Answer:
[tex]F_Q=\frac{Mg}{3}[/tex]
Explanation:
We are given that
Length of beam=L
Mass of object=M
We have to find the FQ , the vertical force that pier exerts on the right end of the bridge .
Torque about P
[tex]F_Q(3L)-MgL=0[/tex]
[tex]F_Q(3L)=MgL[/tex]
[tex]F_Q=\frac{MgL}{3L}[/tex]
[tex]F_Q=\frac{Mg}{3}[/tex]
Hence, the force that exerted pier Q exerts on the right end of the bridge is given by
[tex]F_Q=\frac{Mg}{3}[/tex]
Select the effects of radiation below that are stochastic:
associated with short-term, high-level exposure
associated with long-term, low-level exposure
include cancer and other DNA mutation
include burns and radiation sickness
Answer: Include cancer and other DNA mutation
Explanation:
Stochastic effects are the effects that occur by chance and which may occur without a threshold level of dose, whose probability is proportional to the dose and whose severity is independent of the dose. In the context of radiation protection, the main stochastic effect is cancer.
Therefore the best option is: include cancer and other DNA mutation
An electron in an atom has an uncertainty of 0.2 nm. If it is doubled to 0.4 nm by what factor does the uncertainty in momentum change?
Answer:
The uncertainty in momentum changes by a factor of 1/2.
Explanation:
By Heisenberg's uncertainty principle, ΔpΔx ≥ h/2π where Δp = uncertainty in momentum and Δx = uncertainty in position = 0.2 nm. The uncertainty in momentum is thus Δp ≥ h/2πΔx. If the uncertainty in position is doubled, that is Δx₁ = 2Δx = 0.4 nm, the uncertainty in momentum Δp₁ now becomes Δp₁ ≥ h/2πΔx₁ = h/2π(2Δx) = (h/2πΔx)/2 = Δp/2.
So, the uncertainty in momentum changes by a factor of 1/2.
Two technicians are discussing how a clutch disengages. Technician A says a gap on each side of the clutch disk facing when disengaged. Technician B says the marcel/cushion plage in the disc will flatten. Who is Correct?
Answer: A - a gap on each side of the clutch disk facing when disengaged
Explanation:
A clutch switch is used to ensure the clutch is disengaged
or Prevent the engine from starting unless the clutch pedal is depressed
When a clutch is disengageda gap will be on each side of the facing.
Answer:
Technician A is correct
Explanation:
A clutch switch is used in preventing an engine from starting unless the pedal of the clutch is depressed or to ensure the clutch totally disengaged .
The clutch switch is located normally underneath the dash, while i is still in gear it stops you from starting a vehicle to start . The clutch switch is activated by the clutch pedal arm when the clutch is pushed down and also attached to the pedal linkage.
From the question given, Technician A is right.
The amount of gas that a helicopter uses is directly proportional to the number of hours spent flying. the helicopter flies for 44 hours and uses 2828 gallons of fuel. find the number of gallons of fuel that the helicopter uses to fly for 55 hours.
Answer:
The helicopter uses 35 gallons to fly for 5 hours.
Explanation:
The amount of gas that a helicopter uses for flying varies directly proportional to the number of hours spent flying.
g ∝ T
where g represents amount of gas and T time of flight.
Then,
[tex]\therefore \frac{g_1}{g_2}=\frac{T_1}{T_2}[/tex]
The helicopter files 4 hours and uses 28 gallons of fuel.
Here, g₁= 28 gallons, T₁=4 hours
g₂=?, T₂=5 hours.
[tex]\therefore \frac{g_1}{g_2}=\frac{T_1}{T_2}[/tex]
[tex]\Rightarrow \frac{28}{g_2}=\frac{4}{5}[/tex]
⇒28×5= g₂×4
⇒ g₂×4=28×5
[tex]\Rightarrow g_2=\frac{28\times 5}{4}[/tex]
[tex]\Rightarrow g_2=35[/tex] gallons
The helicopter uses 35 gallons to fly for 5 hours.
A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the wavelength of the light decreases,
Answer: shrinks with all the fringes getting narrower
Explanation: As the wavelength of the light decreases the diffraction pattern does change and shrinks with all the fringes getting narrower
We see a galaxy with a lookback time of 12 billion years when its age could not have been more than ___________.
A. 100 million years
B. 2 billion years
C. 4 billion years
D. 10 billion years
E. 12 billion years
Answer:
B. 2 billion years
Explanation:
If the galaxy has a look-back time of 12 billion years it means it is at a distance of 12 billion light years away from us. The view that we are seeing today is actually the view 12 billion years back.
How old would it have been at that time?
If we see the widely accepted theory of origin of universe i.e. the big bang theory. The universe formation started around 13.8 billion years back. By that logic this galaxy could not have been aged more than 2 billion years. Its age would be around 1 - 1.5 billion year at that time.
The gravitational force between two objects is 45,000 N. What will be the gravitational force between the two objects if the distance between the objects is reduced by one-half?
Answer:
180000 N
Explanation:
According to Newton's law of gravitation
F= G m1 m2 / r^2
This expression shows that if distance is reduced to half the gravitational force will increase 4 times.
The drawing shows a current-carrying wire lying along the x axis. The current I is 3.0 A and flows to the right. The wire is 0.43 m long and situated in a uniform magnetic field B. The magnetic field points along the z axis and has a magnitude of 2.0 T. What is the magnitude F and direction of the magnetic force exerted on the current? F = N
Answer:
The force is 2.58N
The direction of the force at 90° to the conductor
Explanation:
N/B I can't find any attachment for my reference
But this problem bothers on the force on a current carrying conductor
In accordance with the Flemings left hand rule the conductor will experience a force perpendicular to it
F= BILsinθ
Given data
Current I = 3 amps
Length of the conductor L= 0.43m
Magnetic field B= 2T
Angles between conductor and magnetic field θ= 90°
Substituting our data into the expression for force we have
F= 2*3*0.43
F= 2.58N
The direction of the force at 90° to the conductor
The magnitude of the magnetic force on the wire is 2.58 N, and the direction is downward as determined by the right-hand rule-1.
Explanation:The force exerted on a current-carrying wire lying in a magnetic field can be determined using the formula F = IxB. From the conditions given in the question, it can be calculated as follows:
Given:
Current I = 3.0 ALength of wire = 0.43 m Magnetic field B = 2.0 T.By substituting the given value in F = I L B (because the angle between the current and the magnetic field is 90 degrees as given by the right-hand rule, and sine 90 =1), the force F = (3.0 A) x (0.43 m) x (2.0 T) = 2.58 N.
The direction of the force can be determined using the right-hand rule-1 (RHR-1). When your thumb points in the direction of the current, the motion of the fingers when half-closed indicates the direction of B and the force is in the direction of the palm. Thus, the direction of the force on the wire is negative y direction or downward.
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The oxygen isotopic composition of ocean water is measured by determining the ratio of 18O to 16O, expressed as 18O/16O. The isotope 16O preferentially evaporates into the atmosphere. During periods of global cooling, the 18O/16O ratio will:
Final answer:
During periods of global cooling, the ratio of Oxygen-18 (¹₈O) to Oxygen-16 (¹⁶O) in ocean water increases, as ¹⁶O is preferentially evaporated and stored in ice sheets, leaving the seawater enriched in ¹₈O.
Explanation:
During periods of global cooling, such as the Ice Ages, the isotopic composition of ocean water changes due to the evaporation of water molecules containing Oxygen-16 (¹⁶O), a lighter isotope that preferentially enters the atmosphere. This results in ¹⁶O becoming trapped in ice sheets and glaciers, leading to an increase in the ratio of Oxygen-18 (¹₈O) to ¹⁶O in the seawater. The enriched ¹₈O in the oceans during cold periods indicates a higher amount of ice on the planet and is significant for interpreting past global temperatures using oxygen isotope analysis in sediment cores or glacial ice.
Examine the scenario.
A stream of negatively-charged particles is moving to the right in a magnetic field. The particles experience a force downward.
Which situation(s) would result in the particle stream experiencing an upward force?
(Select all that apply.) (I think you have to select 2?)
a) using uncharged particles moving to the right
b) using positively-charged particles moving to the left
c) using positively-charged particles moving to the right
d) using negatively-charged particles moving to the left
Answer:
C and D
Explanation:
From the right-hand rule, positively charged particles moving to the left in a perpendicular magnetic field, will experience an upward force. Also, negatively charged particles moving to the left will experience an upward force. This is because, the direction of the force is irrespective of the sign of the charge but on its velocity.
The two major processes involved in the carbon cycle are
Answer:
Respiration and Photosynthesis
The two major processes involved in the carbon cycle are photosynthesis and respiration. The correct option is 3.
What is carbon cycle?The carbon cycle is nature's own way of recycling carbon atoms, which commute from the ambience into lifeforms on Earth and then returned to the environment.
The maximum of carbon is kept in rocks and sediments, with the leftover in the ocean, atmosphere, and living organisms.
It is critical for our global atmosphere and carbon balance to remain stable. Carbon is the lifeline of the Earth, and the carbon cycle regulates it naturally. The Earth would be frozen if it didn't have it.
The process of photosynthesis requires carbon to form glucose which is taken in as carbon dioxide, and the respiration is the process of excreting out the carbon as carbon dioxide.
Thus, the correct option is 3.
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Your question seems incomplete the missing options could be:
Deposition and soil erosion.Evaporation and transpiration.Photosynthesis and respiration.Fixation and denitrification.An uncharged series RC circuit is to be connected across a battery. For each of the following changes, determine whether the time for the capacitor to reach 90% of its final charge would increase, decrease, or remain unchanged. Indicate your answers with "I," "D," or "U," respectively. (a) The RC time constant t is doubled. (b) The battery voltage is doubled. (c) A second resistor is added in series with the original resistor.
a) Increase
b) Unchanged
c) Increase
Explanation:
a)
The charge on a capacitor charging in a RC circuit connected to a battery follows the exponential equation:
[tex]Q(t)=Q_0 (1-e^{-\frac{t}{RC}})[/tex]
where
[tex]Q_0 = CV[/tex] is the final charge stored in the capacitor, where C is the capacitance and V is the voltage of the battery
t is the time
R is the resistance of the circuit
The capacitor reaches 90% of its final charge when
[tex]Q(t)=0.90Q_0[/tex]
Substituting and re-arranging the equation, we find:
[tex]0.90Q_0 = Q_0(1-e^{-\frac{t}{RC}})\\0.90=1-e^{-\frac{t}{RC}}\\e^{-\frac{t}{RC}}=0.10\\-\frac{t}{RC}=ln(0.10)\\t=-RCln(0.10)=2.30RC[/tex]
We see that if we double the RC constant, then [tex](RC)'=2(RC)[/tex]
So the time taken will double as well:
[tex]t'=2.30(RC)'=2.30(2RC)=2(2.30RC)=2t[/tex]
So, the answer is "increase"
b)
In this second part, the battery voltage is doubled.
According to the equation written in part a),
[tex]Q_0 =CV[/tex]
this means also that the final charge stored on the capacitor will also double.
However, the equation that gives us the time needed for the capacitor to reach 90% of its full charge is
[tex]t=2.30 RC[/tex]
We see that this equation does not depend at all on the voltage of the battery.
Therefore, if the battery voltage is doubled, the final charge on the capacitor will double as well, but the time needed for the capacitor to reach 90% of its charge will not change.
So the correct answer is
"unchanged"
c)
In this case, a second resistor is added in series with the original resistor of the circuit.
We know that for two resistors in series, the total resistance of the circuit is given by the sum of the individual resistances:
[tex]R=R_1+R_2[/tex]
Since each resistance is a positive value, this means that as we add new resistors, the total resistance of the circuit increases.
Therefore in this problem, if we add a resistor in series to the original circuit, this means that the total resistance of the circuit will increase.
The time taken for the capacitor to reach 90% of its final charge is still
[tex]t=2.30 RC[/tex]
As we can see, this time is directly proportional to the resistance of the circuit, R: therefore, if we add a resistor in series, the resistance of the circuit will increase, and therefore this time will increase as well.
So the correct answer is
"increase"
The time for the capacitor to reach 90% of its final charge in an RC circuit depends on the time constant. Doubling the time constant increases the time, while doubling the battery voltage or adding a second resistor in series does not change the time.
Explanation:The time for the capacitor to reach 90% of its final charge in an RC circuit depends on the time constant, which is given by the product of the resistance (R) and the capacitance (C), i.e., RC. Let's analyze each change:
(a) If the time constant (t) is doubled, the time for the capacitor to reach 90% of its final charge will increase. This is because a larger time constant means it takes longer for the capacitor to charge or discharge.
(b) If the battery voltage is doubled, the time for the capacitor to reach 90% of its final charge will remain unchanged. This is because the time constant is determined by the product of R and C, and the battery voltage does not affect this product.
(c) If a second resistor is added in series with the original resistor, the time for the capacitor to reach 90% of its final charge would increase. This is because the total resistance in the circuit increases, which slows down the charging or discharging process.
A combustion reaction occurs when a substance reacts quickly with
Answer:
Oxygen
Explanation:
Any sort of combustion requires oxygen
A 121 turn 121 turn circular coil of radius 2.85 cm 2.85 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coil. Over an interval of 0.179 s 0.179 as, the magnetic field strength increases from 55.1 mT 55.1 mT to 97.9 mT 97.9 mT. Find the magnitude of the average emf E avg Avg induced in the coil during this time interval, in millivolts.
Answer:
0.074 V
Explanation:
Parameters given:
Number of turns, N = 121
Radius of coil, r = 2.85 cm = 0.0285 m
Time interval, dt = 0.179 s
Initial magnetic field strength, Bin = 55.1 mT = 0.0551 T
Final magnetic field strength, Bfin = 97.9 mT = 0.0979 T
Change in magnetic field strength,
dB = Bfin - Bin
= 0.0979 - 0.0551
dB = 0.0428 T
The magnitude of the average induced EMF in the coil is given as:
|Eavg| = |-N * A * dB/dt|
Where A is the area of the coil = pi * r² = 3.142 * 0.0285² = 0.00255 m²
Therefore:
|Eavg| = |-121 * 0.00255 * (0.0428/0.179)|
|Eavg| = |-0.074| V
|Eavg| = 0.074 V
Answer:
The magnitude of the average EMF = 73.83 mv
Explanation:
From faradays law of induction, EMF is given as;
EMF = NA(ΔB/Δt)
We are given that;
N = 121 turns
B1 = 55.1 mT
B2 = 97.9 mT
Thus, ΔB = 97.9 mT - 55.1 mT = 42.8 mT
t = 0.179 s
r = 2.85cm = 0.0285 m
Area = πr² = π x (0.0285)² = 0.0025518 m²
Plugging in the relevant values, we can calculate EMF as;
EMF = (121)(0.0025518)(42.8 mT/0.179) = 73.83 mv
A graduated cylinder contains 62 ml of water. When a small metal block is added to the water, the volume of the water increases to 65.5 ml. If the block is 26g, what is the density
Answer:
The density of the block is 7.4g/ml.
Explanation:
We can determine the volume of the metal block by taking the difference between the volumes measured in the graduated cylinder:
[tex]V_{block}=65.5ml-62ml\\\\V_{block}=3.5ml[/tex]
Now, as we know that the average density of an object is calculated dividing its mass by its volume, we can calculate the density ρ of the metal block using the expression:
[tex]\rho_{block}=\frac{m_{block}}{V_{block}}\\\\\rho_{block}=\frac{26g}{3.5ml}\\\\\rho_{block}=7.4\frac{g}{ml}[/tex]
Finally, it means that the density of the metal block is 7.4g/ml.
Answer:
7.43 g/mL
Explanation:
Step 1:
Data obtained from the question. This include:
Volume of water = 62 mL
Volume of (Metal + water) = 65.5 mL
Mass of metal = 26g
Density =?
Step 2:
Determination of the volume of the block.
From Archimedes' principle, we understood that an object will displace its own volume when completely immersed in a liquid. The volume of the metal block can be obtained as follow:
Volume of water = 62 mL
Volume of (Metal + water) = 65.5 mL
Volume of the matal = Volume of (Metal + water) - volume of water
Volume of the matal = 65.5 - 62
Volume of the matal = 3.5 mL
Step 3:
Determination of the density of the metal block. This is illustrated below:
The density of an object is simply the mass of the object per unit volume of the object. It represented mathematically as:
Density = Mass /volume
Mass of the metal = 26g
Volume of the metal = 3.5 mL
Density =?
Density = Mass /volume
Density = 26g / 3.5mL
Density = 7.43 g/mL
A ________ is a hard shoreline stabilization feature, detached from the shoreline, that protects shorelines from the pounding of waves by creating an area of quiet water behind it.
Answer:
Answer is breakwater.
Refer below.
Explanation:
A breakwater is a hard shoreline stabilization feature, detached from the shoreline, that protects shorelines from the pounding of waves by creating an area of quiet water behind it.
7. A person pushes on a 5.00 kg box with a force of 15.0 N to the right. As a result, the box moves at a constant speed of 10.0 m/s.
Answer
Given,
Mass of the box, m = 5 kg
Force, F = 15 N
Speed of the box, v = 10 m/s
Assuming we need to determine weight, normal force, and the frictional force on the box.
Weight of the box = m g = 5 x 9.8 = 49 N
Normal force on the box = Weight of the box = 49 N.
Frictional force on the box will be equal to 15 N because box is moving with constant velocity.
Calculate the equivalent resistance in the circuit shown please
Answer:
0.55 ohms
Explanation:
Answer:
0.55 ohms
Explanation:
edge 2021
What is the basic definition of a black hole?
a. any compact mass that emits no light
b. a dead star that has faded from view any object from which the escape velocity exceeds
c. the speed of light any object made from dark matter
d. a dead galactic nucleus that can only be viewed in infrared
A black hole is an astronomical object with an escape speed that exceeds the speed of light. Normally created from large, collapsed stars, the intense gravitational force of black holes prevents anything, including light, from escaping. They can only be indirectly observed.
Explanation:The basic definition of a black hole aligns with the option: Any object from which the escape speed exceeds the speed of light. This astronomical phenomenon occurs, typically, when a very large star dies and collapses under its own gravity. With this collapse, the star's gravitational force becomes so intense that nothing can escape it, including light. For this reason, black holes are invisible and can only be observed indirectly, such as through their gravitational effects on other bodies or by the presence of a disk of matter swirling into it (known as an accretion disk).
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Let us suppose the magnitude of the original Coulomb force between the two charged spheres is F. In this scenario, a third sphere touches the grey sphere and the red sphere multiple times, being grounded each touch. If the grey sphere is touched twice, and the red sphere is touched three times, what is the magnitude of the Coulomb force between the spheres now?
Answer:
Answer: F/32
Explanation:
Initial electrostatic force between sphere = F = kQq/r2
Each time the third sphere touches the red or grey sphere the charges in it is reduced to half as half the charges are tranferred into the third sphere. So that both spheres have equal charges
The 3rd sphere touches the grey sphere 2 times, if the initial charge in it is Q ,final charge will be Q / (2x2) = Q/4
In the red sphere if the initial charge was q, then final charge after the 3rd sphere touches it 3 times = q/(2x2x2) =q/8
The magnitude of the Coulomb force between the spheres = kQq/(r2x4x8) = F/32
Answer:
F/32
Explanation:
GIVEN
that the electrostatic force between sphere = F = kQq/r2
ANSWERED
Any time, third sphere touches the red or grey sphere the charges in it, will reduced to half, also, as half the charges are moved into the third sphere. That makes both spheres have equal charges (grounded) .
Also, the 3rd sphere tries to touch the grey sphere two times. Then, when we have initial charge in it to be Q, then, the final charge will be given has Q / (2x2) = Q/4
The similarly with the red sphere, has the initial charge was q, so we have last charge after the third sphere has touches it three times = q/(2x2x2) =q/8
Therefore,given that the new coulombs force = kQq/(r2x4x8) = F/32
Ironman in his suit has a mass of 180 kg. How much gravitational potential
energy does he have if he is hovering 400 m in the air? Record your answer
to the correct number of significant digits. *
A. 2.22 J
B. 7.20 x 104 J
C. 07.06 x 105 J
D. 722 J
Answer:
a
Explanation:
Because I just know thats right.
A point charge q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s. The dipole is initially oriented so that q is in the plane bisecting the dipole. Assume that r≫s.
Answer:
Complete question: A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±qseparated by a distance s. The dipole is initially oriented so that the charge Q is located in the plane that bisects the dipole. Assume that r≫s. Immediately after the dipole is released,
what is the magnitude of the force on the dipole?
In the space provided, enter the factor that multiplies 1ϵ0 in your answer. Express this factor in terms of q, Q, s, π, and r.
what is the magnitude of the torque on the dipole?
in the space provided, enter the factor that multiplies 1ϵ0 in your answer. Express this factor in terms of q, Q, s, π, and r.
Answer: The magnitude of he electric field of the dipole = E = Kqs/r³
the magnitude of the torque on the dipole is Z = (qs) (KQ/r²) = 1/ϵ₀ (qQs)/4πr³)
Explanation:
From the given question,
We find the magnitude of the force on the dipole.
E= the electric field
ϵ₀= permittivity of free space is
q = magnitude of each charge of the dipole
The dipole movement = p =qs
The electric field of the dipole = E = Kqs/r³
Then
F=QE ⇒ F = Q (Kqs)/r³ ⇒ KqQs/r³
= 1/ϵ
₀ ( qQs)/4πr³)
The electric field due to Q is E = KQ/r²
The next step is to find the magnitude of the torque on the dipole
The torque is denoted by Z =PE sign 90
Z = (qs) (KQ/r²) = 1/ϵ
₀ (qQs)/4πr³)
An electric vehicle starts from rest and accelerates at a rate of 2.3 m/s2 in a straight line until it reaches a speed of 18 m/s. The vehicle then slows at a constant rate of 1.0 m/s2 until it stops. (a) How much time elapses from start to stop
Answer:
25.83s
Explanation:
Time taken by car to reach from 0 m/s to 18m/s
Using the kinematic equation,
V= u + at
18=0 + 2.3(t)
t= 18/2.3= 7.83s
Time to stop the top speed
V= u + at
18=0 + 1(t)
t = 18 / 1 = 18 s
total time is
=7.83s + 18s
= 25.83s
Final answer:
The time taken by the electric vehicle to go from start to stop is calculated by finding the time for both the acceleration phase (7.83 seconds) and the deceleration phase (18 seconds), summing up to approximately 25.83 seconds in total.
Explanation:
To calculate the total time elapsed from start to stop for the electric vehicle, we need to determine the time for both the acceleration phase and the deceleration phase. We use the kinematic equations for uniformly accelerated motion.
Acceleration Phase
The vehicle accelerates from rest, meaning the initial velocity ( extit{u}) is 0 m/s, at an acceleration ( extit{a}) of 2.3 m/s2, until it reaches a speed ( extit{v}) of 18 m/s.
Using the equation extit{v} = extit{u} + extit{a} extit{t}, we can find the time ( extit{t}) for this phase.
extit{Time for acceleration} = ( extit{v} - extit{u}) / extit{a} = (18 m/s - 0 m/s) / 2.3 m/s2 = 7.83 s (approximately)
Deceleration Phase
Now, we need to calculate the time it takes for the vehicle to decelerate from 18 m/s to rest (0 m/s) at a rate of 1.0 m/s2.
extit{Time for deceleration} = ( extit{v} - extit{u}) / extit{a} = (0 m/s - 18 m/s) / 1.0 m/s2 = -18 s (since deceleration is negative acceleration, the time would be positive).
Therefore, the total time is the sum of both phases:
extit{Total time} = extit{Time for acceleration} + extit{Time for deceleration} = 7.83 s + 18 s = 25.83 s
So, it takes approximately 25.83 seconds for the electric vehicle to go from starting to stop.
An alternating emf source with amplitude 14.9 14.9 V and an adjustable driving frequency f d fd is connected in series with a 59.4 59.4 Ω resistor and a 23.7 23.7 μF capacitor. At what value of f d fd are the amplitudes of the voltages across the resistor and capacitor equal?
Answer:
113.0 Hz
Explanation:
In a RC circuit with alternating current, the voltage across the resistor is given by Ohm's Law:
[tex]V_R = IR[/tex]
where
I is the current in the circuit
R is the resistance of the resistor
While the voltage across the capacitor is given by:
[tex]V_C = IX_C[/tex]
where
[tex]X_C=\frac{1}{2\pi f C}[/tex] is the impedance of the capacitor, where
f is the frequency
C is the capacitance
The voltages across the resistor and the capacitor are equal when
[tex]V_R = V_C[/tex]
So
[tex]IR=\frac{I}{2\pi fC}[/tex]
Which can be rewritten as
[tex]f=\frac{1}{2\pi RC}[/tex]
In this problem:
[tex]R=59.4\Omega[/tex] is the resistance
[tex]C=23.7\mu F = 23.7\cdot 10^{-6}F[/tex] is the capacitance
Substituting, we find the frequency at which this happens:
[tex]f=\frac{1}{2\pi (59.4)(23.7\cdot 10^{-6})}=113.0 Hz[/tex]
The value of fd represents the amplitudes of the voltages across the resistor and capacitor equal to 113.0 Hz.
Ohm law:Here
V = IR
Here.
I is the current in the circuit
R is the resistance of the resistor
Now the voltage across the capacitor and resistor should be provided by
Vr = Vc
IR = 1/2πFc
Here
f = 1 /2πRC
So,
= 1/2π(59.4)(23.7.10^-60
= 113.0 Hz
Hence, The value of fd represents the amplitudes of the voltages across the resistor and capacitor equal to 113.0 Hz.
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On a frictionless surface, a 32 kg student pushes a 43 kg student. If the 32 kg student slides back at 2.4 m/s, how fast will the 43 kg student be sliding and in what direction?
Answer:
The 43kg student will be sliding at 1.79m/s opposite the direction the 34kg student is going.
Explanation:
Conservation of linear momentum!
The law of conservation of momentum says that in an isolated system, the momentum before must equal the momentum after:
[tex]mv_1+m_1v_2=m_1_v_{1f}+m_2v_{2f}[/tex].
For our two students
[tex](32kg)(v_1)+(43kg)(v_2)= (32kg)+(43kg)(-2.4m/s)+(43kg)(v_{2f})[/tex] (notice the - sign in -2.4m/s, this means going to the left)
since the students were not moving at first, [tex]v_1=v_2= 0[/tex], therefore we have
[tex]0= (32kg)(-2.4m/s)+(43kg)(v_{2f})[/tex]
solving for [tex]v_{2f}[/tex] gives
[tex]76.8=(43kg)(v_{2f})[/tex]
[tex]\boxed{v_{2f} = 1.79m/s}[/tex]
Hence the 43kg student will be sliding at 1.79m/s to the right.
In order for a space shuttle to leave Earth, it must produce a great amount of thrust. Its rocket boosters create this thrusting force by burning great amounts of fuel. However, once in space, the shuttle needs very little fuel. It circles Earth while gravity pulls it toward Earth. What term describes the motion of the shuttle around Earth?
Answer:
Orbit
Explanation:
The term that describes motion of the shuttle around earth is called as Orbit.
The orbit is defined as a regular repeating path that object takes around another.
The shuttle circles around the earth at a constant distance from earth surface is because of earth gravity and forward motion of earth.
Answer:
orbit
Explanation:
Why plate tectonics is a scientific theory and not a scientific law.
Answer:
We have not drilled to the center of the earth.
Explanation:
Plate tectonics is considered a scientific theory because it provides an explanatory framework for understanding geological processes, unlike a scientific law which describes what happens without explaining why or how. Its acceptance was gradual over 50 years due to initial resistance from the geological community and a lack of supporting evidence until later in the 20th century.
Plate tectonics is a scientific theory and not a scientific law because it is an explanatory framework that helps us understand various geological processes. A scientific law describes what happens under certain conditions but does not explain why or how something happens. In contrast, a theory provides a model for understanding the 'why' and 'how.' The plate tectonics theory explains the movement of Earth's lithosphere through the mechanism of mantle convection and provides a model for understanding the origin of continents and oceans, the formation of mountains, and the occurrences of earthquakes and volcanoes.
The development and acceptance of the plate tectonics theory was slow, spanning roughly 50 years. It was initially met with resistance from the established geological community due to its revolutionary nature and the lack of supportive evidence until the mid-20th century. This explanatory model integrated previous concepts like continental drift, proposed by Alfred Wegener, into a cohesive framework that describes Earth's geodynamic processes.
As a comprehensive explanatory model, plate tectonics has significantly enhanced geological science, providing a method to reconstruct Earth's history and predict geological events. Its strength lies in its ability to create testable hypotheses about Earth's past and future. This theory is foundational in the field of geology, akin to the role of evolution by natural selection in biology.
what is the name of the farthest planet away from the sun
Answer:
It's Neptune:)
Explanation:
Answer:
Neptune is the eighth and farthest planet from the Sun, at a distance of about 4.5 billion km (2.8 billion miles) or 30.07 AU.
Explanation:
A car is originally traveling at 15.0 m/s on a straight horizontal road. The driver applies the brakes, causing a car to decelerate uniformly at 4.00 m^2 until it comes to rest. Calculate the car's stopping distance.
Final answer:
The stopping distance of a car initially traveling at 15.0 m/s and decelerating at a rate of 4.00 m/s^2 until it comes to rest is calculated using the kinematic equation. The calculation results in a stopping distance of 28.125 meters.
Explanation:
The question involves a car that is initially traveling at 15.0 m/s and decelerates uniformly at a rate of 4.00 m/s2 until it comes to rest. To calculate the stopping distance of the car, we can use the kinematic equation that relates initial velocity, final velocity, acceleration, and displacement:
v2 = u2 + 2as
Where:
v = final velocity (0 m/s since the car comes to rest)
u = initial velocity (15.0 m/s)
a = acceleration (deceleration in this case, so it's -4.00 m/s2)
s = stopping distance (which we need to find)
Substituting the values we have:
0 = (15.0 m/s)2 + 2(-4.00 m/s2)s
Rearranging the equation to solve for s gives us:
s = (15.0 m/s)2 / (2 * 4.00 m/s2)
s = 225.00 m2/s2 / 8.00 m/s2
s = 28.125 meters
Therefore, the stopping distance of the car is 28.125 meters.
What happens to the magnitude of the charge on each plate of a capacitor if the potential difference between the conductors is doubled?
Answer:
The magnitude of charge on the each plate of the a capacitor will become two times larger.
Explanation:
The capacitor is a device that stores electrical energy and gives back the electrical energy to the circuit when needed ie it charges and discharges the electric charge stored in it.
The charges are of two types positive and negative.The charges on the conducting plates of a capacitor are equal in magnitude but opposite in charges.
The mathematical formula to calculate charge on the capacitor is
Q =CV,
Where Q is the initial charge,
C is the initial capacitance of the capacitor,
V is the initial potential difference
If the potential across the conductors is doubled the V =2 V,
Q =C2V
ie the magnitude of the charge is doubled.