Given a central angle of 100 in a circle with a radius of 7 in., what is the intercepted arc length of the central angle?

**Use 3.14 for π and round to ONE decimal place.

The ordered pair (0 , -2) lies on the line with equation 3 x - y = 2

Step-by-step explanation:

To prove that a point lies on a line

The equation of the line is 3 x - y = 2

a) Point (0 , -2)

∵ x = 0 and y = -2

- Substitute the values of x and y in the left hand side

∵ The left hand side is 3 x - y

∵ 3(0) - (-2) = 0 + 2 = 2

∴ The left hand side = 2

∵ The right hand side = 2

∴ The two sides of the equation are equal

∴ The ordered pair (0 , -2) lies on the line

b) Point (-3 , 4)

∵ x = -3 and y = 4

- Substitute the values of x and y in the left hand side

∵ The left hand side is 3 x - y

∵ 3(-3) - (4) = -9 - 4 = -13

∴ The left hand side = -13

∵ The right hand side = 2

∴ The two sides of the equation are not equal

∴ The ordered pair (-3 , 4) doesn't lie on the line

c) Point (1 , -5)

∵ x = 1 and y = -5

- Substitute the values of x and y in the left hand side

∵ The left hand side is 3 x - y

∵ 3(1) - (-5) = 3 + 5 = 8

∴ The left hand side = 8

∵ The right hand side = 2

∴ The two sides of the equation are not equal

∴ The ordered pair (1 , -5) doesn't lie on the line

The ordered pair (0 , -2) lies on the line with equation 3 x - y = 2

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Answer:

16.78 seconds

Step-by-step explanation:

speed = Distance Traveled / time

thus speed =29.79 Km/sec

time =distance Traveled/speed (from above formula)

time taken=500 km ÷ 29.79 Km/sec

∴time taken=16.78 seconds

There are total of 32 pages in the complete book.

A word problem is a few sentences describing a 'real-life' scenario where a problem needs to be solved by way of a mathematical calculation.

Given is that Tyler reads 2/15 of a book on Monday, 1/3 of it on Tuesday, 2/9 of it on Wednesday, and 3/4 of the remainder on Thursday. He still has 14 pages.

Let the total number of pages in the book will be [x]. Then, we can write -

{2x/15} + {x/3} + {2x/9} + {3x/4} = x + 14

x{2/15 + 1/3 + 2/9 + 3/4} - 14 = x

259x/180 - 14 = x

1.44x - 14 = x

0.44x = 14

x = (14/0.44)

x = 32 (approx.)

Therefore, there are total of 32 pages in the complete book.

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Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

Solution:

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is [tex]\frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }[/tex]

If they work together they can do the entire prospectus in five hours

[tex]\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}[/tex]

On cross-multiplication we get,

[tex]\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}[/tex]

[tex]\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}[/tex]

On cross multiplication ,we get

[tex]\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}[/tex]

using quadratic formula:-

[tex]x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}[/tex]

[tex]x=\frac{12 \pm \sqrt{144-40}}{2}[/tex]

[tex]\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}[/tex]

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

Answer: 0.5

Step-by-step explanation:

For binary distribution with parameters p (probability of getting success in each trial) and n (Total trials) , we have

[tex]\sigma=\sqrt{np(1-p)}[/tex]

We are given that ,

Total batches of televisions : n=25

The probability of defects : p= 0.01

Here success is getting defective batch .

Then, the standard deviation for the number of defects per batch will be :-

[tex]\sigma=\sqrt{(25)(0.01)(1-0.01)}\\\\=\sqrt{(25)(0.01)(0.99)}\\\\=\sqrt{0.2475}\\\\=0.497493718553\approx0.5[/tex] [Rounedde to the nearest tenth.]

Therefore, the standard deviation for the number of defects per batch =0.5

Answer:

D

Step-by-step explanation:

a meter is 100 centimeters so the ratio of the real car to the model is 300 centimeters to 3 centimeters, or 100:1 so D

.---------. _

'-O------O--'

Answer:

Step-by-step explanation:

(a) The general term of an arithmetic sequence is ...

  an = a1 + d(n -1)

If we let the sequence of population numbers be modeled by this, and we use t for the number of years, we want n=1 for t=0, so n = t+1 and we have ...

  p(t) = 854 +3(t+1-1)

  p(t) = 854 +3t

__

(b) The general term of a geometric sequence is ...

  an = a1·r^(n-1)

were r is the common ratio. Here, the multiplier from one year to the next is 1+10% = 1.10. Again, n=t+1, so the population equation is ...

  p(t) = 427·1.10^(t+1-1)

  p(t) = 427·1.10^t

Both jewelers used 26104 beads altogether while making necklaces.

Step-by-step explanation:

No. of necklaces made by Gemma = 106

Necklaces made by Leah = 106+39 = 145 necklaces

Total necklaces made = Gemma's + Leah's

Total necklaces made = [tex]106+145 = 251\ necklaces[/tex]

Beads used in 1 necklace = 104 beads

Beads used in 251 necklaces = 104*251 = 26104

Both jewelers used 26104 beads altogether while making necklaces.

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Answer:

No because the probability of consecutive shows starting late are not independent events

Step-by-step explanation:

Is good begin with the definition of independent events

When we say Independent Events we are refering to  events which occur with no dependency of other evnts. Basically when the occurrence of one event is not affected by another one.

When two events are independent P(A and B) = P(A)xP(B)

But for this case we can't multiply 0.97x0.97x0.97 in order to find the probability that 3 consecutive shows start on time, because the probability for shows starting late are not independent events, because if the second show is late, the probability that the next show would be late is higher. And for this reason we can use the independency concept here and the multiplication of probabilities in order to find the probability required.

Yes, you can multiply (0.97)(0.97)(0.97) because the events are independent.

Yes, you can multiply (0.97)(0.97)(0.97) to find the probability that three consecutive shows on this network start on time. This is because the events are independent; the outcome of one show starting on time does not affect the outcome of the others.

Therefore, the probability that three consecutive shows start on time is the product of the probabilities of each show starting on time:  P(all three shows start on time) = 0.97 * 0.97 * 0.97 = 0.912673.

Answer:

[tex]f(x)=3^{3x-1}[/tex].

The domain of the function is the set of all real number and the range is [tex](0,\infty)[/tex]

Step-by-step explanation:

Given:

The function is  given as:

[tex]f(x)=\frac{1}{3}(81)^{\frac{3x}{4}}[/tex]

Using the rule of the exponents, [tex]a^{mn}=(a^m)^n[/tex],

[tex]f(x)=\frac{1}{3}((81)^{\frac{1}{4}})^{(3x)}\\f(x)=\frac{1}{3}(\sqrt[4]{81} )^{3x}\\f(x)=\frac{1}{3}(3)^{3x}\\f(x)=\frac{3^{3x}}{3^1}[/tex]

Using the rule of the exponents,[tex]\frac{a^m}{a^n}=a^{m-n}[/tex],

[tex]f(x)=3^{3x-1}[/tex]

Therefore, the simplified form of the given function is:

[tex]f(x)=3^{3x-1}[/tex]

Key aspects:

The given function is an exponential function with a constant base 3.

Domain is the set of all possible values of [tex]x[/tex] for which the function is defined.

The domain of an exponential function is a set of all real values.

The range of an exponential function is always greater than zero.

Therefore, the domain of this function is also all real values and the range is from 0 to infinity.

Domain: [tex]x \epsilon (-\infty,\infty)[/tex]

Range: [tex]y\epsilon (0,\infty)[/tex]

Answer: 1/3 27 all real numbers y>0

Step-by-step explanation:

Answer:

Spearman's correlation

Step-by-step explanation:

A researcher records each student’s rank in his/her high school graduating class and the student’s rank in the college graduating class.

The correlation that should be used to measure the relationship between these two variables is - Spearman's correlation

This correlation gives a statistical measure of similar relationship between paired data.

This is used to evaluate relationships involving ordinal variables.

Answer:

D= -16

E= 0

F= 0

Step-by-step explanation:

The given equation is [tex]x^{2} + y^{2} + Dx + Ey + F = 0[/tex]

It is also given that the circle passes through (0,0) (16,0) and (8,8).

Inserting (0,0) in the equation, it gives

[tex]0 + 0 + 0 + 0 + F = 0[/tex]

This gives F = 0 .

Now inserting (16,0) , it gives

[tex]16^{2} + 0^{2} + D(16) + E(0) + 0 = 0[/tex]

[tex]D(16) = -256[/tex]

[tex]D = \frac{-256}{16}[/tex]

D = -16

Now inserting (8,8) , it gives

[tex]8^{2} + 8^{2} + (-16)(8) + (E)(8) + 0 = 0[/tex]

[tex]-16 + E = -16[/tex]

E = 0

Thus the equation of circle is

[tex]x^{2} + y^{2} + (-16)x  = 0[/tex]

We can draw the following graph and thus verify that points (0,0) (8,8) and (16,0) lie on graph.

The equation of the circle passing through points (0, 0), (8, 8), and (16, 0) is x^2 + y^2 - 16x - 16y = 0. Solving the system of equations derived from substituting the given points into the circle equation confirms these coefficients for D and E.

To find the equation of the circle that passes through the points (0, 0), (8, 8), and (16, 0), we can use the standard form of a circle's equation:

x

2

+

y

2

+ D

x

+ E

y

+ F = 0

Because the circle passes through the origin (0,0), we know that F = 0. With the remaining points (8, 8) and (16, 0), we can substitute these coordinates into the equation to form a system of equations.

Using point (8,8), the equation becomes:

64 + 64 + 8D + 8E + F = 0

Using point (16,0), the equation becomes:

256 + 16D + F = 0

Since F = 0, the system of equations is:

Solving these equations, we get:

The equation of the circle is therefore:

To verify the result, plotting the points and the graph of the circle on a graphing utility should show that the points lie on the circumference of the circle.

Answer:

The mean of a binomial distribution is given  by  mean  = n x p where n = the number of items and p equals the probability of success.  Here we have:

mean =  1632 x 0.57  =   930.2

Step-by-step explanation:

The mean for a binomial substitution = n x p

Mean = 1632 x 0.57 = 930.24

The answer would be D.

Picture:

Multiply P(x) by X, then add those together:

0 x 0.42 = 0

1 x 0.12 = 0.12

2 x 0.34 = 0.68

3 x 0.05 = 0.15

4 x 0.07 = 0.28

Mean = 0 + 0.12 + 0.68 + 0.15 + 0.28 = 1.23

Answer:

Yes, it will reach or exceed 141 degree F

Step-by-step explanation:

Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

[tex]T = 0.005x^2 + 0.45x + 125[/tex]

Suppose T = 141°F,

[tex]\implies 141 = 0.005x^2 + 0.45x + 125[/tex]

[tex]\implies 0.005x^2 + 0.45x + 125 - 141 =0[/tex]

[tex]\implies 0.005x^2 + 0.45x - 16=0[/tex]

Since, a quadratic equation [tex]ax^2 + bx + c =0[/tex] has,

Real roots,

If Discriminant, [tex]D = b^2 - 4ac \geq 0[/tex]

Imaginary roots,

If D < 0,

Since, [tex]0.45^2 - 4\times 0.005\times -16 = 0.2025 + 32 > 0[/tex]

Thus, roots of -0.005x² + 0.45x + 125 are real.

Hence, the temperature can reach or exceed 141 degree F.

The temperature of the part will exceed 141°F during the manufacturing process.

To determine if the temperature of the part will ever reach or exceed 141°F, we need to find the value of x when the temperature T equals 141°F. We can do this by setting the equation T = 0.005x² + 0.45x + 125 equal to 141 and solving for x using the quadratic formula.

The quadratic formula is given by x = (-b ± √(b² - 4ac))/(2a), where a, b, and c are the coefficients of the quadratic equation. In this case, a = 0.005, b = 0.45, and c = 125 - 141 = -16.

Calculating the discriminant, which is the value inside the square root in the quadratic formula, we get b² - 4ac = 0.45² - 4(0.005)(-16) = 0.2025 + 0.32 = 0.5225. Since the discriminant is positive, the quadratic equation has two real and distinct solutions, which means the temperature of the part will exceed 141°F at some point during the manufacturing process.

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Answer:

Step-by-step explanation:

The right triangle has three sides which can be called legs. The legs are; shorter leg. Longer leg and hypotenuse

Let the longer leg be x

One leg of a right triangle is 4 mm shorter than the longer leg. This means

The shorter leg = x - 4

the hypotenuse is 4 mm longer than the longer leg. This means

The hypotenuse = x + 4

So the legs of the triangle are

Shorter leg or side = x-4

Longer leg or side = x

Hypotenuse = x + 4

The lengths of the sides of the triangle are 12 mm, 16 mm, and 20 mm.

Let's use variables to represent the lengths of the sides:

According to the Pythagorean theorem, in a right triangle, the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse:

a² + b² = c²

Plugging in the values, we have:

x² + (x + 4)² = (x + 8)²

Expanding and simplifying, we get:

x² + x² + 8x + 16 = x² + 16x + 64

Combining like terms, we get:

x² - 8x - 48 = 0

Factoring the quadratic equation, we find:

(x - 12)(x + 4) = 0

Therefore, x = 12 or x = -4. We discard the negative value, so the lengths of the sides of the triangle are:

Answer:

  1.047 ft

Step-by-step explanation:

The length of an arc is given by ...

  s = rθ

where s is the arc length, r is the radius, and θ is the central angle in radians. Your arc subtends an angle of 12° = (12·π/180) = π/15 radians. The length of the arc is then ...

  s = (5 ft)(π/15) = π/3 ft ≈ 1.047 ft

The weight swings through a total angle of 12°, corresponding to an arc length of approximately 1.047 feet on the circumference of the circle with radius 5 feet.

To answer this question, we need to understand that the weight swings through an arc, and this arc is a part of the circumference of a circle. Given the length of string (5 feet) is the radius, and the weight swings through 6° on either side of the vertical, we can calculate the total arc length.

Firstly, you should know that the total angle a circle encompasses is 360°. So, the weight swings through a total angle of 6° x 2 = 12°.

Secondly, recall the formula for the circumference of a circle is 2πr, or in our case 2π x 5 feet. Now, to find the length of the arc corresponding to 12°, we will use the proportion of the swing angle to the total angle, i.e., (12/360) x (2π x 5 feet).

In this way, the length of the arc travelled is almost 1.047 feet.

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Answer:

  12 mph

Step-by-step explanation:

The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...

  (9 mi)(.75 h) = 12 mi/h . . . average jogging speed

__

Check

1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.

4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.

The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)

_____

Comment on the problem

Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.

Answer:

0.093 ft/min

Step-by-step explanation:

V = 4/3 π r³

Take derivative with respect to time:

dV/dt = 4π r² dr/dt

Plug in values:

141 = 4π (11)² dr/dt

dr/dt = 141 / (484π)

dr/dt ≈ 0.093

The radius is increasing at 0.093 ft/min.

The increasing rate of the radius is equal to 0.093 ft/min.

Volume is defined as the space occupied by the object in a three-dimensional space. The sphere is the shape of a circular ball.

The volume is calculated by the formula below,

V = 4/3 π r³

Take the derivative with respect to time:

dV/dt = 4π r² dr/dt

Solve the equation for the rate of change of radius of the sphere,

141 = 4π (11)² dr/dt

dr/dt = 141 / (484π)

dr/dt ≈ 0.093

Therefore, the increasing rate of the radius is equal to 0.093 ft/min.

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Answer:

Optical axis

Step-by-step explanation:

Optical axis is the rotational symmetry axis of the surfaces.

A line with a certain degree of rotational symmetry is called as the optical axis in an optical system.

It is the straight line that passes through the geometric center of the lens and joins two curvature centers of its surfaces.

It is also called as the principal axis.

The best statement that could be used describe a polygon is that it is a closed plane figure with three or more sides that are straight. Thus, the correct answer is A: a closed plane figure with three or more sides that are straight.

Hope this helps! :)

Answer:

The answer is 1.

Answer:

1

Step-by-step explanation:

any variable of power 0 equal to 1

Final answer:

To find the probability that the first to arrive waits no longer than 5 minutes and the probability that the man arrives first, follow the provided detailed steps.

Explanation:

To find the probability that the first to arrive waits no longer than 5 minutes:

Man arrives first: 1/6

Woman arrives first: 1/4

Man and Woman arrive simultaneously within 5 minutes: 1/12

The probability that the man arrives first: 1/6

Amount of down payment = $46000

Mortgage needs = $184000

Solution:

From the given,

Cost of the house = [tex]\$230000[/tex]

Percentage of down payment = [tex]20\%[/tex]

Number of years of fixed loan = 30

[tex]\text { Total down payment }=\text { cost of the house } \times \text { Percentage of down payment }[/tex]

[tex]\Rightarrow \frac{230000 \$\times 20}{100} \rightarrow 46000 \$[/tex]

[tex]\text {Mortgage needs}=\text { Total cost - Total down payment }[/tex]

[tex]\Rightarrow 230000 \$-46000 \$=184000 \$[/tex]

It can be concluded that the total down payment for the house and mortgage needs would be [tex]\$46000 \text{ and } \$184000[/tex]

Answer:

It would Cost $125 for a 60 day supply of cat food.

Step-by-step explanation:

Given:

Rover eats cat food each day = [tex]\frac{3}{4}[/tex] = 0.75 can

Bono eats cat food each day = [tex]\frac{1}{2}[/tex] = 0.5 can

Each day consumption for both cats = 0.75+0.5 = 1.25 can

Each day both cats consume = 1.25 cans

For 60 days both cats consume = Number of cans in 60 days.

By Using Unitary method we get;

Number of cans in 60 days = [tex]1.25\times60=75 \ cans[/tex]

Now Cans are sold in a pack of 3.

Hence we will divide number of cans in 60 days with 3 we get;

Number of can packs required for 60 days = [tex]\frac{75}{3}=25 \ can \ packs[/tex]

Now Cost for each Can packs(3 can) = $5.00

Hence Cost for 25 Can packs (75 cans) = Price for 25 can packs(75 can)

By Using Unitary method we get;

Price for 25 can packs (75 cans) = [tex]5\times 25 = \$125[/tex]

Hence Price for 25 can packs (75 cans) which are used for 60 supply of cat food is $125.

Answer:

d is the correct answer

Answer:75

Step-by-step explanation:

Answer:

The amount invested in bonds = 35,000

The amount invested in CD = 15,000.

Step-by-step explanation:

The total amount that Daniela invested is $50,000, this means if we call the amount invested in bonds [tex]b[/tex], and the amount invested in CD [tex]d[/tex], then we have:

[tex]b+d=50,000[/tex] this says the total amount Daniela invested is $50,000.

And since the amount invested in bonds [tex]b[/tex] is $5,000 more than twice the amount Daniela put into the CD, we have:

[tex]b=5,000+2d[/tex].

Thus, we have two equations and two unknowns [tex]b[/tex] and [tex]d[/tex]:

(1). [tex]b+d=50,000[/tex]

(2). [tex]b=5,000+2d[/tex],

and we solve this system by substituting [tex]b[/tex] from the second equation into the first:

[tex]b+d=50,000\\5,000+2d+d=50,000\\3d=45,000\\\\\boxed{d=15,000}[/tex]

or, the amount invested in CD is $15,000.

With the value of [tex]d[/tex] in hand, we now solve for [tex]b[/tex] from equation(2):

[tex]b=5,000+2d\\b=5000+2(15,000)\\\boxed{b=35,000}[/tex]

or, the amount invested in bonds is $35,000.

Answer:

A i think

Step-by-step explanation:

Answer:

Step-by-step explanation:

We want to find 95% confidence interval for the mean of the weight of of textbooks.

Number of samples. n = 28 textbooks weight

Mean, u =76 ounces

Standard deviation, s = 12.3 ounces

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

76 +/- 1.96 × 12.3/√28

= 76 +/- 1.96 × 2.3113

= 76 +/- 4.53

The lower end of the confidence interval is 76 - 4.53 =71.47

The upper end of the confidence interval is 76 + 4.53 = 80.53

Therefore, with 95% confidence interval, the mean textbook weight is between 71.47 ounces and 80.53 ounces

Answer:

Step-by-step explanation:

For given points (t1, y1), (t2, y2), I like to write the exponential function as ...

  y(t) = y1·(y2/y1)^((t-t1)/(t2-t1))

This can be converted to other forms (such as a·b^t or a·e^(kt)) fairly easily, but those tend not to reproduce the given numbers exactly as this form does.

Using (15, 300) and (35, 1900) as our data values, the exponential function can be written as ...

  y(t) = 300·(19/3)^((t-15)/20)

__

a) The initial size of the culture is the value of y(0).

 y(0) = 300·(19/3)^(-15/20) ≈ 75.144

  y(0) ≈ 75 . . . initial population

__

b) The doubling period will be the value of t that satisfies ...

  (19/3)^(t/20) = 2

Taking logarithms, we have ...

  (t/20)·log(19/3) = log(2)

  t = 20·log(2)/log(19/3) ≈ 7.5104 . . . . minutes

The doubling time is about 7.51 minutes.

__

c) Evaluating the formula for t=115, we have ...

  y(115) = 300·(19/3)^(100/20) ≈ 3056912.346

The count after 115 minutes will be about 3,056,900.

__

d) Solving y(t) = 11,000, we have ...

  11000 = 300·(19/3)^((t-15)/20)

  11000/300 = (19/3)^((t-15)/20)

  log(110/3) = (t-15)/20·log(19/3)

  t = 20·log(110/3)/log(19/3) + 15 ≈ 54.027

It will take about 54.03 minutes for the count to reach 11,000.

_____

I find a graphing calculator to be a nice tool for solving problems like this.