Answer:
Spores are made by the millions, so some of them are likely to land in a good place to grow. Spores are lightweight and can drift around on the slightest air currents, so spores are spread far and wide. Spores have hard outer coverings to protect them until they begin to grow.
Explanation:
What is a phenotype?
a. the result of an individual's genetic constitution
b. one of the various forms of a gene
c. the set of chromosomes
d. the genetic constitution of an individual
e. the set of chromosomes including the sex ct not counting the sex chromosomes
Answer:
a. the result of an individual's genetic constitution
Explanation:
Phenotype is the morphological expression of genotype. The genetic constituent of an individual is known as genotype. Genotype determines the genetic traits and imparts specific features of the organisms which constitute the phenotype of the organism.
The phenotype of the organisms depends on the type of the alleles of the genes present in the genome of the organisms.
For example, a human with genotype "ii" has blood type "O". Here, "ii" is the genotype that is responsible for phenotype "O blood type".
On the other hand, a human with genotype "IAIA" has blood type "A". Here. "blood type A" is the phenotype.
__________ play(s) an important role in both humoral and cell-mediated immunity.
a. killer cytotoxic (CD8+) T cells
b. neutrophils
c. B lymphocytes
d. Helper T cells (CD4+)
e. all of the above play an important role in both humoral and cell-mediated immunity
Answer:
d. Helper T cells (CD4+)
Explanation:
There are two kinds of immune responses, innate and adaptative (humoral and cell-mediated):
Innate immunity is the first barries the body has against invaders, most of their responses are non-specific and non-induced, but some use pattern recognition receptor to recognize invaders, some of the leucocytes that are involved in this response are neutrophils, macrophages, and NK killers.Adaptative immunity
Cell-mediated immunity (CMI) refers to protective mechanisms that are not characterized by antibody, this kind of immunity is responsible for detecting and destroying intracellular pathogens, tumor cells and delayed-type hypersensitivity reactions. This CMI is mediated by lymphocytes T, T helpers identifying endogenous antigens and stimulating Killer cytotoxic (CD8+) T cells that liberate perforating enzymes into the infected cells causing lysis.
Humoral immunity describes the kind of immunity in which antibodies are produced by B lymphocytes to target exogenous antigens. In this kind of response Helper T cells also play a role secreting cytokines to activate the appropriate B lymphocyte.
Hope you find this information useful! good luck!
Answer:
Helper T cells (CD4+)
Explanation:
In the case of hummoral immunity, Helper T cells help in the differentiation of B cells into plasma B cells . The plasma B cells are then involved in the production of antibodies for specific kind of antigens. In the case of cell-mediated immunity helper T cells are involved in releasing cytokines and help differentiate the T cells into cytotoxic T cells. In the case of cell mediated immunity, the affected cell undergoes the process of lysis.
One of the side effects of anabolic steroids in girls is irregular periods.
a. True
b. False
Answer:
True.
Explanation:
Anabolic steroids may be defined as the hormones that are taken in the forms of pill or can be directly injected into the body. The muscle mass of the body can be increased by the anabolic steroids.
Anabolic steroids can have negative effects on both the male and females. The anabolic steroids effects on female causes irregular menstrual cycle, moustache and the development of broad shoulders.
Thus, the answer is true.
In which direction does RNA synthesis proceed?
a. left to right
b. 3' to 5'
c. top to bottom
d. 5' to 3'
Answer:
5' to 3'.
Explanation:
Transcription may be defined as the process of formation of RNA molecule from the template DNA with the help of enzymes and the various transcriptional factors.
The process of RNA synthesis occur in the 5' to 3' direction. The RNA polymerase reads in the 3' to 5' direction and leads to the synthesis in 5' to 3' direction. The transcription factors binds to the DNA promoter during RNA synthesis.
Thus, the correct answer is option (d).
What is the difference between Southern and Northern hybridizations?
a. southern blots hybridize a DNA probe to a digested DNA sample but northern blots hybridize a DNA probe to, usually, mRNA
b. southern blots use an RNA probe to hybridize to DNA but northern blots use an RNA probe to hybridize to RNA
c. southern blots determine if a particular gene is being expressed but northern blots determina the homology between mRNA and a DNA probe
d. southern blots determine the homology between mRNA and a DNA probe but northern blots determine if a particular gene is being expressed
e. southern and northern blots are essentially the same technique performed in different hemispheres of the world.
Answer:
a. southern blots hybridize a DNA probe to a digested DNA sample but northern blots hybridize a DNA probe to, usually, mRNA
Explanation:
Both techniques are quite similar. The main objective of this technique is to identified specific either DNA or mRNA molecules. Hybridization is the process of forming a double - stranded DNA molecule between a single-stranded DNA probe and a single-stranded target DNA (which is the fragment that wants to be found. Northern blotting targets mRNA while Southern blotting targets DNA sequences.
How might a bacterium resist thekilling effects of a phagolysosome?
Answer:
There are several mechanisms, like resistance to antimicrobial agents, encapsulation or secretation of proteins that affects and might destroy the phagocyte
Explanation:
Some leukocytes in our body perform phagocytosis as a defense mechanism against the pathogenic bacterium. These phagocytes contain lysosomes, intracellular granules that possess bactericidal substances (especially toxic oxygen species, such as H2O2) and enzymes (proteases, lipases, etc.). When the phagocyte ingests the pathogen, a phagosome is formed, which merges with the lysosome, forming the phagolysosome, which is where toxic substances and enzymes kill the ingested microorganism.
There are several mechanisms by which a microorganism can survive this process:
-Resistance to antimicrobial agents. Some bacteria use phenolic glycolipids from their cell wall, to eliminate toxic oxygen compounds (i.e Staphylococcus aureus and mycobacterium tuberculosis).
-Some pathogens produce a protein called leukocidin, a cytotoxin that destroys the phagocyte and the pathogen is free. Generally, these bacteria are the generators of pus, like Streptococcus pyogenes.
- There are bacteria whose mechanism is encapsulation, increasing their resistance to phagocytosis (i.e Streptococcus pneumoniae). Some even secrete substances on their surfaces, called M proteins, that prevents phagocytosis from completing
Answer: Through the inhibition of the fusion between the phagosome and the lysosome.
Explanation:
Bacteria are pathogens recognized by the immune system. When one of them enters the body, cells of the innate immune system such as dendritic cells or macrophages recognize them and phagocyte them. These bacteria, once inside the immune system cell (called phagocyte), are housed in vesicles called phagosomes. They eventually fuse with lysosomes, which are organelles containing hydrolytic enzymes for the degradation of componentens. When the phagosome, which contains the bacteria, fuses with the lysosome, the bacteria are degraded.
The bacteria may be able to survive inside of phagosomes because they prevent the fusion of the phagosome with the lysosome. And this prevents the discharge of lysosomal enzymes into the phagosome.
This strategy is employed, for example, by M. tuberculosis and Salmonella. This can be achieved through the release of sulfates which are bacterial cell wall components. Those sulfates modify the lysosomal membrane and this inhibits the fusion.
-
What does it mean to say that double-stranded nucleic acids are
antiparallel?
Answer:
DNA is the genetic material of all the living organism except some viruses. The structure and the characteristics of the DNA was well explained by Watson and Crick.
DNA is a double stranded molecule in which nitrogenous bases are linked together. Watson and crick explained that DNA strand are antiparallel. The antiparallel nature of the strand means one DNA gas a polarity of 5' to 3' direction whereas the another strand of the DNA gas polarity of 3' to 5' direction. These two strands has opposite polarity and runs in anti parallel directions. Thus, the DNA strand known as antiparallel strands.
How does complement connect the innate and adaptive immune responses?
Answer:
Innate immunity: first line of defense against infectious agents; Most pathogens can be controlled before a declared infection occurs.
Adaptive immunity: takes action when innate immunity fails. Make a specific response for each infectious agent and keep memory of it (it can prevent reinfection).
Explanation:
The immune system has evolved to be able to identify the strangers and develop a protective response to the latter (cognitive and destructive processes).
Innate or natural immunity: it is present at birth, being the first line against invasive microorganisms. Its characteristics are: it is present for life, it is not specific, it lacks memory and does not change intensity with exposure. It is useful against pyogenic microorganisms, fungi and multicellular parasites and includes three components: 1) physicochemical: skin, mucous membranes, secretions and cilia, which perform a washing and continuous cleaning, 2) humoral: complement, lectin binding to mannan and opsonins additional as C-reactive protein and proteolytic enzymes and 3) cellular: neutrophils, eosinophils, mast cells and natural killer lymphocytes.
Complement: it includes a high number of serum proteins that are produced mainly in the liver, form cascades so that each activated component catalyzes the activation of several molecules of the next component, amplifying the response. The consequences are cell lysis, the production of proinflammatory mediators and the solubilization of antigen-antibody complexes. Activation of the complement system occurs through three different pathways (alternating, classical and mannan-binding lectin) that converge in the final common pathway that provides most of the biological activity.
Cellular mechanisms: Neutrophils participate in the destruction of bacteria and fungi. Upon activation, adhesion molecules facilitate their entry into tissues, moving to chemical attractants and phagocytizing microorganisms. Destruction is mediated by oxygen dependent and independent pathways.
acquired immunity: acquired as part of development, increases with age and with repeated exposures, has specificity and memory for what is called adaptive. Its components are antibodies and cells (lymphocytes) and protects against bacteria (including those that produce intracellular infections), viruses and protozoa. In general, innate and acquired immune responses are not activated independently but complement each other.
Antigen-Antibodies: Antigens are structures that generate an anti-response from the immune system that has 3 elements of union and recognition of these;
1) antibodies that are soluble glycoproteins belonging to the group of immunoglobulins produced by B lymphocytes and plasma cells,
2) T-cell receptors that are large glycoproteins that interact with the peptide epitope preserved and presented by the third element
3) which are the major histocompatibility complex (CMH) molecules.
Antibodies perform many functions and have numerous uses as biological and clinical instruments
What are the major differences between the anterior and posterior pituitary?
Answer:
Anterior pituitary:
The anterior pituitary has been originated from the Rathke's pouch. Several different hormones are released from the anterior pituitary. The hormones of anterior pituitary is synthesized in the anterior pituitary. The blood is supplied by the superior hypophyseal nerves. Both the releasing and inhibitory hormones controlled the anterior pituitary.
Posterior pituitary:
Posterior pituitary has been originated by the hypothalamic neural tissue. Only two hormones are released from the posterior pituitary. The hormones are synthesized in the hypothalamus and released by the posterior pituitary. The blood is supplied by the inferior hypophyseal nerves. The posterior pituitary is controlled by the neural signals.
Regarding fiber, which one is not correct?
a. If you want to add fiber in your diet also eat the seeds and skins in fruits and vegetables.
b. The removal of the outer husk or bran from our wheat diminished the integrity of our grains.
c. The lack of fiber in the Western diet (that's our diet) was causing gastrointestinal problems that many countries and continents had not seen: diverticulitis, diverticulosis, constipation, increase in colon cancers, etc.
d. You cannot eat too much fiber.
Answer:
d. You cannot eat too much fiber.
Explanation:
Fiber also called as roughage forms the part of plant based foods. Body is not able to digest it so it passes through the digestive system and makes the bulk of stool. It keeps the digestive system clean and eases bowel movements.
The daily required intake of fiber is 25-30 grams. Many people do not take this much fiber hence suffer from problems like constipation, upset stomach etc. But crossing the threshold of 70 grams of fiber can also lead to another set of problems like:
bloatinggasdehydrationpoor absorption of some nutrients like calcium, zinc, iron and magnesium because they bind with the fiber which hinders the absorption process.In Drosophila, males from a true-breeding stock with raspberry-colored eyes were mated to females from a true-breeding stock with sable-colored bodies. In the F1 generation, all the females had wild-type eye and body color, while all the males had wild-type eye color but sable-colored bodies. When F1 males and females were mated, the F2 generation was composed of 216 females with wild-type eyes and bodies, 223 females with wild-type eyes and sable bodies, 191 males with wild-type eyes and sable bodies, 188 males with raspberry eyes and wild-type bodies, 23 males with wild-type eyes and bodies, and 27 males with raspberry eyes and sable bodies. Explain these results by diagramming the crosses, and calculate any relevant map distances.
Answer:
This results are explained by the fact that these two genes are in the X chromosome and both mutations are recessive.
There is a estimated map distance of 5.76 cM.
Explanation:
First step is to know what are the initial phenotypes, they say "males from a true-breeding stock" that means that they are homozigous for both genes. Also, they say that in F1 generation, all females had the same phenotype but all males had a different phenotype than females, so this suggest a sex-linked inheritance. In the F1 generation, females had a wild type phenotype, but we know these females had to carry the mutant copies of the two genes, so mutant alleles must be recessive.
Therefore, if r is the allele for raspberry-colored eyes and s for sable-colored bodies, the genotypes of parents should be:
- Males with raspberry-colored eyes (wild type for body color):
[tex]X^{rS}Y^{}[/tex]
- Females with sable-colored bodies (wild type for eyes color):
[tex]X^{Rs}X^{Rs}[/tex]
If they are crossed, we obtain the results on the Punnet Square.
If there is not recombination, we expect F2 as in Punnter Square, but in the results, there are two phenotypes that were not expected: wild type males (23) and males with raspberry-colored eyes with sable-colored bodies (27). These two should be recombinants. To calculate the distantance between the two genes, we use:
[tex]Distance=\frac{recombinants}{Total }*100[/tex]
[tex]Distance=\frac{23+27}{868}*100=\frac{50}{868}*100=5.76 cM[/tex]
Therefore, distance between s and r is 5.76 centimorgans.
Which of the following intermediary metabolites enters the Krebs cycle and is formed, in part, by the removal of CO2 from a molecule of pyruvate?
A) lactate
B) glyceraldehyde phosphate
C) oxaloacetic acid
D) acetyl CoA
E) citric acid
Answer:
The correct answer will be option-D.
Explanation:
Before Citric acid cycle or Krebs cycle, an intermediate reaction takes place which converts the pyruvate into Acetyl CoA. This reaction is known as pyruvate decarboxylation as it produces Carbon dioxide.
Coenzyme A reacts with pyruvate which causes the release of two oxygen atoms and one carbon to form CO₂ along with the reduction of NAD+ to NADH and produce "Acetyl CoA."
Thus, option-D is the correct answer.
The intermediary metabolite formed by the removal of CO2 from pyruvate and that enters the Krebs cycle is acetyl CoA. This occurs in the phase of cellular respiration known as decarboxylation.
Explanation:The intermediary metabolite that enters the Krebs cycle and is formed, in part, by the removal of a CO2 molecule from a molecule of pyruvate is acetyl CoA (option D).
The process occurs during cellular respiration. Specifically, one carbon atom from pyruvate is released as one molecule of CO2 in a step called decarboxylation, facilitated by an enzyme complex in the mitochondrial matrix. This remaining two-carbon molecule then combines with Coenzyme A to form Acetyl CoA, which enters the Krebs cycle.
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What is normally present in urine? How does the filtration barrier function to prevent things from entering the filtrate? What does it prevent from entering?
Answer:
Generally urine comprises about 95 percent water, 2 percent electrolytes, that is, ions of salts, primarily sulphates, chlorides, potassium, bicarbonates of sodium, and others, 2.6 percent urea, 0.3 percent uric acid, and small quantities of ammonia, creatinine, hormones, some of the pigments, hippuric acid, and allantoin.
The filtration barrier comprises of the glomerular capillaries fenestrated endothelium, the filtration slits of the podocytes, and the fused basal lamina of the podocytes and the endothelial cells. The barrier allows the entry of water, small molecules, and ions from the bloodstream into the space of Bowman capsule.
The barrier restricts passing of negatively charged and/or large proteins like albumin. The basal lamina of the filtration barrier comprises three layers. Any small molecules like glucose, water, salt, urea, and amino acids can pass freely into the Bowman's space, however, the cells, large proteins, and platelets do not.
What gives DNA its acid property?
a. the parts that make up the steps
b. the sugar
c. the part that alternates with sugars in a strand
d. the hydroxyl group attached to the 4' carbon
e. the covalent bonds that connect the steps to the strands
Answer:
The correct answer will be option-C.
Explanation:
Each DNA molecule exists in helical shape made by two strands of nucleotides. Each nucleotide is composed of a five-carbon sugar, a phosphate group and nitrogenous bases.
The sugar-phosphate unit bond via the phospho-diester bond and form the backbone of the DNA. The phosphate functional group is acidic in nature as it donates the proton while the formation of the phosphodiester bond which provides DNA with the acidic nature.
Thus, Option-C is the correct answer.
Which statements is true of all atoms that are anions?
a. The atom has more electrons than protons.
b. The atom has more protons than electrons.
c. The atom has fewer protons than does a neutral atom of the same element.
d. The atom has more neutrons than protons.
Answer:
The atom has more electrons than protons.
Explanation:
Ions may be defined as the element that contains either positive or negative charge over it. Two types of ions are cations and the anions. The charge on the species is obtained by the loss or gain of electron.
Anions carry negative charge over them. Negative charge occurs by gaining of the electrons from its neighboring atoms. The number of protons and electrons are equal in neutral atom. Since, the ions gain the electron and hence it carries more protons.
Thus, the correct answer is option (a).
An anion is an atom that has gained electrons and has more electrons than protons.
Explanation:The correct statement among the options is a. The atom has more electrons than protons.
An anion is a negatively charged ion, which means it has gained one or more electrons. This results in the atom having more electrons than protons, giving it a net negative charge.
For example, consider the chloride ion (Cl-) in table salt. It has 17 protons and 18 electrons, so it has one extra electron, making it a negatively charged anion.
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Testosterone is produced in the
A. Sperm cells.
B. Seminiferous tubules of the testes.
C. Interstitial cells of the testis.
D. Epididymis.
E. Anterior lobe of the pituitary.
The correct answer is C. Interstitial cells of the testis.
Explanation:
The testosterone is one of the main sex hormones in males, due to this, this hormone is linked to sexual characteristics as well as behavior, mass muscle development, among others. In terms of testosterone production, the production of testosterone occurs mainly on the testis (reproductive glands or gonads) and more specifically in the interstitial cells of these called Leydig cells which are specialized cells that besides producing testosterone produce androstenedione and dehydroepiandrosterone. Additionally, the production of any hormone in this cell is stimulated by the luteinizing hormone. According to tho this, it can be concluded testosterone is produced in the interstitial cells of the testis.
Testosterone is produced in the interstitial cells of the testis.
Explanation:Testosterone is produced in the interstitial cells of the testis. These cells, also known as Leydig cells, are located in the testes and are responsible for the production of testosterone. The hormone is then released into the bloodstream and has various effects on the body, including the development of male reproductive organs and secondary sexual characteristics.
The hormone Testosterone is primarily produced in the Interstitial cells of the testis, also known as Leydig cells. These cells are located in the connective tissue between the seminiferous tubules in the testes. The production of testosterone is stimulated by Luteinising Hormone (LH) which is produced in the anterior lobe of the pituitary gland in the brain. However, the pituitary gland does not produce testosterone itself. Hence, the correct answer to your question is C. Interstitial cells of the testis.
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Absence of bicoid mRNA from a Drosophila egg leads to the absence of anterior larval body parts and mirror-image duplication of posterior parts. This is evidence that the product of the bicoid gene
a. normally leads to formation of head structures.
b. normally leads to formation of tail structures.
c. is transcribed in the early embryo.
d. is a protein present in all head structures.
Answer:
a. normally leads to formation of head structures.
Explanation:
The product of the bicoid gene is a protein that is responsible for establishing the anterior-posterior axis during the embryogenesis phase of Drosophila development.The bicoid protein is localized at the anterior end of the egg of the drosophila and the anterior end it represses the expression of the mRNAs that are translated at the posterior end and helps in the expression of only anterior genes due to which it plays an essential role in the formation of anterior structures and thus the head of the fruit fly.Therefore, from the given question it is very clear that since the absence of anterior larval body parts occurs in the absence of bicoid mRNA, bicoid must be specifying the head structures.The product of the bicoid gene in Drosophila predominantly influences the formation of anterior body parts, suggesting that it primarily leads to the formation of head structures.
Explanation:Based on the provided information, bicoid mRNA's absence from a Drosophila egg causes the absence of anterior (head/front) body parts and duplicates posterior (tail/back) parts. This indicates that the bicoid gene's product primarily influences the formation of anterior parts. It can be inferred that the bicoid gene's product is crucial in the formation of the head structures. So, the correct answer is, (a) the bicoid gene's product normally leads to the formation of head structures.
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Assume that genes A and B are 50 map units apart on the same chromosome. An animal heterozygous at both loci is crossed with one that is homozygous recessive at both loci. What percentage of the offspring will show recombinant phenotypes? Without knowing that these genes are on the same chromosome, how would you interpret the results of this cross?
Answer:
Explanation:
The homozygous recessive individual can only produce 1 type of gamete (aabb).
The heterozygous individual can produce 8 types of gametes, of which 2 are parental and the rest are recombinant.
Genetic distance (m.u.) = Frequency of Recombination (%)
If the distance between genes A and B is 50 m.u., 50% of the gametes produced by the heterozygous individual, and therefore the offspring, will have recombinant phenotypes.
Without knowing that the genes are located on the same chromosomes, I'd think they are on different chromosomes, because you would get the same result: 50% recombinant offspring.
Whenever the genes on the same chromosome are separated by at least 50 m.u., or they are in different chromosomes, crossing over between them can happen with no restrictions and they will behave as independent of one another.
Given a genetic distance of 50 map units (centimorgans, cM), we would expect to see approximately 50% of offspring expressing recombinant phenotypes due to recombination or crossover events. This rate corresponds to a 50% recombination frequency. If we didn't know the genes resided on the same chromosome, we'd expect a Mendelian ratio assuming independent assortment.
Explanation:Given the genetic distance of 50 map units or centimorgans (cM) apart, genes A and B indicate that they are far apart on the same chromosome. Thus, the likelihood of recombination or crossover events between these genes resulting in recombinant phenotypes is high. Specifically, the recombination frequency corresponds to the genetic distance, meaning that with a distance of 50 cM, we expect about 50% of the offspring to express recombinant phenotypes.
Since you asked how one might interpret this information without knowledge of these genes being on the same chromosome, it is important to mention that if we didn't know this, we would expect to see Mendelian ratios assuming independent assortment of the genes. That is, the appearance of recombinant and parental types would be approximately equal, again indicative of a 50% recombination frequency.
This is due to the random segregation during the formation of gametes, where it's equally likely that either allele from one parent will be passed on to the offspring. This recombination frequency therefore, indicates that every type of allele combination is represented with equal frequency or 50 percent of offspring are recombinants. The other 50 percent retain the original, parental combinations of traits.
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What are the organs that comprise the circulatory system?
Answer:
Explanation:
The circulatory system consists of typically two organs these are the heart which also belong to the cardiovascular system and the lungs which also belong to the respiratory system these are connected to the arteries, veins and other blood vessels. The lungs receives the oxygen which diffuse oxygen into the blood vessels which transports the oxygenated blood to the heart which is pumped and circulated by the heart to all the parts of the body.
Assume that you have 1 mL of a solution of amylase (an enzyme) at a concentration of 15 mg protein/mL. Calculate the volume of diluting buffer that you would have to add to 1.0 mL of the amylase stock solution if you wished the final concentration of the solution to be 345 µg protein/mL.
Answer:
42,5 mL
Explanation:
We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.
[tex]DF=\frac{Vi}{Vf}[/tex]
DF in the dilution factor, Vi is the initial volume and Vf is the final volume.
The first step is to have the same measurment unit so we need to convert 345 µg to mg.
we know that 1 µg equals 0,001 g, hence:
[tex]345 µg = 0,345 mg[/tex]
now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula
[tex]DF= \frac{15mg protein/mL}{0.345mg protein/mL}[/tex]
[tex]DF= 43,5 mg protein/ mL[/tex]
Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL
[tex]43,5mL-1,0mL = 42,5 mL[/tex]
So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)
To dilute a 15 mg/mL amylase solution to a final concentration of 345 \\/strong>\mu\g/mL\strong>, approximately 42.48 mL of diluting buffer needs to be added to 1 mL of the initial solution.
To calculate the volume of diluting buffer needed to adjust the concentration of a solution, you can use the dilution equation C₁V₁ = C₂V₂, where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume after dilution. Starting with 1 mL of a 15 mg/mL amylase solution, you want a final concentration of 345 \\mu\g/mL. First, convert the final desired concentration to mg/mL by dividing by 1,000 (because there are 1,000 micrograms in a milligram), giving you 0.345 mg/mL as C₂.
Using the dilution equation:
C₁V₁ = C₂V₂
(15 mg/mL)(1 mL) = (0.345 mg/mL)(V2)
V2 = (15 mg/mL * 1 mL) / (0.345 mg/mL)
V2 = 43.478 mL
To find the volume of buffer required, subtract the initial volume (V₁) from the total final volume (V₂).
Buffer Volume = V₂ - V₁
Buffer Volume = 43.478 mL - 1 mL
Buffer Volume = 42.478 mL
So, you need to add approximately 42.48 mL of diluting buffer to the 1 mL amylase solution to achieve the desired concentration of 345 \\mu\g/mL.
Discuss the major cell and tissue types found in thetypical animal
body.
Answer:
Explanation:
The animal body consists of different types of cells. The cells have arisen from unspecialized cells such as stem cells. The stem cells are the totipotent cells that have the capacity of producing different types of cells. The cells are grouped to perform a particular function and called tissues.
The tissues are an aggregation of cells having a similar structure and function. There are mainly 4 types of tissues epithelial tissue, connective tissue, muscular tissue, nervous tissue.
The epithelial tissues are also 2 types are single epithelial, compound epithelium. The simple epithelial tissues are single-layered cells, and compound epithelial tissue is multilayered cells.
The simple epithelial cells are squamous epithelium, cuboidal epithelium, columnar epithelium, pseudostratified epithelium.
Connective tissues: These are binding tissues, connect different tissues with the body parts. These tissues consist of cellular parts and ground substances. The connective tissues are 3 types - connective tissue proper, skeletal tissues (bone and cartilage), vascular (blood and lymph).
Muscular tissue :
These are the specialized tissues meant for contraction and relaxation. Muscular tissue contains 2 contractile tissues - actin and myosin. Muscular tissue is types - striated muscle, smooth muscle, and cardiac muscle.
Nervous tissue: These are highly excitable cells, carry impulse. These include the neurons. Nervous tissues arise from the ectoderm.
List all the ways in which CO2 is transported in the blood. Of these, how is the majority of the CO2, transported in the blood?
Answer:
Carbon dioxide is the prime waste component of aerobic respiration. Too little or too much carbon dioxide in the blood can result in extreme issues. In order to make this safe and sound, carbon dioxide is transported in the blood in three ways. That is, in the form of carbamino compounds, hydrogen carbonate, and in the form of a dissolved state.
Approximately 30 percent of all the carbon dioxide is mediated in the form of carbamino compounds. At high quantity, carbon dioxide binds directly with amino acids and the amine groups of hemoglobin to produce carbaminohaemoglobin.
Almost 60 percent, that is, the majority of the carbon dioxide is transported in the blood in the form of bicarbonate ions or hydrogen carbonate. The diffusion of carbon dioxide takes place in the RBCs and gets transformed into bicarbonate ions and hydrogen ions with the help of an enzyme known as carbonic anhydrase.
Approximately 10 percent of all the carbon dioxide is transported in the form of a dissolved state in plasma. The concentration of gas dissolved in a liquid relies upon its partial pressure and its solubility. In spite of its solubility, only some of the carbon dioxide in the blood is in reality transported in the form of dissolved state in plasma.
Answer:
CO2 is transported in three forms from tissues to the alveoli: a) In dissolved form through plasma; b) As bicarbonate ions; c) by RBC as HbCO2.
Explanation:
When oxygen reaches the body cells, oxidation of glucose takes place during which CO2 is released along with H2O and energy. CO2 diffuses out of the tissues into the blood capillaries where it is transported to the lungs in three forms:
1. In dissolves form in plasma: About 7% of CO2 gets transported in dissolved form. It gets dissolved in the blood plasma and is carried to the lungs.
2. As bicarbonate ions: about 70% of CO2 is converted into bicarbonate ion and transported in plasma. Within the RBC there is an enzyme called carbonic anhydrase. When CO2 enters the RBC, it reacts with water to form carbonic acid which further dissociates into bicarbonate and hydrogen ion. Both these reactions occur in the presence of carbonic anhydrase enzyme. The HCO3- ion formed in the RBC quickly diffuses into the plasma, where they are carried to the lung.
3. By RBCs as carbaminohemoglobin: About 20-25% of CO2 is transported as HBCO2. CO2 binds with the amino group of globin protein which is a part of Hb.
Which of the following cells or structures are associated with asexual reproduction in fungi?
a.ascospores c.zygosporangia
b.basidiospores d.condiophores
Answer:
d.condiophores is the correct answer.
Explanation:
condiophores is cells or structures are associated with asexual reproduction in fungi
Conidium, a kind of asexual spore-bearing bodies of fungi normally produced at the top of hyphae on specific spore-producing stalks called conidiophores.
The spores get released and detach when it is mature.Then spores germinate into a new hypha and hypha develops into a mycelium.
Thus the Axseual reproduction in Fungi(ascomycetes) occurs by the generation of conidia which are produced on a specialized structure called conidiophores.
Answer:
d. condiophores
Explanation:
As you may know, fungal spores are the main structure for the asexual reproduction of these organisms. These spores are formed in hyphae, but some fungi have special hyphae called conidiophores and their spores called conidia, which are structures for the asexual reproduction of these fungi. For this reason, we can say that, among the options given in the question above, "conidiophores" is the structure that is associated with asexual reproduction in fungi.
Which (if any) of the following statements regarding staphylococcal food-borne illness is not correct? If all of the statements are correct, choose the final answer.
a. the disease is caused by ingestion of a toxin
b. the bacterium that causes the disease is often normal flora in the nose of asymptomatic carriers.
c. the bacterium that causes the disease also causes pus forming wound infections, which can transmit the disease to food.
d. cooking contaminated food to kill the bacteria will prevent transmission of the disease
e. all of the above statements regarding staphylococcal food-borne illness are correct
Answer:
d. cooking contaminated food to kill the bacteria will prevent transmission of the disease
Explanation:
Staphylococcus is an opportunistic pathogen that normally inhabits our skin and respiratory tract. When this bacteria grows in food it produces different enterotoxins, which are stable at high temperatures. That is why if a food is contaminated with this bacterium, it is possible that it already contains enterotoxin and when it is reheated or cooked, even though the bacteria is killed, the toxin will remain active and will generate the disease.
The light reactions of photosynthesis supply the Calvin cycle with
a. light energy.
b. CO2 and ATP.
c. H2O and NADPH.
d. ATP and NADPH.
Answer:
D
Explanation:
Through the process of photosynthesis, CO₂ and H₂O are converted into glucose and O₂. Through a series of reactions, there are high energy bonds within glucose, that when broken down can release a lot of energy.
When glucose is broken down, ADP is converted into ATP, which can be used to supply other reactions with energy.
Also, another indirect product of photosynthesis is the production of NADPH from NADP⁺. That energy contained in that bond to hydrogen can be used in other reactions in the Calvin cycle.
Final answer:
The light reactions of photosynthesis produce ATP and NADPH, which are then used in the Calvin cycle to synthesize glucose from carbon dioxide. Option D is correct.
Explanation:
The light reactions of photosynthesis are responsible for converting light energy into chemical energy in the form of two key molecules: ATP and NADPH. These reactions occur in the thylakoid membranes of chloroplasts. ATP is adenosine triphosphate, a molecule that stores and transfers energy within cells, while NADPH is a reduced form of nicotinamide adenine dinucleotide phosphate, which acts as a reducing agent transferring electrons in reactions.
The Calvin cycle, also known as the light-independent reactions, uses the ATP and NADPH produced from the light-dependent reactions to fix carbon dioxide (CO2) and synthesize glucose. Therefore, the light reactions supply the Calvin cycle with ATP and NADPH, making option d. ATP and NADPH correct.
What is osmolarity? Hemopoiesis?
Answer:
Osmolarity:
Osmolarity may be defined as the number of solutes dissolved in per solution of liters. The osmolarity plays an important role in the human body as it maintains the water electrolyte balance in the body. The osmolarity of the human plasma is about 275-299 milli-osmoles/kilogram.
Hemopoiesis:
Hemopoiesis may be defined as the process of formation of blood cells in the body. The main types of blood cells formed during this process are red blood cells, white blood cells and platelets. The hemopoiesis majorly occurs in the bone marrow cells.
Scientists discovered a new species of freshwater fish that lives in a pond with a very low O2 level. When they measured the oxygen extraction efficiency of the fish, it was twice as high as that of closely-related fresh water fish. Propose a hypothesis to explain how the fish achieve a high O2 extraction efficiency
Answer:
In order to propose a hypothesis, there is a need to first see the function of gills in fishes. The gills of fishes comprise blood vessels that exhibit inherited tendencies of getting oxygen out of the water, which was consumed by fishes from their mouths. These gills also comprise thin walls, and when water moves over these walls of blood vessels, the oxygen from water moves into the blood, and then this oxygen-enriched blood goes to various organs.
Thus, one of the hypotheses in the given case, can be the number of blood vessels, which are found in the gills of the mentioned freshwater fish to be higher in comparison to the blood vessels found in the normal fishes, and apart from this, the surface area of the thin walls, which are found in the gills is also more in the new species of freshwater fish.
Mosquito Dunks contain protein, produced by Bacillus thuringiensis bacteria, that is toxic to some aquatic insect larvae. Mosquito Dunks may help control which of the following?
a. malaria
b. bubonic plague
c. Legionnaires' disease
d. toxoplamosis
e. all of the above
Answer:
a. malaria
Explanation:
Malaria is caused by a parasite that is transmitted by the bite of infected anopheles mosquitoes, entering the bloodstream, affecting the red blood cells. Therefore, Mosquito Dunks may be a good control of malaria in tropical countries.
On the other hand, mosquito dunk is an inappropriate control method for the other diseases listed, because bubonic plague was transmitted by the fleas of rats, legionellosis is an infectious disease caused by a bacterium (Legionella) that is found mainly in water bodies and toxoplasmosis is caused by a parasite present in undercooked contaminated meat and the feces of cats.
What are two types of membrane diffusion? Describe the enzymes that promote membrane diffusion.
Answer:
Simple diffusion and Facilitated diffusion
Explanation:
The simple diffusion process involves movement of molecules. This movement occurs from high concentration to low concentration. The facilitated diffusion process is a passive diffusion process. This process requires proteins for movement of molecules, the proteins are carrier and channel proteins.
The enzymes that promote membrane diffusion are carrier proteins. These proteins act as enzymes and allows transport by changing the conformation and opening of channels.
The two types of membrane diffusion are simple diffusion and facilitated diffusion. Simple diffusion does not involve any enzymes, as it's the movement of small and nonpolar molecules down their concentration gradient through the phospholipid bilayer directly. Facilitated diffusion may involve carrier proteins or channel proteins but does not involve classical enzymes that catalyze reactions; instead, these proteins facilitate the movement of substances across cell membranes that cannot easily pass through the lipid bilayer directly.
Diffusion is critical for the transport of materials across biological membranes, helping to maintain homeostasis within cells and organisms. Simple diffusion allows for the passive movement of substances like oxygen and carbon dioxide, relying on the concentration gradient to drive the process without energy input. Facilitated diffusion also moves substances along their concentration gradient but through specific carrier proteins or channels. These proteins provide a pathway for larger or polar molecules that cannot diffuse through the lipid bilayer unaided. Temperature is one of the factors that can affect the rate of diffusion; higher temperatures increase molecular kinetic energy, which generally speeds up diffusion rates.
Diagram the forces and structures that dictate chromosomal movement during mitosis.
Answer:
Mitosis is the biological process by which cell division occurs
Explanation:
-in interphase the nucleolus and its cell membrane are differentiated, and the chromosomes are in the form of chromatin
- in prophase the chromosomes are condensed, and the chromatin is no longer visible
-in metaphase the rolled chromosomes each with their chromatids line up in the metaphase plate
in anaphase the chromatids of each chromosome separate and move towards the poles
in telophase the chromosomes are in each pole, the cell membrane forms again and the cytoplasm is divided.
Finally in cytokinesis cell division is completed