Find the width (w)of a rectangular room with a length (l) of 60 meters and an area (a) of 2,400 square meters

my brain tells me that the Correct answer is B my duuuuuuuddddeee

For this case we have the following data:

If we divide the volume of the container between the volume of the boxes, we obtain the number of boxes that fit in the container. Therefore:

[tex]\frac{50.148}{2.786}=18[/tex]

Answer:

the shipping container holds:

Option D

Answer:

168  which is not listed

Step-by-step explanation:

Do what is inside the brackets first. Subtract the two terms

52 - 10 = 42

Now multiply by 4

42 * 4 = 168 which is none of your answers. There must be more to the problem.

-68x + p = qx + 34

p - 34 = qx + 68x    added 68x to both sides & subtracted 34 from both sides.

p - 34 = x(q + 68)

[tex]\frac{p - 34}{q + 68} = x[/tex]

The denominator cannot be equal to zero so q + 68 ≠ 0   ⇒   q ≠ -68

You didn't upload the options but look for the one that has q = -68.

about 3 beats per second

note 1 minute = 60 seconds

divide beats per minute by 60 for beats per second

[tex]\frac{200}{60}[/tex] = 3.333.... ≈ 3 beats per second

To estimate Camila's heart beats per second, divide her target heart rate of 200 bpm by 60 to get 3.33 beats per second.

To estimate the number of times Camila's heart will beat in one second, we need to convert her target heart rate from beats per minute (bpm) to beats per second. To do this, we divide her target heart rate by 60 (since there are 60 seconds in a minute). So, for Camila, her target heart rate in beats per second would be:

200 bpm ÷ 60 = 3.33 beats per second

Therefore, Camila's heart will beat approximately 3.33 times in one second.

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If you look at the circle, center is B. It's located right in the center of the circle.

Answer

A. B

The center of the circle in the given figure is B.

Option A is the correct answer.

A circle is a two-dimensional figure with a radius and circumference of 2πr.

The area of a circle is given as πr².

We have,

The given figure has:

AB = radius

Ay = chord

B is the center

Thus,

The center of the circle is B.

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Yes, there is.

Two variable are in a proportional relationship if one is a multiple of other, i.e. if their ratio is constant.

In fact, two equivalent ways of saying that x and y are in a proportional relationship are saying that there exists a number k such that

[tex] y = kx\quad\text{or}\quad \dfrac{y}{x}=k [/tex]

In this case, you can see that the perimeter is always three times the side, which makes sense, because the perimeter of an equilateral triangle is composed of three "copies" of the side of the triangle.

So, the perimeter is a multiple of the side (with k=3), and in fact you have

[tex] p = 3s \iff \dfrac{p}{s} = 3 [/tex]

which are the two equivalent ways of saying that p and s are in a proportional relationship.

Yes, there is a proportional relationship between the perimeter and the side length of an equilateral triangle as indicated by the equation p = 3s. If you double the side length, the perimeter also doubles.

Yes, there is a proportional relationship between the perimeter and the side length of an equilateral triangle. This can be observed from the equation p = 3s, which indicates that the perimeter is always three times the length of each side. In terms of proportionality, if you double the side length of the triangle (for instance), the perimeter also doubles. This is because the three sides of an equilateral triangle are of equal length, so any change in side length will cause a proportional change in the perimeter.

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The initial number of transactions that took place in the first hour of Monday, which was 10, will not have any impact or bearing on the transactions for the rest of the day. Likewise, the initial number of transactions will not be affected by any other transactions or any other parameter. Thus, we can safely say that the initial number of transactions is neither an independent or a dependent variable.

Thus, out of the given options, Option C is the correct answer.

a) substitution   (refer to statements 1 and 2)

b) definition of supplementary

c) subtraction property of equality

We are given the equation:

[tex]6(x-5)^{4}+4(x-5)^{2}+6=0[/tex]..........(1)

Now we have to write it in quadratic form using substitution.

The general form of quadratic equation is given by:

[tex]ax^{2}+bx+c=0[/tex]

So let us say

[tex](x-5)^{2}=u[/tex].......(2)

Plugging the value of (x-5)² from equation (2) in (1),

[tex]6u^{2}+4u+6=0[/tex]

Answer : Option B. [tex]6u^{2}+4u+6=0[/tex]

Answer:

B

Step-by-step explanation:

you need a lot to explain

The graph of the line is obtained as the straight line passes through (-2.667,0) and (0,2).

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

A linear equation has the form y = mx + b in the slope-intercept format. X and Y are the variables in the equation. The values m and b represent the line's slope (m) and the value of y when x is 0.

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

It is given that, the equation of the line is f(x)=3/4x+2.

We have to draw the graph using the two points. The point through which the line passes.

The slope of the given line is -3/4 and having an intercept of 2.

Thus, the graph of the line is obtained as the straight line passes through (-2.667,0) and (0,2).

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To graph the line y = (3/4)x + 2, choose two points and connect them by drawing a straight line.

To graph the line y = (3/4)x + 2, we can select two points and connect them. Let's choose the points (0, 2) and (4, 5). Substitute the x-values into the equation to find the corresponding y-values:

Plot these two points on the graph and draw a straight line passing through them. Label the graph with f(x) and x.

-3x + 2y + z = -6

(3)x + 3y + 2z = 5(3) We want to get rid of any variable within 2 equations. The easiest one would be by multiplying both sides of eq#2 by 3 and add it to eq#1.

-3x+2y+z=-6

3x+9y+6z=15

Add them together to get 11y+7z=9

(-4)x+3y+2z=5(-4) Now,multiply the original eq#2 by -4 to cancel out x in the last equation

-4x-12y-8z=-20

4x + 4y + 3z = 13

add them together to get -8y-5z=-7

Now multiply the eq 11y+7z=9 by 5 and the equation -8y-5z=-7 by 7 to cancel out the z variable when we add them together.

Once we multiply them, we get

-56y-35z=-49

55y+35z=45

add them together to get -y=-4 and we know y=4

substitute y into any equation here that has y and any other 1 variable like -8y-5z=-7 and get z=-5

Finally, we know y=4 and z=-5, we can substitue that into any of the original eqs like  -3x + 2y + z = -6 and we get x=-3

To check, just substitute these values into any of the equations above

Answer:

Option (a) is correct.

The interest that Perry will earn each month on $650 is $ 2.70

Step-by-step explanation:

Given : Perry earns 5 percent simple interest annually on his savings account.

We have to determine the interest that  Perry will earn each month on $650.

Since, Given Perry rate of interest is 5%

So , her monthly rate of interest will be [tex]\frac{5}{1200}[/tex]

Using Formula for Simple interest

[tex]S.I = P\times r\times t[/tex]

Thus, for principal $ 650 at rate of interest [tex]\frac{5}{1200}[/tex] for one month .

Perry interest will be,

[tex]S.I.=650\cdot\frac{5}{1200}\cdot1[/tex]

Simplify, we get ,

Simple interest = $ 2.70

Thus, The interest that Perry will earn each month on $650 is $ 2.70

THE ANSWER IS 24

A and b are in parenthesis and there is no sign next to them, so you automatically have to multiply.

If that is supposed to be ab^2 then:

First you multiply 4 and 3 to get 12.

Then you multiply 12 by itself to get 144.

If it is supposed to be 2ab then:

First multiply 4 and 3 to get 12.

Then multiply 12 and 2 to get 24.

there is a 1:8 ratio so there will be 40 nickels and 5 dimes

So the y would be hopefully that helps you ❤.

y = 2/9

2/3+y-1/9=7/9

=> 2/3+y=7/9+1/9

=> 6/9+y=8/9

So, y=2/9

Two decimals equivalent to 8.1 are 8.100 and 8.10. Zeroes added after the decimal do not change the value. 08.1 is also equivalent to 8.1 as a zero before the decimal does not alter the value.

Two decimals equivalent to 8.1 could be represented as 8.100 and 8.10. The reason for this is that adding zeros at the end of a decimal does not change its value. So, 8.100, 8.10, and 8.1 all represent the same decimal value.

Similarly, we can place a zero before the decimal, then 08.1 would be equivalent to 8.1. Note that the zero that comes before the decimal point does not change the actual value of the number.

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Think that the domain is n=1.

Answer:

n belongs to set of natural numbers

Step-by-step explanation:

Given the geometric sequence

[tex]a_n = 2(−3)^n − 1,[/tex]

Here an denotes the nh term.

Naturally, n cannot be 0 or negative.

Because the first term has n =1, and so on.

Domain for n is the set of all natural numbers

n = 1,2,3.....

The number after rounded to nearest whole number is,

⇒ 28

We have to given that,

To round the number 28.37 nearest whole number.

Since, Rounding numbers refers to changing a number's digits such that it approximates a value. The provided number is more simply represented by this value.

Here, Number is,

28.37

Since, 3 < 5

Hence, The number after rounded to nearest whole number is,

⇒ 28

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∠BEC ≅ ∠CED          definition of angle bisector

∠BEC = ∠CED           definition of congruency

∠AEB , ∠BEC, and ∠CED are supplementary    

∠AEB + ∠BEC + ∠CED = 180    definition of supplementary angles

∠AEB + ∠CED + ∠CED = 180    substitution

11x - 12 + 4x + 1 + 4x + 1 = 180    substitution

19x - 10 = 180              simplified (added like terms)

19x = 190                    addition property of equality

  x = 10                       division property of equality

*****************************************************************

∠AEB = 11x - 12

         = 11(10) - 12

          = 110 - 12

          = 98

∠BEC = ∠CED = 4x + 1

                        = 4(10) + 1

                         = 40 + 1

                          = 41

********************************************************************

∠AEB + ∠BEC = ∠AEC   segment addition property

98 + 41 = ∠AEC               substitution

 139 = ∠AEC                  simplified (added like terms)

Answer: 139°

An angle bisector divides an angle into two equal halves. The measure of angle AEC is: [tex]139^o[/tex]

Given that:

[tex]\angle AEB = 11x - 12[/tex]

[tex]\angle CED = 4x + 1[/tex]

Since ray BD bisects [tex]\angle BED[/tex], then:

[tex]\angle BEC = \angle CED[/tex]

This implies that:

[tex]\angle BEC = 4x + 1[/tex]

[tex]\angle AEC[/tex] is calculated as:

[tex]\angle AEC = \angle AEB + \angle BEC[/tex]

This gives:

[tex]\angle AEC = 11x - 12 + 4x + 1[/tex]

Collect like terms

[tex]\angle AEC = 11x + 4x- 12 + 1[/tex]

[tex]\angle AEC = 15x-11[/tex]

Next, we calculate the value of x as follows:

[tex]\angle AEB + \angle CED + \angle BEC = 180[/tex] --- angle on a straight line.

This gives:

[tex]11x - 12 + 4x + 1 + 4x + 1 = 180[/tex]

Collect like terms

[tex]11x + 4x + 4x = 180+12-1-1[/tex]

[tex]19x = 190[/tex]

Divide by 19

[tex]x = 10[/tex]

Substitute 10 for x in [tex]\angle AEC = 15x-11[/tex]

[tex]\angle AEC= 15 \times 10 - 11[/tex]

[tex]\angle AEC= 139^o[/tex]

Hence, the measure of [tex]\angle AEC[/tex] is [tex]139^o[/tex]

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Anita began solving the system ​ {x+y=8, x−y=2 ​ by writing 2x=10 .

x+y=8

x−y=2

When we add both equations , we will get 2x = 10

x+x becomes 2x

+y -y becomes 0

8 + 2 becomes 10

So by adding two equations we got 2x = 10

Hence we say Addition Property of Equality.

Addition Property of Equality means adding both sides of equations.

x  terms  and y terms are added . then number are added on the right side

Answer:

Option C is correct

Addition property of Equality justifies the step.

Step-by-step explanation:

Given the system of equation:   x+y = 8  and x-y = 2.

Addition Property of Equality: The method of solving systems of linear equations is the addition Property, in which the two equations are added together to eliminate one of the variables.

Adding the equations states that we add the left sides of the two equations together, and we add the right sides together.

Using the addition property in equation: x+y=8 and x-y =2

then,

[tex](x+y)+(x-y)=8+2[/tex]  or

[tex](x+x)+(y-y)[/tex] =10

Eliminate the y- variable; we have

2x=10

Therefore, the only property justifies the step is, Addition Property of Equality.

Step 1. Use Multiplication Distributive Property

-3 * 2^4x^4(4x^5y)^2

Step 2. Simplify 2^4 to 16

-3 * 16x^4(4x^5y)^2

Step 3. Use Multiplication Distributive Property

-3 * 16x^4 * 4^2(x^5)^2y^2

Step 4. Simplify 4^2 to 16

-3 * 16x^4 * 16(x^5)^2y^2

Step 5. Use the Power Rule

-3 * 16x^4 * 16x^10y^2

Step 6. Take out the constants

-(3 * 16 * 16)x^4x^10y^2

Step 7. Simplify 3 *16 * 16 to 768

-768x^4x^10y^2

Step 8. Use the Product Rule

-768x^4 + 10y^2

Step 9. Simplify 4 + 10 to 14

-768x^14y^2

​-3(2x)⁴(4x⁵y)² = When a power is raised to a power the exponents have to be multiplied.

​-3(2⁴x⁴)(4²x⁽⁵*²⁾y²) = We can take out the constants.

=-3*16*16(x⁴)(x¹⁰y²) = We can group the same variables​.

=-768(x⁴x¹⁰)(y²) = When multiplying two powers that have the same base, you have to add the exponents.​

​=-768x⁽⁴⁺¹⁰⁾y² = -768x¹⁴y²

​Answer : -768x¹⁴y²

Hope this helps!​​​​​

​​[tex]\textit{\textbf{Spymore}}[/tex]​​​​​​