Find the area of the shaded parts

The correct solution of the quadratic equation 3x^2 - x = 10 is found using the quadratic formula, giving two solutions x = -5/3 and x = 2.

The equation given is 3x2 − x = 10, which is a quadratic equation that needs to be rearranged to the standard form ax2 + bx + c = 0.

First, we subtract 10 from both sides of the equation, resulting in 3x2 − x − 10 = 0. Now, we can use the quadratic formula:

x = −b ± √(b2 - 4ac) / (2a)

Substituting the values a = 3, b = −1, and c = −10 into the formula yields:

x = −(−1) ± √((−1)2 - 4 × 3 × (−10)) / (2 × 3)

This simplifies to:

x = 1 ± √(1 + 120) / 6

Which further simplifies to:

x = 1 ± √121 / 6

And results in:

x = 1 ± 11 / 6

Therefore, the two solutions are:

x = 2 (1 + 11 / 6)

x = − five over three (1 − 11 / 6)

Hence, the correct answer is x = − five over three and x = 2.

The quadratic equation 3x^2 - x = 10 is solved via the quadratic formula, resulting in two solutions: x = 2 and x = -5/3 (or -1.67 when expressed as a decimal).

To solve the quadratic equation 3x2 − x = 10, we first need to set it to zero by subtracting 10 from both sides, yielding 3x2 − x − 10 = 0. This is a standard form quadratic equation, ax2 + bx + c = 0, where a = 3, b = -1, and c = -10. We can solve for x by using the quadratic formula, x = ∛ ( b2 - 4ac ) / (2a).

Plugging in our values, we get:

x = (-(-1) ± √ ( (-1)2 - 4(3)(-10) ) ) / (2(3))
x = (1 ± √ ( 1 + 120) ) / 6
x = (1 ± √ (121) ) / 6
x = (1 ± 11) / 6

Thus:

Therefore, the solutions are x = 2 and x = -5/3.

Answer: Total cost will be $398.15.

Step-by-step explanation:

Since we have given that

Cost of his equipment = $67.95

Cost of membership fees = $70

Cost of per hour =$5.50

For 40 hours,

Cost will be [tex]5.50\times 40=\$220[/tex]

Cost of per trip = $1.34

Cost for 30 trips will be

[tex]1.34\times 30=\$40.2[/tex]

According to question,

[tex]\$67.95+\$70+\$220+\$40.2=\$398.15[/tex]

Hence, total cost will be $398.15.

The correct equation to use is D. 233.10 = 102.15(1.086)^t, which represents how the value of the share increases over time assuming consistent growth. The growth factor is represented by (1.086)^t as the share is increasing by 8.6% quarterly.

The correct equation to determine how long it will take for the share to reach $233.10 is D. 233.10 = 102.15(1.086)^t.

This equation represents a classic compound interest formula that describes how an investment grows over time, where 102.15 is the initial share price, 1.086 is the quarterly growth rate (1+8.6%), and t is the number of quarters.

The equation shows that the future value, $233.10, is equal to the initial value, $102.15, multiplied by the growth factor, (1.086)^t, raised to the number of quarters.

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Let xbe a positive integer number. Then x, x+1 and x+2 are three positive consecutive integers (the first one is x, the second is x+1 and the third is x+2).

The product of the second integer and the third integer is (x+1)·(x+2) and is equal to 72. So you have the equation

[tex](x+1)\cdot (x+2)=72.[/tex]

Solve it:

[tex]x^2+2x+x+2=72,\\ \\x^2+3x+2-72=0,\\ \\x^2+3x-70=0,\\ \\D=3^2-4\cdot (-70)=9+280=289,\\ \\\sqrt{D}17,\\ \\x_1=\dfrac{-3-17}{2}=-10,\ x_2=\dfrac{-3+17}{2}=7.[/tex]

Solution [tex]x_1=-10[/tex] is extra because [tex]x_1[/tex] is negative.

Answer: three positive consecutive integers are 7, 8 and 9.

Final answer:

To determine the diameter of a circle with a circumference of 12.56 feet using π as 3.14, divide the circumference by π resulting in a diameter of 4 feet.

Explanation:

The student has asked to find the length of the diameter of a circle if the circumference is 12.56 ft using 3.14 for π (Pi). The formula for the circumference C of a circle is C = π * d, where d is the diameter of the circle. To find the diameter, we rearrange the formula to d = C / π. Substituting the given values, we get:

d = 12.56 ft / 3.14

After dividing the circumference by pi, we find that:

d = 4 ft

Therefore, the length of the diameter is 4 feet.

Final answer:

To measure the spread of data, you can use the range, variance, or standard deviation, which respectively measure the absolute difference between extremes, the average squared deviation from the mean, and the average deviation from the mean in the same units as the data.

Explanation:

The question refers to the methods used to measure the spread of data in a dataset. The spread, or variability, indicates how much the data points in a set differ from each other and from the central measures like the mean. There are several ways to quantify this spread, including:

The range, which is the difference between the largest and smallest values in the set.

The variance, which is the average of the squared differences from the mean.

The standard deviation, which is the square root of the variance and provides a measure of spread in the same units as the data.

Knowing the spread of data helps in understanding the distribution and consistency of the dataset, which is essential for statistical analysis.

The brightness of a light bulb in watts is considered continuous quantitative data as it represents measurable amounts that can vary and take on any value within a range.

The brightness of a light bulb, measured in watts, represents the power it uses and is an example of quantitative data. Since wattage can take on any positive value and is not restricted to whole numbers (for example, a bulb can be rated at 60.5 watts), it is considered to be continuous quantitative data. Unlike discrete data, which involve counts that must be whole numbers, continuous data can include any value within a range. Hence, when comparing the brightness of light bulbs by their wattage, one is dealing with continuous quantitative data.

Look at changes of signs to find this has 1 positive zero, 1 or 3 negative zeros and 0 or 2 non-Real Complex zeros.

Then do some sums...

f(x)=−3x4−5x3−x2−8x+4

Since there is one change of sign, f(x) has one positive zero.

f(−x)=−3x4+5x3−x2+8x+4

Since there are three changes of sign f(x) has between 1 and 3 negative zeros.

Since f(x) has Real coefficients, any non-Real Complex zeros will occur in conjugate pairs, so f(x) has exactly 1 or 3 negative zeros counting multiplicity, and 0 or 2 non-Real Complex zeros.

f'(x)=−12x3−15x2−2x−8

Newton's method can be used to find approximate solutions.

Pick an initial approximation a0 .

Iterate using the formula:

ai+1=ai−f(ai)f'(ai)

Putting this into a spreadsheet and starting with a0=1 and a0=−2 , we find the following approximations within a few steps:

We can then divide f(x) by (x−0.42) and (x+2.195) to get an approximate quadratic −3x2+0.325x−4.343 as follows:

Notice the remainder 0.013 of the second division. This indicates that the approximation is not too bad, but it is definitely an approximation.

Check the discriminant of the approximate quotient polynomial:

Since this is negative, this quadratic has no Real zeros and we can be confident that our original quartic has exactly 2 non-Real Complex zeros, 1 positive zero and 1 negative one.

Answer:

Positive: 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0

The optimum angle at which a projectile should be launched to cover maximum distance is 45°. This angle gives the projectile the greatest range by maximizing the time of flight.

The optimum angle at which a projectile should be launched in order to cover the maximum distance is 45°. This launch angle gives the projectile the greatest range.

To understand why this angle is optimal, we can consider that the motion of a projectile can be divided into two independent components: horizontal and vertical. The range of a projectile is maximized when the time it spends in the air is maximized. At a launch angle of 45°, the horizontal and vertical components of the projectile's velocity are equal. This means that the time of flight is maximized, resulting in the maximum range.

For example, if a projectile is launched at a shallower angle, such as 30°, the vertical component of the velocity is decreased, reducing the time of flight and therefore the range. Similarly, if the projectile is launched at a steeper angle, such as 60°, the horizontal component of the velocity is decreased, again reducing the time of flight and range.

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