For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?
You do not need to look up any values to answer this question.
Check all that apply.
Check all that apply.
C(s,graphite)+O2(g)→CO2(g)
Li(s)+12F2(l)→LiF(s)
CO(g)+12O2(g)→CO2(g)
BaCO3(s)→BaO(s)+CO2(g)
2Li(s)+F2(g)→2LiF(s)
Li(s)+12F2(g)→LiF(s)

Answers

Answer 1

inal answer:

The reaction C(s, graphite) + O2(g) → CO2(g) is the one where ΔH°rxn equals the ΔH°f of the product, CO2(g), because it forms carbon dioxide from its constituent elements in their standard states. Option A

Explanation:

For an element or compound, the enthalpy change (ΔH) of a reaction that forms it from its elements in their standard states is called the standard enthalpy of formation (ΔH°f).

Therefore, ΔH°rxn is equal to ΔH°f for a reaction that produces a compound directly from its constituent elements in their most stable forms at 1 atm pressure and 25°C (298 K). Examining the provided reactions, the one that fits this description is:

C(s, graphite) + O2(g) → CO2(g)

This reaction forms carbon dioxide (CO2) directly from its elements, carbon in the form of graphite (the most stable form of carbon at standard conditions) and oxygen gas, both of which are in their standard states. Thus, ΔH°rxn for this reaction is equivalent to the ΔH°f of carbon dioxide.

Other reactions listed may be formation reactions, but they introduce compounds like fluorine in liquid form (F2(l)), which is not the standard state of fluorine at 25°C; hence, they do not meet the criteria. Option A


Related Questions

Consider the following reaction. 2Fe2O3 --> 4Fe + 3O2 deltaH = +824.2KJ The formation of 42.0 g of O2 results in? 1) the absorption of 361 kJ of heat. 2) the absorption of 11500 kJ of heat. 3) the absorption of 1080 kJ of heat.

Answers

If deltaH is positive, that means the reaction took heat from its environment (endothermic reaction).
   The molar mass of O2 is 32 g/mol.
 Therefore, 42g of O2 is equal to 1.3 moles O2.
   The equation assumes 3 moles of O2. That means, only 1.3/3 = 43% of the delta H in the equation was formed.
   824.2 kJ x 43% = 354 kJ. The closest answer is 1) the absorption of 361 kJ of heat.

The formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.

The heat of formation of oxygen will be

[tex]\rm \Delta H[/tex] is +824.2 kJ.

The positive sign of H denotes that the reaction accepts energy from the surroundings. It is an endothermic reaction.

In the reaction the % formation of Oxygen is :

Total product formed = 7 moles

Oxygen formed = 3 moles

% Oxygen formed = [tex]\rm \frac{3}{7}\;\times\;100[/tex]

% oxygen formed  = 42.85 %

The total enthalpy for the formation of product is +824.2 kJ.

The enthalpy for the formation of 42.85 % Oxygen = +824.2 [tex]\times[/tex] 42.85 / 100 kJ.

The enthalpy of the formation of oxygen in the reaction will be 353.22 kJ.

The closest is 361 kJ.

So, for the formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.

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which of the following is an inorganic compound?
h2o water molecule
ch3(ch2)3ch3 pentane
c4h10 butane
c6h12o6 glucose,

Answers

H2O water molecule is inorganic. Organic molecules contains carbon atom. Pentane, Butane, and Glucose have carbon in their molecules. Water is inorganic it contains hydrogen and oxygen. there is no carbon molecule. Carbohydrates, lipids etc are examples of organic molecules.

A chemical reaction takes place in which energy is absorbed arrange the characteristics of the reaction in order from start to finish

Answers

A chemical reaction in which energy is absorbed is known as an endothermic reaction. The characteristics of the reaction in order from start to finish is as follows:

1. Lower energy of reactants
2. Transition state
3. Higher energy of products

This implies that in an endothermic reaction, the products are less stable than the reactants.

What equals the molar mass of a element

Answers

The molar mass of an element is equal to the element's atomic weight mentioned in the periodic table.

What is molar mass?

Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.

The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.

Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.The element's molar mass is mentioned in the box of the element's symbol in the periodic table.

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Calculate the mass of water produced when 6.97 g of butane reacts with excess oxygen

Answers

the balanced reaction equation for the combustion of butane is as follows;
C₄H₁₀ + 13/2O₂ ---> 4CO₂ + 5H₂O 
the limiting reactant in this reaction is C₄H₁₀  This means that all the butane moles are consumed and amount of product formed depends on the amount of C₄H₁₀ used up.
stoichiometry of C₄H₁₀ to H₂O is 1:5
mass of butane used - 6.97 g
number of moles - 6.97 g / 58 g/mol = 0.12 mol
then the number of water moles produced - 0.12 mol x 5 = 0.6 mol
Therefore mass of water produced - 0.6 mol x 18 g/mol = 10.8 g

Determine the number of particles in each of the following. Show the unit conversion method. A. 0.250 mol silver B. 8.56 x 10-3 mol NaCl C. 35.4 mol CO2 D. 0.425 mol N2

Answers

The number of particles in A is 1.506 x 10²³, in B is 5.156 x 10²⁰, in C is 2.131 x 10²⁵, and in D is 2.559 x 10²³.

What is the number of particles in the given elements or compounds?

To determine the number of particles in each of the following substances, it is required to use Avogadro's number, which is 6.022 x 10²³ particles per mole. We can use dimensional analysis, also known as the unit conversion method, to convert from moles to particles.

A. 0.250 mol silver

Number of particles = 0.250 mol x 6.022 x 10²³ particles/mol

Number of particles = 1.506 x 10²³ particles

B. 8.56 x 10⁻³ mol NaCl

Number of particles = 8.56 x 10⁻³ mol x 6.022 x 10²³ particles/mol

Number of particles = 5.156 x 10²⁰ particles

C. 35.4 mol CO₂

Number of particles = 35.4 mol x 6.022 x 10²³ particles/mol

Number of particles = 2.131 x 10²⁵ particles

D. 0.425 mol N₂

Number of particles = 0.425 mol x 6.022 x 10²³ particles/mol

Number of particles = 2.559 x 10²³ particles

Therefore, there are approximately 1.506 x 10²³ particles in 0.250 mol of silver, 5.156 x 10²⁰ particles in 8.56 x 10⁻³ mol of NaCl, 2.131 x 10²⁵ particles in 35.4 mol of CO₂, and 2.559 x 10²³ particles in 0.425 mol of N₂.

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The astronaut then measures the abundance of magnesium on the new planet, obtaining the following results:
Isotope Abundance (%) Mass (amu)
86 Sr 9.46 85.91
87 Sr 7.00 86.91
88 Sr 83.54 87.91
What is the atomic mass of magnesium for this planet?
Express your answer to two decimal places, and include the appropriate units.

Answers

Solution:

Atomic mass = ΣzₓAₓ  zₓ = relative abundance of the isotope
and Aₓ = the atomic mass of the isotope.

Atomic mass = (0.0946x85.91) + (0.07x86.91) + (0.8354x87.91)
= 87.65 amu

Answer: The average atomic mass of Strontium is 87.65 u

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

[tex]\text{Average atomcic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex]     .....(1)

For [tex]_{38}^{86}\textrm{Sr}[/tex] isotope:

Mass of [tex]_{38}^{86}\textrm{Sr}[/tex] isotope = 85.91 u

Percentage abundance of [tex]_{38}^{86}\textrm{Sr}[/tex] isotope = 9.46 %

Fractional abundance of [tex]_{38}^{86}\textrm{Sr}[/tex] isotope = 0.09460

For [tex]_{38}^{87}\textrm{Sr}[/tex] isotope:

Mass of [tex]_{38}^{87}\textrm{Sr}[/tex] isotope = 86.91 u

Percentage abundance of [tex]_{38}^{87}\textrm{Sr}[/tex] isotope = 7.00 %

Fractional abundance of [tex]_{38}^{87}\textrm{Sr}[/tex] isotope = 0.0700

For [tex]_{38}^{88}\textrm{Sr}[/tex] isotope:

Mass of [tex]_{38}^{88}\textrm{Sr}[/tex] isotope = 87.91 u

Percentage abundance of [tex]_{38}^{88}\textrm{Sr}[/tex] isotope = 83.54 %

Fractional abundance of [tex]_{38}^{88}\textrm{Sr}[/tex] isotope = 0.8354

Putting values in equation 1, we get:

[tex]\text{Average atomic mass of Sr}=[(85.91\times 0.0946)+(86.91\times 0.0700)+(87.91\times 0.8354)][/tex]

[tex]\text{Average atomic mass of Sr}=87.65u[/tex]

Hence, the average atomic mass of Strontium is 87.65 u

Among teenagers, what is the most commonly used substance?

Answers

'alcohol'The most commonly used and abused substance in terms of prevalence and recency of use.

How are the electron structures of boron (B) and aluminum (Al) similar?

Answers

The electron structures of boron and aluminum are similar because they share the same group, therefore they have the same amount of valence electron. 

Answer:

- Both of their valence electrons are at p subshell.

- They have the first subshell full of electrons.

- Both of them have just 1 electron at the last p subshell.

Explanation:

Hello,

In this case, we could understand their electron structures by identifying their electron configurations as shown below:

[tex]B^5\rightarrow 1s^2,2s^2,2p^1\\Al^{13}\rightarrow 1s^2,2s^2,2p^6,3s^2,3p^1[/tex]

In such a way, we could notice the following similarities:

- Both of their valence electrons are at p subshell.

- They have the first subshell full of electrons.

- Both of them have just 1 electron at the last p subshell.

Best regards.

A certain hydrocarbon (a compound consisting of carbon and hydrogen) is 82.66% carbon by mass and has a molar mass of 58.12 g. determine the molecular formula of this hydrocarbon.

Answers

firstly need to determine the empirical formula of the hydrocarbon. Empirical formula is the simplest whole number ratio of components of the compound. Molecular formula  is the actual composition of the components in the compound.

percentage of C - 82.66%
percentage of H - (100-82.66) = 17.34 %
in 100 g of compound ;
mass of C - 82.66 g
mass of H - 17.34 g
                                 C                               H
mass in 100 g        82.66 g                      17.34 g
molar mass           12 g/mol                      1 g/mol
number of moles    6.88 mol                     17.34 mol
(mass/molar mass)
divide the number of moles by least number of moles (6.88 mol)
                               6.88 mol/6.88             17.34/6.88
                                1                                 2.52
multiply these by 2 to get a whole number 
C - 1x 2 = 2
H - 2.52 x 2 = 5.04
round off to nearest whole number 
C - 2
H - 5
ratio of C to H is 2:5
empirical formula - C₂H₅
empirical formula mass = 12 g/mol x 2 + 5 * 1 g/mol = 29 g

next have to find how many empirical units are there in the molecular unit 
molecular unit mass = 58.12 g
empirical unit = 29 g
then number of empirical units = 58.12 / 29 = 2
rounded off , number of empirical units = 2
(C₂H₅) * 2 units
molecular formula = C₄H₁₀

Final answer:

The molecular formula of the hydrocarbon is C4H8.

Explanation:

The molecular formula of the hydrocarbon can be determined using the given information. Since the compound is 82.66% carbon by mass, we can assume that the remaining percentage is hydrogen. The molar mass of the compound is 58.12 g/mol.

To find the molecular formula, we need to determine the empirical formula first. We assume 100 g of the compound, so 82.66 g is carbon and 17.34 g is hydrogen. Using the molar mass and the atomic masses of carbon and hydrogen, we can determine the moles of each element.

The empirical formula is CH2, and the molar mass of CH2 is 14.03 g/mol. To find the molecular formula, we divide the molar mass of the compound (58.12 g/mol) by the molar mass of CH2 (14.03 g/mol). The result is approximately 4.15. We round this to the nearest whole number, which gives us a molecular formula of C4H8.


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Which equation expresses Newtons second law of motion

Answers

F = MA 
force = mass times accleration
Newton's second law states that the acceleration of an object is directly proportional to the net force acting upon the object and inversely proportional to the mass of the object. The law is often expressed in the form of the following two equations.

Dissolving 25.00 g cucl2 in enough water to make 250 ml of solution gives a solution concentration equal to

Answers

Final answer:

The concentration of the solution made by dissolving 25.00 g of CuCl2 in enough water to make 250 mL of solution is 0.74 M.

Explanation:

In this question, we are dealing with molarity calculation. The molarity of a solution is determined by the formula: Molarity (M) = moles of solute/volume of solution in liters. But first, we need to convert the mass of CuCl2 into moles. CuCl2 has a molar mass of about 134.45 g/mol. So, we divide 25.00 g CuCl2 by 134.45 g/mol which equals 0.185 moles. The volume of the solution is 250 mL, which we convert to liters to match the units in the molarity formula. This gives us 0.250 L. We now substitute these values into the molarity formula - M = 0.185 moles/0.250 L = 0.74 M. Therefore, the concentration of the solution is 0.74 M.

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When writing 6,020,000 in scientific notation, it is correctly written as: 6.02 x 106 6.02 x 10-6 602. x 106 0.602 x 10-8

Answers

The answer is 6.02x 10^-6

6.02 x 10^6 is correct it's not negative because youre moving in the positive direction in terms of sci not.

Please help! ill give medal
26. Write the general chemical formula for an acid, and discuss what each component of the formula represents. (3 points)

Answers

An example of a general formula of an acid is
HCl

This is called as hydrochloric acid or hydrogen chloride.

H represents for the atom of Hydrogen
and Cl represents for the atom of Chlorine

Since their charges are -1, and +1, it's ratio is 1:1

If 3.0 moles of x and 4.0 moles of y react according to the hypothetical reaction below, how many moles of the excess reactant will be left over at the end of the reaction? x + 2 y yields xy2

Answers

firstly the limiting reactant should be identified. Limiting reactant is the reactant that is in limited supply, the amount of product formed depends on the moles present of the limiting reactant.

the stoichiometry of x to y = 1:2
1 mole of x reacts with 2 moles of y
if x is the limiting reactant, there are 3 moles of x, then 6 moles of y should react, however there are only 4 moles of y. Therefore y is the limiting reactant and x is in excess.
4 moles of y reacts with 2 moles of x 
since there are 3 moles of x initially and only 2 moles are used up, excess amount of x is 1 mol thats in excess.


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According to Ampere, which of the following sets of current-carrying wires would repel each other? The arrow point indicates the direction of the current in each wire.

Answers

The answer would be c, they are going in opposite directions so they repel each other. 

Answer: Option (c) is the correct answer.

Explanation:

When current passes through a wire then a magnetic field is formed. Therefore, when two wires carry current in the same direction then both the wires with have respective magnetic fields in the same direction and their total magnetic field will be large.

But when current between two wires flow in opposite direction then the magnetic field produced will also be in opposite direction. Therefore, both the magnetic fields cancel each other out. Thus, total magnetic field will be small.

As a result, wires which carry current in the opposite direction repel each other.


Which compound will form an acidic solution when dissolved in water? which compound will form an acidic solution when dissolved in water? nano2 khso4 kbr ba(no3)2?

Answers

Hello!

The compound that will form an acidic solution when dissolved in water is KHSO₄.

An acidic solution is one with a pH between 0-7. For it to be in this pH range, the solution needs to have hydronium ions (H₃O⁺). KHSO₄ generates these ions by the following dissociation reactions:

KHSO₄(s) →K⁺(aq) + HSO₄⁻ (aq)

HSO₄⁻(aq) + H₂O → H₃O⁺(aq) + SO₄⁻²(aq)

As the solution has hydronium ions, it will be an acidic solution. 
Final answer:

Among the compounds NaNO2, KHSO4, KBr, and Ba(NO3)2, KHSO4 forms an acidic solution when dissolved in water. It can donate a proton, subsequently increasing the concentration of hydronium ions. The other compounds do not result in an increased concentration of hydronium ions and thus, do not form acidic solutions.

Explanation:

When you're determining which of these compounds--NaNO2, KHSO4, KBr, Ba(NO3)2--forms an acidic solution when dissolved in water, it's important to understand how compounds behave in water. Most notably, you should know that an acidic solution contains a greater concentration of hydronium ions (H3O+) than hydroxide ions (OH-).

Sulfuric acid is a diprotic acid, which means it can donate two protons. It forms both sulfates and hydrogen sulfates in solution, and most of these compounds moderate the pH when dissolved in water. Consequently, KHSO4 is the compound that will result in an acidic solution, since upon dissolution, it can donate a proton and thereby increase the concentration of H3O+ ions.

As a note, the other compounds listed (NaNO2, KBr, Ba(NO3)2) do not increase the concentration of H3O+ ions; thus, they won't form acidic solutions. For instance, Ba(NO3)2 in a neutralization reaction with water will form a neutral salt and water.

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Summarize your conclusion about how temperature difference and humidity affect weather conditions

Answers

The measure of the amount of water the air can hold is called humidity. When the temperature increases the humidity and pressure of the environment also increases. The increase in pressure pushes the air together and squeezes out water. This is how rain or snow is made.The high humidity level in the air is what makes it to rain or snow.

Answer:

Increasing the temperature Decreases the humidity and vice versa

Explanation:

When the temperature is increasing, the air can hold more water molecules ,thereby making the humidity to reduce. A high humidity will make the weather to be more hotter because the body sweat will not evaporate easily. A low humidity makes the weather cooler due to the fact the body sweat evaporate easily .

If 5.400 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temperature of the water?

Answers

Actually, we will use this formula:
Q = m.C.ΔT
when Q is the heat released during the reaction.
and m is the mass of water.
and C is the specific heat of water 
and ΔT is the change of the temperature of the water.
So according to the balanced equation for this reaction:
2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(l) + 6542 KJ
So when 2 moles of C6H6 released 6542 KJ of heat, So how many moles of the 5.4 g 
no of moles of C6H6 = 5.4 / molar mass of C6H6
                                    = 5.4g/78.11 g/mol =0.069 moles
so     2 moles of C6H6 released          → 6542 
 ∴  0.069 moles of C6H6 will release  →  X
∴Q = (0.069 * 6542)/2 = 226 KJ
So by substitution in Q= m.c.ΔT to get ΔT
∴Δ T = Q/(m.c) = 226 / (5691*0.004186) = 9.496 
when we have Ti
ΔT=Tf-Ti 
∴Tf = 9.496 + 21 = 30.5 °C
                


The final temperature of the water : 30.506 °C

Further explanation  

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Qin = Qout  

Heat can be calculated using the formula:  

Q = mc∆T  

m = mass, g  

∆T = temperature difference, °C / K  

From reaction:  

2C₆H₆ (l) + 15O₂ (g) ⟶12CO₂ (g) + 6H₂O (l) +6542 kJ, heat released by +6542 kJ to burn 2 moles of C₆H₆

If there are 5.400 g of C₆H₆ then the number of moles:  

mol = mass: molar mass C₆H₆

mol = 5.4 : 78  

mol C₆H₆ = 0.0692

so the heat released in combustion 0.0692 mol C₆H₆:  

[tex]\rm Q=heat=\dfrac{0.0692}{2}\times 6542\:kJ\\\\Q=226.353\:kJ[/tex]

the heat produced from the burning is added to 5691 g of water at 21 C

So :

Q = m . c . ∆T (specific heat of water = 4,186 joules / gram ° C)  

226353 = 5691 . 4.186.∆T  

[tex]\rm \Delta T=\dfrac{226353}{5691\times 4.186}\\\\\Delta T=9.506\\\\\Delta T=T(final)-Ti(initial)\\\\9.506=T_f-21\\\\T_f=30.506\:C[/tex]  

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Can someone help me please?

If 75.0 g of silderite ore (FeCO3) is heated with an excess of oxygen, 45.0 g of ferric oxide (Fe2O3) is produced.

4feCO3(s) + O2(g) -> 2fe2O3(s) + 4CO2(g)

what is the percent of yield of this reaction?,

Answers

The limiting reactant is FeCO3.
Molar mass of FeCO3 = 55.845 + 12 + 48 = 115.845
Number of moles of FeCO3 = 75/ 115.845 = 0.6475
But from the chemical reaction 4 moles of FeCO3 reacts with 2 moles of
Fe2O3. If we divide the number of molecules of our desired product, Fe2O3,
by the number of molecules of your limiting reactant FeCO3. We obtain our
theoretical yield. So we have 1/2 * 0.6475 = 0.3235 moles of Fe2O3
Molar mass of Fe2O3 = 159.7. Hence mass of Fe2O3 = 159.7 * 0.3235 =
51.66.
Percentage yield = Actual yield/ theoretical yield * 100
Percentage yield = 45/51.66 * 100 = 87%

Given concentration equilibrium constants (1) h3o +(aq) + noâ 2 (aq) ââ½ hno2(aq) + h2o, kc = 3.86 Ã 103 , (2) 2 h2o(â) ââ½ h3o +(aq) + ohâ(aq), kw = 1.0 Ã 10â14 , calculate kc for the reaction noâ 2 (aq) + h2o(â) ââ½ hno2(aq) + ohâ(aq).

Answers

Final answer:

To calculate the equilibrium constant for the reaction NO− 2 (aq) + H2O(l) → HNO2(aq) + OH−(aq), reverse the first given reaction, H3O+ + NO− 2 → HNO2 + H2O with Kc = 3.86 × 10³, and divide by the autoionization constant of water, Kw = 1.0 × 10−14, to obtain Kc = 3.86 × 10³17.

Explanation:

To calculate the equilibrium constant (Kc) for the chemical reaction NO− 2 (aq) + H2O(l) → HNO2(aq) + OH−(aq), we need to use the given equilibrium constants for related reactions and the autoionization of water.

The first reaction is:

H3O+ (aq) + NO− 2 (aq) ⇌ HNO2(aq) + H2O(l), Kc = 3.86 × 10³.

The second reaction is the autoionization of water:

2H2O(l) ⇌ H3O+ (aq) + OH−(aq), Kw = 1.0 × 10−14.

By reversing the first reaction and dividing its Kc by Kw, we can obtain the equilibrium constant for the reaction NO− 2 (aq) + H2O(l) → HNO2(aq) + OH−(aq):

Kc for the desired reaction = Kc for H3O+ + NO− 2 → HNO2 + H2O / KwKc for NO− 2 + H2O → HNO2 + OH− = 3.86 × 10³ / 1.0 × 10−14 = 3.86 × 10³17.

Diffusion of nonpolar molecules would not be affected by

Answers

 +molecule size +steepness of the concentration gradient +temperature + steepness of the electric gradient +steepness

Diffusion of nonpolar molecules is does not affected by charge. Because they have no partial charges. Hence option d is correct.

What is diffusion?

Diffusion of substance is the spreading or transfer of compounds based on concentration gradient or pressure gradient. Molecules diffuses from higher concentration region to lower concentration region.

Non-polar molecules are those which have no permanent dipole moment. They have no partial charges formed during chemical bonding. Whereas, polar compounds are those having permanent dipole moment and are having partial charges.

All other factors, such as temperature, pressure, concentration and molecular size will affect the rate of diffusion. Thus for non-polar compounds charge is  affecting the diffusion.

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Your question is incomplete but your complete question probably was:

Diffusion of nonpolar molecules would not be affected by

a.molecule size.

b.steepness of the concentration gradient.

c.temperature.

d.charge.

e.steepness of the pressure gradient

An atom of potassium loses one electron. what does it become a negative potassium, positive potassium

Answers

Yes, K+ is a potassium ion, and Mg2+ is a magnesium ion. But However, when non-metallic elements gain the electrons to form anions, Yes the end of their name is changed to “-ide.” and yes the example, a fluorine atom gains one electron to become a yes fluoride ion (F-) sooo yeessyes

Many manufacturing processes involve chemical reactions that reach equilibrium. Why would chemists adjust conditions to favor the forward reaction in a process

Answers

the answer is to increase the amount of product -gradpoint
To increase the amount of product

0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml of water. what is the final concentration? assume the volumes are additive.

Answers

54.0 ml of a 1.2 m solution was diluted to a total volume of 228 ml
USing dilution equation
M1V1 = M2V2
Where M1V1 is before dilution while M2V2 is after dilution.
Therefore;
M1= 1.20 M, V2= 54 ml,  
M2=              V2 = 228 ml

1.20 M × 54 ml = M2 × 228 ml
  M2 = (1.2 ×54)/ 228 ml
       = 0.2842 M

0.2842 × 114 ml = M2 × (114 +111)
      M2 = (0.2842 ×114)/ 225
            = 0.143995
            = 0.144 M

The final concentration of the solution after the described dilution process is approximately 0.00855 M.

Let's first ascertain the original dilution's concentration. Using the dilution equation:

[tex]C_1V_1 = C_2V_2[/tex]

Where:

C₁ = 1.20 M (initial concentration)V₁ = 0 mlV₂ = 228 mlC₂ = final concentration after the first dilution

Since 0 ml is a typo, let us assume the starting volume V₁ is enough such as 1 mL. Plugging in the values:

(1.20 M)(1 ml) = (C₂)(228 ml)C₂ = 1.20 / 228

Now, calculate the concentration after the second dilution:

V₁ = 114 mlV₂ = 114 ml + 111 ml = 225 ml

Using the intermediate solution:
[tex]C_1V_1 = C_2V_2[/tex]

C₃ = (C₂)(114 ml) / 225 mlSubstitute C₂ from above:
[tex]C_3 = [(1.20/228) \times 114] / 225 = 1.2\ M \times (114 / 228) / 225[/tex]

The final concentration after the second dilution is about 0.00855 M.

A balloon contains 0.158 mol of gas and has a volume of 2.46 l. if an additional 0.113 mol of gas is added to the balloon (at the same temperature and pressure), what is its final volume?

Answers

Answer is: final volume is 4.21 liters.

Use Avogadro's Law (the Volume Amount Law): If the amount of gas in a container is increased, the volume increases.

The volume-amount fraction will always be the same value if the pressure and temperature remain constant.

V₁ / n₁ = V₂ / n₂.

2.46 l / 0.158 mol =  V₂ / 0.271 mol.

V₂ = 4.21 l.

Final answer:

To find the final volume of the balloon, we can use the combined gas law equation. The initial pressure is calculated using the number of moles and volume. This pressure, along with the final number of moles, initial volume, and constant temperature, can be used to find the final volume.

Explanation:

To solve this problem, we can use the combined gas law equation (P1V1/T1 = P2V2/T2) which relates the pressure, volume, and temperature of a gas. Since the temperature and pressure remain constant, we can use the equation to find the final volume. First, calculate the initial pressure by dividing the number of moles by the volume. Then substitute the initial pressure, final number of moles, and initial volume into the equation, and solve for the final volume.



Given:

N1 = 0.158 mol

N2 = 0.113 mol

V1 = 2.46 L

V2 = ?

P1 = N1/V1

Substituting the values:

P1 = 0.158 mol / 2.46 L = 0.0642 atm

Now, substitute the values into the combined gas law equation:

P1V1/T1 = P2V2/T2

Solving for V2:

V2 = (P1V1T2) / (P2T1)

Since the temperature and pressure remain constant, we can write the equation as:

V2 = (P1V1) / P2

Substituting the values:

V2 = (0.0642 atm * 2.46 L) / (0.113 mol) = 1.396 L

The final volume of the balloon is 1.396 L.

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When copper (ii) carbonate is heated if forms copper (ii) oxide and carbon dioxide?

Answers

Is this the answer you are looking for CuCO3=> CuO + CO2.

Based on the entries in the following table, which element is most commonly bonded to the acidic hydrogen? table some weak acids in water at 25 ∘c

Answers

Final answer:

Hydrogen bonding in acids, solvation energy terms, and the impact of strong acids on conjugate bases are crucial concepts in understanding acid dissociation and acid-base behavior in solution.

Explanation:

Hydrogen bonding occurs when a hydrogen atom, part of a polar covalent bond, is bonded to a more electronegative atom. In the case of acids, hydrogen bonds form between the hydrogen atom of the acid (H-A) and water molecules. This results in the acid dissociation process, where the acid molecule becomes an anion.

Solvation energy terms play a crucial role in driving hydrogen ion transfer in solution. Despite thermodynamic considerations indicating that most strong Brønsted acids should not act as acids towards water, solvation energy terms, aided by entropic effects, drive hydrogen ion transfer in solution.

In general, strong acids form very weak conjugate bases, while weak acids form stronger conjugate bases. Water has a leveling effect on dissolved acids, generating hydronium and hydroxide ions, the strongest acid and base in water.

The mass of an object is found by _____.



comparison with standard mass units
weighing the object
displacing water
measuring the object

Answers

that's the answer comparison with standard mass units

Hello!

comparison with standard mass units

is your answer

What is the estimated effective nuclear charge, Z eff, experienced by an electron in a 3p orbital of a chlorine atom?
a. -1
b. 5
c. 7
d. 17,

Answers

Effective nuclear charge is the charge felt by valence electrons of multi-electron atom taking into consideration the number of shielding electrons that surround the nucleus.
To calculate Z eff for electron we use this formula :
Z eff = Z - S where Z is the number of protons in nucleus and S is the average amount of electron density between the nucleus and electron in consideration
so Z eff = 17 - 10 (core electrons) = 7 
So the correct answer is C 
Final answer:

The estimated effective nuclear charge (Zeff) experienced by an electron in the 3p orbital of a chlorine atom is approximately 7, as inner electrons shield the nucleus' full charge of 17. This is derived from considering the electron configuration of chlorine and the shielding effects provided by inner electrons.

Explanation:

The question is asking about the effective nuclear charge (Zeff) experienced by an electron in the 3p orbital of a chlorine atom. The effective nuclear charge is the net positive charge an electron feels after accounting for the shielding effect of the other electrons. A neutral chlorine atom has an atomic number of 17, which means there are 17 protons in the nucleus. However, the effective nuclear charge felt by an electron in the 3p orbital is not the full charge of 17 due to the shielding of the electrons in closer orbitals.

The electron configuration of a neutral chlorine atom is 1s22s22p63s23p5. The 10 electrons in the 1s, 2s, and 2p orbitals shield the 3p electrons from the full nuclear charge. Using Slater's rules, one can estimate the effective nuclear charge felt by a 3p electron. The value of Zeff is typically between 1 and the actual nuclear charge (Z), which is 17 for chlorine. The exact Zeff would require taking into account the actual amount of shielding provided by the inner electrons, which tends to be a complex calculation considering electron-electron interactions and the distribution of electron density.

However, based on Slater's rules and shielding effects, a rough estimate for the Zeff would be closer to the chlorine's atomic number (17) than to 1, making options a (-1) and b (5) incorrect. Since the 10 inner electrons shield the nuclear charge, a reasonable estimate for Zeff for a 3p electron in chlorine might be around 7 (17 nuclear charge - 10 shielding electrons), but advanced calculations are required for a precise value. Therefore, answer choice c (7) seems to be the most appropriate estimate based on basic principles.

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