Given that the vapor pressure of water is 17.54 torr at 20 °c, calculate the vapor-pressure lowering of aqueous solutions that are 2.20 m in (a) sucrose, c12h22o11, and (b) aluminum chloride. assume 100% dissociation for electrolytes.

Protons and neutrons are held together rather closely in the center of the atom. Together they make up the nucleus, which accounts for nearly all of the mass of the atom.

Electrons move rapidly around the nucleus and constitute almost the entire volume of the atom. Although quantum mechanics are necessary to explain the motion of an electron about the nucleus, we can say that the distribution of electrons about an atom is such that the atom has a spherical shape.

To calculate the equilibrium constant (Kc) for a reaction, detailed information about the reaction and the concentrations of all species at equilibrium is essential, which is not fully provided in the question.

The question at hand requires calculating the value of the equilibrium constant (Kc) for a given chemical reaction. However, from the information provided, it looks like there might be a mix-up or missing data. For calculating Kc, information about the reaction itself and the concentrations of all reactants and products at equilibrium is essential. Without knowing the specific reaction or having the concentrations of other species besides O2, it's impossible to directly calculate Kc. In a typical calculation, if the reaction were known, and assuming O2 participates in the reaction, its concentration along with those of other species involved would be used in the formula for Kc, which usually follows the form: Kc = [Products]coefficients / [Reactants]coefficients. Precision in these values is crucial for determining the reaction's dynamic equilibrium accurately.

Visible light waves have specific properties, including wavelength, that allow them to be detected by the human eye and reach Earth's surface effectively.

Visible light consists of electromagnetic waves that behave like other waves. One important property of light waves is the wavelength, which is the distance between one peak of a wave and the next peak. In the case of visible light, the wavelengths range from about 400 to 700 nanometers (nm). This range of wavelengths is found within the visible light spectrum because these are the waves that human vision can perceive. Human eyes have evolved to see these waves most effectively, and visible light also readily reaches Earth's surface, penetrating the atmosphere effectively.

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Answer:

nitrite ion is NO2- and nitrate ion is NO3-

Explanation:

The nitrite ion has two oxygen atoms and one nitrogen atom while nitrate ion has three oxygen atoms and one nitrogen atom. They are both univalent negative anions that form compounds with metallic cations as shown below;

Na+ + NO3- ⇒ NaNO3 (sodium nitrate)

Na+ + NO2- ⇒ NaNO2 (sodium nitrite)

Ca2+ + NO3- ⇒ Ca(NO3)2 (calcium nitrate)

Ca2+ + NO2- ⇒ Ca(NO2)2 (calcium nitrite)

You can deduce from the above ionic equations that nitrate ion is NO3- while nitrite ion is NO2-.

we have been given the [OH⁻] therefore we can first find the pOH value

pOH scale is used to determine the basicity of a solution

pOH = - log [OH⁻]

pOH = - log (1 x 10⁻¹¹ M)

pOH = 11

after knowing the pOH we can calculate pH using following equation

pH + pOH = 14

since pOH = 11

pH = 14 - 11

pH = 3

pH scale is used to determine how acidic a solution is

once pH is known we can can calculate Hydrogen ion concentration

pH = - log [H⁺]

[H⁺] = antilog (-pH)

[H⁺] = antilog(-3)

[H⁺] = 1 x 10⁻³ M

if pH is less than 7 - solution is acidic

pH = 7 the solution is neutral

pH more than 7 - solution is basic

pH of solution is 3 which is less than 7

therefore solution is acidic

and hydrogen ion concentration is 1 x 10⁻³ M

Answer:

Liquid

Explanation:

Solids have definite shape and definite volume. Since, they have a definite shape, they do not take the shape of the container they are kept in.

Liquids do not have a definite shape but have a definite volume. So, they take the shape of the container they are kept in. You can pour them into a bottle, a glass, or even a polybag. They will take the shape of the container they are kept in.

Gasses neither have a definite shape or a definite volume. So, they also take the shape of the container they are kept in but they do not have a definite volume either.

Therefore, the answer is "Liquid".

The given chemical reaction is:

Mg + Cl₂ → Mg²⁺ + 2Cl⁻

The reaction can be broken down into two half-reactions as follows:

Mg → Mg²⁺ + 2e⁻  ------(1)

Cl₂ + 2e⁻ → 2Cl⁻   ------(2)

Reaction (1) is an oxidation reaction as it involves loss of electrons.

Reaction (2) is reduction reaction as it involves gain of electrons.

The oxidation state of Mg changes from 0 (Mg) to +2 (Mg2+). Hence, Mg is the oxidized substance

Answer:

Mg

Explanation:

Edge

To make it easier, assume that we have a total of 100 g of aegirine. Hence, we have 10g of Na, 24.2g of Fe, 24.3g of Si and 41.5g of O. Know we will convert each of these masses to moles by using the atomic masses of Na, Fe, Si, and O:

[tex] \frac{10g Na}{23g/mole} = 0.43 mole Na[/tex]

[tex]( \frac{24.2g Fe}{55.9g/mole} ) = 0.43 mole Fe[/tex]

[tex] ( \frac{24.3g Si}{28.1g/mole} ) = 0.86 mole Si[/tex]

[tex] ( \frac{41.5g O}{16g/mole} ) = 2.59 mole O[/tex]

Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the mineral:

Na = 0.43/0.43 = 1

Fe = 0.43/0.43 = 1

Si = 0.86/0.43 = 2

O = 2.59/0.43 = 6

So, the empirical formula of the compound NaFeSi2O6

Answer:

The gravitational pull of the moon on the water near the coast (option A) can explain the daily change in sea level observed along a coast.

Explanation:

The tides are rising and falling from sea level that occur several times a day. These periodic changes in the level of the sea are produced by the gravitational forces of attraction of the Sun and the Moon with respect to the Earth. But the force of attraction of the Moon is greater than that of the Sun, due to the proximity of the satellite.

High tide or high tide is the time when the sea reaches its maximum height. Low tide or low tide is the time when the sea reaches its minimum height.

The tide is noticed on the beaches because the coastline can go forward or backward many meters.

Finally, the gravitational pull of the moon on the water near the coast (option A) can explain the daily change in sea level observed along a coast.

At equilibrium, the pH of the solution is 3.48; [H2A] = 0.0496 and [A2-] = 8.2 × 10^-9 M

H2A <----> H+ + HA- ;Ka1 = 2.2 × 10^-6

Ka1 = 2.2x10^-6 = [H+][HA-]/[H2A]

At equilibrium:

Substituting in the equation of Ka1

2.2 × 10^-6 = X^2/0.050 - X

X^2 = 1.1 × 10^-7

X = 3.31 × 10^-4

Since Ka1 <<< Ka2 and [H+] = X

[H+] = 3.31 × 10^-4

pH = - log 3.31 × 10^-4

pH = 3.48

[H2A] = 0.05 - 3.31 × 10^-4

[H2A] = 0.0496

HA- <------> H+ + A- Ka2 = 8.2 × 10^-9

Ka2 = 8.2 × 10^-9 = [H+][A2-]/[HA-]

HA- ------> H+ + A2-

3.31 × 10^-4 3.31 × 10^-4 0 Initial

-y +y +y Change

{3.31 ×10^-4 -y} {3.31 x10^-4+y} {+y} Equilibrium

Assuming y is very small:

Substituting in the equation of Ka2

8.2 × 10^-9 = (3.31x10^-4) × y /3.31 ×10^-4

y = 8.2 × 10^-9

Since [A2-] = y

[A2-] = 8.2 × 10^-9 M

Therefore, at equilibrium, the pH of the solution is 3.48; [H2A] = 0.0496 and [A2-] = 8.2 × 10^-9 M

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Answer:

F

Explanation:

edg

Answer:

lys-arg-cys

Explanation:

The balanced chemical reaction between [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{AgN}}{{\text{O}}_3}[/tex] is

[tex]\boxed{{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( s\right)}[/tex]

Further Explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In this reaction, [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] reacts with [tex]{\text{AgN}}{{\text{O}}_3}[/tex] to form [tex]{\text{NaN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex]. The unbalanced chemical equation is as follows:

[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + {\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to {\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of sodium atoms is 2.

Number of carbon atoms is 1.

Number of oxygen atom is 6.

Number of silver atom is 1.

Number of nitrogen atom is 1.

• On product side,

Number of sodium atom is 1.

Number of carbon atoms is 1.

Number of oxygen atom is 6.

Number of silver atoms is 2.

Number of nitrogen atom is 1.

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. But nitrogen atoms on both sides of the equation are already equal. To balance the number of sodium and silver atoms, multiply [tex]{\text{AgN}}{{\text{O}}_{\text{3}}}[/tex] and [tex]{\text{NaN}}{{\text{O}}_{\text{3}}}[/tex] by 2. So the equation is,

 [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + \boxed2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to \boxed2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. But these are already balanced. Now the reaction is,

[tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]  

Step 5: So the balanced chemical equation is given as follows:

 [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left( {aq} \right) + 2{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) \to 2{\text{NaN}}{{\text{O}}_3}\left( {aq} \right) + {\text{A}}{{\text{g}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Learn more:

1. Balanced chemical equation: https://brainly.com/question/1405182

2. Identification of all of the phases of the reaction: https://brainly.com/question/8926688

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: balanced chemical reaction, reactant side, product side, AgNO3, NaNO3, Ag2CO3, Na2CO3, nitrogen atom, sodium atoms, oxygen atoms, carbon atoms, silver atoms.

Ans: D) 7930 g

Given:

Moles of H2SO4 = 60.0 mol

NH3 in excess

To determine:

The amount in grams of (NH4)2SO4 produced

Explanation:

The chemical reaction is as follows:

2NH3 + H2SO4 → (NH4)2SO4

Since, NH3 is in excess, H2SO4 will be the limiting reagent and will influence the amount of product formed

Based on the reaction stoichiometry:

1 mole of H2SO4 forms 1 mole of (NH4)2SO4

Therefore, 60.0 mol of H2SO4 will produce 60.0 mol of (NH4)2SO4

Now:

[tex]moles = \frac{mass}{molar mass} \\[/tex]

molar mass (NH4)2SO4 = 132.14 g/mol

[tex]mass of (NH4)2SO4 = moles * molar mass\\\\= 60.0 mol * 132.14 g/mol = 7928.4 g[/tex]

The molality, millimolality, and milliosmolality of the solutions are calculated. Osmosis will occur between the solutions, with water moving from the glucose solution to the NaCl solution.

To calculate the molality, millimolality, and milliosmolality of the solutions, we will use the formulas:

Molality (m) = moles of solute / mass of solvent in kg

Millimolality (mm) = millimoles of solute / mass of solvent in kg

Milliosmolality (mOsm) = milliosmoles of solute / mass of solvent in kg

For the NaCl solution:

For the glucose solution:

Osmosis will occur between the solutions since there is a difference in solute concentrations. Water molecules will move from the region of lower solute concentration (higher water concentration) to the region of higher solute concentration (lower water concentration). In this case, water will move from the glucose solution to the NaCl solution.

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Answer : The correct option is, Chemical change.

Explanation :

Physical change : It is a change in which there is no new compound or substance is formed. In this, changes occurs only in the phase.  This change is reversible in nature.

For example : Water boiled  : It is a physical change because in this process only phase changes from liquid state to gaseous state.

Chemical change : It is a change in which a new or different compound or substance is formed and releases some amount of energy. There is no changes occurs in the phase. This change is irreversible in nature.

For example : Marshmallows browned  : It is a chemical change due to the burning of sugar. In the sugar burning process, sugar react with oxygen to give carbon dioxide and water as a product.

As per question, when the substances are different from the starting substances, chemical change has occurred.

Hence, the correct option is, Chemical change.

Final answer:

The molality of a solution containing 75.2 grams of AgClO₄ in 885 grams of benzene is approximately 0.41 m, following calculations based on molar mass and the definition of molality.

Explanation:

To find the molality of a solution that contains 75.2 grams of AgClO₄ in 885 grams of benzene, one must first calculate the number of moles of AgClO₄ present.

The molar mass of AgClO₄ (Ag=107.87, Cl=35.45, O=16.00) is approximately 207.87 g/mol. Therefore, the moles of AgClO₄ are 75.2 g / 207.87 g/mol = 0.362 moles.

Since molality (m) is defined as moles of solute per kilogram of solvent, and the mass of benzene is given in grams, we must convert this to kilograms (885 g = 0.885 kg).

Thus, molality = 0.362 moles / 0.885 kg = 0.409 m, which rounds off to approximately 0.41 m, option A).

The molality of a solution with 75.2 grams of AgClO4 in 885 grams of benzene is calculated to be approximately 0.383 m. The answer closest to the calculation is 0.41 m, which is choice A.

Calculating Molality

To find the molality of a solution containing 75.2 grams of AgClO4 in 885 grams of benzene, we need to use the formula:

First, calculate the number of moles of AgClO4 by using its molar mass:

Molar mass of AgClO4 = 143.321 (Ag) + 35.453 (Cl) + 4*(15.999 (O)) = 221.722 g/mol

Moles of AgClO4 = 75.2 g / 221.722 g/mol = 0.339 moles

Next, convert the mass of the benzene solvent into kilograms:

885 g = 0.885 kg

Now, divide the moles of AgClO4 by the kilograms of benzene:

Molality = 0.339 moles / 0.885 kg = 0.383 m

Looking at the answer choices, the closest value is 0.41 m, which is choice A. Therefore, the correct answer to the student's question is A.) 0.41 m.