GETS BRAINLIEST AND 50 PTS!

The seventh-grade class is building target areas for a PE activity. The bases for the game will be in a circular shape. The diameter of each circle is 3 feet. Approximately, how many square feet of the turf needs to be painted for a base circle? Use 3.14 for π and round your answer to the nearest tenth. 7.1 square feet 9.4 square feet 18.8 square feet 28.3 square feet

Final answer:

For the expression R(x)=(500+ax)(50-bx), a represents the increase in yearbooks sold for each $5 decrease in price and b represents the corresponding decrease in price per yearbook. The correct values for a and b are 100 and 5 respectively, resulting in the revenue expression R(x) = (500 + 100x)(50 - 5x).

Explanation:

The student's question revolves around the concept of revenue generation based on the number of items sold and the selling price per item.

When examining revenue, we understand it as the product of price per unit times the number of units sold. In the given example, a school is selling yearbooks with a base scenario of 500 yearbooks at $50 each. We are given that for every $5 decrease in price, the school can sell an additional 100 yearbooks. This can be formulated as:

R(x) = (500 + ax)(50 - bx)

Here x represents the number of $5 decreases from the original price. With each decrease, the number of books sold increases by 100, and the price decreases by $5.

Therefore, variable a must represent the increase in quantity sold for each $5 price decrease (a = 100), and variable b must represent the decrease in price per yearbook for each price decrease (b = 5).

Therefore, the values of a and b are 100 and 5, respectively.

The expression for the revenue becomes:

R(x) = (500 + 100x)(50 - 5x)

The angles for Brian's triangular plot of farmland are approximately 27° for ∠A, 38° for ∠B, and 115° for ∠C.

To determine the angles of a triangular plot of land with sides measuring 1.1 miles, 1.5 miles, and 2.2 miles, we can use the Law of Cosines. The Law of Cosines states:

⇒ c² = a² + b² - 2ab × cos(C)

⇒ a = 1.1 miles

⇒ b = 1.5 miles

⇒ c = 2.2 miles

⇒ cos(C) = (a² + b² - c²) ÷ (2ab)

⇒ cos(C) = (1.1² + 1.5² - 2.2²) ÷ (2 × 1.1 × 1.5)

= (1.21 + 2.25 - 4.84) ÷ (3.3)

= (-1.38) ÷ (3.3)

= -0.4182

⇒ ∠C ≈ 115°

⇒ cos(A) = (b² + c² - a²) ÷ (2bc)

⇒ cos(A) = (1.52 + 2.22 - 1.12) ÷ (2 × 1.5 × 2.2)

= (2.25 + 4.84 - 1.21) ÷ (6.6)

= (5.88) ÷ (6.6)

= 0.8909

⇒ ∠A ≈ 27°

⇒ ∠B = 180° - ∠A - ∠C

= 180° - 27° - 115°

= 38°

The angles at which the fences of the three sides will meet are approximately 27° for ∠A, 38° for ∠B, and 115° for ∠C, when rounded to the nearest degree.

Complete question:

Brian wants to fence in his triangular plot of farm land that measures 1.1 × 1.5 × 2.2 miles.

Determine the angles at which the fences of the three sides will meet.

Rounding each angle to the nearest degree:

To calculate the portion of the first month's payment that goes towards the principal, we need the monthly payment amount, which is calculated from the loan amount, interest rate, and term. From there, we subtract the first month's interest from the monthly payment. In the absence of adequate information or a mortgage calculator, we cannot provide the correct option from (a-d).

To determine how much of the first month's payment goes towards the principal of a $175,000 mortgage at a rate of 5.5% for a 30-year fixed mortgage, we need to calculate the monthly payment and then separate the interest from the principal.

The monthly payment M can be calculated using the formula:

M = P x (r(1+r)^n) / ((1+r)^n-1)

Where:

Next, we find the monthly interest portion by multiplying the principal by the monthly interest rate and subtract it from the monthly payment to find how much goes towards the principal.

Unfortunately, the information given does not provide a clear way to calculate the exact monthly payment or the portion applied to the principal without additional information or a financial calculator. In practice, you would use a formula or a mortgage calculator to find the total monthly payment, and then deduct the first month's interest to determine the amount applied to the principal. Without the correct formula or values, we can't determine the answer options (a-d) provided.

Final answer:

The original number is determined by setting up an algebraic equation based on the relationship given in the problem, solving for the variable, and using algebraic operations. The original number is found to be 30.

Explanation:

To find the original number when its half and fifth are added to it to get 51, we can set up an algebraic equation. Let's denote the original number as x. Half of that number would be x/2 and one fifth of that number would be x/5. The equation representing the given condition is:

x + x/2 + x/5 = 51

To solve this, we need a common denominator to combine the fractions:

Therefore, the original number is 30.

You can use the fact that median is affected only if the middle value(s) are changed if number of values are same.

The median is the middle value of the sorted(ordered in ascending or descending way)data values. If value changed is not the middle value (if number of observations are odd) or is not changing the average of two mid values (if number of observations are even), then the median won't change as it does't care about the value of the data unless its about the mid value of the sorted data or average of mid values.

The mean is affected by the data.

The mean of n values  is calculated as:

[tex]\overline{x} = \dfrac{x_1 + x_2 + ... + x_i + ... + x_n}{n}[/tex]

Suppose that x_i changed to y

Then we have then new mean as

[tex]\begin{aligned}\overline{x}_{new} &= \dfrac{x_1 + x_2 + ... + (x_i -x_i + y)+ ... + x_n}{n}\\&= \dfrac{x_1 + x_2 + ... + x_i+ ... + x_n}{n} + \dfrac{-x_i + y}{n}\\&= \overline{x} + \dfrac{y-x_i}{n}\\\end{aligned}[/tex]

For the given data, one value was changed from $40,000 to $20,000, thus, as $40,000 was lowest value of the data, thus median stays same as before,.

And for new mean, we have:

[tex]\overline{x}_{new} = \overline{x} + \dfrac{y-x_i}{n} = \overline{x} + \dfrac{-20000}{5}\\\\\overline{x}_{new} = \overline{x} -4000[/tex]

Thus, new mean salary will be $4000 less than the previous mean  salary.

Learn more about mean versus median here:

https://brainly.com/question/14315366

Decreasing Valerie's salary will lower the mean salary of the teachers. The effect on the median depends on the other salaries, but if Valerie's salary was the minimum, the median may remain unchanged.

Decreasing Valerie's salary from $40,000 to $20,000 will affect both the mean and median salaries of the teachers in the school. To determine the impact on the mean salary, we would subtract the amount of the decrease from the total salaries and then divide by the number of teachers. Originally, if we assume the other four teachers earn salaries between $40,000 and $70,000, the total salary pool would be the sum of all five teachers' salaries. With Valerie’s decrease, the new total would be $20,000 less. Dividing this new total by 5 would give us the new mean salary.

As for the impact on the median salary, this depends on where Valerie's original salary of $40,000 stood in relation to the other four salaries. Since she was making the minimum amount within the provided salary range, if all other teachers make more than $40,000, Valerie's reduced salary will not change the median, as the median is the middle value when all salaries are listed in order. However, if Valerie's salary was at the median, her reduced salary would lower the median if the next lowest salary is less than $40,000.

You would expect to roll a 6 approximately 20 times in 120 rolls. This is because, on average, in the long run, you would expect a specific outcome (in this case, rolling a 6) to occur with a frequency proportional to its probability (1/6) over a large number of trials (120 rolls).

When rolling a fair 6-sided number cube, each of the six faces has an equal probability of landing face up. The probability of rolling a 6 on a fair 6-sided number cube is 1/6.

To find out how many times you would expect to roll a 6 in 120 rolls, you can use the probability formula:

Expected number of successful outcomes = Probability of success * Total number of trials

Expected number of times to roll a 6 = (1/6) * 120

Expected number of times to roll a 6 = 20

To know more about roll:

https://brainly.com/question/10184142

#SPJ6

Answer:

{(3, –1), (7, 1), (–6, –1), (9, 1), (2, –1)}

Step-by-step explanation:

A set of ordered pairs in the format [tex](x,y)[/tex] represents a function if for each value of x, there is only one value for y.

The first set of ordered pairs is:

{(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)}

There are two values of y for [tex]x = 1[/tex]. This means that this set of ordered pairs does not represent a function.

The second set of ordered pairs is:

{(3, –1), (7, 1), (–6, –1), (9, 1), (2, –1)}

For each value of x here, there is only one value of y. This means that this set of ordered pairs represents a function. This is the answer.

The third set of ordered pairs is:

{(6, 8), (5, 2), (–2, –5), (1, –3), (–2, 9)}

There are two values of y for [tex]x = -2[/tex]. This means that this set of ordered pairs does not represent a function.

The fourth set of ordered pairs is:

{(–3, 1), (6, 3), (–3, 2), (–3, –3), (1, –1)}

There are two values of y for [tex]x = -3[/tex]. This means that this set of ordered pairs does not represent a function.

Answer: quadrant 4

Step-by-step explanation:

Answer:

Area of ellipse is ≈ 77.78 [tex]m^{2}[/tex]

Step-by-step explanation:

Given the dimension of ellipse

  a = 4.5 m

  b = 5.5 m

Now, Area of ellipse = [tex]\pi ab[/tex]

                                  = [tex]\frac{22}{7}\times 4.5\times 5.5[/tex]

                                  = [tex]\frac{5445}{70}[/tex]

                                  = 77.78 [tex]m^{2}[/tex]

Hence Area of ellipse will be 77.78 [tex]m^{2}[/tex]

The area of the ellipse is calculated using the formula A = ab, with the given semi-major axis of 4.5 m and semi-minor axis of 5.5 m, estimated to two significant figures as 78 m².

The area A of an ellipse with semi-major axis a and semi-minor axis b is given by the formula A = \ab. Given that a = 4.5 m and b = 5.5 m, we can calculate the area of the ellipse using a calculator. Keeping in mind that we should report our final answer to the same number of significant figures as the least precise measurement provided (which in this case is two significant figures), we have:

A = \(4.5 m)(5.5 m)

A = 3.1415927... × 24.75 m²

A = 77.66546225 m²

However, due to the significant figures rule our reported answer should be:

A = 78 m²

Answer: I, III, and IV only

Step-by-step explanation:

Here, we need to find unit cost. Unit cost can be defined as a cost per unit of a product.

We are given that 16 ounce will cost $ 4.00.

That means -

Cost of 16 ounce of cereal package = $ 4.00

Cost of 1 ounce of cereal package -

(We will divide both sides by 16)

Cost of 16 ounce of cereal package ÷ 16 = $ 4.00 ÷ 16

Cost of 1 ounce of cereal package = $ 0.25.

Thus, the cost of 1 ounce of cereal package = $ 0.25.

Answer: 1 oz. Over 0.25 is your answer.

Step-by-step explanation:

The length of row of bolt will be calculated by adding the size of all the bolts.

To find the mass of the solid hemisphere using spherical coordinates with density proportional to distance from center, integrate the density times the volume element over the hemisphere.

To find the mass of the solid hemisphere using spherical coordinates, we first need to understand that the density at any point is proportional to its distance from the center of the base. Let's denote the constant of proportionality as k. The mass can be found by integrating the product of density and volume over the entire hemisphere. The volume element in spherical coordinates is given by ρ² sinϕ dρ dϕ dθ, where ρ is the radial distance, ϕ is the polar angle, and θ is the azimuthal angle.

We can denote the density as ρ = kρ, where ρ is the radial distance from the center. The mass element dm is then given by dm = ρ² sinϕ dρ dϕ dθ = kρ³ sinϕ dρ dϕ dθ. To obtain the mass of the hemisphere, we need to integrate the mass element over the appropriate limits, which are ρ = 0 to 1, ϕ = 0 to π/2, and θ = 0 to 2π.

Performing the integration, we get the mass as M = ∫∫∫ kρ³ sinϕ dρ dϕ dθ = πk/6.

https://brainly.com/question/35872066

#SPJ11

Answer:

d

Step-by-step explanation:

denisity * volume = mass

Here, in order to find the solutions to the quadratic equation - x² + x - 30 = 0, we will use factorization method.

In the method, we will split 30, in such factors, which when added or subtracted gives us 1,  and when multiplied gives us -30.

So, we will use, -5 and 6. When they are added they will give us 1 and when multiplied they will give us -30 as answer.

Now, the equation will be written as -

x² - 5x + 6x - 30 = 0

Taking common, we get

x(x - 5) +6(x-5) = 0

(x-5)(x+6) = 0

So, x - 5 = 0 and x +6 = 0, we will get, x = 5 and x = - 6

Thus, the correct option is C). x = 5 and -6

the correct option is:

b.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4: 15.44-0.6562=14.7838

Let's break down the calculations:

Step 1: Calculate the amount of water lost at the end of the first hour.

[tex]\[ \text{Amount lost} = 0.035 \times 16 = 0.56 \][/tex]

Step 2: Subtract the amount lost from the initial amount to find the remaining water at the end of the first hour.

[tex]\[ \text{Remaining water} = 16 - 0.56 = 15.44 \][/tex]

Step 3: Calculate the amount of water lost at the end of the second hour.

[tex]\[ \text{Amount lost} = 0.0425 \times 15.44 = 0.6562 \][/tex]

Step 4: Subtract the amount lost from the remaining water at the end of the first hour to find the remaining water at the end of the second hour.

[tex]\[ \text{Remaining water} = 15.44 - 0.6562 = 14.7838 \][/tex]

So, the correct option is:

b.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4: 15.44-0.6562=14.7838

The complete Question is given below:

A student uses a solution that contains 16 grams of water to conduct an evaporation experiment.

At the end of one hour, the amount of water in the solution has decreased by 3.5% .

At the end of two hours, the amount of water in the solution has decreased by another 4.25% .

Which calculations can be used to determine the amount of water, in grams, remaining in the solution at the end of the second hour?

a.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4:16-0.6562=15.3438

b.

Step 1:0.035 xx16=0.56

Step 2: 16-0.56=15.44

Step 3: 0.0425 xx15.44=0.6562

Step 4: 15.44-0.6562=14.7838

c.

Step 1:0.35 xx16=5.6

Step 2: 16-5.6=10.4

Step 3: 0.425 xx10.4=4.42

Step 4:16-4.42=11.58

d.

Step 1: 0.35 xx16=5.6

Step 2: 16-5.6=10.4

Step 3: 0.425 xx10.4=4.42

Step 4:10.4-4.42=5.98