given f(x) = 5x^6 and g(x) = 15x^-2, what is f(x)/g(x)?


A)x^8/3

B) 3x^8

C) x^4/3

D) 3x^4

We are given that

y-scale is a distance in miles

x-scale is a time in hours

and we are given

The graph of the distance a car travels at a constant speed passes through the points (0,0) and (2,136)

so, points would be

(0,0)

x1=0 , y2=0

(2,136)

x2=2 , y2=136

so, slope would be speed

because speed = distance / time

we can use slope formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

now, we can plug values

[tex]m=\frac{136-0}{2-0}[/tex]

[tex]m=68[/tex] miles per hour

so, option-B..........Answer

Answer:

B

Step-by-step explanation:

let y = x^2

4y^2 -21y + 20 = 0

solve for y

then substitute back in to get x

Answer:

4y^2 - 21y + 20 = 0

Step-by-step explanation:

As (4x^4 - 21x^2 + 20=0) being a biquadratic equation, meaning it is a 4-degree equation without the terms of degree 1 and 3.

To solve this particular case you only need to replace the variables of degree 4 and 2 for a new variable of degree 2 and 1 and solve it as regular quadratic equation and then undo the change.

* Using a new variable we can rewrite the equation:

Let y be the new variable;

y= x^2, then y^2= x^4

Then we have;

4y^2- 21y+20=0

Solve for y and then find X which will be the roots for the biquadratic equation.

Because there are 2 minus signs next to each other, we can replace both of them with a single plus sign.

This changes the equation to -7 + 3

Adding to a negative number makes the number appear smaller, so 3 + -7 = -4.

Remove parenthesis

-7=3

Calculate the sum

-4

Answer:

0.14

Hope this helps :-)

To draw a perpendicular bisector, her next step should be to: draw two arcs to the left and right of A and B using the same width of the compass.

A perpendicular bisector of a segment can be described as a line that divides a segment into two equal parts at right triangle.

Thus, based on the definition of a perpendicular bisector of a segment, for Audra to draw a perpendicular bisector of segment AB, her next step should be to: draw two arcs to the left and right of A and B using the same width of the compass.

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The expression 6a − 3b = 5b after solving for a:b is 4:3 after using arithmetic operation.

It is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.

It is given that:

The expression is:

6a − 3b = 5b

To solve the above expression:

6a = 5b + 3b

6a = 8b

a/b = 8/6

As we know,

The expression can be defined as the combination of constants and variables with mathematical operators.

a:b = 8: 6

a:b = 4: 3

If in the linear expression, one variable is present, then the expression is known as the linear expression in one variabe.

Thus, the expression 6a − 3b = 5b after solving for a:b is 4:3 after using arithmetic operation.

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its's 200 sq feet, I added extra lenghts and the circled numbers are areas for that part of the shape.

A graph that is undefined has a slope of [tex]x=0[/tex]

Graph the function as usual, but skip the undefined point. You may want to graph the surroundings to see how the function behaves near the undefined point.

Just graph the function as usual, but skip the troublesome point. You may want to graph the surroundings of the said undefined point.

For example, when you're graphing  y=1/x, we know that when  x=0 the function is undefined, so just skip it. But, you can draw the surroundings of  x=0, for example, when  x=±1,±0.1,±0.01,±0.001,... and see what happens to the function as it approaches  x=0.

This is an example of the plot. As you can see, you just skip over when  x=0, but still plot the rest of the domain. You can see that the function behaves erratically near  x=0.

Another example: try to plot f(x)=(x2−4)/(x−2). If you plotted it correctly, you should see a 'straight-line', except that it was punctured on the point  (2,4), because f(x) wasn't defined for  x=2. In this case, you just draw a hollow circle on that point (like: o ), to show that the function is not exactly continuous and there is a hole on point  (2,4).

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Question:

How do you graph a point of a function if it is undefined?

The formula of a midpoint between two points:

[tex]M\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)[/tex]

We have (5, 8) and (-1, 6).

Substitute:

[tex]\dfrac{5+(-1)}{2}=\dfrac{4}{2}=2\\\\\dfrac{8+6}{2}=\dfrac{14}{2}=7[/tex]

Answer: The coordinates of the midpoint of the segment are (2, 7).

Answer:

NO the Earth to Sun distance is 9.3 x 10^7 miles.

Earth to Noon distance is 2.4 x 10^5 miles

9.3 x 10^7 is 387.5 times larger than 2.4 x 10 ^ 5

Step-by-step explanation:

Answer:

31 times bigger is the distance from earth to the sun than the distance from earth to the moon.

Step-by-step explanation:

Given : The distance from the earth to the sun is 9.3×10 to the 6(power) miles. The distance from earth the moon is 3×10 to the 5th(power) miles.

To find : How many times bigger is the distance from earth to the sun than the distance from earth to the moon?

Solution :          

The distance from the earth to the sun is [tex]9.3\times 10^{6}[/tex] miles.

The distance from the earth to the moon is [tex]3\times 10^{5}[/tex] miles.

To know, times bigger is the distance from earth to the sun than the distance from earth to the moon is given by,

[tex]n=\frac{9.3\times 10^{6}}{3\times 10^{5}}[/tex]

[tex]n=3.1\times 10^{6-5}[/tex]

[tex]n=3.1\times 10[/tex]

[tex]n=31[/tex]

Therefore, 31 times bigger is the distance from earth to the sun than the distance from earth to the moon.

Answer:

We have

k^2 - 25f^2 + 5kf - 25f^2 =

k^2 - (5f)^2 + 5f( k - 5f) =

( k - 5f )( k + 5f ) + 5f( k - 5f ) =

( k - 5f )( k + 5f + 5f ) =

( k - 5f )( k + 10f );

Step-by-step explanation:

Answer:  The required factored form of the given expression is [tex](k-5f)(k+10f).[/tex]

Step-by-step explanation:  We are given to factor the following quadratic expression :

[tex]E=k^2+5kf-50f^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

To factor the given expression, we need two integers with sum 5 and product -50 and those two integers are 10 and -5.

The factorization of expression (i) is as follows :

[tex]E\\\\=k^2+5kf-50f^2\\\\=k^2+10kf-5kf-50f^2\\\\=k(k+10f)-5f(k+10f)\\\\=(k-5f)(k+10f).[/tex]

Thus, the required factored form of the given expression is [tex](k-5f)(k+10f).[/tex]

Answer:

answer is 9.

Step-by-step explanation:

396 is the answer since it's closer to the 10's than the 0s

Answer:

Option C is correct

Step-by-step explanation:

In similar triangles corresponding sides are in same ratio.

Notice that  sides b and q are corresponding ( they are opposite equal angles)  and so are a and p

The correct equation from the option is b/q = a/p. Hence, option C is correct.

To make a proportional relationship from the two triangles ABC and PQR given ;

Express corresponding sides as ratios ;

Using the given sides , the possible proportions are ;

a/p = b/q

b/q = c/r

a/p = c/r

Comparing the ratios with the options given, Only option B gives a correct proportional relationship.

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Answer: The antiderivative of [tex]e^{x^{2}}[/tex] is [tex]\sqrt{\pi} \sqrt{e^{x^2}-1} +C[/tex].

Explanation:

[tex]I=\int{e^{x^2}dx}\\I^2=\int{e^{x^2}dx}\int{e^{x^2}dx}[/tex]

Using dawson integral.

[tex]I^2=\int{e^{x^2}dx}\int{e^{y^2}dy}[/tex]

[tex]I^2=\int{\int{e^{x^2+y^2}dxdy}}[/tex]

Put [tex]x^2+y^2=r^2[/tex]

[tex]I^2=\int{\int{e^{r^2}rdrd\theta}}[/tex]

[tex]\int_{0}^{2\pi}{d\theta}\int_{0}^{x}{re^{r^2}dr}[/tex]

Use substitution method and sunbstitute [tex]r^2=t[/tex].

[tex]\int_{0}^{2\pi}{d\theta}\int_{0}^{x^2}{\frac{1}{2}e^tdt}[/tex]

[tex]I^2=\frac{1}{2}|\theta|_{0}^{2\pi}|e^t|_{0}^{x^2}\\I^2=\frac{1}{2}(2\pi)(e^{x^2}-1)\\I=\sqrt{\pi}\sqrt{e^{x^2}-1}[/tex].

Therefore, the antiderivative of [tex]e^{x^{2}}[/tex] is [tex]\sqrt{\pi} \sqrt{e^{x^2}-1} +C[/tex].

greatest number for what

Answer:

Im pretty sure its graph A

Step-by-step explanation:

Answer:

graph A

Step-by-step explanation:

V = 1/3 area of base * height

Area of  base = h [(b₁ +b₂)]/2

[(3 + 6) * 4] : 2 =

18 ft²

Volume =

18 * 3 =

54 ft³

Simplify 1/3x to x/3

y = -x/3 - 9

Add 9 to both sides

y + 9 = -x/3

Multiply both sides by 3

(y + 9) * = -x

Regroup terms

3(y + 9) = -x

Using the formula, rewrite in standard form

Answer: x + 3y = -27

To convert the equation y = -1/3x - 9 to standard form, you need to eliminate the fraction and rearrange the equation. Multiply both sides of the equation by 3 to get 3y = -x - 27. Rearrange the equation to get x + 3y = -27, which is the standard form.

The equation y = -1/3x - 9 can be written in standard form as Ax + By = C, where A, B, and C are constants. To write the equation in standard form, we need to eliminate the fraction by multiplying both sides of the equation by 3. This gives us 3y = -x - 27. Rearranging the equation, we get x + 3y = -27, which is the standard form.

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*(Step-By-Step)*

[tex]5x+6=5x-9[/tex]        Combine Like Terms

[tex]6=9[/tex]                Subtract [tex]5x[/tex] to both sides

*(Answer)*= No solution because [tex]6[/tex] is not [tex]9[/tex]

Hope this helps

BangtanBoyScouts

Given the speed is 200 km /hr

use 1 km  = 1000 meter

1 hr = 3600 seconds

so

[tex]200 km/hr = \frac{200*1000}{1*3600}   m/s[/tex]

simplifies to

[tex]\frac{5000}{9} m/s[/tex]

[tex]55.6 m/s[/tex]

so option C

Answer:  C) 55.6 m/s  

Step-by-step explanation:  200km/1hr x 1000m/1km x 1hr/60min x 1min/60s = 55.6 m/s

If the conversion factors are properly set up and all numbers are correct, the unwanted units cancel out leaving the units of the final answer.

The equation is: 7 + (x + 5)

The expression for '7 plus the sum of a number x and 5' is written as '7 + (x + 5)'.

The phrase '7 plus the sum of a number x and 5' can be written as an algebraic expression. This involves taking the sum of the variable x and the number 5, and then adding 7 to this sum. In mathematical terms, this is expressed as 7 + (x + 5).

Let's break it down step by step:

First, identify the sum: x + 5.

Next, add 7 to the result of this sum.

So, if we were to evaluate this expression for x = 4, we would calculate it as follows:

7 + (4 + 5) = 7 + 9 = 16

80 = 3y + 2y + 4 +1

80 = 5y + 5

80 - 5 = 5y

75 = 5y

75 = 5y/5y

75/5 = y

15 = y

Answer:

5 adult and 3 student tickets were purchased

Explanation:

Let x be the number of adult tickets

Then 8−x is the number of student tickets

7.25x+5.5(8−x)=52.75

7.25x+44−5.5x=52.75

1.75x=8.75

x=5

Therefore, 5 adult and 3 student tickets were purchased.

1 ≤ s -8

1+8 ≤ s

9. ≤ s

The value of the variable s is greater than or equal to 9.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.

The inequality is given below.

1 ≤ s - 8

Simplify the inequality, then the value of the variable s will be

1 ≤ s - 8

1 + 8 ≤ s

9 ≤ s

Thus, the value of the variable s is greater than or equal to 9.

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Answer:

60 degree

Step-by-step explanation:

adding 1 both sides of equation

2cos x -1+1 = 0.0068 +1

2cosx = 0.9932

dividing by 2 both sides

cosx = 0.9932 / 2

cosx =0.4966

x= cos^-1(0.4966)

x=60 degree

(28x^3 + 42x^2 - 35x) / 7x

** keep in mind, when dividing exponents, u subtract the exponents

4x^2 + 6x - 5 <==

mark brainliest plsss

Answer:

[tex]4x^{2} +6x -5[/tex].

Step-by-step explanation:

Given  :  28x³ + 42x² − 35x .

To find : Divide by 7x .

Solution : We have given   28x³ + 42x² − 35x .

Divide by 7x

28x³ + 42x² − 35x ÷ 7x.

Now Distribute 7x over 28x³ + 42x² − 35x to divide the terms.

[tex]\frac{28x^{3}}{7x} +\frac{42x^{2} }{7x} -\frac{35x}{7x}[/tex].

[tex]4x^{2} +6x -5[/tex].

Note : on dividing exponent is subtract.

Therefore, [tex]4x^{2} +6x -5[/tex].

The swimming pool is leaking 1 6/8 gallons of water per hour.

Answer:

1.75 gallons/hour

Step-by-step explanation:

Thinking process:

The leaking amount in a half hour = [tex]\frac{7}{8}[/tex]

The amount of water that leaks per hour = [tex]2 * \frac{7}{8} \\= \frac{7}{4}\\ = 1.75 gallons/hour[/tex]