Find the volume of the prism. 192 cu. ft. 64√(13) cu. ft. 96 cu. ft.

 Find The Volume Of The Prism. 192 Cu. Ft. 64(13) Cu. Ft. 96 Cu. Ft.

Answers

Answer 1
The answer is 96 cu. ft
Answer 2

Given is a Right Triangular Prism whose height is 8 feet, and whose base is a right triangle with legs 4 feet and 6 feet.

To find the volume of the prism, we must find the area of its base. Its base is in shape of right triangle. We know the formula for area of Right triangle is given as follows :-

[tex] Area = \frac{1}{2} bh \\\\
Area = \frac{1}{2} *4*6 \\\\
Area = \frac{24}{2} \\\\
Area = 12 \;\;feet^{2} [/tex]

So Prism's base area, B = 12 squared feet.

and Prism's height, H = 8 feet.

We know the formula for volume of Prism is given as follows :-

Volume of Prism = (Base Area) x (Height of Prism)

Volume = B x H

Volume = 12 feet² x 8 feet

Volume = 96 feet³

Hence, option C is correct i.e. 96 cubic feet.


Related Questions

An initial investment of $200 is now valued at $350. The annual interest rate is 8% compounded continuously. The equation mc022-1.jpg represents the situation, where t is the number of years the money has been invested. About how long has the money been invested? Use a calculator and round your answer to the nearest whole number.

Answers

Answer:

7 years

Step-by-step explanation:

An initial investment of $200 is now valued at $350.

The annual interest rate is 8% compounded continuously.

Formula:

[tex]A=Pe^{rt}[/tex]

Where,

A is amount, A=350

P is principle, P=200

R is rate of interest, r=0.08

t is time, t=?

Substitute the value into formula

[tex]350=200e^{0.08\cdot t}[/tex]

[tex]e^{0.8t}=1.75[/tex]

Taking ln both sides

[tex]0.08t = ln(1.75)[/tex]

[tex]t=6.99\approx 7[/tex]

Hence, 7 years ago money was invested.

Answer:

Its 7 years

Step-by-step explanation:

WORTH 20 POINTS!!
The endpoints of one diagonal of a rhombus are (0, -8) and (8, -4). If the coordinates of the 3rd vertex are (1, 0), what are the coordinates of the 4th vertex? (7, -12)
(7, -8)
(-8, -4)
(-4, -12)

Answers

Think about this problem as follows:

The rhombus consists of two lines which connecting the endpoints which are intersecting each other. If you have the slopes of these, you can create a relation which says that
[tex]k_1 \cdot k_2 = -1[/tex]
where [tex]k_i[/tex] are the slopes of the lines.

Now you have one slope, which is [tex]k_1 = \frac{-8 - (-4)}{0-8} = \frac{1}{2}[/tex] which means that the slope of the other one has to be

[tex]k_2 = -1 \cdot 2 = -2[/tex]

Given that you have the point (1,0) its trivial to see that this is satisfied by the point (7,-12)[tex]k_2 = \frac{-12-0}{7-1}=\frac{-12}{6} = -2[/tex]

Its worth noting that you want to draw the points, that you have the correct order when you calculate the slope.

Determine the volume of the pencil

Answers

we have that 
[Volume of the pencil]=[Volume of cylinder]+[volume of cone]
[Volume of cylinder]=pi*(0.5²)*15=11.78 cm³
[volume of cone]=pi*(0.5²)*2/3=0.52 cm³
[Volume of the pencil]=[11.78]+[0.52]=12.30 cm³

the answer is 12.30 cm³

The volume of the pencil is approximately 4.05 cm³.

To determine the volume of the pencil, we need to calculate the volumes of the cylindrical body and the conical tip separately and then add them together.

Volume of the cylindrical body:

The formula for the volume of a cylinder is [tex]V = \pi r^2h[/tex], where r is the radius and h is the height.

[tex]V_{cylinder} = \pi (0.5 cm)^2 * 15 cm[/tex]

Volume of the conical tip:

The formula for the volume of a cone is [tex]V = (1/3)\pi r^2h[/tex], where r is the radius and h is the height.

[tex]V_{cone} = (1/3) * \pi (0.5 cm)^2 * 2 cm[/tex]

Now, we can calculate the volumes:

[tex]V_{cylinder} = \pi * (0.5 cm)^2 * 15 cm = 3.53 cm^3\\\\V_{cone} = (1/3) * \pi * (0.5 cm)^2 * 2 cm = 0.52 cm^3[/tex]

Finally, we can add the volumes of the cylindrical body and the conical tip to get the total volume of the pencil:

[tex]Total\ volume = V_{cylinder} + V_{cone} = 3.53 cm^3 + 0.52 cm^3 = 4.05 cm^3[/tex]

Therefore, the volume of the pencil is approximately 4.05 cubic centimeters ([tex]cm^3[/tex]).

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A test is worth 140 points. Ten percent of those points are from one short-answer question. How many points is the short-answer question worth?

Answers

If the total amount of points in a test is 140, and we want to find 10% of those points, we can do the following to figure out how much points the question is worth...

140 points x 10% = 140 x 0.1 = 14 points for the short-answer quesion.

The short-answer question worth of 14 points.

What is unitary Method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

Total points of test =140

and 10 % of those points are from one short-answer question.

So, the points for short-answer question are

=10 % of 140

=10/100 x 140

=1400/100

=14

Hence,  short-answer question worth of 14 points.

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The perimeter of an equilateral triangle with a side of 6 inches is
12 in.
18 in.
36 in.

Answers

equilateral means all sides are equal. perimeter is all sides added up. 6+6+6 = 18

Using radicals , write an equivalent expression for the expression 2 1/3

Answers

I'm assuming that the 1/3 is an exponent.

If so, then [tex]2^{1/3} = \sqrt[3]{2}[/tex]

Which is the cube root of 2. Raising any value to the 1/3 power is the same as taking the cube root.

I'm assuming that the 1/3 is an exponent.

If so, then  

Which is the cube root of 2. Raising any value to the 1/3 power is the same as taking the cube root.

Which function is a shrink of the exponential growth function shown on the graph?
A.) f(x) = 2(3)x
B.) f(x) = 1/2(3)x
C.) f(x) = 2(1/3)x
D.) f(x) = 1/2(1/3)x 

Answers

The exponential function shown in the graph is 3^x, so (1/2)3^x is a shrink of it.

Selection B is appropriate.

Rene has a coupon for $3.25 off a package of name brand cookies that normally costs $7.89. The store brand cookies coats $5.58. How much will Rene save if she uses her coupon and buys the name brand cookies instead of the store brand cookies? HELP

Answers

she would save 94 cents buying the name brand cookies
Final answer:

Rene will save $0.94 if she uses her coupon and buys the name brand cookies instead of the store brand cookies.

Explanation:

To find out how much Rene will save if she uses her coupon and buys the name brand cookies instead of the store brand cookies, we have to first determine how much the name brand cookies will cost after applying the coupon. We subtract the value of the coupon i.e. $3.25 from the original cost of name brand cookies which is $7.89. The result comes out to be $4.64.

To calculate the savings, we now have to subtract the cost of name brand cookies after coupon ($4.64) from the original cost of the store brand cookies ($5.58). Hence, the savings amount to $5.58 - $4.64 which equals $0.94

So, if Rene uses her coupon and buys the name brand cookies instead of the store brand cookies, she will save $0.94.

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Find the volume of this square pyramid, given that its height is 8 m.

A) 24 m3.

B) 72 m3.

C) 216 m3.

D) 648 m3.

Answers

Answer:

A) [tex]24\text{ m}^3[/tex].

Step-by-step explanation:

We have been given an image of a square pyramid and we are asked to find the volume of our given pyramid.

[tex]\text{Volume of square pyramid}=\frac{a^2*h}{3}[/tex], where,

a = Base length of square,

h = height of pyramid.

Upon substituting our given values in above formula we will get,

[tex]\text{Volume of square pyramid}=\frac{\text{(3 m)}^2*\text{ 8 m}}{3}[/tex]

[tex]\text{Volume of square pyramid}=\frac{9\text{ m}^2*\text{ 8 m}}{3}[/tex]

[tex]\text{Volume of square pyramid}=\frac{72\text{ m}^3}{3}[/tex]

[tex]\text{Volume of square pyramid}=24\text{ m}^3[/tex]

Therefore, the volume of our given square pyramid is 24 cubic meters and option A is the correct choice.

Answer:

A. 24 m3.

Step-by-step explanation:

PLEASE HELP ASAP!!!

Answers

the correct answer is A because if you add 200 and 85 together to get the amount of money he has to have, and then divide that by 45, you get 13 weeks
The correct answer is A

How do I solve and graph this?

Answers

3x -y ⩾ 6

3x - 6 ⩾ y

now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".

if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,

3(4) - 0 ⩾ 6

12 - 0 ⩾ 6

12 ⩾ 6   

is 12 really greater or equals to 6?  well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.

now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.

check the picture below.

what is the approximate distance between the points (1 -2) and (-9 3) on a coordinate grid?

Answers

[tex]d= \sqrt{(-9-1)^2+(3-(-2))^2}= \sqrt{100+25}= \sqrt{125} \approx 11.18 \ \ \text{units}[/tex]

Answer:

11.18

Step-by-step explanation:

Who worthy the book “I love fractions”

Answers

I’m guessing we’ll the whole main thing is about Fractions isn’t it?

Consider the diagram. What is the length of segment AB?

Answers

B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks. 

we know that

A median of a triangle is a line segment joining a vertex to the midpoint of the opposing side, bisecting it.

In this problem the line DB is a median of triangle ADC

The line DB is also the altitude of a triangle ADC, because is perpendicular to the side AC

so

AB=BC

we have that

[tex]BC=9\ units[/tex]

therefore

[tex]AB=9\ units[/tex]

the answer is the option

[tex]9[/tex]


The half-life of iodine-123 is about 13 hours. You begin with 52 grams of iodine-123. (a) Write an equation that gives the amount of iodine-123, I , remaining after t hours. Write your answer in the form I ( t ) = a ⋅ b t . Round your answer for b to three decimal places.

Answers

Final answer:

The amount of iodine-123 remaining after t hours can be expressed as I(t) = 52 · 0.945^t, where the constant 0.945 is calculated using the half-life of 13 hours.

Explanation:

The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms to decay. For iodine-123, which has a half-life of approximately 13 hours, we can use an exponential decay model to express the amount of iodine-123 remaining after t hours.

The decay formula is generally given by I(t) = I0e-kt, where I0 is the initial amount, k is the decay constant, and t is time. However, the question asks us to express the equation in the form of I(t) = a · bt, which is another common representation for exponential decay.

To find the value of b, we know that after one half-life, b13 = 1/2. Thus, b = (1/2)1/13.
Let's calculate b: b = (0.5)1/13 ≈ 0.945 (rounded to three decimal places).

Since we start with 52 grams of iodine-123, our initial amount (a) is 52. Therefore, the equation for the amount of iodine-123 remaining after t hours is:

I(t) = 52 · 0.945t

Final answer:

The equation to calculate the amount of iodine-123 remaining after t hours is I(t) = a * b^t, where a is the initial amount of iodine-123, b is the decay constant, and t is the time in hours. The decay constant can be calculated using the formula b = 0.693 / t1/2, where t1/2 is the half-life of iodine-123. In this case, the half-life is 13 hours.

Explanation:

The equation that gives the amount of iodine-123 remaining after t hours can be written as:

I(t) = a * b^t

Where:

I(t) is the amount of iodine-123 remaining after t hoursa is the initial amount of iodine-123b is the decay constant, which can be calculated using the half-life formulat is the time in hours

To calculate the decay constant b, we can use the formula:

b = 0.693 / t1/2

where t1/2 is the half-life of iodine-123. In this case, the half-life is 13 hours, so:

b = 0.693 / 13 = 0.053

Therefore, the equation becomes:

I(t) = a * 0.053^t

Round the value of b to three decimal places, so b = 0.053.

Kathleen has been tracking how fast she walks over the last month and determined that she walks 1 1/4 miles in 2/5 of an hour. Lynn has been tracking how fast she walks over the last few weeks and determined that it takes her 19 minutes and 12 seconds to walk 1 mile. Part A: Write both Kathleen's and Lynn's walking rate in the same format, either miles per hour, miles per minute, minutes per mile, or hours per mile and compare their rates to each other. Part B: Give a logical argument on why that format was chosen over the other three.

Answers

A:


K: 24 minutes per 2 3/4 miles
L: 19.12 minutes per mile


B:


I chose minutes per mile because it was already being used for one of them so it takes less work.

negative 1 over 2x + 2 = −x + 7

Answers

Multiply by the denominator and solve the resulting quadratic.
.. -1/(2x +2) = -x +7
.. -1 = (2x +2)(-x +7)
.. 2x^2 -12x -15 = 0
And from the quadratic formula
.. x = (12 ±√((-12)^2 -4(2)(-15)))/(2(2))
.. x = 3 ±√16.5

x ≈ -1.062019 or 7.062019

Solve the system of equations using the linear combination method.

{9x+5y=35
{2x+5y=0



Enter your answers in the boxes.

x =_

y =_

Answers

(5,-2)
please mark as brainliest 
hope it helps
the answer was 5, -2 thx

Find the first six terms of the sequence.
a1 = -4, an = an-1 + 7

-4, 3, 10, 17, 24, 31
-4, 7, 14, 21, 28, 35
3, 10, 17, 24, 31, 38
0, 7, 14, 21, 28, 35

Answers

I think it is the first option

Answer: A) -4, 3, 10, 17, 24, 31

Step-by-step explanation: To solve the given problem we need to calculate the first six terms of the sequence (starting with a1):

a1=-4

a2=a1+7

a2=-4+7

a2=3

a3=a2+7

a3=3+7

a3=10

a4=a3+7

a4=10+7

a4=17

a5=a4+7

a5=17+7

a5=24

a6=a5+7

a6=24+7

a6=31.

A farmer has a collection of chickens and dogs. all together there are 120 legs and 43 heads. how many of each animal does he have? answer

Answers

Using trial and error method,

(26*2)+(17*4)=120 legs
26 chickens and 17 dogs

Number of chicken = 26

And, Number of dogs = 17

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

A farmer has a collection of chickens and dogs.

And, all together there are 120 legs and 43 heads.

Hence, Number of chicken = x

And, Number of dogs = y

Thus, We get;

⇒ x + y = 43  

⇒ x = 43 - y .. (i)

⇒ 2x + 4y = 120

⇒ x + 2y = 60 .. (ii)

Substitute value of x from (i) to (ii);

⇒ x + 2y = 60

⇒ 43 - y + 2y = 60

⇒ y = 60 - 43

⇒ y = 17

And, From (i);

⇒ x = 43 - y

⇒ x = 43 - 17

⇒ x = 26

Thus,  Number of chicken = 26

And, Number of dogs = 17

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Which expression can you simplify by combining like terms? Clear Check 6 d 2 +5cd−3dc+8 6d2+5cd-3dc+8 12 c 2 −8 d 2 c+3dc+4 12c2-8d2c+3dc+4 7 d 2 −3 c 2 +6d−c 7d2-3c2+6d-c 16 c 2 +8cd+7c−8d 16c2+8cd+7c-8d

Answers

Final answer:

The expression that can be simplified by combining like terms is 16 c^2 + 8cd + 7c - 8d, where 8cd and -3dc are like terms and can be combined to simplify the expression to 16c^2 + 5cd + 7c - 8d.

Explanation:

The expression 16 c2 + 8cd + 7c - 8d can be simplified by combining like terms. Like terms in an algebraic expression are terms that have the same variable raised to the same power. Here, the terms 8cd and -3dc are like terms and can be combined.

Here's the step-by-step simplification:

First, identify like terms in the expression. In 8cd and -3dc, since multiplication is commutative (meaning ab = ba), cd and dc are essentially the same term. So, 8cd and -3dc can be combined.Combine the like terms by adding their coefficients. For 8cd and -3dc, we have 8 - 3 to get 5cd.Now, the simplified expression is 16c2 + 5cd + 7c - 8d.

This process of combining like terms helps in simplifying algebraic expressions, making them easier to work with.

After combining like terms, it's important to always check the answer to see if the simplification is reasonable and if there are any other like terms that can be combined.

So, the simplified expressions are:

1. [tex]\(6d^2 + (5c - 3d)d + 8\)[/tex]

2. [tex]\(12c^2 - (c(8d - 3)) + 4\)[/tex]

3. [tex]\(7d^2 - 3c^2 + 6d - c\)[/tex]

4. [tex]\(16c^2 + c(8d + 7) - 8d\)[/tex]

Let's simplify each expression by combining like terms:

1. [tex]\(6d^2 + 5cd - 3dc + 8\)[/tex]

  Combine like terms:

  [tex]\(6d^2 + (5cd - 3dc) + 8\)[/tex]

 [tex]\(6d^2 + (5c - 3d)d + 8\)[/tex]

2. [tex]\(12c^2 - 8d^2c + 3dc + 4\)[/tex]

  Combine like terms:

[tex]\(12c^2 - (8d^2c - 3dc) + 4\)[/tex]

  [tex]\(12c^2 - (c(8d - 3)) + 4\)[/tex]

3. [tex]\(7d^2 - 3c^2 + 6d - c\)[/tex]

  No like terms to combine.

4. [tex]\(16c^2 + 8cd + 7c - 8d\)[/tex]

  Combine like terms:

  [tex]\(16c^2 + (8cd + 7c) - 8d\)[/tex]

  [tex]\(16c^2 + c(8d + 7) - 8d\)[/tex]

Five is a solution of (Y < -3)

A.True

B.False

Answers

This is false. 

The integer '5' has a higher value than -3 as it leans on the right side of a number scale, while -3 sits on the left side.

I hope this helps!

Use k as the constant of proportionality to write the equation expressing the relationship: y varies inversely as x. if y = 10 when x = 5, determine k.

Answers

For an inverse relationship of the form 
[tex]y= \dfrac{k}{x} [/tex]
you can solve for k, the constant of variation (or proportionality), by multiply both sides of the function to get [tex]xy=k[/tex]. Substituting 5 for x and 10 for y, you see that k = 50.

y = k/x

Step-by-step explanation:

Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is also 53. 6f – 1 evaluated at f = 3 is 17. what is 2f + 4f + 2 – 3 evaluated at f = 3?

Answers

we have that

the expression 2f + 4f + 2 – 3-------> we can group it   (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

let's check it
[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok

Answer: 17

Step-by-step explanation:

The band is selling wrapping paper for a fundraiser. Customers can buy rolls of plain wrapping paper and rolls of shiny wrapping paper. The band sold a total of 55 rolls and made $950. If a roll of plain wrapping paper cost $14 and a roll of shiny cost $20, how many rolls of each did they sell ?

Answers

x= # plain rolls
y= # shiny rolls

QUANTITY EQUATION:
x+y=55

COST EQUATION:
$14x + $20y= $950

SOLVE:
Solve for one variable in quantity equation. Substitute that answer in cost equation.

STEP 1:
x+y=55
subtract y from both sides
x= 55-y

STEP 2:
$14x + $20y= $950
14(55-y) + 20y= 950

multiply 14 by all in parentheses
(14*55)+(14*-y) + 20y= 950
770-14y+20y= 950

combine like terms
770+6y= 950

subtract 770 from both sides
6y= 180

divide both sides by 6
y= 30 shiny rolls

STEP 3:
Substitute y answer in either equation to solve for x.

x+y=55
x+30=55
subtract 30 from both sides
x= 25 plain rolls

Hope this helps! :)

The roll of plain wrapping paper sold is  25.

The  roll of shiny wrapping paper sold is 30.

What are the linear equations that represent the question?

a + b = 55 equation 1

14a + 20b = 950 equation 2

Where:

a =  roll of plain wrapping paper sold

b = roll of shiny wrapping paper sold

What is the roll of shiny wrapping paper sold?

Multiply equation 1 by 14

14a + 14b = 770 equation 3

Subtreact equation 3 from equation 2

6b = 180

Divide both sides by 6

b  = 30

What is the roll of plain wrapping paper sold?

Subtract 30 from 55

55 - 33 = 25

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Select all that have a value of 0.  

Answers

Answer:

It's 1,3, and 5.

The functions that have  a value of 0 are : [tex]cos(\frac{\pi}{2} ),~sin(0),~tan(\pi)[/tex]

What is function?"It defines a relation between input and output values.""In function for each input there is exactly one output."

For given question,

We have been given some trigonometric functions.

We need to find the functions that have a value zero.

[tex]i)~cos(\frac{\pi}{2} )=0\\\\ii)~cos(0)=1\\\\iii)~sin(0)=0\\\\iv)sin(\frac{3\pi}{2} )=-1\\\\v)tan(\pi)=0[/tex]

From above, we can observe that functions [tex]cos(\frac{\pi}{2} ),sin(0)[/tex] and [tex]tan(\pi)[/tex] have a value of zero.

Therefore, the functions that have  a value of 0 are : [tex]cos(\frac{\pi}{2} ),~sin(0),~tan(\pi)[/tex]

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If three tangents to a circle form an equilateral triangle, prove that the tangent points form an equilateral triangle inscribed in the circle

Answers

I added a figure so you can guide yourself throughout the proof I'm about to write, so I recommend that you download the picture beforehand and have this window and the picture's window open. Alright, let's get started!
Assuming that [tex]FED[/tex] is an equilateral triangle according to the wording of the problem, we have that the angles [tex]\widehat{AFB}=\widehat{BEC}=\widehat{CDA}=60[/tex].
We also know that the circle in green is Inscribed in [tex]FED[/tex].

The following applies to every inscribed circle inside a triangle:
The center of the inscribed circle of a triangle is the intercept of all three angle bisectors of the triangle.

The above theorem implies that the line [tex](FO) [/tex] is an angle bisector because it goes through the vertex F and the center of the inscribed circle.

The previous statement implies that the angle [tex]\widehat{OFB}=30[/tex].

Now let's work on the [tex]OFB[/tex] triangle.
Knowing that [tex]\widehat{OBF}=90[/tex] (because [tex](EF)[/tex] is tangent to the circle at B and [tex]OB[/tex] is a radius of the circle. If you're lost here, remember that a tangent to a circle is always perpendicular to the radius of the circle.) we can then derive that [tex]\widehat{FOB}=180-90-30=60[/tex] (because the sum of the measures of all angles in a triangle is always equal to 180 degrees).

In the same way, we can prove also that:
[tex]\widehat{BOE}=\widehat{EOC}=\widehat{COD}=\widehat{DOA}=\widehat{AOF}=60 degrees[/tex].
Knowing the above we notice that [tex]\widehat{BOC}=\widehat{COA}=\widehat{AOB}=120degrees[/tex].

We're at the last part of our proof here:
Now notice that [tex]\widehat{BOA}[/tex] subtends the same arc on the circle  that [tex]\widehat{BCA}[/tex].
According to the inscribed angle theorem, an angle [tex]\theta[/tex] inscribed in a circle is half of the central angle [tex]2\theta[/tex] that subtends the same arc on the circle. 
Therefore [tex]\widehat{BCA}=\frac{\widehat{BOA}}{2}=60degrees[/tex]

We can prove in a similar fashion that:  [tex]\widehat{CAB}=\widehat{ABC}=60degrees[/tex] 
Therefore all the angles of the [tex]ABC[/tex] triangle have a measure of 60 degrees, we conclude then that  [tex]ABC[/tex] is equilateral.


Given: What type of angles are ∠2 and ∠3 are adjacent angles.
Which of the following options describes the adjacent angles in terms of their sum? complementary angles, 90° complementary angles, 180° supplementary angles, 90° supplementary angles, 180°

Answers

The correct answer is:  [D]:  "supplementary angles, 180° " .
_____________________________________________________
Note:  

Choices:
_____________________________________________________
   [B]:  "complementary angles, 180° " ; and:
_____________________________________________________
   [C]:  "supplementary angles, 90° "  ;  
_____________________________________________________
can automatically be ruled out ; since by definition:

     →  Complementary angles always add up to 90° — NOT 180° ; 
and:   supplementary angles always add up to 180° — NOT 90° .
_____________________________________________________
Note:  "Adjacent angles" refer to "supplementary angles" ; which, by definition add up to 180° .  Futhermore, looking at the image provided,

we see that ∠1 and ∠2 are, in fact "adjacent" and that ∠1 and ∠2 comprise the entire portion of a "straight line" (being intersected by a transversal)" ;  

  and as such;  ∠1 and ∠2 are supplementary angles—
 
  and as such—add up to 180° .

(which rules out:  Choice [A]:  "complementary angles, 90°) ; 

→  and demonstrates the correct answer:
______________________________________________________
Answer choice:  [D]:  "supplementary angles, 180° " .
 ______________________________________________________

Final answer:

Adjacent angles can be either complementary or supplementary depending on their sum. Complementary angles add up to 90°, while supplementary angles sum to 180°. The term for adjacent angles in terms of their sum is 'supplementary angles', adding up to 180°.

Explanation:

Adjacent angles are two angles that have a common side and vertex, and don't overlap. In terms of their sum, if adjacent angles add up to 90 degrees, they are called complementary angles. If they add up to 180 degrees, they are called supplementary angles. Since the question involves angles ∠2 and ∠3 as adjacent angles but does not provide their specific measures, it's not possible to definitively classify them as complementary or supplementary without additional information. However, the question asks which term describes adjacent angles in terms of their sum. The correct answer is supplementary angles, which have a sum of 180°.

Which of the following inequalities is best represented by this graph?

5x + y ≤ 2
5x + y ≥ 2
5x − y ≤ 2 
5x − y ≥ 2

Answers

For this case, the first thing to do is find the equation of the line correctly and then see which of the inequalities represents the shaded region.
 We have then:
 5x - y = 2
 For x = 0 
 5 (0) - y = 2
 -y = 2
 y = -2
 For y = 0
 5x - 0 = 2
 5x = 2
 x = 2/5 = 0.4
 Therefore the line is:
 5x - y = 2 
 Then, we see that for the point (0, 0)
 5x - y ≥ 2
 5 (0) - (0) ≥ 2
 0 ≥ 2
 The inequality is not met, which is correct because this point is not part of the shaded region.
 Answer:
 The inequality that best is represented by the graph if: 
 5x - y ≥ 2

Answer:the answer is d

Step-by-step explanation:

5x - y ≥ 2

If you wanted to predict the value of the y variable when the x variable is 15, you would be _____ the data.

A.) Correlating
B.) Extrapolating
C.) Interpolating

Answers

B) extrapolating ...

Answer:

If you wanted to predict the value of the y variable when the x variable is 15, you would be extrapolating the data.

Step-by-step explanation:

If you wanted to predict the value of the y variable when the x variable is 15, you would be Extrapolating the data.

Extrapolation means, estimating the value of a variable beyond its given range.

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