall:

The quotient of two quantities or values is the result you get by dividing one with the other.

Therefore, the quotient of [tex]\frac{4}{7} $ and $ \frac{3}{5}[/tex] is solved as shown below:

[tex]\frac{4}{7} \div \frac{3}{5} \\[/tex]

Change the division sign to multiplication sign and turn the second fraction upside down

[tex]\frac{4}{7} \times \frac{5}{3} \\[/tex]

Multiply both fractions together

[tex]= \frac{4 \times 5}{7 \times 3}\\= \frac{20}{21}[/tex]

Therefore the quotient of [tex]\frac{4}{7} $ and $ \frac{3}{5}[/tex] is [tex]\frac{20}{21}[/tex]

Learn more about finding quotient here:

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A group of 2n people, consisting of n men and n women, are to be independently distributed among m rooms. Each woman chooses room j with probability pj while each man chooses it with probability qj,j=1,…,m. Let X denote the number of rooms that will contain exactly one man and one woman. (a) Find µ = E[X] (b) Bound P{|X − µ} > b} for b > 0

Answers

Step-by-step explanation:

Assume that

[tex]X_i = \left \{ {{1, If , Ith, room, has,exactly, 1,man, and , 1,woman } \atop {0, othewise} \right.[/tex]

hence,

[tex]x = x_1 + x_2+....+x_m[/tex]

now,

[tex]E(x) = E(x_1+x_2+---+x_m)\\\\E(x)=E(x_1)+E(x_2)+---+E(x_m)[/tex]

attached below is the complete solution

Raj has a full deck of 52 cards. Sydney chooses the queen of clubs and holds onto it. Then Yolanda chooses a card. What is the total number of possible outcomes for Yolanda’s card?

Answers

1/51 I believe is the answer

The total number of possible outcomes for Yolanda’s card is 51.

What is Probability?

A branch of mathematics concerned with the analysis of random phenomena, or occurrence of things.

Given that, Raj has a full deck of 52 cards. Sydney chooses the queen of clubs and holds onto it. Then Yolanda chooses a card.

Since, there is only 1 queen of clubs in a deck of cards, so, after choosing 1 card from deck there will be remaining only 51 cards.

Therefore, there will be 51 cards remaining for Yolanda to choose.

Hence, The total number of possible outcomes for Yolanda’s card is 51.

For more references on Probability, click;

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#SPJ6

A noted psychic was tested for extrasensory perception. The psychic was presented with 2 0 0 cards face down and asked to determine if each card were one of five symbols: a star, a cross, a circle, a square, or three wavy lines. The psychic was correct in 5 0 cases. Let p represent the probability that the psychic correctly identifies the symbol on the card in a random trial. Assume the 2 0 0 trials can be treated as a simple random sample from the population of all guesses the psychic would make in his lifetime. What do we know about the value of the P -value for the hypothesis test: Ha: p>0.20 ? ( Note: Use the large-sample z statistic. ) a. P-value < 0.01 0.02 < b. P-value < 0.03 0.03 < c. P-value < 0.04 0.05 < d. P-value < 0.10

Answers

Answer:

C. P- value < 0.04 0.05

Step-by-step explanation:

hello,

we were given the sample size, n = 200

also the probability that the psychic correctly identifies the symbol on the 200 card is

[tex]p=\frac{50}{200}= 0.25[/tex]

using the large sample Z- statistic, we have

[tex]Z=\frac{p- 0.20}{\sqrt{0.2(1-0.2)/200} }[/tex]

   = [tex]\frac{0.25-0.20}{\sqrt{0.16/200}}[/tex]

    = 1.7678

thus the P - value for the hypothesis test is P(Z > 1.7678) = 0.039.

from the above, we conclude that the P- value < 0.04, 0.05

find the value of x in 2(x+1)=4​

Answers

Answer:

x = 1

Step-by-step explanation:

We need to solve for x by isolating the variable.

First, expand the parentheses:

2(x + 1) = 4

2 * x + 2 * 1 = 4

2x + 2 = 4

Then subtract by 2:

2x + 2 - 2 = 4 - 2

2x = 2

Finally, divide by 2:

2x/2 = 2/2

x = 1

Thus, x = 1.

Hope this helps!

Answer:

x = 1

Step-by-step explanation:

Wellllll....

X = the number to solve the equation to equal 4

2(x +1) = 4

Multiply 2 by x and 1 by x

2x +2 = 4

Solve!

2x = 4-2

2x = 2

x = 1

Hope this works!

Rosa

please help, im so confused!

Which point is on the graph of the function

f(x) = One-half(2)x?

(0, 1)
(0, 2)
(1, One-half)
(1, 1)

Answers

Answer:

D (1,1)

Step-by-step explanation:

Answer:

D. (1,1)

Hope it works!

Step-by-step explanation:

Bankers at a large financial institution created the linear regression model dˆ=0.37−0.0004s to predict the proportion of customers who would default on their loans, d , based on the customer’s credit score, s . For a customer with a credit score of 700, which of the following is true?

Answers

Answer:

The correct option is (a).

Step-by-step explanation:

The complete question is:

Bankers at a large financial institution created the linear regression model dˆ=0.37−0.0004s to predict the proportion of customers who would default on their loans, d , based on the customer’s credit score, s . For a customer with a credit score of 700, which of the following is true?

(a) The default proportion is predicted to be 0.09.

(b) The default proportion will be 0.09.

(c) The default proportion is predicted to be approximately 1.75 million.

(d) The default proportion will be approximately 1.75 million.

(e) The default proportion is predicted to be 0.28.

Solution:

The linear regression model is used to predict the value of the response or dependent variable based on only one explanatory or independent variable.

The general form of a linear regression model is:

[tex]\hat y=\alpha +\beta x[/tex]

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

The linear regression model to predict the proportion of customers who would default on their loans, based on the customer’s credit score is:

[tex]\hat d=0.37-0.0004\ s[/tex]

d = default on loans

s = customer’s credit score

Compute the predicted value of d for s = 700 as follows:

[tex]\hat d=0.37-0.0004\ s[/tex]

  [tex]=0.37-(0.0004\times 700)\\=0.37-0.28\\=0.09[/tex]

Thus, for a customer with a credit score of 700, the default proportion is predicted to be 0.09.

Thus, the correct option is (a).

NEED HELP ASAP!! FILL IN THE BLANKS!! I'LL MARK YOU BRAINLIEST IF YOU ANSWER RIGHT!!!​

Answers

Answer:

(x+8)^2 = 127

Step-by-step explanation:

The Institute of Management Accountants (IMA) conducted a survey of senior finance professionals to gauge members’ thoughts on global warming and its impact on their companies. The survey found that 65% of senior professionals that global warming is having a significant impact on the environment. Suppose that you select a sample of 100 senior finance professionals.
1. What is the probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69%?
2. The probability is 90% that the sample percentage will be contained within what symmetrical limits of the population percentage?
3. The probability is 95% that the sample percentage will be contained within what symmetrical limits of the population percentage?

Answers

Answer:

(1) The probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69% is 0.3674.

(2) The two population percentages that will contain the sample percentage with probability 90% are 0.57 and 0.73.

(3) The two population percentages that will contain the sample percentage with probability 95% are 0.55 and 0.75.

Step-by-step explanation:

Let X = number of senior professionals who thought that global warming is having a significant impact on the environment.

The random variable X follows a Binomial distribution with parameters n = 100 and p = 0.65.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of p if the following conditions are satisfied:

np ≥ 10 n(1 - p) ≥ 10

Check the conditions as follows:

 [tex]np= 100\times 0.65=65>10\\n(1-p)=100\times (1-0.65)=35>10[/tex]

Thus, a Normal approximation to binomial can be applied.

So,  [tex]\hat p\sim N(p, \frac{p(1-p)}{n})=N(0.65, 0.002275)[/tex].

(1)

Compute the value of [tex]P(0.64<\hat p<0.69)[/tex] as follows:

[tex]P(0.64<\hat p<0.69)=P(\frac{0.64-0.65}{\sqrt{0.002275}}<\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}<\frac{0.69-0.65}{\sqrt{0.002275}})[/tex]

                              [tex]=P(-0.20<Z<0.80)\\=P(Z<0.80)-P(Z<-0.20)\\=0.78814-0.42074\\=0.3674[/tex]

Thus, the probability that the sample percentage indicating global warming is having a significant impact on the environment will be between 64% and 69% is 0.3674.

(2)

Let [tex]p_{1}[/tex] and [tex]p_{2}[/tex] be the two population percentages that will contain the sample percentage with probability 90%.

That is,

[tex]P(p_{1}<\hat p<p_{2})=0.90[/tex]

Then,

[tex]P(p_{1}<\hat p<p_{2})=0.90[/tex]

[tex]P(\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}<\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}<\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}})=0.90[/tex]

[tex]P(-z<Z<z)=0.90\\P(Z<z)-[1-P(Z<z)]=0.90\\2P(Z<z)-1=0.90\\2P(Z<z)=1.90\\P(Z<z)=0.95[/tex]

The value of z for P (Z < z) = 0.95 is

z = 1.65.

Compute the value of [tex]p_{1}[/tex] and [tex]p_{2}[/tex]  as follows:

[tex]-z=\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}\\-1.65=\frac{p_{1}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{1}=0.65-(1.65\times 0.05)\\p_{1}=0.5675\\p_{1}\approx0.57[/tex]                 [tex]z=\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}}\\1.65=\frac{p_{2}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{2}=0.65+(1.65\times 0.05)\\p_{1}=0.7325\\p_{1}\approx0.73[/tex]

Thus, the two population percentages that will contain the sample percentage with probability 90% are 0.57 and 0.73.

(3)

Let [tex]p_{1}[/tex] and [tex]p_{2}[/tex] be the two population percentages that will contain the sample percentage with probability 95%.

That is,

[tex]P(p_{1}<\hat p<p_{2})=0.95[/tex]

Then,

[tex]P(p_{1}<\hat p<p_{2})=0.95[/tex]

[tex]P(\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}<\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}<\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}})=0.95[/tex]

[tex]P(-z<Z<z)=0.95\\P(Z<z)-[1-P(Z<z)]=0.95\\2P(Z<z)-1=0.95\\2P(Z<z)=1.95\\P(Z<z)=0.975[/tex]

The value of z for P (Z < z) = 0.975 is

z = 1.96.

Compute the value of [tex]p_{1}[/tex] and [tex]p_{2}[/tex]  as follows:

[tex]-z=\frac{p_{1}-p}{\sqrt{\frac{p(1-p)}{n}}}\\-1.96=\frac{p_{1}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{1}=0.65-(1.96\times 0.05)\\p_{1}=0.552\\p_{1}\approx0.55[/tex]                 [tex]z=\frac{p_{2}-p}{\sqrt{\frac{p(1-p)}{n}}}\\1.96=\frac{p_{2}-0.65}{\sqrt{\frac{0.65(1-0.65)}{100}}}\\p_{2}=0.65+(1.96\times 0.05)\\p_{1}=0.748\\p_{1}\approx0.75[/tex]

Thus, the two population percentages that will contain the sample percentage with probability 95% are 0.55 and 0.75.

Final answer:

The questions concern calculating the probability of a sample proportion falling within a given range and constructing confidence intervals around the population proportion. These questions are related to statistical concepts such as the normal approximation to the binomial distribution and the use of z-scores for interval estimation, which are typically covered in college-level statistics courses.

Explanation:

The student has asked about determining the probability that a sample percentage will fall within certain ranges, given a known proportion from a survey conducted by the Institute of Management Accountants (IMA) regarding the impact of global warming on their companies. Specifically, the student is looking to estimate probabilities related to the sample proportion and construct confidence intervals around a population percentage. These are statistical concepts typically covered in college-level courses in probability and statistics, specifically in chapters related to sampling distributions and confidence interval estimation.

To answer the first question, we would need to use the normal approximation to the binomial distribution, since the sample size is large (n=100). The sample proportion p = 0.65, and we can calculate the standard error for the sampling distribution of the sample proportion. However, since the full calculations are not provided here, a specific numerical answer cannot be given.

For the second and third questions, constructing confidence intervals at 90% and 95% requires using the standard error and the appropriate z-scores that correspond to these confidence levels. Again, the specific limits are not calculated here, but the process involves multiplying the standard error by the z-score and adding and subtracting this product from the sample percentage.

R=1/6 the problem is 3r2

Answers

Step-by-step explanation:

Putting the value of r

3 ( 1/6) 2

So 3 × (1/6) = 0.5 × 2 = 1

You are offered the following gamble based on coin flips. If the first heads occurs on the first flip, you get $2. If the first heads occurs on the second flip, you get $4, and so on, so that if the first heads is on the Nth flip, you get $2N. The game continues until there is a heads. Which of the following best represents the expected value of this gamble in dollars? e 0 π [infinity] When offered, most people say they would pay only less than $10 to play this game.

Answers

Answer:

infinity

Step-by-step explanation:

a) the expected value of this gamble in dollars is Infinity

i.e

expected value = [tex]\frac{1}{2}*2 + \frac{1}{4}*4 + \frac{1}{8}*8 + \frac{1}{16}*16 + ... + \to \infty (infinty) \\[/tex]

= [tex]1+1+1+1+1 + ... = \infty[/tex]

b)

When offered, most people say they would pay only less than $10 to play this game.

What are two reasons why people are willing to pay so much less than the expected value?

These people are ready to pay less than $10 to play this game due to the fact that people usually overlook the unlikely event when making decisions. In a bid to that logic, they gamble in order to double their amount of money and the probability that heads may never come is ignored by these people and they may hope for a likely event i.e a head every time they play the game.

Also, the expected value is so humongous that if and only if that the first head appears after a long series of tails which is  very less certain to occur, because mostly people would think that on an average the length of a series of tails ( or heads) is somewhat near 10 or so, but definitely infinity.

I need help please?!!

Answers

Answer:

No, the expression is not linear because the highest power of x is 2.

Answer:

No it isn't  it is Quadratic

A bookstore had 45 copies of a magazine. Yesterday, it sold 23 of them. Today, it sold 15 of what remained. How many copies does the bookstore have left?

Answers

Answer:

45 original books then 23 is sold = 22

next day 15 is sold so

23-15=7

7 books remain

Step-by-step explanation:

45-23-15=7

In a study of the accuracy of fast food​ drive-through orders, one restaurant had 36 orders that were not accurate among 324 orders observed. Use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to​ 10%. Does the accuracy rate appear to be​ acceptable?
Identify the null and alternative hypotheses for this test. Choose the correct answer below.

Answers

Answer:

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to​ 10%.

Step-by-step explanation:

We want to use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to​ 10%.

We set up our hypothesis to get:

[tex]H_0:p=0.10[/tex]------->null hypothesis

[tex]H_1:p\ne0.10[/tex]------>alternate hypothesis

This means that: [tex]p_0=0.10[/tex]

Also, we have that, one restaurant had 36 orders that were not accurate among 324 orders observed.

This implies that: [tex]\hat p=\frac{36}{324}=0.11[/tex]

The test statistics is given by:

[tex]z=\frac{\hat p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n} } }[/tex]

We substitute to obtain:

[tex]z=\frac{0.11-0.1}{\sqrt{\frac{0.1(1-0.1)}{324} } }[/tex]

This simplifies to:

[tex]z=0.6[/tex]

We need to calculate our p-value.

P(z>0.6)=0.2743

Since this is a two tailed test, we multiply the probability by:

The p-value is 2(0.2723)=0.5486

Since the significance level is less than the p-value, we fail to reject the null hypothesis.

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to​ 10%.

A movie theater is keeping data on the number of tickets sold and the price of a single ticket. Which scatterplot is
correctly labeled?

Answers

Answer: 3rd option

Step-by-step explanation:

Answer:the third option is the answer

Step-by-step explanation:I just took the assignment on edge

Gabriel finds some wooden boards in the backyard with lengths of 5 feet, 2.5 feet and 4 feet. He decides he wants to make a triangular garden in the yard and uses the triangle inequality rule to see if it will work.
PLEASE ANSWER IMMEDIATELY Which sums prove that the boards will create a triangular outline for the garden? Select all that apply.
5 + 2.5 > 4
5 + 2.5 < 4
4 + 2.5 > 5
4 + 2.5 < 5
4 + 5 > 2.5
first one to answer will get brainliest

Answers

Answer:

Third one

4 + 2.5 > 5

Step-by-step explanation:

To form a triangle, the longest side should be less than the sum of the two shorter sides (triangular inequality)

Longest side < sum of the shorter ones

Longest side: 5

Shorter ones: 2.5 & 4

5 < 2.5 + 4

This is the same as:

4 + 2.5 > 5

Answer:

1 3 5

Step-by-step explanation:

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